Please discuss what you consider to be some of the biggest challenges your company will face when working from the Linux command line. Discuss some of the different ways in which employees might be able to remember and associate commands with common tasks.

Answer:

In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets. It might go a week or longer between charges if you only use the tablet once or twice each day.

Many people find that charging merely 80% is ineffective. Your phone won't function if you fully charge it and then use it in a single day. The 40-80% rule applies if, like me, your daily usage is limited to 25–50%.

The typical runtime of a tablet is between three and ten hours. More charge is typically needed for less expensive models than for more expensive tablets.                          

Therefore, In my opinion I would spend my money on a pc, tablets are of no use anymore besides having a larger screen, nowadays you either have a phone or a computer.

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Answer:

c. Purging

Explanation:

Based on the information provided it can be said that the best method for sanitizing the data would be Purging. This is a process that permanently erases the data from a specific storage unit. Doing so prevents data from being recovered by an expert and also frees up storage and memory space to be used for other information. Since it is very inexpensive and provides the best overall results this would be the best option in this scenario.

Answer:

True

Explanation:

Solution

ZigBee uses unlicensed frequency bands but operate at slower speed or data rates.

ZigBee: This communication is particular designed for control and sensor networks on IEEE 802.15.4 requirement for wireless personal area networks (WPANs), and it is a outcome from Zigbee alliance.

This communication level defines physical and  (MAC) which is refereed to as the Media Access Control layers to manage many devices at low-data rates.

Answer:

Car insurance

Explanation:

they are machines with ai

Answer:

I have updated answer in google

Explanation:

please chek it. I hope it will nice

Answer:

Bulk Ethernet Cable - Category 5e or CAT5e

Bulk RJ45 Crimpable Connectors for CAT-5e

Explanation:

Answer:

She removed the complex blue background and added artistic effects.

Explanation:

This is the best answer because both aspects are correct. If Megan were to "Crop" the backgrounds the shape would have changed and she would not have been able to get the whole background without cropping some of the flowers out. Therefore it is not A or C. The pictured change is most definitely artistic effects. So D is the best option.

Answer:

She removed the complex blue background and added artistic effects.

Explanation:

on edg

Answer:

Following are the description of the given points:

Explanation:

A) The Multiple greedy approaches could exist, which could be to reach for the closest emergency diamond, and yet clearly we are going to miss some very essential routes in that case. So, it can make every argument quickly, and seek to demonstrate a reference case for that.

B) An approach to the evolutionary algorithm and its users are going to just have states M x N. But each state (i, j) indicates the absolute difference between the amount of the selected diamond and the amounts of the costs incurred.

DP(i, j) = DimondVal(i, j) + max ((DP(i, j-1)-2), (DP(i-1,j-1)-3))

DP(i, j) is a description of the state.

DimondVal(i, j) is the diamond value at (i j), 0 if there is no diamond available.

This states must calculate the states of M N  and it involves continuous-time for each State to determine. Therefore the amount of time of such an algo is going to be O(MN).

Answer:

The tokens are:

January

space

1

,

space

2008

Explanation:

StringTokenizer class is basically used to break a string into tokens. The string consists of numbers, letters, quotation marks commas etc,

For example if the string is "My name is ABC" then StringTokenizer will break this string to following tokens:

My

name

is

ABC

So in the above example, the string is "January 1, 2008". It contains January with a space, then 1, then a comma, then 2008

The last comma and true in the statement do not belong to the string. They are the parameters of the StringTokenizer constructor i.e.

StringTokenizer(String str, String delim, boolean flag)

So according to the above constructor str= "January 1, 2008"

String delim is ,

boolean flag = true

So  the StringTokenizer strToken = new StringTokenizer("January 1, 2008", ", ", true); statement has:

a string January 1, 2008

a delim comma with a space (, ) which is used to tokenize  the string "January 1, 2008".

boolean flag set to true which means the delim i.e. (, ) is also considered to be a token in the string. This means the comma and space are considered to be tokens in the given string January 1, 2008.

Hence the output is January space 1 comma space 2008.

Check the attached image to see the output of the following statement.

Answer:

The program written in Python is as follows

nums = []

for i in range(0,68):

-->nums.append(i)

print(nums)

Explanation:

Please note that --> is used to denote indentation

The first line creates an empty list

nums = []

This line creates an iteration from 0 to 67, using iterating variable i

for i in range(0,68):

This line saves the current value of variable i into the empty list

nums.append(i)

At this point, the list has been completely filled with 0 to 67

This line prints the list

print(nums)

Answer:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Explanation:

The method to generate the binary number from a decimal is :

Keep on dividing the number by 2 and keep on tracking the remainder

And the quotient is again divided and remainder is tracked so that the number is completely divided.

And then write the binary digits from bottom to top.

Please have a look at the method in below examples:

A) 35

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 35 & 1 \\ 2 & 17 & 1 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1\end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary number is 100011

B) 3

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 3 & 1 \\ 2 & 1 & 1 \\ \end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 11.

C) 27

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 27 & 1 \\ 2 & 13 & 1 \\ 2 & 6 & 0 \\ 2 & 3 & 1 \\ 2 & 1 & 1 \end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 11011.

D) 16

[tex]\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 16 & 0 \\ 2 & 8 & 0 \\ 2 & 4 & 0 \\ 2 & 2 & 0 \\ 2 & 1 & 1 \\\end{tabular}\end{center}[/tex]

Writing the remainder from bottom to top.

So, binary equivalent is 10000.

Answers are:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Answer:

Internet backbone

Explanation:

The internet backbone is made up of multiple networks from multiple users. It is the central data route between interconnected computer networks and core routers of the Internet on the large scale. This backbone does not have a unique central control or policies, and is hosted by big government, research and academic institutes, commercial organisations etc. Although it is governed by the principle of settlement-free peering, in which providers privately negotiate interconnection agreements, moves have been made to ensure that no particular internet backbone provider grows too large as to dominate the backbone market.

Answer:

one disk

Explanation:

RAID 5:is an  independent disks configuration of redundant array that utilizes disk striping in addition to parity. Data and parity bits are striped uniformly across the entire the disks configuration, so that no any single disk can create a bottleneck.  

"Today one disk has failed in this RAID. How many disks do you replace"

Since RAID 5 guard against data through implementation of stripping of both data and parity bits, the failed disk can be replaced to restore the company's RAID 5 array fully back into service.

Answer: YES

Explanation:

int year=2019;

int yearNext=2020;

 int &ref=year;

&ref=yearNext; {This line leads to error as references cannot be reassigned}

(//compilation error: lvalue required as left operand of assignment

) lvalue(&ref) is not something which can be assigned.

To get this better, here are the difference between pointers and reference variables

Pointers

Pointers can be incremented

Array can be formed with pointers

Pointers can be reassigned

Pointer can be declared as void  

Reference variable

References cannot be incremented

Array cannot be formed with references

References cannot be reassigned as references shares the address of the variable its assigned

References can never be void

Answer:

Following are the code to this question:

#include <stdio.h> //defining header file

#include <string.h>//defining header file

int main()//defining main method

{

char name[50]; //defining character variable

int A=0,E=0,I=0,O=0,U=0,value=0,i,l; //defining integer variables

printf("Enter string value: ");//print message

gets(name);//input value by gets method

l=strlen(name);//defining l variable to store string length

for(i=0; i<50; i++) //defining loop to count vowels value

{

if(name[i] == 'A' || name[i] == 'a') //defining if condition count A value A++;//increment value by 1

else if(name[i] == 'E' || name[i] == 'e')//defining else if condition count E value

E++;//increment value by 1

else if(name[i] == 'I' || name[i] == 'i') //defining else if condition count I value

I++;//increment value by 1

else if(name[i] == 'O' || name[i]== 'o') //defining else if condition count O value

O++;//increment value by 1

else if(name[i] == 'U' || name[i] == 'u')//defining else if condition count U value

U++;//increment value by 1

else if(name[i]>= '0' && name[i] <= '9')//defining else if condition count digits value

value++;//increment value by 1 }

printf("A: %d\n",A);//print A value

printf("E: %d\n",E); //print E value

printf("I: %d\n",I);//print I value

printf("O: %d\n",O);//print O value

printf("U: %d\n",U);//print U value

printf("value: %d",value);//print digits value

return 0;

}

Output:

please find the attachment.

Explanation:

If my computer has 4 gigabytes of ram memory then I have 4e+9 bytes of memory.  I think-

Answer: That isn't a software problem, its a hardware problem. There is a difference between 12gb of ram versus 100 gb of HDD. Ram is temporary storage, you can not turn SSD or HDD storage into RAM. If you are a gamer, STEER AWAY FROM LAPTOPS, DO NOT BUY A GAMING LAPTOP. Either buy a DESKTOP (or build) or a console. They give more performance for the price and they are easily upgradable. Not many people can open up a laptop and put in more RAM because the hardware is incredibly small.

Answer:

def random_marks(apostrophe, quotation, apostrophe_quotation):

   return "'"*apostrophe + "\""*quotation + "'\""*apostrophe_quotation

print(random_marks(3, 2, 3))

Explanation:

Create a function called random_marks that takes apostrophe, quotation, and apostrophe_quotation as parameters. Inside the function, return apostrophe sign times apostrophe plus quotation mark times quotation plus apostrophe sign quotation mark times apostrophe_quotation.

Note that plus sign (+) is used to concatenate strings. Also, if you multiply a string with a number, you get that number of strings ("#"*3 gives ###).

Then, call the function with given parameters and print

Answer:

Linked lists and arrays are both linear data structures but while an array is a collection of items that can be accessed randomly, a linked list can be accessed sequentially.

A sparse matrix contains very few non-zero elements. For example;

_                        _

|  0   0   3  0  6    |

|   0   5   0  0  4   |

|   2   0   0  0  0   |

|_ 0   0   0  0  0 _|

In the implementation of a sparse matrix, the following are some of the pros and cons of using a linked list over an array;

PROS

i.  Linked lists are dynamic in nature and are readily flexible - they can expand and contract without having to allocate and/or de-allocated memory compared to an array where an initial size might need to be set and controlled almost manually. This makes it easy to store and remove elements from the sparse matrix.

ii. No memory wastage. Since the size of a linked list can grow or shrink at run time, there's no memory wastage as it adjusts depending on the number of items it wants to store. This is in contrast with arrays where you might have unallocated slots. Also, because the zeros of the sparse matrix need not be stored when using linked lists, memory is greatly conserved.

CONS

i. One of the biggest cons of linked lists is the difficulty in traversing items. With arrays, this is just of an order of 0(1) since the only requirement is the index of the item. With linked lists, traversal is sequential which means slow access time.

ii. Storage is another bottle neck when using linked lists in sparse matrix implementation. Each node item in a linked list contains other information that needs to be stored alongside the value such as the pointer to the next or previous item.

Answer:

No

Explanation:

The other websites provide very detailed information, when you search the same information that is mentioned at CDC website. The information related to causes and symptoms of brain injuries is similar on both the websites. The reliability of information provided on other websites is questioned. These websites provide a lot of information and it is sometimes time consuming to find the relevant information.

Answer:

Here is the C++ program for Employee class with fields id,name and sal.

#include <iostream>  // to use input output functions

#include <string>  //to manipulate and use strings

using namespace std;   // to access objects like cin cout

class Employee {  //class Employee

private:  

/* the following data members are declared as private which means they can only be accessed by the functions within Employee class */

  string name;  //name field

  int id; //id field

  double sal;   //salary field

public:    

  Employee();  // constructor that initializes an object when it is created

/* setName, setID and setSalary are the mutators which are the methods used to change data members. This means they set the values of a private fields i.e. name, id and sal */

  void setName(string n)  //mutator for name field

     { name = n; }        

  void setId(int i)  //mutator for id field

     { id = i; }        

  void setSalary(double d)  //mutator for sal field

     { sal = d; }  

/* getName, getID and getSalary are the accessors which are the methods used to read data members. This means they get or access the values of a private fields i.e. name, id and sal */

  string getName()  //accessor for name field

     { return name; }        

  int getId()  //accessor for id field

     { return id; }        

  double getSalary()  //accessor for sal field

     { return sal; }  };  

Employee::Employee() {  //default constructor where the fields are initialized

  name = "";  // name field initialized

  id = 0;  // id field initialized to 0

  sal = 0;   }   // sal field initialized to 0

void display(Employee);  

// prototype of the method display() to display the data of Employee

int main() {  //start of the main() function body

  Employee emp;  //creates an object emp of Employee class

/*set the name field to Abc Xyz which means set the value of Employee class name field to Abc Xyz  through setName() method and object emp */

  emp.setName("Abc Xyz");  

/*set the id field to 1234 which means set the value of Employee class id field to 1234  through setId() method and object emp */

  emp.setId(1234);

/*set the sal field to 1000 which means set the value of Employee class sal field to 1000  through setSalary() method and object emp */

  emp.setSalary(1000);    

  display(emp);  }   //calls display() method to display the Employee data

void display(Employee e) {  // this method displays the data in the Employee //class object passed as a parameter.

