PHMWMHWPTYSM(15 points)

Chlorine is a halogen, not a noble gas.

The last two groups of the periodic table is named as halogen family and Nobel gas family.

The group 17 is composed of gases collectively called as halogen and it includes the following gases:

Fluorine

Chlorine

Bromine

Iodine

Astatine

Tennessine

The group 18 is composed of elements which are collectively called as Nobel gas and it includes:

Helium

Neon

Argon

Krypton

Xenon

Radon

Oganesson

these are some

Hope this helped!!

Answer:

Some nutrients also act as antioxidants. These may be vitamins, minerals, proteins, or other types of molecules. They help the body remove toxic substances known as free radicals, or reactive oxygen species. If too many of these substances remain in the body, cell damage and disease can result.

Answer:

Explanation:

Ratio of mass of C , N , H and O

= .8007 :0.9333:0.2016:2.133

Ratio of moles of C , N , H and O

= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16

= .0667 : .0667: .2016 : .1333

= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667

= 1 : 1 : 3: 2

Hence empirical formula = CNH₃O₂

7 .

Weight of titanium Ti = 1.916 g

Weight of oxygen = 3.196 - 1.916 = 1.28 g

Ratio of weight of Ti and O

= 1.916 : 1.28

Ratio of moles  of Ti and O

1.916/48 : 1.28/16  [ Molecular  weight of Titanium is 48 ]

= .04 : .08

= .04/.04 : .08/.04

= 1 :2 .

Empirical formula

TiO₂

Answer:

1.281 Latm/molK

Answer: Metalloids

Explanation:

The dark “stair step” line on the right side of the periodic table is where the metalloids are. Metalloids “touch” the SSL. (Stair step line)

The metals are to the left of the SSL and the non metals are to the right of the SSL.

Answer:

The empty space between the atomic cloud of an atom and its nucleus is just that: empty space, or vacuum. ... Electrons are thus 'spread out' quite a bit in their orbits about the nucleus. In fact, the wave-functions for electrons in s-orbitals about a nucleus actually extend all the way down into the nucleus itself.

Answer:

Cup of volume [tex]0.0675[/tex] cubic centimeter is required

Explanation:

Given

Density of the Cup [tex]= 1.325[/tex] g/cm^3

Total weight of the chocolates [tex]= 20,000[/tex] mg or 20 grams

Density is equal to mass divided by volume

Volume of the chocolates

[tex]\frac{1.325}{20} \\= 0.0675[/tex] cubic centimeter

Answer:

Sugar dissolves in water because energy is given off when the slighty polar sucrose molecules form intermoleeular bonds with the polar water molecules.

Explanation:

Answer:

PORS U N DISOLVENTE ELAGA YU E LAZUCR UAE SOLN TOU

Explanation:

Answer:

7

Explanation:

just add p has 1 o has 4 and h has 2

Answer:

aajajjajajajajajajajajdsjsjjx jajajjajajajajaisjn

Explanation:

Answer:

Explanation:

Hehs

Answer:

52.2 g

Explanation:

Step 1: Write the balanced equation

3 KOH + H₃PO₄ ⟶ K₃PO₄ + 3 H₂O

Step 2: Calculate the moles corresponding to 89.7 g of KOH

The molar mass of KOH is 56.11 g/mol.

89.7 g × 1 mol/56.11 g = 1.60 mol

Step 3: Calculate the moles of H₃PO₄ needed to react with 1.60 moles of KOH

The molar ratio of KOH to H₃PO₄ is 3:1. The moles of H₃PO₄ needed are 1/3 × 1.60 mol = 0.533 mol.

Step 4: Calculate the mass corresponding to 0.533 moles of H₃PO₄

The molar mass of H₃PO₄ is 97.99 g/mol.

0.533 mol × 97.99 g/mol = 52.2 g

Answer: MCCCMC

Please. Mark as brainliest

The option A describes an exothermic reaction.

i.e, ΔHt,reactant > ΔHt, product

The reaction in which energy is release during the formation of reaction is called exothermic reaction.

Mathematically,

ΔHf = ΔH(product) - ΔH(reactant)

For exothermic reaction, ΔHt,reactant > ΔHt, product

So,for exothermic reaction, ΔHf is negative.

Where,

ΔHf = Enthalpy of formation of reaction

ΔH(product) = enthalpy of formation of product

ΔH(reactant) = enthalpy of formation of reactant

To learn more about exothermic reaction here.

https://brainly.com/question/10373907

#SPJ3

Answer:

my network was gone so I cant

Answer:

Diatomic. molecule

hope it helps

and yr day will be full of happiness

(つ ◕.◕ )つ Hey there again!

Answer → Last one Spreading Plates on the Sea Floor

✨Hope this helps✨

Answer:  a) [tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]

b) 4.00 L of [tex]H_2O[/tex] will be produced

Explanation:

a) The balanced chemical reaction is:

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]

b) According to avogadros law, equal moles of gases occupy equal volumes at same temperature and presure conditions.

According to stoichiometry :

2 L of [tex]H_2[/tex] require  = 1 L of [tex]O_2[/tex]

Thus 4.00 L of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 4.00=2.00L[/tex]  of [tex]O_2[/tex]

Thus [tex]H_2[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.

As 2 L of [tex]H_2[/tex] give = 2 L of [tex]H_2O[/tex]

Thus 4.00 L of [tex]H_2[/tex] give =[tex]\frac{2}{2}\times 4.00=4.00L[/tex]  of [tex]H_2O[/tex]

Thus 4.00 L of [tex]H_2O[/tex] will be produced

a. The balanced reaction for the process should be 2h_2(g) + O_2(g) ⇒2H_2O(g)

b. The number of liters of water vapor should be 4.00 liters of H_2O.

a. The balanced reaction for the process should be 2h_2(g) + O_2(g) ⇒2H_2O(g)

b. As per the law, the equal moles of gases occupied equal volumes at the similar temperature

So, the number of liters should be

= 2/2*4.00

= 4.00 of H_2O

Learn more about the reaction here: https://brainly.com/question/4417455

Answer: Thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat is the flow of thermal energy. ... This energy is usually in the form of low-level thermal energy. Here, low-level means that the temperature associated with the thermal energy is close to that of the environment. hope this helps. Can u pls give me brainliest

Explanation:

Answer:

b tissues,cells,organs,organ system,organisms,populations

Tissues, Cells, Organs, Organ Systems, Organsims, Population. the correct answer is B

Answer:

rough surface

Explanation:

Diffuse reflection occurs when parallel light waves strike a rough surface

Answer:

Rippling fountain

Explanation:

Answer:

Weak acids and weak bases are only partially dissociated.

Explanation:

When a small amount of an acid or a base is added to water (or a solution of some strong acid or base of some certain [tex]pH \![/tex],) the [tex]pH[/tex] of that solution tends to change significantly.

In contrast, when the same amount of acid or base is added to a buffer system of some certain [tex]pH\![/tex], the [tex]pH[/tex] of this system tends to change by a much smaller amount.

Weak acids and weak bases dissociate only partially. That allows the buffer solutions to contain a large reservoir of both the (undissociated) weak acid (or weak base) and the corresponding conjugate ion, while maintaining the required [tex]pH[/tex].

This reservoir of the partially-dissociated weak acid (or weak base) and its conjugate ion allows the buffer system to absorb [tex]\rm H^{+}[/tex] and [tex]\rm OH^{-}[/tex] that were added to the solution without much change to the [tex]pH[/tex].

For example, consider a [tex]1\; \rm L[/tex] buffer solution that initially included [tex]0.1\; \rm mol[/tex] of acetic acid [tex]\rm CH_3COOH[/tex] (a weak acid with [tex]pK_\text{a} = 4.765[/tex]) and [tex]0.1\; \rm mol\![/tex] of sodium acetate [tex]\rm CH_3COONa[/tex]. The [tex]pH[/tex] of this solution would be [tex]4.765[/tex].

In contrast, if a solution of [tex]\rm HCl[/tex] (a strong acid) and an equal amount of [tex]\rm NaCl[/tex] also needs to be [tex]4.765[/tex], only [tex]10^{-4.765}\; \rm mol \approx 0.0000172\; \rm mol[/tex] of each species could be included.

Assume that [tex]0.001\; \rm mol[/tex] of [tex]{\rm NaOH}\, (s)[/tex] is added to the buffer solution of [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COONa[/tex]. The quantity of the partially-dissociated weak acid in this solution is much larger than that of the [tex]\rm OH^{-}[/tex] added to the solution.

Only a small portion of the weak base would be consumed.The [tex]pH[/tex] of the solution would likely change by less than [tex]0.001[/tex].

In contrast, assume that [tex]0.001\; \rm mol[/tex] of [tex]{\rm NaOH}\, (s)[/tex] is added to the [tex]1\; \rm L[/tex] solution with [tex]0.0000172\; \rm mol[/tex] of [tex]\rm HCl[/tex] (fully-dissociated) and [tex]\rm NaCl[/tex].

All the [tex]\rm HCl\![/tex] in this solution would be consumed. The [tex]pH[/tex] of this solution would go well above [tex]7[/tex].

Answer:

Weak acids and weak bases are partially dissociate

Explanation:

I took the test and got 100%

Answer:

2000 (km)

Explanation:

:)

Answer:

110 g

Explanation:

Step 1: Write the balanced equation for the decomposition of calcium carbonate

CaCO₃(s) ⇒ CaO(s) + CO₂(g)

Step 2: Convert 260.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 260.0 + 273.15 = 533.2 K

Step 3: Calculate the moles of CO₂ produced

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T = 1 atm × 48.0 L/0.0821 atm.L/mol.K × 533.2 K = 1.10 mol

Step 4: Calculate the moles of CaCO₃ that reacted to produce 1.10 moles of CO₂

The molar ratio of CaCO₃ to CO₂ is 1:1. The moles of CaCO₃ that reacted are 1/1 × 1.10 mol = 1.10 mol.

Step 5: Calculate the mass corresponding to 1.10 moles of CaCO₃

The molar mass of CaCO₃ is 100.09 g/mol.

1.10 mol × 100.09 g/mol = 110 g

Answer: B

Explanation:

A is evaporation. B is condensation. C is precipitation.

Answer:

it would be b

Explanation:

b would be condensation

Answer: it decreases because it reacts with hydronium ions that form during exercise

Explanation: 100% on edge

Answer:

B: it decreases because it reacts with hydronium ions that form during exercise

Explanation: