An Particle a has Weston practical.
What is Friction?
The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab).
According to the book Soil Mechanics(opens in new tab), scientists started putting together the laws governing friction in the 1400s.
However, because the interactions are so complex, characterizing the force of friction in various circumstances typically requires experiments and can't be derived from equations or laws alone. There are numerous exceptions to every frictional general rule.
Therefore, An Particle a has Weston practical.
To learn more about friction, refer to the link:
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Any is 160 cm tall and stands 50 cm in front of a plane mirror. The image of Amy is ?
Answer:
Option A. 160 cm tall and 100 cm in front of Amy
Explanation:
To know the the correct answer to the question, we must recognise that the image formed by plane mirror is:
I. Same size as the object.
II. Same distance as the object from the mirror.
III. Laterally inverted.
IV. Virtual
With the above information, we obtained the answer to the question as follow:
Object height = 160 m
Thus,
Image height = 160 m
Distance of object from mirror = 50 cm
Therefore,
Distance of image from the mirror = 50 cm
Distance between the object and image = 50 + 50 = 100 cm
Thus, option A gives the correct answer to the question because the image of Amy is 160 cm tall and 100 cm in front of her.
if something is frictionless does it have thermal energy
Answer:
No
Explanation:
because there is no pressure
A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 5.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do
Answer:
1568 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 80 Kg
Distance (d) = 5 m
Coefficient of kinetic friction (μ) = 0.4
Workdone (Wd) =?
Next, we shall determine the normal reaction. This can be obtained as follow:
Mass (m) = 80 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?
N = mg
N = 80 × 9.8
N = 784 N
Next, we shall determine force of friction. This can be obtained as follow:
Coefficient of kinetic friction (μ) = 0.4
Normal reaction (N) = 784 N
Force of friction (F) =?
F = μN
F = 0.4 × 784
F = 313.6 N
Finally, we shall determine the work done. This can be obtained as follow:
Distance (d) = 5 m
Force of friction (F) = 313.6 N
Workdone (Wd) =?
Wd = F × d
Wd = 313.6 × 5
Wd = 1568 J
Thus, the workdone is 1568 J
23. Lunar Gravity Compare the force holding a
10.0-kg rock on Earth and on the Moon. The
gravitational field on the Moon is 1.6 N/kg.
Explanation:
Given
mass of the rock is 10 kg
Force requires to hold the rock is equal to its weight
Weight is given by the product of mass and acceleration due to gravity
Weight on the earth surface
[tex]\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N[/tex]
Weight on the moon surface
[tex]\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N[/tex]
So, the force holding the rock on earth is approximately 6 times the force on the moon.
what is acceleration?
Answer:
the rate of change of velocity per unit of time.
Answer:
accelerate is rate of chang of velocity
Descriptions of the sky at various locations on Earth
which of the following changes will increase the frequency of an oscillating pendulum?
a. an increase in the mass of the pendulum.
b. an increase in the initial height of release.
c. an increase in the length of the rope.
d. more than one of the above
e. none of the above
explain your answer in your own words.
NO LINKS.
Answer:
b (i think)
Explanation:
A ball of mass 8kg falls from rest from a height of 100m. Neglecting air resistance, calculate its total energy after falling a distance of 40m.
Answer:
Total energy, T= 4704 Joules
Explanation:
Given the following data;
Mass = 8kg
Initial height, h1 = 100m
Final height, h2 = 40 m
We know that acceleration due to gravity is equal to 9.8 m/s².
To find the total energy, T;
T = mg(h1 - h2)
T = 8 * 9.8 * (100 - 40)
T = 78.4 * 60
Total energy, T= 4704 Joules
What does the potential energy diagram of a chemical reaction tell you?
O A. Whether atoms are being created or destroyed
O B. Whether the reaction is endothermic or exothermic
C. Whether there are more reactants or products
D. Whether the law of conservation of matter is being obeyed
Answer:
B
Explanation:
I'm learning about this now actually and it can be a little confusing but it would be endothermic or exothermic. if endothermic the products have less energy than the reactants and if exothermic products have more energy than reactants
Which quantity does not change when there is an increase in temperature?
Answer:
But Mass of solids does not depend upon the temperature because it is matter contained in the solids.
Explanation:
The mass is the quantity which does not change when there is an increase in temperature.
What is mass?A tangible body's mass is the amount of matter it possesses. It's also a metric of inertial, or the resistance to velocity when a net force is exerted.
The quantity does not change when there is an increase in temperature is mass because it is matter that makes up solids, their mass is unaffected by temperature.
Thus, the mass is the quantity which does not change when there is an increase in temperature.
Learn more about the mass here:
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Water in an electric teakettle is boiling. The power absorbed by the water is 0.90 kW. Assuming that the pressure of vapor in the
kettle equals atmospheric pressure, determine the speed of effusion of vapor from the kettle's spout if the spout has a cross-
sectional area of 1.60 cm2. Model the steam as an ideal gas.
Answer:
v = 4.233 m/s
Explanation:
By applying the rate of boiling from [tex]Q= mL_v[/tex];
the rate of the boiling can be described as:
[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]
The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:
[tex]P_oV_o = nRT[/tex] --- (1)
where;
n = number of moles;
[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]
Then; equation (1) can be rewritten as:
[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]
∴
[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]
Then:
[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]
making (v) the subject of the formula:
[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]
Given that:
[tex]\mathcal{P}[/tex] = 0.90 kW = 900 W
R(rate constant) = 8.314 J/mol.K
Temperature at 100° C = 373K
For water vapor:molar mass= 18.015 g/mol ≅ 0.0180 kg/mol
Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg
Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]
Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²
[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]
v = 4.233 m/s
A 1.5 V battery is connected to a 1,000 μF capacitor in series with a 150 Ω resistor. a. What is the maximum current that flows through the resistor during charging? b. What is the maximum charge on the capacitor? c. How long does the capacitor take to reach a potential of 1.0V?
Answer:
[tex]0.01\ \text{A}[/tex]
[tex]0.0015\ \text{C}[/tex]
[tex]0.0608\ \text{s}[/tex]
Explanation:
[tex]V_0[/tex] = Voltage = 1.5 V
[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]
[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]
Current is given by
[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]
Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].
Charge is given by
[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]
The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].
Voltage is given by
[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]
Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].
PLEASE HELP ME WITH THOSE TWO QUESTIONS
A 122 Ohm, 232 Ohm, and 500 Ohm resistors are all connected in series with a 12 V battery. What is the current flowing through them?
A 100 Ohm, 200 Ohm, and 300 Ohm resistor are all connected in series to a 12 V battery. What is the potential difference drop across the 100 Ohm resistor?
Answer:
(a) 0.014 A
(b) 2 V
Explanation:
(a) Applying
V = IR'...................... Equation 1
Where V = Voltge, I = current, R = total resistance.
make I the subject of the equation
I = V/R'................... Equation 2
From the question,
Given: V = 12 V, R' = (122+232+500) ohms (The resistance are connected in series) = 854 ohms
Substitute these values into equation 2
I = 12/854
I = 0.014 A
(b) Applying
V' = V(R₁)/(R₁+R₂+R₃)...................... Equation 3
Where V' = Voltage across the 100 ohms resistor.
From the question,
V = 12V, R₁ = 100 ohm, R₂ = 200 ohm, R₃ = 300 ohm.
Substitute these values into equation 3
V' = (12×100)/(100+200+300)
V' = 1200/600
V' = 2 V
Question 6 of 10
The mass number of a nucleus decreases during which nuclear reactions?
A. Nuclear fusion and alpha decay
B. Nuclear fission and beta decay (electron emission)
C. Nuclear fusion and beta decay (positron emission)
D. Nuclear fission and alpha decay
Answer:
D. Nuclear Fission and alpha decay
Convert 0.0375 kg to g
Answer: 37.5 g
Explanation: you multiply 0.0375 by 1000 which equals 37.5
Answer:
0.0375 kilograms are equal to 37.5 grams
An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D (which overlaps A), as shown in the figure below. O is the origin. Suppose you take measurements and find that AB is 31 cm , BC is 12 cm , and AO is 7 cm .(Figure 1)
A. What is the ant’s position at point A?
B. What is the ant’s position at point B?
C. What is the ant’s position at point C?
D. What is the ant’s position at point D?
Answer:
Ants position at point A = -7 cm
Ants position at point B = 38 cm
Ants position at point C = 26 cm
Ants position at point D = -7 cm
Explanation:
In this question, we are dealing with displacement which is the change in position of an object.
