PLEASE FAST IF YOU DO THANK You SO MUCH

Answer:

Kindly check explanation

Step-by-step explanation:

Given The samples:

X = 10.2, 9.7, 10.1, 10.3, 10.1, 10.3, 10.1, 9.8, 9.9, 10.4, 10.3, 10.5,11.2,11.3, 9.8

Using a calculator ;

Sample mean, xbar = 10.27

Sample standard deviation, s = 0.462

H0 : μ = 15

H1 : μ < 15

The test statistic :

(xbar - μ) ÷ (s/sqrt(n))

(10.27 - 15) / (0.462/sqrt(15))

-4.73 / 0.1192878

= - 39.65

Using the Pvalue form Tscore, calculator, df = 14

Pvalue = 0.000001,

Since, Pvalue < α ; then we reject the Null

Confidence interval :

Xbar ± Margin of error

Margin of Error = Tcritical * s/√n

TCritical at 95%, df = 14

Margin of Error = 2.145 * 0.462/sqrt(15) = 0.2559

Lower boundary :

10.27 - 0.2559 = 10.0141

Upper boundary :

10.27 + 0.2559 = 10.5259

(10.0141 ; 10.5259)

The true population means should reside within the interval

Answer:

120

Step-by-step explanation:

120

every other number is in the 70s

Step-by-step explanation:

the true statement is:

every term in pattern B is 2 times the corresponding term in pattern A

Answer:

Step-by-step explanation:

Pattern A

Pattern B

Statements:

Every term in Pattern B is 10 more than the corresponding term in Pattern A.

Every term in Pattern B is 2 times the corresponding term in Pattern A.

Every term in Pattern B is 12 the corresponding term in Pattern A.

Every term in Pattern B is 10 times the corresponding term in Pattern A.

Answer:

Value of x =  15.1 unit (Approx.)

Step-by-step explanation:

Given:

For angle 54°

Base of triangle = 11 unit

Perpendicular of triangle = x unit

Find:

Value of x

Computation:

Using trigonometry function;

Tanθ = Perpendicular / Base

Tan 54 = Perpendicular of triangle / Base of triangle

Tan 54 = x / 11

1.376 = x / 11

Value of x = 1.376 × 11

Value of x = 15.136

Value of x =  15.1 unit (Approx.)

Step-by-step explanation: This simple confidence interval calculator uses a Z statistic and sample mean (M) to generate an interval estimate of a population mean (μ).

Note: You should only use this calculator if (a) your sample size is 30 or greater; and/or (b) you know the population standard deviation (σ), and use this instead of your sample's standard deviation (an unusual situation). If your data does not meet these requirements, consider using the t statistic to generate a confidence interval.

where:

M = sample mean

Z = Z statistic determined by confidence level

sM = standard error = √(s2/n)

As you can see, to perform this calculation you need to know your sample mean, the number of items in your sample, and your sample's standard deviation (or population's standard deviation if your sample size is smaller than 30). (If you need to calculate mean and standard deviation from a set of raw scores, you can do so using our descriptive statistics tools.)

Answer:

nAnI

Step-by-step explanation:

Step-by-step explanation:

Math is hard.....

and I don't like it anymore

Question

If Johnathon has work 16 hours a day from 8am to 12pm, and he has to drive from point a to b, which the distance is 3600 miles. His car can drive for 700 miles on a full tank of gas, which 1 gallon is 28 miles. What is the amount of stops and gallons of gas to get to point a and b?

Step-by-step explanation:

We'll first need to determine what the composite function f(g(x)) is equal to.

Start with the outer function f(x). Then replace every copy of x with g(x). Afterward, plug in g(x) = 3x-2

So we get the following:

[tex]f(x) = \sqrt{x^2-4}\\\\f(g(x)) = \sqrt{(g(x))^2-4}\\\\f(g(x)) = \sqrt{(3x-2)^2-4}\\\\f(g(x)) = \sqrt{9x^2-12x+4-4}\\\\f(g(x)) = \sqrt{9x^2-12x}\\\\[/tex]

Next, we apply the derivative

[tex]f(g(x)) = \sqrt{9x^2-12x}\\\\f(g(x)) = (9x^2-12x)^{1/2}\\\\f'(g(x)) = \frac{1}{2}(9x^2-12x)^{-1/2}*\frac{d}{dx}(9x^2-12x)\\\\f'(g(x)) = \frac{1}{2}(9x^2-12x)^{-1/2}*(18x-12)\\\\f'(g(x)) = \frac{9x-6}{\sqrt{9x^2-12x}}\\\\[/tex]

Don't forget about the chain rule. The chain rule is applied in step 3 of that block of steps shown above.