/*displays the name of the Employee . This name is read or accessed through accessor method getName() and object e of Employee class */

  cout << "Name: " << e.getName() << endl;  

/*displays the id of the Employee . This id is read or accessed by accessor method getId() and object e */

  cout << "ID: " << e.getId() << endl;

/*displays the salary of the Employee . This sal field is read or accessed by accessor method getSalary() and object e */

  cout << "Salary: " << e.getSalary() << endl;  }

Explanation:

The program is well explained in the comments mentioned with each statement of the program.

The program has a class Employee which has private data members id, name and sal, a simple default constructor Employee(), mutatator methods setName, setId and setSalary to set the fields, acccessor method getName, getId and getSalary to get the fields values.

A function display( ) is used to display the Employee data i.e. name id and salary of Employee.

main() has an object emp of Employee class in order to use data fields and access functions defined in Employee class.

The output of the program is:

Name: Abc Xyz                                                                                                      

ID: 1234                                                                                                                  

Salary: 1000

The program and its output are attached.

Answer:

A. LCD power inverter

B. AC adapter

C. Battery

Answer:

1 (true)

Explanation:

10 == 10 is valid=> 10 >= 10 is valid => 10 >=(5*2) is valid

10 == 10 is valid=> 10 <= 10 is valid => 10 <=(5*2) is valid

=>  ((10 >= 5*2) and (10 <= 5*2)) is valid => Return 1 or True

Explanation:

Hardware virtualization refers to the creation of virtual (as opposed to concrete) versions of computers and operating systems. ... Hardware virtualization has many advantages because controlling virtual machines is much easier than controlling a physical server.

The name of the provision of services based around hardware visualization is called cloud computing

The cloud hypervisor is the software that is made use of during hardware visualization. The hypervisor does the function of managing hardware resources involving the customer and the service provider.

The work of hypervisor is that it manages the physical hardware resource which is shared between the customer and the provider.

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Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

The code for function calling is coded below.

To assign the maximum sum of `(numA, numB)` plus the maximum of `(numY, numZ)` to the variable `maxSum` using just one statement, you can call the `FindMax()` function twice in an expression.

Here's the code:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

This code calls the `FindMax()` function twice, once with the parameters `(numA, numB)` and again with the parameters `(numY, numZ)`.

It calculates the maximum of each pair of numbers using the `FindMax()` function and then adds the two maximum values together. The result is assigned to the `maxSum` variable.

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Answer:

The classification including its given topic has always been outlined in section through below justifications.

Explanation:

Answer:

public class TestImport{

   public static void main(String[] args) {

       String string1 = args[1];

       String string2 = args[2];

       System.out.println(string1 +" " +string2);

   }

}

Explanation:

The solution here is to use string concatenation as has been used in this statement System.out.println(string1 +" " +string2);

When this code is run from the command line and passed atleast three command line arguments for index 0,1,2 respectively, the print statment will return the second string (that is index1) and the third argument(that is index2) with a space in-between the two string.

Answer:

milespergallon = float(input())

dollarspergallon = float(input())

milestodrive = int(input())

trip_cost = milestodrive / milespergallon * dollarspergallon

print('Cost to drive {:d} miles at {:f} mpg at $ {:.2f}/gallon is: $ {:.2f}'.format(milestodrive, milespergallon, dollarspergallon, trip_cost))

Explanation:

Get the inputs from the user for milespergallon, dollarspergallon and milestodrive

Calculate the trip_cost, divide the milestodrive by milespergallon to get the amount of gallons used. Then, multiply the result by dollarspergallon.

Print the result as requested in the question

Answer:

def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):

  gallon_used = driven_miles / miles_per_gallon

  cost = gallon_used * dollars_per_gallon  

  return cost  

miles_per_gallon = float(input(""))

dollars_per_gallon = float(input(""))

cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)

cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)

cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)

print("%.2f" % cost1)

print("%.2f" % cost2)

print("%.2f" % cost3)

Explanation:

Answer:

Brainly is not meant to give paragraph answers to large questions.

In a computer (desktop)

There are 8-9 main components to a PC

Motherboard

CPU

GPU (for gamers)

RAM

SSD

HDD

PSU

Cooling fans (for AMD processors stock fans are included)

Case (some fans included)

I personally build my computers (desktops) as its cheaper and I won't have to pay a build fee.

Answer:

Adobe Photoshop To Manipulate The Photo.

Explanation:

BLACKPINKS new album is amazing OMG I LOVE Lovesick Girls!!!

Answer:

The function can return multiple values and the function can return an object

Explanation:

The advantage of returning a structure type from a function when compared to returning a fundamental type is that the function can return multiple values and also the function can return an object

A function in a structure can be passed to a function from any other function or from the main function itself and the definition of a structure can be seen in the function where it is found