Please answer these quickly. :)

Please Answer These Quickly. :)

Answers

Answer 1

Q.1

a) 1 mol of N2 requires 3 moles of H2

so 4 moles of hydrogen will require = 4/3 = 1.33 moles

Answer of A) 1.33 moles

b) 2.5 moles of nitrogen gas were require to produce 5.00 moles of NH3

c) 7.5 moles of hydrogen gas were require to produce

5.00 moles of NH3

Q.2

a) 6 moles of H2 gas were require to make 6.00 mol H2S

b)24 moles of H2 gas were required to react with 3 moles of S8

c)56 moles of H2S are produced from 7 mol of S8


Related Questions

A gas has a volume of 450. mL at 55.0 °C. If the volume changes to 502 ml, what is the new temperature?

Answers

Answer:

92.9 °C

Explanation:

Step 1: Given data

Initial volume (V₁): 450. mLInitial temperature (T₁): 55.0 °CFinal volume (V₂): 502 mL

Step 2: Convert 55.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 55.0 + 273.15 = 328.2 K

Step 3: Calculate the final temperature of the gas

If we assume constant pressure and ideal behavior, we can calculate the final temperature of the gas using Charles' law.

T₁/V₁ = T₂/V₂

T₂ = T₁ × V₂/V₁

T₂ = 328.2 K × 502 mL/450. mL = 366 K = 92.9 °C

Is nuclear energy good or bad?

Answers

Answer:

It is bad

Explanation:

Is nuclear energy good or bad?

Bad it’s bad bad baddddddddddddddd

The total number of sodium atoms in 46.0 grams of sodium
is

Answers

The answer is 2.0, and it is because

what geological forces might be responsible for the range of mountains

Answers

Answer:

Mountains are built by tectonic processes that cause portions of the Earth's crust to rise. These processes are fueled by the escape of heat from the interior of the Earth, causing crustal uplift by volcanic activity and by movement along faults that, in turn, is responsible for the formation of mountains.

Explanation:

Select all of the abiotic factors in an ecosystem.

Plants

Sunlight

Soil

Animals

Rocks

Dead deer in the forest

Temperature

Answers

Answer:

Sunlight, Soil, Rocks, Temperature and dead deer

Explanation:

You could say the dead tree is now an abiotic factor because biotic factors refer to living things

Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to four significant figures. View Available Hint(s)

Answers

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = [tex]Mass \ of \ (NaCl+H_2O)[/tex]

                                 = [tex]51.56+164.2[/tex]

                                 = [tex]215.76 \ g[/tex]

hence,

⇒ [tex]Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100[/tex]

                           [tex]=\frac{51.56}{215.76}\times 100[/tex]

                           [tex]=23.896 \ percent[/tex]

What is the mass in grams of 5.50 moles of Copper, Cu?

Answers

Answer:

349.503 g

https://www.convertunits.com/from/moles+Copper/to/grams

here is a link, you can convert moles of copper to grams here

The answer is 5.50 moles of Cu (Copper) has 349.503 grams mass .

What is a mole ?

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10 23 atoms, molecules, or formula units of that substance.

1 mole of Cu has 63.546 grams of Cu

So 5.50 moles will have 5.50 * 63.546 grams

=349.503 grams

Therefore 5.50 moles of Cu (Copper) has 349.503 grams mass .

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How much heat does it take to increase the temperature of 2.70 mol of an ideal gas by 30.0 K near room temperature if the gas is held at constant volume and is diatomic

Answers

Answer:

1683.6J

Explanation:

Given:

n= no. Of mol= 2.70 mol

T= Temperature= 30.0 K

Q= n Cv × ∆T .........eqn(1)

Where CV= molar heat capacity=5/2R for diatomic particle ,such as H2

CV= molar heat capacity=3/2R for diatomic, such as H

R= gas constant= 8.314 J/mol.K

Q= heat energy

For a diatomic molecules

Q= n Cv × T

But

Cv= molar heat capacity=5/2R = 5/2(8.314)=20.785

CV= 20.785

. ∆T= Temperature= 30.0 K

Then substitute the values into the eqn(1)

Q= 2.70 × 5/2(8.314) × 30

Q= 2.70 × 20.785 × 30

=1683.6J

An atmospheric concentration of 380 ppm CO2 corresponds to a partial pressure of 0.00038 atm. What percentage of the CO2 originally dissolved in the solution in Part A remains in solution after the soft drink reaches equilibrium with the ambient atmosphere

Answers

Answer:

8.44 * 10^-3 %

Explanation:

The solubility of CO2 gas in water is 0.15g/100 ml at a CO2 pressure of 760 mmHg.

Determine the percentage of the CO2 that dissolved originally in the solution that remains

Amount remaining ( Sg = kpg )

Sg = solubility of gas = 0.15 / 100 g/ml

pg. = partial pressure of gas = 760 mmHg = 1 atm

therefore ; K = 1.5 * 10^-3 gm^-1 atm^-1

solubility of gas inside container

Sg = 0.675 * 10^-2 g/ml

solubility of gas during/after dissolution ( amount that remains )

sg = 1.5 * 10^-3 * 0.00038

    =  5.7 * 10^-7  g/ml

therefore the percentage remaining

= (5.7 * 10^-7  / 0.675 * 10^-2 ) * 100

= 8.44 * 10^-3 %

The percentage of CO2 remaining in the solution after the soft drink reaches equilibrium is 8.4 × 10⁻³ %

There exists some missing information in the question.

Let us assume that:

the solubility of CO2 gas in the water = 0.15 g/100 mL = 1.5 × 10⁻³ the partial pressure of CO2 = 760 mmHg = 1 atm

Then, by applying Henry's law:

[tex]\mathbf{S_g = k P_g}[/tex]

[tex]\mathbf{k = \dfrac{S_g}{P_g}}[/tex]

[tex]\mathbf{k =\dfrac{1.5 \times 10^{-3} g/mL}{1\ atm}}}[/tex]

k = 1.5 × 10⁻³ g/m* atm

The percentage of CO2 that was originally dissolved in the solution is:

[tex]\mathbf{S_g = k P_g}[/tex]

Assuming the partial pressure of CO2 = 4.5 atm

Then;

[tex]\mathbf{S_g = 1.5 \times 10^{-3} g/mL* atm \times 4.5 \ atm}[/tex]

[tex]\mathbf{S_g =0.00675 \ g/mL}[/tex]

The partial pressure in the can when the soft drink is being opened is 0.00038 atm.

The solubility of the gas [tex]\mathbf{S_g = 1.5 \times 10^{-3} g/mL* atm \times 0.00038 \ atm}[/tex]

[tex]\mathbf{S_g =5.7 \times 10^7 \ g/mL}[/tex]

Thus, the percentage of CO2 remaining in the solution after the soft drink reaches equilibrium is:

[tex]\mathbf{=\dfrac{5.7\times 10^{-7}}{0.00675} \times 100 \%}[/tex]

[tex]\mathbf{=0.0084 \%}[/tex]

= 8.4 × 10⁻³ %

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Which best compares kinetic energy and temperaturo?
A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.
B. Temperature is energy of motion, whilo kinetic energy is a measure of that energy in substances,
C.Kinetic energy is internal transferable energy, while temperature is a measure of that energy in substances,
D.Temperature is internal transferable energy, while kinetic energy is a measure of that energy in substances.

Answers

Which best compares kinetic energy and temperature?

[tex]{\boxed{\mathcal{\red{Answer:}}}}[/tex]

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances. ✅

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.

Explanation:

got it right on edge 2021

A 10.00 mL sample of a solution containing formic acid (a weak acid) was placed in a 25 mL volumetric flask and diluted to the mark with water. A 10.00 mL sample of the diluted formic acid solution was then titrated with 0.1322 M sodium hydroxide. The titration required 15.80 mL of sodium hydroxide to reach the equivalence point. Calculate the molarity and the percentage (by mass) formic acid in the original solution. The density of the formic acid solution was found to be 1.02 g/mL.

Answers

Answer:

Molarity: 0.522M

Percentage by mass: 2.36 (w/w) %

Explanation:

Formic acid, HCOOH reacts with NaOH as follows:

HCOOH + NaOH → NaCOOH + H₂O

To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:

Moles NaOH = Moles HCOOH:

0.01580L * (0.1322mol / L) =0.002089 moles HCOOH

Moles in the original solution:

0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH

Molarity of the solution:

0.005222 moles HCOOH / 0.01000L =

0.522M

Mass HCOOH in 1L -Molar mass: 46.03g/mol-

0.522moles * (46.03g / mol) = 24.04g HCOOH

Mass solution:

1L = 1000mL * (1.02g / mL) = 1020g solution

Mass percent:

24.04g HCOOH / 1020g solution * 100

2.36 (w/w) %

What volume is occupied by 0.108 mol of helium gas at a pressure of 0.96 atm and a
temperature of 315 K?

