Order Of Operations and solving word problems.

During a promotion at an aquarian,the number of adult tickets sold was 4 times the total number of student tickets and senior citizen tickets sold. The number of students tickets sold was three times that of senior citizen tickets.142 more student tickets than senior citizen tickets were sold.How many adult tickets were sold.

Solve this using order of operations.

The assignment is gonna be due in an hour pls answer quickly.

Answer:

well.......................................3 cups are in a cup serving

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Step-by-step explanation:

1. Ok so first we need to figure out how many boxes of shirts he bought. In each box there are 20 shirts and he sold 93. So if we round it, he bought about 100 T-shirts. 100 ÷ 20 = 5. So he bought 5 boxes of shirts.

2. Next we need to figure out how much he spent on the shirts. 5*80=400. So he spent $400 dollars on the shirts.

3. We need to find out the amount of money he made from selling the shirts. 6*93=558  

4. We need to find the profit so you subtract the total expenses from the total revenue. 558-400= 158.  So the profit is $158

Answer: Mr. Youngbear made 158 dollars worth of profit after selling 93 T-shirts.

(I dont know if this is correct, but I hope I was able to help!)

Answer:

Brainly doesn’t help people

Step-by-step explanation:

Khan Acadmey or Google helps! Trust me this doesn’t help

Answer:

26 and 32 are the two numbers, the product is 832

Answer:

IT 2

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

4 is the initial value of the exponential function shown on the graph.

Have a great day

Answer:

what is the question? lol

Step-by-step explanation:

Answer:

what question ??

Step-by-step explanation:

Step-by-step explanation:

1.

[tex] {m}^{2} + 15m + 56 = ( \: \: \: \: \: )(m + 8) \\ solution \\ \: \: taking \: lhs \\ = {m}^{2} + 15m + 5 \\ = {m}^{2} + (7 + 8)m + 56 \\ \: \: \: \: = {m}^{2} + 8m + 7m + 56 \: \: \\ now \: taking \: common \: factor \\ m(m + 8) + 7(m + 8) \\ (m + 7)(m + 8) \\ now \\ {m}^{2} + 15m + 56 = (m + 7)(m + 8)[/tex]

2.

[tex] {a}^{2} + 5ab + 6 {b}^{2} = ( a + 2b)( \: \: \: \: \: \: \: \: ) \\ solution \\ taking \: \: lhs \\ = {a}^{2} + 5ab + 6 {b}^{2} \\ = {a}^{2} + ( 3+ 2)ab + 6 {b}^{2} \\ = {a}^{2} + 3ab + 2ab + 6 {b}^{2} \\now \: taking \: common \: factor \\ a(a + 3b) + 2b(a + 3) \\ (a + 2b)(a + 3) \\ now \\ {a}^{2} + 5ab + 6 {b}^{2} = ( a + 2b)( a + 3) ans[/tex]

this may help you(:

Answer:  S(q) represents a quantity that changes at a constant rate per unit interval is true and S(q) represents a linear function is true. The rest is false. Hope this helps

Step-by-step explanation:

Answer: x=5

Step-by-step explanation:

Distribute the 4 to the 2 and 9 and you will get (8x-36)=4.

Then you'd add the 36 to 4 to get 40.

Lastly you'd divide 8 and 40 to get 5. Hope this helps!!!

Answer:

=

Step-by-step explanation:

Answer:

39=39

Step-by-step explanation:

because it is the same number so it equals each other

Answer:

0.969

Step-by-step explanation:

Given that:

Mean lifetime (m) = 520 hours

Variance = 900

Hence, standard deviation (s) = √900 = 30

Probability that bulb will last for at most 576 hours

X ≤ 576

Obtain the standardized score :

Using the relation :

Zscore = (x - m) / s

Zscore = (576 - 520) / 30

Zscore = 56 / 30

Zscore = 1.867

P(Z ≤ 1.867) : using the z probability calculator ;

P(Z ≤ 1.867) = 0.96905

Hence, P(Z ≤ 1.867) = 0.969

Given:

Lee has 3 dog walking customers.

Each month he gains another customer.

To find:

The arithmetic sequence that represents the number of customers he has.

Solution:

Initial number of customers = 3

First term : [tex]a_1=3[/tex]

Each month he gains another customer.

