Patricia needs 2 pints of purple icing to decorate cupcakes. She will use the following recipe for 1 pint of purple icing.

· 1 pint of white icing

· 4 1/4 teaspoons of blue food coloring

· 2 1/2 teaspoons of red food coloring.



Explain two different ways for Patricia to find the total number of teaspoons of blue and red food coloring necessary to make the 2 pints of purple icing. (Do not solve the problem.)

Answer:

310 cm 2

Step-by-step explanation:

Answer:

[tex] \sqrt{145} [/tex]

Step-by-step explanation:

I think you've been tricked 2 root 37 = root 148

Its 336 sorry if I'm wrong

Answer:

The 92.7% confidence interval for the expected amount of garbage per bin for all bins in the city is between 48.135 pounds and 50.685 pounds. The lower limit is 48.135 pounds.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 46 - 1 = 45

92.7% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 45 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.927}{2} = 0.9635[/tex]. So we have T = 2.1437

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.1437\frac{3.99}{\sqrt{45}} = 1.275[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 49.41 - 1.275 = 48.135 pounds

The upper end of the interval is the sample mean added to M. So it is 49.41 + 1.275 = 50.685 pounds.

The 92.7% confidence interval for the expected amount of garbage per bin for all bins in the city is between 48.135 pounds and 50.685 pounds. The lower limit is 48.135 pounds.

Answer:

Step-by-step explanation:

you add all them up

Answer:

C.

Step-by-step explanation:

there is a measuement of 12 cm missing.

Just multiply all the sides!

Answer:

depends on the size of the house

let's say the house is 10 square meter then you would need 5 gallons

let's the house is 60 square meter then you would need 30 gallons

Step-by-step explanation:

whatever the square meter just divide it with 2 and that should be your answer

Answer:

5x+2

Step-by-step explanation:

Answer:

Step-by-step explanation:

3 너 도넛

Answer:

hiro ..................

Answer:

[tex]D' = (1,3)[/tex]

Step-by-step explanation:

Given

See attachment

Required

Find D'

From the attachment, we have:

[tex]D = (3,1)[/tex]

When reflected across y = x.

The rule is:

[tex](x,y) \ to (y,x)[/tex]

So, if [tex]D = (3,1)[/tex]

Then:

[tex]D' = (1,3)[/tex]

Answer: 60.2 inches

The perimeter of the triangle is 80.24 inches.

The relationship between the three sides of a right-angled triangle is explained by the Pythagoras theorem, commonly known as the Pythagorean theorem. The Pythagoras theorem states that the square of a triangle's hypotenuse is equal to the sum of its other two sides' squares.

Given:

Altitude = 24 inches

Base = 11 inches

Half of the base = 11/2 = 5.5 inches

Using Pythagoras theorem:

Hypotenuse = √(24² + 5.5²)

Hypotenuse = √(576+ 30.25)

                     = √606.25

                     =  34.62 inches

Now, perimeter of a triangle

= (base + side 1 + side 2)

= (11 + 34.62+ 34.62)

= 80.24 inches

Hence, the perimeter of the triangle is 80.24 inches.

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Answer:

Step-by-step explanation:

The LCM of 10,12,15 is 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60 .

I’m just tryna get up my bag yurt

Answer:

a) Then minimum sample size is  n = 12

b) We got  245 successes  

c)p-value is greater than 0,01 Therefore we accept H₀.

