On average, there are 12 potholes per mile on a particular stretch of the state highway. Suppose the potholes follow a Poisson distribution on the highway. a. Find the probability of finding fewer than two potholes in a quarter-mile stretch of the highway. (Do not round intermediate calculations. Round your final answer to 4 decimal places.) b. Find the probability of finding more than one pothole in a quarter-mile stretch of the highway. (Do not round intermediate calculations. Round your final answer to 4 decimal places.)

Answers

Answer 1

Answer:

a) 0.1992 = 19.92% probability of finding fewer than two potholes in a quarter-mile stretch of the highway.

b) 0.8008 = 80.08% probability of finding more than one pothole in a quarter-mile stretch of the highway.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

a. Find the probability of finding fewer than two potholes in a quarter-mile stretch of the highway.

Mean of 12 potholes per mile, which means that in a quarter-mile stretch, the mean is [tex]\mu = \frac{12}{4} = 3[/tex]

This probability is:

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3}*(3)^{0}}{(0)!} = 0.0498[/tex]

[tex]P(X = 1) = \frac{e^{-3}*(3)^{1}}{(1)!} = 0.1494[/tex]

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.0498 + 0.1494 = 0.1992[/tex]

0.1992 = 19.92% probability of finding fewer than two potholes in a quarter-mile stretch of the highway.

b. Find the probability of finding more than one pothole in a quarter-mile stretch of the highway.

This is

[tex]P(X > 1) = 1 - P(X < 2)[/tex]

We have that [tex]P(X < 2) = 0.1992[/tex]

So

[tex]P(X > 1) = 1 - P(X < 2) = 1 - 0.1992 = 0.8008[/tex]

0.8008 = 80.08% probability of finding more than one pothole in a quarter-mile stretch of the highway.


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Step-by-step explanation:

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Step-by-step explanation:

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(06.04 LC)
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Step-by-step explanation:

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\fn qf7f

The value of the matrix X is X =  [tex]\left[\begin{array}{ccc}-7&-2\\7&0\\\end{array}\right][/tex].

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Answer:

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Step-by-step explanation:

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Answer:

x= -8

Step-by-step explanation:

Move the terms

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Change the signs

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Answers

Answer:

B. L and N

Step-by-step explanation:

Let's solve each system

✔️System L:

3x + y = 8 => Eqn. 1

x - 4y = -6 => Eqn. 2

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Substitute x = (-6 + 4y) in eqn. 1

3(-6 + 4y) + y = 8

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13y = 8 + 18

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✔️System M:

4x - 3y = 2 => Eqn. 1

5x - 4y = -30 => Eqn. 2

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2x - 8y = -12 => Eqn. 2

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Substitute y = 2 into eqn. 1

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