All of the following elements are metals EXCEPT?
A. Br B. Co C. Cu D. Zn
Answer:
Br
Explanation:
container has 3 moles of gas with a volume of 60 liters and at a temperature of 250 K, Calculate the pressure inside the container in kPa
Answer:
103.9 KPa
Explanation:
From the ideal gas equation;
PV=nRT
From the parameters given;
P= ?
T=250 K
V= 60L
n=3
R=0.082 atmLK-1mol-1
P= nRT/V
P= 3 × 0.082 × 250/60
P= 1.025 atm
1 atm=101325 pascals
1.025 atm = 1.025 atm × 101325 pascals/1atm
= 103.9 KPa
Answer:
103.9kPa
Explanation:
To solve this question we must use the equation:
PV = nRT
P = nRT / V
Where P is pressure in atm
n are moles of the gas = 3mol
R is gas constant = 0.082atmL/molK
T is absolute temperature = 250K
V = 60L
P = 3mol*0.082atmL/molK*250K / 60L
P = 1.025atm
As 1atm = 101.325kPa
1.025atm * (101.325kPa / 1atm) = 103.9kPa
8.
(a) Tick (™) the box next to the correct statement about the mixture.
mixture of four elements
mixture of four compounds
mixture of two elements and two compounds
mixture of one element and three compounds
Answer:
mixture of four compounds
mixture of two elements and two compounds
Explanation:
it can be one of thosecan u tell me if its correct pls I'm studying this too1. Hay un gas con 700 milímetros de Mercurio de presión en 922 ml de volumen a 20 grados Celsius. Calcula la temperatura final a 500 mm de mercurio con 451 ml.
2. un gas ocupa un gas ocupa 205 mililitros a 20 grados centígrados y 1,05 atm. Calcule el volumen final a 60 grados centígrados y 2,4 Atmósferas de presión.
3. tenemos 22 L de un gas a una temperatura de 220 K y una presión de 5 Atm, si se modifican la presión a 6.5 atm y la temperatura a 200 K, cuál será el volumen que obtenemos.
Answer:
püvinlbxyfsswgrxzvnnchcyv nkivtcdg
Inicialmente una muestra de neón tiene un volumen de 2,50 L a 15 °C. ¿Cuál es la
temperatura en °C, cuando el volumen de la muestra cambia a cada uno de los
siguientes volúmenes, ¿manteniéndose la presión constante?
a. 5,0 L b. 1250 ml c. 7,50L d. 3550 ml
naoooooooo seiiiiiiiii !!!!!!!!!!!!!!
Can someone help me with this?
(2-2) Looking at the chemical formula CaF2 (calcium fluoride), what do you think this substance is made of? (Choose ALL that apply)
Metal
Metalloid
Non-metal
Answer:
Metal
Non-metal
Explanation:
CaF2 is an ionic compound. Ionic compounds are mostly composed of a metal and a non metal. Metals donate electrons to non-metals to form ionic compounds.
Calcium is a divalent ion of group two in the periodic table while F is a univalent nonmetal of group 17 in the periodic table. Hence the compound CaF2 is composed of a metal and a nonmetal.
Which of the following pH numbers are acidic? (Choose 2)
9
11
7
5
3
the pH numbers that are acidic above is 3 and 5
Balance the following equation by providing the correct coefficients C2H6 + O2 -> CO2 + H2O
Calculate the Molar Mass of Radon pentaiodide (Rnls)
857
349
1237
Explanation:
222.01758 g/mol
3.1Computed Properties
What is the molecular weight (rmm) of NaOH?
40
20
50
60
Answer: A/40 it is actually 39.997 but since that is not an answer they rounded up
Explanation:
Why does the rate of the forward reaction increase when the surface area of a reactant is increased
?
When the surface area increases, the concentration of the substance increases, which reduces
the number of effective collisions.
When the surface area increases, the temperature of the system increases, which in turn
increases the number of effective collisions.
When the surface area increases, the density of the substance increases, which increases the
number of collisions.
When the surface area increases, the number of particle collisions increases, which in turn
increases the number of effective collisions.
answer questions 3 and 4 for a brainly!
Answer:
The correct answer is -
3. Butyne
4. Pentene
Explanation:
The names of such organic compounds are classified on the number of the carbon atoms and based on a number these prefixes are attached -
Meth - one carbon
Eth - two carbons
Prop - three carbons
But - four carbons
Pent - five carbons, and so on
The bonds can be identified by names of an organic compound by their suffixes -
- ane = single bond
- ene = double bond
-yne = triple bond
Thus, for question 3, carbon numbers are 4 and triple bond so Butyne, and similarly for question 4, 5 carbon atoms and double bond so Pentene.
Thermal energy is a measure of the __________ of particles of matter. *
(subject is science I just cant change it right now)
Why does Watney get left behind on Mars?
Answer:
I think it's because he was presumed dead after a storm, or like a problem with his suit
Explanation: I think it was because somebody thought he was dead in the storm? And the remaining of the crew were forced to leave him behind thinking he was dead on mars.
I might be right, might not ^^
H=1.01
What is the molality of a solution containing 75.3 grams of KCI
dissolved in 100.0 grams of water?
K= 39
Cl = 35.45
Answer:
Molality of solution=10.11 m
Explanation:
We are given that
Given mass of KCl(WB)=75.3 g
Given mass of water (WA)=100 g=100/1000=0.1 kg
1 kg=1000 g
Molar mass of H=1.01 g
Molar mass of K=39g
Molar mass of Cl=35.45 g
We have to find the molality of a solution.
Molar mass of KCl(MB)=39+35.45
Molar mass of KCl(MB) =74.45 g
Number of moles of solute (KCl)=[tex]\frac{given\;mass}{molar\;mass}=\frac{W_B}{M_B}[/tex]
Number of moles of solute (KCl)=[tex]\frac{75.3}{74.45}[/tex]
Number of moles of solute (KCl)=1.011 moles
Molality of solution
=[tex]\frac{number\;of\;moles\;of\;solute}{mass\;of\;solvent}[/tex]
Using the formula
Molality of solution=[tex]\frac{1.011}{0.1}[/tex]
Molality of solution=10.11 m
How many Fluorine atoms are needed to accept the electrons of one Ca atom?
1
2
3
4
2 F atoms
Explanation:
A Ca atom has a valence number of +2, which means that when ionized, it will give up two electrons. In turn, a F atom has a valence number of -1, which means it can only accept 1 electron when ionized. So to accommodate the two electrons from Ca atom, we need 2 F atoms.
What is the iupac name of CH3-O-CH2-CH2-CH3?
Answer:
The iupac name of CH3-O-CH2-CH2-CH3 is Methoxybutane.
A mixture of oxygen( O2), dinitrogen monoxide (N2O), and argon (Ar) has a total pressure of 0.98 atm. What is the partial pressure of N2O, if the partial pressure of O2 is 0.48 atm and the partial pressure of Ar is 0.15 atm?
Answer: The partial pressure of [tex]N_{2}O[/tex] is 0.35 atm.
Explanation:
Given: Total pressure = 0.98 atm
Partial pressure of [tex]O_{2}[/tex] = 0.48 atm
Partial pressure of Ar = 0.15 atm
Partial pressure of [tex]N_{2}O[/tex] = ?
Total pressure is the sum of partial pressure of each component present in a mixture of gases.
Hence, partial pressure of [tex]N_{2}O[/tex] is calculated as follows.
Total pressure = [tex]P_{N_{2}O} + P_{O_{2}} + P_{Ar}[/tex]
Substitute the values into above formula as follows.
[tex]Total pressure = P_{N_{2}O} + P_{O_{2}} + P_{Ar}\\0.98 atm = P_{N_{2}O} + 0.48 atm + 0.15 atm\\P_{N_{2}O} = 0.35 atm[/tex]
Thus, we can conclude that the partial pressure of [tex]N_{2}O[/tex] is 0.35 atm.
You have 11.27 moles of Cl2 gas. How many moles of NaBr do you need to completely undergo this reaction?
Answer:
22.54 moles of NaBr are needed
Explanation:
The reaction of Cl2 with NaBr occurs as follows:
Cl2 + 2NaBr → 2NaCl + Br2
Where 1 mole of Cl2 requires 2 moles of NaBr for a complete reaction
As in the problem, we have 11.27 moles of Cl2, the moles of NaBr required are:
11.27mol Cl2 * (2mol NaBr / 1mol Br2) =
22.54 moles of NaBr are neededCalculate the current in amperes required to produce 18.0g of aluminium in 1.50hrs (al=27.og )
Answer:
35.7 A
Explanation:
Let's consider the reduction half-reaction of Al³⁺.
Al³⁺ + 3 e⁻ ⇒ Al
We will calculate the charge required to produce 18.0 g of Al using the following conversion factors.