We can´t support our claim

Step-by-step explanation:

a) The minimum population size required to use the approximation of binomial distribution to normal distribution can be obtained from:

n*p > 5      p  = 0,45     0,45 * n  >  5     n > 11  

Then minimum sample size is  n = 12

b)  We got  245 successes  out of  n = 500

x =  245       p  =  245/500    p  = 0,49

q  =  1 - p     q  =  1  - 0,49    q  =  0,51

Test Hypothesis:

Null Hypothesis                        H₀      p  =  0,45

Alternative Hypothesis            Hₐ      p  > 0,45

Alternative Hypothesis indicates that the test is a one tail test to the right

z( s)  =   (  p  -  0,45  )  / √ p*q/n

z( s)  =   (  0,49 - 0,45 ) / √ 0,49*0,51 / 500

z( s)  =  0,04 /  0,0223

z(s)  =  1,793

p- value for  z = 1.79  is from z-table    p-value = 0,0367

Comparing p-value with the significance level  0,01 we see that

p-value is greater than 0,01 Therefore we accept H₀.

We can´t support our claim

Answer:

B

Step-by-step explanation:

Base area = (base x width) = 20 x 18 = 360 cm^2

Base perimeter = (base + width) x 2 = (20 + 18) x 2 = 76 cm

lateral surface = (base perimeter x height) = 76 x 15 = 1140 cm^2

Surface area = (base area x 2) + lateral surface = (360 x 2) + 1140= 1860 cm^2

surface area of a single prism = 1860 / 2 = 930 cm^2

Answer:Please see answer in explanation column

Step-by-step explanation:

A

The sum of a number and 7 is not more than 10

Given answer: x + 7 < 10  , This is false

Reason :Not more than 10 means at most 10, less than or equal to 10 , " or " not greater than 10 "and therefore the correct inequality  is written as

x + 7  ≤ 10

B

The product of a number and 4 is at least 20

Given answer: 4X > 20  ---- False

Reason :At least 20  means at no less than 20 " or " greater than or equal to 20  therefore the correct inequality  is written as

4X ≥ 20

C

The difference between a 15 and a number is at most 12

Given answer: 15-x>12----False

Reason :At most 12  means  " no more than 12 , "  " less than or equal to 12 , " or " not greater than 12"therefore the correct inequality  is written as

15-x  ≤  12

D

The quotient of a number and 8 is greater than or equal to

Given answer 8x <3 --False

Reason : It clearly stated greater than or equal to 3. Therefore the correct inequality is  8x  ≥ 3

Answer:

[tex]A.\ \tan(x) \to 2.\ \sin(x) \sec(x)[/tex]

[tex]B.\ \cos(x) \to 5. \sec(x) - \sec(x)\sin^2(x)[/tex]

[tex]C.\ \sec(x)csc(x) \to 3. \tan(x) + \cot(x)[/tex]

[tex]D. \frac{1 - (cos(x))^2}{cos(x)} \to 1. \sin(x) \tan(x)[/tex]

[tex]E.\ 2\sec(x) \to\ 4.\ \frac{\cos(x)}{1 - \sin(x)} +\frac{1-\sin(x)}{\cos(x)}[/tex]

Step-by-step explanation:

Given

[tex]A.\ \tan(x)[/tex]

[tex]B.\ \cos(x)[/tex]

[tex]C.\ \sec(x)csc(x)[/tex]

[tex]D.\ \frac{1 - (cos(x))^2}{cos(x)}[/tex]

[tex]E.\ 2\sec(x)[/tex]

Required

Match the above with the appropriate identity from

[tex]1.\ \sin(x) \tan(x)[/tex]

[tex]2.\ \sin(x) \sec(x)[/tex]

[tex]3.\ \tan(x) + \cot(x)[/tex]

[tex]4.\ \frac{cos(x)}{1 - sin(x)} + \frac{1 - \sin(x)}{cos(x)}[/tex]

[tex]5.\ \sec(x) - \sec(x)(\sin(x))^2[/tex]

Solving (A):

[tex]A.\ \tan(x)[/tex]

In trigonometry,

[tex]\frac{sin(x)}{\cos(x)} = \tan(x)[/tex]

So, we have:

[tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex]

Split

[tex]\tan(x) = \sin(x) * \frac{1}{\cos(x)}[/tex]

In trigonometry

[tex]\frac{1}{\cos(x)} =sec(x)[/tex]

So, we have:

