Answer:
T₁ = 15.66 N
Explanation:
From the given information:
Using the free body system in the chain.
T - mg = ma
47 - 3.12 × 9.8 = 3.12a
47 - 30.576 = 3.12a
16.424 = 3.12a
a = 16.424/3.12
a = 5.26 m/s²
Now, by the free body diagram of the lowest link; the tension (T₁ ) in the chain is:
T₁ - (3.12/3) × 9.8 = (3.12/3) × 5.26
T₁ - 1.04 × 9.8 = 1.04 × 5.26
T₁ - 10.192 = 5.4704
T₁ = 5.4704 + 10.192
T₁ = 15.6624
T₁ = 15.66 N
CAN SOMEONE PLEASE HELPPPPPP
Answer:
0.54
Explanation:
2.7÷5 = 0.54
Hope this helps!
Force is a vector because it has both ___
and ____
A. distance and direction
B. size and distance
C. size and direction
Answer:
C. Size and Direction
a charge Q exerts a 2.4 N force on another charge q.If the distance between the charges is doubled,what is the magnitude of the force exerted on Q by q ?
What are some of the physical properties of minerals
Answer:
hardness, luster, color, streak, specific gravity, cleavage, fracture, and tenacity.
Explanation:
doesn't really need one.
Assume the ground is uniformly level. If the horizontal component a projectile's velocity is doubled, but the vertical component is unchanged, what is the effect on the time of flight
Answer:
Explanation:
Time of flight = 2 x u sinα / g where u sinα is vertical component of projectile's velocity u .
So Time of flight = 2 x vertical component / g
vertical component = constant
g is also constant so
Time of flight will also be constant .
It will remain unchanged .
A student determines a value for a force using the formula F = k I l.
k is a constant with units of N A-1 m-1
I is current measured in mA
l is length measured in mm
The student uses the numbers directly from each measurement in their calculation.
What will be the units of the force from that calculation?
1 Newton force is equal to the 10⁻⁵ dynes. The unit of force will be dyne and the value of force will be 0.1 dynes.
What is force?
Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration.
Its SI unit is Newton, MKS unit is kgm/s² and CGS unit is dyne.
The given formulae are;
F = k I l
k is a constant with unit= N A-1 m-1
I is currently measured in mA = 10⁻³A
l is the length measured in mm= 10⁻³ m
F = k I l
F= N A-1 m-1× 10⁻³A×10⁻³ m
F= 10⁻⁶ N ( 1N = 10⁻⁵ dyne)
F= 0.1 dyne
Hence the unit of force will be dyne and the value of force will be 0.1 dynes.
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1. The more velocity an object has the harder it is to slow
it down, speed it up, or turn it.
Answer:
The more velocity an object has the harder it is to slow it down
Explanation:
slow it down
A train takes 2.5 hours to travel 120 kilometers. What is the train's average speed?
A: 0.02 hr/km
B: 48 km/hr
C: 48 hr/km
D: 0.02 km/hr
PLS HELPPP
Answer:
48
Explanation:
The formula is d, time t, and speed or rate of travel r is:
d = rt.
We know that d = 120 km and t = 2 hours and 30 minutes = 2.5 hrs.
So you now plug in for d and t to find r, we get:
120 km = r(2.5 hrs)
divide both sides by 2.5 and we get
120 km/2.5 hrs = [r(2.5 hrs)]/2.5 hrs
120 km/2.5 hrs = r(2.5 hrs/2.5 hrs)
48 km/hr = r(1)
r = 48 km/hr
Speed = (distance covered) / (time to cover the distance)
Speed = (120 km) / (2.5 hr)
Speed = (120/2.5) (km/hr)
Speed = 48 km/hr (B)
plz solve 90-(3+9)∙7
Answer:
The answer is 6.
90 - (3+9) • 7
90 - (12) • 7
90 - 12 • 7
90 - 84
6
She walks 50 yards north 20 yards east 50 yards south what is total displacement
Answer:
|---20----|
| |
| 50 |50
|---D--->|
Start End
Total displacement(D) 20 yards (East).
Explanation:
What is the length of the x-component of the vector shown below?
c. 6.6
What is x component?The x-component of a vector can be either sinθ or cosθ, depending on which angle you are given.
Cosθ always goes with the side of a right triangle that is adjacent to (touches) the given angle.
The projection of a vector quantity on the x axis of a coordinate system.
If you shine a light straight down onto that vector, then the length of its shadow on the x-axis is
x-component = 8· cosine(34°)
x-component = 8 · (0.829)
x-component = 6.6
Therefore,
6.6 is the length of the x-component of the vector.
