on the strange planet, zorgg, you weigh 1283 n. what will you weigh on the even stranger planet, quoozeptinaletina, that is 226 times more massive than zorgg and has a radius 17.1 times larger?

After collision velocity of yellow ball become 3 m/s.

What is collision velocity?

Collision is short-duration interaction between two bodies or more than two bodies simultaneously causing change in motion of bodies involved due to internal forces acted between them during this. Collisions involve forces (there is a change in velocity).

Velocity of red ball = 3 m/s

Velocity of yellow ball = -2m/s

Red ball and yellow ball both have same mass

So, after head on collision their velocity will be exchanged.

So after collision velocity of yellow ball become 3 m/s.

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If log 3 4 = 1. 2619, then the solution to the equation above, which evaluates log 3 0, 25, is -1. 2619.

When one assess something or someone, then take them into account in order to form an opinion on them, such as whether or not they are good or terrible. It's challenging to assess the state of the market. Synonyms: evaluate, rank, value, and decide More alternatives to analyze. to evaluate or determine the degree, significance, scope, or worth of something: Doctors assess the patient's health. He was only genuinely content while working alone since then he had complete control over the strategy and the dangers.

Convert decimal to fraction:

log₃ 25/100

Reduce the fraction:

log₃ 1/4

Round the number:

=-1.2619

hence, its evaluate -1.2619 when If log 3 4=1. 2619.

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The maximum angle due to angular momentum measured from vertical, does the rod (with the attached ball of clay) rotate is 57°.

Given that,

Mass of the rod, [tex]\small M= 80\;g=0.08\; kg[/tex]

Mass of the clay ball, [tex]\small m=11\;g=0.011\;g[/tex]

Length of the rod, \small[tex]L=35\;cm=0.35\;m[/tex]

Initial speed of the ball, [tex]\small v_{i}=2.3\;m/s[/tex]

From law of conservation of angular momentum, Total initial angular momentum of the system = total final angular momentum of the system[tex]\small mv_{i}\frac{L}{2}=\frac{1}{2}(I_{rod}+I_{ball})\omega_{f}\small mv_{i}L=(I_{rod}+I_{ball})\frac{V_{f}}{(L/2)}[/tex].

[tex]\small mv_{i}L=\left (\frac{1}{12}ML^{2}+m\left (\frac{L}{2} \right )^{2} \right )\frac{V_{f}}{(L/2)}[/tex]

Now, From law of conservation of energy, Initial rotational kinetic energy = final potential energy:

[tex]\small \frac{1}{2}(I_{rod}+I_{ball})\left (\frac{V_{f}}{(L/2)} \right )^{2}=m(L/2)g(1-\cos\theta)[/tex]

[tex]\small \frac{1}{2}\left (\frac{1}{12}ML^{2}+m\left (\frac{L}{2} \right )^{2} \right )\left (\frac{V_{f}}{(L/2)} \right )^{2}=m(L/2)g(1-\cos\theta)[/tex]

[tex]\small \left (\frac{1}{12}M+m\left (\frac{1}{2} \right )^{2} \right )\left (\frac{V_{f}}{(1/2)} \right )^{2}=mLg(1-\cos\theta)[/tex]

[tex]\small \therefore \theta=\cos^{-1}\left (0.5496 \right )\small \boldsymbol{\therefore \theta=56.66^{o}}[/tex]

ROUNDING TO 2 SIGNIFICANT FIGURES

[tex]\small \boldsymbol{\therefore \theta=57^{o}}[/tex]

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The expansion of the universe after its origin takes place by a phenomenon called Big bang

As the universe widened, it cooled and matter began to form. Neutrons, protons, electrons, anti-electron, photons, and neutrinos were all present in the universe one second after the Big Bang. The Big Bang nucleosynthesis, which took place during the first three minutes of the universe, produced the light elements.

The big bang theory is the most commonly accepted explanation. Learn about the initial explosion and how the universe expanded from the size of an atom to include everything that exists today.

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The force exerted on the motorcycle of mass 500 kg is 2272.72 N.

Force can be calculated by multiplying the mass of a body to its acceleration. The S.I Unit of force is Newton (N).

To calculate the force exerted on the motorcycle, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the force acting on the motorcycle is 2272.72 N.

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The critical angle for the liquid when surrounded by air is 48.75°.

The critical angle is the maximum angle at which a light beam traversing a transparent media can collide with the surface of a second medium having a lower refractive index without being completely reflected within the first medium.

Given that:

Angle of incident: i = 30.0°.

Angle of refraction, r = 22.0°.

Hence, refractive index of the medium: n = sini/sinr

= sin 30.0°/sin22.0°

= 1.34.

Hence, the critical angle for the liquid when surrounded by air:

= sin⁻¹(1/n)

= sin⁻¹(1/1.33)

= 48.75°.

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Angle of the disk's momentum. 0881 kg*m^2/s.

Given:- mass is 2.00 kg, radius is 3.00 m, velocity of 4.00 rad/s.

The most important metric for determining an object's position and rate of movement is its velocity. The distance that an object travels in a certain amount of time might be used to define it. The object's movement in a unit of time is referred to as velocity.

In contrast to velocity, which describes the speed and direction of an object's movement, speed is the rate of movement along a path. Alternatively, velocity is a vector while speed is a scalar quantity.

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If the expansion of the Universe is currently accelerating, can we conclude that the Universe will necessarily expand forever Since little is currently known about the source of the dark energy which is causing the present accelerated expansion of the Universe, it cannot be concluded that it will continue unchanged in the future? Thus, the Universe might, or might not expand forever.

According to the relativistic perspective, although the space around the Earth is contracting, its atoms are resisting this compression. This implies that the Earth's surface is moving higher at a constant rate. On Earth, falling would be the only option to avoid accelerating up. When you are at rest, you fall.

A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both.

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The momentum of the kid on the right having a mass of 31 kilograms is 0 Kg.m/s

Momentum is defined as the product of mass and velocity. It is expressed mathematically as:

Momentum = mass × velocity

With the above formula, we can obtain the momentum of the kid on the right as follow:

Momentum = mass × velocity

Momentum = 31 Kg × 0 m/s

Momentum = 0 Kg.m/s

Thus, the momentum of the kid on the right is 0 Kg.m/s

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The final pressure of the gas will be 26.8 kPa when has a final volume of 78.0L.

Boyle's law, also known as the Boyle-Mariotte law, is an experimental gas law that explains the connection between a confined gas's pressure and volume. The pressure of a gas is inversely related to its volume at constant temperature, as well as its number of moles, according to Boyle's law.

P ∝ 1/V

[tex]PV=k[/tex] or [tex]P_{1} V_{1} =P_{2} V_{2}[/tex]

[tex]P_{1}[/tex]= initial gas pressure is 209 kPa

[tex]P_{2}[/tex]= final pressure which is unknown.

[tex]V_{1[/tex]= 10.0 L, which is the gas's initial volume.

[tex]V_{2}[/tex]= 78.0 L, which is the gas's final volume.

We can now use this formula to obtain the final gas pressure by entering all the specified variables.

[tex](209kPa)(10.0L)=P_{2}(78.0L)\\P_{2}=26.8kPa[/tex]

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Answer:

23 m/s

Explanation:

Additional Saving in power is 1.48mw.

As a result of primary action, power dissipation is the process by which power is lost as heat. The process of power dissipation happens naturally. The power will be dissipated by each resistor in the circuit that has a voltage drop across it.

Since Pdyn = fc v²oo is proportional to v²oo reducing power supply

from 5v to 3v reduces the power dissipation by a factor of

(3.3)²/5² = 0.436

The power dissipation now become 0.436×10×10⁻³ = 436×10⁻³ = 4.36mw.

Since Pdyn is proportional to reducing f by the some factor as the supply voltage 3.3/5 = 0.66results in reducing the power dissipation

further by factor of 0.66

Additional Saving in power = (1.0.66) X(4.36 × 10⁻³ )

Additional Saving in power = 1.48mw.

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The maximum power that the siren can put out is of 4.74 dB.

Given that,

The height of the tower above the ground is, h = 105 m

Sound intensity from the siren is, I = 116 dB

We know that, the maximum intensity of sound allowed is 11.6 B.

