Answers
Answer:
[tex]\boxed{CD = 7.1}[/tex]
Step-by-step explanation:
The coordinates are (6,-5) and (-1,-4)
Distance Formula = [tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
CD = [tex]\sqrt{(-1-6)^2+(-4+5)^2}[/tex]
CD = [tex]\sqrt{(-7)^2+(1)^2}[/tex]
CD = [tex]\sqrt{49+1}[/tex]
CD = [tex]\sqrt{50}[/tex]
CD = 7.1 units (nearest tenth)
Answer: CD = 7.1
Step-by-step explanation:
Plug in each x coordinate and y coordinate into the distance formula.
d = √(-1 - 6)² + (-4 + 5)²
d = √(-7)² + (1)²
d = √49 + 1
d = √50
√50 = 7.1
d = 7.1
Related Questions
A jar contains 5 brown marbles, 3 yellow marbles, 4 red marbles, 6 blue marbles, and 2 orange marbles. A marble is chosen and replaced. Then another marble is chosen. What is the likelihood that a brown marble AND a red marble were chosen? A: 9/20 B: 1/2 C: 1/20 D: 0
Answers
Answer:
1/20
Step-by-step explanation:
5 brown marbles, 3 yellow marbles, 4 red marbles, 6 blue marbles, and 2 orange marbles = 20 marbles
P( brown) = brown / total = 5/20 = 1/4
Replace
5 brown marbles, 3 yellow marbles, 4 red marbles, 6 blue marbles, and 2 orange marbles = 20 marbles
P( red) = red / total = 4/20 = 1/5
P( brown, replace, red) = 1/4 * 1/5 = 1/20
Not sure how I would solve this
Answers
Answer:
0
Step-by-step explanation:
Using the slope formula
m = (y2-y1)/(x2-x1)
= (4-4)/(3-4)
= 0/-1
= 0
What measures of center and spread are best used if the data is symmetrical and asymmetrical? Explain your reasoning.
Answers
Answer:
If the data is symmetrical, then the mean is the best measure of central tendency to use, and the standard deviation is the best spread to use.
If the data is unsymmetrical, the median is the best measure of central tendency to use, and the inter-quarterly range is the best spread to use.
Step-by-step explanation:
An histogram for a symmetrical data will give a symmetrical shape, and the mean, median and mode will all be the same value. Therefore, the best measure of central tendency to use is the mean. The standard deviation shows how far away the values in a given data set are from the mean, and since the mean is used as the measure of central tendency in this case, the standard deviation should be used as the spread.
An histogram for a an asymmetric data set will give an asymmetric shape, and the mean is not always equal to the median. Therefore, the best measure of central tendency to use is the median. The inter-quarterly range shows the range of the middle 50% of a certain data, which is considered from the median value. Since the median is used as the measure of central tendency in this case, it is wise to use the inter-quarterly range as the measure of spread.
Answer:
i ama
Step-by-step explanation:
Brainliest? Get this correct What is the sum of the rational expressions below?
Answers
Answer:
A)
Step-by-step explanation:
Answer:
[tex] \dfrac{5x^2 + 5x + 3}{3x^2 + 3x} [/tex]
Step-by-step explanation:
[tex] \dfrac{2x + 3}{3x} + \dfrac{x}{x + 1} = [/tex]
[tex] = \dfrac{(x + 1)(2x + 3)}{(x + 1)(3x)} + \dfrac{(3x)(x)}{(3x)(x + 1)} [/tex]
[tex] = \dfrac{2x^2 + 3x + 2x + 3}{3x^2 + 3x} + \dfrac{3x^2}{3x^2 + 3x} [/tex]
[tex] = \dfrac{2x^2 + 5x + 3 + 3x^2}{3x^2 + 3x} [/tex]
[tex] = \dfrac{5x^2 + 5x + 3}{3x^2 + 3x} [/tex]
Keisha wants to estimate the percentage of managers at her company that hold an MBA. She surveys 320 managers and finds that 70 hold an MBA. Find the margin of error for the confidence interval for the population proportion with a 90% confidence level.
Answers
Answer:
The margin of error is of 0.038 = 3.8%.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 320, \pi = \frac{70}{320} = 0.21875[/tex]
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]M = 1.645\sqrt{\frac{0.21875(1-0.21875)}{320}}[/tex]
[tex]M = 0.038[/tex]
The margin of error is of 0.038 = 3.8%.
