Physics- Static Equilibrium Please show work :(

A uniform, horizontal 300 N beam, 5.00 m long, is attached to a wall by a pin connection that allows the beam to rotate. Its far end is supported by a cable that makes an angle of 53.0° with the horizontal. If a 600 N person stands 1.50 m from the wall, find the tension in the cable and the force exerted on the beam by the wall

Answers

Answer 1

Answer:Given A uniform horizontal beam with a length of 8.00 m and a weight of 200 n is attached to a wall by a pin connection ( allows rotation). Its far end is supported by a cable that makes an angle of 53 degrees with the horizontal. If a 600 n person stands on the beam at 2.00 m from the wall , find the tension in the cable

Now the force acting on the beam are the gravitational force of earth and weight attached to a wall is 200 N which acts at centre. Also force of person standing is 600 N and force exerted is r and tension is T , also torque due to r is zero because it acts at the pivot point. So r = 0

Torque due to tension in the rope is sin 53 x 8.00 x T.

Torque due to force is 2.0 m x 600 N

The weight of beam acts in the centre since the beam is uniform.

So we have

sin 53 x 8.00 x T - 2 m x 600 N - 4 x 200 N = 0

8 .00 x 0.8 x T = 1200 + 800

0.64 T = 2000 N-m

T = 2000 / 0.64

T = 312.5 N

Explanation:

Answer 2

The tension in the cable and the force exerted on the beam by the wall will be 312.5 N and 1200N respectively.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem is;

L is the length 5.00 m long,

[tex]\rm \theta[/tex] is the angle of 53.0°

d is the distance =  1.50 m

T is the  tension in the cable

F is the force exerted on the beam by the wall= ?

Torque due to tension in the rope is

[tex]\rm \tau = 8.00 \times sin 53^0 \times T[/tex]

Force due to the torque will be;

F= 2.0 m x 600 N

F= 1200 N

The net tension is found as on applying the static equilibirium equation;

sin 53 x 8.00 x T - 2 m x 600 N - 4 x 200 N = 0

8 .00 x 0.8 x T = 1200 + 800

0.64 T = 2000 N-m

T = 2000 / 0.64

T = 312.5 N

Hence the tension in the cable and the force exerted on the beam by the wall will be 312.5 N and 1200N .

To learn more about the force refer to the link;

https://brainly.com/question/26115859


Related Questions

Which of these organisms is connected to all other organisms in a food web?
carnivores
herbivores
scavengers
decomposers

Answers

Answer:

I want to say decomposers, because they break down plants that the herbivores eat, and they can also decompose the remains of a scavenger, herbivore, OR carnivore, that was killed and eaten by a carnivore, and maybe even found and eaten by a scavenger. I'm sorry if it's not correct, that's just what my brain has decided right now

Answer:

The answer is number 4. Decomposers

Explanation:

Hope this helps!!

in of the Solar System
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Answer:

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Explanation:

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You are on a boat cruising at 10 m/s when you decide to accelerate at 5 m/s^2 until you reach a speed of 30 m/s.
How far did you travel during the acceleration

Answers

Answer:

Avg time (s) * Avg velocity (m/s) = Answer (m)

Can someone please help me I don’t understand this

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I think it’s a because it the only reasonable answer

If the resistance of a circuit is 3 ohms, and the voltage produced by the cell in the
circuit is 12 volts, what's the magnitude of the current?
0.25 amperes
09 amperes
36 amperes
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Answers

Answer:

The magnitude of the current is 4A (amperes).

Explanation:

We can use [tex]V=IR[/tex], where V stands for Voltage, I stands for current, and R stands for resistance to solve this problem.

A such:

[tex]V=12\\I=\text{ ?}\\R=3\\\\\text{Solve for I}:\\12=3I\\3I=12\\I=\frac{12}{3}\\I=4\text{A}[/tex]


The length of the track itself is 500m. The vehicles (each of mass 15kg) are dragged
along the track back to the top of the ride in stacks of 4. The force required to drag
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Use an equation from page 2 to calculate the total work done in dragging the stack
back to the start of the ride

Answers

Answer:

W = 100000 J = 100 KJ

Explanation:

Here we will use the most basic and general formula of work, which is as follows:

[tex]W = Fd[/tex]

where,

W = Work Done = ?

F = Force Required = 200 N

d = Length of Track = 500 m

Therefore,

[tex]W = (200\ N)(500\ m)\\[/tex]

W = 100000 J = 100 KJ

match the microscopes with their useable

Answers

Microscopes with life science and physics

Answer:

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Explanation:

but have a great day :D

Do you think it is possible to control the magnetic properties of a magnet? Can a magnet be turned on and off? Explain your answer.

Answers

Answer:

Yes it is possible to control to some extent

Explanation:

Yes it is possible to control to some extent. Explanation: In general there are two types of magnets : permanent and temporary (electromagnets). ... On the other hand permanent magnet cannot be switched on and off but the magnetic properties can be altered event to an extent when it loses all its magnetic properties.

WILL GIVE YOU WHAT EVER YOU WANT JUST HELP ME
Which of the following best compares the structures in protists and fungi that allow these organisms to explore their environment.

Question 2 options:

Protists and fungi move using cilia, flagella, and hyphae.




Some protists move using cilia and flagella. Fungi do not move but have fast growing hyphae.




Protists move using hyphae. Some fungi move using cilia, and flagella.


Neither protists nor fungi have cilia, flagella, and hyphae. They obtain energy only if the food source moves by them.


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Answers

Answer:

Explanation:

Essential Knowledge

It is essential that the student be able to distinguish between specialized structures that allow protists and fungi to obtain energy and explore their environment.

Protists

Protists are organisms that are classified into the Kingdom Protista. Although there is a lot of variety within the protists, they do share some common characteristics.

● Protists are usually single celled organisms.

● Live in moist environments.

● Vary in the ways they move and obtain energy.

Protists obtain their energy in several ways.

● Animal-like protists ingest or absorb food after capturing or trapping it.

● Plant-like protists produce food through photosynthesis.

● Fungus-like protists obtain their food by external digestion either as decomposers or as parasites.

● Some protists have both autotrophic and heterotrophic characteristi

The one which best compares the structure in protists and fungi that allow these organism to explore their environment is option B. Some protists move using cilia and flagella. Fungi do not move but have fast growing hyphae.

What are moving aids in protists and fungi ?

Protists are the eukaryotes that are not considered to be either fungi, animals, or plants. They are mainly tiny and unicellular. Many unicellular protists are motile and can move by employing flagella, cilia, or pseudopods, especially protozoans.

Cells that employ cilia for movement are typically referred to as ciliates, whereas those that use flagella are typically referred to as flagellates.

In marine, brackish, and freshwater reservoirs, hundreds of species of the ciliate genus Paramecium or flagellated Euglena can be found; the green alga Chlamydomonas is found in soil and freshwater all over the world.

Due of their inability to move, fungi produce spores that resemble seeds. These spores spread by the wind, animals, etc., and seek out new environments to flourish.

As the primary means of vegetative growth in the majority of fungi, hyphae are referred to as a mycelium. Therefore, option B is correct.

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Answers

Answer:

10 J

Explanation:

work = force x distance

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Joule is the unit for work

need help due in 30 mins​

Answers

Answer:

1. v₂ = 12.43 m/s

2. I₁ = - 80 N.s

3. I₂ = 80 N.s

Explanation:

Consider the following data given in the question:

m₁ = mass of the Cart 1 = 16 kg

m₂ = mass of the Cart 2 = 7 kg

u₁ = velocity of cart 1 before collision = 4 m/s

u₂ = velocity of cart 2 before collision = 1 m/s

v₁ = velocity of cart 1 after collision = - 1 m/s

v₂ = velocity of cart 2 after collision = ?

1.

Applying the law of conservation of momentum:

[tex]m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\(16\ kg)(4\ m/s)+(7\ kg)(1\ m/s)=(16\ kg)(-1\ m/s)+(7\ kg)(v_{2})\\v_{2} = \frac{87\ kg.m/s}{7\ kg}[/tex]

v₂ = 12.43 m/s

2.

Impulse of cart 1 = I₁ = m₁(v₁ - u₁)

I₁ = (16 kg)(- 1 m/s - 4 m/s)

I₁ = - 80 N.s

3.

Impulse of cart 2 = I₂ = m₂(v₂ - u₂)

I₂ = (7 kg)(12.43 m/s - 1 m/s)

I₂ = 80 N.s

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Answers

Answer:

13

Explanation:

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Answer:

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Explanation:

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Answers

The answer is Homeostasis

(b) The figure below shows a model train, travelling at speed , approaching a
buffer
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buffer
spring
The train, of mass 2.5 kg, is stopped by compressing a spring in the buffer.
After the train has stopped, the energy stored in the spring is 0.48 J.
Calculate the initial speed v of the train.


Answers

Answer:

0.62 m/s

Explanation:

Given that a model train, travelling at speed , approaching a buffer model train buffer spring

The train, of mass 2.5 kg, is stopped by compressing a spring in the buffer.

After the train has stopped, the energy stored in the spring is 0.48 J.

Calculate the initial speed v of the train

Solution

The total energy stored in the spring will be equal to the kinetic energy of the train.

That is,

1/2fe = 1/2mv^2

Substitutes the spring energy, and mass into the formula

0.48 = 1/2 × 2.5 × V^2

2.5V^2 = 0.96

V^2 = 0.96 / 2.5

V^2 = 0.384

V = sqrt ( 0.384 )

V = 0.62 m/s

Therefore, the initial velocity of the train is 0.62 metres per second.

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Answers

answer:

The muscles, joints and bones are adversely affected by immobility. The bones lose calcium as a result of the lack of weight bearing activity and this can lead to disuse osteoporosis, hypercalcemia, and fractures.

Suppose that it takes 0.6 seconds for a mass on a spring to move from its
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Answers

Answer:

1.2

Explanation:

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Answer:

650N

Explanation:

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USE THE PICTURE THANKS WILL GIVE B WRONG ANSWER=report lol love ya

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Wiley coyote pushes a 5kg boulder from an initial height of 10m, the boulder rolls down the hill, across the road, and up the hill on the left. The rock is able to reach a height of 17 m before rolling back down. How fast did Wiley have to push the rock to make this happen?

Answers

Answer:

  v = 11.7 m / s

Explanation:

For this exercise we can use the conservation of energy

starting point. Where you drop the stone

          Em₀ = K + U = ½ m v² + m g h₁

final point. Point where the stone arrives

          Em_f = U = mgh₂

We are assuming that there is no friction, so the energy is conserved

          Em₀ = Em_f

          ½ m v² + m g h₁ = m g h₂

         v² = 2g (h₂-h₁)

let's calculate

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Answers

Answer:

magnetic energy (proton) and magnetic plasma.

Explanation:

The solar fare consists of bright light that occurs in various wavelengths and is observed at the surface. They are not as strong as compared to the coronal mass ejection or CME. The solar fares consist of 10²² joules, while the plasma is ejected from the solar corona and can be clearly seen from a distance. The Solar flares represent an atmospheric disturbance and plasms are the medium for the growth and development of solar flare and lead to solar activity.

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Answers

Answer:

move less/slower

Explanation:


If unbalanced forces act on an object, how will it move?
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B.It will accelerate in the opposite direction of the net force.

Answers

a ! ! ! ! ! ! ! ! ! !

Answer:

A

Explanation:

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Answer: b

Explanation:

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Answers

Real images are those where light actually converges, whereas virtual images are locations from where light appears to have converged

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2. How does a solar eclipse happen?
3. Which one occurs more often?

Answers

Answer:

1.lunar eclipse- happen when Earths shadow block the sun light

2.solar eclipse-A solar eclipse occurs when a portion of the Earth is engulfed in a shadow cast by the Moon which fully or partially blocks sunlight

3. lunar and solar eclipses occur with about equal frequency. Lunar eclipses are more widely visible because Earth casts a much larger shadow on the Moon during a lunar eclipse than the Moon casts on Earth during a solar eclipse. As a result, you are more likely to see a lunar eclipse than a solar eclipse.

Explanation:

The compass is a small bar magnet that’s free to spin. Based on what you observed, is the coil of wire with current passing through it a magnet?

Answers

Answer:

People have been aware of magnets and magnetism for thousands of years. The earliest records date back to ancient times, particularly in the region of Asia Minor called Magnesia—the name of this region is the source of words like magnet. Magnetic rocks found in Magnesia, which is now part of western Turkey, stimulated interest during ancient times. When humans first discovered magnetic rocks, they likely found that certain parts of these rocks attracted bits of iron or other magnetic rocks more strongly than other parts. These areas are called the poles of a magnet. A magnetic pole is the part of a magnet that exerts the strongest force on other magnets or magnetic material, such as iron. For example, the poles of the bar magnet shown in Figure 20.2 are where the paper clips are concentrated.

A bar magnet with paper clips attached to it.

Figure 20.2 A bar magnet with paper clips attracted to the two poles.

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Answer:

Yes, the coil of wire with current passing through it is a magnet.

Explanation:

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