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Answer:

There are 27 Valence electrons : )

4+1+1+1+6+4+1+1+4+1+1+1 is 27

Explanation:

There are a total of [5×1]+[2×4]+[7]=21[5×1]+[2 × 4 ] + [ 7]=21 valence electrons

The formula for calculating the amount of energy or heat released is:

ΔH = C ΔT

where ΔH is heat of combustion, C is heat capacity, while ΔT is change in temperature

ΔH = 8.69 kJ / °C * (5.14°C)

ΔH = 44.67 kJ

Then we calculate the moles of CH3OH which has molar mass of 32.04 g/mol:

moles = 1.922 / 32.04 = 0.05999 mol

SO the molar heat of combustion is:

ΔHm = 44.67 kJ / 0.0599875 mol

ΔHm = 744.60 kJ / mol

Answer:

it indicates that the lower orbitals are filled first and they have the maximum number of electrons compared to the higher orbitals

The replacement reaction will not occur because iodine is less reactive than chlorine.

A replacement reaction is a type of reaction in which one element is replaced by another in a compound.

The principle behind one element replacing the other is based on the reactivity of an element. A more reactive element will displace a less reactive one.

According to this question, the following displacement reaction is given: MgCl2 + I2 → ?

This reaction will not occur because chlorine is more reactive/electronegative than iodine, hence, iodine cannot displace it.

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Answer:

liquid and gas........................

I believe the answer would be D

Answer:

A) Carbon dioxide and Oxygen

Explanation:

Percentage of gases in the Planet's atmosphere:

Percentage of gases in the Earth's atmosphere:

___________________

On observing the percentage composition of the atmospheres of the two Planets, we get:

___________________

Answer:

What's asked is the name of the gases that are in higher amounts in the atmosphere of the newly discover planet

Therefore,

Answer:

7.36

Explanation:

my teacher said that was the right answer

The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

Isomers are compounds that has the same molecular formula but different structural formulas. Hence, isomers of compounds can be represented by the same molecular formula since they contain the same number of each atom.

The molecule shown has molecular formula C6H14. The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

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The acid ionization constant is the quantitative measure of the acidic strength. For oxalic acid, Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

Acid dissociation (Ka) is the ratio of the concentration of the conjugate base and hydrogen ion to the concentration of the chemical.

Oxalic acid is a weak acid and gets dissociated as:

H₂C₂O₄ ⇌ H⁺ + HC₂O₄⁻

or

HC₂O₄⁻ ⇌ H⁺ + C₂O₄²⁻

The acid ionization constant for the reactant and the product is given as:

Ka = [H⁺] [A⁻] / [HA]

Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

Therefore, the ionization constant for oxalic acid is given as Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

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The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is [tex]SO_{2}[/tex]

So, [tex]1[/tex]  mole of [tex]SO_{2}[/tex] = [tex]Mass[/tex] [tex]of[/tex] [tex]2'O'[/tex]

[tex]=32+2*16[/tex]

[tex]= 64[/tex] grams

Now, [tex]64g[/tex] of sulphur dioxide [tex]= 1[/tex] mole

So, [tex]1g[/tex] of sulphur dioxide = [tex]\frac{1}{64}[/tex] mole

Thus, we have [tex]\frac{1}{64}[/tex] mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, [tex]\frac{1}{64}[/tex] mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is [tex]CH_{4}[/tex]

So, 1 mole of [tex]CH_{4}[/tex]  = Mass of C + Mass of 4 H

[tex]=12+4*12[/tex]

Now, 16g of methane = 1 mole

So, 1 g of mathane = [tex]\frac{1}{16}[/tex] mole

We know that:

[tex]\frac{1}{64}[/tex] mole of methane contains = x molecules

So, [tex]\frac{1}{16}[/tex]  mole of contains will contain =[tex]\frac{x*64}{16}[/tex] molecules

=[tex]4x[/tex] molecules

in test tube 1 iron nail gets both air and moisture which is required for rusting. ... in the test tube 3 iron nail is not rusted because of the calcium chloride which is moisture absorber. hence nail would not get moisture for the rusting.

Answer:

Explanation: Atomic weight is measured in atomic mass units (amu), also called daltons.

Answer:

A compound is something like atoms coming together as a team, and a mixture is 2 or more substances mixing together.