The last thing we do is plug in x = 3 and simplify.

[tex]f'(g(x)) = \frac{9x-6}{\sqrt{9x^2-12x}}\\\\f'(g(3)) = \frac{9*3-6}{\sqrt{9*3^2-12*3}}\\\\f'(g(3)) = \frac{21}{\sqrt{45}}\\\\f'(g(3)) = \frac{21}{\sqrt{9*5}}\\\\f'(g(3)) = \frac{21}{\sqrt{9}*\sqrt{5}}\\\\f'(g(3)) = \frac{21}{3*\sqrt{5}}\\\\f'(g(3)) = \frac{7}{\sqrt{5}}\\\\[/tex]

Side note: if you choose to rationalize the denominator, then you'll multiply both top and bottom by sqrt(5) to end up with [tex]f'(g(3)) = \frac{7\sqrt{5}}{5}\\\\[/tex]; however, your teacher has chosen not to rationalize the denominator.

9514 1404 393

Answer:

  (x, y) = (12, -1)

Step-by-step explanation:

I find the simplest solution is often found using a graphing calculator.

  (x, y) = (12, -1)

__

We notice that the coefficients of x are identical, so we can eliminate x by subtracting the first equation from the second.

  (x +3y) -(x -2y) = (9) -(14)

  5y = -5 . . . . simplify

  y = -1 . . . . . divide by 5

  x = 14 +2y = 14 +2(-1) . . . . using the first equation to find x

  x = 12

Answer:

sin

Step-by-step explanation:

take 34 degree as reference angle

usinf sin rule

sin 34=opposite/hypotenuse

0.55=16/x

x=16/0.55

x=29.09

x=29.1

Answer:

The responses to these question can be defined as follows:

Step-by-step explanation:

[tex]n = 16\\\\ \bar{x}= 73.7\\\\\sigma = 12\\\\a = 0.05\ or\ a = 0.10\\\\H_{o} \ : \mu = 68\\\\H_{a} \ : \mu \neq 68\\\\a = 0.05\\\\[/tex]

critical values [tex]=\pm t0.025,15 = \pm 2.131\\\\[/tex]

[tex](n-1) = 15^{\circ}\\\\a = 0.10\\\\[/tex]

critical values[tex]= \pm t0.05,15 = \pm 1.753\\\\[/tex]

[tex](n-1) = 15^{\circ}\\\\[/tex]

Testing the statistic values:

[tex]t = \frac{x-\mu_{0}}{ \frac{s}{\sqrt{n}}}\\\\[/tex]

  [tex]= \frac{73.7-68}{(\frac{12}{\sqrt{16}})}\\\\\ = \frac{5.7}{(\frac{12}{4})}\\\\ = \frac{5.7}{(3)}\\\\ = 1.9\\[/tex]

Test statistic ta [tex]= -1.90\ lies[/tex]

The critical values[tex]\pm t_{0.05,15} =\pm 1.753[/tex]

It is in the region of dismissal. We dismiss the 10% significant null hypothesis.

[tex]t_a = 1.90 \\\\df = 15\\\\a = 0.05\\\\p-value = 076831\\\\[/tex]

P - value is greater than the level of significance a= 0.05  

Null hypothesis we don't reject. At a 95% level, the claim is justified.

[tex]t_a = 1.90\\\\ df = 15\\\\ a = 0.10\\\\p-value = 076831\\\\[/tex]

P - value below the meaning level a = 0.10, we reject the hypothesis null. At a level of 90% the claim is not justified.