If the infinite curve y = e^−3x, x ≥ 0, is rotated about the x-axis, find the area of the resulting surface.
Answers
Answer:
S = 2π/9 [³/₂√10 − ½ ln(-3 + √10)]
S ≈ 3.946
Step-by-step explanation:
For a curve rotated about the x-axis, the surface area is:
S = ∫ₐᵇ 2πy ds,
where ds = √(1 + (dy/dx)²) dx.
y = e⁻³ˣ
dy/dx = -3e⁻³ˣ
ds = √(1 + (-3e⁻³ˣ)²) dx
S = ∫₀°° 2πe⁻³ˣ √(1 + (-3e⁻³ˣ)²) dx
If u = -3e⁻³ˣ, then du = 9e⁻³ˣ dx, or du/9 = e⁻³ˣ dx.
When x = 0, u = -3. When x = ∞, u = 0.
S = ∫₋₃⁰ 2π √(1 + u²) (du/9)
S = 2π/9 ∫₋₃⁰ √(1 + u²) du
S = 2π/9 [ ½ u √(1 + u²) + ½ ln|u + √(1 + u²)| ] |₋₃⁰
S = 2π/9 {[0] − [ -³/₂√10 + ½ ln(-3 + √10) ]}
S = 2π/9 [³/₂√10 − ½ ln(-3 + √10)]
S ≈ 3.946
The area of a surface is the amount of space it occupies.
The area of the resulting surface is [tex]3.947[/tex] square units
The infinite curve is given as:
[tex]y =e^{-3x},\ \ x \ge 0[/tex]
Integrate y, with respect to x
[tex]\frac{dy}{dx} = -3e^{-3x}[/tex]
The area of the curve about the x-axis is:
[tex]S = \int\limits^a_b {2\pi y} \, ds[/tex]
[tex]ds = \sqrt{(1 + (\frac{dy}{dx})^2)}\ dx[/tex]
Substitute [tex]\frac{dy}{dx} = -3e^{-3x}[/tex] in [tex]ds = \sqrt{(1 + (\frac{dy}{dx})^2)}\ dx[/tex]
[tex]ds = \sqrt{(1 + (-3e^{-3x})^2)}\ dx[/tex]
Let
[tex]u = -3e^{-3x}[/tex]
So:
[tex]\frac{du}{dx} = 9e^{-3x}[/tex]
Make [tex]e^{-3x}\ dx[/tex] the subject
[tex]e^{-3x}\ dx = \frac{du}9[/tex]
[tex]x \ge 0[/tex] means that, the value of x is: [tex][0,\infty][/tex]
When [tex]x = 0[/tex]
[tex]u = -3e^{-3x}[/tex]
[tex]u = -3 \times e^{-3 \times 0} = -3[/tex]
When [tex]x = \infty[/tex]
[tex]u = -3 \times e^{-3 \times \infty} = 0[/tex]
Recall that:
[tex]S = \int\limits^a_b {2\pi y} \, ds[/tex]
Substitute [tex]ds = \sqrt{(1 + (-3e^{-3x})^2)}\ dx[/tex] and [tex]y =e^{-3x}[/tex]
This gives
[tex]S = \int\limits^0_{-3} {2\pi (e^{-3x}) \sqrt{(1 + (-3e^{-3x})^2)}\ dx}[/tex]
Rewrite as:
[tex]S = \int\limits^0_{-3} {2\pi \sqrt{(1 + (-3e^{-3x})^2)}\ (e^{-3x})\ dx}[/tex]
Substitute [tex]u = -3e^{-3x}[/tex] and [tex]e^{-3x}\ dx = \frac{du}9[/tex]
[tex]S = \int\limits^0_{-3} {2\pi \sqrt{(1 + u^2)}\ \frac{du}9}[/tex]
This gives
[tex]S = \frac{2\pi}{9} \int\limits^0_{-3} {\sqrt{(1 + u^2)}\ du}[/tex]
Integrate with respect to u
[tex]S = \frac{2\pi}{9}[\frac 12 u\sqrt{(1 + u^2)} + \frac 12\ln|u + \sqrt{1 + u^2}|\ ]|\limits^0_{-3}[/tex]
Substitute 0 and -3 for u
[tex]S = \frac{2\pi}{9}([\frac 12\times 0 \times \sqrt{(1 + 0^2)} + \frac 12\ln|0 + \sqrt{1 + 0^2} ] - [\frac 12 \times (-3) \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]
[tex]S = \frac{2\pi}{9}([0] - [\frac 12 \times (-3) \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]
[tex]S = \frac{2\pi}{9}(- [\frac 12 \times (-3) \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]
[tex]S = \frac{2\pi}{9}(- [\frac{-3}2 \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]
[tex]S = \frac{2\pi}{9}( [\frac{3}2 \times \sqrt{10} - \frac 12\ln(-3 + \sqrt{10}\ )] )[/tex]
[tex]S = \frac{2\pi}{9}( [4.743 + 0.909] )[/tex]
[tex]S = \frac{2\pi}{9}( 5.652 )[/tex]
[tex]S = 3.947[/tex]
Hence, the area of the resulting surface is [tex]3.947[/tex] square units
Read more about areas at:
https://brainly.com/question/3547303
Figure A is a scale image of Figure B. What is the value of x?