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6.8. A marble with a mass m of 3.00 g is released from rest in a bottle of syrup. Its terminal speed vt is 1.79 cm/s. (a) Presuming the resistive force R = −bv, what is the value of b (N s/m)? (b) What is the strength of the resistive force (N) when the marble reaches terminal speed? (c) How long in milliseconds does it take for it to reach a speed of 0.600vt?
Answer:
a. 1.642 Ns/m b. 0.0294 N c. 5 × 10⁵ ms
Explanation:
a. Presuming the resistive force R = −bv, what is the value of b (N s/m)?
Using the equation of motion on the object,
W + R = ma where W = weight of the mass = mg where m =mass of marble = 3.00 g = 0.003 kg and g = acceleration due to gravity = 9.8 m/s² , R = resistive force = -bv where v = velocity and a = acceleration of marble.
So,
mg - bv = ma
At terminal speed, a = 0,
So, mg - bvt =m(0)
mg - bvt = 0
mg = bvt
b = mg/vt since terminal speed vt = 1.79 cm/s = 0.0179 m/s
So, b = 0.003 kg × 9.8 m/s²/0.0179 m/s
b = 0.0294 kgm/s² ÷ 0.0179 m/s
b = 1.642 Ns/m
b. What is the strength of the resistive force (N) when the marble reaches terminal speed?
Since the resistive force R = -bv, at terminal speed, vt
R = -bvt
R = -1.642 Ns/m × 0.0179 m/s
R = -0.0294 N
So, its strength is 0.0294 N
(c) How long in milliseconds does it take for it to reach a speed of 0.600vt?
Using mg - bv = ma where a = dv/dt,
mg - bv = mdv/dt
g - bv/m = dv/dt
separating the variables, we have
dv/(g - bv/m) = dt
Integrating, we have
∫dv/(g - bv/m) = ∫dt
(-b/m)/(-b/m) × ∫dv/ (g - bv/m) = ∫dt
1/(-b/m) ∫(-b/m)dv/(g - bv/m) = ∫dt
1/(-b/m) ㏑(g - bv/m) = t + C
㏑(g - bv/m) = -m/bt - mC/b
㏑(g - bv/m) = -m/bt + C' (C' = -mC/b)
taking antilogarithm of both sides, we have
g - bv/m = exp(-m/bt + C')
g - bv/m = exp(-m/bt)expC'
g - bv/m = Aexp(-m/bt) (A = expC')
bv/m = g - Aexp(-m/bt)
v = mg/b - (Am/b)exp(-m/bt)
when t = 0, v = 0 (since the marble starts from rest)
0 = mg/b - (Am/b)exp(-m/b(0))
0 = mg/b - (Am/b)exp(0))
-mgb = -Am/b
A = g
v = mg/b - (mg/b)exp(-m/bt)
when v = 0.600vt = 0.600 × 0.0179 m/s = 0.01074 m/s
mg/b = 0.003 kg × 9.8 m/s²/1.642 Ns/m = 0.0179 m/s and m/b = 0.003 kg/1.642 Ns/m = 0.00183/s
So,v = mg/b - (mg/b)exp(-m/bt)
0.01074 m/s = 0.0179 m/s - (0.0179 m/s)exp[(-0.00183/s)t]
0.01074 m/s - 0.0179 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]
-0.00716 m/s = - (0.0179 m/s)exp[(-0.00183/s)t]
exp[(-0.00183/s)t] = -0.00716 m/s/-0.0179 m/s
exp[(-0.00183/s)t] = 0.4
taking natural logarithm of both sides, we have
(-0.00183/s)t = ㏑(0.4)
(-0.00183/s)t = -0.9163
t = -0.9163/-0.00183
t = 500 s
t = 500 × 1000 ms
t = 5 × 100000
t = 5 × 10⁵ ms
The cause of weather systems on earth is ___________?
A. Conduction
B. Convection
C. Radiation
Answer:
Convection and Radiation
Explanation:
Because the sun heats up the earth which cause the warm temperature and you probably know convection heat up the coefficient and radiation transfer heat electromagnetic or heat LOL
The cause of weather systems on earth is CONVECTION.
Convection can be defined as the transfer of heat from one site to another caused by the movement of fluid.This transfer of heat can be calculated as
Q=h A\Delta Twhere Q is equal to the rate of transference of heat; h is equal to convection heat-transfer coefficient; A to the surface area that is exposed and Delta T is equal to the temperature difference.Heat energy is always transferred from hot sites to cooler sites.This transfer of heat (convection) only occurs in liquids and gases.In conclusion, the cause of weather systems on earth is CONVECTION.
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Need help with this pleases
an oscillator with a mass of 310 g and a period of 0.180 s has amplited that decreases by 20 % during each complete oscillation what is the damping constant
Answer:
1.241/s
Explanation:
From this question, we have the following information:
Mass of oscillator = 310
The time Period, t = 0.180
Decrease = 20 %
Amplitude of oscillation has the formula
A = Aoe^yt
1-20% = 80%
= 0.80
Y x 0.18 = -ln(0.8)
= 0.18Y = 0.2234
Y = 0.2233/0.18
Y = 1.241/s
The damping constant y is Therefore equal to 1.241s
why do bees sting i think they do because when the get disturbed they use thier stinger to sting people
what happens to the strength of an electromagnet when the number of coils in the solenoid in increased
a. it depends on what metal makes up the solenoid
b. it increases
c. it remains the same
d. it deceases
Answer:
B. It increases
Explanation:
Im sure
What are the functions of the codons
What is the potential energy at point e when the total mechanical energy is 4900 for the 100 kg moving at 2 m/ s
Answer:
B. 4700 J
Explanation:
Given the following data;
Mechanical energy = 4900J
Mass = 100kg
Velocity = 2m/s
To find the potential energy;
Mechanical energy = kinetic energy + potential energy
First of all, we would determine the kinetic energy of the object;
K.E = ½mv²
K.E = ½*100*2²
K.E = 50*4
K.E = 200 J
Substituting into the equation, we have;
4900 = 200 + P.E
P.E = 4900 - 200
P.E = 4700 Joules
Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 1 m. Conductor B is a hollow tube of inside diameter 1 m and outside diameter 2 m. The ratio of their resistance, RA/RBRA/RB, is:
Answer:
Ra / Rb = 3
Explanation:
The resistance is defined by the expression
r = ρ L / A
where A is the area of the wire and L is the length
let's find the area of each wire
a) solid wire (A) of d₁ = 1 m
r = d₁ / 2 = 0.5 m
A = π r²
A = π 0.5²
R_a = [tex]\frac{\rho \ L}{\pi \ 0.5^2}[/tex]
R_a = 4 \frac{\rho \ L}{\pi }
b) hollow tube (B) of d₁ = 1 m and d₂ = 2m
the radios are
r₁ = 0.5 m
r₂ = 1 m
the area is
A = π r₂² - π r₁²
A = π (r₂² - r₁²)
A = π (1² - 0.5²)
A = π 0.75
resistance is
R_b = [tex]\frac{ \rho \ L }{\pi \ 0.75}[/tex]
R_b = 1.33 \frac{ \rho \ L }{\pi }
therefore the relationship between these two resistances is
Ra / Rb = 4 / 1.33
Ra / Rb = 3
a kids toy has a mass of 2.6kg. what is the weight of the object on earth
Answer:
25.48
Explanation:
the earth's gravitational pull is 9.8 m/s. So to find the answer, multiply 2.6 x 9.8
A squirrel pulls a 8.7 kg bag of acorns along the ground with a constant force of 80 N. If the force of friction opposing this sliding is 32 N. what will be the acceleration of the bag of acorns?
Answer:
[tex]a=5.51\ m/s^2[/tex]
Explanation:
Given that,
The mass of a bag of acorns, m = 8.5 kg
The force acting on the bag = 80 N
The force of friction = 32 N
We need to find the acceleration of the bag of acorns.
Net force acting on it is = 80 N - 32 N
= 48 N
Let a be the acceleration of the bag of acorns. So,
F = ma
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{48}{8.7}\\\\a=5.51\ m/s^2[/tex]
So, the acceleration of the bag of acorns is [tex]5.51\ m/s^2[/tex].
Janice jumps directly up into the air. Which direction is she accelerating as she moves upward?
A Up
B.
Down
C.
Not accelerating
Answer:
b down
Explanation:
because as she is jumping she is bending her nees so the acceleration is down words
Answer:
b down
Explanation:
A 30.8 kg box rests on an incline of 13 degrees. What is the normal force, in Newtons, exerted by the incline?
so 30.8/13= is 2.369
so round your ans to I dp which is
2.4d/kg
What is the correct definition of a 'field vector'?
a) A measurement that must have both a number and a unit
b) A measurement that can only be measured using scientific digits
c)A measurement that has both a magnitude and direction represented with an arrow
d)A measurement that is drawn in as it cannot be seen visually
i think it is c but can someone help me with this?
Answer: Yes the answer is C
Explanation: Look a pictures of field vectors, they are represented with the arrows.
The diagram shows a proposed design for a ship that could be used for long-distance space travel. Explain why the ship must rotate so that passengers feel effects similar to gravity.
Answer:
I don't know this for sure, but I think its because they need to be able to sit in their seats without flying in the air.
Explanation:
Because of the centrifugal force he ship must rotate so that passengers feel effects similar to gravity.
What is Centrifugal force ?''Centrifugal force is force acting on a body performing circular motion, which is along radius of the circle and directed outwards from the center of circle". Since Centrifugal force acts at right angle to the tangential velocity of the body, there is no displacement in the direction of the force, hence no work done. It has newton(N) as Si unit.
centripetal force is given by,
F= mv²÷r
Where m is mass of the body v is velocity of the body r is radius of circle at which body is moving.
When space ship rotate to the certain angular velocity, centrifugal force will act on each object in the space ship. that force will force the object radially outwards as result all will stuck on the floor and all will experience the feel of gravity.
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A jet aircraft with a mass of 4,250 kg has an engine that exerts a force (thrust) equal to 60,100 N.
(a) What is the jet's acceleration when it takes off? (Give the magnitude.)
m/s2
(b)What is the jet's speed after it accelerates for 9 s? (Assume it starts from rest.)
m/s
(c) How far does the jet travel during the 9 s?
m
Answer:
A. 14.14 m/s²
B. 127.26 m/s
C. 572.67 m
Explanation:
From the question given above, the following data were obtained:
Mass (m) of jet = 4250 kg
Force (F) = 60100 N
A. Determination of the acceleration of the jet.
Mass (m) of jet = 4250 kg
Force (F) = 60100 N
Acceleration (a) =?
F = ma
60100 = 4250 × a
Divide both side by 4250
a = 60100 / 4250
a = 14.14 m/s²
B. Determination of the speed of the jet after 9 s.
Initial velocity (u) = 0 m/s
Acceleration (a) = 14.14 m/s²
Time (t) = 9 s
Final velocity (v) =?
v = u + at
v = 0 + (14.14 × 9)
v = 0 + 127.26
v = 127.26 m/s
C. Determination of the distance travelled during the time.
Initial velocity (u) = 0 m/s
Acceleration (a) = 14.14 m/s²
Time (t) = 9 s
Distance travelled (s) =?
s = ut + ½at²
s = (0 × 9) + (½ × 14.14 × 9²)
s = 0 + (7.07 × 81)
s = 0 + 572.67
s = 572.67 m.
A toy car of mass 1.2 kg is driving vertical circles inside a hollow cylinder of radius 2.0m. It is moving at a constant speed of 6 m/s. a) Calculate the magnitude of the normal force acting on the car when it is on the top of the circle and when it is on the bottom of the circle, respectively. b) What is the minimum speed the car needs to go around the circle without falling off
Answer:
a)[tex]|N|=9.83\: N[/tex] at the top
[tex]|N|=33.37\: N[/tex] at the botton
b) The minimum velocity will be [tex]v=4.43\: m/s[/tex].
Step-by-step explanation:
a) Using the second Newton's law, at the top of the circle we have.
[tex]\Sigma F=ma_{c}[/tex]
The forces at the top are the weight and the normal force.
[tex]W-N=m\frac{v^{2}}{R}[/tex]
[tex]mg-N=m\frac{v^{2}}{R}[/tex]
[tex]N=mg-(m\frac{v^{2}}{R})[/tex]
[tex]N=1.2*9.81-(1.2\frac{6^{2}}{2})[/tex]
[tex]N=-9.83\: N[/tex]
[tex]|N|=9.83\: N[/tex]
At the botton of the circle we have:
[tex]N-W=m\frac{v^{2}}{R}[/tex]
[tex]N-mg=m\frac{v^{2}}{R}[/tex]
[tex]N=1.2*9.81+(1.2\frac{6^{2}}{2})[/tex]
[tex]|N|=33.37\: N[/tex]
b) If we do the normal force equal to zero we can find the minimum velocity, which means:
[tex]W-0=m\frac{v^{2}}{R}[/tex]
[tex]mg=m\frac{v^{2}}{R}[/tex]
[tex]v=\sqrt{Rg}[/tex]
[tex]v=\sqrt{2*9.81}[/tex]
Therefore, the minimum velocity will be [tex]v=4.43\: m/s[/tex].
I hope it helps you!
How can an electromagnet be made stronger?
A.Add more coils of wire.
B.Add an iron core.
C.All the above.
D.Increase the voltage.
All four choices are correct responses. (A), (B), (C), (D)
How do motion and Newton's laws apply to your everyday life? (all of the laws)
Answer:
This may help
Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation: