Please answer ASAP my assigned due tomorrow WORTH 15 POINTS

It wont let me just put the number

20.2

Answer:

20.2

Step-by-step explanation:

because 155 can be rounded to 200 and you can take the zeros off

Answer: FALSE

Step-by-step explanation:

Answer:

It should be -8 please let me know if I am right

Step-by-step explanation:

(2*3+7)+(1-2*3^2)-4*3

(6+7)+(-3^2)-12

13+-9-12

=-8

Answer:

Step-by-step explanation:

A solution is any value of a variable that makes the specified equation true. A solution set is the set of all variables that makes the equation true. The solution set of 2y + 6 = 14 is {4}, because 2(4) + 6 = 14.

Answer:

Solution

Step-by-step explanation:

To make the equation true, you need to have proof that it is correct. Therefore, a solution.

Answer:

1. [tex]-x \div 11 = \frac{-1}{11}x[/tex]

2. [tex]z \times -5 = -5x[/tex]

Hope this helped you!

(32°F − 32) × 5/9 = 0°C

Answer:

6 3/10.

Step-by-step explanation:

4 1/5 = 21/5

21/5 / 2/3

=21/5 * 3/2

= 63/ 10

=  6 3/10.

Answer:

70.4 is 80% of 88

Answer:

(3, 4, 6, 8, 11)

Step-by-step explanation:

The complement of a set are elements of a universal set that isn't present in the given set.

The universal set is  U = {3, 4, 5, 6, 7, 8, 9, 10, 11)

[tex]\left \{ 3,4,6,8,11 \right \}[/tex]

A set is a well-defined collection of objects.

The collection of all items in a certain context or theory is known as a universal set.

The complement of a set is the set that contains all of the universal set's elements that aren't found in the provided set.

[tex]U=\left \{ 3,4,5,6,7,8,9,10,11 \right \}[/tex]

Let [tex]A=\left \{ 5,7,9,10 \right \}[/tex]

Complement of set is [tex]\left \{ 3,4,6,8,11 \right \}[/tex]

For more information:

https://brainly.com/question/2332158?referrer=searchResults

Answer:

178

Step-by-step explanation:

Answer:

negotiating

Step-by-step explanation:

negotiating

Answer:

B. negotiating

Step-by-step explanation:

Answer:

total stick she has = 9*4 = 36

6 sticker is need in 1 page

so page required for 36 stickers = 36/6 = 6pages

Step-by-step explanation:

Answer:

true

i just anwwsered this one in my lessons

Answer:

When a ratio is written in fraction form, the fraction should be simplified. If it is an improper fraction, we do not change it to a mixed number. Because a ratio compares two quantities, we would leave a ratio as 41 instead of simplifying it to 4 so that we can see the two parts of the ratio.

Answer:

-60

Step-by-step explanation:

-42+3×(-6)

-42-(3×6)

-42-18

-60

Answer:

-2x cos x + 2 sin x + C

Step-by-step explanation:

∫ (2x sin x) dx

If u = 2x, then du = 2 dx.

If dv = sin dx, then v = -cos x.

∫ u dv = uv − ∫ v du

= 2x (-cos x) − ∫ (-cos x) (2 dx)

= -2x cos x + 2 ∫ cos x dx

= -2x cos x + 2 sin x + C

Answer:

[tex]\displaystyle \large{2 \sin x - 2x \cos x + C}[/tex]

Step-by-step explanation:

We are given the indefinite integral:

[tex]\displaystyle \large{\int {2x \sin x} \ dx }[/tex]

Using by-part method, we have to substitute u-term and dv appropriately.

By-part is an integration of product rules, when integrated the product rules of differentiation, we’ll obtain:

[tex]\displaystyle \large{\int {u} \ dv = uv - \int {v} \ du}[/tex]

Above is by-part method/formula.

Where 4 terms are presented:

Our main terms to substitute are u and dv which mean u-term has to be a function that’s differentiatable and dv has to be a function that’s integratable.

The main concept of by-part is to understand how to substitute appropriately which you can simply follow below:

LIATE

Stands for Logarithm, Inverse (Trigonometry), Algebraic, Trigonometric and Exponential.

These are in orders from first to last on what to let u-term first. That means logarithm functions must be the first to substitute themselves as u-term, so if you encounter a logarithmic function and a polynomial function, you must let u = logarithmic function while dv = polynomial.

In this case, we have 2x which is polynomial and sin(x) which is trigonometric. According to LIATE, we have to let Algebraic or Polynomial 2x be first to substitute as u-term, that means our dv is trigonometric sin(x).

Therefore, we have:

Now, substitute these terms in accordingly to formula of by-part.

[tex]\displaystyle \large{\int {2x \sin x} \ dx = 2x \cdot (-\cos x) - \int {-\cos x \cdot 2 \ dx}}\\ \displaystyle \large{\int {2x \sin x} \ dx = -2x \cos x + \int {2 \cos x \ dx}}\\ \displaystyle \large{\int {2x \sin x} \ dx = -2x \cos x + 2 \int {\cos x \ dx}}\\ \displaystyle \large{\int {2x \sin x} \ dx = -2x \cos x + 2 \cdot \sin x + C}\\ \displaystyle \large{\int {2x \sin x} \ dx = -2x \cos x + 2 \sin x + C}[/tex]

__________________________________________________

Summary

  Property

[tex]\displaystyle \large{ \int {k f(x)} \ dx = k \int{f(x)} \ dx \ \ \ \ \tt{(k \ \ \ is \ \ \ a \ \ \ constant.)}\\[/tex]

Only shown in explanation.

  By-Part

[tex]\displaystyle \large{\int u \ dv = uv- \int v \ du}[/tex]

  LIATE

The functions in order that should be u-term from first to last.

These functions above do not have integration formula by default.

  Indefinite Integral

Make sure to always add + C after evaluating the integral, regardless what multiplies or attempts to affect + C, we must always add + C.

__________________________________________________

Answer:

I think it would be angles A and B.

Hope this helps!

Answer:

Width = 8 m

Length = 32 m

Step-by-step explanation:

Width = w

Length = 4w

Perimeter = 80 m

2*(length +width) = 80

2 *(4w +w ) = 80

       2* 5w  = 80

           10w = 80

               w = 80/10

                w = 8 m

Width = 8 m

Length = 4 * 8 = 32 m

Answer:

$1.26 or $1.27 depending on whether you round up or down. The number in the thousandths is an 8 though

Step-by-step explanation:

You would divide 3.05 by itself to get one pound

and then 3.87 by 3.05. You have to divide both numbers so you get the number for one pound.

3.87÷3.05=1.268852459

Round up or down depending on what your teacher would want you to do so that the decimal is in the hundreths like money.

The reciprocal of 15 1/4 is 4/61

Step-by-step explanation:

15 1/4 multiply 15 by 4 and then add 1 it will give you 61/4 then you change into reciprocal which will be 4/61

Answer:

$91.07

Step-by-step explanation:

You cannot take off 9.8% from $100 to find the answer, since 9.8% of $100 is more tax than she will pay. The toy has to cost less than $100, so that when you add 9.8% tax the price you end up with exactly $100, and 9.8% of under $100 is less that 9.8% of $100. Maybe this is why you are a few cents off.

This is how you do it.

The price of the toy is unknown, so we'll cal it x.

When you add 9.8% tax to x, you want to end up with exactly $100.

x + 9.8% of x = 100

Write 9.8% as a decimal by dividing the percent by 100.

9.8% = 9.8/100 = 0.098

Now we have:

x + 0.098x = 100

Add like terms on the left side:

1.098x = 100

Divide both sides by 1.098:

x = 100/1.098

x = 91.07

Answer: The most expensive toy she can get costs $91.07 before tax.

Check:

We now add 9.8% tax to $91.07 and make sure the total cost including tax  is no more than $100.

$91.07 + 9.8% of $91.07 =

= $91.07 + 0.098 * $91.07

= $91.07 + $8.92

= $99.99

It seems that you could try to spend one more cent, to really get to the $100 limit, so let's try $91.08 as the most expensive toy she can buy.

We now add 9.8% tax to $91.08 and see what the total cost including tax is.

$91.08 + 9.8% of $91.08 =

= $91.08 + 0.098 * $91.08

= $91.08 + $8.93

= $100.01

You see that if Megan gets a $91.08 toy, with tax, the total cost is $100.01, which is over the $100 limit, so the answer is indeed $91.07.

Answer:   [tex]A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right][/tex]

Step-by-step explanation:

                  [tex]\left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right][/tex]

[tex]\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right][/tex]

[tex]Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right][/tex]

[tex]Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right][/tex]

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]7.5d = 2.5d[/tex]

Analyzing Lin's

[tex]\frac{7.5d}{2.5d} = \frac{2.5d}{2.5d}[/tex]

[tex]3 = 1[/tex]

This isn't a solution because [tex]3 \neq 1[/tex]

Analyzing Elena's

[tex]7.5d - 2.5d= 2.5d-2.5d[/tex]

[tex]5d = 0[/tex]

Divide through by 5

[tex]d = 0[/tex]

Hence;

Going by the analysis above; only Elena's  move will lead to a solution

Step-by-step explanation:

∫ 9 arctan(1/x) dx

If u = 9 arctan(1/x), then:

du = 9 / (1 + (1/x)²) (-1/x²) dx

du = -9 dx (1/x²) / (1 + (1/x²))

du = -9 dx / (x² + 1)

If dv = dx, then v = x.

∫ u dv = uv − ∫ v du

= 9x arctan(1/x) − ∫ -9x dx / (x² + 1)

= 9x arctan(1/x) + 9/2 ∫ 2x dx / (x² + 1)

= 9x arctan(1/x) + 9/2 ln(x² + 1)

Evaluate from x=1 to x=√3.

[9√3 arctan(1/√3) + 9/2 ln(3 + 1)] − [9 arctan(1) + 9/2 ln(1 + 1)]

[9√3 (π/6) + 9/2 ln(4)] − [9 (π/4) + 9/2 ln(2)]

(3π√3)/2 + 9/2 ln(4) − (9π/4) − 9/2 ln(2)

(6π√3)/4 + 9 ln(2) − (9π/4) − 9/2 ln(2)

(6π√3 − 9π)/4 + 9/2 ln(2)

Answer:

[tex]9\left(\frac{1}{2}\ln \left(2\right)-\frac{\pi }{4}+\frac{\pi }{2\sqrt{3}}\right)[/tex]

Step-by-step explanation:

We are given the integral 9 arctan(1/x)dx on the interval x[ from 1 to √3 ].

Now let's say that u = arctan(1/x). The value of 'du' would be as follows:

du = - x / (1 + x²) * dx

If we apply integration by parts, v = 1, and of course u = arctan(1/x):

=> 9x arctan(1/x) − ∫ -9x dx / (x² + 1)

=> 9[x arctan(1/x) - ∫ - x / (1 + x²) * dx] on the interval x[ from 1 to √3 ]

Let's now simplify the expression ' ∫ - x / (1 + x²) * dx':

=> (Take the constant out, in this case constant = - 1), - ∫ x / (1 + x²) * dx

=> (Apply u-substitution, where u = 1 + x²), - ∫ 1/2u * du

=> (Take constant out again, in this case 1/2), - 1/2 ∫ 1/u * du

=> (Remember that 1/u * du = In( |u| )), - 1/2In( |u| )

=> (Substitute back 'u = 1 + x²), - 1/2In| 1 + x² |

So now we have the expression '9[x arctan(1/x) + 1/2In| 1 + x² |]' on the interval x[ from 1 to √3 ]. Let's further simplify this expression;

[tex]9\left[x\arctan \left(\frac{1}{x}\right)+\frac{1}{2}\ln \left|1+x^2\right|\right]^{\sqrt{3}}_1\\\\=> 9\left[\frac{1}{2}\left(2x\arctan \left(\frac{1}{x}\right)+\ln \left|1+x^2\right|\right)\right]^{\sqrt{3}}_1[/tex]

Now computing the boundaries we have the following answer:

[tex]9\left(\frac{1}{2}\ln \left(2\right)-\frac{\pi }{4}+\frac{\pi }{2\sqrt{3}}\right)[/tex]