Persistent pulmonary hypertension of the newborn (PPHN) is characterized by elevated pulmonary vascular resistance resulting in right-to-left shunting of blood and hypoxemia. PPHN is often secondary to parenchymal lung disease (such as meconium aspiration syndrome, pneumonia or respiratory distress syndrome) or lung hypoplasia (with congenital diaphragmatic hernia or oligohydramnios) but can also be idiopathic. The diagnosis of PPHN is based on clinical evidence of labile hypoxemia often associated with differential cyanosis. The diagnosis is confirmed by the echocardiographic demonstration of – (a) right-to-left or bidirectional shunt at the ductus or foramen ovale and/or, (b) flattening or leftward deviation of the interventricular septum and/or, (c) tricuspid regurgitation, and finally (d) absence of structural heart disease. Management strategies include optimal oxygenation, avoiding respiratory and metabolic acidosis, blood pressure stabilization, sedation and pulmonary vasodilator therapy. Failure of these measures would lead to consideration of extracorporeal membrane oxygenation (ECMO); however decreased need for this rescue therapy has been documented with advances in medical management. While trends also note improved survival, long-term neurodevelopmental disabilities such as deafness and learning disabilities remain a concern in many infants with severe PPHN.

Answers

Answer 1

The echocardiographic demonstration of the right-to-left or bidirectional shunt at the ductus or foramen ovale, flattening or leftward deviation of the interventricular septum and/or tricuspid regurgitation confirms the diagnosis of Persistent pulmonary hypertension of the newborn (PPHN).

PPHN stands for persistent pulmonary hypertension of the newborn. This is a severe and potentially life-threatening lung condition that affects infants. This occurs when the circulation changes after birth. As a result, blood flow bypasses the baby's lungs, decreasing the baby's oxygen levels.

PPHN diagnosisThe diagnosis of PPHN is confirmed by the echocardiographic demonstration of:

a) right-to-left or bidirectional shunt at the ductus or foramen ovale and/or

b) flattening or leftward deviation of the interventricular septum and/or

c) tricuspid regurgitation, and finally

d) absence of structural heart disease.

Management of PPHN- Management strategies include optimal oxygenation, avoiding respiratory and metabolic acidosis, blood pressure stabilization, sedation, and pulmonary vasodilator therapy.

However, decreased need for this rescue therapy has been documented with advances in medical management. If these measures fail, extracorporeal membrane oxygenation (ECMO) should be considered. Despite trends towards improved survival, many infants with severe PPHN suffer long-term neurodevelopmental disabilities such as deafness and learning disabilities.

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Related Questions

help please
These questions cover Sections 1-2 of Keystone Predator. Q5.1.Recall that some species in the intertidal zone are mobile,while others are sessile stationary),and this affects how individuals compete with each other.Which of the following compete for space on intertidal rocks? Algae and Starfish Mussels,Whelk,and Chiton Algae and Barnacles Whelk and Starfish

Answers

Algae and barnacles are the species that compete for space on intertidal rocks in the intertidal zone. Among the given options, the correct choice is "Algae and Barnacles."

Algae, which are photosynthetic organisms, can attach themselves to rocks and other substrates in the intertidal zone. They compete for space by occupying available surfaces on the rocks, utilizing light and nutrients to grow and reproduce.

Barnacles, on the other hand, are sessile crustaceans that also attach themselves to hard surfaces, including intertidal rocks. They have a conical-shaped shell and extend feeding appendages known as cirri to filter and capture food particles from the water.

Both algae and barnacles compete for space on intertidal rocks as they strive to secure suitable locations for attachment and maximize their access to necessary resources. This competition is driven by their need for light, water movement, and access to nutrients for growth and survival.

While the other options presented in the question involve species found in the intertidal zone, they do not directly compete for space on intertidal rocks:

Starfish and whelk are mobile species rather than stationary organisms. While they may interact with other organisms in the intertidal zone, their movement allows them to access different habitats and food sources, rather than competing for space on rocks.

Mussels, whelk, and chiton are mentioned together as a group, but they do not specifically compete for space on intertidal rocks. Mussels, for instance, tend to attach themselves to various substrates, including rocks, but they do not directly compete with algae and barnacles for space on the same rocks.

In conclusion, among the options provided, algae and barnacles are the species that compete for space on intertidal rocks. Understanding the dynamics of competition in the intertidal zone helps us comprehend the complex relationships between organisms and how they adapt to their environment.

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Which of the following explains the suppression of lactation during pregnancy?*
A -Blood prolactin levels are too low for milk production to occur.
B -The fetal adrenal gland does not produce sufficient estriol.
C-Blood levels of estrogen and progesterone are high.
D- The maternal anterior pituitary is suppressed.
why answer is c not A ?

Answers

Lactation is the process of producing and discharging milk from the mammary glands of a woman. The hormone prolactin is responsible for lactation. During pregnancy, estrogen and progesterone levels increase, which is why a woman’s breast size increases.

The level of estrogen and progesterone in the bloodstream rises dramatically during pregnancy. These hormones are responsible for blocking milk production. They cause the cells that produce milk to stop working, and they keep the milk ducts from growing. This keeps milk from being produced, preventing lactation.Prolactin is a hormone produced in the anterior pituitary gland that is responsible for lactation. The high levels of estrogen and progesterone suppress prolactin production, preventing milk production. As a result, during pregnancy, the maternal anterior pituitary is suppressed.

Thus, the suppression of lactation during pregnancy is explained by the high levels of estrogen and progesterone. Option C is the correct option.

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Ardipithecus ramidus lacked the specialized teeth seen in living apes (such as exaggerated canines). Like later Homo species this accounts for their ability to target a broad set of resources. At the same time the species maintained an opposable toe as is seen in living great ape species. This suggests that Ardipithecus specimens could be considered a _______

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Ardipithecus ramidus lacked the specialized teeth seen in living apes, and like later Homo species, it had the ability to target a broad set of resources. At the same time, it maintained an opposable toe, as seen in living great ape species. This suggests that Ardipithecus specimens could be considered a hybrid.

Ardipithecus specimens could be considered a hybrid because they exhibited features of both early hominids and apes.

The ability to adapt to the environment by targeting a broad set of resources indicates a more versatile diet, allowing them to thrive and survive.

Additionally, the presence of an opposable toe was an important adaptation for climbing trees in their arboreal environment.

Therefore, the correct answer is "hybrid" since Ardipithecus specimens possessed features of both early hominids and apes.

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Which pathways are responsible for producing the substrates for
fatty acid synthesis?

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There are multiple pathways that are responsible for producing the substrates for fatty acid synthesis. The primary pathway is the de novo synthesis pathway.

In this pathway, fatty acids are synthesized from simple precursors, such as acetyl-CoA and malonyl-CoA, which are produced in the mitochondria and the cytoplasm. The de novo synthesis pathway is regulated by the enzyme acetyl-CoA carboxylase (ACC), which catalyzes the conversion of acetyl-CoA to malonyl-CoA. This enzyme is regulated by a variety of factors, including insulin, glucagon, and AMPK.

Another pathway that is responsible for producing the substrates for fatty acid synthesis is the glycolysis pathway. In this pathway, glucose is metabolized to produce pyruvate, which is then converted to acetyl-CoA. Acetyl-CoA can then be used in the de novo synthesis pathway to produce fatty acids.

In addition to these pathways, there are other pathways that can contribute to the production of substrates for fatty acid synthesis, including the pentose phosphate pathway and the TCA cycle. Overall, fatty acid synthesis is a complex process that involves multiple pathways and enzymes. The production of substrates for fatty acid synthesis is tightly regulated by a variety of factors, and disruption of this regulation can lead to a variety of metabolic disorders.

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Write a short essay explaining the importance of glucagon in the
regulation of intermediate metabolism. In your answer make
reference to the key metabolic pathways that glucagon regulates.
200 marks

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Glucagon plays a vital role in the regulation of intermediate metabolism. It is a peptide hormone produced by the alpha cells of the pancreas. Glucagon functions in opposition to insulin and helps maintain glucose homeostasis by stimulating several key metabolic pathways:

Glycogenolysis: Glucagon activates the breakdown of glycogen into glucose, primarily in the liver. This process increases blood glucose levels during periods of fasting or low blood sugar.

Gluconeogenesis: Glucagon promotes gluconeogenesis, the synthesis of glucose from non-carbohydrate sources such as amino acids and glycerol. This occurs primarily in the liver, ensuring a steady supply of glucose for energy production.

Lipolysis: Glucagon stimulates the breakdown of triglycerides stored in adipose tissue, releasing fatty acids into the bloodstream. These fatty acids can be used as an energy source, particularly by tissues such as muscle.

Ketogenesis: Glucagon enhances ketone body synthesis in the liver. Ketone bodies serve as an alternative fuel source for various tissues, including the brain, during prolonged fasting or carbohydrate restriction.

Overall, glucagon acts as a counter-regulatory hormone to insulin, ensuring the availability of glucose and energy substrates during periods of low blood sugar or increased energy demand. Its regulation of glycogenolysis, gluconeogenesis, lipolysis, and ketogenesis is crucial for maintaining metabolic balance and energy homeostasis in the body.

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Match the body cavities that have to be opened during the surgical procedures listed below. Note that more than one choice may apply. Choose the innermost cavity applicable to the procedure. Answer choices may be used more than once or may not be used at all. Removal of a brain tumor vertebral cavity Appendix removal pleural cavity triple bypass heart surgery dersal.cavity Removal of a section of ventral cavity. lung tubal ligation ("having your tubes tied") pericardial cavity

Answers

Body cavities opened during surgical procedures are quite important. During surgical procedures, various body cavities may need to be opened. Different types of surgical procedures are required for different types of medical conditions.

The different body cavities opened during surgical procedures are as follows: Removal of a brain tumor - Dorsal cavityAppendix removal - Ventral cavityTriple bypass heart surgery - Pericardial cavityRemoval of a section of the lung - Pleural cavityTubal ligation - Abdominopelvic cavity. Therefore, a brain tumor removal involves the opening of the dorsal cavity.

Removal of the appendix requires opening of the ventral cavity. Triple bypass heart surgery requires opening of the pericardial cavity. Removal of a section of the lung requires opening of the pleural cavity. Lastly, tubal ligation involves the opening of the abdominopelvic cavity.

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Most bacteria cannot cause disease solely by adhering to and colonizing the body. Instead, they must invade the host tissue Coagulase is a virulence factors, describe its function in the invasiveness of the pathogen _______.
Question 16 (3.5 points) Most bacteria cannot cause disease solely by adhering to and colonizing the body. Instead, they must invade the host tissue Hyaluronidases a widence factors describe its function in the invasiveness of the pathogen ______

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Coagulase is a virulence factor that plays a crucial role in the invasiveness of certain pathogens. It promotes the formation of blood clots, which can help protect bacteria from the immune system and facilitate their spread within the host.

Coagulase is an enzyme produced by certain bacteria, notably Staphylococcus aureus. Its primary function is to promote the conversion of fibrinogen (a soluble protein) into fibrin (an insoluble protein), leading to the formation of blood clots.

In the context of bacterial pathogenesis, coagulase contributes to the invasiveness of the pathogen. When bacteria secrete coagulase, it triggers the formation of a protective layer of fibrin around the bacteria, creating a barrier that shields them from the host's immune defenses. This fibrin clot helps the bacteria evade phagocytosis by immune cells and can facilitate their dissemination within the host's body.

Moreover, the fibrin clot also serves as a nidus for bacterial colonization and biofilm formation. The bacteria can attach to the fibrin meshwork and establish a stable community, enabling them to persist and cause further damage to the host tissue.

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Define the medical condition 'deep vein thrombosis' in terms of the structure formed and common location of thrombus development. Include in your response the vital organ where complications could arise if the thrombus (or a piece of it) breaks away, and briefly outline the seriousness of this complication. Which 3 factors (3 broad categories or circumstances) could contribute to venous thrombosis development?

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Three factors that could contribute to venous thrombosis development include the following:1. Prolonged immobility, 2. Blood flow changes, 3. Blood clotting factors.

Deep vein thrombosis (DVT) is a medical condition where a blood clot or thrombus forms inside one or more of the deep veins in the body, usually in the leg. This condition arises when the blood flow slows down or stops, allowing the platelets to clump and form a clot. The most common location of thrombus development in deep vein thrombosis is in the lower leg. When a piece of a thrombus breaks away, it can travel through the bloodstream to the lungs, causing a life-threatening condition known as pulmonary embolism. The lungs are the vital organ where complications could arise if the thrombus (or a piece of it) breaks away. Pulmonary embolism occurs when a blood clot that originated in the leg travels through the veins to the lungs.

This condition is potentially fatal and requires immediate medical attention. The seriousness of this complication can cause chest pain, shortness of breath, and sudden death in severe cases. Three factors that could contribute to venous thrombosis development include the following:1. Prolonged immobility: Being bedridden for an extended period, having long plane flights, or sitting for a long time can lead to sluggish blood flow, increasing the risk of developing DVT.2. Blood flow changes: Some factors, such as injury, surgery, or infection, can damage the blood vessels, making them more susceptible to forming a blood clot.3. Blood clotting factors: Individuals with genetic conditions or family history of blood clotting disorders are at higher risk of developing DVT. Hormonal changes, such as pregnancy, estrogen-based birth control pills, and hormone replacement therapy, can also increase the risk of blood clotting.

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In the fruit fly Drosophila, white eye color is a X-linked recessive trait. A male fruit fly with red eye color (unaffected) is mated with a female fruit fly with white eye color (affected).
What are the genotypes, phenotypes, genotypic ratio, and phenotypic ratio?
Use the following to represent the given: (use punnett square)
Sex chromosomes - X, Y
E - red eye color
e - white eye color

Answers

The male fruit fly is likely to have the genotype XEY, representing red eye color, while the female fruit fly is likely to have the genotype XeXe, representing white eye color.

