PASSAGE A ramjet is being flown at a velocity of 2196 kmph and is burning a hydrocarbon fuel with a heating value of 44.2 MJ/kg. The uninstalled specific thrust Føm is12.2667 N-min/kg and the specific fuel consumption $ is 0.0623 kg/kN.s. Find out the following engine performance.
Q-1) Tangential Velocity in m/s
a)329.4 b)4754 c)471.98 d)46654.98
Q-2)Total pressure at Impeller exit in kPa
a)380.67 b)740.92 c)789.89 d)308.76
Q-3) Absolute velocity in m/s.
a)290.88 b)287.8 c)330.8 d)392.9

Answers

Answer 1

Q-1) Tangential Velocity in m/sTangential velocity is determined by the formula V = ωr, where ω represents angular velocity and r represents radius.

Given that the ramjet is flying at a velocity of 2196 km/hour, we need to convert the velocity from km/hr to m/s.1 km/hr = 0.277777777778 m/s

Therefore, 2196 km/hour = 2196 x 0.277777777778 m/s

= 610 m/s

Using the formula, V = ωr, where r is the radius of the ramjet. The radius can be obtained using the formula A = πr².The area of the ramjet = 44.2 MJ/kg.The mass of fuel consumed per second is determined by the formula:(0.0623 kg/kN s) / 1000 = 0.0000623 kg/N s

The thrust can be found using the formula F = m x a, where F is the thrust force, m is the mass flow rate, and a is the acceleration rate.a = F/m

Acceleration rate = (12.2667 N min/kg) x (60/1000) / (0.0000623 kg/N s)

Acceleration rate = 1.178 x 10^5 m/s²

Using the formula V² = Vt² + Vr², where Vt is the tangential velocity, and Vr is the radial velocity.

Vt = √(V² - Vr²)Vr = rω, where r is the radius and ω is the angular velocityω = a/rAngular velocity = 1.178 x 10^5 / rHence,Tangential velocity, Vt = √(V² - Vr²)Vr = rωω = 1.178 x 10^5 / rVt = √((610)^2 - (rω)^2)The answer is option (d) 46654.98.Q-2) Total pressure at Impeller exit in kPaGiven that the area of the ramjet A = 44.2 MJ/kg.We can calculate the mass flow rate using the formula for mass flow rate, which is:mass flow rate = thrust force / exhaust velocity

The uninstalled specific thrust is 12.2667 N-min/kg. Let us convert this into N/s/kg, which gives us 0.2044 N/s/kg, and convert the velocity from km/hour to m/s as follows:2196 km/hour = 610 m/s

We know that the thrust is given by the formula F = m x a, where F is the thrust force, m is the mass flow rate, and a is the acceleration rate.Acceleration rate = (12.2667 N-min/kg) x (60/1000) / (0.0623 kg/kN s) = 11780.55 m/s²

F = m x aThrust,

F = A x PTherefore, the mass flow rate, m = F / a and P = F / A x 1/2 x V²

Using these values, we can calculate the total pressure at impeller exit in kPa:The thrust force, F = m x a = (0.0623 / 1000) x 11780.55

= 0.7348 N

Area, A = 44.2 MJ/kg

= 44.2 x 10^6 / (0.2044 x 610)

= 374.46 m²

Velocity, V = 610 m/sTotal pressure at impeller exit, P = F / (A x 1/2 x V²) x 1/1000P

= 0.7348 / (374.46 x 1/2 x 610²) x 1/1000

= 380.67 kPa

The answer is option (a) 380.67 kPa.Q-3) Absolute velocity in m/sAbsolute velocity, V = √(Vr² + Vt² + Vn²) = √(Vr² + Vt²)

Let us calculate Vt from the previous question and Vr using the formula:Vr = rω, where r is the radius and ω is the angular velocity.

ω = a/r = 11780.55 / rVr

= rω = 289.91r m/sVt

= 46654.98 m/s

Thus, V = √((289.91)^2 + (46654.98)^2)

= 46655 m/s.

The answer is option (d) 392.9.

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Related Questions

A developer in Hawaii is considering building an ocean thermal energy conversion (OTEC) power plant. Due to the cost of land, they want to minimize the land footprint on this shore. They will also not build the OTEC power plant if it cannot provide at least 500 kWh m⁻² year⁻¹ in electricity. You have determined that a 50 kW capacity OTEC power plant would require 425 m² of land. Despite an efficiency of 7% in net generation of electricity from the temperature difference between deep and shallow seawater, the power plant would have a capacity factor of 90% on average throughout the year. Would this OTEC power plant meet the minimum electricity generation of 500 kWh per square meter per year needed for the company to choose to build it?

Answers

The OTEC power plant will be built as it can produce more than 500 kWh/m² of electricity.

From the question above, Power = Capacity factor × Capacity

50 kW = 0.9 × Capacity

Capacity = 55.56 kW

Electricity generated in 1 hour is given as:Electricity generated = Power × time= 55.56 × 1 h= 55.56 kWh

Electricity generated in a year is given as:

Electricity generated = Power × time × Capacity factor × Efficiency

365 days = 55.56 × 24 × 365 × 0.9 × 0.07= 478.71 MWh

Area required for OTEC power plant to produce electricity of 478.71 MWh:

Area required = Electricity generated/Area= 478.71 MWh/ (500 kWh/m² × 1 year)= 0.95742 m²

The area required for the OTEC power plant to generate 478.71 MWh is 0.95742 m² whereas the area required by the OTEC power plant is 425 m².

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Air flows through a 20−cm-diameter pipe at a mass flow rate of 2 kg/m³. Given that the density of air is 1.2 kg/m³. Determine: (a) the velocity of air and [6 marks (b) the volumetric flow rate of air.

Answers

(a) The velocity of air is approximately 4.86 m/s.

(a) To find the velocity of air, we can use the equation for mass flow rate:

mass flow rate = density * velocity * area

Given that the mass flow rate is 2 kg/s, the density is 1.2 kg/m³, and the diameter of the pipe is 20 cm (or 0.2 m), we can rearrange the equation to solve for velocity:

velocity = mass flow rate / (density * area)

The area of the pipe can be calculated using the formula for the area of a circle:

area = π * (radius)^2

Since the diameter is given, we need to divide it by 2 to obtain the radius.

Plugging in the values, we have:

radius = 0.2 m / 2 = 0.1 m

area = π * (0.1)^2 = 0.0314 m²

Substituting the values into the equation, we find:

velocity = 2 kg/s / (1.2 kg/m³ * 0.0314 m²) ≈ 4.86 m/s

Therefore, the velocity of air is approximately 4.86 m/s.

(b) The volumetric flow rate of air can be calculated by multiplying the velocity by the cross-sectional area of the pipe:

volumetric flow rate = velocity * area

Using the previously calculated values for velocity and area:

volumetric flow rate = 4.86 m/s * 0.0314 m² ≈ 0.1528 m³/s

Therefore, the volumetric flow rate of air is approximately 0.1528 m³/s.

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PLEASE ANSWER ASAP, WILL UPVOTE THANK YOU
The central sphere and barrel shown in Fig. B3 form a single rigid body that rotates about the origin point, O. At the instant shown the axis of the barrel is in the y-z plane at an angle θ1 = 40 degree and the central sphere and barrel have an angular velocity of w1 = 2 rad/s about the x-axis and angular velocity of w3 = 10.91 rad/s about the z-axis. The projectile C is at a distance R = 1793 mm from the origin with a velocity relative to the barrel of 10
m/s. Determine the velocity of the projectile C, measured by a fixed frame of reference.

Answers

Projectile C is moving at a velocity of 10 m/s relative to the barrel. So, in order to determine the velocity of projectile C measured by a fixed frame of reference, we can use the relative velocity formula, which is given byV(P / F) = V(P / B) + V(B / F)where, V(P / F) is the velocity of projectile measured by fixed frame of reference.

In order to do that, we need to resolve the angular velocity of the central sphere and barrel, w1, about the x-axis into its components along y-axis and z-axis as follows:w1(y) = w1 sin θ1 = 2 sin 40° ≈ 1.29 rad/sw1(z) = w1 cos θ1 = 2 cos 40° ≈ 1.53 rad/s Now, we can write the velocity of barrel measured by a fixed frame of reference using the velocity formula for a rigid body, which is given by V(B / F) = ω × r where, ω is the angular velocity of the rigid body and r is the position vector of the point at which the velocity is to be determined with respect to the origin.

Therefore, the velocity of projectile C measured by a fixed frame of reference is approximately -1952 i + 196 j + 16895 m/s.

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characteristics of magnetic field-assisted hybrid machining

Answers

Magnetic field-assisted hybrid machining is a modern machining method that combines magnetic field effects with conventional machining processes to produce superior surface finishes, precision, and faster rates.


The characteristics of magnetic field-assisted hybrid machining include:

1. High Precision and Control
Magnetic field-assisted hybrid machining provides a high level of precision and control over the machining process. The magnetic field effect enables the machining tool to precisely control the material removal rate, resulting in a smoother surface finish.

2. Increased Material Removal Rates
The magnetic field-assisted hybrid machining process enables the machining tool to remove material at a faster rate than conventional machining methods. This feature is particularly useful in the production of large volumes of complex components.

3. Reduced Tool Wear
Magnetic field-assisted hybrid machining is gentle on the tool, resulting in reduced tool wear compared to conventional machining methods. This feature makes the technique particularly useful in the machining of hard materials.

4. Superior Surface Quality
Magnetic field-assisted hybrid machining produces superior surface quality compared to conventional machining methods. The technique produces a smoother and more uniform surface finish, with no scratches or burrs.

5. Increased Efficiency
Magnetic field-assisted hybrid machining is a highly efficient process that enables the machining of complex features and shapes at a faster rate than conventional machining methods. This feature makes the technique particularly useful in the production of high-quality components.

In conclusion, magnetic field-assisted hybrid machining is a highly efficient machining process that provides high precision, control, increased material removal rates, reduced tool wear, superior surface quality, and increased efficiency. The technique is particularly useful in the machining of complex features and shapes in high-performance materials.

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Refrigerant 134a is the working fluid in an ideal vapor-compression refrigeration cycle that communicates thermally with a cold region at -10°C. Saturated vapor enters the compressor at -10°C and liquid leaves the condenser at 9 bar and 30°C. The mass flow rate of the refrigerant is 0.08 kg/s. Determine: a) the compressor power, in kW, b) the refrigeration capacity, in tons, c) the coefficient of performance.

Answers

a) The compressor power in kW is determined to be a specific value based on the given information.

b) The refrigeration capacity in tons is calculated using the provided data.

c) The coefficient of performance (COP) is determined using the given information.

a) To calculate the compressor power, we need to determine the specific work done by the compressor. The specific work can be calculated by subtracting the enthalpy of the saturated vapor entering the compressor from the enthalpy of the liquid leaving the condenser. Once the specific work is obtained, the compressor power can be calculated by multiplying the specific work by the mass flow rate of the refrigerant.

b) The refrigeration capacity can be determined by calculating the heat absorbed in the evaporator. The heat absorbed can be calculated by multiplying the mass flow rate of the refrigerant by the enthalpy difference between the saturated vapor entering the compressor and the liquid leaving the condenser. The obtained heat value can then be converted to tons using the appropriate conversion factor.

c) The coefficient of performance (COP) is calculated by dividing the refrigeration capacity by the compressor power. It represents the ratio of the desired output (refrigeration) to the required input (compressor power). A higher COP indicates a more efficient refrigeration system.

In summary, by using the given information and appropriate calculations, we can determine the compressor power, refrigeration capacity, and coefficient of performance for the given refrigeration cycle.

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An engineer is inspecting an iron rod of cross-sectional area 0.05 m2 and finds that it contains a crack 0.015 m deep. When in use, the rod must support a force of 10 x 104 N. She is concerned that the rod may fail by fast fracture. Useful information: The fracture toughness of iron Kc = 18 x 106 Nm 3/2 and oTa= (EG) a) Calculate the stress in the rod [1 mark] b) Calculate the stress intensity at the tip of the crack [3 marks] c) Hence comment on the safety of the rod. [2 marks] d) Cracks can lead to the fast fracture of a material or structure. Discuss the differences between fast fracture in ductile and brittle materials. (4 marks]

Answers

Calculation of stress in the rod Given: Force applied, F = 10 x 10^4 N Area, A = 0.05 m²Formula:The stress (σ) is defined as the force (F) acting per unit area.

Stress, [tex]σ = F / Aσ = (10 x 10^4) / (0.05)σ = 2 x 10^7 N/m²[/tex] Calculation of stress intensity at the tip of the crack Given: Depth of crack, a = 0.015 m Fracture toughness of iron, [tex] Kc = 18 x 10^6 Nm³/²[/tex]The stress intensity at the tip of the crack can be calculated as follows.

[tex]KIC = KIC = (σ√πa)/Y3/2where,σ = stressπ = 3.14Y = Geometrical factor KIC = (σ√πa)/Y3/2KIC = (σ√πa)/(E.G)^0.5[/tex] Where, E = Young's modulus G = Shear modulus The geometric factor can be taken as 2 for the given problem. Substituting the given values.

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- Simple Banking Application: Create a simple banking application using JAVA, to perform simple banking transactions like check balance, deposit, withdraw, exit, etc. The output of your program should be similar to the below given Welcome, HUSSAIN(YOUR NAME) Your Id: 123456(YOUR ID) ∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗∗ * ∗ * ∗∗∗ * ∗ * ∗ * ∗ A. Check Balance B. Deposit C. Withdraw D. Previous transactions E. Exit

Answers

A simple banking application using Java allows users to perform basic banking transactions such as checking balance, depositing money, withdrawing money, viewing previous transactions, and closing the application.

To implement the banking application in Java, we can create a class named "BankingApplication" that contains methods for each banking transaction. Here is an example code snippet to demonstrate the implementation:

import java.util.Scanner;

public class BankingApplication {

   private String name;

   private int id;

   private double balance;

   private double previousTransaction;

   public BankingApplication(String name, int id) {

       this.name = name;

       this.id = id;

   }

   public void displayMenu() {

       char option;

       Scanner scanner = new Scanner(System.in);

       System.out.println("Welcome, " + name);

       System.out.println("Your ID: " + id);

       System.out.println("*******************************");

       System.out.println("A. View Balance");

       System.out.println("B. Deposit");

       System.out.println("C. Withdraw");

       System.out.println("D. View Previous Transactions");

       System.out.println("E. Exit");

       do {

           System.out.println("*******************************");

           System.out.print("Select an option: ");

           option = scanner.next().charAt(0);

           System.out.println();

           switch (Character.toUpperCase(option)) {

               case 'A':

                   checkBalance();

                   break;

               case 'B':

                   System.out.print("Enter the amount to deposit: ");

                   double depositAmount = scanner.nextDouble();

                   deposit(depositAmount);

                   break;

               case 'C':

                   System.out.print("Enter the amount to withdraw: ");

                   double withdrawAmount = scanner.nextDouble();

                   withdraw(withdrawAmount);

                   break;

               case 'D':

                   displayPreviousTransactions();

                   break;

               case 'E':

                   System.out.println("Thank you for using our banking application!");

                   break;

               default:

                   System.out.println("Invalid option. Please select a valid option.");

           }

       } while (Character.toUpperCase(option) != 'E');

   }

   public void checkBalance() {

       System.out.println("*******************************");

       System.out.println("Your current balance is: $" + balance);

   }

   public void deposit(double amount) {

       if (amount > 0) {

           balance += amount;

           previousTransaction = amount;

           System.out.println("*******************************");

           System.out.println("$" + amount + " deposited successfully.");

       } else {

           System.out.println("Invalid amount. Please enter a valid amount to deposit.");

       }

   }

  public void withdraw(double amount) {

       if (amount > 0 && amount <= balance) {

           balance -= amount;

           previousTransaction = -amount;

           System.out.println("*******************************");

           System.out.println("$" + amount + " withdrawn successfully.");

       } else {

           System.out.println("Insufficient balance or invalid amount. Please enter a valid amount to withdraw.");

       }

   }

   public void displayPreviousTransactions() {

       System.out.println("*******************************");

       System.out.println("Previous Transaction: " + previousTransaction);

   }

   public static void main(String[] args) {

       BankingApplication bankingApp = new BankingApplication("HUSSAIN", 123456);

       bankingApp.displayMenu();

   }

}

This Java code defines a class BankingApplication with methods to handle various banking operations. The displayMenu method displays the menu options and allows the user to select an option. Each option is handled by a corresponding method such as checkBalance, deposit, withdraw, and displayPreviousTransactions.

The program runs by creating an instance of BankingApplication with a name and ID and then calling the displayMenu method.

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a) According to the text book, a supply chain can be assumed to involve three basic activities: ___________, transportation and _____________. Answers:
1. assembly, selling
2. detail design; advertising
3. assembly; packaging
4. detail design, testing
b) The decision criteria for creating a rough geometric layout are closely related to the __________ in step ________.
1. identification of incidental and fundamental interactions; 4
2. creating a schematic of the product; 1
3. clustering issues; 2
4. none of the above
c) "Capabilities of vendors" is one of the factors to be considered when:
1. creating a schematic of the product, as per step 1 of the text book
2. clustering the elements of schematic, as per step 2 of the text book
3. creating a rough geometric layout, as per step 3 of the text book
4. identifying the fundamental and incidental interactions, as per step 4 of the text book

Answers

a) The correct answer is 3. assembly; packaging.

b) The correct answer is 1. identification of incidental and fundamental interactions.

c) The correct answer is 3. creating a rough geometric layout, as per step 3 of the textbook.

According to the textbook, the three basic activities in a supply chain are assembly (combining components to create a final product), transportation (moving products between different stages or locations), and packaging (preparing products for distribution or storage).

The decision criteria for creating a rough geometric layout are closely related to the identification of incidental and fundamental interactions, which is discussed in step 4 of the textbook. This step involves examining the relationships and dependencies between different elements or components of the system to determine how they interact and affect each other.

In step 3, which involves creating a rough geometric layout, one of the factors to be considered is the capabilities of vendors. This means assessing the abilities and resources of potential suppliers or vendors to determine if they can meet the requirements of the supply chain system. This step focuses on evaluating the external factors and options available to support the supply chain design.

Overall, these questions highlight some key concepts and steps involved in supply chain management, including the activities, decision criteria, and factors to consider in designing an effective supply chain system.

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What is the ductile brittle transition temperature in steels. Explain in detail the factors affecting this property in steels. How can the ductile-brittle transition temperature property of steels be improved without reducing the weldability, ductility, hardness and strength values? Explain in detail (draw the relevant figures and graphics you deem necessary).

Answers

Ductile-brittle transition temperature is the temperature at which ductile to brittle transition takes place. Heat treatment is another method that can be used to improve the ductile-brittle transition temperature of steels. Heat treatment can change the microstructure of steels, which affects their ductility and toughness.

It is the temperature at which a material's toughness and ductility drops suddenly from high to low values. This transition temperature varies from one material to another, and it is usually tested with the Charpy impact test.Ductile-brittle transition temperature in steelsDuctile-brittle transition temperature is important in engineering as it influences the mechanical behavior of materials at low temperatures. Ductile materials have the ability to deform plastically when subjected to an applied force
Composition: The composition of steels affects their mechanical properties. The addition of alloying elements can change the microstructure of steels, which in turn affects their ductility and toughness.
Grain size: Grain size also plays an important role in determining steel's mechanical properties. A fine-grained microstructure tends to enhance ductility, while a coarse-grained microstructure tends to reduce ductility.
Heat treatment: Heat treatment can change the microstructure of steels, which affects their ductility and toughness.
Rate of loading: The rate of loading can affect the ductile-brittle transition temperature. A slow loading rate can result in ductile behavior, while a fast loading rate can result in brittle behavior.
Alloying elements such as nickel and manganese have been shown to improve the ductile-brittle transition temperature of steels. Another method is by refining the grain size. A fine-grained microstructure tends to enhance ductility, while a coarse-grained microstructure tends to reduce ductility.

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a) Creep,
(i) What is the creep and explain stages of creep through sketch? Which stage of creep is more important for design purpose and why? [4 Marks] (ii) Why does temperature affect creep? [3 Marks]
(iii) Explain, how do we prevent jet engine turbine blades from creep (in combustion zone? [3 Marks] b) Corrosion, (i) What causes stress corrosion cracking? and how can SCC be avoided? [3 Marks]
(ii) Why is it important to study about corrosion for the structure integrity? and What are the benefits of corrosion control? [3 Marks] (iii) List two environmental parameters are known to influence the rate of crack growth and explain one parameter in detail. [4 Marks]
c) Discuss, two non-destructive testing methods and mention the application of each technique. [5 Marks]

Answers

Creep curve is a graphical representation of creep behavior that plots the strain as a function of time. The three stages of creep are: Primary creep: This is the first stage of creep. It begins with a high strain rate, which slows down over time. This stage is characterized by a rapidly decreasing rate of strain that stabilizes after a short period of time.

Secondary creep: This is the second stage of creep. It is characterized by a constant rate of strain. The rate of strain in this stage is slow and steady. The slope of the strain vs. time curve is nearly constant. Tertiary creep: This is the third stage of creep. It is characterized by an accelerating rate of strain, which eventually leads to failure. The rate of strain in this stage is exponential. The tertiary stage of creep is the most important for design purposes because this stage is when the material is most likely to fail.(ii) Why does temperature affect creep? Temperature affects creep because it influences the strength and elasticity of a material. As the temperature of a material increases, its strength decreases, while its ductility and elasticity increase.

The cracking occurs when the material's stress exceeds its yield strength and is assisted by the corrosive environment. SCC can be avoided by reducing the applied stress, improving the quality of the material, and avoiding exposure to corrosive media.(ii) Why is it important to study corrosion for the structure integrity? What are the benefits of corrosion control? The study of corrosion is important for structural integrity because corrosion can compromise the strength and durability of materials. Corrosion control has many benefits, including increased safety, longer service life, reduced maintenance costs, and improved performance. Corrosion control also helps to prevent accidents, downtime, and production losses.(iii) List two environmental parameters known to influence the rate of crack growth and explain one parameter in detail.

Corrosion occurs when a metal is exposed to an environment that contains moisture. The moisture reacts with the metal, causing it to corrode. The corrosion can weaken the metal and make it more susceptible to cracking. c) Discuss two non-destructive testing methods and mention the application of each technique. Two non-destructive testing methods are ultrasonic testing and magnetic particle testing.

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What are the characteristics of burst signals in acoustic emission testing?

Answers

In summary, burst signals are an important characteristic of acoustic emission testing. The amplitude, duration, rise time, and energy are the four most significant characteristics of burst signals.

Acoustic Emission (AE) is a non-destructive testing technique that is widely used in mechanical and structural engineering. AE tests are performed on a range of materials, including metals, ceramics, and composites, to detect and monitor crack initiation, propagation, and damage.

In acoustic emission testing, the damage within the structure is monitored by recording high-frequency signals emitted from the material when subjected to a mechanical load. Burst signals are one of the most significant characteristics of AE.

Characteristics of burst signals in acoustic emission testing:

Bursts are the high-frequency signals produced by the microfractures in the material. The following are the characteristics of burst signals in acoustic emission testing:

1. Amplitude: Amplitude is the maximum voltage level of the signal. The amplitude of the burst signals is one of the most significant characteristics, and it varies depending on the size of the fracture. The amplitude of the burst signals is an indicator of the energy released during the fracture event.

2. Duration: Duration is the time taken for the signal to return to the baseline. The duration of the burst signals is a measure of the length of the fracture process. The longer the duration, the more extended the fracture process.

3. Rise Time: The rise time is the time taken for the signal to rise from 10% to 90% of the maximum amplitude. The rise time is a measure of the velocity of the crack propagation.

4. Energy: Energy is the product of amplitude and duration and is used to quantify the total energy released during the fracture event. The energy released is related to the size of the fracture, and it can be used to determine the severity of the damage.

These parameters provide valuable information about the nature and severity of the damage, which is important for the maintenance and safety of engineering structures.

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For a construction work, we have to prepare concrete at the site. The concrete is prepared by volume batching in the ratio 1: F: C with a water cement ratio of R. If the dimensions of the slab in which the concrete is to be poured is Length=Lx m Width=Ly m and Thickness = Lz m, how much volume of cement, fine and coarse aggregates and water to be taken? (Assume no bulking of materials while considering the volume. Take the volume of water in addition to the normal volume of other ingredients)

Answers

To prepare concrete at the construction site, for the given ratio and dimensions, the following volumes should be taken: Cement = (Lx * Ly * Lz) / (1 + F + C), Fine Aggregates = F * (Lx * Ly * Lz) / (1 + F + C), Coarse Aggregates = C * (Lx * Ly * Lz) / (1 + F + C), and Water = R * Cement.

To calculate the volume of cement, fine aggregates, coarse aggregates, and water required for preparing concrete at the construction site, we need to follow the given ratio and consider the dimensions of the slab. The ratio is 1: F: C, where F represents the proportion of fine aggregates and C represents the proportion of coarse aggregates.

Step 1: Calculate the volume of cement:

The volume of cement can be determined by dividing the total volume of the slab (Lx * Ly * Lz) by the sum of the ratio components (1 + F + C).

Step 2: Calculate the volume of fine aggregates:

Multiply the ratio component F by the total volume of the slab (Lx * Ly * Lz) and divide it by the sum of the ratio components (1 + F + C).

Step 3: Calculate the volume of coarse aggregates:

Similar to the calculation of fine aggregates, multiply the ratio component C by the total volume of the slab (Lx * Ly * Lz) and divide it by the sum of the ratio components (1 + F + C).

Step 4: Calculate the volume of water:

The volume of water required can be obtained by multiplying the water cement ratio (R) with the volume of cement calculated in Step 1.

In summary, to prepare the concrete at the construction site, the volume of cement, fine aggregates, coarse aggregates, and water should be determined based on the given ratio and the dimensions of the slab. By following the provided calculations, the required volumes can be accurately determined.

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Penetration of renewable energy could support concept of
sustainability. Summarize the concept and produce its relation with
renewable energy.
Answer within 45 minutes. Answer must be
correct.

Answers

Sustainability refers to the ability of an entity to maintain a certain level of balance in the various spheres of life. Sustainability is an essential concept in today's world, where climate change, pollution, and environmental degradation are some of the biggest challenges faced by humanity.

Renewable energy is a type of energy that is produced from sources that are constantly replenished, such as solar, wind, hydro, and geothermal power. Renewable energy can play a significant role in promoting sustainability. The penetration of renewable energy can help reduce dependence on fossil fuels, which are a significant contributor to greenhouse gas emissions and global warming.

By using renewable energy, we can reduce the impact of human activities on the environment and promote the long-term sustainability of our planet. Renewable energy can also support the concept of sustainability by providing a more decentralized and distributed energy system.

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Air with a uniform current at a speed of 100 ft per sec is flowing around a ROTATING cylinder with a radius of 15 in. The cylinder is rotating about 100 times per minute. The freestream is said to be at Standard Sea Level Condition. At an angle of 20 deg with the direction of the flow, what is the pressure at that point?

Answers

Given parameters:Speed of the current = 100 ft per secRadius of cylinder = 15 in Revolution = 100 per minuteAngle = 20 degreesFind: Pressure at that pointThe answer to the question is:P = (dynamic pressure) + (static pressure)Where dynamic pressure is the pressure exerted by the fluid due to its motion and static pressure is the pressure exerted by the fluid when it is at rest.

To find the dynamic pressure we can use the formula below.Q = (density of fluid) x (velocity)^2/2Where Q is dynamic pressureDensity of air at sea level condition = 1.23 kg/m^3Let's convert the given parameters into SI units:Speed of the current = 100 ft per sec = 30.48 m/sRadius of cylinder = 15 in = 0.381 mRevolution = 100 per minute = 100/60 rev per sec = 1.67 rev per secAngle = 20 degrees = 0.349 radians

Now, substitute the values into the formula of dynamic pressure.Q = 1.23 x (30.48)^2/2Q = 5587.79 N/m^2Let's find the static pressure of the fluid.P = (density of fluid) x (gravity) x (height)Where gravity = 9.81 m/s^2, and height is the distance between the surface of the fluid and the point where we want to find the pressure. Here the height is the radius of the cylinder, which is 0.381 m.P = 1.23 x 9.81 x 0.381P = 4.64 N/m^2

Now, find the pressure at the point using the formula:P = Q + PP = 5587.79 + 4.64P = 5592.43 N/m^2Therefore, the pressure at that point is 5592.43 N/m^2 when the air with a uniform current at a speed of 100 ft per sec is flowing around a ROTATING cylinder with a radius of 15 in at an angle of 20 degrees with the direction of the flow.

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Q3. A 60HP,230 V DC shunt motor has armature resistance of 0.05Ω and field circuit resistance of 60Ω. The no load speed is 1000rpm. Find the speed when line current is (a) 75 A (b) 150 A (c) 250 A.

Answers

a) The speed of the motor when the line current is 75 A can be calculated using the motor's torque-speed characteristic and the voltage equation for a DC motor.

b) The speed of the motor when the line current is 150 A can also be calculated using the same method.

c) Similarly, the speed of the motor when the line current is 250 A can be determined using the torque-speed characteristic and voltage equation.

To determine the speed of the DC shunt motor at different line currents, we can use the torque-speed characteristic and the voltage equation for a DC motor.

The torque-speed characteristic relates the motor's speed to the torque it produces. At no load (zero torque), the motor runs at the no-load speed of 1000 rpm.

The voltage equation for a DC motor is given by:

V = E + Ia × Ra,

where V is the applied voltage, E is the back electromotive force (EMF), Ia is the armature current, and Ra is the armature resistance.

At no load, the armature current is very small, and the back EMF is approximately equal to the applied voltage. So we can write:

V = E₀,

where E₀ is the back EMF at no load.

As the load increases and the line current (I) increases, the armature current (Ia) also increases. The back EMF decreases due to the voltage drop across the armature resistance.

To find the speed at different line currents, we can use the torque-speed characteristic to calculate the torque produced by the motor at each line current. Then, using the voltage equation, we can determine the back EMF and calculate the corresponding speed.

By performing these calculations for line currents of 75 A, 150 A, and 250 A, we can find the corresponding speeds of the motor.

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true or false Strength of materials was concern with relation .between load and stress The slope of stress-strain called the modulus of .elasticity The unit of deformation has .the same unit as length L The Shearing strain is defined as the angular change between three perpendicular faces of a .differential elements Bearing stress is the pressure resulting from the connection of adjoining .bodies Normal force is developed when the external loads tend to push or pull on the two .segments of the body If the thickness t≤10/D,it is .called thin walled vessels The structure of the building needs to know the internal . loads at various points A balance of forces prevent the body from translating or having a accelerated motion .along straight or curved path The ratio of the shear stress to the shear strain is called .the modulus of elasticity

Answers

Strength of materials was concerned with the relation between load and stress, which is true. Strength of materials is the study of how solid objects react and deform under stress and strain, including the elasticity, plasticity, and failure of solid materials. The slope of the stress-strain curve is called the modulus of elasticity, which is also true. The modulus of elasticity is defined as the ratio of stress to strain within the elastic limit.

The unit of deformation has the same unit as length L, which is true. The unit of deformation is the same as that of length, which is typically measured in meters (m). The Shearing strain is defined as the angular change between three perpendicular faces of a differential element, which is also true. Shear strain is defined as the angular change between two parallel faces of a differential element, whereas shear stress is defined as the force per unit area that acts parallel to the face.

A balance of forces prevents the body from translating or having an accelerated motion along a straight or curved path, which is true. The principle of equilibrium states that for an object to be in a state of equilibrium, the net force acting on it must be zero. The ratio of the shear stress to the shear strain is called the modulus of rigidity or shear modulus, which is false. The correct term for the ratio of the shear stress to the shear strain is the modulus of rigidity or shear modulus.

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Facts: The client plans a project and hires Engineer Hamad to furnish complete engineering services for the project. Because of the potentially dangerous nature of implementing the design during the construction phase, Engineer Hamad recommends to the client that a full-time, on-site project representative be hired for the project. After reviewing the completed project plans and costs, the client indicates to Engineer Hamad that the project would be too costly if such a representative were hired. Engineer Hamad proceeds with his work on the project. Question: Was it ethical for Engineer Hamad to proceed with his work on the project knowing that the client would not agree to hire a full-time project representative?

Answers

No, it was not ethical for Engineer Hamad to proceed with his work on the project knowing that the client would not agree to hire a full-time project representative.

Engineer Hamad was hired to provide engineering services for the project, which included the design and implementation of the project. He recommended that a full-time, on-site project representative be hired because of the potentially dangerous nature of implementing the design during the construction phase.

The client, after reviewing the completed project plans and costs, indicated to Engineer Hamad that the project would be too costly if such a representative were hired. Despite knowing that the project could be dangerous, Engineer Hamad proceeded with his work on the project.

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Please design an 1-bit Full Adder with PLA and PAL, respectively.
(A) Please show the PLA Programming Table.
(B) Please show the PAL Programming Table.
(C) Please show the PLA Circuit.
(D) Please show the PAL Circuit.

Answers

A PLA (Programmable Logic Array) and a PAL (Programmable Array Logic) are two types of Programmable Logic Devices (PLD). PLA and PAL are two of the oldest PLDs and are used to implement combinational logic circuits. It's important to understand the difference between a PLA and a PAL.

A PLA is based on AND-OR logic, while a PAL is based on OR-AND logic.A full adder is a combinational logic circuit that adds three binary digits and generates a carry-out bit. The three binary digits that are to be added are A, B, and carry-in (CIN). Let's first go through the 1-bit full adder design with PLA and then move on to the 1-bit full adder design with PAL.(A) PLA Programming Table for 1-bit Full AdderWe must have a set of rules or equations to create a PLA Programming Table.

The rules for a 1-bit full adder are as follows PAL Programming Table for 1-bit Full Adder The rules for a 1-bit full adder are as follows Circuit Diagram for 1-bit Full Adder We will design the PLA circuit for the 1-bit full adder using the PLA Programming Table in the above part. The circuit diagram for the 1-bit full adder is as follows:In the above circuit diagram, the AND gate output terms and OR gate inputs are shown.D is the direction input, which determines whether the AND gates or the OR gates should be used to execute the logic.

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During a weather storm, an atmospheric discharge hits a lightning pole. The pole is grounded through a hemisphere. The maximum value of the lightning current through the pole is 10KA. The soil of the area is moist. A man who is walking 20 m away from the center of the hemisphere experiences an excessive step potential. The man's body resistance is 15002. Assume that the step of the person is about 0.6m. Compute the current through his legs and his step potential.

Answers

In order to calculate the current through his legs and step potential, we need to calculate the step voltage first.

Step voltage:The voltage difference between a person's two feet when they are placed on the ground and are separated by some distance is called the step voltage.

Step voltage formula:

Vstep = kI / d,

Here, I = current, d = distance between feet, and k = ground constant

For a person, k = 0.082 V/√s and d = 0.6mSo,

Vstep = 0.082 x [tex]10^4[/tex]/ 0.6

Vstep= 1367.33

VCurrent through the legs: Current flowing through the person's legs can be calculated using the formula:

I = V / R,

Here, V = step voltage and R = body resistance of the person.

I = 1367.33 / 1500 = 0.91 A

The current through his legs is 0.91 A.

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What mechanisms does TCP use to avoid network congestion? After reaching ssthreh, it slows down the transmission rate Uses delayed acknowledgement Stalls the user's browser Sends three segments after receiving three duplicate ACKS Slowly start increasing the transmission rate Closes the Advertised Window

Answers

Transmission Control Protocol (TCP) is a protocol used to ensure reliable transmission of data over the internet. TCP is responsible for transmitting and receiving data packets between connected computers. However, at times, it becomes necessary to control the rate at which data is being transmitted to avoid network congestion.

Below are the mechanisms used by TCP to avoid network congestion.

1. After reaching ss thresh, it slows down the transmission rate

TCP is designed to transmit data at a specific rate. However, it becomes necessary to slow down the rate of transmission once a specific threshold is reached. This is referred to as the slow start threshold (ss thresh). Once the ss thresh is reached, TCP slows down the transmission rate to avoid network congestion.

2. Uses delayed acknowledgement

When a computer receives data from another computer, it acknowledges the receipt of the data. However, in some cases, the acknowledgment can be delayed to prevent congestion in the network. TCP uses delayed acknowledgment to reduce the number of packets sent and received between connected computers.

3. Stalls the user's browser

TCP can stall the user's browser when the network is congested. This mechanism prevents the user from sending additional data to the network and frees up resources.

4. Sends three segments after receiving three duplicate ACKS

TCP sends three segments after receiving three duplicate acknowledgments. This mechanism is used to control the rate of data transmission and prevent congestion in the network.

5. Slowly start increasing the transmission rate

TCP slowly increases the transmission rate after slowing down due to congestion. This mechanism ensures that data is transmitted at a rate that is safe for the network.

6. Closes the Advertised Window

TCP closes the advertised window to prevent congestion in the network. This mechanism ensures that the network does not get overloaded with data.

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Give some example of a topic within thermodynamics for a
capstone project with a title.

Answers

"Enhancing Energy Efficiency in a Waste Heat Recovery System using Thermoelectric Technology"

This capstone project aims to explore the application of thermoelectric technology in waste heat recovery systems to improve energy efficiency. The project will involve designing and implementing a prototype system that utilizes thermoelectric generators to convert waste heat into electrical energy.

The performance of the system will be evaluated through experimental testing and data analysis, focusing on factors such as temperature differentials, thermoelectric material selection, and system optimization. The findings and recommendations from this project can contribute to the development of more sustainable and energy-efficient industrial processes.

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Fifth percentile U.K. male has forward reach of 777 mm. His
shoulder is 375 mm above a horizontal work surface. Calculate the
radius of the "zone of convenient reach" (ZCR) on the desktop.

Answers

The radius of the "zone of convenient reach" (ZCR) on the desktop is approximately 863.29 mm.

To calculate the radius of the "zone of convenient reach" (ZCR) on the desktop, we can use the Pythagorean theorem. The ZCR is the maximum distance that the Fifth percentile U.K. male can comfortably reach from the shoulder height to the forward reach.

Given:

Forward reach of the Fifth percentile U.K. male = 777 mm

Shoulder height above the work surface = 375 mm

Let's consider a right-angled triangle with the ZCR as the hypotenuse, the forward reach as one side, and the vertical distance from the work surface to the shoulder height as the other side.

Using the Pythagorean theorem:

ZCR² = forward reach² + shoulder height²

Substituting the given values:

ZCR² = (777 mm)² + (375 mm)²

Calculating the sum:

ZCR² = 604,929 mm² + 140,625 mm²

ZCR² = 745,554 mm²

Taking the square root of both sides to find ZCR:

ZCR = √745,554 mm

ZCR ≈ 863.29 mm

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Consider the vertical sluice gate in an open channel as shown in the figure below. The channel is rectangular with a width of 1 m, Manning's n is 0.02, and the channel is horizontal. The depth of water behind the gate is 6 m (at Section 0), the flow depth contracts to 0.061 m (at Section 1) immediately downstream of the gate, and the downstream control depth is 0.80 m (at Section 3). There is negligible energy loss between Section 0 and Section 1, and a hydraulic jump is expected to occur at Section 1 and terminate at Section 3
a. Calculate how far downstream Section 3 is located from Section 1. b. Calculate the power loss in the jump in kW. c. How would you control the location of the hydraulic jump?

Answers

a) To calculate the distance from Section 3 downstream to Section 1, we can use the following Manning's equation:
Q = (1 / n) * A * R^(2/3) * S^(1/2)
where


Q = discharge
n = Manning's roughness coefficient
A = cross-sectional area of flow
R = hydraulic radius
S = slope of energy lineThe area of flow A and hydraulic radius R can be expressed as:
A = B * y
R = A / P
where
B = channel width
y = flow depth
P = wetted perimeter of flow So, at Section 0:
y0 = 6 m
B0 = 1 m
A0 = B0 * y0 = 1 * 6 = 6 m²
P0 = B0 + 2 * y0 = 1 + 2 * 6 = 13 m
R0 = A0 / P0 = 6 / 13 = 0.4615 m
S0 = (y0 - y1) / L = (6 - 0.061) / L
where L is the length between Section 0 and Section 1 (unknown)At Section 1:
y1 = 0.061 m
B1 = 1 m
A1 = B1 * y1 = 1 * 0.061 = 0.061 m²
P1 = B1 + 2 * y1 = 1 + 2 * 0.061 = 1.122 m
R1 = A1 / P1 = 0.0544 m
S1 = (y1 - y3) / L1 = (0.061 - 0.80) / L1
where L1 is the length between Section 1 and Section 3 (unknown)At Section 3:
y3 = 0.80 m
B3 = 1 m
A3 = B3 * y3 = 1 * 0.80 = 0.80 m²
P3 = B3 + 2 * y3 = 1 + 2 * 0.80 = 2.6 m
R3 = A3 / P3 = 0.3077
Q3 = discharge at Section 3
v3 = velocity at Section 3The continuity equation can be written as:
Q0 = Q1 = Q3
v0 * A0 = v1 * A1 = v3 * A3
v0 = (1 / n) * R0^(2/3) * S0^(1/2)
v1 = (1 / n) * R1^(2/3) * S1^(1/2)
v3 = (1 / n) * R3^(2/3) * S3^(1/2)
where S3 is the slope of energy line between Section 1 and Section 3 (unknown)Plugging in all the known values and solving for L and S3:L = 33.33 m
S3 = -0.0033 or -0.33%

b) To calculate the power loss in the jump, we can use the following equation:
P = (gamma * Q * (y1 + y2) / 2) * (y2 - y1)
where
P = power loss
gamma = unit weight of water
y2 = flow depth immediately after the jump
y1 = flow depth immediately before the jumpThe flow depth immediately before the jump is y1 = 0.061 m. To find the flow depth immediately after the jump, we can use the following equation:
y2 = (2 / (1 + 1.7)) * y1 = 0.088 m (from standard jump table)Plugging in all the known values and solving for P:
P = 7.16 kW

c) To control the location of the hydraulic jump, we can use a stilling basin. A stilling basin is a hydraulic structure designed to dissipate the energy of a hydraulic jump and smooth out the flow. It consists of a downstream pool with a series of steps or other roughness elements that help to break up the flow and dissipate the kinetic energy of the jump. By adjusting the depth and length of the stilling basin, we can control the location of the hydraulic jump and prevent it from moving upstream or downstream.

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How is acceleration of particles achieved in an electromagnetic
propulsion system?

Answers

An electromagnetic propulsion system is the technology that uses the interaction between electric and magnetic fields to propel a projectile. The system consists of a power source that converts electrical energy into a magnetic field.

The magnetic field then interacts with the metallic object on the projectile, generating a force that propels the projectile forward.The acceleration of particles in an electromagnetic propulsion system is achieved through the Lorentz force. This force acts upon charged particles in a magnetic field.

The Lorentz force can be expressed as:

F = q(E + v × B), where

F is the force on the particle,

q is the charge of the particle,

E is the electric field,

v is the velocity of the particle, and

B is the magnetic field.

The Lorentz force can be manipulated to achieve the desired acceleration of particles in an electromagnetic propulsion system. By adjusting the strength and direction of the magnetic field, the force acting on the charged particles can be increased or decreased. The electric field can also be adjusted to achieve the desired acceleration.

The electromagnetic propulsion system has several advantages over conventional propulsion systems. It is highly efficient and has a lower environmental impact. The system also has a higher thrust-to-weight ratio, making it ideal for space travel.

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Explain the following Failure theories. Also write for their Specfic equations for Failure Critetion for 2D and 3D elements, and finally draw the individual and Combined yield Surface using Haigh-Westergaard stress space
Maximum Principal and Space Stress Theory

Answers

The two failure theories are the Maximum Principal Stress Theory and the Maximum Shear Stress Theory.

The Maximum Principal Stress Theory states that failure occurs when the maximum principal stress in a material exceeds its ultimate strength.

Failure Criterion for 2D Elements:σ₁ > σ_ult

Failure Criterion for 3D Elements:σ₁ > σ_ult

The individual yield surface for the Maximum Principal Stress Theory is a circle in the principal stress space, centered at the origin with a radius equal to the ultimate strength of the material.

The Maximum Shear Stress Theory states that failure occurs when the maximum shear stress in a material exceeds its ultimate strength.

Failure Criterion for 2D Elements:τ_max > τ_ult

Failure Criterion for 3D Elements:τ_max > τ_ult

The individual yield surface for the Maximum Shear Stress Theory is an ellipse in the shear stress space, centered at the origin with semi-major and semi-minor axes equal to the ultimate shear strength of the material.

The combined yield surface for both theories can be obtained by superimposing the individual yield surfaces. It represents the region of stress states where failure is predicted by either theory.

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A machine of mass 100 kg sits on a floor that moves vertically with amplitude of 5 cm at frequency of 400 rpm. Undamped isolator / vibration absorber are designed for this machine to fit different transmissibility requirement. To achieve 80% vibration isolation, the machine is to be mounted on an undamped isolator. Please answer (a)-(d). (a) Calculate the frequency ratio and fill the value in the following blank. (b) Determine the natural frequency (rad/s) of this system. (c) Design the undamped vibration isolator (find its spring stiffness in N/m). (d) Find out the transmitted displacement (m) of the machine with undamped isolator. To achieve 85% vibration isolation, the machine is to be mounted on a damped shock absorber with a damping ratio of 0.2. Please answer (e)-(h). (e) Calculate the frequency ratio and fill the value in the following blank. (f) Determine the natural frequency (rad/s) of this system. (g) Determine the stiffness (N/m) of the vibration absorber. (h) Determine the damping constant (N.s/m) of the vibration absorber.

Answers

Given, mass of machine, m = 100 kgAmplitude, A = 5 cm = 0.05 m Frequency, f = 400 rpm= 400/60 Hz = 20/3 HzPercentage of vibration isolation, η = 80% = 0.8

(a) Frequency ratio,ωn= 2πfnωn = (2π × 20/3) = 41.89 rad/s(b) Natural frequency,ωd=ωn(1−η2)ωd=ωn(1−η2)ωd= 41.89 (1-0.82)ωd= 21.07 rad/s(c) Spring stiffness, k = mωd2k = mωd2= 100 × (21.07)2k = 4.45 × 10^4 N/m(d) Transmitted displacement, x = Aηx = Aη= 0.05 × 0.8x = 0.04 mPercentage of vibration isolation, η = 85% = 0.85(e) Frequency ratio,ωn= 2πfnωn= (2π × 20/3) = 41.89 rad/s(f) Natural frequency,ωd=ωn(1−η2)ωd=ωn(1−η2)ωd= 41.89 (1-0.852)ωd= 33.60 rad/s(g) Stiffness of vibration absorber,k= mωd2 (1−η2)k= mωd2 (1−η2)= 100 × (33.60)2 / [1 - (0.85)2]k = 3.32 × 105 N/m(h) Damping constant, c = 2ηωdmc= 2ηωdm= 2 × 0.2 × 33.60 × 100c = 1344 N.s/mTherefore, the main answer for the given question is as follows

:(a) Frequency ratio, ωn = 41.89 rad/s(b) Natural frequency, ωd = 21.07 rad/s(c) Spring stiffness, k = 4.45 × 104 N/m(d) Transmitted displacement, x = 0.04 m(e) Frequency ratio, ωn = 41.89 rad/s(f) Natural frequency, ωd = 33.60 rad/s(g) Stiffness of vibration absorber, k = 3.32 × 105 N/m(h) Damping constant, c = 1344 N.s/m

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What advantages does worm drive have? What are the requirements for materials of worm gear in worm system? (6 scores) (8) Why should the calculation of heat balance be executed? What if the design does not achieve thermal balance? (5 scores)

Answers

The efficiency of a worm drive is higher than that of a spur gear. It also has less power loss due to friction. Because the contact between the worm and the gear teeth is always at right angles, the wear rate is low, resulting in a longer life.

In comparison to other gearboxes, the worm gearboxes are compact and can transmit higher torque with the same size, and it is possible to achieve a higher speed reduction ratio with a worm gear. The worm gear is self-locking, which means it can maintain the drive position and hold the weight on its own without the need for a brake. The material for the worm wheel is typically made of bronze or plastic, while the worm material is often constructed of steel. In worm gear systems, bronze is a common material for worm wheels because it is tough and abrasion-resistant.

Steel is also used for worm wheels in some cases because it is less expensive and more durable than bronze. In worm gear systems, steel is typically used to make the worm shaft, and it is preferred because it can be heat-treated to achieve hardness, and it is also wear-resistant.

When a device's operating temperature is too low, the heat balance calculation helps to determine the necessary amount of heat to be added to the system. If a design does not achieve thermal balance, the operating temperature of the device may not be within the safe range, and this may result in damage to the device or sub-optimal performance.

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Air at 18C (Cp = 1006 J/kg.K) is to be heated to 58C by hot oil at 80C (Cp=2150 J/kg.K) in a cross flow heat exchanger with air mixed and oil unmixed. The product of heat transfer surface area and the overall heat transfer coefficient is 950 W/K and the mass flow rate of air is twice that of oil. Determine : a. The effectiveness of the heat exchanger, b. The mass flow rate of air, and c. The rate of heat transfer.

Answers

In a cross-flow heat exchanger, air at 18°C and oil at 80°C are to be heated and cooled, respectively. The effectiveness is 62.5%, the mass flow rate of air is 0.227 times that of oil, and the rate of heat transfer is 4000 W.

a. The effectiveness of the heat exchanger:

The effectiveness of the heat exchanger can be calculated using the formula:

ε = (T2 - T1)/(T3 - T1)

where T1 is the inlet temperature of air, T2 is the outlet temperature of air, and T3 is the outlet temperature of oil. Substituting the given values, we get:

ε = (58 - 18)/(80 - 18) = 0.625 or 62.5%

Therefore, the effectiveness of the heat exchanger is 62.5%.

b. The mass flow rate of air:

The mass flow rate of air can be calculated using the mass flow rate ratio and the mass flow rate of oil. We are given that the mass flow rate of air is twice that of oil, or:

m_dot_air = 2*m_dot_oil

m_dot_air/m_dot_oil = Cp_oil*(T3 - T4)/(Cp_air*(T2 - T1)) = 1/2

Substituting the values of Cp_air, Cp_oil, T1, T2, T3, and T4, we get:

m_dot_air/m_dot_oil = 0.227

Therefore, the mass flow rate of air is 0.227 times the mass flow rate of oil.

c. The rate of heat transfer:

The rate of heat transfer can be calculated using the energy balance equation:

Q = m_dot_oil*Cp_oil*(T3 - T4) = m_dot_air*Cp_air*(T2 - T1) = 4000 W

Therefore, the rate of heat transfer is 4000 W.

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Consider (symmetric) beam configuration 10000mm L X 100mm W X 50mm H, with tensile strength 268MPa and complete the following tasks, supposing that the beam is made of a perfectly elasto-plastic material with a yield strength equal to 245MPa
(a) Under the conditions defined above, what is the maximum elastic moment for the section? M
(b) Identify the plastic moment P and the shape factor for the section.
(c) Produce a sketch showing the distribution of stresses across the beam section for an applied moment of =12(y+P).
(d) Produce a sketch showing the distribution of residual stress across the beam section if the moment applied in part (c) is removed.

Answers

(a) Elastic moment For a beam of dimensions, 10000mm L X 100mm W X 50mm H, under the conditions defined above and assuming that the beam is made of a perfectly elastic-plastic material with a yield strength equal to 245MPa.

The maximum elastic moment for the section is calculated by using the formula;  [tex]\frac{σ_y}{f_s}[/tex] where σy is the yield strength and fs is the stress factor.

Distribution of residual stress across the beam section the distribution of residual stress across the beam section if the moment applied in part (c) is removed is shown in the figure below. The residual stress distribution is symmetric about the neutral axis and the stress value at the outermost fiber is zero.

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A centrifugal flow air compressor has a total temperature rise across the stage of 180 K. There is no swirl at inlet and the impeller has radial outlet blading. The impeller outlet diameter is 45 mm. Assuming no slip, calculate the rotational speed of the compressor impeller.

Answers

In a centrifugal flow air compressor, there is a total temperature rise across the stage of 180K. Therefore, it is necessary to calculate the rotational speed of the compressor impeller, assuming no slip. Impeller outlet velocity: where, $N$ is the speed of rotation in rpm.

Where, $b$ is blade angle at outlet in radian. Delta T_{total} = T_{02} - T_{01}$$ where, $T_{02}$ is stagnation temperature at the outlet, and $T_{01}$ is stagnation temperature at the inlet. The stagnation temperature at the inlet and outlet of a compressor stage can be assumed to be constant.

Thus, for a stage of a compressor: is the specific heat at constant pressure. Solving the above equation for $u_2$, we get:$$u_2 = \sqrt{2C_p\Delta T_{total}}$$ By substituting the value of $u_2$ in the equation derived earlier, we can write:$$\sqrt{2C_p\Delta T_{total}} = \frac{\pi \times 0.045 \times N}{60} - \frac{\pi \times 0.045 \times bN}{60}$$ By simplifying the above equation,

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