Answers
Hey there! :)
Answer:
x = 21 units.
Step-by-step explanation:
Since we know Figure A is just Figure B scaled, we can set up a proportion:
[tex]\frac{45}{35}= \frac{27}{x}[/tex]
Cross multiply to solve for x:
45 · x = 35 · 27
45x = 945
Divide both sides by 45:
x = 21 units.
3
Select the correct answer from each drop-down menu.
Consider the expressions given below.
A. 213 – 12 – 61
B. 213 + 81 + 4
C. 374 + 12 + 1 - 7
D. 314 – 312 + 51 - 7
For each expression below, select the letter that corresponds to the equivalent expression from the given list.
(413 - 4 + 71) (223 - 1 - 8) is equivalent to expression
(-332 + 14 + 1) + (234 - 7 + 41) is equivalent to expression
(22 – 21)(2x + 3) is equivalent to expression
BP
Reset
Next
Answers
Answer:
B
D
A
Step-by-step explanation:
Given:
A. [tex]2x^3-x^{2} -6x[/tex]
B. [tex]2x^3+8x+4[/tex]
C. [tex]3x^4+x^{2} +x-7[/tex]
D. [tex]3x^4-3x^{2} +5x-7[/tex]
Now, let us evaluate the given expressions one by one.
[tex](4x^3-4+ 7x)-(2x^3-x-8)\\\Rightarrow 4x^3-4+ 7x-2x^3+x+8\\\Rightarrow 2x^3+8x+ 4[/tex]
It is equation B.
So, [tex](4x^3-4+ 7x)-(2x^3-x-8)[/tex] is equivalent to B.
[tex](-3x^2+x^4+x)+(2x^4-7+4x)\\\Rightarrow -3x^2+x^4+x+2x^4-7+4x\\\Rightarrow3x^4-3x^{2} +5x-7[/tex]
It is equation D.
So, [tex](-3x^2+x^4+x)+(2x^4-7+4x)[/tex] is equivalent to D.
[tex](x^{2} -2x)(2x+3)\\\Rightarrow 2x^3-4x^{2} +3x^{2} -6x\\\Rightarrow 2x^3-x^{2} -6x[/tex]
It is equation A.
So, [tex](x^{2} -2x)(2x+3)[/tex] is equivalent to A.
So, answer is:
B
D
A
Answer:
B D A
Step-by-step explanation:
Hope I Helped
In her last semester at SPC, Polly Hedron needs to take Statistics, Composition 2, Ethics, and Physics. Because Polly is registering early, she has 14 choices for her section of Statistics, 12 choices for her section of Composition, 11 choices for her section of Ethics, and 18 choices for her section of Physics. From how many possible schedules can Polly choose? (You may presume that none of these sections interfere with each other)
Answers
Answer:
Polly can choose 33264 schedules.
Step-by-step explanation:
None of these sections interfere with each other, so:
For each statistics choice, there are 12 composition choices.
For each composition choice, there are 11 section of Ethics choices.
For each section of Ethics choice, there are 18 Physics choises.
There are 14 statistics choices.
From how many possible schedules can Polly choose?
14*12*11*18 = 33264
Polly can choose 33264 schedules.