Then the intensity of sound in terms of W/m² can be found as follows,

log(I / I₀) = 11.6

I / I₀ = 10¹¹°⁶

I = 10¹¹°⁶ * I₀

⇒ 10¹¹°⁶ * 10⁻¹²

⇒ 10⁻⁰°⁴

At 105 m above the ground the intensity will be 105² times.

Then the intensity at source point = 10⁻⁰°⁴ * 105²

⇒ 0.398 * 105² = 4387.95 W/m²

The energy of sound from the source is given as,

4π* intensity= 4* 3.14* 4387.95 = 55112.65 W/m²

To convert into decibels:

log(55112.65/ 10⁻¹²) = log(55112.65+12) = 4.74 dB

Thus, we can conclude that the maximum power that the siren can put out is of 4.74 dB.

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The oscillating and regular motion of an object is known as the SHM. The object must move 0.532 meters from x(t) = 0.65 meters to x(t) = A = 1.182 meters.

It is a periodic and oscillating movement that moves in a rectilinear fashion.

Knowing that there will always be a restoring force (F) that tends to return the motion to its initial location when it moves an amount called an amplitude is important when thinking about simple harmonic motion.

There are some important factors to take into account with this motion,

The movement's position, X (m), in its initial, equilibrium, and other positions.

The speed is a (m/s2).

Speed, V (m/s)

The volume, A (m)

The periodicity, w (rad/s),

The distance that the object needs to move from x(t) = 0.65m to x(t) = A = 1.182m is 0.532m.

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At maximal displacement, the speed is zero, the kinetic energy is zero, and the only source of energy is the potential energy held in the spring. E = 1/2 kA² is the energy at the greatest distance.

The process of any variable or measure fluctuating repeatedly about its equilibrium value in time is known as oscillation. A periodic change in a substance's quality between discrete choices or around its central value is another way to describe oscillation.

Here, A represents the oscillation's amplitude.

Dropping the sandbag won't change the system's overall energy since all of the energy is derived from the energy stored of spring.

Therefore, the amplitude won't be affected.

The square of oscillation's intensity determines the system's energy in an exact correlation. The energy in the system remains constant, hence the oscillation's amplitude does not vary.

Hint:

Utilize the energy at balance to ascertain whether the maximum speed for dropping the sandbag at the cart's maximal changes in any way.

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The magnitude of the acceleration due to gravity on planet p is 5 meters per seconds squared.

From the Second Equation of Motion;

s = ut + (1/2)gt²

Where v is final velocity, u is initial velocity, g is acceleration due to gravity and t is time elapsed.

Given the data in the question;

Plug the given data in the above formula and solve for g.

s = ut + (1/2)gt²

40m = (0 × 4s) + ( (1/2) × g × (4s)²

40m =  (1/2) × g × 16s²

Multiply both sides by 2

2 × 40m = 2 × (1/2) × g × 16s²

80m = g × 16s²

g × 16s² = 80m

g = 80m / 16s²

g = 5m/s²

Therefore, the acceleration due to gravity is 5m/s².

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The work done have been calculated as : Wgravity = 15,250 joules, W rope1 = - 9667.158 joules and W rope2 = - 5584.94 joules

Given ; Force of gravity on piano = 2500 N

r = distance of the ground =  6.10 m

As the angles are mentioned in the diagram, thus we can write

Work done can be calculated by ;

Wgravity = 2500 N . 6.10m . cos 0 = 15,250 joules

W rope1 = 1830 N . 6.10 m . cos 150 = - 9667.158 joules

W rope2 = 1295 N . 6.10 m . cos 135 = - 5584.94 joules

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Answer:

W = 12500 J

T1 = -7920 J

T2 = - 4580 J

Explanation:

The angle between the force w and the displacement is 0 degrees, therefore:

[tex]W_{w} = wdcos(0) = (2500)(5)(1) =[/tex] 12500 J

The angle between the force T1 and the displacement is 90 + 60 = 150 degrees, therefore:

[tex]T_{1}= T_{1} dcos (150) = (1830)(5)(cos(150)) =[/tex] - 7920 J

The angle between the force T2 and the displacement is 90 + 45 = 135 degrees, therefore:

[tex]T_{2} = T_{2} dcos(135) = (1295)(5)(cos (135)) =[/tex] - 4580 J

If the moon were five times more distant from earth than it is now, the gravitational force would decrease.

