Answer:
The change on the Celsius scale is 27.22 °C.
Explanation:
The conversion of Fahrenheit to Celsius is the following:
[tex]T = \frac{5}{9}(^{\circ} F - 32)[/tex]
So, we need to convert T₁ and T₂ from °F to °C:
[tex]T_{1} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(- 4 - 32) = -20 ^{\circ} C[/tex]
[tex]T_{2} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(45 - 32) = 7.22 ^{\circ} C[/tex]
Hence, the change on the Celsius scale is:
[tex] \Delta T = T_{2} - T_{1} = 7.22 - (-20) = 27.22 ^{\circ} C [/tex]
Therefore, the change on the Celsius scale is 27.22 °C.
I hope it helps you!
A refrigerator recieves 240 V of electricity. If it use 32 A of current, what is the resistance of the refrigerator?
Answer:
7.5 Ω
Explanation:
Voltage = Current x Resistance
(V = IR)
240 = 32 R
R = 240 / 32
= 7.5 Ω
What does addition of two vectors give you?
Answer:
Explanation:
To add or subtract two vectors, add or subtract the corresponding components. Let →u=⟨u1,u2⟩ and →v=⟨v1,v2⟩ be two vectors. The sum of two or more vectors is called the resultant. The resultant of two vectors can be found using either the parallelogram method or the triangle method .
Why is hydraulic jack used ? Write.
Answer:
it is used because
It occupies less spaceheavy loads are easily movedminimum of effort is usedit is a bit lighter than screw jacks.They are also less likely to jam due to rust in the screw thread.
Hydraulic jacks are often used to lift elevators in low and medium rise buildings.
A hydraulic jack uses a liquid that is forced into a cylinder by a pump plunger.
How do you find the rest mass (kg) of a 3.1 eV electron?
Answer:
Explanation:
The rest energy of any substance is defined by the Einstein's mass energy equivalence relation. Thus the rest mass of a electron is 9.11x10^-31 kg. The speed of light is 299,792,458 m/s. Thus multiplying the square of speed of light with the rest mass of electron gives the rest energy of the electron.
You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when it reaches the bottom
Explanation:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 0.75 m)
v = 3.83 m/s
Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel and Jerry are using the same force F. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do.
Answer:
The work done by Joel is greater than the work done by Jerry.
Explanation:
Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:
[tex]W = F\cdot \Delta s[/tex]
Where:
[tex]W[/tex] - Work, measured in joules.
[tex]F[/tex] - Force exerted on the object, measured in newtons.
[tex]\Delta s[/tex] - Travelled distance by the object, measured in meters.
During the first 10 minutes, the net work exerted on the object is zero. That is:
[tex]W_{net} = W_{Joel} - W_{Jerry}[/tex]
[tex]W_{net} = F\cdot \Delta s - F\cdot \Delta s[/tex]
[tex]W_{net} = (F-F)\cdot \Delta s[/tex]
[tex]W_{net} = 0\cdot \Delta s[/tex]
[tex]W_{net} = 0\,J[/tex]
In exchange, the net work in the next 5 minutes is the work done by Joel on the object:
[tex]W_{net} = W_{Joel}[/tex]
[tex]W_{net} = F\cdot \Delta s[/tex]
Hence, the work done by Joel is greater than the work done by Jerry.
Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, centripetal acceleration, or both when: (a) The plate starts to spin
Answer:
the only acceleration it has is radial (centripetal)
Explanation:
The microwaves plate rotates at a constant speed after a very short period of acceleration.
Therefore we can apply Newton's second law
F = m a
where the acceleration is centripetal
a = v2 / r = w2 r
therefore as it rotates constant speed it cannot have a tangential acceleration since it changes the modulus of the speed.
Consequently the only acceleration it has is radial (centripetal)
What is density?
O A. The net energy transferred between two objects
B. A measure of mass per unit volume
O C. A measure of the movement of molecules
O D. The force exerted on an area
Answer:
B. A measure of mass per unit volume
Explanation:
Mass and volume are intimately correlated with density. In reality, it explains the precise nature of the connection between the two. We can determine an object's density by dividing its mass by volume. Thus, option B is correct.
