SAT College

Part III: Soft Drink Case (randomized block ANOVA)
A soft drink producer has developed four new products with different flavors. The
company wants to know whether customers have different preferences for these four
products. Six persons were asked to sample taste and rate each flavor on a scale of 1-20.
Delivery Time (Hours)
District Office UPX INTEX
Seattle 32 25
Los Angeles 30 24
Boston 19 15
Cleveland 16 15
N.Y.C. 15 13
Houston 18 15
Atlanta 14 15
St. Louis 10 8
Milwaukee 7 9
Denver 16 11
2
The data are given in the Excel dataset “drink.xls” which is attached. Based on the data
given, with a significance level of α = 0.05, conduct a formal hypothesis test to check
whether there exists different preferences.
Part IV: Credit card application case (Two-way ANOVA analysis)
In studying potential customers’ application for new credit cards, you are required to
analyze their credit scores (a value between 300 and 850). Attached Excel file
“creditcard.xls” contains credit scores for randomly selected individuals from Texas,
Pennsylvania, California, and Florida, who are grouped according to their ages. With
significance level of α = 0.05, test whether the state factor influence applicants’ credit
scores, whether the age factor has an influence on the creditworthiness, and whether there
is an interaction effect between two factors.

Part V: Lakeland Case (Contingency table analysis, test of independence)
Each home sold by Lakeland Homes can be classified according to the price level and to
the style. The management would like to determine if the price of the home and the style
of the home are independent variables. With the observed data given in the following
table and with a significance level of  = 0.05, conduct a formal hypothesis test to help
the management in decision making process.

Answers

Answer 1

Answer:

Don't forget to make brainliest answer

Explanation:

I apologize, but I am not able to access the attached Excel files. However, I can provide a general overview of the types of analysis and tests that could be used for each case.

Part III: Soft Drink Case (randomized block ANOVA)

To determine whether there are differences in preferences for the four new soft drink products, a randomized block ANOVA could be conducted. This type of ANOVA is used when there are groups or blocks of individuals that are expected to have similar responses, such as in this case where the six persons were asked to sample and rate each flavor. The null hypothesis would be that there are no significant differences in the mean ratings for the four products, and the alternative hypothesis would be that at least one of the means is significantly different. If the null hypothesis is rejected, further post-hoc tests could be conducted to determine which means differ significantly from each other.

Part IV: Credit card application case (Two-way ANOVA analysis)

To analyze whether the state and age factors have an influence on applicants' credit scores, a two-way ANOVA could be conducted. This type of ANOVA is used when there are two factors that could potentially have an effect on the response variable, such as in this case where the factors are state and age. The null hypothesis for each factor would be that there are no significant differences in the mean credit scores across the different levels of that factor, and the alternative hypothesis would be that there is at least one significant difference. If the null hypothesis is rejected for either factor, further post-hoc tests could be conducted to determine which levels differ significantly from each other. Additionally, an interaction effect could be tested to determine if the effect of one factor on credit scores depends on the level of the other factor.

Part V: Lakeland Case (Contingency table analysis, test of independence)

To determine if the price and style of the home are independent variables, a contingency table analysis could be conducted. This type of analysis is used when there are two categorical variables and the goal is to test whether they are independent or whether there is an association between them. In this case, the observed data would be entered into a 2x3 contingency table (two levels of price and three styles) and a chi-squared test of independence could be conducted. The null hypothesis would be that there is no association between the price and style of the home, and the alternative hypothesis would be that there is an association. If the null hypothesis is rejected, further analyses could be conducted to determine the nature of the association.

Related Questions

27
2 Homework
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mylab.pearson.com
Question 2, 8.2.11-T
Part 1 of 5
(a) Describe the sampling distribution of p.
Choose the phrase that best describes the shape of the sampling distribution below.
Chasitie Woodruff
A. Approximately normal because n≤0.05N and np(1-p) < 10.
B. Not normal because n ≤0.05N and np(1-p) < 10.
OC. Not normal because n ≤0.05N and np(1-p) ≥
10.
O D. Approximately normal because n≤0.05N and np(1-P) z 10.
HW Score: 8.33%, 0.5 of 6 points
O Points: 0 of 1
Suppose a simple random sample of size n = 75 is obtained from a population whose size is N = 15,000 and whose population proportion with a specified
characteristic is p=0.4. Complete parts (a) through (c) below.
Save

Answers

The phrase that best describes the shape of the sampling distribution of p below is D. Approximately normal because n≤0.05N and np(1 - p) ≥ 10.

What is a sampling distribution?

A sampling distribution simply means a probability distribution of a statistic obtained from a larger number of samples drawn from a specific population.

In this case, the phrase that best describes the shape of the sampling distribution of p below is approximately normal because n≤0.05N and np(1 - p) ≥ 10.

Learn more about sample on

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Should deandre ayton be a all star?

Answers

I believe he should but that is not a quiz question

Answer:

i think he should he's a pretty good player ngl

Question
The figure is the net for a rectangular prism.

What is the surface area of the rectangular prism represented by the net?



Enter your answer in the box.


in²

An unfolded rectangular prism with a length of nine inches labeling the top and bottom, a width of three inches labeling the sides and arrows pointing to the other sides for the height measuring five inches. SUBJECT IS MATH I NEED HELP..

Answers

We can find the surface area of the rectangular prism by adding up the areas of all six faces. The rectangular prism has three pairs of identical faces, each with an area of length x width. Therefore, the surface area is:

Surface area = 2lw + 2lh + 2wh

Substituting the given values, we get:

Surface area = 2(9)(3) + 2(9)(5) + 2(3)(5) = 54 + 90 + 30 = 174 square inches

Therefore, the surface area of the rectangular prism represented by the net is 174 square inches.

Answer: 270in^3

Explanation:

9x9 = 81

81x2=162  

9x3=27

27*4=108

162+108=270

Kylie works for a large nursery and is investigating whether to use a new brand of seeds. The new brand of seeds advertises that 93% of the seeds germinate, which is higher than the germination rate of the seeds she is currently using. She will change over to this new brand unless the actual germination rate is less than what is advertised. Kylie conducts an experiment by randomly selecting 76 seeds of the new brand and plants them. She finds that 70 of those seeds germinated. What are the null and alternative hypotheses for this hypothesis test?

Answers

The correct null and alternative hypothesis for the hypothesis test will be: B. H0: p=0.93

H a: p<0.93

What is the null and alternative hypothesis?

The null hypothesis is a type of scientific prediction that shows no correlation between variables whereas the alternative hypothesis indicates a connection between some variables.

So, for Kylie's experiment above, the null hypothesis indicated by H0: p=0.93 indicate the absence of a relationship while the alternative hypothesis indicates a relationship of less than 93%.

Learn more about the null and alternate hypotheses here:

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The null hypothesis is that the actual germination rate of the new brand of seeds is equal to or less than 93%. The alternative hypothesis is that the actual germination rate of the new brand of seeds is greater than 93%.
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