Pentagon WFNSC is shown on the coordinate grid. Pentagon WFNSC is dilated with the origin as the center of dilation using the rule (x, y)→(3x, 3y) to create pentagon pentagon W'F'N'S'C'. Which statement is true? Pentagon W'F'N'S'C' is larger than pentagon WFNSC because the scale factor is greater than 1. Pentagon W'F'N'S'C' is larger than pentagon WFNSC because the scale factor is less than 1. Pentagon W'F'N'S'C' is smaller than pentagon WFNSC because the scale factor is less than 1. Pentagon W'F'N'S'C' is smaller than pentagon WFNSC because the scale factor is greater than 1.

Answer:

look at the picture

Step-by-step explanation:

the picture explains everything

Answer:

reflected across the y axis, the point (1, 1) becomes (-1, 1).

Step-by-step explanation:

To reflect a point across the y-axis, all you need to do is negate the x coordinate.  That gives you (-1, 1)

The number of small sized bowls on the counter = 68 bowls

The number of medium sized bowls on the counter = 82 bowls

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of small bowls on the counter be = x

Let the number of medium bowls on the counter be = y

The total number of bowls is = 150

So , the equation will be

x + y = 150   be equation (1)

The amount the small bowl can hold = 4 ounces

The amount the medium bowl can hold = 6 ounces

The total amount of all the bowls on the counter = 764 ounces

So , the equation will be

4x + 6y = 764   be equation (2)

Now , on simplifying the equation (1) and equation (2) , we get

Multiply equation (1) by 4 , we get

4x + 4y = 600   be equation (3)

Subtracting equation (3) from equation (2) , we get

2y = 164

Divide by 2 on both sides , we get

y = 82

Therefore the number of medium sized bowl is 82 bowls

Substituting the value of y in equation (1) , we get

x + y = 150

x + 82 = 150

Subtracting 82 on both sides , we get

x = 68

Therefore , the number of small sized bowl is 68 bowls

Hence ,

The number of small sized bowls on the counter = 68 bowls

The number of medium sized bowls on the counter = 82 bowls

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Answer:

Vg

Step-by-step explanation:

All the others are decimals

pls give thanks, 5 star, brainliest

Answer:

Distributive property

Step-by-step explanation:

Answer:

do you need a bandaid?

Step-by-step explanation:

Step-by-step explanation:

Wth?

Are u okay??

call 911

Answer:

30 hens, 20 cows.

Step-by-step explanation:

Step one:

let the number of cows be x

and the number of hens be y

Each cow has 2 eyes, each hen has 2 eyes also.

the total number of eyes is

2x+2y

Each cow has 4 legs, each hen has 2 legs.

the total number of legs is

4x + 2y

Step two:

the number of legs exceeds the number of eyes by 40:  

4x+2y - (2x+2y) = 40

open bracket

4x+2y-2x-2y=40

4x-2x=40

2x=40

Divide both sides by 2

x=40/2

x=20

Step three:

we know also that x = 2/3*y, so y = 3/2*x = 3/2 * 20 = 30

30 hens, 20 cows.

Check:

60 + 40 eyes = 100, 60 + 80 legs = 140legs.

Answer:

1/2

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

answer is 9

Step-by-step explanation:

12/4=3

1/4=3

3/4=9

Answer:

nice hand writing

Step-by-step explanation:

Answer:

The answer is...

1: quadrant III

2: quadrant II

3: quadrant IV

4: quadrant I

Step-by-step explanation:

If A is in quadrant |, and is multiplied by a negative scalar C, CA is in Quadrant |||, If A is in quadrant ||, and is multiplied by a positive scalar C, CA is in Quadrant ||, If A is in quadrant ||, and is multiplied by a  negative scalar C, CA is in Quadrant |V and If A is in quadrant ||I, and is multiplied by a  negative scalar C, CA is in Quadrant |.

Coordinate system is a system that uses one or more numbers, or coordinates, to uniquely determine the position of the points.

The point A to the location indicated in each scenario.

If A is in quadrant |, and is multiplied by a negative scalar C, CA is in Quadrant |||

If A is in quadrant ||, and is multiplied by a positive scalar C, CA is in Quadrant ||

If A is in quadrant ||, and is multiplied by a  negative scalar C, CA is in Quadrant |V

If A is in quadrant ||I, and is multiplied by a  negative scalar C, CA is in Quadrant |.

Hence, A is in quadrant |, and is multiplied by a negative scalar C, CA is in Quadrant |||, If A is in quadrant ||, and is multiplied by a positive scalar C, CA is in Quadrant ||, If A is in quadrant ||, and is multiplied by a  negative scalar C, CA is in Quadrant |V and If A is in quadrant ||I, and is multiplied by a  negative scalar C, CA is in Quadrant |.

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Answer:

88.89%

Step-by-step explanation:

Calculation for what is the minimum percentage of quiz scores between 4.8 and 8.4

The calculated minimum percentage value of quiz scores between

First step is to calculate the lower k value using this formula

k=(x1−m)/s

Where:

x1 represent first random value 4.8

x2 represent second random value 8.4

m represent mean 6.6

s represent standard deviation 0.6

Let plug in the formula

k=(4.8−6.6)/0.6

k=−1.8/0.6

k=−3

Second step is to calculate the upper k value

k=(x2−m)/s

k=(8.4−6.6)/0.6

k=1.8/0.6

k=3

Now let calculate the minimum percentage

Using this formula

Minimum percentage=1−1/k^2

Let plug in the formula

Minimum percentage=1−1/3^2

Minimum percentage=1−1/9

Minimum percentage=1−0.1111

Minimum percentage=0.8889*100

Minimum percentage=88.89%

Therefore the minimum percentage of quiz scores between 4.8 and 8.4 is 88.89%

Answer:

75%

Step-by-step explanation:

5.2−6.40.6=−2  and 7.6−6.40.6=2.

This means that 5.2 lies 2 standard deviations below the mean and 7.6 lies 2 standard deviations above the mean.

According to Chebyshev's Theorem, at least 75% of data values lie within 2 standard deviations of the mean.

Therefore, we can say that 75% is the minimum percentage of quiz scores between 5.2 and 7.6.

Answer:

Step-by-step explanation:

Each oven weights 300 pounds and there 80 ovens:

Weight left for freezers:

Number of freezers could be added:

Answer:

5 mins.

Step-by-step explanation:

hope his helps good luck

Answer:

5 minutes

Step-by-step explanation:

Answer:

126 marbles

Step-by-step explanation:

if 42 is 1/3 of the jar, times it by 3 and that's the total.

Answer:

126 marbles

Step-by-step explanation:

24 - blue

18 - green

42 are blue or green

let 't' = total number of marbles

1/3t = 42

t = 42 x 3 = 126

Answer: F is 11m.

Step-by-step explanation: Because H,I,G are all increasing their numbers like plus 3, plus 2, and the last one has to be plus 1.

Answer:

9,12?

Step-by-step explanation:

Step-by-step explanation:

If you divide the distance by the elapsed time, the result will be the rate of water loss (evaporation). To convert this evaporation rate in to gallons lost over a specific time period, you will need convert the measure into a volume. WTG GLAD U GOT IT RIGHT..

Complete Question:

A closed box has a square base with side length L feet and height h feet. Given that the volume of the box is 39 cubic feet, express the surface area of the box in terms of L only.

Answer:

[tex]A = \frac{156}{L} + 2L^2[/tex]

Step-by-step explanation:

Given

[tex]Volume = 39ft^3[/tex]

Required

Express the surface area in terms of L

Because the box has a square base:

The volume is:

[tex]Volume = Base\ Area * Height[/tex]

Where

[tex]Base\ Area = L * L[/tex]

So, we have:

[tex]Volume = L * L * H[/tex]

Substitute 39 for Volume

[tex]39= L * L * H[/tex]

[tex]39= L^2 * H[/tex]

Make H the subject

[tex]H = \frac{39}{L^2}[/tex]

The surface area (A) of a box with square base is:

[tex]A = 2(LH + LH + L^2)[/tex]

[tex]A = 2(2LH + L^2)[/tex]

Open bracket

[tex]A = 4LH + 2L^2[/tex]

Substitute [tex]\frac{39}{L^2}[/tex] for H

[tex]A = 4L * \frac{39}{L^2} + 2L^2[/tex]

[tex]A = \frac{4L *39}{L^2} + 2L^2[/tex]

[tex]A = \frac{4*39}{L} + 2L^2[/tex]

[tex]A = \frac{156}{L} + 2L^2[/tex]

Answer:

QR is 1.2 due to both triangle are similar

Answer:

the answer should be 0.96 units

Step-by-step explanation:

1.6/2.0=.8

.8x1.2= .96

Answer:

False

Step-by-step explanation:

a+(-a)=a-a = 0 which means irrational numbers are not closed under addition or subtraction.

False. Irrational numbers are not closed under subtraction.

Given data:

Closure under subtraction means that if you subtract two irrational numbers, the result will always be another irrational number.

However, this is not true for irrational numbers.

For example, consider the irrational numbers √2 and √2 + √2. Both of these numbers are irrational. However, when we subtract √2 from √2 + √2, we get:

(√2 + √2) - √2 = √2

The result, √2, is still an irrational number. But if we subtract two irrational numbers like √2 from √2, we get:

√2 - √2 = 0

The result, 0, is a rational number, not an irrational number.

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Answer:

v-8.4=6.62 +8.4

v=15.02

Step-by-step explanation:

prove me wrong

Find the tangent vector T to the given line (t) = 〈 x(t), y(t), z(t) 〉, with parametric equations,

x(t) = -1 + 3t

y(t) = 6 - 3t

z(t) = 3 + 7t

by differentiating (t) component-wise:

T = '(t) = 〈 dx(t)/dt, dy(t)/dt, dz(t)/dt 〉

T = 〈3, -3, 7〉

Scale T by any real number t to get the line through the origin (when t = 0) and the point (3, -3, 7) (when t = 1), which of course runs parallel to '(t). This gives the vector tT. Translate this by any vector v = 〈a, b, c〉 to force this line to pass through the point (a, b, c) instead of the origin, while still remaining parallel. You want the new line to pass through (0, 11, -9), so take v = 〈0, 11, -9〉.

Then the vector equation of the new line is

tT + v = t 〈3, -3, 7〉 + 〈0, 11, -9〉 = 〈3t, 11 - 3t, -9 + 7t〉

with parametric equations

x(t) = 3t

y(t) = 11 - 3t

z(t) = -9 + 7t

[tex]2 = {x}^{2} + 5x[/tex]

[tex]0 = {x}^{2} + 5x - 2 \\ {x}^{2} + 5x - 2 = 0[/tex]

From the standard form equation and from the given equation.

[tex]a {x}^{2} + bx + c = 0 \\ a = 1 \: \: \: b = 5 \: \: \: c = - 2[/tex]

Discriminant Formula

[tex]D = {b}^{2} - 4ac[/tex]

Substitute the value of terms in the discriminant formula.

[tex]D = {(5)}^{2} - 4(1)( - 2) \\ D = 25 - 4( - 2) \\ D = 25 + 8 \\ D = 33[/tex]

Discriminant Types

[tex]D > 0 \: \: \: \: 2 \: \: real \: \: roots \\ D = 0 \: \: \: \: 1 \: \: real \: \: root \\ D < 0 \: \: \: imaginary \: \: roots[/tex]

We can rule out the Imaginary root and double root because the discriminant is greater than 0. Therefore, the only choices are either Irrational or Rational.

However, we cannot factor the expression by using two brackets or common factor. We can say that the equation has two real irrational roots.