                                   [tex]F= G\frac{M_{1}M_{2}}{R^{2} }[/tex]

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An extinguisher is not suitable for a certain class of fire if it has a red diagonal line through it on a black background.

Other concepts and beliefs can be conveyed using symbols. Words, music, gestures, ideas, or visual images could all be used to describe them. For example, on maps, rivers are commonly represented by blue lines, and a red rose is frequently associated with compassion and love. A typical symbol for "STOP" is a red octagon.

When an image in a text seems to suggest something beyond its exact meaning, symbolism is present. Although authors don't always do this, it could be repeated or seem startling, as if the author is purposefully drawing attention to it.

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When white light passes through a cool cloud of gas an absorption line spectrum is observed.

An absorption line spectrum is made up of frequencies of light transmitted with dark bands when electrons absorb energy in the ground state to reach higher energy states.

No two types of atoms or molecules give the same patterns.

In other words, any particular gas can absorb or emit only certain wavelengths of light that are typical for that gas.

In contrast, absorption spectra are produced when white light passes through a cold, rarefied gas.

Since cloud of gases are cold and hence when white light passes through a cool cloud of gas an absorption line spectrum can be observed.

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The original mass of the Argon-37 sample (N₀) was 14.98651g or approximately 15g. We Use the equation for first-order kinetics for determining the original mass of the given Argon-37 sample.

If the rate of radioactive decay is first order, we can write r = k[N]1, where N is the quantity of radioisotope present at the time the rate is recorded, k is the isotope's first order rate constant, and r is the rate of decay as observed.

According to First-Order Rate Equation,

[tex]ln(\frac{N}{N_{0} } )=-kt[/tex]

Here,

N = The amount of radioisotope left after "t" time.

N₀= The initial amount of radioisotope,

k = Rate constant of the radioisotope.

t = Time

Given,

N = 2. 14 g.

N₀ = ?

k = 0. 0198

t = 98. 3 days

Now, substituting these values in the first order rate equation we get,

[tex]ln(\frac{N}{N_{0} } )=-kt\\ln(\frac{2.14}{N_{0} } )=-0.0198*98.3\\ln(\frac{2,14}{N_{0} } )=-1.94634\\\frac{2.14}{N_{0} } =e^{-1.94634} \\\frac{2.14}{N_{0} }=0.142795\\N_{0} = 14.98651g[/tex]

Hence, the original mass of the sample (N₀) was 14.98651 g or approximately 15 g.

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Two vertical wires are used to hoist a 12 kilogram lantern from the ceiling; as a result, each wire is under 58.8 N of tension.

The phrase "wire transfer" dates back to a time when banks used telegraph wires to transmit this type of financial transfer. A bank wire stored procedures on who should receive the funds, along with the user's bank account information and the amount they should receive.

Well, we know from Newton that, if m is the mass of the lantern,

Fnet = ma

Additionally, it is clear that the two forces pulling on the candle are now the strain on the two wires and the gravitational force. Since the candle isn't moving, its speed is 0, which means that the final quantity of forces acting on it must likewise be zero.

The positive y-axis should point up, and also the negative y-axis should point below. Listing the forces reveals that

-mg + T1 + T2 = 0

The two wires' tensions are also equal because they are both straight and orbital angular momentum, or T1 = T2 = T. The preceding equation can be revised to say

-mg + 2T = 0, or

2T = mg.  

Thus,

T = mg/2 = (12kg*9.8m/s2) / 2 = 58.8N

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Internal energy associated with systems and particles is thermal energy.

What is Internal energy?

A thermodynamic system's internal energy is the entire amount of energy it contains. The energy required to construct or prepare the system in its current internal condition comprises both internal kinetic energy and potential energy contributions.

The internal energy has been described as the energy that has been assessed by the molecules and bonds at the STP. Thermal energy has been the energy of particular molecules and the system comprising all the molecules have the summation of the thermal energy.