[tex]\tan(x) = \sin(x) * \sec(x)[/tex]

[tex]\tan(x) = \sin(x) \sec(x)[/tex] --- proved

Solving (b):

[tex]B.\ \cos(x)[/tex]

Multiply by [tex]\frac{\cos(x)}{\cos(x)}[/tex] --- an equivalent of 1

So, we have:

[tex]\cos(x) = \cos(x) * \frac{\cos(x)}{\cos(x)}[/tex]

[tex]\cos(x) = \frac{\cos^2(x)}{\cos(x)}[/tex]

In trigonometry:

[tex]\cos^2(x) = 1 - \sin^2(x)[/tex]

So, we have:

[tex]\cos(x) = \frac{1 - \sin^2(x)}{\cos(x)}[/tex]

Split

[tex]\cos(x) = \frac{1}{\cos(x)} - \frac{\sin^2(x)}{\cos(x)}[/tex]

Rewrite as:

[tex]\cos(x) = \frac{1}{\cos(x)} - \frac{1}{\cos(x)}*\sin^2(x)[/tex]

Express [tex]\frac{1}{\cos(x)}\ as\ \sec(x)[/tex]

[tex]\cos(x) = \sec(x) - \sec(x) * \sin^2(x)[/tex]

[tex]\cos(x) = \sec(x) - \sec(x)\sin^2(x)[/tex] --- proved

Solving (C):

[tex]C.\ \sec(x)csc(x)[/tex]

In trigonometry

[tex]\sec(x)= \frac{1}{\cos(x)}[/tex]

and

[tex]\csc(x)= \frac{1}{\sin(x)}[/tex]

So, we have:

[tex]\sec(x)csc(x) = \frac{1}{\cos(x)}*\frac{1}{\sin(x)}[/tex]

Multiply by [tex]\frac{\cos(x)}{\cos(x)}[/tex] --- an equivalent of 1

[tex]\sec(x)csc(x) = \frac{1}{\cos(x)}*\frac{1}{\sin(x)} * \frac{\cos(x)}{\cos(x)}[/tex]

[tex]\sec(x)csc(x) = \frac{1}{\cos^2(x)}*\frac{\cos(x)}{\sin(x)}[/tex]

Express [tex]\frac{1}{\cos^2(x)}\ as\ \sec^2(x)[/tex] and [tex]\frac{\cos(x)}{\sin(x)}\ as\ \frac{1}{\tan(x)}[/tex]

[tex]\sec(x)csc(x) = \sec^2(x)*\frac{1}{\tan(x)}[/tex]

[tex]\sec(x)csc(x) = \frac{\sec^2(x)}{\tan(x)}[/tex]

In trigonometry:

[tex]tan^2(x) + 1 =\sec^2(x)[/tex]

So, we have:

[tex]\sec(x)csc(x) = \frac{\tan^2(x) + 1}{\tan(x)}[/tex]

Split

[tex]\sec(x)csc(x) = \frac{\tan^2(x)}{\tan(x)} + \frac{1}{\tan(x)}[/tex]

Simplify

[tex]\sec(x)csc(x) = \tan(x) + \cot(x)[/tex]  proved

Solving (D)

[tex]D.\ \frac{1 - (cos(x))^2}{cos(x)}[/tex]

Open bracket

[tex]\frac{1 - (cos(x))^2}{cos(x)} = \frac{1 - cos^2(x)}{cos(x)}[/tex]

[tex]1 - \cos^2(x) = \sin^2(x)[/tex]

So, we have:

[tex]\frac{1 - (cos(x))^2}{cos(x)} = \frac{sin^2(x)}{cos(x)}[/tex]

Split

[tex]\frac{1 - (cos(x))^2}{cos(x)} = \sin(x) * \frac{sin(x)}{cos(x)}[/tex]

[tex]\frac{sin(x)}{\cos(x)} = \tan(x)[/tex]

So, we have:

[tex]\frac{1 - (cos(x))^2}{cos(x)} = \sin(x) * \tan(x)[/tex]

[tex]\frac{1 - (cos(x))^2}{cos(x)} = \sin(x) \tan(x)[/tex] --- proved

Solving (E):

[tex]E.\ 2\sec(x)[/tex]

In trigonometry

[tex]\sec(x)= \frac{1}{\cos(x)}[/tex]

So, we have:

[tex]2\sec(x) = 2 * \frac{1}{\cos(x)}[/tex]

[tex]2\sec(x) = \frac{2}{\cos(x)}[/tex]

Multiply by [tex]\frac{1 - \sin(x)}{1 - \sin(x)}[/tex] --- an equivalent of 1

[tex]2\sec(x) = \frac{2}{\cos(x)} * \frac{1 - \sin(x)}{1 - \sin(x)}[/tex]

[tex]2\sec(x) = \frac{2(1 - \sin(x))}{(1 - \sin(x))\cos(x)}[/tex]

Open bracket

[tex]2\sec(x) = \frac{2 - 2\sin(x)}{(1 - \sin(x))\cos(x)}[/tex]

Express 2 as 1 + 1

[tex]2\sec(x) = \frac{1+1 - 2\sin(x)}{(1 - \sin(x))\cos(x)}[/tex]

Express 1 as [tex]\sin^2(x) + \cos^2(x)[/tex]

[tex]2\sec(x) = \frac{\sin^2(x) + \cos^2(x)+1 - 2\sin(x)}{(1 - \sin(x))\cos(x)}[/tex]

Rewrite as:

[tex]2\sec(x) = \frac{\cos^2(x)+1 - 2\sin(x)+\sin^2(x)}{(1 - \sin(x))\cos(x)}[/tex]

Expand

[tex]2\sec(x) = \frac{\cos^2(x)+1 - \sin(x)- \sin(x)+\sin^2(x)}{(1 - \sin(x))\cos(x)}[/tex]

Factorize

[tex]2\sec(x) = \frac{\cos^2(x)+1(1 - \sin(x))- \sin(x)(1-\sin(x))}{(1 - \sin(x))\cos(x)}[/tex]

Factor out 1 - sin(x)

[tex]2\sec(x) = \frac{\cos^2(x)+(1- \sin(x))(1-\sin(x))}{(1 - \sin(x))\cos(x)}[/tex]

Express as squares

[tex]2\sec(x) = \frac{\cos^2(x)+(1-\sin(x))^2}{(1 - \sin(x))\cos(x)}[/tex]

Split

[tex]2\sec(x) = \frac{\cos^2(x)}{(1 - \sin(x))\cos(x)} +\frac{(1-\sin(x))^2}{(1 - \sin(x))\cos(x)}[/tex]

Cancel out like factors

[tex]2\sec(x) = \frac{\cos(x)}{1 - \sin(x)} +\frac{1-\sin(x)}{\cos(x)}[/tex] --- proved

Answer:

a) 0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

b) 0.4129 = 41.29% probability that the mean return will be less than 8%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean 8.7% and standard deviation 20.2%.

This means that [tex]\mu = 8.7, \sigma = 20.2[/tex]

40 years:

This means that [tex]n = 40, s = \frac{20.2}{\sqrt{40}}[/tex]

(a) What is the probability (assuming that the past pattern of variation continues) that the mean annual return on common stocks over the next 40 years will exceed 13%?

This is 1 subtracted by the pvalue of Z when X = 13. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{13 - 8.7}{\frac{20.2}{\sqrt{40}}}[/tex]

[tex]Z = 1.35[/tex]

[tex]Z = 1.35[/tex] has a pvalue of 0.9115

1 - 0.9115 = 0.0885

0.0885 = 8.85% probability that the mean annual return on common stocks over the next 40 years will exceed 13%.

(b) What is the probability that the mean return will be less than 8%?

This is the pvalue of Z when X = 8. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{8 - 8.7}{\frac{20.2}{\sqrt{40}}}[/tex]

[tex]Z = -0.22[/tex]

[tex]Z = -0.22[/tex] has a pvalue of 0.4129

0.4129 = 41.29% probability that the mean return will be less than 8%

Answer:

-48.3° Celsuis

Step-by-step explanation:

Mark as brainllest

Answer:

250 degrees

Step-by-step explanation:

The arc intercepted by the angle formed by a secant and a tangent is twice the measure of the angle. See the attached image.  The intercepted arc measures 110 degrees.

x is the measure of the rest of the circle, so it is 360 - 110 = 250 degrees.

Explanation is[tex]^{}[/tex] in a file

bit.[tex]^{}[/tex]ly/3gVQKw3

Answer:

x=7

hope this helps

have a good day :)

Step-by-step explanation:

Plan B pays more $2,683,948.55 more than plan A.

Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

A geometric progression is a sequence in which any element after the first is obtained by multiplying the preceding element by a constant called the common ratio which is denoted by r.

The first payment plan forms an arithmetic progression with first term

[tex]a_{1} =[/tex] $1 and common difference d = $1.

The total amount gotten after 4 weeks is the sum of the terms in the arithmetic progression when the number of terms is [tex](4\times7) = 28 days[/tex]

[tex]S_{n}=\frac{a}{2}[2a_{1} +(n-1)d][/tex]

Total payment = [tex]S_{n}=\frac{28}{2}[2(1) +(28-1)1][/tex]

= [tex]14(2+27)[/tex]

= [tex]14(29)[/tex]

= $406

The second payment plans a geometric progression with first term

[tex]a_{1} =[/tex] $0.01 and common difference r = 2.

The total amount gotten after 4 weeks is the sum of the first 28 terms of the geometric progression

[tex]S_{n}=\frac{a_{1}(1-r^{n} ) }{1-r}[/tex]

Total payment = [tex]\frac{0.01(1-2^{28}) }{1-2}[/tex]

= [tex]\frac{-2684354.55}{-1}[/tex]

= $2684354.55

The second plan pays more by

= $2684354.55 - $406

= $2683948.55

Plan B pays more $2,683,948.55 more than plan A.

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Answer:

29ft

Step-by-step explanation:

Answer:

what are the rest of the choices, if the ones are the top ones they dont make sense.

Step-by-step explanation:

Answer:

Mizuki is here to help! The answer will be $11.95

Step-by-step explanation:

Ok so... Frankie wants 5 bananas, 15 oranges, and 10 peaches for the salad right?

First, let's find the price of the 5 bananas. We multiply 1 by 5 and get 5, so $5 is the cost for the bananas he is going to spend.

Next, let's find the price for 15 oranges. First, we will divide 15 by 6, which will end up with 2.5. Then, we multiply 1.5 by 2.5 which will be 3.75. The price for the oranges he is going to buy is $3.75.

Then, let's find the price of the 10 peaches. The step is similar from the way we solved the price of oranges. We divide 10 by 4 and get 2.5. Next, we will multiply 1.28 by 2.5 and get 3.2. The price for peaches is $3.2.

Finally, let's add up 5, 3.75, and 3.2! The total should be 11.95! That will be your answer!

Answer:

63°

Step-by-step explanation:

...................................

Answer:

x = 15.4

Step-by-step explanation:

Reference angle = 33°

Opposite side reference angle = 10

Adjacent side = x

Therefore, we would apply the trigonometric function, TOA.

Thus:

Tan 33° = Opposite/Adjacent

Tan 33° = 10/x

Multiply both sides by x

x*Tan 33° = 10

Divide both sides by Tan 33°

x = 10/Tan 33°

x = 15.3986496

x = 15.4 (nearest tenth)

Answer:

A and D

I graphed the equation on desmos

Answer:

A,D

Step-by-step explanation: