PLEASE ANSWER THIS VERY FAST!! A gym membership costs $40 per month plus a one time sign up fee of $20. How many months would it take to spend $1000 for the gym membership? about 24 months or 2 years. about 12 months or 1 year. about 36 months or 3 years.

Answer:

Time = distance/speed

max distance = 380+10 = 390 m

Max Time = 390/3.9 = 100 s

Answer:

$850.7

Step-by-step explanation:

Penelope has $1459.75 in her account.

She pays different amount that are given above.

i.e.

=1459.75-200.25-359.45-125-299.35

=475.7

Then she deposit $375

Now,

=475.7+375

=850.7

So, She has $850.7 in her account after she pays her bills and makes deposits.

Answer:

$805.7 OwO

Step-by-step explanation:

Answer:

x ≥ -8/3

Step-by-step explanation:

=> [tex]\frac{3x+8}{x-4} \geq 0[/tex]

Multiplying both sides by (x-4)

=> 3x+8 ≥ 0

Subtracting 8 to both sides

=> 3x ≥ -8

Dividing both sides by 3

=> x ≥ -8/3

Answer:

[tex]x\le \:-\frac{8}{3}[/tex]

[tex]x>4[/tex]

Step-by-step explanation:

[tex]\frac{3x+8}{x-4}\ge \:0[/tex]

Multiply both sides by (x - 4).

[tex]\frac{3x+8}{x-4} (x-4) \ge \:0(x-4)[/tex]

[tex]3x+8\leq \:0[/tex]

[tex]3x+8-8\leq \:0-8[/tex]

[tex]3x \leq \:-8[/tex]

[tex]x\le \:-\frac{8}{3}[/tex]

Makes denominator equal to 0.

[tex]x-4=0[/tex]

[tex]x = 4[/tex]

[tex]-8/3 \leq x<4[/tex]  doesn't work in the original inequality.

[tex]x>4[/tex]  works in the original inequality.

Answer:

105.86 grams of AuCl3, if the compound has 6.3 x10^23 atoms of Cl.

Step-by-step explanation:

We are given that the compound has 6.3 x10^23 atoms of Cl.

To find how many molecules of AuCl3 are in the given compound, we divide the compound by 3, i.e;

[tex]\frac{6.3 \times 10^{23} }{3}[/tex]  =  [tex]2.1\times 10^{23}[/tex] molecules of AuCl3.

Now, as we know that 1 mole of AuCI3 has [tex]6.022 \times 10^{23}[/tex] molecules.

So, the moles that our compound has is given by;

      =  [tex]\frac{2.1 \times 10^{23} }{6.022 \times 10^{23} }[/tex]  = [tex]\frac{2.1}{6.022}[/tex]  = 0.349 mole AuCI3

Also, the molar mass of AuCI3 = 303.33 g/mole

So, the molar mass of 0.349 moles AuCI3 =  [tex]303.33 \times 0.349[/tex]

                                                                      =  105.86 g

Hence, 105.86 grams of AuCl3, if the compound has 6.3 x10^23 atoms of Cl.

Answer:

6, 10, 8 is the correct answer.

Step-by-step explanation:

Given that, the recursive function:

[tex]a_n=a_{n-1}-(a_{n-2}-4)[/tex]

6th term, [tex]a_{6} =0[/tex]

5th term, [tex]a_{5} =-2[/tex]

To find:

First three terms of the sequence = ?