What best defines about density?The mass or amount per unit of volume of a substance determines its density. Density is calculated using the formula mass/volume. It is considered to have a low density if a mass has a high volume but a tiny mass.
The volume and subsequently the density of a material typically alter when it changes its phase or state of matter. Temperature is the primary component, even though pressure can also affect how a material changes state.
Water availability, climate, relief (the contour of the terrain), vegetation, soils, and the accessibility of renewable energy sources are physical elements that impact population density. Social, political, and economic variables altering humans all have an impact on population density.
Therefore, A measure of mass per unit volume.
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A mass of 1.15 kg of air at 111 kPa and 27 C is contained in a gas-tight, frictionless piston cylinder device. The air is now compressed to a final pressure of 0.84 MPa. During this process, heat is transferred from the air such that the temperature inside the cylinder remains constant. Calculate the work input (in kJ) during this process.
Answer:
Work input W = -200.39 KJ
Explanation:
From the question, we are given;
m = 1.15 kg
Constant temperature T1 = T2 = 27 + 273 = 300k
Since the temperature is constant, we can say that the process is isothermal
P1 = 111 KPa
P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa
Now what we want to calculate is W1-2
Mathematically, for isothermal process;
W1-2 = mRTlnP1/P2
where R can be obtained from table and it is equal to 0.287 KJ/kg.k
Hence;
W1-2 = (1.15)(0.287)(300)(ln 111/840)
W1-2 = 99.015 * -2.023871690525 = -200.39 KJ
Kindly note that the value of the work is negative because work is done on the system and not by the system
How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 22.0 cmcm in diameter to produce an electric field of 1340 N/CN/C just outside the surface of the sphere?
Answer:
1.125x10^-10 electrons
Explanation:
Pls see attached file
What rule should be used to transform a table of data to represent the
reflection of f(x) over the yaxis?
Answer:
Multiply the x values with -1.
Explanation:
By multiplying the numbers by one, you are changing them to be the opposite of their original state.
You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.
Hope this helped and good luck!
Answer:
Multiply each x-value in the table by -1
Explanation:
The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)
Answer:
[tex]\boxed{ V_{2}= 0.03189 m^3}[/tex]
Explanation:
According to Charles Law
=> [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Where [tex]V_{1}[/tex] = 0.0279 m³, [tex]T_{1}[/tex] = 280 K and [tex]T_{2}[/tex] = 320 K
=> [tex]\frac{0.0279}{280} = \frac{V_{2}}{320}[/tex]
=> [tex]V_{2}[/tex] = 0.03189 m³
Suppose you are testing a new amusement park roller coaster with an empty car with a mass of 100 kg. One part of the track is a vertical loop with a radius of 12.0 m. At the bottom of the loop (point A), the car has a speed of 25.0 m/s and at the top of the loop (point B), it has a speed of 8.00 m/s. As the car rolls from point A to point B, how much work is done by friction? Use 9.81 m/s2 for the acceleration due to gravity.
Answer:
Explanation:
Gain of kinetic energy + work done by friction = loss of potential energy
= 1 / 2 m ( 25² - 8² ) + work done by friction = m x 9.8 x ( 12 + 12 )
= .5 x 100 x ( 625 - 64 ) + work done by friction = 100 x 9.8 x 24
28050 + work done by friction = 23520
work done by friction = -4530 J
Which of the following would cause the force of static friction to increase?
Answer:
Answer B) An increase in [tex]\mu_S[/tex]
Explanation:
Since we are talking about the force of static friction, due to its definition as the product between the normal force to the surface times the coefficient of static friction, the only two ways such force could increase is due to an increase in the normal force, or an increase in the coefficient of static friction [tex]\mu_S[/tex].
So the only valid answer is answer B)
How will you connect 3 cells each of value 2V to give a total of 3V * Two in parallel with one in series Two in series with one in parallel All in parallel All in series
Answer:
two of them in series with one in parallel
Explanation:
When two or more batteries are connected in
(a) series: the total voltage produced is equal to the sum of the voltages on each of the batteries. For example, if two batteries A and B of 3V and 2V respectively are connected in series, then the total voltage produced is
3V + 2V = 5V
(b) parallel: the total voltage produced is equal to the voltage on any one of the batteries. As a mention, only batteries of the same voltage should be connected together in parallel. For example, if two batteries A and B each of 4V are connected together in parallel, then the total voltage produced is 4V.
If these batteries are not of the same voltage, then the one of larger voltage will charge the one of the lower voltage until they both have the same voltage. That means that their eventual voltage will be the average of their voltages. For example, if two batteries A and B of 3V and 2V respectively, are connected in parallel, their total voltage will be,
(3V + 2V) / 2 =2.5V
Now, from the question.
Since there are three cells each of value 2V.
=>If we connect two of them in series, the total voltage from those two cells will be 2V + 2V = 4V
=>If we then connect this series connection in parallel with the third cell, then we have a parallel combination of 4V and 2V. Since they have different voltages, then the total voltage will be the average of the two voltages. i.e
(4V + 2V) / 2 = 6 / 2 = 3V
Therefore, to have a total of 3V from three cells each of 2V, we need to connect two of them in series with one in parallel
A point charge +Q is located on the x axis at x = a, and a second point charge –Q is located on the x axis at x = –a. A Gaussian surface with radius r = 2a is centered at the origin. The flux through this Gaussian surface is
Answer:
Net flux through the surface is zero.
Explanation:
Recall that the net electric flux through a closed surface depends on the net charge enclosed inside that surface.
In our case, there are two point charges of exactly opposite charge (net charge - zero), which are located inside the Gaussian surface of radius "2 a" centered at the origin - both charges are located at a distance "a" from the origin of coordinates, therefore inside the Gaussian surface.
Then the net flux through the surface is also ZERO.
A river flows with a speed of 3km/h in still water. A man who can swim with a speed of 5km/h wishes to reach a point on the other bank just opposite to the starting point. In which direction should he put his strokes and how long will he take to cross the river of width 1.2km? Please try to provide a diagram and step by step explanation.
Answer:
Explanation:
Let the angle required be θ with direction opposite to current .
cos θ = 3 / 5
θ = 53° .
Resultant velocity towards the opposite side
= √ ( 5 ² - 3²)
= 4 km /h
distance covered = 1.2 km
time taken = 1.2 / 4 = .3 h
= 18 min .
Which of the following statements describes nucleons?
A. Nucleons are the particles that make up a nucleus.
B. Nucleons are the particles in an atom that are neutral.
C. Nucleons are the particles that make up an atom.
D. Nucleons are the particles in an atom that have a charge.
Answer: nucleons are the particles that make up in nucleus
Explanation:
Nucleons are the particles that make up a nucleus, and they include protons and neutrons.
What are nucleons?Nucleons are particles that make up nucleus of an atom. They include either proton or neutron, or both found in atomic nucleus.
Generally, nucleons are subatomic particles found within nucleus of an atom.
Therefore, we can conclude that, nucleons are the particles that make up a nucleus.
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Which force acts on a body if it is fully or partially immersed in a
liquid?
Answer:
Buoyant Force
Explanation:
That's literally the definition of the buoyant force
Round the numbers that follow to three significant figures and express the result in standard exponential notation: (a) 143,700; (b) 0.09750; (c) 890,000; (d) 6,764E4; (e) 33,987.22; (f) - 6.5559.
Explanation:
Non-zero digits are always significant.
Zeros between significant digits are also significant.
Trailing zeros are significant only after a decimal point.
(a) 143,700
First, write in scientific notation.
1.437×10⁵
Now, round to 3 significant figures.
1.44×10⁵
(b) 0.09750
= 9.750×10⁻²
= 9.75×10⁻²
(c) 890,000
= 8.9×10⁵
= 8.90×10⁵
(d) 6,764×10⁴
= 6.764×10⁷
= 6.76×10⁷
(e) 33,987.22
= 3.398722×10⁴
= 3.40×10⁴
(f) -6.5559
= -6.5559×10⁰
= -6.56×10⁰
The scientific notation and round-off of the number are given below:-
(a) 143,700 = 1.44×10⁵
(b) 0.09750 = 9.75×10⁻²
(c) 890,000 = 8.90×10⁵
(d) 6,764×10⁴ = 6.76×10⁷
(e) 33,987.22 = 3.40×10⁴
(f) -6.5559 = -6.56×10⁰
What is a scientific notation?Numbers that are either too large or too little to be conveniently stated in decimal form can be expressed using scientific notation. It may be called scientific form.
When a number is written using only the digits of the number, that is considered standard notation. Since words are not used in conventional number notation, this is the way that numbers are typically written.
Non-zero digits are always significant. Zeros between significant digits are also significant.
Trailing zeros are significant only after a decimal point.
(a) 143,700
First, write in scientific notation.
1.437×10⁵
Now, round to 3 significant figures.
1.44×10⁵
(b) 0.09750
= 9.750×10⁻²
= 9.75×10⁻²
(c) 890,000
= 8.9×10⁵
= 8.90×10⁵
(d) 6,764×10⁴
= 6.764×10⁷
= 6.76×10⁷
(e) 33,987.22
= 3.398722×10⁴
= 3.40×10⁴
(f) -6.5559
= -6.5559×10⁰
= -6.56×10⁰
Therefore, the numbers can be written in the scientific notations as above.
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When you urinate, you increase pressure in your bladder to produce the flow. For an elephant, gravity does the work. An elephant urinates at a remarkable rate of 0.0060 m3 (a bit over a gallon and a half) per second. Assume that the urine exits 1.0 m below the bladder and passes through the urethra, which we can model as a tube of diameter 8.0 cm and length 1.2 m. Assume that urine has the same density as water, and that viscosity can be ignored for this flow.
1) What is the speed of the flow? It is 1.2 m/s
2) If we assume that the liquid is at rest in the bladder (a reasonable assumption) and that the pressure where the urine exits is equal to atmospheric pressure, what does Bernoulli's equation give for the pressure in the bladder? (In fact, the pressure is higher than this; other factors are at work. But you can see that no increase in bladder pressure is needed!)
Answer:
1) v = 1.19 m / s , 2) P₁ = 9.308 10⁴ Pa
Explanation:
In this exercise we will simulate the emission of urine as a fluid mechanics system
1) they indicate the urine flow rate Q = 0.0060 m³ / s, they also give the diameter of the tube 8.0 cm, they ask us the speed.
Let's use the continuity equation
Q = v A
The area of a cycling tube is
A = π r² = π d² / 4
we substitute
Q = v π d² / 4
v = 4Q / π d²
let's calculate
v = 4 0.006 / (π 0.08²)
v = 1.19 m / s
2) they ask to find the pressure in the bladder, for this we use the Bernoulli equation, where the index is for the bladder and the index 2 is for the exit point
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
in the exercise it indicates that the outlet pressure is equal to the atmospheric pressure P₂ = 1,013 10⁵ Pa, the velocity of the liquid in the bladder is v₁ = 0 and the height difference 1.0 m
P₁ = P₂ + ½ ρ v₂² + ρ g (y₂-y₁)
let's calculate
P₁ = 1.013₁ 10⁵⁵ + ½ 1000 1.19 + 1000 9.8 (0-1)
P₁ = 1.013 105 + 595 - 9800
P₁ = 9.308 10⁴ Pa
Diagram 7 shows the velocity-time graph of an
object for 12 s.
When is the object at a distance of one-quarter of
the total distance travelled in the 12 s?
A 3 s
B 4 s
C 5 s
D 6 s
*The answer is D but can anyone tell me the solving steps? Or perhaps the answer is wrong?*
Answer:
t = 6
Explanation:
Displacement is equal to the area under a velocity vs time graph.
In this case, the area is a triangle. At time t, the base of the triangle is t. The height of the triangle can be found with similar triangles:
h / t = 8 / 12
h = ⅔ t
So the distance traveled at time t is:
d = ½ (t) (⅔ t)
d = ⅓ t²
The distance traveled at time 12 is:
D = ½ (12) (8)
D = 48
We want to find when d = D/4.
d = D/4
⅓ t² = 48/4
⅓ t² = 12
t² = 36
t = 6
Alternatively, since the acceleration is constant here, we could use a constant acceleration equation.
Δx = v₀ t + ½ at²
Given v₀ = 0 m/s and a = ⅔ m/s²:
Δx = (0) t + ½ (⅔) t²
Δx = ⅓ t²
When t = 12, Δx = 48.
⅓ t² = 48/4
t = 6
explain why the term Nano is used to describe nanotechnology
Answer:
Nanotechnology means working with materials at the scale of one billionth of a metre.
Explanation:
The prefix “nano” refers to one billionth: it’s part of the scientific scale of measurement. Its science, engineering, and technology are conducted at the nanoscale, which is about 1 to 100 nanometers. Nanoscience and nanotechnology are the study and application of extremely small things. Thus, this describes why the term nano is used to describe nanotechnology.
I hope this helps :)
Answer:
Nanotechnology is technology that is about a nanometer in size, or between 1 nm and 100 nm.
Explanation:
its the sample response on edge 2021
Earthquake damage causes two rabbits to be separated from the rest of the rabbits in their large habitat. They have no way to get back to their original habitat. The two rabbits mate with each other. Over time, all the offspring in the new habitat are descendants of the original two rabbits. What are the outcomes of this situation? A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat. B. The rabbits in the new habitat will have a higher risk of random genetic mutations than the rabbits in the original habitat. C. The rabbits in the original habitat have a greater likelihood of choosing an unrelated mate than the rabbits in the new habitat. D.The rabbits in the original habitat will be less likely to reproduce than the rabbits in the new habitat.
Answer:
A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat.
Explanation:
If two animals of opposite sex are isolated from a larger group of animal, and made to reproduce. They will produce offspring with similar genetic makeup. If this offspring still remain isolated, and continue to interbreed within themselves for a number of consecutive generations, their offspring will all be very closely related genetically. Situations like this just as with the two rabbits in the question leads to a lower genetic variation within the offspring of the two animals.
Animals need to reproduce within a larger group in order to increase genetic variation. Increasing genetic variation reduces the risk of been sucked into a gene pool. A lower genetic variation reduces the fitness of the animals involved. It is only an advantage in cases in which the the original pair are resistant to a deadly disease. In this case all the offspring also develop this immunity. Mostly the effects of a lower genetic variation leaves negative impacts, and animals try to avoid this by preferring to interbreed with unrelated partner
Answer:
I got this and got the answer correct.
Explanation:
Hope it helps :)
Salt compounds are commonly used to melt ice that forms on sidewalks in the winter. A common chemical that is used to melt sidewalk ice is calcium chloride, CaCl2(s). When calcium chloride dissolves into solution is releases thermal energy which aides in melting
the ice.
The molar mass of water is 18.02 g/mol
The thermal energy, in kilojoules (kJ) that must be released from the calcium chloride,
CaCl2(s), to melt 10.0 kg of ice, expressed in scientific notation is a.bc x 104 k).
46
55
The values of a, b, c, and d.
Answer:
The values of a, b, c and d are
a = 3, b = 3, c = 4 and d = 3
Explanation:
The quantity of heat needed to melt the ice is given by Q = mL where m = mass of ice and L = latent heat of fusion of ice = 334 kJ/kg. This quanity of heat is also the thermal energy needed to be released by the calcium chloride, CaCl₂
Now, the mass of ice = 10 kg. So,
Q = mL
Q = 10 kg × 334 kJ/kg
Q = 3340 kJ
In scientific notation,
Q = 3.34 × 10³ kJ
So the thermal energy needed to be released by the calcium chloride is 3.34 × 10³ kJ
Comparing Q = 3.34 × 10³ kJ with a.bc × [tex]10^{d}[/tex] kJ
So, a = 3, b = 3, c = 4 and d = 3
The values of a, b, c and d are
a = 3, b = 3, c = 4 and d = 3
A hollow circular shaft made of 304 stainless steel uniformly tapers from an outer diameter of 3.0 cm to an outer diameter of 4.0 cm over a length of 2 meters. The inner diameter of 1.0 cm is constant over the length of the shaft. The shaft is subjected to an applied torque of 500 Nm. Determine the maximum shear stress in the shaft.
Answer:
maximum shear stress = τ(max) = 95.49 × 10⁶N/m²
Explanation:
given
outer diameter at one end(D₁) = 3.0cm
outer diameter at the other end(D₂) = 4.0cm
inner diameter(d₁) = 1.0cm
torque applied(T) = 500Nm
maximum shear stress will occur at lower outer diameter
the formula is τ/r = T/J
τ= T × r/J
where r is radius
T is the torque
J is the polar 2nd M of area
attached is the calculation of the question
The power source provides a current of 1.86 A at a potential difference of 3.90 V. Calculate the power of the power source. Use the equation:
power = potential difference × current
Choose the correct unit from the box below
C W J
Answer:
W
Explanation:
The unit for Power which is (Volt X Current) is Watts. and the symbol for Watts is W.
identify the motion when a car is moving with constant speed along a curve
Answer:
Uniform circular motion
Explanation:
When a car is moving with constant speed along a curve, it will said to have uniform circular motion. The speed of the car remains constant in this case. But its velocity keeps on changing. The velocity can be calculated by drawing the tangent on the circle. Hence, the motion of the car is uniform circular motion.
Answer:
Uniform motion
Explanation:
The motion when a car is moving with constant speed along a curve is an example of uniform motion.
A car moving at constant speed covers equal distances in equal intervals of time. The average speed remains the same in uniform motion.
The curve defines the path of the motion and the speed remains constant.
How is a less-intense wave different from a more-intense wave?
It has fewer decibels.
O It has a higher pitch.
O It has more volume.
It has more energy.
Answer: It has fewer decibels.
Explanation:
In a sound-wave, the intensity is defined as the power carried by the wave. The decibel is a measure of the ratio between two quantities. And in acoustics is used as the unit of the sound pressure level, which is related to the intensity of the wave, then:
As the intensity increases, we also should notice an increase in the decibels.
How is a less-intense wave different from a more-intense wave?
The less-intense wave has fewer decibels.
Answer:
It has fewer decibels.
Explanation:
Answer the following three questions in complete sentences. 1. How much does the earth weigh? 2. How far away is the sun? 3. What is a black hole?
Answer: find the answer in the explanation.
Explanation:
1.) The weight of the earth can be calculated and estimated by the physicist by considering the mass of the earth and the knowlegde of gravity.
If the mass of the earth is considered to be 6 × 10^24 kg. Then with Physics formula and some mathematical techniques, we can conclude that the weight of the earth is approximately equal to 6 × 10^25 N.
2.) The distance of the sun to the earth is approximately 1.5 × 10^8 km. This measure is the distance from the surface of the earth to the sun.
3.) The black hole is approximately the size of the earth of very large gravitational field strength. It is a region of space of enormous gravity where no particular object can escape from it. Even electromagnetic radiation or light cannot escape from it.
Answer:
The Earth weighs 5.972 × 10^24 kg
The Sun is 94.022 million miles away.
A black hole is is a region of spacetime where gravity is so strong that nothing, no particles or even electromagnetic radiation such as light can escape from it. The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.
I hope this helps!! :)