Part A: Consider the distance from the school to the coffee shop and the distance from the library to the coffee
shop. Draw their respective line segments in the above graph. If the school is relocated in a way that it
is collinear to the coffee shop and the library and distance to the coffee shop is preserved, then the
point representing the school will partition the line segment from the coffee shop to the library in a x: y
ratio. What are the values of x and y

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

Answer:

-8  7/9

Step-by-step explanation:

-9x+1=80

-9x+1-1=80-1

-9x=79

-9x=79

-9   -9

x= -8  7/9

Step-by-step explanation:

Hey there!!!!

Your required answer is option A.

The reason is.

When we solve it through elimination method we need to multiply second equation by "2" and then subtract to get "-4y" in 1st equation and "+4y" in 2nd equation cancelled.(As when we multiply equation 2 by 2 and subtract we get "-2y" as "+4y".)

So, it the equation seems like,

[tex]12 {x}^{2} + 4 {y}^{2} = 22[/tex]

Now, this equation is made after multiplying it by 2 and subtracting the 1st and 2nd equation to solve the equation s.

So, the answer is option A.

Hope it helps...

Answer:

√

36

=

6

lies between consecutive odd integers  

5

and  

7

.

Step-by-step explanation:

"The" square root of  

36

is itself an integer, namely  

6

, since  

6

2

=

36

. So it does not lie between consecutive integers.

It does lie between consecutive odd integers  

5

and  

7

.

Note that  

36

has another square root, namely  

−

6

, since  

−

6

satisfies:

(

−

6

)

2

=

36

Answer:

r = -3

Step-by-step explanation:

- 60= - 24 + 12r

Add 24 to each side

- 60+24= - 24+24 + 12r

-36 = 12r

Divide each side by 12

-36/12 = 12r/12

-3 =r

Answer:

2x^2-18x

Step-by-step explanation:

Answer:

4750

Step-by-step explanation:

950x

950× 5

4750

varying directly with number of days

Answer:

-5

Step-by-step explanation:

Answer:

-5

Step-by-step explanation:

hope it helped!! Brainliest? I need em

Answer:

this is the answer x=-1

Given:

Height of rectangle = 4 units

Area of rectangle up to 48 square units.

To find:

The inequality which represents all the possible lengths in units of the bases.

Solution:

Let the possible lengths in units of the bases be b.

Area of rectangle = Length × width

Here, Height of rectangle = width = 4 units. So, area of rectangle is

[tex]Area=b\times 4[/tex]

[tex]Area=4b[/tex]

Area of rectangle up to 48 square units. It means the area should be less than or equal to 48 square units.

[tex]4b\leq 48[/tex]

Divide both sides by 4.

[tex]b\leq \dfrac{48}{4}[/tex]

[tex]b\leq 12[/tex]

Length can not be negative or zero.

[tex]0<b\leq 12[/tex]

Therefore, the required inequality is [tex]0<b\leq 12[/tex].

Answer:

H) b ≤ 12

Step-by-step explanation:

48/4 = 12.

12 is the only one you can divide into 48 equally.

X 48 ÷ 192: Can't do

X 48 ÷ 44: Can't do

X 48 ÷ 52: Can't do

√ 48 ÷ 12 = 4

Answer:

$3.50

Step-by-step explanation:

Answer:

y=3x+6, y=5x,

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

Here's where you'll use the infamous PEMDAS, which just means how to solve the equation in order.

P means parentheses

E means exponents

M means multiplication

D means division

A means addition

S means subtraction

So start with P. Here we have (2+1) so that becomes 3. Which then turns the equation into: 3 - 4 × 5 + 31. Next Is E but since there are no exponents here you skip that step. Next is M. You have 4 × 5 which is 20 so the equation then becomes: 3 - 20 + 31. Next is D but since there's nothing to divide you can skip that too. You can actually go right ahead and solve it here because in PEMDAS you can actually just do all MD problems together from left to right, same as and AS problems in order from left to right, instead of doing M and then D or A and then S.