Solution:

Putting n = 6 in the recursive function:

[tex]a_6=a_{5}-(a_{4}-4)\\\Rightarrow 0=-2-(a_{4}-4)\\\Rightarrow 2=-(a_{4}-4)\\\Rightarrow -2=(a_{4}-4)\\\Rightarrow -2+4=a_{4}\\\Rightarrow a_{4}=2[/tex]

Putting n = 5 in the recursive function:

[tex]a_5=a_{4}-(a_{3}-4)\\\Rightarrow -2=2-(a_{3}-4)\\\Rightarrow -2-2=-(a_{3}-4)\\\Rightarrow 4=(a_{3}-4)\\\Rightarrow a_{3}=8[/tex]

Putting n = 4 in the recursive function:

[tex]a_4=a_{3}-(a_{2}-4)\\\Rightarrow 2=8-(a_{2}-4)\\\Rightarrow 2-8=-(a_{2}-4)\\\Rightarrow 6=(a_{2}-4)\\\Rightarrow a_{2}=10[/tex]

Putting n = 3 in the recursive function:

[tex]a_3=a_{2}-(a_{1}-4)\\\Rightarrow 8=10-(a_{1}-4)\\\Rightarrow 8-10=-(a_{1}-4)\\\Rightarrow -2=-(a_{1}-4)\\\Rightarrow 2=a_{1}-4\\\Rightarrow a_{1}=4+2\\\Rightarrow a_{1}=6[/tex]

So, first, second and third terms are 6, 10, 8.

Answer:

3

Step-by-step explanation:

6/2

I hope this is right :)

Answer:

575 boxes

Step-by-step explanation:

Let the total number of boxes = x

The farmer already loaded [tex]\dfrac25[/tex] of the boxes onto the truck.

Therefore, the remainder [tex]=1-\dfrac25=\dfrac35[/tex]

Since he needed to load 345 more boxes of tomatoes onto the truck.

[tex]\dfrac35 \times x =345\\3x=345\times5\\x=(345\times5) \div 3\\x=575[/tex]

The farmer had 575 boxes of tomatoes to load altogether.

Answer:

19/40

Step-by-step explanation:

just divide the number of girls by the total number of students.

323/680 = 19/40 or 0.48

Answer:

I think the answer is it stretches the graph horizontally by a factor of 3.

Step-by-step explanation:

Answer: it stretches the graph horizontally by a factor of 3

Step-by-step explanation: I got it correct on a-pex

Anwer:3.537m

STEP BY STEP EXPLANATIOND:using SOH CAH TOA

First find the opposite

Represent the opposite with x

Tan 33° =x\10

x=10Tan 33°

x=6.494

To find m

Sin 33°=m\6.494 Sin 33°

m=3.5368

m=3.537meteres

Answer:

$6

Step-by-step explanation:

Tico’s taco truck is trying to determine the best price at which to sell tacos, the only item on the menu, to maximize profits. The taco trucks owner decided to adjust the price per taco and record data on the number of tacos sold each day with each new price. When the taco truck charges $4 for a taco, it sells an average of 60 tacos in one day. With every $1 increase in the price of a taco, the number of tacos sold per day decreases by 7.

The owner can calculate the daily revenue using the polynomial expression (-7x²+32x+240),

where x is the number of $1 increases in the taco price. In this activity, you’ll interpret and manipulate this expression and the scenario it represents.

x is number of $1 increments above the initial price of $4.  (x=0 means a price of $4, x=1 means a price of $5, etc.)

The revenue is -7x²+32x+240.  The average number of tacos sold is the revenue divided by the price.

For example, if x = 0, then the taco price is $4, the revenue is $240, and the number of tacos sold is 60.

If x = 1, then the taco price is $5, the revenue is $265, and the number of tacos sold is 53.

Each time x increases by 1, the number of tacos sold decreases by 7.

Continuing:

[tex]\left[\begin{array}{cccc}Value\ of\ x&Taco\ Price\ (\$)&Average\ Number\ of\ Tacos\ Sold&Daily\ Revenue\ (\$)\\0&4&60&240\\1&5&53&265\\2&6&46&276\\3&7&39&273\\4&8&32&256\\5&9&25&225\\6&10&18&180\end{array}\right][/tex]

The optimal price is $6.  At this price, the revenue is a maximum at $276.