Answer:

x= 1.2  or  6/5

Step-by-step explanation:

Answer:

6/5 or 1.2 or 1 1/5

Step-by-step explanation:

but 6/5 is the exact answer

Answer:

Step-by-step explanation:

In the first part, we are given the function:

[tex]\int \dfrac{x^6}{\sqrt{1+x}^2} \ dx[/tex]

Suppose we make x = tan θ

Then dx = sec² θ.dθ

[tex]= \int \dfrac{tan^6 (\theta)}{\sqrt{1+ tan ^2 \theta }}* dx[/tex]

[tex]= \int \dfrac{tan^6 (\theta)}{\sqrt{1+ tan ^2 \theta }}* sec ^2 (\theta) * d\theta[/tex]

Since; sec² θ - tan² θ = 1

sec² θ = 1+ tan² θ

[tex]sec \ \theta = \sqrt{1 + tan^2 \ \theta}[/tex]

∴

[tex]= \int \dfrac{tan^6 (\theta)}{sec \ \theta}* sec ^2 (\theta) * d\theta[/tex]

[tex]= \int tan^6 (\theta)* sec (\theta) * d\theta[/tex]

Thus; In the first part, Use x = tan θ, where  [tex]- \dfrac{\pi}{2} < \theta <\dfrac{\pi}{2}[/tex], since the integrand comprise the expression [tex]\sqrt{1+x^2}[/tex]

From the second part by using substitution method;

[tex]\int \dfrac{x^6}{\sqrt{1+x^2}} \ dx = \int \mathbf{tan^6(\theta) * sec ( \theta) } \ d \theta[/tex]

Answer:

-3/5

Step-by-step explanation:

Not sure.....................

Answer:15 heads out of 30 is the most likely outcome when flipping 30 coins, if you run the same calculation with 14 or 16 heads you will get two equal, but smaller probabilities, same with 13 and 17 heads, and so on.

Step-by-step explanation:

Answer:

C. 16 inch 3

Step-by-step explanation:

Answer: The answer is 15 gallons. Hope this helped!

Step-by-step explanation:

Answer:

the answer is a, d, e

Step-by-step explanation:

the product of 18 and a number is 109.8=

18n=109.8

to find n, you need to divided by 109.8 by 18. You will get 6.1

To check, replace c with 6.1.

18x6.1=109.8

Answer:

ade

Step-by-step explanation:

Answer:

0.825

Step-by-step explanation:

To convert to lowest form, you have to shift the decimal place 2 places to the left.

Answer:

www.numerade.com/questions/the-average-monthly-cell-phone-bill-was-reported-to-be-5007-by-the-us-wireless-industry-random-sampl/

Step-by-step explanation:

Answer:

5^2x ÷ 5^-3 = 5⁵(5×5×5×5×5)

5^2x ÷ 1/5³(5×5×5) = 3125

5^2x ÷ 1/125 = 3125

5^2 × 4 = 3125

125

5⁸(5×5×5×5×5×5×5×5) = 3125

125

390625 = 3125

125

so the value X is = 4

Answer:

0

Step-by-step explanation:

It is zero because Madison friends were not specified(number)

Answer:

We can't see it all that well sorry.

Step-by-step explanation:

Answer:

See picture

Step-by-step explanation:

Answer:

n = 78

Step-by-step explanation:

hope that helped!

Answer:

The calculated value  |Z| = |-2.5| >2.326 at 0.05 level of significance

The alternative hypothesis is accepted at a 0.05 level of significance

The manager of  Publix in Clemson believes 64% is too high for his own store

Step-by-step explanation:

Step:-1

Given that the consumer Reports showed that 64% of supermarket shoppers.

Given that the population proportion

                                 P = 0.64

Given that random sample size 'n' = 100

Given that 52 believe the supermarket brands were as good as the national brands.

sample proportion

                          [tex]p^{-} = \frac{x}{n} = \frac{52}{100} = 0.52[/tex]

Step:-2

Null hypothesis: The manager of the Publix in Clemson believes 64% is too low for his own store

μ < 0.64

Alternative Hypothesis:H₁:μ > 0.64

Test statistic

               [tex]Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }[/tex]

               [tex]Z = \frac{0.52-0.64}{\sqrt{\frac{0.64 X 0.36}{100} } }[/tex]

              Z =  -2.5

Level of significance = 0.05

Z₀.₀₅ = 2.326

The calculated value  |Z| = |-2.5| >2.326 at 0.05 level of significance

Final answer:-

The null hypothesis is rejected at a 0.05 level of significance

The alternative hypothesis is accepted at a 0.05 level of significance