Please find the measure of the exterior angle

Answer:

Yes because the y value is 0 thus the ordered pair is located on the x - axis

Step-by-step explanation:

Answer:

13.7 cookies per cup

Step-by-step explanation:

Here, we want to write the constant of proportionality that relates the number of cookies to the

number of flours.

What we do

simply here is to divide the number of cookies by the number of cups of flowers

That would be;

y/x = 48 cookies/3.5 cups = 13.7 cookies per cup

Answer:

C. Quadratic

Step-by-step explanation:

Solve for a:

2 a^3 + a^2 + a + 4 = 0

Hint: | Look for a simple substitution that eliminates the quadratic term of 2 a^3 + a^2 + a + 4.

Eliminate the quadratic term by substituting x = a + 1/6:

23/6 + (x - 1/6)^2 + 2 (x - 1/6)^3 + x = 0

Hint: | Write the cubic polynomial on the left-hand side in standard form.

Expand out terms of the left hand side:

2 x^3 + (5 x)/6 + 104/27 = 0

Hint: | Write the cubic equation in standard form.

Divide both sides by 2:

x^3 + (5 x)/12 + 52/27 = 0

Hint: | Perform the substitution x = y + λ/y.

Change coordinates by substituting x = y + λ/y, where λ is a constant value that will be determined later:

52/27 + 5/12 (y + λ/y) + (y + λ/y)^3 = 0

Hint: | Transform the rational equation into a polynomial equation.

Multiply both sides by y^3 and collect in terms of y:

y^6 + y^4 (3 λ + 5/12) + (52 y^3)/27 + y^2 (3 λ^2 + (5 λ)/12) + λ^3 = 0

Hint: | Find an appropriate value for λ in order to make the coefficients of y^2 and y^4 both zero.

Substitute λ = -5/36 and then z = y^3, yielding a quadratic equation in the variable z:

z^2 + (52 z)/27 - 125/46656 = 0

Hint: | Solve for z.

Find the positive solution to the quadratic equation:

z = 1/216 (3 sqrt(4821) - 208)

Hint: | Perform back substitution on z = 1/216 (3 sqrt(4821) - 208).

Substitute back for z = y^3:

y^3 = 1/216 (3 sqrt(4821) - 208)

Hint: | Take the cube root of both sides.

Taking cube roots gives 1/6 (3 sqrt(4821) - 208)^(1/3) times the third roots of unity:

y = 1/6 (3 sqrt(4821) - 208)^(1/3) or y = -1/6 (208 - 3 sqrt(4821))^(1/3) or y = 1/6 (-1)^(2/3) (3 sqrt(4821) - 208)^(1/3)

Hint: | Perform back substitution with x = y - 5/(36 y).

Substitute each value of y into x = y - 5/(36 y):

x = 1/6 (3 sqrt(4821) - 208)^(1/3) - 5/(6 (3 sqrt(4821) - 208)^(1/3)) or x = -1/6 (208 - 3 sqrt(4821))^(1/3) - (5 (-1)^(2/3))/(6 (3 sqrt(4821) - 208)^(1/3)) or x = 5/6 ((-1)/(3 sqrt(4821) - 208))^(1/3) + 1/6 (-1)^(2/3) (3 sqrt(4821) - 208)^(1/3)

Hint: | Simplify each solution.

Bring each solution to a common denominator and simplify:

x = ((3 sqrt(4821) - 208)^(2/3) - 5)/(6 (3 sqrt(4821) - 208)^(1/3)) or x = -1/6 (208 - 3 sqrt(4821))^(1/3) - (5 (-1)^(2/3))/(6 (3 sqrt(4821) - 208)^(1/3)) or x = 1/6 (5 ((-1)/(3 sqrt(4821) - 208))^(1/3) + (-1)^(2/3) (3 sqrt(4821) - 208)^(1/3))

Hint: | Perform back substitution on the three roots.

Substitute back for a = x - 1/6:

Answer: a = ((3 sqrt(4821) - 208)^(2/3) - 5)/(6 (3 sqrt(4821) - 208)^(1/3)) - 1/6 or a = -1/6 - 1/6 (208 - 3 sqrt(4821))^(1/3) - (5 (-1)^(2/3))/(6 (3 sqrt(4821) - 208)^(1/3)) or a = 1/6 (5 (-1/(3 sqrt(4821) - 208))^(1/3) + (-1)^(2/3) (3 sqrt(4821) - 208)^(1/3)) - 1/6

Answer: +2

Step-by-step explanation: :)

===============================================

Explanation:

Subtract the second equation from the first one

[tex]\ \ \ \ 3x+3y-5z = 4 \ \ ... \text{ eq 1}\\-(4x-4y+z = -1) \ \ ... \text{ eq 2}\\---------\\\ \ -x+7y-6z = 5[/tex]

Let's call that result equation 4.

Now focus on equation 3 and equation 4

equation 3 is   -x+7y-6z = 2

equation 4 is   -x+7y-6z = 5

Note how the left hand sides are identical, but the right hand sides are different. This means that we have an inconsistent system with no solutions. No matter what numbers we pick for x,y,z, there is no way to make all three given original equations to be true.