Answer:  5.  P = (-4, 6)   R = (-4, -4)

               6. (a) a = 4, b = 3      (b) BC = 8     (c) B = (3, 4)

               7. (a) m = 4, n = 6     (b) PQ = (-2, 6)     (c) SR = (2, -6)

Step-by-step explanation:

5. The distance from Q (4, 0) to A (0, 3) is 4 left and up 3.

   So the distance from A to P is 4 left (0 - 4) and up 3 (3 + 3)

   --> P = (-4, 6)

    Similarly, the distance from Q (4, 0) to B (0, -2) is 4 left and down 2.

   So the distance from A to P is 4 left (0 - 4) and down 2 (-2 - 2)

   --> P = (-4, -4)

6. Follow the same steps as #5 (above) to get the following coordinates:

   A = (-3, 4)   B = (3, 4)

   D = (-3,-4)  C = (3, -4)

a) a = 4, b = 3

b) BC = 2(4) = 8

c) B = (3,4)

7. Follow the same steps as #5 (above) to get the following coordinates:

   P = (-4, 6)    Q = (0, 6)

   S = (0, -6)    R = (4, -6)

a) m = 4, n = 6

b) midpoint PQ = (-2, 6)

c) midpoint SR = (2, -6)

Answer:

151,200

Step-by-step explanation:

The possible set of numbers will be 151200  

A permutation is an arrangement of objects in a definite order.

Given that, John want to find his bicycle's number, so he decided to write down all the possible 6-digit numbers from 0 to 9.

Here, we will use permutation to find the possible numbers,

Formula =

ⁿPₓ = n! / (n-x)!

Therefore,

¹⁰P₆ = 10! / (10-6)!

= 10! / 4!

= 10 × 9 × 8 × 7 × 6 × 5 = 151200

Hence, the possible set of numbers will be 151200  

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Answer:

18.87 square cm.

Step-by-step explanation:

The area of the rectangle will be (4 + 4) * 4, since the length of the rectangle would be the diameter of the circle, and the width of the rectangle would be the radius. (4 + 4) * 4 = 8 * 4 = 32 square cm.

Then, we can calculate the area of the semicircle. The area of a circle is pi * r^2, so the area of a semicircle will be half of that. pi * (4^2) / 2 = pi * 16 / 2 = 8pi. 8 * 3.14159265 = 25.1327412 square cm.

The shaded area of the middle of the shape will then be 32 - 25.1327412 = 6.8672588 square cm.

The two triangles will have the same area. Their bases will be 14 minus the diameter of the circle, then divide that by 2 to get each separate base. 14 - 8 = 6 / 2 = 3. The heights of the triangles will be the radius of the circle, or 4 cm.

1/2 * 3 * 4 = 1/2 * 12 = 12/2 = 6. That is the area of one triangle, so the area of both triangles would be 6 * 2 = 12 square cm.

6.8672588 + 12 = 18.8672588, or 18.87 square cm.

Hope this helps!

Answer:

(44 - 8(pi)) cm^2    Exact area

18,9 cm^2    Approximate area

Step-by-step explanation:

The shaded area is the area of the trapezoid minus the area of the semicircle.

area of trapezoid = (b1 + b2)h/2

area of semicircle = (pi)(r^2)/2

The triangles at both sides are right triangles. Each of the horizontal legs has length (14 cm - 8 cm)/2 = 3 cm. Each of the vertical legs is congruent to the radius of the semicircle.

b1 = lower base = 14 cm

b2 = upper base = 14 cm - 3 cm - 3 cm = 8 cm

shaded area = (b1 + b2)h/2 - (pi)(r^2)/2

= (14 cm + 8 cm)(4 cm)/2 - (pi)(4 cm)^2 / 2

= 44 cm^2 - 8(pi) cm^2

= (44 - 8(pi)) cm^2    Exact area

= 18.9 cm^2    Approximate area

Answer: 536,000

Step-by-step explanation:

Answer:

536 000

Step-by-step explanation:

because it izz what it izz

Answer:

See bolded / underlined / italicized below -

Step-by-step explanation:

This is a great question!

