Answer:
2. "a number is greater than 17.2"
Step-by-step explanation:
m > 17.2 can be read by saying "the number m is greater than the number 17.2" which also can be read as 2. "a number is greater than 17.2"
Given the two similar triangles below, which proportion is true?
Answer:
B) 10/15 = 15/22.5
Step-by-step explanation:
For the two triangles, proportions that involve ratios of the corresponding sides are true.
A cylinder has a height of 4 centimeters. Its volume is 12.56 cubic centimeters. What is the radius of the cylinder?
Step-by-step explanation:
hope it will help you...
Answer:
radius of cylinder = 1 cm
Step-by-step explanation:
Start with the formula for the volume of a cylinder: V = (pi)r²h, where r is the radius and h is the height. We want to solve this for the radius, r.
Dividing both sides of the Volume formula (above) by (pi)h, we get:
V
r² = -----------
(pi)h
If we now substitute 12.56 cc for V, 3.14 for pi and 4 cm for h, we get:
V 12.56 cc
r² = ---------- = ----------------- = 1 cm²
(pi)h 3.14(4 cm)
Taking the square root of both sides, we get r = 1 cm
Given that AABCDEF, solve for X.
B
A. 10
o
B. 6
C. 17
0 0
Answer:
D
Step-by-step explanation:
Given Δ ABC is similar to Δ DEF then the ratios of corresponding sides are in proportion, that is
[tex]\frac{EF}{BC}[/tex] = [tex]\frac{DE}{AB}[/tex] , substitute values
[tex]\frac{x}{42}[/tex] = [tex]\frac{5}{30}[/tex] ( cross- multiply )
30x = 5 × 42 = 210 ( divide both sides by 30 )
x = 7
The ratio remains same
[tex]\\ \sf\dashrightarrow \dfrac{5}{x}=\dfrac{30}{42}[/tex]
[tex]\\ \sf\dashrightarrow \dfrac{5}{x}=\dfrac{15}{21}[/tex]
[tex]\\ \sf\dashrightarrow 15x=105[/tex]
[tex]\\ \sf\dashrightarrow x=7[/tex]
3 ½ pints = ___ cups
Answer:
8.40665 cups
Step-by-step explanation:
hope this is helpful!
The diagram shows a map of three land masses, numbered region 1, region 2, and region 3, connected via bridges over water. Each bridge can be traversed in either direction. (diagram is attached)
Show that there are 10 walking routes that start and end in region 2, crossing over water exactly twice. Assume each bridge, when crossed, is fully traversed to the next land mass.
Answer:
Explanation
Step-by-step explanation:
If you look closely, every route connected to region 2 could go to either region 1 or 3, which each could go back to region 2 in 3 different formats. For example the top bridge of region 2, could go through region 1, then region 3 then to the middle bridge of region 2. This can happen for all three of the other route when going backs and works for all bridges in region 2.
Marla was given the point (1, 3), (2, 1), and (-2, -15). She was asked to find a quadratic function that fit these 3 given points. Marla created a system of three equations with three variables to solve the problem and then used the matrix functions on her graphing calculator to find the equation. Which equation can be written given these 3 points?
The quadratic equation is given by y = -2x² + 4x + 1
The standard form of a quadratic equation is given by:
y = ax² + bx + c
At point (1, 3):
3 = a(1)² + b(1) + c
a + b + c = 3 (1)
At point (2, 1):
1 = a(2)² + b(2) + c
4a + 2b + c = 1 (2)
At point (-2, -15):
-15 = a(-2)² + b(-2) + c
4a - 2b + c = -15 (3)
Solving equations 1, 2 and 3 simultaneously gives:
a = -2, b = 4, c = 1
The quadratic equation is given by y = -2x² + 4x + 1
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(Question in the picture)
Answer:
I Don't know
Step-by-step explanation:
I don't know I don't know I don't know
System practice problems
Looking at the first system of equations,
16x - 10y = 10
-8x - 6y = 6
If we multiply both sides of the second equation by 2, the coefficient of x is exactly the negative of the coefficient of x in the first equation.
-8x - 6y = 6
⇒ 2 (-8x - 6y) = 2 (6)
⇒ -16x - 12y = 12
By combining this new equation with the first one, we can eliminate x and solve for y :
(16x - 10y) + (-16x - 12y) = 10 + 12
⇒ -22y = 22
⇒ y = -1
Then we just solve for x by replacing y in either equation.
16x - 10y = 10
⇒ 16x - 10 (-1) = 10
⇒ 16x + 10 = 10
⇒ 16x = 0
⇒ x = 0
The main idea behind elimination is combining the given equations in just the right amount so that one of the variables disappears. The "right amount" involves using the LCM of the coefficients of a given variable. In this example, the x-coefficients had LCM(8, 16) = 16, so we only had to scale one of the equations (the one with -8x) to cancel all the x terms.
If we wanted to eliminate y first instead, we first note that LCM(6, 10) = 30. To get 30 as a coefficient on y, in the first equation we would have multiplied by 3:
16x - 10y = 10
⇒ 3 (16x - 10y) = 3 (10)
⇒ 48x - 30y = 30
And in the second equation, we would have multiplied by -5 (negative so that upon combining the equations, we end up with -30y + 30y = 0):
-8x - 6y = 6
⇒ -5 (-8x - 6y) = -5 (6)
⇒ 40x + 30y = -30
Now combining the two scaled equations gives
(48x - 30y) + (40x + 30y) = 30 + (-30)
⇒ 88x = 0
⇒ x = 0
We then solve for y :
16x - 10y = 10
⇒ -10y = 10
⇒ y = -1
so we end up with the same solution as before.
in a sale there is a 40% discount.what is the discount on a dress that costs $150.00
Answer:
$90 or $60
Step-by-step explanation:
Find the length of OP.
Answer:
OP = 84
Step-by-step explanation:
The triangle is equilateral meaning all angles equal and all sides are equal.
5y - 6 = 4y + 12
y - 6 = 12
y = 12 + 6
y = 18
Now
OP = 4y + 12
OP = 4(18) +12
OP = 84
Find the area of a rectangle & triangle! NEED HELP ASAP
Answer:
For rectangle: A=wl
Step-by-step explanation:
Multiply the length by the with to find the answer
9e +4= -5e + 14+ 13e
step by step pls
Answer:
e = 10
Step-by-step explanation:
9e +4= -5e + 14+ 13e
combine like terms on left side of the equation : -5e + 13e = 8e
9e + 4 = 8e + 14
subtract 8e from both sides : 9e - 8e = e and 8e - 8e cancels out
e + 4 = 14
subtract 4 from both sides : 4 - 4 cancels out and 14 - 4 = 10
we're left with e = 10
2(t+1)=10
t= ? ............................................
Answer:
4
Step-by-step explanation:
2x5=10
5-1=4
2(4+1)=10
Find the sum of all solutions to the equation $3x(x+4) = 135$.
Answer:
-4
Step-by-step explanation:
3x(x + 4) = 135
3x² + 12x = 135
3x² + 12x - 135 = 0
On dividing by 3
x² + 4x - 45 = 0
x² + (9x - 5x) - 45 = 0
x² + 9x - 5x - 45 = 0
x(x + 9) - 5(x + 9) = 0
(x + 9)(x - 5) = 0
x = 5 & -9
Sum = -9 + 5
Sum = -4
The sum of the solutions of the given quadratic equation will be -4.
What is a quadratic equation?An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, and a must not be zero.
As per the given equation,
⇒ 3x(x + 4) = 135
Multiply the 3x as,
3x² + 12x = 135
3x² + 12x - 135 = 0
Divide the above equation by 3 as
3x²/3 + 12x/3 - 135/3 = 0
x² + 4x - 45 = 0
x² + 9x - 5x - 45 = 0
x(x + 9) - 5(x + 9) = 0
(x - 5)(x + 9) = 0
x = 5 and x = -9
Therefore the sum will be -9 + 5 = -4
Hence "The total of the quadratic equation's answers will be -4".
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Please help me asap
ty :)
Answer:
y = -3x - 3
Step-by-step explanation:
Subtract 3x both sides
y = -3 - 3x
y = -3x + (-3)
solve this to pretty pretty pls
Answer:
3) 161
Step-by-step explanation:
Indeed this is pretty easy :D
What we need to find is the surface area of the rectangular prism excluding the area of the hole. First, let's find out the width of the box, we can do this by using the area, the length, and the height, and we can write:
[tex]V=lhw[/tex]
(Formula to find the volume of a rectangular prism)
[tex]140=(4)(7)w\\ 140=28w\\ 5=w[/tex]
Now that we have the width, can find the area of the top part of the prism:
[tex](5)(4)=20[/tex]
The area of the top part of the prism is 20, and the circle has 1/4 of the area of that:
[tex]A_{circle} = \frac{A_{top part} }{4}\\ A_{circle} = \frac{20}{4} \\ A_{circle} = 5[/tex]
So the area of the circle is 5. Now we just need to find the surface area of the rectangular prism and subtract that result with the area of the circle:
[tex]A_{circle}=5\\ SA_{rec.pri.}=2(lh+lw+wh)\\ SA_{rec.pri.}=2((4)(7)+(4)(5)+(5)(7))\\ SA_{rec.pri.}=2(28+20+35)\\ SA_{rec.pri.}=2(83)\\ SA_{rec.pri.}=166[/tex]
Subtract these two results...:
[tex]166-5=161[/tex]
And we are done!
Hello da 234234r32 ef3qew3e2wr3qefwasdwasd
triangle abc has an area of 6 and a perimeter of 12. if the triangle is dilated by a scale factor of 3 centered at the origin, what is the area and perimeter of its image, triangle a'b'c'?