Answer:

y=4/5x-2

Step-by-step explanation:

Answer:

1000000

Step-by-step explanation:

Answer:

y= -3x + 20

Step-by-step explanation:

just graph it out

Answer: none

Step-by-step explanation:

Answer:

200 / 69% is 289.855072464

Answer:

A. True

Step-by-step explanation:

A. P. E. X. Just took the quiz.

Answer:

Step-by-step explanation:

it is true

Answer: aₙ = -12 + 4*n

Step-by-step explanation:

We know that:

a₃ = 0

a₄ = 4

a₅ = 8

a₆ = 12

a₇ = 16

This seems to be an arithmetic sequence.

To test this, we need to calculate the difference between any two consecutive terms in the sequence, and this must be a constant for any pair that we choose.

a₄ - a₃ = 4 - 0 = 4

a₅ - a₄ = 8 - 4 = 4

a₆ - a₅ = 12 - 8 = 4

etc

we can conclude that this is an arithmetic sequence.

The n-th term in an arithmetic sequence, where the increase between consecutive terms is 4, is:

aₙ = aₙ₋₁ + 4.

Another way is:

aₙ = a₀ + n*4.

Where to find a₀, we can start with the value that we know and go back:

a₂ = a₃ - 4 = -4

a₁ = a₂ - 4 = -8

a₀ = a₁ - 4 = -12

Then the n-th term can be written as:

aₙ = -12 + 4*n

Answer:

12x + y = 16

Step-by-step explanation:

Standard Form: Ax + By = C

Step 1: Write point-slope form

y + 4 = -12(x - 1)

Step 2: Find slope-intercept form

y + 4 = -12x + 12

y = -12x + 16

Step 3: Find standard form

12x + y = 16

Answer:

y=-20x+20

Step-by-step explanation:

Answer:

if your solving for a its a=10b/9

Step-by-step explanation:

Answer:

A. Going public  should be the answer!

Let me know if thats right or not!

Answer:

When a company can secure an additional capital without going into debt the best and suitable answer is Going public.

Answer: 1. Function 2. Not a function 3. Not a function

Step-by-step explanation:

( this is an guess so don’t judge much)

Answer: a and b are functions c is not a function

Step-by-step explanation:

I’m smart

Answer: i think it would be 5

[tex]\sqrt{x} \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \\[/tex]

Answer:

354 feet below sea level

Step-by-step explanation:

Subtract 23 from  215, then add 119

Answer:

B

Step-by-step explanation:

The equivalent expression to - 11/4 is, - (-11/-4).

Option B is true.

A fraction is a part of whole number, and a way to split up a number into equal parts. Or, A number which is expressed as a quotient is called fraction. It can be written as the form of p : q, which is equivalent to p / q.

Given that;

The fraction is,

⇒ - 11/4

Now, By option B;

The number is,

⇒ - (- 11/ - 4)

Multiply by - 1 in denominator and numerator,

⇒ - (- 1 × - 11 / - 1 × - 4)

⇒ -  (11/4)

⇒ - 11/4

Thus, The equivalent expression is, - (-11/-4).

Learn more about the fraction visit:

https://brainly.com/question/5454147

#SPJ2

The complete question is this,

Which of the following expression are equivalent to -11/4?

A) - (11/ - 4)

B) - (-11/-4)

C) None of these

Answer:

The answer is 2.

Step-by-step explanation:

2 appears three times while the others appear only twice

Answer:

0.6778 to 4 dec. places.

Step-by-step explanation:

That is  387 / (184+387)

= 387 / 571

= 0.677758

Answer:

The answer is x = 0

Step-by-step explanation:

-7x - 8 = x - 8(1-5x)

Simplify and FOIL.

-7x - 8 = x - 8 + 40x

-7x - 8 = 41x - 8

Add 7x to both sides.

-8 = 48x - 8

Add 8 to both sides.

0 = 48x

x can only be 0 to multiply it by any other number and get 0.

x = 0

Answer:

Haha

Step-by-step explanation:

Answer:

The oval

Step-by-step explanation: A function must pass the vertical line test.

Answer:

The third one (oval)

Step-by-step explanation:

To see if something is a function or not, you do the vertical line test. So just draw lines vertically over the x-values. If an x-value has more than one y-value then it is not a function. It is a relation.

 [tex]\bold{Hello!}\\\bold{Your~Answer~Is~Below!}[/tex]

______________________________

 [tex]\bold{Solution~Steps:}[/tex]

[tex]1.)~Combine~8s~and~-4s:[/tex]

[tex]2.)~Subtract~7s~from~both~sides:[/tex]

[tex]3.)~Subtract~15~from~both~sides:[/tex]

[tex]4.)~Divide~both~sides~by~-3:[/tex]

______________________________

 [tex]\bold{Answer:}[/tex]

______________________________

 [tex]\bold{Hope~this~helps,}\\\bold{And~best~of~luck!}\\\\\bold{~~~~~~~-TotallyNotTrillex}[/tex]