If x were the length of this rectangle, then we could conclude the following,

2( 38 ) + 2( x ) > 692,

As you can see there is a greater than sign present, as the perimeter is at least 692 centimeters. In this case the perimeter is given to be at least 692 centimeters, but can also be calculated through double the width and double the length together. And of course we are given the width to be 38 cm -

2( 38 ) + 2x > 692,

76 + 2x > 692,

2x > 616,

x > 308

Solution = Length should be at least 308 cm

( The attachment below is not drawn to scale )

Answer:  [tex]a)\ \text{Vertex}:y=-\dfrac{3}{2}(x+1)^2+6[/tex]

                [tex]b)\ \text{Standard}:y=-\dfrac{3}{2}x^2-3x=\dfrac{9}{2}[/tex]

              c) Transformations: reflection over the x-axis,

                                               vertical stretch by a factor of 3/2,

                                               horizontal shift 1 unit to the left,

                                               vertical shift 6 units up

Step-by-step explanation:

Intercept form: y = a(x - p)(x - q)

Vertex form: y = a(x - h)² + k

Standard form: y = ax² + bx + c

We can see that the new vertex is (-1, 6). Use the Intercept form to find the vertical stretch: y = a(x - p)(x - q) where p, q are the intercepts.

p = -3, q = 1, (x, y) = (-1, 6)

a(-1 + 3)(-1 -1) = 6

       a (2)(-2) = 6

                a  = -6/4

                 a = -3/2

a) Input a = -3/2 and vertex (h, k) = (-1, 6) into the Vertex form to get:

[tex]y=-\dfrac{3}{2}(x+1)^2+6[/tex]

b) Input a = -3/2 into the Intercept form and expand to get the Standard form:

[tex]y=-\dfrac{3}{2}(x+3)(x-1)\\\\\\y=-\dfrac{3}{2}(x^2+2x-3)\\\\\\y=-\dfrac{3}{2}x^2-3x+\dfrac{9}{2}[/tex]

c) Use the Vertex form to identify the transformations:

[tex]y=-\dfrac{3}{2}(x+1)^2+6[/tex]

Hey there! :)

Answer:

x = -36.

Step-by-step explanation:

Starting with:

-1 = 5 + x/6

Begin by subtracting 5 from both sides:

-1 - 5 = 5 - 5 + x/6

-6 = x/6

Multiply both sides by 6:

-6 · 6 = x/6 · 6

-36 = x.

Answer:

x = -36

Step-by-step explanation:

- 1 = 5 + x/6

Subtract 5 on both sides.

-1 - 5 = x/6

-6 = x/6

Multiply both sides by 6.

-6 × 6 = x

-36 = x

Answer:

x = 1 , y = 7

Step-by-step explanation:

Solve the following system:

{y = 5 x + 2 | (equation 1)

3 x = 10 - y | (equation 2)

Express the system in standard form:

{-(5 x) + y = 2 | (equation 1)

3 x + y = 10 | (equation 2)

Add 3/5 × (equation 1) to equation 2:

{-(5 x) + y = 2 | (equation 1)

0 x+(8 y)/5 = 56/5 | (equation 2)

Multiply equation 2 by 5/8:

{-(5 x) + y = 2 | (equation 1)

0 x+y = 7 | (equation 2)

Subtract equation 2 from equation 1:

{-(5 x)+0 y = -5 | (equation 1)

0 x+y = 7 | (equation 2)

Divide equation 1 by -5:

{x+0 y = 1 | (equation 1)

0 x+y = 7 | (equation 2)

Collect results:

Answer: {x = 1 , y = 7

Answer:

D) (1,7)

Step-by-step explanation:

just took the test

Answer:

D.

Step-by-step explanation:

Original dimensions:

L = x

W = x

Now we reduce the width by 2 ft and increase the length by 2 ft.

L = x + 2

W = x - 2

The area is the product of the length and width.

A = LW = (x + 2)(x - 2)

The original length and width are 10 ft.

L = W = x = 10

A = LW = (10 + 2)(10 - 2) = 12 * 8 = 96

The new area is 96 sq ft.

Answer: D.