Now, we are told the journey began from A to B and then from C to D.
Now, AB = 31 cm and AO = 7cm
But along AB, we have the origin O.
Since A is on the left hand side of the origin, it means it is negative. Thus, position A = -7cm
Then position B = 31 - (-7) = 31 + 7 = 38 cm
Since BC = 12cm, then position C = 38 - 12 = 26 cm
Position D is same as position A = -7cm
A piece of stone of mass 80 g is
dropped into a measuring cylinder
containing water. The water level
increases from 12 cm² to 37 cm
Calculate the density of the stone.
A. 32 g/cm
B. 3.2 g/cm
C. 320 g/cm
D. 3.20 g/cm
8
37+12
Answer:
this is how I know it though my answer is not in the choices
Explanation:
M=80g
V=37cm-12 cm
15cm
Density=mass/volume
80g/15cm3
5.33g/cm3
Which of these would have the most kinetic energy?
O A. a stormy ocean
O B. a running stream
O C. an icy lake
O D. a lake in summer
Answer:
A stormy ocean, having the most kinetic energy means it moves more and faster
Typical novae occur when (a) a red-giant star ejects a planetary nebula; (b) two neutron stars merge, forming a more massive neutron star; (c) an extremely massive star collapses, and also ejects its outer atmosphere; (d) matter accreted from a companion star unstably ignites on the surface of a white dwarf; or (e) a neutron star’s magnetic field becomes strong enough to produce two oppositely directed jets of rapidly moving particles.
Answer:
I think its d matter accreted from a companion star unstable ignites on the surface of a white dwarf.
A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep encounters an unbanked curve of radius 50 m. The Jeep follows the road from B to C traveling at a constant speed of 10 m/s while the direction of the Jeep changes from east to south. What is the magnitude of the acceleration of the Jeep as it travels from A to B
Answer:
a = 0 m/s²
Explanation:
From A to B the jeep travels in a straight line with a constant speed of 10 m/s. Acceleration is defined as the rate of change in velocity. In the current scenario, the velocity of the jeep remains constant. The direction of the jeep does not change as it travels in the straight path. Also, the magnitude of the velocity is constant at 10 m/s.
Therefore, there is no change in the velocity of the jeep from A to B. Hence, the will be no acceleration from A to B.
a = 0 m/s²
You throw a ball straight up. Compare the sign of the work done by gravity while the ball goes up with the sign of the work done by gravity while it goes down.
a. Work is + on the way up and + on the way down
b. Work is + on the way up and - on the way down
c. Work is - on the way up and + on the way down
d. Work is - on the way up and - on the way down
Answer:
c. Work is - on the way up and + on the way down
Explanation:
Work done is given as the product of the applied force and the displacement of the object.
Work done = F x d
Work done = mg x d
where;
g is acceleration due to gravity = 9.8 m/s²
When the ball goes up, it moves against the force of gravity which tends to pull every object downwards. Since the ball moves against gravity, the work done is negative.
Also, when the ball goes down, it moves in the direction of gravity which acts downwards. Since the ball moves in the same direction as gravity, the work done is positive.
The correct option is "C. Work is negative (-) on the way up and positive (+) on the way down"
A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 290 N applied to its edge causes the wheel to have an angular acceleration of 0.854 rad/s2.
(a) What is the moment of inertia of the wheel?
kg · m2
(b) What is the mass of the wheel?
kg
(c) If the wheel starts from rest, what is its angular velocity after 5.80 s have elapsed, assuming the force is acting during that time?
rad/s
Answer:
c
Explanation:
units c mark me brainless k
write the formula of mechanical advantage
Answer:
the formula of mechanical advantage is
MA = load / effort
VR = effort distance / load distance
hope it is helpful to you
Future space stations could create an artificial gravity by rotating. Consider a cylindrical space station that rotates with a period of 28 seconds about its axis. Astronauts walk on the inside surface of the space station, and they experience an Earth-like gravitational acceleration of 9.8 m/s2. What is the diameter of the space station?
510m
145m
660m
390m
Answer:
P = 2 pi R / v period of space station
F / m = v^2 / R centripetal force per unit of mass
So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2
Also, F / m = 9.8 m/s^2 earth's gravitational attraction
So 9.8 = 4 pi^2 R / P^2 or R = 9.8 P^2 / 4 * pi^2) = 195 m
Or D = 2 R = 390 m the diameter required
Convert 0.00553s to cs
Answer: 0.553
Explanation:
Please help with all three questions
Answer:
The correct answer is D C A
Two people are carrying a uniform 704.0 N log through the forest. Bubba is 2.2 m from one end of the log (x), and his partner is 0.9 m from the other end (y). The log is 6.2 m long (z). What weight is Bubba supporting
Answer:
F₁ = 499.61 N , this is the force that Bubba support
Explanation:
The trunk is in equilibrium with the two forces applied by man, let's use the equilibrium relation
let's set a reference frame at the extreme left and assume that the counterclockwise rotations are positive
Let's write the expression for the translational equilibrium
subscript 1 is for Bubba's mass and subscript 2 for his partner
F₁ + F₂ -W = 0
F₁ + F₂ = W
the expression for rotational equilibrium
∑ τ = 0
F₁ 2.2 + F₂ (6.2-0.9) - W 6.2/2 = 0
2.2 F1 + 5.3 F2 = 3.1 W
let's write our system of equations
F₁ + F₂ = W
2.2 F₁ + 5.3 F₂ = 3.1 W
we solve for F₁ in the first equation and substitute in the second
F₁ = W-F₂
2.2 (W- F₂) + 5.3 F₂ = 3.1 W
F₂ ( -2.2 +5.3) = W (3.1 - 2.2)
F₂ = 704 0.9 / 3.1
F₂ = 204.39 N
This is the force that the partner supports
we look for F1
F₁ = W-F₂
F₁ = 704 - 204.39
F₁ = 499.61 N
This is the force that Bubba support
Describe the processes that take place inside the nucleus for the following decays; Beta- decay and Beta+ decay.
Answer:
Explanation:
(a) Electron Emission (Beta- decay):
When an unstable nucleus decays by the emission of Beta- particle, its charge number ‘Z’ increases by 1 but, its mass number ‘A’ remains unchanged. The transformation is represented by the equation:
[tex]_zX^A\ -------->\ _{Z+1}Y^A\ +\ _{-1}e^0[/tex]
It is called ‘Negative Beta Decay’. It is more common than alpha decay.
Example:
[tex]_6C^{14}\ -------->\ _{7}N^{14}\ +\ _{-1}e^0[/tex]
Note:
There are no electrons in a nucleus so, with the emission of a particle, one of the neutrons is converted to a proton and an electron.
[tex]_0n^1\ --------->\ _1P^1\ +\ _{-1}e^0[/tex]
(b) Positron Emission (Beta+ decay):
When an unstable nucleus decays by the emission of the positron, its charge number ‘Z’ decreases by 1 but, its mass number ‘A’ remains unchanged. The transformation is represented by the equation:
[tex]_zX^A\ -------->\ _{Z-1}Y^A\ +\ _{+1}e^0[/tex]
Examples:
[tex]_{15}P^{30}\ -------->\ _{14}Si^{30}\ +\ _{+1}e^0[/tex]
Note:
Inside the nucleus, only a proton can be transformed into a neutron with the emission of a positron (anti-particle of electron)
[tex]_1P^1\ -------->\ _0n^1\ +\ _{+1}e^0[/tex]
PLS HELPP MEEE
Fiber-optic cables rely on total internal reflection.
Please select the best answer from the choices provided
T
F
In the diagram shown below, the distance from the dotted line to Point A, or the distance from the dotted line to Point D is known as the
Answer:
The dotted line connecting two points is known as the distance traveled.
Explanation:
The distance traveled is a physical quantity that refers to the total displacement of a body. This distance is usually shown as a dotted line that connects two points in an image. In general, we can say that the distance traveled is calculated by adding all the distances that an element makes when leaving one point and reaching another point, which is its final position.
An example of this can be seen in the image shown below, where the red line represents the displacement of a body that left point A and arrived at point B. The blue dotted line represents the distance traveled and refers to the total displacement of that body, showing all the distances it covered while walking from point A to point B.