The genotypic ratio of the offspring is predicted to be phenotypes 1 XEY: 1 XeXe, and the phenotypic ratio is expected to be 1 red eye: 1 white eye.

Since white eye color is a recessive trait on the X chromosome in Drosophila, the male fruit fly with red eye color must have at least one dominant allele for eye color, represented by XE. As a male, he has one X chromosome (from the mother) and one Y chromosome (from the father). Therefore, his genotype can be represented as XEY.

The female fruit fly with white eye color is affected by the recessive allele and must be homozygous for the recessive allele, represented by XeXe. As a female, she has two X chromosomes (one from each parent).

When the male and female are crossed, their potential offspring can be represented using a Punnett square. The possible genotypes are XEY and XeXe, resulting in a genotypic ratio of 1 XEY: 1 XeXe. The phenotypic ratio corresponds to the genotype ratio, so it is also 1 red eye: 1 white eye.

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DNA damage can cause the cell cycle to halt at A any phase except the M phase. B M phase only S phase only G1 phase only E G2 phase only

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The correct answer is E) G2 phase only. DNA damage triggers various cellular responses to ensure accurate repair before cell division proceeds.

In the cell cycle, the G2 phase serves as a checkpoint where DNA damage can induce a temporary halt. This pause allows time for DNA repair mechanisms to fix any damage before the cell progresses into mitosis (M phase). The G2 checkpoint monitors DNA integrity and activates signaling pathways that delay the progression of the cell cycle, preventing the damaged DNA from being replicated or passed on to daughter cells. In contrast, the other phases of the cell cycle (M phase, S phase, and G1 phase) do not typically exhibit a specific checkpoint for DNA damage-induced arrest.

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Which of the following are likely to lead to reproductive isolation? (Select all the apply) A lion and a tiger mate in the artificial confines of a zoo but the offspring is infertile Fruit flies on one Hawaiian island live for hundreds of generations and do not regularly come into contact with fruit flies on other islands One brood of the seventeen-year cicada emerged in 1987 (and will do so every 17 years) and lives a few months as adults; another brood emerged in 1992 (and will do so every 17 years); the larvae of both feed side-by-side on tree roots Two populations of crickets are indistinguishable in physical features, but the females in each group only come to the different songs of their males

Answers

Reproductive isolation is the process by which different species are formed. It happens when individuals within a population can no longer mate successfully with each other.

Therefore, the offspring of any such attempts are either infertile or less fit, decreasing their likelihood of surviving and producing offspring of their own. The following are likely to lead to reproductive isolation: When a lion and a tiger mate in the artificial confines of a zoo, the offspring is infertile, which is due to hybridization, and they do not constitute a species of their own.

Fruit flies on one Hawaiian island live for hundreds of generations and do not regularly come into contact with fruit flies on other islands. It is also known as geographic isolation or allopatric speciation. As a result of geographic separation, genetic drift and natural selection act independently on the separated populations, making it more difficult for the populations to mate with each other, resulting in reproductive isolation. One brood of the seventeen-year cicada emerged in 1987 (and will do so every 17 years) and lives a few months as adults; another brood emerged in 1992 (and will do so every 17 years); the larvae of both feed side-by-side on tree roots.

It is an example of temporal isolation, which occurs when two or more groups of organisms reproduce at different times. Two populations of crickets are indistinguishable in physical features, but the females in each group only come to the different songs of their males. It is also known as behavioral isolation, and it occurs when two populations are capable of mating but have different mating rituals or signals, and therefore do not mate with each other. The answer to the given question is as follows:

A lion and a tiger mate in the artificial confines of a zoo but the offspring is infertile, Fruit flies on one Hawaiian island live for hundreds of generations and do not regularly come into contact with fruit flies on other islands, One brood of the seventeen-year cicada emerged in 1987 (and will do so every 17 years) and lives a few months as adults; another brood emerged in 1992 (and will do so every 17 years); the larvae of both feed side-by-side on tree roots, and Two populations of crickets are indistinguishable in physical features, but the females in each group only come to the different songs of their males.

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Suppose you found an overly high level of pyruvate in a patient's blood and urine. One possible cause is a genetic defect in the enzyme pyruvate dehydrogenase, but another plausible cause is a specific vitamin deficiency. Explain what vitamin might be deficient in the diet, and why that would account for high levels of pyruvate to be excreted in the urine. How would you determine which explanation is correct?

Answers

If you found an overly high level of pyruvate in a patient's blood and urine, a possible cause is a deficiency of the vitamin thiamine. This is also called Vitamin B1.

A genetic defect in the enzyme pyruvate dehydrogenase is another possible cause. A few tests could help identify the root cause. The first test would be a blood test. The blood test would assess the level of thiamine in the blood. If the levels are low, it may indicate that the patient has a thiamine deficiency. The second test would be a urine test. The urine test would show if there is an excessive amount of pyruvate excreted in the urine, indicating a high level of pyruvate in the body, due to the body's inability to metabolize the pyruvate. The third test would be to look for other symptoms that could be caused by either pyruvate dehydrogenase deficiency or thiamine deficiency. Symptoms of pyruvate dehydrogenase deficiency can include seizures, developmental delays, and difficulty feeding. Symptoms of thiamine deficiency can include fatigue, muscle weakness, and confusion.

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thanks! Q:why are viruses not included in the tree of life.

Answers

Viruses are not included in the tree of life due to several reasons. Here are the reasons: Viruses are not cells: A virus is not a cell and lacks the cytoplasm and cellular organelles that cells possess.

It consists of a genome of nucleic acid surrounded by a protein coat called a capsid. Most viruses do not have the machinery required for self-replication and protein synthesis and must use the host cell's machinery to replicate and produce viral proteins.Viruses do not reproduce: Viruses are obligate intracellular parasites and must infect living host cells to reproduce. They lack the necessary components and machinery for self-replication, such as ribosomes, and must use the host cell's machinery to reproduce.

As a result, they cannot replicate independently. Viruses do not have a metabolism: Viruses do not require energy or nutrients to survive, grow, or reproduce, as living cells do. They lack the metabolic pathways and enzymes required for the synthesis and metabolism of macromolecules, energy production, or ion transport, all of which are required for life. Viruses lack a cellular structure: Viruses lack the cellular structure found in all living organisms and are classified as acellular. The cells in the tree of life are characterized by a complex structure with various organelles and a defined nucleus with a membrane. They also have a cytoskeleton, which maintains the cell's structure and shape, and an extracellular matrix, which provides a protective and supportive structure for cells. Viruses do not have any of these characteristics and cannot be placed in the tree of life.