Common difference : [tex]d=1[/tex]

Recursive formula of an AP is

[tex]a_n=a_{n-1}+d[/tex]

where, d is common difference.

Substituting d=1, we get

[tex]a_n=a_{n-1}+1[/tex]

So, the required arithmetic sequence is [tex]a_n=a_{n-1}+1[/tex], where [tex]a_1=3[/tex].

Therefore, the correct option is A.

Answer:

41/28

Step-by-step explanation:

mixed form is 13/28*1

follow me please.

Answer:

4.5 ounces of yellow and 7.5 ounces of blue will create 12 ounces of the perfect shade of green.

Step-by-step explanation:

1.5 + 2.5 = 4 ounces.

Multiply by 3

4.5 + 7.5 = 12 ounces

So, she needs 4.5 ounces of yellow.

Answer:

-6+x≤15

negative six: -6

plus: +

a number: variable (I chose x)

Less than or equal to: ≤ (an inequality)

fifteen: 15

Answer:

-6 + n ≤ 15

or

n ≤ 21

Step-by-step explanation:

negative six is -6

plus a number would be a variable (I will use n) + n

is less than or equal to would be ≤

fifteen is 15

-6 + n ≤ 15

If you want to solve it, continue

-6 + n ≤ 15

+6         +6

n ≤ 21

I hope that this helps! :)

Answer:

n=16

Step-by-step explanation:

n/4 + 1 = 5

inverse operations, (subtract the one from both sides)

n/4 = 4

inverse operations, multiply by 4 on both sides, (you're isolating the variable)

n = 16

Answer:

Multiply the normal price of the item by .25 and then subtract that from the normal price.

Step-by-step explanation

[tex]x -(x*.25)[/tex]  

x is the item

Step-by-step explanation:

100%-25%= discounted price= 75%

You do the discounted price divided by 75 to find 1%

do that times 100 to find the pre-discounted price.

e.g

find the original price of a sweater when it was on sale of 25%. the sale price is £15.00.

£15.00 = 75%

15.00 divided by 75 = 1% =£0.20

£0.20 x 100 = pre-sale price = £20.00

The price of the sweater before the sale is £20.00.

You are welcome xx

Answer:

9.80

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

If you pull up a graph you can more accurately see it, I just did it in my head

Answer:

150×500=30, i got you man

Answer: D. Addition property of equality

Step-by-step explanation:

Answer:

0.8958

Step-by-step explanation:

Given that:

The mean [tex]\mu[/tex] = 4959

The standard deviation [tex]\sigma[/tex] = 448

The sample size n = 43

[tex]\mu_{\overline x} = \mu = 4959[/tex]

[tex]\sigma __{\overline x}} = \dfrac{\sigma}{\sqrt{n}}= \dfrac{448}{\sqrt{43}}[/tex]

By applying the central limit theorem;

[tex]\overline X \sim N \bigg( \mu_{\overline x} = 4959 , \sigma_{\overline x} = \dfrac{448}{\sqrt{43}}\bigg )[/tex]

The purpose of this question is to calculate the probability that the mean of a sample of 43 cars would differ from the population mean by less than111 miles.

This implies that;

[tex]P( |\mu-\overline x| <111) = p( 4959-111 < \overline X < 4959 +111)[/tex]

[tex]= P( 4848 < \overline X < 5070)[/tex]

[tex]= P \bigg ( \dfrac{ \overline x - \mu_x }{ \dfrac{\sigma}{\sqrt{n}}} < Z < \dfrac{ \overline x - \mu_x }{ \dfrac{\sigma}{\sqrt{n}}} \bigg )[/tex]

[tex]= P \bigg ( \dfrac{4848 -4959 }{ \dfrac{448}{\sqrt{43}}} < Z < \dfrac{5070 -4959 }{ \dfrac{448}{\sqrt{43}}} \bigg )[/tex]

[tex]= P \bigg ( \dfrac{-111 }{ 68.319} < Z < \dfrac{111 }{68.319} \bigg )[/tex]

[tex]= P ( -1.6247< Z < 1.6247 )[/tex]

= P ( Z < 1.627 ) - P(Z < -1.627)

From the standard normal tables

= 0.94791 -0.05208

= 0.89583

≅ 0.8958  to four decimal places.