Solve the equation. y + 3 = –y + 9
A. y = 1
B. y = 3
C. y = 6
D. y = 9
Answers
Answer:
y=3
Step-by-step explanation:
y + 3 = –y + 9
Add y to each side
y+y + 3 = –y+y + 9
2y+3 = 9
Subtract 3 from each side
2y+3-3 = 9-3
2y = 6
Divide by 2
2y/2 = 6/3
y =3
Answer:
Hello!
_______________________
Your answer would be (B) y = 3
Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.
Hope this helped you!
All cell phone plans from Mobile USA require an additional $10/month data fee on top of the base plan price.
Lindsay has the $39.99/month base cell phone plan from MobileUSA.
Conjecture: Lindsay pays at least $49.99/month for her cell phone.
Use deductive reasoning to verify the conjecture, or provide a counterexample if the conjecture is false.
A true, law of detachment
В. false, Lindsay does not have a data fee
С. false, Lindsay is not a Mobile USA customer
Dfalse, not all MobileUSA customers have a data fee
Answers
Answer:
A
Step-by-step explanation:
Answer:
A True, law of detachment.
The cube of a number is less than five times the square of the number. For what set of numbers is this true?
(–ꝏ, 5)
(5, ꝏ)
(–ꝏ, 0) U (0, 5)
(–ꝏ, 5) U (5, ꝏ)
Answers
Answer:
(–ꝏ, 0) U (0, 5)
Step-by-step explanation:
The relation can be written as ...
x³ < 5x²
x³ -5x² < 0
x²(x -5) < 0
This is not true for x = 0. It is true for x < 5, otherwise. Then the solution set is ...
x ∈ {(–ꝏ, 0) U (0, 5)}
Answer:
C
Step-by-step explanation:
got it right on edge
Need help, Will mark brainlest!
Answers
Answer:14/3 ×2/7Step-by-step explanation:14/3÷7/2
take reciprocal
=14/3×2/7
Hope this may help you
If the answer is correct please mark me the brainlest
Answer:
Option 2
Step-by-step explanation:
=> [tex]4\frac{2}{3} / 3\frac{1}{2}[/tex]
Changing them into improper fractions
=> [tex]\frac{14}{3} / \frac{7}{2}[/tex]
Changing division sign into multiplication and inverting the term after it
=> [tex]\frac{14}{3} * \frac{2}{7}[/tex]
**Hello !** I need help to do that algebra homework. I don't really know how that website works, so just tell me how much points you want if your answer is good and i'll give them to your with a lot of pleasure. Here is the homework : Thank you so much for your help ! :)
Answers
Answer:
y = √(900 -x²); see below for a graph
Step-by-step explanation:
The high point (30 ft) is the radius of the circle, so the equation is ...
x² +y² = 30²
Subtract the x-term and take the square root to find y.
y² = 30² -x²
y = √(30² -x²) = √(900 -x²)
The graph is shown in the attachment.
_____
Comment on "how that website works"
We don't know what web site you're referring to, but the one I like is Desmos. It only takes a few minutes to learn to graph the equation here.
You don't even need to solve for y to get the desired graph. You can simply specify that y ≥ 0.
Consider the matrices. A=⎡⎣⎢4−3−578−2⎤⎦⎥ and B=⎡⎣⎢−27−35−12⎤⎦⎥ What is the result of A−B? Enter your answer by filling in the boxes.
Answers
hello
[tex]A-B=\left[\begin{array}{cc}4-(-2)&7-5\\-3-7&8-(-1)\\-5-(-3)&-2-2\end{array}\right] \\\\=\left[\begin{array}{cc}4+2&2\\-10&8+1\\-5+3&-4\end{array}\right] \\\\=\left[\begin{array}{cc}6&2\\-10&9\\-2&-4\end{array}\right][/tex]
hope this helps
Using matrices A and B, the result of A-B is
[tex]A-B=\left[\begin{array}{ccc}6&2\\-10&9\\-2&-4\end{array}\right][/tex]
Given :
Two matrices A and B. We need to subtract both matrix
Lets find out A-B
Given matrices A and B are
[tex]A=\left[\begin{array}{ccc}4&7\\-3&8\\-5&-2\end{array}\right] \\B=\left[\begin{array}{ccc}-2&5\\7&-1\\-3&2\end{array}\right][/tex]
When we subtract A-B we need to subtract the corresponding elements in that matrix
[tex]A-B=\left[\begin{array}{ccc}4&7\\-3&8\\-5&-2\end{array}\right] -\left[\begin{array}{ccc}-2&5\\7&-1\\-3&2\end{array}\right]=\left[\begin{array}{ccc}4-(-2)&7-5\\-3-7&8-(-1)\\-5-(-3)&-2-2\end{array}\right] \\A-B=\left[\begin{array}{ccc}6&2\\-10&9\\-2&-4\end{array}\right][/tex]
The above is the resultant matrix .
Learn more: brainly.com/question/12579158
A firefighter holds a hose 3 m off the ground and directs a stream of water toward a burning building. The water leaves the hose at an initial speed of 16 m/sec at an angle of 300, The height of the water can be approximated by hx)0.02612 + 0.577x+ 3, where hcx) is the height of the water in meters at a point x meters horizontally from the firefighter to the building.
a. Determine the horizontal distance from the firefighter at which the maximum height of the water occurs Round to 1 decimal place. I decimal place branch of the parabola at a height of 6 m. How far is the
b. What is the maximum height of the water? Round to
c. The flow of water hits the house on the downward firefighter from the house? Round to the nearest meter
Answers
Answer:
a). Horizontal distance = 11.1 m
b). Maximum height = 6.2 m
c). Firefighter is 13.7 m from the house
Step-by-step explanation:
Given question is incomplete; find the complete question in the attachment.
Height of the water can be determined by the expression,
h(x) = -0.026x²+ 0.577x + 3
Here x = Horizontal distance of the from the firefighter
a). Since the stream of the water will follow a parabolic path, maximum point of the parabola will be = Vertex of the parabolic path
Horizontal distance from the firefighter at which the water achieves the maximum height = -[tex]\frac{b}{2a}[/tex]
From the quadratic function,
h(x) = -0.026x²+ 0.577x + 3
a = -0.026
b = 0.577
Therefore, the horizontal distance = [tex]-\frac{0.577}{2\times (-0.02612)}[/tex] = 11.05 m
≈ 11.1 meters
b). By putting x = 11.1 in the quadratic equation,
h(x) = -0.02612(11.1)²+ 0.577(11.1) + 3
= -3.2182 + 6.4047 + 3
= 6.18 m
≈ 6.2 m
c). For h(x) = 6 m
6 = -0.02612x² + 0.577(x) + 3
0.02612x² - 0.577x + 3 = 0
From quadratic formula,
x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
x = [tex]\frac{0.577\pm \sqrt{(-0.577)^2-4(0.02612)(3))}}{2(0.02612)}[/tex]
x = [tex]\frac{0.577\pm\sqrt{0.019489}}{0.05224}[/tex]
x = [tex]\frac{0.577\pm0.1396}{0.05224}[/tex]
x = 13.7 m, 8.37 m
Therefore, the farthest distance of the firefighter from the house will be 13.7 m
A study was conducted to determine whether magnets were effective in treating pain The values represent measurements of pain using the visual analog scale. Assume that both samples are independent simple random samples from populations having normal distributions. Use α= 0.05 significance level to test the claim that those given a sham treatment have pain reductions that vary more than the pain reductions for those treated with magnets.Sham: n=20,¯x=0.44,s=1.24 Magnet: n=20x=0.49,s=0.95a. Identify the test statistic. (Round to two decimal places as needed)b. Use technology to identify the P-value. (Round to three decimal places as needed)c. What is the conclusion for this hypothesis test?A. Reject H0. There is insufficient evidence to support the claim that those given a sham treatment have pain reductions that vary more than those treated with magnets.B. Reject H0. There is sufficient evidence to support the claim that those given a sham treatment have pain reductions that vary more than those treated with magnets.C. Fail to reject H0. There is sufficient evidence to support the claim that those given a sham treatment have pain reductions that vary more than those treated with magnets.D. Fail to reject H0. There is insufficient evidence to support the claim that those given a sham treatment have pain reductions that vary more than those treated with magnets.
Answers
Answer:
a. Test statistic t = -0.14
b. P-value = 0.443
c. D. Fail to reject H0. There is insufficient evidence to support the claim that those given a sham treatment have pain reductions that vary more than those treated with magnets.
Step-by-step explanation:
This is a hypothesis test for the difference between populations means.