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please help...
1. Use the Born approximation to determine the total cross-section of an electron scattered by the Yukawa potensial potential V(r) = Ae¯Hr² 2. Describe the SEMI CLASSICAL solution approach for a par

Answers

The total cross-section is obtained by integrating the differential cross-section over all angles:σ = ∫ dσ/dΩ dΩ . The semiclassical approach gives a good approximation to the wavefunction in the intermediate region between the classical and quantum regions.

1. Born approximation to determine the total cross-section of an electron scattered by the Yukawa potential:The Born approximation formula is used to estimate the scattering of charged particles. When an electron is scattered by a potential, the Born approximation is used to find the cross-section.

This approximation requires that the potential be small compared to the energy of the incoming electron.

The total cross-section of an electron scattered by the Yukawa potential can be calculated using the Born approximation formula.

The formula is given by:dσ/dΩ = |f(θ)|²where dσ/dΩ is the differential cross-section, θ is the scattering angle, and f(θ) is the scattering amplitude. The scattering amplitude can be calculated using the Yukawa potential:

f(θ) = -2mV(r)/ħ²k²

where V(r) = Ae^-λr/r,

m is the mass of the electron, k is the wave vector, and λ is the screening length. The total cross-section is obtained by integrating the differential cross-section over all angles:

σ = ∫ dσ/dΩ dΩ

where σ is the total cross-section.

2. SEMI-CLASSICAL solution approach for a parabola:The parabolic potential is given by

V(x) = 1/2 mω²x²

where m is the mass of the particle and ω is the frequency of the oscillator. The semiclassical approach to solving this problem involves treating the particle classically in the potential well and quantum mechanically outside the potential well.

In the classical region, the particle has sufficient energy to move in the parabolic potential. The turning points of the motion are given by

E = 1/2 mω²x²

where E is the total energy of the particle. The semiclassical approximation to the wavefunction is given by:

ψ(x) ≈ 1/√p(x) exp(i/ħ ∫ p(x') dx')

where p(x) = √(2m[E-V(x)]), and the integral is taken from the classical turning points.

The wavefunction is then matched to the exact solution in the quantum region outside the potential well.

The semiclassical approach gives a good approximation to the wavefunction in the intermediate region between the classical and quantum regions.

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The staff at a game park tries to breed miniature camels. They chose a set of parents that is 10 cm shorter at the shoulder than average. Suppose height in camels has 40% heritability. How much shorter than average are the offspring expected to be?
2 cm
4 cm
6 cm
8 cm
10 cm

Answers

The difference in the offspring's height from the average height will be 4 cm.

Suppose height in camels has 40% heritability and the staff at a game park try to breed miniature camels.

They chose a set of parents that is 10 cm shorter at the shoulder than average. Then, the expected difference in the offspring's height will be found as follows:

Limited to a heritability of 40%, the formula for the change in height of the offspring from the average height is given by;

∆h = 0.40 x (parents' height difference from average height)

∆h = 0.40 x 10 cm = 4 cm

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Question 6 In response to food in the digestive tract, what is the correct order of activation in the short reflex? The myenteric plexus, sensory receptors, smooth muscle cells O Sensory receptors, my

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In response to food in the digestive tract, the correct order of activation in the short reflex involves the sensory receptors, myenteric plexus, and smooth muscle cells. The process begins with the activation of sensory receptors located within the walls of the digestive tract.

These receptors, known as mechanoreceptors and chemoreceptors, detect mechanical and chemical stimuli, respectively, that are generated by the presence of food. Upon stimulation, these receptors generate electrical signals.

The electrical signals are then transmitted to the myenteric plexus, which is a network of nerve fibers located between the layers of smooth muscle in the digestive tract. The myenteric plexus serves as an integrative center that receives and processes the sensory information from the receptors.

Within the myenteric plexus, the electrical signals are relayed and modulated, leading to the activation of excitatory and inhibitory motor neurons. Excitatory motor neurons release neurotransmitters, such as acetylcholine, which stimulate the smooth muscle cells in the digestive tract. On the other hand, inhibitory motor neurons release neurotransmitters, such as nitric oxide, which relax the smooth muscle cells.

Finally, the smooth muscle cells in the digestive tract respond to the neurotransmitters released by the motor neurons. The activation of the smooth muscle cells leads to coordinated contractions, known as peristalsis, that propel the food along the digestive tract. These contractions mix and churn the food, facilitating digestion and absorption.

In summary, the correct order of activation in the short reflex in response to food involves the sensory receptors detecting stimuli, transmitting signals to the myenteric plexus, which then activates motor neurons that stimulate or inhibit the smooth muscle cells in the digestive tract, resulting in coordinated contractions for proper digestion and absorption.

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Question 6 In response to food in the digestive tract, what is the correct order of activation in the short reflex? The myenteric plexus, sensory receptors, smooth muscle cells

Where do fatty acids and glycerol go after going from small intestine villi to lacteal? How does it go from lymphatic system to the blood? Does it go through the liver or heart?
Please explain the steps fatty acids and glycerol go through and which organs are related in this process

Answers

After being absorbed by the small intestine villi, fatty acids and glycerol combine to form triglycerides.

These triglycerides are then packaged into structures called chylomicrons and enter the lymphatic system through lacteals.

To reach the bloodstream, chylomicrons from the lymphatic system enter larger lymphatic vessels called thoracic ducts. The thoracic ducts eventually empty into the left subclavian vein near the heart. From there, the chylomicrons are released into the bloodstream.

Once in the bloodstream, the chylomicrons are transported throughout the body. As they circulate, lipoprotein lipase (LPL) enzymes break down the triglycerides in the chylomicrons, releasing fatty acids. The fatty acids are then taken up by various tissues in the body for energy or storage.

In the liver, fatty acids can be used for energy production or converted into other molecules, such as ketones or cholesterol. The liver also plays a role in the production and secretion of lipoproteins, which transport lipids in the bloodstream.

So, the journey of fatty acids and glycerol from the small intestine villi to the blood involves passage through the lymphatic system, specifically the lacteals and thoracic ducts, and ultimately reaching the bloodstream near the heart.

The liver is an important organ in the metabolism and processing of fatty acids, but the heart is not directly involved in this process.

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Please submit a one page paper describing nutrient need changes
during breastfeeding and the benefits of
breastfeeding.

Answers

Breastfeeding is a valuable and natural way to nourish infants. It supports the baby's optimal growth and development while providing numerous health benefits for both the mother and the baby.

During breastfeeding, the nutritional needs of both the mother and the baby undergo significant changes. The mother's nutrient requirements increase to support milk production and meet her own metabolic demands. Key nutrients like protein, energy, vitamins, and minerals should be consumed in adequate amounts through a balanced diet or with the guidance of a healthcare professional.

Breastfeeding offers numerous benefits for both the mother and the baby. For the baby, breast milk provides optimal nutrition, including the right balance of carbohydrates, proteins, and fats, along with essential vitamins, minerals, and antibodies. Breast milk is easily digested and promotes healthy growth and development. It also lowers the risk of various infections, allergies, and chronic diseases.

Breastfeeding benefits the mother by helping with postpartum recovery, promoting bonding with the baby, and potentially reducing the risk of certain diseases such as breast and ovarian cancer. It also aids in weight loss and provides emotional satisfaction.

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biochemist please assit!!!
we
need to calculate the concentration of the unknown protein in mg/ml
The Bradford method described in the Background section was used to determine protein concentrations of known and unknown samples The following results was obtained: Table 1: Absorbance at 505nm obtai

Answers

Given that the Bradford method was used to determine protein concentrations of known and unknown samples, the following results were obtained as follows.

Absorbance at 505nm obtained from the Bradford assay.Sample name Absorbance (A505nm)  standard curve generation must be done to determine the concentration of the unknown sample.Plot the standard curve using the data in Using the data in Table plot the standard curve graph.

To generate the standard curve, the absorbance readings are plotted against known protein concentrations to create the standard curve. The standard curve graph is used to determine the protein concentration of the unknown sample.Step Plot the standard curve using the data in Table Using the data in Table , plot the standard curve graph by plotting the concentration.

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b) Viruses that cause chromosomal integration have created
issues in previous gene therapy trials. Explain the problems
associated with chromosomal integration and give an example

Answers

Gene therapy has become an emerging treatment strategy for genetic disorders.

However, the development of gene therapy has been inhibited by safety concerns associated with vector-mediated chromosomal integration. Chromosomal integration leads to an alteration of endogenous genes or may cause gene activation that leads to unpredictable and unwanted side effects. Problems associated with chromosomal integration: One of the issues associated with chromosomal integration is the insertion of therapeutic genes within the chromosomal sequence of a host cell.

This can disrupt the functionality of the gene leading to genetic disorders. Another problem is that the integration of therapeutic genes into host cells can lead to a loss of cell functionality.Example:One example of the problems associated with chromosomal integration can be seen in the gene therapy trials conducted for the treatment of severe combined immunodeficiency (SCID). In this case, two children who had undergone gene therapy developed leukemia-like symptoms as a result of the gene therapy. The vector used in the gene therapy had integrated into a location near the LMO2 oncogene, which caused gene activation and leukemia-like symptoms in the children.

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Microarrays is a technique used for determining the number and
location of RFLP's?
True or False
All most all genomic tests are used in predicting breeding
values are based on differences in SNPs?
True or false

Answers

The statement that microarrays are used for determining the number and location of RFLPs is False. Additionally, the statement that almost all genomic tests used in predicting breeding values are based on differences in SNPs is True.

Microarrays are a technique used in genetic analysis to measure the expression levels of thousands of genes simultaneously. They are not specifically designed for determining the number and location of RFLPs (Restriction Fragment Length Polymorphisms). RFLP analysis involves the use of restriction enzymes to identify variations in DNA fragments, and it is typically carried out using gel electrophoresis, not microarrays. On the other hand, it is true that most genomic tests used in predicting breeding values are based on differences in SNPs (Single Nucleotide Polymorphisms). SNPs are the most common type of genetic variation found in the human genome, and they are used as markers for mapping traits and identifying genetic variations associated with specific phenotypes. Genomic tests, such as SNP genotyping arrays or whole-genome sequencing, are commonly employed to identify and analyze SNPs for predicting breeding values and understanding genetic diversity in livestock and other organisms. Therefore, the statement that microarrays are used for determining the number and location of RFLPs is False, while the statement that almost all genomic tests used in predicting breeding values are based on differences in SNPs is True.

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UDR innate vs. adaptive, cellular vs. humoral, natural vs. artificial, and passive vs. active immunity
Recognize innate mechanisms of immunity (outermost ring of bullseye or bottom of pyramid; analogies used in class to describe hierarchy of immune mechanisms)
Explain the role of T-cells and the subtypes; same for B-cells
Describe the different types of leukocytes: granulocytes (4), lymphocytes (2), phagocytes (1), and APC’s
Distinguish between the 5 types of antibodies produced by B-cells ("MADGE")
Explain T and B-cell "memory"
Describe how T-cells learn to recognize "self" antigens in the Thymus
What is the mechanism of autoimmune disease?
What are MHC antigens and how do they limit organ transplantation?
What’s in a vaccine and why do we vaccinate?
What makes for a good, strong antibody response when we vaccinate? What can contribute to a poor response? When and why do we need "boosters"?
Understand the idea of bone marrow stem cells and "plasticity"

Answers

The immune system consists of innate and adaptive immunity, with cellular and humoral components. T-cells and B-cells play crucial roles in immune responses, and leukocytes, including granulocytes, lymphocytes, phagocytes, and APCs, contribute to immune defense. Antibodies produced by B-cells have different functions. Memory cells provide long-term immunity, and the thymus helps T-cells recognize "self" antigens. Autoimmune diseases, MHC antigens, vaccines, and vaccination have specific mechanisms and implications. A strong antibody response is desirable, but various factors can influence it. Bone marrow stem cells exhibit plasticity in differentiating into various blood cells.

Innate vs. Adaptive Immunity:

Innate immunity is the first line of defense against pathogens and is present at birth. It includes physical barriers, chemical defenses, and innate immune cells. Adaptive immunity is acquired over time and involves the recognition of specific antigens. It includes cellular and humoral immune responses and the production of antibodies.

Cellular vs. Humoral Immunity:

Cellular immunity involves the action of immune cells, particularly T-cells, in targeting and destroying infected cells. Humoral immunity refers to the production of antibodies by B-cells that circulate in bodily fluids and neutralize pathogens.

Natural vs. Artificial Immunity:

Natural immunity is acquired through natural exposure to pathogens or maternal transfer of antibodies. Artificial immunity is induced through vaccination or administration of immune system components.

Passive vs. Active Immunity:

Passive immunity is temporary and involves the transfer of preformed antibodies from another individual or animal. Active immunity is long-lasting and occurs when the immune system produces its own antibodies in response to an antigen.

Innate Mechanisms of Immunity:

Innate mechanisms of immunity include physical barriers (skin, mucous membranes), chemical defenses (enzymes, pH), and innate immune cells (neutrophils, macrophages, natural killer cells) that provide immediate protection against pathogens.

Role of T-cells and B-cells:

T-cells play a central role in cellular immunity. They are divided into subtypes, such as helper T-cells (CD4+) and cytotoxic T-cells (CD8+), which regulate and directly kill infected cells, respectively. B-cells are responsible for humoral immunity and produce antibodies to neutralize pathogens.

Types of Leukocytes:

Granulocytes include neutrophils, eosinophils, basophils, and mast cells. Lymphocytes include T-cells and B-cells. Phagocytes, such as macrophages and dendritic cells, engulf and destroy pathogens. Antigen-presenting cells (APCs) display antigens to activate immune responses.

Antibodies Produced by B-cells:

B-cells produce five types of antibodies: IgM, IgA, IgD, IgG, and IgE (referred to as "MADGE"). Each type has distinct roles in immune defense, such as neutralization, opsonization, and allergic responses.

T and B-cell Memory:

T and B-cells can develop memory after encountering an antigen. Memory cells enable a faster and more effective immune response upon re-exposure to the same antigen, leading to quicker elimination of the pathogen.

Recognition of "Self" Antigens in the Thymus:

T-cells undergo a selection process in the thymus to recognize "self" antigens without triggering an immune response against the body's own cells. T-cells that fail this selection are eliminated or undergo apoptosis.

Mechanism of Autoimmune Disease:

Autoimmune diseases occur when the immune system mistakenly targets and attacks the body's own tissues as if they were foreign. The exact mechanisms are complex and can involve genetic, environmental, and immunological factors.

MHC Antigens and Organ Transplantation:

Major histocompatibility complex (MHC) antigens, also known as human leukocyte antigens (HLA), play a crucial role in organ transplantation. MHC molecules on the surface of cells determine compatibility between donor and recipient, and a close match is necessary to prevent rejection.

Vaccines and Vaccination:

Vaccines contain harmless forms of pathogens or their antigens. They stimulate the immune system to produce a specific immune response, including the generation of memory cells. Vaccination helps protect against infectious diseases and contributes to herd immunity.

Factors Affecting Antibody Response:

A good, strong antibody response to vaccination depends on factors such as the type and dosage of the vaccine, the individual's immune system, and the presence of memory cells. Poor response can be influenced by factors like age, underlying health conditions, and immunosuppression.

Bone Marrow Stem Cells and Plasticity:

Bone marrow stem cells are undifferentiated cells capable of giving rise to various blood cells, including leukocytes. They exhibit plasticity, meaning they can differentiate into different cell lineages depending on the body's needs.

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36
Which of the following most closely describes the actions of aldosterone in the kidney? Increases potassium reabsorption in the proximal tubule Increases sodium reabsorption in principal cells Binds t

Answers

The following statement most closely describes the actions of aldosterone in the kidney: Increases sodium reabsorption in principal cells. Aldosterone is a hormone that is produced by the adrenal cortex.

Aldosterone is a hormone that is produced by the adrenal cortex. Its primary function is to regulate the body's salt and water balance by controlling sodium and potassium ion reabsorption and excretion in the kidneys. This is important because these ions play a vital role in many body functions, such as maintaining blood volume and blood pressure levels.

When aldosterone binds to receptors in the principal cells of the collecting ducts of the kidney, it increases the number of sodium channels and sodium-potassium ATPase pumps on the apical and basolateral membranes, respectively. As a result, more sodium is reabsorbed from the urine into the bloodstream, while more potassium is excreted in the urine.

The following statement most closely describes the actions of aldosterone in the kidney: Increases sodium reabsorption in principal cells. Aldosterone plays an important role in regulating the body's fluid and electrolyte balance, which is essential for the proper functioning of many body systems. When aldosterone levels are too high, the kidneys reabsorb too much sodium, which can lead to high blood pressure and other health problems.

Aldosterone is a hormone that helps regulate the body's fluid and electrolyte balance by controlling sodium and potassium ion reabsorption and excretion in the kidneys. It increases sodium reabsorption in principal cells, which helps maintain blood volume and blood pressure levels.

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answer in 2 minutes please
Is the nitrogenous base labeled (A) a purine or a pyrimidine? Briefly explain how you can tell. A. 5' end 3 end 3 end B. 5 end

Answers

The nitrogenous base labeled (A) is a purine. This can be determined by looking at the structure of the base. Purines are larger, double-ringed bases (adenine and guanine), while pyrimidines are smaller, single-ringed bases (cytosine, thymine, and uracil).

Adenine is a purine because it has a double-ring structure that contains both nitrogen and carbon atoms, whereas pyrimidines only have a single-ring structure.Purines have a double-ring structure, and the nitrogenous base labeled (A) has a double-ring structure, which means it must be a purine.

Purines include adenine and guanine, while pyrimidines include cytosine, thymine, and uracil. The structure of A shows it is a double-ring structure, hence it is a purine. The nitrogenous base labeled (A) is a purine.

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In
a F2 progeny of two homozygous golden labrador dogs (BBEE x bbee)
brown hair color is a recombination phenotype.
True or false

Answers

In a F2 progeny of two homozygous golden Labrador dogs (BBEE x bbee) brown hair color is a recombination phenotype. Therefore, the statement is true.

Labrador retrievers are a type of gun dog that comes in three colors: black, chocolate, and yellow. It has long been thought that coat color in dogs was determined by a single gene. However, it was discovered that several genes regulate the coat color in dogs.B and E are both dominant genes, and dogs that have both genes have a golden coat. b and e are both recessive genes, and dogs with both genes have brown coats. The genotype BBEE, BBEe, BbEE, or BbEe all yield a golden coat. On the other hand, the genotype bbEe, bbee, bBEe, or Bbee produces a brown coat.The combination of BBEE and bbee (the parental generation) will generate golden offspring (BbEe) in the F1 generation since they both have one dominant B gene.

Then, when two golden offspring breed, the expected ratio of golden to brown puppies in the F2 generation is 3:1. However, the offspring of the F2 generation have been observed to have a brown coat, which is an unexpected recombination phenotype, even though the parental generation has two different coat colors

.In conclusion, in a F2 progeny of two homozygous golden labrador dogs (BBEE x bbee), brown hair color is a recombination phenotype.

Hence the correct option is true.

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Select a biomaterial used in the human body. Explain the following items about this material. i) Production (How it is produced? It will be explained in detail.) ii) Properties (What are the general properties of the material?) iii) Expectations (What features are expected to have in order to be used in the body? Which of these features does it provide?) iv) Standards and restrictions (Which standards and conditions must be met for the material to be used in the human body)

Answers

Titanium alloy is a widely used biomaterial due to its favorable properties, including biocompatibility, strength, and corrosion resistance. It is produced through a process of alloying and casting, meeting the expectations and standards necessary for safe and effective use in the human body.

One biomaterial commonly used in the human body is titanium alloy. Let's explore the different aspects of this material:

i) Production: Titanium alloy is typically produced through a process called melting and casting. The raw material, titanium, is extracted from ores and purified through various chemical processes. Once purified, it is combined with other elements such as aluminum or vanadium to create the desired alloy composition. The alloy is then melted and cast into various forms, such as sheets, rods, or implants, using techniques like vacuum arc melting or electron beam melting.

ii) Properties: Titanium alloy possesses several desirable properties for biomedical applications. It has excellent biocompatibility, meaning it is well-tolerated by the human body without causing adverse reactions. It is also lightweight, strong, and corrosion-resistant. These properties make it suitable for use in medical implants, such as orthopedic devices (e.g., joint replacements), dental implants, and cardiovascular implants.

iii) Expectations: Biomaterials used in the human body are expected to meet specific requirements. For titanium alloy, some key expectations include biocompatibility, mechanical strength, durability, and resistance to corrosion. Biocompatibility ensures that the material does not elicit harmful immune responses or toxicity when in contact with living tissues. Mechanical strength and durability are crucial to withstand the physiological stresses and loads encountered in the body, especially for load-bearing applications. Additionally, resistance to corrosion is vital to maintain the integrity and longevity of the implant.

iv) Standards and restrictions: Titanium alloy used in the human body must meet certain standards and regulations. In many countries, biomaterials are subject to regulations and guidelines set by regulatory bodies, such as the U.S. Food and Drug Administration (FDA) or the International Organization for Standardization (ISO). These standards ensure that the material meets specific requirements for safety, biocompatibility, and performance. Additionally, rigorous testing and characterization are performed to assess the material's mechanical properties, corrosion resistance, and compatibility with the body's tissues.

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Hybridoma cell lines are useful because
a. they generate many different kinds of antibodies in the same culture
b. they can be made by fusing two different types of normal cells
c. they can be used to generate antibodies against a specific antigen
d. they are used by the immune system to fight bacterial infections

Answers

c. Hybridoma cell lines can be used to generate antibodies against a specific antigen.

Hybridoma cell lines are a valuable tool in biomedical research and antibody production. They are formed by fusing antibody-producing B cells with immortal tumor cells, resulting in cells that have the ability to continuously produce a specific antibody. The key advantage of hybridoma cell lines is their ability to generate antibodies against a specific antigen of interest.

Once the hybridoma cells are created, they can be cultured and maintained in the laboratory. These cells will continuously produce large quantities of the specific antibody, allowing for its purification and use in various applications, such as diagnostic tests, therapeutic treatments, and research studies.

By using hybridoma cell lines, scientists can generate monoclonal antibodies that exhibit high specificity and affinity for a particular antigen. This specificity makes them valuable tools in immunology, allowing for targeted detection, identification, and manipulation of specific molecules in biological samples.

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22. Which of the following is concerned most directly in the control of insulin secretion? a. sympathetic nervous system b. hypothalamus c. pituitary gland d. parasympathetic nervous system e. blood g

Answers

Blood glucose levels is concerned most directly in the control of insulin secretion.

Insulin secretion is primarily controlled by the blood glucose levels. When blood glucose levels rise, such as after a meal, the pancreas releases insulin to facilitate the uptake and storage of glucose by cells. Conversely, when blood glucose levels decrease, insulin secretion decreases.

The other options listed (a. sympathetic nervous system, b. hypothalamus, c. pituitary gland, d. parasympathetic nervous system) are not directly involved in the control of insulin secretion. While the nervous system and certain brain structures can influence insulin secretion indirectly, they do not have the primary role in regulating insulin release.

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What are the two principal factors that lead to microevolution? O b. O a. non-random mating and new genetic variation new genetic variation and genetic mulations Oc. genetic mutations and evolutionary

Answers

The two principal factors that lead to microevolution are genetic mutations and natural selection. The correct answer is option c.

Genetic mutations introduce new genetic variations into a population, while natural selection acts on these variations, favoring traits that provide a reproductive advantage and leading to changes in the gene frequency over time.

Therefore, option (c) "genetic mutations and natural selection" is the correct answer. Non-random mating can also contribute to microevolution by altering the distribution of genotypes within a population, but it is not one of the principal factors mentioned in the question.

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Hypercalcemia can effect sodium permeability potassium permeability Oraising blood pH A and C Onone of the above

Answers

the correct answer is: none of the above. Hypercalcemia refers to a higher-than-normal level of calcium in the blood.

It primarily affects the levels of calcium in the body and does not directly impact sodium permeability, potassium permeability, or blood pH.

Sodium permeability and potassium permeability refer to the ability of these ions to move across cell membranes. These processes are primarily regulated by specific ion channels and transporters, and hypercalcemia does not directly alter their permeability.

Similarly, hypercalcemia does not have a direct effect on blood pH. Blood pH is primarily regulated by the balance of acids and bases in the body, with the lungs and kidneys playing key roles in maintaining pH homeostasis.

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Other Questions
Examine this pedigree for a rare human disease and determine the most likely mode of inheritance. If person II-3 and person III-1 had a child, what would be the probability of that child having the disease? a) zero chance b) 1/4 c) 100 percent d) 1/2 1. Two objects travel through R in accordance with the vector-valued functions F (t) = (6+t+ 0.5t, t + 2t, 5t - 2+) and 7 (t) = (7t - 0.5t,1 +0.5t-t, t - 9t). where t E R. An obser Statistical Mechanics.Metallic sodium (Na) has approximately 2.6x1022 electrons of conduction per cm3 (e-/cm3) and behaves approximately like an ideal electron gas. a) Calculate the approximate valu 14) Determine whether the infinite geometric series convergesor diverges. If it converges, find its sum.15) Determine whether the infinite geometric series convergesor diverges. If it converges, fiDetermine whether the infinite geometric series converges or diverges. If it converges, find its sum. 14) \( 1-\frac{1}{3}+\frac{1}{9}-\cdots \) 14) 15) \( 2+6+8+10+\ldots \) 15) Use the Principle of Use Matlab to create the required Bode plots. 1) Design a lead compensator for the system below. The ramp error constant should be K) = 20 and the phase margin should be greater than or equal to 50. Hand in your uncompensated Bode plot and your compensated Bode plot.G(s) = 4/s(s+2)solutionG(s) = 40.16 s+4.39/s+17.64 . a. You have collected records on a herd of X Hampshire swine. You are interested in knowing how many swine in your herd are heterozygous for the belting phenotype (belting is completely dominant to full color). You have the following information for a herd of 2000 Hampshires: 1920 belted & 80 full color. This population is in Hardy Weinberg Equilibrium for this trait. What are the gene and genotypic frequencies for the belted phenotype? How many Hampshires in your herd are heterozygous for belting? b. It just so happens that while you were determining the gene and genotypic frequencies for this herd, it was discovered that the belting loci has also been implicated in influencing litter weaning weight in swine. Therefore, you want to take advantage of this new information by crossing dams from your animals to sires of another separate population. You find a fellow Hampshire breeder that has also kept records for the same loci. Their records indicate a gene frequency of p = 0.3 and q=0.7. With this information, answer the following: If you crossed these two populations (yours and the breeders), what would be the new gene and genotypic frequencies for the Fl population? 2-D Optimal Wiener Filtration Process image 'lena'-image degraded by a smooth filer plus random noise n (from file 'noise.raw') 1. i(n,m)=(oh)(n,m)+n(n,m),n,m=0:(N1),N=256. The smooth filter has the point characteristic that h(n,m)=0 for all pixels except the following 1. 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The migration of tumor cells requires changes in the adhesion properties of the cell that allow it to move and invade more readily.There are several molecules involved in cell-to-cell connections and cellular architecture: laminins, matrix metalloproteinases, cadherins, and integrins. While mutations in genes that control the cell cycle or recognize DNA damage are the causes of tumor cell formation, tumor cell spread to other tissues may be caused by mutations in the genes the code for these extracellular proteins. The loss of cellular connections, cellular identification and signaling, and tissue structure may lead to the release of expanding tumor cells into the circulatory and lymphatic systems. Once tumor cells have access to blood and lymph vessels, they can travel to most parts of the body. This spread of tumor cells is called metastasis.(1) Cancer cells from a person suffering from malignant melanoma are analyzed and found to have an elevated ability to bind to laminin; they also secrete much higher than normal levels of a certain proteolytic enzyme activity. How would these differences from normal, control cells promote metastasis of these cancer cells?(2) In contrast to the situation described in question 1, it has recently been found that nearly 25% of melanomas have mutations in matrix metalloproteinases (MMPs). Why is this contradictory and what does this suggest about the likelihood of MMP inhibitors being effect chemotherapy agents?(3) Why would cells that express less E-cadherin be more likely to become malignant and give rise to epithelial cell tumors?(4) If you were able to inject the gene for a5b1 integrin (a fibronectin receptor) into some tumor cells in such a way that it was expressed extremely efficiently, would those cells be more or less invasive? Why? Normally, a monohybrid cross results in a phenotype ratio of 3:1. However, in some cases, the phenotype ratio from a monohybrid cross can be distorted, to where the phenotype ratio appears as 2:1. In this event, what is the likely mechanism of inheritance for a single gene with this type of phenotypic ratio? a.dominant lethal b. incompletely dominant c.recessive lethal d.codominant please help Finite math 7.Twelve computer disks are randomly selected. Let s represent a good disk and f represent a damaged disk A.How many ways to select twelve computer disks? What counting technique are you applyingM,P,S,or C)? B.How many ways to select five good and seven defective computer disks? What counting technique are you applying M,P,S,or C) Identify the conditions. List a few outcomes i.e., ways of selecting a batch of 12 disks C.How many ways to select three good and nine defective disks or five good and seven defective disks What counting technique are you applyingM,P.S,or C) What is the cause of the evolution of senescence according to the two evolutionary hypotheses (Mutation Accumulation and Antagonistic Pleiotropy)? a)mutations accumulate in individuals as they grow older, leading to senescenceb)mutations that have pleiotropic fitness effects are removed by selectionc)mutations that cause deleterious fitness effects late in life are effectively neutrald)mutations that cause deleterious fitness effects late in life experience a strong "force of natural selection" (a) Consider the complex numbers z and w satisfy the given simultaneous equations as below: 2z+iw=1zw=3+3i(i) Use algebra to find z, giving your answer in the form a+ib, where a and b are real. [4 marks] (ii) Calculate arg z, giving your answer in radians to 2 decimal places. [2 marks] Air enters a turbine at 800 kPa, 1200 K and expands in a reversible adiabatic process to 100 kPa.i) State any assumptions made ii) Calculate the exit temperature iii) Calculate the specific work output Explain how a single strand of mRNA could be manipulated to create multiple variants of the same protein. Hypothesize as to why it is important that mRNA have this feature. a A beef producer has utilized the Breeder's Equation and found a BV equal to 2.95 lbs./day in average daily gain. Indicate the best explanation of this value. The average breeding value for an animal over its generation interval is 2.95 lbs./day The average breeding value of the herd increased 2.95 lbs./day The estimated breeding value for an animal in the herd is 2.95 lbs./day The expected breeding value of the progeny in the herd is 2.95 lbs./day Targeting an Antibiotic Resistance Gene using CRISPR-Cas9The rise and spread of antibiotic resistance in bacteria are alarming because of the impact on the cost, complications, and outcomes of treatment. Of particular concern are resistant bacteria that cause hospital-acquired infections (HAIs). Enterococcus faecalis, a member of the intestinal normal microbiota, is now a leading cause these infections. This organism is an opportunist, meaning that if the normal microbiota population is disturbed (for example by antibiotic treatment), it proliferates and becomes pathogenic. The pathogenic strains usually exhibit larger than normal genomes, having acquired mobile genetic elements such as plasmids, transposons, or phages (viruses that infect bacteria). Some of these elements contain antibiotic resistance genes.Now a collaborative research team from the University of Texas at Dallas and the University of Colorado is investigating the use of CRISPR-Cas9 for overcoming antibiotic resistance in E. faecalis. Recall that bacteria use the CRISPR-Cas system as a defense mechanism, protecting them against the foreign DNA of mobile gene elements. CRISPR-Cas9 consists of an endonuclease (Cas9) that uses a guide RNA (gRNA) to locate and cleave foreign double stranded DNA at a specific site. For example, if a phage injects its DNA into a bacterial cell, that cell uses its CRISPR-Cas9 system to identify and destroy that phage DNA. The system also creates "memory" so that the bacterial cell is protected against future encounters with that same type of phage. Scientists can manipulate the CRISPR-Cas9 system by inserting specific gRNAs to target the Cas9 endonuclease to exactly where they want it to go in a genome, a potential tool for gene silencing or editing.The research team previously showed that drug resistant E. faecalis does not have an intact CRISPR-Cas system; it lacks the Cas9 component and is thus susceptible to the uptake of foreign DNA. Now the team has developed a novel way of getting a functional CRISPR-Cas9 into those organisms in an effort to rid them of their antibiotic resistance genes. They engineered a plasmid, inserting genes for CRISPR-Cas9 along with gRNA sequences that are homologous to a resistance gene for the antibiotic erythromycin. The engineered plasmid was then introduced into a donor strain of E. faecalis that has conjugation ability. The presence of the CRISPR-Cas9 in the donor strain makes it immune to acquiring foreign DNA. When the donor strain conjugated with the drug resistant E. faecalis strain, the resistant strain gained a copy of the engineered plasmid containing the modified CRISPR-Cas9 system. The CRISPR-Cas9 in that cell then targeted its erthromycin resistance gene.The team was able to show that the introduced plasmid significantly reduced the resistance of the resistant E. faecalis to erythromycin, making it sensitive to this drug. The work indicates that it may be possible in the future to use conjugation delivery of CRISPR-Cas9 antimicrobials.Rodrigues, M. et. al. 2019. Conjugative Delivery of CRISPR-Cas9 for the Selective Depletion of Antibiotic-Resistant Enterococci. Antimicrob Agents Chemother. 63(11). pii: e01454-19.Why is the genome of pathogenic Entercoccus aerogenes slightly larger than that of their nonpathogenic counterparts?a. Pathogenic strains of Enterococcus have a CRISPR-Cas9 cassette and this makes them larger.b. Pathogenic Entercoccus strains make the enzyme Dicer, so have an additional gene for this enzyme.c. Pathogenic strains have acquired extra DNA in the form of a mobile genetic element (MGE).d. Pathogenic strains do not have a larger genome; they have a double copy of their single chromosome.e. Pathogenic strains of any bacterium are larger than nonpathogenic strains, and have larger genomes.