Thus, internal energy associated with systems and particles is thermal energy.

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A heuristic device in which a solution to a problem is found by evaluating the difference between the current situation and the goal is the mean end analysis.

Heuristics are mental shortcuts that are frequently utilized to streamline issues and prevent cognitive overload. Heuristics, which enable people to arrive at rational conclusions or answers to complex situations rapidly, are a function of how the human brain evolved and is wired.

This designates a notion or idea that is employed more because it facilitates our thinking about the issue than because it is strongly supported by the data. A heuristic tool is Max Weber's ideal type. The three heuristics that attracted the most attention were representativeness, anchoring and adjustment, and availability.

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Answer: B: counter clockwise

Explanation: I learned about this in the 9th grade!

Itis going to the speed of obstinacy.

speed is the fastest movement of something.

n the question time of flight of blocked ball time off flight of the ball that is represented by capital D This is the time of flight. It is given time of flight, height of time of flight, and hi of both ball, the same or equal, yet. We need to find out how fast production is. We need to find the projection that is represented by you. It was not possible to be on the time of projectile flight. The value of time of flight is equal to the number of years you have left in your life. We'll get equal to 11.1 until 9.81 upon two and two signed 27.4, because he dies at 27.4. Two is 118.31 little per second. obstinacy is the right answer. I think that is Mhm. Correct answer is obstinacy It is necessary to explain this questio.

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The time taken by the truck to get to the required position 5 km away from the fire is 261.55 s.

Tone at which the truck approaches at = 470 hz

Tone at which the truck recedes = 420 hz

Distance = 5.0 Km away

Speed = constant

Speed of sound = v

Speed of air = V

Frequency of sound = f

Frequency when truck approaches = f₁ =

= f₁ = [( V + v) / V ] X f

Frequency when the truck recedes = f₂ =

= f₂ = [( V - v) / V ] X f

Thus, equating both equations =

= f₁ / f₂ = (V + v) / (V - v)

= 470/420 = (340.278 + v) / (340.278 - v )

= [ 470 X 340.278 ] - 470v = [ 420 X 340.278 ] + 420v

= 159930.66 - 470v = 142916.76 + 420v

= 17013.9 = 890v

= v = 19.117 m/s

The time taken = t =

= s = ut + (1/2)at²

= 5 X 10³ = 0 + (19.117 X t)

= t = 261.55 s

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In order to search for the signal, we would need to tune our telescopes to a wavelength of 208.3 cm.

If an extraterrestrial civilization were to transmit a signal using the spin-flip of the electron in hydrogen, the frequency of the signal would be 1.43 GHz, now to determine the wavelength of the signal, we can use the formula (λ = c/f), where c is the speed of light and f is the frequency. The speed of light is 299,792,458 meters per second, so the wavelength of the signal would be 208.3 cm.

In order to search for the signal, we would need to tune our telescopes to a wavelength of 208.3 cm. This is because radio telescopes detect electromagnetic radiation in the radio frequency range, which is measured in wavelengths.

By tuning our telescopes to the wavelength of 208.3 cm, we will be able to detect any signals transmitted by an extraterrestrial civilization using the spin-flip of the electron in hydrogen.

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In an PNP transistor, the base controls the amount of current passing through it while allowing current flow from the base to the emitter.

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The kinetic energy in the spring is equal to the mechanical work done by the spring

The kinetic energy in then spring is

E = 1 / 2 kA2

The mechanical work done by the spring is,

E= 1 / 2 mv2

Compare the above two equations to find the amplitude of oscillation:

1 / 1 kA2 = 1 / 2 mv2

A = v√ m/k

(3.58 m/s) √ 1.12 kg / 32.3 N/m

= 0.66m

The mechanical work done by the spring is,

E = 1/2 mv2

= 1 / 2 (1.12 kg) (3.58 m/s)2

= 7.17 J

Work modifications the quantity of mechanical and internal energy possessed by gadgets. Whole work is achieved on a machine or item, energy is introduced to it.

The character of work achieved can be categorised in three classes. they are +ve work, -ve work and zero work. The character of work relies upon on the perspective among pressure and displacement.

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