Explanation:

Answer:

2. 389.15K , 3. 229.15K

Explanation:

K-273.15 = °C

A bomb calorimeter with a heat capacity of 3.63 kJ/°C experiences a temperature rise of 4.21 °C when .8210 g of naphthalene is burned.

The combustion of naphthalene is used to calibrate the heat capacity of a bomb calorimeter.

It is a device used to measure the change in the internal energy of a reaction.

To determine the heat capacity of the calorimeter (C), we need to follow a series of steps.

The heat of combustion of naphthalene is -40.1kJ/g and .8210g were burned.

Qcomb = -40.1kJ/g × .8210g = -32.9 kJ

According to the law of conservation of energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.

Qcomb + Qbomb = 0

Qbomb = -Qcomb = 32.9 kJ

32.9 kJ were absorbed, part by the calorimeter itself and part by the 1,000 g (m) of water, whose specific heat capacity (c) is 4.18 J/g°C.

A temperature rise (ΔT) of 4.21 °C is observed. We can determine the heat capacity of the bomb calorimeter (C) using the following expression.

Qbomb = Qcal + Qwater

32.9 kJ = C × ΔT + c × m × ΔT

32.9 kJ = C × 4.21 °C + (4.18 × 10⁻³ kJ/g.°C) × 1,000 g × 4.21 °C

C = 3.63 kJ/°C

A bomb calorimeter with a heat capacity of 3.63 kJ/°C experiences a temperature rise of 4.21 °C when .8210 g of naphthalene is burned.

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Answer:

child stage.

Explanation:

they are more vubnlerabke at that stage

Answer:it's b hope that help

The molar mass of water is 18 g. Given that there are 0.23 teaspoon for every 1 g. Thus , for 18 g there would be 4.14 teaspoons.

Any substance that contains  6.022 × 10²³ number of atoms is called one mole of that substance. The mass of a compound or molecule containing these much atoms is called its molar mass.

Molar mass of water is 18 g. Thus, it means that one mole of water weighs 18 g. Given that for every 1 g of water there are 0.23 teaspoon. Thus, number of teaspoons for one mole or 18 g of water is:

number of teaspoons = 18 g × 0.23  /1 g

                                    = 4.14 teaspoons.

Therefore, 4.14 teaspoons are required for one mole of water.

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Answer:

About 7.0 × 10³ J or 7.0 kJ

Explanation:

We want to determine the amount of energy needed to raise the temperature of 67 grams of water from 20°C to 45°C.

We can use the heat equation:

[tex]\displaystyle q = mC\Delta T[/tex]

Where C is the specific heat of water.

Substitute and evaluate:

[tex]\displaystyle \begin{aligned} q & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)\left(45^\circ \text{ C}- 20.^\circ\text{ C}\right) \\ \\ & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)(25^\circ \text{ C}) \\ \\ & = 7.0\times 10^3 \text{ J}\end{aligned}[/tex]

Recall that there are 1000 J in a kJ. Hence:

[tex]\displaystyle \begin{aligned} q & = 7.0\times 10^3 \text{ J} \cdot \frac{1\text{ kJ}}{1000\text{ J}} \\ \\ & = 7.0 \text{ kJ}\end{aligned}[/tex]

In conclusion, it will take about 7.0 × 10³ J or 7.0 kJ of energy to raise the temperature of 67 grams of water from 20 °C to 45 °C.

Answer:

A

Explanation:

A liquid will will have the same color, it will not have the same shape and its volume will always be constant because you are not creating mass.

Hope this helps!

Answer:

A

Explanation:

The trick here is to know what the conservation of mass means.

It means that no matter what happens and how much change there is, the mass of the carbons on the reactants = the mass of the carbons on the products.

That's exactly what A says.

Very Very sorry

Answer:

the bond is ionic

Explanation:

Answer:

2. Products; FeCl2 and H2S

Reactants; FeS and HCl

3. a) 36g of water

b) 64g of oxygen

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➡PV = nRT

➡PV = (W/M)RT

➡PM = (W/V)RT

➡PM = PRT

➡P = pRT/M

➡P = 2.85 × 0.082 x 298 / 44

➡P = 1.583 atm

➡P = 1.583 × 760

➡P = 1203 mm Hg

Hope this helps you:)

Answer:

Explanation:

AND REMEMBER DO ALWAYS READ AND WRITE

Answer:

D

Explanation:

The valence electrons are the outer electrons and must be located in the outermost shell. In this case, D.

Answer:

C. 4%

Explanation:

The answer is 4%