The claim is that those given a sham treatment have pain reductions that vary more than the pain reductions for those treated with magnets.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2< 0[/tex]
The significance level is α=0.05.
The sample 1 (sham), of size n1=20 has a mean of 0.44 and a standard deviation of 1.24.
The sample 2 (magnet), of size n2=20 has a mean of 0.49 and a standard deviation of 0.95.
The difference between sample means is Md=-0.05.
[tex]M_d=M_1-M_2=0.44-0.49=-0.05[/tex]
The estimated standard error of the difference between means is computed using the formula:
[tex]s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{1.24^2+0.95^2}{20}}\\\\\\s_{M_d}=\sqrt{\dfrac{2.4401}{20}}=\sqrt{0.122}=0.3493[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-0.05-0}{0.3493}=\dfrac{-0.05}{0.3493}=-0.14[/tex]
The degrees of freedom for this test are:
[tex]df=n_1+n_2-2=20+20-2=38[/tex]
This test is a left-tailed test, with 38 degrees of freedom and t=-0.14, so the P-value for this test is calculated as (using a t-table):
[tex]P-value=P(t<-0.14)=0.443[/tex]
As the P-value (0.443) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that those given a sham treatment have pain reductions that vary more than the pain reductions for those treated with magnets.
someone help me out pls
Answers
Answer:
EF ≈ 3.8
Step-by-step explanation:
Using the Sine rule in Δ DEF
[tex]\frac{EF}{sin75}[/tex] = [tex]\frac{DE}{sin50}[/tex] , that is
[tex]\frac{EF}{sin75}[/tex] = [tex]\frac{3}{sin50}[/tex] ( cross- multiply )
EF × sin50° = 3 × sin75° ( divide both sides by sin50° )
EF = [tex]\frac{3sin75}{sin50}[/tex] ≈ 3.8
A college student wanted to estimate the average amount of time spent texting each day among college students. He randomly sampled 125 college students and asked them to keep track of how many minutes they spent texting (reading and writing texts) on a certain day. The average time spent texting in one day for the 125 in the study was 150 minutes. The population data is known to be right skewed. Determine if the following statement is true or false.
The condition that the distribution of sample means is normal is met.
The statement is:________.
Answers
Answer:
true
Step-by-step explanation:
3. A 12 % discount on a pair of washer and dryer that Gayle purchased, amounted to $156.00. Calculate the net price.
Answers
Answer:
For this case we know that the price after the 12% of discount is 156 and we want to findd the net price so then we can use the following proportional rule:
[tex] \frac{x}{100} = \frac{156}{100-12}[/tex]
Where x represent the net price. And if we solve for the value of x we got:
[tex] x= 100 *\frac{156}{88}= 177.273[/tex]
So then the net price for this case would be $ 177.273
Step-by-step explanation:
For this case we know that the price after the 12% of discount is 156 and we want to findd the net price so then we can use the following proportional rule:
[tex] \frac{x}{100} = \frac{156}{100-12}[/tex]
Where x represent the net price. And if we solve for the value of x we got:
[tex] x= 100 *\frac{156}{88}= 177.273[/tex]
So then the net price for this case would be $ 177.273
How many ways can a 4-person subcommittee be selected from a committee of 6 people? (B) How many ways can a president comma vice dash president comma secretary comma and treasurer be chosen from a committee of 6 people?
Answers
Answer:
A) 360
B) 360
Step-by-step explanation:
Part A)
Given that there are a total of 6 people and 4 person subcommittee is to be selected.
Number of ways to select 1st person = 6
Now, 1 person is selected, total persons left are 5
Number of ways to select 2nd person = 5
Now, 1 person is selected, total persons left are 4
Number of ways to select 3rd person = 4
Now, 1 person is selected, total persons left are 3
Number of ways to select 4th person = 3
So, total number of ways = 6[tex]\times[/tex]5[tex]\times[/tex]4[tex]\times[/tex]3 = 360
Part B)
Given that there are a total of 6 people in the committee
Number of ways to select president = 6
Now, 1 person is selected, total persons left are 5
Number of ways to select vice president = 5
Now, 1 person is selected, total persons left are 4
Number of ways to select secretary = 4
Now, 1 person is selected, total persons left are 3
Number of ways to select treasurer = 3
So, total number of ways = 6[tex]\times[/tex]5[tex]\times[/tex]4[tex]\times[/tex]3 = 360
which graph is the solution to lx| > 10? HELP PICTURE INCLUDED
Answers
Answer:
Its the first answer choice.