(I made a careless mistake in the original post, this should be the correct answer)

Answer: She should us a ratio of 1:5 for grapes to blueberries

Step-by-step explanation:

Blueberries are a lot smaller than a typical grape, hence you should have 5 blueberries for every grape. Hence, the 1:5 ratio.

Answer:

(C)

Step-by-step explanation:

12:3  

Answer:

t=9

Step-by-step explanation:

Move all terms that don't contain

t to the right side and solve.t=9

Answer:

t=9

Step-by-step explanation:

48=4t+12

Subtract 12 in both sides

36=4t

Divide 4 both sides

9=t

t=9

Answer:

[tex]g(f(3))=-2[/tex]

Step-by-step explanation:

So we have the two functions:

[tex]g(x)=4x+2\text{ and } f(x)=3x-10[/tex]

And we want to find g(f(3)).

So, let's find f(3) first:

[tex]f(3)=3(3)-10[/tex]

Multiply:

[tex]f(3)=9-10[/tex]

Subtract:

[tex]f(3)=-1[/tex]

Therefore, we can substitute -1 for f(3):

[tex]g(f(3))=g(-1)[/tex]

Now, find g(-1):

[tex]g(-1)=4(-1)+2[/tex]

Multiply:

[tex]g(-1)=-4+2[/tex]

Add:

[tex]g(-1)=-2[/tex]

And we're done!

So:

[tex]g(f(3))=-2[/tex]

≈ 63.30 ft²

Heron formula

A = √p(p - a)(p - b)(p - c)

a = 9 ; b = 15 ; c = 20

p = (a + b + c)/2 = (9 + 15 + 20)/2 = 44/2 = 22

A = √22(22-9)(22-15)(22-20)

= √22×13×7×2

= √4004

≈ 63,27

≈ 63.30 ft²

Answer:

distribute the 3

Step-by-step explanation:

follow pemdas ill put a brainpop link below

its the answer highlighted in yellow

Answer:

the 4th option is the right answer

subtract the constants

hope this helped you

please mark as the brainliest (ㆁωㆁ)

Answer:

[tex]x=\log_3{(15+ 4\sqrt{14})}\approx3.0949\text{ or } \\x=\log_3{(15- 4\sqrt{14})}\approx-3.0949[/tex]

Step-by-step explanation:

So we have the equation:

[tex]3^{1-x}+3^{1+x}=90[/tex]

First, note that this is the same as:

[tex]3\cdot 3^{-x}+3\cdot 3^x=90[/tex]

Factor out a 3:

[tex]3(3^{-x}+3^{x})=90[/tex]

Divide both sides by 3:

[tex]3^{-x}+3^x=30[/tex]

Change the negative exponent into a fraction:

[tex]\frac{1}{3^x}+3^x=30[/tex]

Multiply both sides by 3^x:

[tex]3^x(\frac{1}{3^x}+3^x)=(30)(3^x)[/tex]

Distribute:

[tex](1)+(3^x)^2=30(3^x)[/tex]

Let u equal 3^x. So:

[tex]1+u^2=30u[/tex]

Subtract 30u from both sides:

[tex]u^2-30u+1=0[/tex]

This is a quadratic. Solve using the quadratic formula. A is 1, b is -30, and c is 1. So:

[tex]u=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Substitute:

[tex]u=\frac{-(-30)\pm \sqrt{(-30)^2-4(1)(1)}}{2(1)}[/tex]

Simplify:

[tex]u=\frac{30\pm \sqrt{900-4}}{2}[/tex]

Subtract:

[tex]u=\frac{30\pm \sqrt{896}}{2}[/tex]

Simplify:

[tex]u=\frac{30\pm 8\sqrt{14}}{2}[/tex]

Simplify:

[tex]u=15\pm 4\sqrt{14}[/tex]

Substitute back u:

[tex]3^x=15\pm 4\sqrt{14}[/tex]

Take the log to base 3 of both sides:

[tex]\log_3{3^x}=\log_3{15\pm 4\sqrt{14}}[/tex]

The left side cancels:

[tex]x=\log_3{15\pm 4\sqrt{14}}[/tex]

So, our solutions are:

[tex]x=\log_3{(15+ 4\sqrt{14})}\approx3.0949\text{ or } \\x=\log_3{(15- 4\sqrt{14})}\approx-3.0949[/tex]

And we're done!