1 mole of Al has a mass of 27.0 g1 mole of Al is formed upon the circulation of 3 moles of electrons1 mole of electrons has a charge of 96486 C (Faraday's constant)[tex]18.0gAl \times \frac{1molAl}{27.0gAl} \times \frac{3mole^{-} }{1molAl} \times \frac{96486C}{1mole^{-} } = 1.93 \times 10^{5} C[/tex]
1.93 × 10⁵ C circulate in 1.50 hours. The intensity is:
[tex]I = \frac{1.93 \times 10^{5} C}{1.50h} \times \frac{1h}{3600s} = 35.7 A[/tex]
a gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the container if the temperature remains constant?
1. 2.54 kPa
2. 157 kPa
3. 481 kPa
pls help ;(
Answer:
[tex]\boxed {\boxed {\sf 2. \ 157 \ kPa}}[/tex]
Explanation:
Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using Boyle's Law. This states that the pressure is inversely proportional to the volume. The formula is:
[tex]P_1V_1=P_2V_2[/tex]
We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.
[tex]275 \ kPa *20.0 \ L=P_2V_2[/tex]
We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.
[tex]275 \ kPa *20.0 \ L=P_2* 35.0 \ L[/tex]
Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.
[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}[/tex]
[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2[/tex]
The units of liters cancel.
[tex]\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2[/tex]
[tex]\frac {5500}{35.0} \ kPa= P_2[/tex]
[tex]157.142857 \ kPa=P_2[/tex]
The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.
The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.
[tex]157 \ kPa= P_2[/tex]
If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.
The balanced equation for the combustion of Hexane,C6H14 , is
Answer:
[tex]2C _{6}H _{14} + 19O _{2}→12CO _{2} +14H _{2} O[/tex]
What does an increase in temperature do to the reaction rate?
Answer:
An increase in temperature typically increases the rate of reaction because an increase in temperature will raise the average kinetic energy of the reactant molecules. Therefore, a greater proportion of molecules will have the minimum energy necessary for an effective collision.Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.
Explanation:
Can you please give this answer a brainliest answer please
Can I please get help with chemistry.
I got these three questions wrong and I’m wondering which answers would be right for the questions.
Answer: The 3rd one
Explanation: Electronegativity is a measure of how strongly atoms attract bonding electrons to themselves.
I might be wrong
How many miles are in 27.4 g of NO2
Answer:
0.59 moles
Explanation:
Given mass = 27.4 g
Molar mass of NO₂ = 46 g/mol
We need to find the number of moles. We know that,
No of moles = given mass/molar mass
Put all the values,
[tex]n=\dfrac{27.4}{46}\\\\n=0.59[/tex]
Hence, there are 0.59 moles of NO₂ .
An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
working substance and operates from a most compressed stage of 100 Nm and
327 K. It expands isothermally to a pressure of 90 Nm and then adiabatically to a
most expanded stage of 27 K. Calculate the AU, 9, and w for each step. Calculate
the net work done and the efficiency of the cycle [Cv,m for the gas) is 25 J/k/mol.
Answer:
Step 1;
q = w = -0.52571 kJ, ΔS = 0.876 J/K
Step 2
q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ
Explanation:
The given parameters are;
[tex]P_i[/tex] = 100 N·m
[tex]T_i[/tex] = 327 K
[tex]P_f[/tex] = 90 N·m
Step 1
For isothermal expansion, we have;
ΔU = ΔH = 0
w = n·R·T·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71
w ≈ -0.52571 kJ
At state 1, q = w = -0.52571 kJ
ΔS = -n·R·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = -1 × 8.314 × ln(90/100) ≈ 0.876
ΔS ≈ 0.876 J/K
Step 2
q = 0 for adiabatic process
ΔU = 25×(27 - 327) = -7,500
w = ΔU = -7.5 kJ
ΔH = ΔU + n·R·ΔT
ΔH = -7,500 + 8.3142 × 300 = -5,005.74
ΔH = ΔU = -5.00574 kJ
N2 + 3H2 → 2NH3 How many moles of hydrogen are needed to react with 5 moles of nitrogen?
Answer: 15 mol
Explanation:
From the equation, we know that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.
So, the answer is 5(3) = 15 mol
Two water molecules are weakly attracted to each other when a slightly positive hydrogen atom in the first molecule is attracted to the slightly negative oxygen atom on the second molecule. What type of bond is this
If I have 4.4 moles of nitrous oxide (laughing gas) that is kept at 32.9 °C in a container under 1.6 atm, what is the volume of the container? (R = 0.0821 (L*atm)/(mol*K))
Round your answer to 1 decimal place.
Answer:
Explanation:
Using the ideal gas equation as follows:
PV = nRT
Where:
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
Based on the information provided in this question;
P = 1.6atm
n = 4.4 moles
R = 0.0821 L*atm/mol*K
T = 32.9°C = 32.9 + 273 = 305.9K
V = ?