Step-by-step explanation:
Its open circle because the sign is just greater than. And since x is an absolute value, the negative sign doesnt matter so, it points to the right of 10 and to the left of -10.
The management of Acrosonic plans to market the ElectroStat, an electrostatic speaker system. The marketing department has determined that the demand for these speakers is represented by the following function, where p denotes the speaker's unit price (in dollars) and x denotes the quantity demanded. Find the following functions (in dollars), find the value (in dollars) and interpret your results.
p = −0.02x + 610 (0 ≤ x ≤ 20,000)
a. Find the revenue function R.
b. Find the marginal revenue function R'(x).
c. Compute the following value.
R'(5,400) = _______________
Answers
Answer:
(a)[tex]R(x)=-0.02x^2+610x[/tex]
(b)[tex]R'(x)=-0.04x+610[/tex]
(c)R'(5400)=$394
Step-by-step explanation:
Given that x is the quantity demanded and the speaker's unit price (in dollars) is p where:
p = −0.02x + 610 (0 ≤ x ≤ 20,000)
(a)Revenue function R.
Revenue = Price X Quantity Demanded
Therefore:
R(x)=xp
[tex]=x(-0.02x + 610)\\R(x)=-0.02x^2+610x[/tex]
(b)Marginal revenue function R'(x)
If [tex]R(x)=-0.02x^2+610x[/tex]
Then, the marginal revenue function
[tex]R'(x)=-0.04x+610[/tex]
(c)We want to compute R'(5,400)
[tex]R'(5400)=-0.04(5400)+610\\R'(5400)=394[/tex]
From the above, we can infer that the revenue that will be generated on the sales of the 5401st item is $394.
In a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (beforeminusafter) in their levels of LDL cholesterol (in mg/dL) have a mean of 2.7 and a standard deviation of 17.8. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?
Answers
The 90% confidence interval for the mean net change in LDL cholesterol after the garlic treatment is approximately -1.799 to 7.199, suggesting that the effectiveness of garlic in reducing LDL cholesterol is not statistically significant.
We have,
To construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment, we can use the formula:
CI = X ± (Z * (σ/√n))
where:
CI is the confidence interval
X is the sample mean
Z is the critical value corresponding to the desired confidence level (90% confidence level corresponds to Z = 1.645 for a large sample size)
σ is the population standard deviation
n is the sample size
Given that the sample mean X of the net change in LDL cholesterol is 2.7, the standard deviation (σ) is 17.8, and the sample size (n) is 47, we can calculate the confidence interval as follows:
CI = 2.7 ± (1.645 * (17.8/√47))
Calculating the standard error (SE):
SE = σ/√n = 17.8/√47 ≈ 2.587
Substituting the values into the confidence interval formula:
CI = 2.7 ± (1.645 * 2.587)
Calculating the upper and lower bounds of the confidence interval:
Upper bound = 2.7 + (1.645 * 2.587) ≈ 7.199
Lower bound = 2.7 - (1.645 * 2.587) ≈ -1.799
Therefore, the 90% confidence interval estimate for the mean net change in LDL cholesterol after the garlic treatment is approximately -1.799 to 7.199.
Interpreting the confidence interval:
Since the confidence interval contains both positive and negative values, it suggests that the effectiveness of garlic in reducing LDL cholesterol is not statistically significant.
The interval includes zero, indicating that there is a possibility that the mean net change in LDL cholesterol after the garlic treatment could be zero (no change).
However, it is important to note that further studies or a larger sample size may be needed to draw more definitive conclusions.
Thus,
The 90% confidence interval for the mean net change in LDL cholesterol after the garlic treatment is approximately -1.799 to 7.199, suggesting that the effectiveness of garlic in reducing LDL cholesterol is not statistically significant.
Learn more about confidence intervals here:
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The 90% confidence interval suggests that the true mean net change in LDL cholesterol after the garlic treatment lies between -1.57 and 6.97 mg/dL. Since the interval contains both positive and negative values, it indicates that the garlic treatment may or may not be effective in reducing LDL cholesterol.
What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?To construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment, we can use the formula:
CI = mean ± (Z * (standard deviation / √n))
Here, n represents the sample size (47), Z is the critical value corresponding to a 90% confidence level (Z = 1.645 for a 90% confidence level), and the mean is 2.7 with a standard deviation of 17.8.
Plugging in the values:
CI = 2.7 ± (1.645 * (17.8 / √47))
CI = 2.7 ± (1.645 * (17.8 / 6.856))
CI = 2.7 ± (1.645 * (2.596))
CI = 2.7 ± 4.270
CI = 2.7 + 4.270 ; CI = 2.7 - 4.270
CI = 6.97 ; CI = -1.57
Thus, the 90% confidence interval estimate for the mean net change in LDL cholesterol after the garlic treatment is approximately (-1.57, 6.97).
The confidence interval suggests that the effectiveness of garlic in reducing LDL cholesterol is inconclusive. The interval spans both positive and negative values, indicating that the true mean change in LDL cholesterol could be anywhere within this range. Further research or a larger sample size might be needed to draw a more definitive conclusion about the effectiveness of garlic in lowering LDL cholesterol.
Read more about confidence interval here: https://brainly.com/question/20309162
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No need of a answer anymore.
Answers
Answer:
mean score of class B = 1778/25 = 71.12
Step-by-step explanation:
This was your question : Class A has 12 pupils and class B has 25 pupils. Both classes sit the same maths test. The mean score for class A is 80. The mean score for both classes is 74. What is the mean score (rounded to 2 DP) in the maths test for class B?
mean of class A = Σfx/Σf
mean of class A = 80
Σfx = 80 × 12 = 960
Mean score for both classes = 74
where
b = Σfx of class B
960 + b/37 = 74
cross multiply
960 + b = 2738
b = 2738 - 960
b = 1778
mean score of class B = Σfx/Σf
Σfx = 1778
Σf = 25
Therefore,
1778/25 = 71.12
Geometric sequence find common ratio 0.45,0.9,1.8
Answers
Answer:
The common ratio is 2Step-by-step explanation:
To find the common ratio of the geometric sequence divide the previous term by the next term
That's
0.9 / 0.45 = 2
1.8 / 0.9 = 2
Therefore the common ratio is 2
Hope this helps you
Equations and functions
What’s the answer to this ? I’m haveing trouble
Answers
Answer:
B / px= k
Step-by-step explanation:
B = kpx
Divide each side by px
B / px= kpx/px
B / px= k
Answer:
First option
Step-by-step explanation:
B=kpx
B=k*(px)
Then,
[tex]k = \frac{b}{px} [/tex]
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. Nash's test. Which student has the higher standardized score
Answers
Answer:
Due to the higher z-score, David has the higher standardized score
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Which student has the higher standardized score
Whoever had the higher z-score.
David:
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So [tex]X = 52, \mu = 70, \sigma = 11[/tex]
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{52 - 70}{11}[/tex]
[tex]Z = -1.64[/tex]
Steven:
Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So [tex]X = 52, \mu = 64, \sigma = 6[/tex]
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{52 - 64}{6}[/tex]
[tex]Z = -2[/tex]
Due to the higher z-score, David has the higher standardized score
-3x + y = -6 Y= 1/2x-1
Answers
Answer:
Step-by-step explanation:
Given system of equations in the question are,
-3x + y = -6
y = [tex]\frac{1}{2}x-1[/tex]
We can rewrite these equation as,
-3x + y = -6
y = 3x - 6 ------(1)
Table of input-output values for this equation will be,
x 0 1 2 3 4
y -6 -3 0 3 6
y = [tex]\frac{1}{2}x-1[/tex] ------(2)
Table for this equation will be
x 0 2 4 6 8
y -1 0 1 2 3
By plotting these points on the graph we find (2, 0) is a common point in both the tables,
Therefore, (2, 0) is the only one solution of the given system of equations.
Exercise 9
The bedroom is similar to the bed. Find the perimeter of the bedroom to the nearest foot
Bedroom
7 ft
16 ft
15 ft
Answers
Answer:
56 ft
Step-by-step explanation:
Because the bedroom is similar to the bed we can write that
7 : 15 = 6 : x
x = 15*6/7 ≈ 12.86 ft
Perimeter of the bedroom is
15*2 + 12.86 *2 ≈ 56 ft