Step-by-step explanation:

a-2=3+6a/3

By cross multiply

3(a-2)=3+6a

3a-6=3+6a

-6-3=6a-3a

-9=3a

a=-3

Answer:

(8-n) + 4

4+ (8-n)

Step-by-step explanation:

I added 4 because it says "4 more" and I subtracted 8 and a variable because it says the "difference". I used a variable because the number is not specifically defined. I hope this helps!

Answer:

simplify

Step-by-step explanation:

just simpify then theres an answer waiting for you to jearney on

Answer

Kendal will be 60 meters away from the library after 80 seconds and again after 100 seconds.

Step-by-step explanation:

Let t represent time in seconds. Kendal is riding at a rate of 6 meters/second, so 6t represents the distance she can travel in t seconds.

The distance to the library is 540 meters. Because Kendal is riding toward the library, subtract 6t from 540 to find the distance between Kendal and the library before she passes it:

540 − 6t.

Kendal will be 60 meters away from the library twice, once as she approaches it and again after she passes it. The absolute value of the difference 540 − 6t represents Kendal's distance from the library. To find the time after which Kendal will be 60 meters away from the library, form an absolute value equation:

|540 − 6t| = 60.

Solve an absolute value equation by writing it as two separate linear equations and solving each one:

540 − 6t = -60 540 − 6t = 60

-6t = -600 -6t = -480

t = 100 t = 80

Let t represent time in seconds. Kendal is riding at a rate of 6 meters/second, so 6t represents the distance she can travel in t seconds.

The distance to the library is 540 meters. Because Kendal is riding toward the library, subtract 6t from 540 to find the distance between Kendal and the library before she passes it:

540 − 6t.

Kendal will be 60 meters away from the library twice, once as she approaches it and again after she passes it. The absolute value of the difference 540 − 6t represents Kendal's distance from the library. To find the time after which Kendal will be 60 meters away from the library, form an absolute value equation:

|540 − 6t| = 60.

Solve an absolute value equation by writing it as two separate linear equations and solving each one:

540 − 6t = -60 540 − 6t = 60

-6t = -600 -6t = -480

t = 100 t = 80

The answer is 80

algebra is the branch of mathematics that helps in the representation of problems or situations in the form of mathematical expressions. it involves variables like x, y, z, and mathematical operations like addition, subtraction, multiplication, and division to form a meaningful mathematical expression.

Given:

Kendal is riding at a rate of 6 meters/second

The distance to the library is 540 meters.

Let x represent time in seconds

So, kendal travel = 6x

So, distance between Kendal and the library before she passes it:

=540 − 6x.

Now, Kendal will be 60 meters away from the library.

Kendal will be 60 meters away from the library

540 − 6x= 60

-6x= 60-540

-6x= -480

x= -480/-6

x= 80

Hence, the answer is 80

Learn more about algebra here:

https://brainly.com/question/24875240

#SPJ2

-2 + n = -8(1 - 8n) + 6

Distribute the -8

-2 + n = -8 + 64n + 6

Combine like terms.

-2 + n = 64n - 2

Add 2 to both sides and subtract n from both sides.

0 = 63n

Divide both sides by 63

0 = n

Answer:

29i

Step-by-step explanation:

https://socratic                 .org/questions/how-do-you-evaluate-2-5i-p-q-i-when-p-2-and-q-5i#304498

If you want a description, copy that into your browser and take out the spaces between "socratic" and ".org".

Answer:

A

Step-by-step explanation: