Answer:
60%
Step-by-step explanation:
3 of the 5 elements in P are odd (5, 11, & 13), so the probability is 3/5 or 60% or 0.6. (Depending on the format your teacher wants it in).
Please answer this correctly
Answer:
0
Step-by-step explanation:
3 cards
P( odd) = 1 odd/ 3 cards = 1/3
No replacement
2 cards 6,8
No odds
P( odd) = 0/2
P( odd, no replacement, odd) = 1/2 * 0 = 0
Please answer this correctly
Answer:
100%
Step-by-step explanation:
First, let's determine the probability for each of the conditions.
For P(greater than 2), we will have the cards 3, 4, 5, 6, 7, and 8.
For P(less than 3), we will have the cars 2.
In other words, every single card fits the conditions.
Thus, P(greater than 2 or less than 3)=7/7=100%
100%
Answer:
100%
Step-by-step explanation:
Greater than 2 is 3, 4, 5, 6, 7, 8
And less than 3 is 2 so that’s all the numbers which is 100%
divide
a) 21564÷2
b)40565÷5
c)6365÷8
d)1436÷7
answer please fast
Answer:
21564 ÷ 2 = 10782
40565 ÷ 5 = 8113
6365 ÷ 8 = 795.625
1436 ÷ 7 = 205.142857143
Solving by factoring
Answer:
3
Step-by-step explanation:
Help me plzzzzz!!!!
Answer:124
Step-by-step explanation:
2x + 8 + x - 2 = 180
Add like terms
3x + 6 = 180
Subtract the 6 from both sides
3x + 6 - 6 = 180 - 6
3x = 174
Divide by 3
x = 58
Now we have to find the measure of angle ACD
2(58) + 8 = 124
Suppose that early in an election campaign, a telephone poll of 800 registered voters shows that 460 favor a particular candidate. Just before Election Day, a second poll shows that 520 of 1,000 registered voters now favor that candidate. At the 0.05 significance level, is there sufficient evidence that the candidate's popularity has changed?
Answer:
Yes. At the 0.05 significance level, there is enough evidence to support the claim that the proportion that support the candidate has significantly changed.
Step-by-step explanation:
This is a hypothesis test for the difference between proportions.
The claim is that the proportion that support the candidate has significantly changed.
Then, the null and alternative hypothesis are:
[tex]H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0[/tex]
The significance level is 0.05.
The sample 1, of size n1=800 has a proportion of p1=0.58.
[tex]p_1=X_1/n_1=460/800=0.58[/tex]
The sample 2, of size n2=1000 has a proportion of p2=0.52.
[tex]p_2=X_2/n_2=520/1000=0.52[/tex]
The difference between proportions is (p1-p2)=0.05.
[tex]p_d=p_1-p_2=0.58-0.52=0.05[/tex]
The pooled proportion, needed to calculate the standard error, is:
[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{464+520}{800+1000}=\dfrac{980}{1800}=0.54[/tex]
The estimated standard error of the difference between means is computed using the formula:
[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.54*0.46}{800}+\dfrac{0.54*0.46}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.00031+0.000248}=\sqrt{0.000558}=0.02[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.05-0}{0.02}=\dfrac{0.05}{0.02}=2.33[/tex]
This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):
[tex]\text{P-value}=2\cdot P(z>2.33)=0.02[/tex]
As the P-value (0.02) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that the proportion that support the candidate has significantly changed.
A surveyor is trying to find the height of a hill. He/she takes a ‘sight’ on the top of the hill and find that the angle of elevation is 40°. He/she move a distance of 150 metres on level ground directly away from the hill and takes a second ‘sight’. From this point, the angle of elevation is 22°. Find the height of the hill, correct to 1 d.p.
Answer:
The height of the hill is 116.9 meters.
Step-by-step explanation:
The diagram depicting this problem is drawn and attached below.
From Triangle ABC
[tex]\tan 22^\circ=\dfrac{h}{150+x}\\\\h=\tan 22^\circ(150+x)[/tex]
From Triangle XBC
[tex]\tan 40^\circ =\dfrac{h}{x}\\\\h=x\tan 40^\circ[/tex]
Therefore:
[tex]h=\tan 22^\circ(150+x)=x\tan 40^\circ\\150\tan 22^\circ+x\tan 22^\circ=x\tan 40^\circ\\x\tan 40^\circ-x\tan 22^\circ=150\tan 22^\circ\\x(\tan 40^\circ-\tan 22^\circ)=150\tan 22^\circ\\x=\dfrac{150\tan 22^\circ}{\tan 40^\circ-\tan 22^\circ} \\\\x=139.30[/tex]
Therefore, the height of the hill
[tex]h=139.3\times \tan 40^\circ\\=116.9$ meters( correct to 1 d.p.)[/tex]
The height of the hill is 116.9 meters.
What tool is used to draw circles
Answer:
Pair of compasses.
Step-by-step explanation:
These are used to inscribe circles/arcs.
Compasses are used in maths, navigation,e.t.c.
Hope it helps.
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Consider the given function.
Answer:
to determine the inverse of the given function, change f(x) to y, switch [tex]\boxed{x}[/tex] and y and solve for [tex]\boxed{y}[/tex]
The resulting function can be written as
[tex]f^{-1}(x)=x^2+\boxed{4}[/tex] where [tex]x\geq\boxed{0}[/tex]
Step-by-step explanation:
Hello,
f is defined for [tex]x\geq 4[/tex] as x-4 must be greater or equal to 0
and [tex]f(x)\geq 0[/tex]
so [tex]f^{-1}[/tex] is defined for [tex]x\geq 0[/tex]
and then we can write
[tex]x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{f^{-1}(x)-4} \ so\\f^{-1}(x)-4=x^2 <=> f^{-1}(x)=x^2+4[/tex]
hope this helps
The mean of 100 numerical observations is 51.82 what is the value of all 100 numbers
Answer: 5182
To get the value of all 100 numbers you would need to multiply.
Step-by-step explanation:
51.82x100= 5182
What is the equation of the line which passes through (-0.5,-5) and (2,5)
Answer:
[tex]y = 4x-3[/tex]
Step-by-step explanation:
The coordinates are (-0.5,-5) and (2,5)
Finding the slope, m:
=> Slope = [tex]\frac{rise}{run}[/tex]
=> Slope = [tex]\frac{5+5}{2+0.5}[/tex]
=> Slope = [tex]\frac{10}{2.5}[/tex]
=> Slope = 4
Now, y-intercept, b:
Taking any of the two coordinate and putting it in the slope intercept equation:
=> Point = (x,y) = (2,5)
So, x = 2, y = 5
=> [tex]y = mx+b[/tex]
=> 5 = (4)(2) + b
=> 5 = 8 + b
=> b = 5-8
=> b = -3
Now, Putting in slope intercept equation:
=> [tex]y = mx+b[/tex]
=> [tex]y = 4x-3[/tex]
Gradient (m) = x2-x1
y2-y1
considering
y1 = -5 y2 = 5
x1 = -0.5. x2 = 2
m = 2-(-0.5)
5-(-5)
m = 5.5
10
m = 11. = 0.55
20
equation of a line is given by
y-y1 = m+(x-x1)
y-(-5) =0.55 + {x-(-0.5)}
y+5 = 0.55 + x+0.5
making y the subject
y = 0.55 +0.5 -5 + x
y = -3.95 + x
A survey of enrollment at 35 community colleges across the United States yielded the following figures:
6414; 1550; 2109; 9350; 21828; 4300; 5944; 5722; 2825; 2044; 5481; 5200; 5853; 2750; 10012; 6357; 27000; 9414; 7681; 3200; 17500; 9200; 7380; 18314; 6557; 13713; 17768; 7493; 2771; 2861; 1263; 7285; 28165; 5080; 11622
a. Organize the data into a chart with five intervals of equal width. Label the two columns "Enrollment" and "Frequency."
b. Construct a histogram of the data.
c. If you were to build a new community college, which piece of information would be more valuable: the mode or the mean?
d. Calculate the sample mean.
e. Calculate the sample standard deviation.
f. A school with an enrollment of 8000 would be how many standard deviations away from the mean?
Answer: (a) The chart is in the first attachment named table frequency.
(b) The histogram is in the second attachment named frequency vs. enrollment
(c) Mode
(d) x = 9071.4
(e) s = 6677.64
(f) It is -0.16 standard deviation away
Step-by-step explanation:
(c) Mode is the number in the data set which appears more often. When thinking about builiding a new community college, if you choose mode will have which college enrollment will appear more often, i.e., which courses have more students wanting to enroll.
(d) To calculate sample mean of a frequency data:
1) Find the midpoint for each interval;
2) Multiply each midpoint for its correspondent frequency;
3) Sum up each multiplication obtained in the previous step;
4) Sum up all the frequencies;
5) Divide the sum in step 3 by the sum in step 4;
For this chart:
x = [tex]\frac{3000.10+7500.16+12500.3+17500.3+22500.1+27500.2}{35}[/tex]
x = 9071.4
(e) To find the standard deviation:
1) With each midpoint, calculate its square;
2) Multiply the midppoint square by its correspondent frequency;
3) Use the following formula to determine the sample standard:
s = √∑f.M² - n(μ)² / n-1
For this chart:
s = [tex]\sqrt{\frac{4396250000 - 35*(9071.4)^{2}}{34} }[/tex]
s = 6677.64
(f) To find how many standard deviations away is the enrollment:
z = [tex]\frac{8000-9071.4}{6677.64}[/tex]
z = - 0.16
8000 enrollments are -0.16 standard deviations away from the mean.
Do class limits and class marks make sense for qualitative data classes? Explain
your answer.
NEED QUICKLY
Answer: NO, class limits and class marks are not meaningful to qualitative data.
Step-by-step explanation: Qualitative data are non-numerical data. They are collected mostly through observation. They include; sex, name and soon.
Class limits and class marks are groupings used in numerical data (quantitative data). They are not relevant and are meaningless to qualitative data classes as these data class are non- numerical.
How would I Evaluate 8×5÷10?
Answer:
4
Step-by-step explanation:
8×5÷10
PEMDAS says multiply and divide from left to right
40÷10
4
Answer:
4
Step-by-step explanation:
Follow the PEMDAS order of operations
8*5=40
40÷10=4
=4
OR
8x5÷10
8x0.5=4
=4
Have a good day and stay safe!
What is the solution to the equation below? Round your answer to two decimal places. 4+4•log2 x=4
Answer:
Option (C)
Step-by-step explanation:
Given expression is,
[tex]4+4\times \text{log}_2(x)=14[/tex]
By subtracting 4 from both the sides of the equation.
[tex]4\times \text{log}_2(x)=14-4[/tex]
Now divide the equation by 4
[tex]\text{log}_2(x)=\frac{10}{4}[/tex]
[tex]\text{log}_2(x)=2.5[/tex]
[If [tex]\text{log}_ab=x[/tex] , then [tex]b=a^{x}[/tex]]
[tex]x=(2)^{2.5}[/tex]
[tex]x = 5.657[/tex]
x ≈ 5.66
Therefore, Option C will be the correct option.
4+4•log2 x=14
x= 5.66
For data sets having a distribution that is approximately bell-shaped, _______ states that about 68% of all data values fall within one standard deviation from the mean.
Answer:
The Empirical Rule
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
So the answer to this question is the Empirical Rule
A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the probability that during a randomly selected hour, the organization will receive fewer than two calls.A) 0.087
B) 0.894
C) 0.317
D) 0.106
Answer:
B) 0.894
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
A local animal rescue organization receives an average of 0.55 rescue calls per hour.
This means that [tex]\mu = 0.55[/tex]
Probability that during a randomly selected hour, the organization will receive fewer than two calls.
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577[/tex]
[tex]P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894[/tex]
Q1. 12.5g of medicine cost 1,075 naira. What is the cost of 1g of medicine. Q2. What is the total pay for someone who works 42 hours and gets 645 naira per hour
Step-by-step explanation:
Q1. 1,075÷12.5 =8
So Therefore 1g of medicine cost 8 naira
Q2.645÷42=15.3
so therefore 1 hour cost 15.3 naira
The cost of 1g of medicine is 86 naira and the total pay for someone who works 42 hours is 27090 naira.
What is Division?A division is a process of splitting a specific amount into equal parts.
Given that 12.5g of medicine cost 1,075 naira.
We have to find the cost of 1g of medicine.
12.5g=1075 naira
1g=1075/12.5
1g=86 naira.
the total pay for someone who works 42 hours and gets 645 naira per hour
The cost for 42 hours
42×645
27090 naira
Hence, the cost of 1g of medicine is 86 naira and the total pay for someone who works 42 hours is 27090 naira.
To learn more on Division click:
https://brainly.com/question/21416852
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The radius of a sphere is 3 inches. Which represents the volume of the sphere?
12 cubic inches
362 cubic inches
647 cubic inches
817 cubic inches
Answer:
Volume of the sphere= 113.112 cubic inch(Inch ³)
Step-by-step explanation:
First of all the formula for the volume of a sphere Is given as 4πr³
Already the radius r is already given as 3 inches
While π = 3.142
Volume of the sphere = 4/3πr³
Volume of the sphere = 4/3(3.142)(3)³
Volume of the sphere= 4/3(3.142)(27)
Volume of the sphere= 4/3(84.834)
Volume of the sphere= 339.336/3
Volume of the sphere= 113.112 Inch ³
Volume of the sphere= 113.112 cubic inch
A six sided fair number cube is 100 times as part of an experiment The frequency of the role of the Number three is 20 which statement about rolling a three is correct
Answer:
8
Step-by-step explanation:
don't cheat sike i cheat
Answer: the real answer is c you can go to both places I gave you the answer in both
Step-by-step explanation:
Because I got it right please have a good day or night
Please answer this correctly without making mistakes
Answer:
<
Step-by-step explanation:
750,000,000 times 10^5 can be expressed as 7.5 times [tex]10^{11}[/tex]
7.55 times 10^13 is greater than 7.5 times 10^11.
Answer:
The appropriate sign that makes the statement true is <
Hope this helps you
ab = cde
In order to solve the equation above for c, you must multiply both sides of the equation by the same expression
ab x _? = cde x _?
The resulting equation is
C= _?
Answer:
1) We have to multiply both sides by 1/(de)
2) c=ab/(cd)
Step-by-step explanation:
We have to achieve the right side expression be c only. To do that we have to multiply cde by 1/(de) . However we have to multiply the left side by
1/(de) as well.
So the resulting left side expression is:
ab *1/(de)=ab/(de)
So c= ab/(de)
Given equation in the question is,
ab = cde
To solve the given equation for the value of c, follow the algebraic rules,
1). Multiply both the sides of the equation with [tex]\frac{1}{de}[/tex],
[tex]ab\times \frac{1}{de} = \frac{cde}{de}[/tex]
[tex]\frac{ab}{de}= \frac{cde}{de}[/tex]
[tex]\frac{ab}{de}=c[/tex]
Therefore, resulting equation for c will be,
[tex]c=\frac{ab}{de}[/tex]
Learn more,
https://brainly.com/question/11496615
Using the diagram below, solve the right triangle. Round angle measures to the
nearest degree and segment lengths to the nearest tenth.
Answer:
m∠A = 17 degrees m∠B = 73 degrees m∠C = 90 (given) a = 12 (given) b = 40 c = 42 (given)
Step-by-step explanation:
Use sin to solve m∠A
sin x = 12/42 Simplify
sin x = 0.2857 Use the negative sin to solve for x
sin^-1 x = 17 degrees
Add together all of the angle measures to solve for m∠B
17 + 90 + x = 180 Add
107 + x = 180
-107 -107
x = 73 degrees
Use Pythagorean Theorem to solve for b
12^2 + x^2 = 42^2 Simplify
144 + x^2 = 1764
-144 -144
x^2 = 1620 Take the square root of both sides
x = 40
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p.
n = 130
x = 69; 90% confidence
a. 0.463 < p < 0.599
b. 0.458 < p < 0.604
c. 0.461 < p < 0.601
d. 0.459 < p < 0.603
Answer:
d. 0.459 < p < 0.603
Step-by-step explanation:
We have to calculate a 90% confidence interval for the proportion.
The sample proportion is p=0.531.
[tex]p=X/n=69/130=0.531[/tex]
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.531*0.469}{130}}\\\\\\ \sigma_p=\sqrt{0.001916}=0.044[/tex]
The critical z-value for a 90% confidence interval is z=1.645.
The margin of error (MOE) can be calculated as:
[tex]MOE=z\cdot \sigma_p=1.645 \cdot 0.044=0.072[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=p-z \cdot \sigma_p = 0.531-0.072=0.459\\\\UL=p+z \cdot \sigma_p = 0.531+0.072=0.603[/tex]
The 90% confidence interval for the population proportion is (0.459, 0.603).
[tex]\frac{5x-11}{2x^2+x-6}[/tex] You need to work for your points now!
Answer:
[tex]\frac{5x-11}{\left(2x-3\right)\left(x+2\right)}[/tex]
Step-by-step explanation:
[tex]\frac{5x-11}{2x^2+x-6}[/tex]
Factor the denominator.
[tex]\frac{5x-11}{\left(2x-3\right)\left(x+2\right)}[/tex]
The fraction cannot be simplified further.
Answer:
[tex] \frac{5x - 11}{(x + 2)(2x - 3)} [/tex]solution,
[tex] \frac{5x - 11}{2 {x}^{2} + x - 6} \\ = \frac{5x - 11}{2 {x}^{2} + (4 - 3)x - 6} \\ = \frac{5x - 11}{2 {x}^{2} + 4x - 3x - 6 } \\ = \frac{5x - 11}{2x(x + 2) - 3(x + 2)} \\ = \frac{5x - 11}{(x + 2)(2x - 3)} [/tex]
Hope this helps..
According to an airline, flights on a certain route are on time 80% of the time. Suppose 17 flights are randomly selected and the number of on-time flights is recorded.
Required:
a. Explain why this is a binomial experiment.
b. Find and interpret the probability that exactly 11 flights are on time.
c. Find and interpret the probability that fewer than 11 flights are on time
d. Find and interpret the probability that at least 11 flights are on time.
e. Find and interpret the probability that between 9 and 11 flights, inclusive, are on time.
Answer:
a) Check Explanation
b) Probability that 11 out of the 17 randomly selected flights are on time = P(X = 11) = 0.0680
c) Probability that fewer than 11 out of the 17 randomly selected flights are on time
= P(X < 11) = 0.0377
d) Probability that at least 11 out of the 17 randomly selected flights are on time
= P(X ≥ 11) = 0.9623
e) Probability that between 9 and 11 flights, inclusive, out of the randomly selected 17 are on time = P(9 ≤ X ≤ 11) = 0.1031
Step-by-step explanation:
a) How to know a binomial experiment
1) A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (Probability of each flight being on time is 80%)
2) It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (It's either the flights are on time or not).
3) The outcome of each trial/run of a binomial experiment is independent of one another.
All true for this experiment.
b) Probability that exactly 11 flights are on time.
Let X be the random variable that represents the number of flights that are on time out of the randomly selected 17.
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = 17 randomly selected flights
x = Number of successes required = number of flights required to be on time
p = probability of success = Probability of a flight being on time = 80% = 0.80
q = probability of failure = Probability of a flight NOT being on time = 1 - p = 1 - 0.80 = 0.20
P(X = 11) = ¹⁷C₁₁ (0.80)¹¹ (0.20)¹⁷⁻¹¹ = 0.06803777953 = 0.0680
c) Probability that fewer than 11 flights are on time
This is also computed using binomial formula
It is the probability that the number of flights on time are less than 11
P(X < 11) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0376634429 = 0.0377
d) Probability that at least 11 out of the 17 randomly selected flights are on time
This is the probability of the number of flights on time being 11 or more.
P(X ≥ 11) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17)
= 1 - P(X < 11)
= 1 - 0.0376634429
= 0.9623365571 = 0.9623
e) Probability that between 9 and 11 flights, inclusive, are on time = P(9 ≤ X ≤ 11)
This is the probability that exactly 9, 10 or 11 flights are on time.
P(9 ≤ X ≤ 11) = P(X = 9) + P(X = 10) + P(X = 11)
= 0.0083528524 + 0.02672912767 + 0.06803777953
= 0.1031197592 = 0.1031
Hope this Helps!!!
Sandy can fold 6 towels in 3 minutes. If she continues at this rate, how many minutes will it take her to fold 36 towels?
Hey there! :)
Answer:
x = 18 minutes.
Step-by-step explanation:
To solve this equation, set up a ratio.
# of towels over time taken:
[tex]\frac{6}{3} = \frac{36}{x}[/tex]
Cross multiply:
6x = 108
Divide both sides by 6:
6x/6 = 108/6
x = 18 minutes.
Answer:
In eighteen minutes she will have folded all 36
A triangle with side lengths of 4 , 5 , 6 , what are the measures of it angles to the nearest degree ?
Answer:
41°, 56°, 83°
Step-by-step explanation:
We can find the largest angle from the law of cosines:
c² = a² +b² -2ab·cos(C)
C = arccos((a² +b² -c²)/(2ab))
C = arccos((4² +5² -6²)/(2(4)(5))) = arccos(5/40) ≈ 82.8192°
Then the second-largest angle can be found the same way:
B = arccos((4² +6² -5²)/(2·4·6)) = arccos(27/48) ≈ 55.7711°
Of course the third angle is the difference between the sum of these and 180°:
A = 180° -82.8192° -55.7711° = 41.4096°
Rounded to the nearest degree, ...
the angles of the triangle are 41°, 56°, 83°.
A ship traveled at an average rate of 25 miles per hour going west. It then traveled at an average rate of 19 miles per hour heading north. If the ship traveled a total of 145 miles in 7 hours, how many miles were traveled heading west?
Answer:
50 miles
Step-by-step explanation:
hello,
let's note x the number of miles travelled heading west,
it takes 1 hour to travel 25 miles
so it takes x/25 hours to travel x miles
we know that in total it travels 7 hours so it will travel 7-x/25 hours heading North, then heading North it takes 1 hour to travel 19 miles
so in 7-x/25 hours it travels 19(7-x/25) miles
we can write, as the total distance is 145 miles
[tex]x+19(7-\dfrac{x}{25})=145\\<=> 25x+3325-19x=3625\\<=> 6x=300\\<=> x = 50[/tex]
we can verify
50 miles heading West takes 2 hours
in 5 hours it travels 19*5 = 95 miles
the total is 145 miles
so this is correct
hope this helps
Find the value of x that makes A||B
Answer:
For lines A and B to be parallel, the Same Side Interior angles must be supplementary which means:
2x + 10 + 4x + 80 = 180
6x + 90 = 180
6x = 90
x = 15°