Express your answer using two significant figures.

Answers

Answer:

[tex]V=2.9L[/tex]

Explanation:

Hello there!

In this case, by considering the given information in this problem, it is possible  for us to infer that this problem is solved by using the ideal gas equation:

[tex]PV=nRT[/tex]

Next, since we are given the moles, pressure and temperature, we proceed as follows:

[tex]V=\frac{nRT}{P}[/tex]

Then, we plug in the given data to obtain:

[tex]V=\frac{0.108mol*0.08206\frac{atm*L}{mol*K}*315K}{0.96atm}\\\\V=2.9L[/tex]

Best regards!

As the temperature increases from 0°C to 25°C the amount of NH3 that can be dissolved in 100 grams of water.

A) decreases by 10 grams
B) decreases by 40 grams
C) increases by 10 grams
D) increases by 40 grams​

Answers

Answer:

decreases by 10 gram

Explanation:

what is a saturated organic compound and unsaturated organic compound?​

Answers

Answer:

Saturated organic compound has only single bonds between carbon atoms. An important class of saturated compounds are the alkanes. Many saturated compounds have functional groups, e.g., alcohols.

Unsaturated organic compound have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may be added to the hydrocarbon to make it saturated (i.e. consisting all single bonds).

An unbalanced chemical equation:a. does not obey Conservation of Mass law b.does obey Conservation of Mass law c.has equal numbers of atoms of each element in both reactants and productsd.none of the above

Answers

Answer:

a. Does not obey Conservation of Mass law

Explanation:

An example of an unbalanced chemical equation is:

H₂SO₄ + NaOH → Na₂SO₄ + H₂O

As you can see, there are two Na atoms on the right side of the equation, while only one on the left side, causing the masses on both sides of the equation to not be equal. In other words, not fulfilling the Conservation of Mass law.

Compare with the correctly balanced equation:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

Now both sides of the equation possess the same number of atoms for each element.

What are the characteristics of acids and bases, and some examples of each?

Answers

Answer:

Acids taste sour while bases taste bitter. An acid reacts with metals to produce bubbles of hydrogen gas while a base feels slimy to the touch. Acids turn blue litmus paper red while bases turn red litmus paper blue.

What is the percent yield when 1.72 g of H2O2 decomposes and produces 375 mL of O2 gas measured at 42 oC and 1.52 atm

Answers

Answer:

87.0%

Explanation:

Step 1: Write the balanced reaction

H₂O₂ ⇒ H₂O + 0.5 O₂

Step 2: Calculate the real yield of oxygen, in grams

We have 375 mL (0.375 L) of O₂ at 42 °C (315 K) and 1.52 atm. First, we will calculate the number of moles using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.52 atm × 0.375 L / (0.0821 atm.L/mol.K) × 315 K = 0.0220 mol

The molar mass of oxygen is 32.00 g/mol.

0.0220 mol × 32.00 g/mol = 0.704 g

Step 3: Calculate the theoretical yield of oxygen, in grams

According to the balanced equation, the mass ratio of H₂O₂ to O₂ is 34.01:16.00.

1.72 g H₂O₂ × 16.00 g O₂/34.01 g H₂O₂ = 0.809 g O₂

Step 4: Calculate the percent yield of oxygen

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 0.704 g / 0.809 g × 100% = 87.0%

Considering the reaction stoichiometry and the ideal gas law, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

Theoretical yield of oxygen

The balanced reaction is:

2 H₂O₂ → 2 H₂O +  O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂O₂: 2 moleH₂O: 2 mole O₂: 1 moles

The molar mass, this is the amount of mass a substance contains in one mole, of H₂O₂ is 34 [tex]\frac{g}{mole}[/tex]. Then, the amount of moles of H₂O₂ that decomposes when 1.72 grams of H₂O₂ reacts is calculated as:

[tex]1.72 gramsx\frac{1 mole}{34 grams}= 0.0506 moles[/tex]

Then you can apply the following rule of three: if by stoichiometry 2 moles of H₂O₂ produce 1 moles of O₂, 0.0506 moles of H₂O₂ will produce how many moles of O₂?

[tex]amount of moles of O_{2} =\frac{0.0506 moles of H_{2} O_{2} x1 mole of O_{2} }{2 moles of H_{2} O_{2}}[/tex]

amount of moles of O₂= 0.0253 moles

Real yield of oxygen

On the other side, an ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, for O₂ gas you know:

P= 1.52 atmV= 375 mL= 0.375 L (being 1000 mL= 1 L)n= ?R= 0.082 [tex]\frac{atmL}{molK}[/tex]T= 42 °C= 315 °K (being 0°C= 273°K)

Replacing:

1.52 atm× 0.375 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 315 K

Solving:

[tex]n=\frac{1.52 atmx 0.375 L}{0.082\frac{atmL}{molK}x 315 K }[/tex]

n= 0.022 moles

Percent yield of oxygen

The percent yield is calculated as

[tex]Percent yield= \frac{real yield}{theoretical yield} x100[/tex]

In this case, for oxygen the percent yield is calculated as

[tex]Percent yield of oxygen= \frac{0.022 moles}{0.0253 moles} x100[/tex]

Percent yield of oxygen= 86.96 %

Finally, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

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One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/Kg.K.

Answers

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ([tex]s_{2} - s_{1}[/tex]), in joules per gram-Kelvin, by the following model:

[tex]s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-Kelvin.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures of water, in Kelvin.

If we know that [tex]m = 1\,kg[/tex], [tex]c_{w} = 4190\,\frac{J}{kg\cdot K}[/tex], [tex]T_{1} = 373.15\,K[/tex] and [tex]T_{2} = 288.15\,K[/tex], then the change in entropy for the entire process is:

[tex]s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}[/tex]

[tex]s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}[/tex]

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Answer:

The change in entropy = [tex]-1083.534 J/k[/tex]

Explanation:

Change in entropy,

[tex]\delta S = mCp * In[\frac{T2}{T1}][/tex]

The initial temperature,

[tex]T1 = 100^oC\\\\T1 = 100+273\\\\T1 = 373k[/tex]

Final value of temperature,

[tex]T2 = 15^oC\\\\T2 = 15+273\\\\T2 = 288k[/tex]

where,

[tex]m = 1kg\\\\Cp = 4190 J/kg.k[/tex]

Substitute into [tex]\delta S[/tex]

[tex]\delta S = mCp * In[\frac{T2}{T1}]\\\\\delta S = 1 * 4190 * In[\frac{288}{373}]\\\\\delta S = 4190 * In[0.7721]\\\\\delta S = 4190 * [-0.2586]\\\\\delta S = -1083.534 J/k[/tex]

The negative sign exists because the change in entropy will be decreasing due to cooling.

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Two iron-clad characteristics of matter
are that it has mass and also exhibits
which of the following?
A. It flows from hot to cold.
B. It can do work,
C. It has volume (takes up space).
D. It is a solid.

Answers

Answer:

it has volume( takes up space).

Explanation:

The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

What is Matter ?

A physical substance in general, that which occupies space and possesses rest mass, especially as distinct from energy.

Matter is important because it makes up everything around us and matter can not be created or destroyed but instead, they just transformed into a different form.

Any characteristic that can be measured, such as an object's density, colour, mass, volume, length, malleability, melting point, hardness, odour, temperature, and more, are considered properties of matter.

Therefore, The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

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28. If the total pressure of a mixture of four gases (neon, carbon dioxide, oxygen and hydrogen) is 1245 mm
Hg, what is the pressure of neon gas if the pressure of carbon dioxide is 145 mm Hg, the pressure of hydrogen is
499 mm Hg and the pressure of oxygen is 228 mm Hg?
A) 601 mm Hg
B) 746 mm Hg
C) 872 mm Hg
D) 373 mm Hg

Answers

Answer:

D) 373 mm Hg.

Explanation:

We can solve this problem by keeping in mind Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:

Total Pressure = Ne Pressure + CO₂ Pressure + O₂ Pressure + H₂ Pressure1245 mm Hg = Ne Pressure + 145 mm Hg + 228 mm Hg + 499 mm HgNe Pressure = 373 mm Hg

The answer is option D) 373 mm Hg.

help please
A gas in a sealed container has a pressure of 125 kPa at a temperature of 303K. If the temperature in the container is increased to 487K, what is the new pressure?

A 201kpa
B 200kpa
C 400kpa
D 78kpa​

Answers

Answer:

A. 201 kPa

Explanation:

We can solve this problem by using Boyle's law, which states:

P₁T₂ = P₂T₁

Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:

P₁ = 125 kPaT₂ = 487 KP₂ = ?T₁ = 303 K

We input the data:

125 kPa * 487 K = P₂ * 303 K

And solve for P₂:

P₂ = 201 kPa

If 1000 molecules enter the first-order reaction and 500 of them disintegrate in 1 s, then how many molecules disintegrate in 2 s?

Answers

Answer:

250 molecules

Explanation:

The number of molecules at the end of 1s are half the initial number of molecules.So, we can see that 1s is basically the half live.

For first order reactions t1/2=(ln2)/k

k=(ln2)/t1/2

k =(ln2)/1s

k =ln 2 /s

Because we know k ,we can use the integrated rate laws.

For 1st order:

ln[A]=ln[A]initial -kt

[A]= ?

[A]initial=1000

k=ln2

t=2s

ln[A]=ln[1000]-[ln 2 x 2]

ln[A]~5.521

[A]=e^(5.521)

    =250 molecules

Hope it helps:)

A flask contains 85.5 grams C12H2011 (sucrose) in 1.00 L of solution. What is the molarit
Your answer.
3.8 M
25 M
10M
1.2M

Answers

Answer:

0.25 M

Explanation:

First we convert 85.5 grams of sucrose into moles, using its molar mass:

Molar Mass of C₁₂H₂₂O₁₁ = (Molar Mass of C)*12 + (Molar Mass of H)*22 + (Molar Mass of O)*11Molar Mass of C₁₂H₂₂O₁₁ = 342.3 g/mol85.5 g ÷ 342.3 g/mol = 0.25 mol

Then we divide the number of moles by the number of liters to calculate the molarity:

0.25 mol / 1.00 L = 0.25 M

how the government support communities affected by xenophobia​

Answers

Answer:

They tax the citizens and then provide them with relief efforts

Explanation:

Common disease protocol

Heytggt did did did dk did did did r eeueueieuwo said that he was a member of the new acc party

what are ambident nucleopliles​

Answers

Answer:

I hope this helps you

.......................................

Evaluate each of the statements below. Select those that accurately describe the role of genes and chromosomes in
the process of inheriting a specific trait. Choose ALL that apply.
-0)
A)
Chromosomes are made of DNA.
B)
There are 26 pairs of chromosomes in humans.
C)
Alleles are the different forms of a gene that can exist.
D)
Chromosomes contain genes that control the inheritance of traits.
E)
Genes are made of chromosomes and contain all of the genetic information
for an organism.

Answers

Answer:

HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER

What is the mass of a gas with a molar mass of 44.01 g/mol at a temperature of 298 K, a pressure of 0.957 atm and a volume of 1.30L?

Answers

Answer:

2.24 g

Explanation:

First we use the PV=nRT formula to calculate the number of moles of the gas:

0.957 atm * 1.30 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298 Kn = 0.0509 mol

Then we can use the given molar mass to calculate the mass:

Molar Mass = Mass / number of moles44.01 g/mol = Mass / 0.0509 molMass = 2.24 g

How many hydrogen atoms are in 0.1854 mol
of H2SO4?
Answer in units of atoms H.

Answers

Sulfuric Acid, H2SO4 is a chemical compound made up of two hydrogen atom, one sulfer atom, and four oxygen atoms.

WILL GIVE BRAINLIEST!!!
Which of the following conditions remain constant in Boyle's law?

Volume and pressure
Density and temperature
Pressure and number of moles
Temperature and number of moles

Answers

Answer: Temperature and number of moles are the conditions which remain constant in Boyle's law.

Explanation:

Boyle's law states that at constant temperature the pressure of a gas is inversely proportional to the volume of gas.

Mathematically, it is represented as follows.

[tex]P \propto \frac{1}{V}[/tex]

As equation for ideal gas is as follows.

PV = nRT

And, at constant temperature the pressure is inversely proportional to volume which also means that number of moles are also constant in Boyle's law.

Thus, we can conclude that temperature and number of moles are the conditions which remain constant in Boyle's law.

Answer:

Temperature and number of moles

Explanation:

Which has the strongest conjugate base?

Phenol
1.3 x 10-10

Formic
1.8 x 10-4

Lactic
1.4 x 10-4

Answers

Answer:

Phenol.

Explanation:

Hello there!

In this case, for this question about the strength of the resulting conjugate base, it is possible for us to know that the higher the Ka (stronger aid) the weaker the conjugate base. In such a way, since the phenol has the smallest Ka (weakest acid) we infer that it has the strongest conjugate base.

In addition to the aforementioned, the reason why phenol was the answer is because the Kb of its conjugate base is the greatest due to the Kb=Kw/Ka and thus, the smaller the Ka the bigger Kb.

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