Answer:

B. 7

Step-by-step explanation:

Answer:

B.12.32

Step-by-step explanation:

From the first information we can write :

3y-x=2

from the second one :

2y+2x= 92

so our equation are :

Multiply the first one by 2 then add it to the second one to get rid of x :

Answer:

C

Step-by-step explanation:

First you find which line is which.

The one with 5x in it is the steepest one, and we have to be above it due to the >.

The one with 2x in it is the least steep, and we have to be below it due to the <.

Graph C satisfies both these restrictions.

Answer:

Their speed is 32 km/h.

Step-by-step explanation:

Since they're at the same speed, we can assign a variable to their speed called "x". When the first car increases its speed by 1 km/h, its new speed is "x + 1", while the other car decreases its speed by 10 km/h, so its new speed is "x - 10". The distance's formula can be expressed as below:

[tex]\text{distance} = \text{speed}*\text{time}\\[/tex]

With the modifications to their speed, the distance the first car covers in 2 h and the distance the second car covers in 3 h is shown below:

[tex]\text{distance}_{car1} = (x + 1)*2 \\\text{distance}_{car1} = 2*x + 2[/tex]

[tex]\text{distance}_{car2} = \text{speed}*\text{time}\\\text{distance}_{car2} = (x - 10)*3\\\text{distance}_{car2} = 3*x - 30[/tex]

Since the distance covered by them must be the same, we can find the value of x that makes the expressions equal.

[tex]2*x + 2 = 3*x - 30\\2*x - 3*x = -30 -2\\-x = -32\\x = 32[/tex]

Their speed is 32 km/h.

Answer:

4 x minus 3 y = 16. 8 x minus 6 y = 34 has no solution

Step-by-step explanation:

Examine the system

2 x + 8 y = 15

4 x + 16 y = 30

We see that these equations are identical except for a factor of 2, and thus recognize that this system has infinitely many solutions.

Next, look at the system

2 x minus y = 18

4 x + 2 y = 38

If we divide the second equation by 2, we get the system

2x - y = 18

2x + y = 19

Combining these two equations, we get 4x = 37, which has a solution.

Third, analyze the system

4 x + 7 y = 17                =>  8x + 14y = 34

8 x minus 14 y = 36      => 8x - 14y  = 36, or 16x = 70, which has a solution

Finally, analyze the system

4 x minus 3 y = 16    => -8x + 6y = -32

8 x minus 6 y = 34   =>  8x  - 6y  = 34

If we combine these two equations, we get 0 + 0 = 2, which is, of course, impossible.  This system has no solution.

Answer:

4 x minus 3 y = 16. 8 x minus 6 y = 34 has no solution. the 4th option.

Step-by-step explanation:

Answer:

Not True

Step-by-step explanation:

>_<

[tex]\text{To find your answer, plug in the values to the equation and solve:}\\\\3(2)-2(-1)=13\\\\\text{Solve:}\\\\3(2)-2(-1)=13\\\\6+2=13\\\\8=13\\\\\text{8 does not equal 13, therefore making the equation FALSE}\\\\\boxed{\text{False}}[/tex]

Answer:

-27p^2 q^2 +6p^3 -2p^4 -q^3

Step-by-step explanation:

COMBINE LIKE TERMS

Answer:

d.) 36

Step-by-step explanation:

f(x) = 4.[tex]3^{x}[/tex]

f(2) = 4 × 3² = 4 × 9 = 36

Answer:

B.

Step-by-step explanation:

"negative reciprocal slopes" means the lines are perpendicular, so they will always intersect.

Hence there will be exactly one solution.

B. The system will have one solution.

The slopes of perpendicular strains, or bisecting strains, are continually terrible reciprocals of each other. For instance, if the slope of a line is -five, then the slope of a line perpendicular to this line will be the negative reciprocal of -five.

If the 2 traces have exclusive slopes, then they'll intersect as soon as. consequently, the gadget of equations has exactly one answer. If the two traces have the equal slope however of kind y-intercepts, then they're parallel strains, and they'll by no means intersect.

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