Answer:
perimeter: 36 unitsarea: 54 square unitsStep-by-step explanation:
The perimeter is multiplied by the scale factor:
image perimeter = 3 × original perimeter = 3×12 = 36 units
The area is multiplied by the square of the scale factor:
image area = 3² × original area = 9×6 = 54 square units
Please help guys this is just domain and range
Answer:
domain: x>=0
range: y>=1
Step-by-step explanation:
domain: x>=0
range: y>=1
100
O () = 97 +18
or()- +2
x= +
OF (x) = 97 +2
F(x) = -27 + -
10
Answer:
9x+2
Step-by-step explanation:
the inverse of the function is the opposite. 1/9 becomes 9 and negative 2 becomes positive 2
Answer:
first option
Step-by-step explanation:
let y = f(x) and rearrange making x the subject
y = [tex]\frac{1}{9}[/tex] x - 2 ( add 2 to both sides )
y + 2 = [tex]\frac{1}{9}[/tex] x ( multiply through by 9 to clear the fraction )
9y + 18 = x
change y back into terms of x with x = [tex]f^{-1}[/tex] (x) , then
[tex]f^{-1}[/tex] (x) = 9x + 18
7363626x726=???? Helpppppp
Answer:
The answer is 5345992476
Step-by-step explanation:
Brady rode his bike 70 miles in 4 hours. He rode at an average speed of 17 mph for t hours and alah
respeed of 22 mph for the rest of the time. How long did Brady
ride at the slower speed? Use the variablet to
represent the time, in hours, Brady rode at 17 mph.
Answer:66 slower speed
Step-by-step explanation:
I need help to find the radius
Answer:
Step-by-step explanation:
i think 0.6
WHAT DOES AN ANIMAL BREEDER DO?????????
I LITERALLY NEED HELP ON THIS ONE!!
Some school commercial thingy.
Answer:
Breeders cross animals of the same species with desirable traits to create desirable offspring.
Step-by-step explanation:
what is the area of the square units ? W (11,2), X (11,8), Y (14,8), Z (14,2)
Answer:
18 units²
Step-by-step explanation:
Find the side lengths then multiply the length and width to find the area.
2(x-3) < 3(2x+2)
How do I solve for x
Answer:
x < -3
Step-by-step explanation:
2(x-3) < 3(2x+2)
Use the distributive property.
(2× x)-(2×3) < (3 × 2x) + (3×2)
2x-6 < 6x+6
add 6 to both sides
2x < 6x+12
subtract 6x from both sides.
-4x < 12
divide both sides by -4
x < -3
Please help me Find the slope no links or bots please and thank you I really need help
Answer:
B) -7/4
General Formulas and Concepts:
Algebra I
Slope-Intercept Form: y = mx + b
m - slope b - y-interceptStep-by-step explanation:
Step 1: Define
Identify.
y = -7/4x + 4
Step 2: Break
Slope m = -7/4
y-intercept b = 4
16 =
ОА. 4
ОВ. 3
ОС. 8
O D. 6
Answer:
A. 4
Step-by-step explanation:
I hope this helps you!!!
A store owner bought 15001500 pencils at \$0.10$0.10 each. If he sells them for \$0.25$0.25 each, how many of them must he sell to make a profit of exactly \$100.00$100.00
Based on the information given, the number of pencils that should be sold will be 1000 pencils.
Let the number that should be sold be x.
A store owner bought 1500 pencils at $0.10 each. Therefore, the cost price will be:
= 1500 × $0.10 = $150
Profit = Selling price - Cost price
100 = 0.25x - 150
0.25x = 100 + 150
0.25x = 250
x = 250/0.25
x = 1000
Therefore, 1000 pencils should be sold.
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how to graph transformations of quadratic functions
Answer:
Shift "h" units to the right, "k" units up, and reflect over the x or y axis when needed.
Step-by-step explanation:
1) I want to talk about reflections first.
Reflections across the x-axis --> [tex]y = ax^2[/tex], a is the coefficient. if a is negative, then the equation should be reflected across the x-axis. This is known as a vertical reflection. Reflections across the y-axis --> [tex]y=a(bx)^2[/tex], b is the coefficient. If b is negative, then reflect the equation over the y-axis. There are cases where the reflection across the y-axis does not change anything. But, let's say its [tex]y=(x-3)^2[/tex]... the reflection across the y-axis is different (that equation is: [tex]y=(-x-3)^2[/tex] )2) Rigid transformations
Horizontal transformations (to the left or right): [tex]y=a(bx-h)^2[/tex], factor out b from "bx-h" and whatever h equals is the units to the right. If h is a negative number, then you move to the left. Vertical transformations (up and down): [tex]y = a(bx-h)^2+k[/tex]... k is just the units up... if k is negative then we move it down.Example (check image for visual)
We transform [tex]y = x^2[/tex] to [tex]y = -(-x-3)^2+3[/tex] , you move right 3, then reflect across the x-axis, then reflect across y-axis, then move 3 up.
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Note: In the image, the red line is the original function, the blue one is the transformed function. See if you can follow along with the verbal instructions I gave above.