of the relation
{(16,5), (-15, -17), (22, -16), (-1, –4), (-6, -14)}.
What is the domain and ramge

Answers

Answer 1

Answer:

Domain is x and Range is y

Step-by-step explanation:

Domain-(16,-15,22,-1,-6)

Range-(5,-17,-16,-4,-14)


Related Questions

This year Tammy watched 60 movies. She thought that 15 of them were very good. Of the movie she watched, what percentage did she rate as very good?

Answers

Answer:

25%

Step-by-step explanation:

She watched in total 60 movies. Out of that total, she rated 15 of them as very good. Thus, she rated 15/60 or 1/4 or a quarter of them as very good.

To convert 1/4 into a percentage, simply divide them and you get 0.25. The percentage is the first two digits after the decimal, which is 25%.

A biker’s speed is 1.5 times faster than a walker’s. They started simultaneously from the same point and in 1.5 hours the distance between them was 12.5 miles. What are their speeds?

Answers

Answer:

Biker = 25 mph

Walker = 16⅔ mph

Step-by-step explanation:

Distance = rate × time

If x is the walker's speed and y is the biker's speed, then:

1.5 y − 1.5 x = 12.5

y = 1.5 x

Solve the system of equations.

1.5 y − y = 12.5

0.5 y = 12.5

y = 25

x = 16⅔

Solve x^2 + 4x + 8 = 0

Answers

Answer:

x = -2 + 2 i or x = -2 - 2 i

Step-by-step explanation:

Solve for x:

x^2 + 4 x + 8 = 0

Subtract 8 from both sides:

x^2 + 4 x = -8

Add 4 to both sides:

x^2 + 4 x + 4 = -4

Write the left hand side as a square:

(x + 2)^2 = -4

Take the square root of both sides:

x + 2 = 2 i or x + 2 = -2 i

Subtract 2 from both sides:

x = -2 + 2 i or x + 2 = -2 i

Subtract 2 from both sides:

Answer:  x = -2 + 2 i or x = -2 - 2 i

Suppose you have a set of requests {1,2,...,n} where the ith request corresponds to an interval of time starting at s(i) and finishing at f(i). How can you choose the largest subset of these requests such that none overlap?

Answers

Answer:

You can choose the largest subset by using ; Earliest finish time first

Step-by-step explanation:

In the set of requests { 1,2,....n} where the ith request corresponds to an interval of time for you to choose the largest subset such that none will overlap is by employing/using EARLIEST FINISH TIME FIRST method.

This is because we will have to sort out the finish times of the set of requests before we can proceed to choosing the largest subset contained in the set of requests.

The Toyota Camry is one of the best-selling cars in North America. The cost of a previously owned Camry depends on many factors, including the model year, mileage, and condition. To investigate the relationship between the car’s mileage and the sales price for Camrys, the following data show the mileage and sale price for 19 sales (PriceHub web site, February 24, 2012).Miles(1000s) Price($1,000s) 22 16.2 29 16.0 36 13.8 47 11.5 63 12.5 77 12.9 73 11.2 87 13.0 92 11.8 101 10.8 110 8.3 28 12.5 59 11.1 68 15.0 68 12.2 91 13.0 42 15.6 65 12.7 110 8.3A. Test whether each of the regression parameters b0 and b1 are equal to zero at 0.01 level of significance.B. What are the correct interpretations of the estimated regression parameters?C. Are these interpretations reasonable?

Answers

Answer:

Step-by-step explanation:

Hello!

Given the variables

Y: Cost of a previously owned Camry.

X: Mileage of a previously owned Camry.

Scatter plot in attachment.

As you can see in the scatter plot, the price of the previously owned Camry decreases as their mileage increases this suggest that there is a negative linear regression between these two variables.

Hypothesis test for the y-intercept

H₀: β₀ = 0

H₁: β₀ ≠ 0

Level of significance α: 0.01

p-value < 0.0001

The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry, when the mileage is zero, is different from zero.

H₀: β = 0

H₁: β ≠ 0

Level of significance α: 0.01

p-value: 0.0003

The decision is to reject the null hypothesis. You can conclude that the population mean of the cost of a previously owned Camry is modified when the mileage increases in one unit.

6• 2hen+3pens-5anchors

Answers

Answer:

[tex]180[/tex]

Step-by-step explanation:

[tex]6 \times 2 \times 3 \times 5[/tex]

[tex]12 \times 15[/tex]

[tex]=180[/tex]

Steps to solve:

6 * 2 + 3 - 5

~Multiply

12 + 3 - 5

~Add

15 - 5

~Subtract

10

Best of Luck!

anyone know the answer for this

Answers

Answer:There you go X is the middle, a only brother, b only sister.

a X =11

b X =9

a b X =14 (20-6)

a b 2x=20

X=6

So 6 in the middle, 6 on the outside, 5 only brothers, 3 only sisters. let me know if I missed anything but we have a total of 20, 6 with none, 11 with brothers and 9 with sisters

Step-by-step explanation:

The Hernandez family orders 3 large pizzas. They cut the pizzas so that each pizza has the same number of slices, giving them a total of 24 slices. The Wilson family also orders several large pizzas from the same pizza restaurant. They also cut the pizzas so that all their pizzas have the same number of slices. For the Wilson family, the equation y = 10x represents the relationship, where x represents the number of pizzas and y represents the number of total slices. Which statements best describe the pizzas bought by the Hernandez and Wilson families? Select two options. For the Hernandez family, the equation y = 3x represents the relationship between the number of slices and number of pizzas, where x represents the number of pizzas and y represents the number of total slices. For each family, a graph of the relationship between number of pizzas, x, and number of slices, y, goes through the point (0, 0) and is a straight line. The Hernandez family’s slices are smaller than the Wilson family’s slices. If the Wilson family ordered 3 large pizzas from the same restaurant as the Hernandez family, they would have more slices than the Hernandez family after each family cut their pizzas into slices. The constant of proportionality is 10 for the Wilson family, but cannot be determined for the Hernandez family.

Answers

Answer:

B and D

Step-by-step explanation:

edge 2021

Sample data for the arrival delay times (in minutes) of airlines flights is given below. Determine whether they appear to be from a population with a normal distribution. Assume that this requirement is loose in the sense that the population distribution need not be exactly normal, but it must be a distribution that is roughly bell-shaped Click the icon to view the data set. Is the requirement of a normal distribution satisfied? A. No, because the histogram of the data is not bell shaped, there is more than one outlier, and B. Yes, because the histogram of the data is bell shaped, there are less than two outliers, and the C. Yes, because the histogram of the data is not bell shaped, there is more than one outlier, and D. No, because the histogram of the data is bell shaped, there are less than two outliers, and the the points in the normal quantile plot do not lie reasonably close to a straight line points in the normal quantile plot lie reasonably close to a straight line the points in the normal quantile plot do not lie reasonably close to a straight line points in the normal quantile plot lie reasonably close to a straight line Arrival delay times (minutes) 9 40 - 36 36 105 15- 45 45 27 32 24 5-30 38 2 16 -31 -21-45-30 9837 14 29 50 -44-37 41 - 4-2510 3 -27 6 -38 -26 -25

Answers

Answer:

sdvsdsdfdff

Step-by-step explanation:

Not sure how to answer question 4

Answers

Answer:

Option D is correct

Step-by-step explanation:

Applying the cosine theorem for triangle ABC, you would have:

cos (angle BAC) = (BA^2 + CA^2 - BC^2)/(2*BA*CA)

                           = (10^2 + 18^2 - 20^2)/(2*10*18)

                           = 24/360

=> angle BAC = ~86 deg

Hope this helps!

D = 86
Because its the nearest degree to 90 as you see < BAC seems to be 90

A large department store is curious about what sections of the store make the most sales. The manager has data from ten years prior that show 30% of sales come from Clothing, 25% Home Appliances, 18% Housewares, 13% Cosmetics, 12% Jewelry, and 2% Other. In a random sample of 550 current sales, 188 came from Clothing, 153 Home Appliances, 83 Housewares, 54 Cosmetics, 61 Jewelry, and 11 Other. At α=0.10, can the manager conclude that the distribution of sales among the departments has changed? Enter the p-value - round to 4 decimal places. Make sure you put a 0 in front of the decimal.

Answers

Based on the information given, the null hypothesis will be that there's no difference in the distribution of current sales.

The alternate hypothesis will be that's there's a difference in the distribution of current sales.

Also, it should be noted that the test statistic is 23.0951. The p-value is 0.00003 and the conclusion is that the distribution of sales among the departments has changed.

Learn more about null hypothesis on:

https://brainly.com/question/15980493

The null hypothesis would be that there is no difference in the prevalence of current sales based on the information provided. This alternative hypothesis says there was variance in the distribution of current sales.

It is also worth noting that the test statistic is 23.0951. The p-value is 0.00003, as well as the inference, is that the sales distribution across divisions has altered.

Learn more:

brainly.com/question/14578907

This applet illustrates 95% confidence intervals for samples from a normal distribution with known variance.

When taking 100 samples of size 30 or greater from a population, exactly 95 of them will create a confidence interval that contains the true population mean.

a. True
b. False

Which statement is the correct interpretation of the confidence interval in this illustration

a. The probability the true mean is between 76.08 and 83.92 is 0.95 or 95%.
b. We are 95% confident that the true mean is between 76.08 and 83.92.

Answers

Answer:

1- b. False

2 b. We are 95% confident that the true mean is between 76.08 and 83.92.

Step-by-step explanation:

Confidence Interval is the estimated value that is computed from the statistic of data which is observed. The range value is plausible for unknown parameters. To find the critical value the confidence interval value is observed through the t-value table.

Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 5.0 millimeters (mm) and a standard deviation of 1.7 mm. For a randomly found shard, find the following probabilities.
a. the thickness is less than 3.0 mm
b. the thickness is more than 7.0 mm
c. the thickness is between 3.0 mm and 7.0 mm

Answers

Answer:

(a) The probability that the thickness is less than 3.0 mm is 0.119.

(b) The probability that the thickness is more than 7.0 mm is 0.119.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is 0.762.

Step-by-step explanation:

We are given that thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 5.0 millimeters (mm) and a standard deviation of 1.7 mm.

Let X = thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village.

So, X ~ Normal([tex]\mu=5.0,\sigma^{2} =1.7^{2}[/tex])

The z-score probability distribution for the normal distribution is given by;

                           Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean thickness = 5.0 mm

           [tex]\sigma[/tex] = standard deviation = 1.7 mm

(a) The probability that the thickness is less than 3.0 mm is given by = P(X < 3.0 mm)

    P(X < 3.0 mm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{3.0-5.0}{1.7}[/tex] ) = P(Z < -1.18) = 1 - P(Z [tex]\leq[/tex] 1.18)

                                                           = 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(b) The probability that the thickness is more than 7.0 mm is given by = P(X > 7.0 mm)

    P(X > 7.0 mm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{7.0-5.0}{1.7}[/tex] ) = P(Z > 1.18) = 1 - P(Z [tex]\leq[/tex] 1.18)

                                                           = 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is given by = P(3.0 mm < X < 7.0 mm) = P(X < 7.0 mm) - P(X [tex]\leq[/tex] 3.0 mm)

    P(X < 7.0 mm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{7.0-5.0}{1.7}[/tex] ) = P(Z < 1.18) = 0.881

    P(X [tex]\leq[/tex] 3.0 mm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{3.0-5.0}{1.7}[/tex] ) = P(Z [tex]\leq[/tex] -1.18) = 1 - P(Z < 1.18)

                                                           = 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

Therefore, P(3.0 mm < X < 7.0 mm) = 0.881 - 0.119 = 0.762.

match the term with the definition​

Answers

Answer:

1 - c

2 - a

3 - e

4 - d

5 - b

Answer:  c, a, e, d, b

Step-by-step explanation:

1. Angle: (c) A figure consisting of two rays with the same endpoint.

2. Circle: (a) The set of all points in a plane that are a given distance from a point. That distance is called the radius.

3. Point: (e) A location, has no size.

4. Ray: (d) The portion of a line that starts at one point and goes off to infinity.

5. Vertex: (b) A point where two or more rays or "arms" of an angle meet.

Find an equation of the plane that passes through the point P0(- 3,3,1) with a normal vector n = (1,4, -3). Which of the following equations is an equation of the plane that passes through the point P0( - 3,3,1) with a normal vector n (1,4, -3)?

a. An equation for the plane is -3x+3y + Z = 6.
b. An equation for the plane is x+ 3y +z = 19.
c. An equation for the plane is x + y+ z = 26.
d. An equation for the plane is x +4y - 3z= 6.

Answers

Take an arbitrary vector (x, y, z), which goes from the origin to some point (x, y, z) on the plane we want to find.

Subtract from this vector, the vector that points to [tex]P_0[/tex], which is (-3, 3, 1). This translates the first vector so that it starts at the point [tex]P_0[/tex] and is directed at some point (x, y, z). We get a new translated vector, (x + 3, y - 3, z - 1), which lies in the plane.

The normal vector to the plane is orthogonal to every vector in the plane. So taking the dot product of any vector in the plane with the normal to the plane will always result in 0. We use this to find the plane's equation:

[tex]\vec n\cdot((x,y,z)-P_0)=(1,4,-3)\cdot(x+3,y-3,z-1)=0[/tex]

[tex]\implies(x+3)+4(y-3)-3(z-1)=0[/tex]

[tex]\implies x+4y-3z=6[/tex]

and so the answer is D.

Identify three misconception each of any five topic's in mathematics

Answers

62 = 12.

7 x 0 = 7.

Four hundred and eight is written as 4008.

0.10 = point ten.

0.5 x 10 = 0.50.

6 -:- ½ = 3.

- 5 + 3 = -8.

4% is 0.4 as a decimal.

Kenneth had $5. He spent g cents everyday. How much money he left afterone week? (a) Give you answer in cents (b) Give your answer in dollars.

Answers

Answer:

answer in cents = (500 - 7g ) cents

answer in dollars = ((500 - 7g)/100 ) dollar

Step-by-step explanation:

Money with Kenneth = $5

we know that 1 dollar = 100 cents

Money with Kenneth in cents= 5*100 = 500 cents

Money spent in 1 day = g cents

Money spent in 1 day in dollar = g /100 dollar

(a) Give you answer in cents

One week has 7 days

money spent in 7 days = Money spent in 1 day*7 = g*7 = 7g cents

Money left with Kenneth  after one week= total money Kenneth had in cents - money spent in 7 days  = (500 - 7g ) cents

(b) Give you answer in cents dollars

One week has 7 days

money spent in 7 days in dollars = Money spent in 1 day*7 = g/100*7 = 7g/100 cents

Money left with Kenneth  after one week= total money Kenneth had in dollars - money spent in 7 days  = (5 - 7g/100 ) dollar

=  ((500 - 7g)/100 ) dollar

 

I would really appreciate it if you could help me please

Answers

Answer:

Yes, triangle GYK is similar to triangle BAK.

Step-by-step explanation:

The sides of each triangle are proportional to each other.

Take the longest side of each triangle. You are comparing line AK with line KY.

The proportion is 15/25.

Now, take the shortest side of each triangle. You are comparing line KB with GK.

The proportion is 6/10.

To determine if the triangles are proportional, we can see if the two proportions are equal to each other:

15/20=6/10

3/5=6/10

Correct! 3/5 equals to 6/10. Therefore, the two triangles are similar because their sides are proportional.

Hope this helps :)

Answer:

O  Yes!

Step-by-step explanation:

We would check whether the proportionality of their sides is equal

Taking proportionality

= [tex]\frac{6}{10} = \frac{15}{25}[/tex]

Cross Multiplying

6 × 25 = 15 × 10

150 = 150

So, ΔABK is similar to ΔGKY

Jiangsu divided 751.6 by 10 by the power of 2 and got a quotient of 0.7516. yesseinafhinks that the quotient should be7.516. Who is correct?

Answers

Answer:

yesseinafhinks

Step-by-step explanation:

Dividing by 10² is also the same thing as multiplying by 10^-2. In that case, we simply move the decimal places only 2 places back. That would give us 7.516, not 0.7516 (which is 3 times, not 2).

Help me please thank u

Answers

Answer:

4+3n

Step-by-step explanation:

We get the formula 4+3n because the pattern is +3 each term starting with the first term as 7. Since the first term is 7, we get 4+3n.

Paloma ran 3 /3/4 miles around the school track if each lap is a 1/2 mile how many laps she ran

Answers

Answer:

7.5 laps

Step-by-step explanation:

there are 6 laps for the 3 miles

1/2 mile is 2/4 which makes it 7 laps

1/4 is half of a lap so 7.5

Answer:

7.5 laps

Step-by-step explanation:

there are 6 laps for the 3 miles

1/2 mile is 2/4 which makes it 7 laps

1/4 is half of a lap so 7.5

Weekly demand for cell phones at a Best Buy store is normally distributed, with a mean of 300 and a standard deviation of 200. The supplier takes two weeks to supply a Best Buy order. Best Buy is targeting a CSL of 95 percent and monitors its inventory continuously. How much safety inventory of cell Chopra, Sunil. Supply Chain Management (What's New in Operations Management) (p. 346). Pearson Education. Kindle Edition.

Answers

Answer:

The amount of safety inventory of cell phones best  buy should carry is $465.277

Step-by-step explanation:

Solution

We recall that:

The weekly demand for cell phones=  300 per week

The Standard Deviation = 200 per week

The lead time or number of weeks = 2 weeks (14 days)

Thus,

Z = 95%

= 1.645

Now,

The standard deviation of lead time = Standard deviation√ *√ lead time

Which is

= 200 * √ (2) =2.82.843

So,

The safety inventory = Z * Standard deviation of the lead time

= 1.645 * 2.82.843

$465.277

In a large university, 70% of the students live in the dormitories. A random sample of 110 students is selected for a particular study.The probability that the sample proportion of students living in the dormitories falls in between 0.6 and 0.8 equals a.0.9780 b.0.9318 c.0.9365 d.1.6450

Answers

Answer:

The correct option is (a) 0.9780.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 [tex]\mu_{\hat p}=p[/tex]

The standard deviation of this sampling distribution of sample proportion is:

 [tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]

As the sample selected is quite large, i.e. n = 110 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample proportion by a Normal distribution.

The mean and standard deviation are:

[tex]\mu_{\hat p}=p=0.70\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.70(1-0.70)}{110}}=0.044[/tex]

Compute the probability that the sample proportion of students living in the dormitories falls in between 0.60 and 0.80 as follows:

[tex]P(0.60<\hat p<0.80)=P(\frac{0.60-0.70}{0.044}<\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}<\frac{0.80-0.70}{0.044})[/tex]

                              [tex]=P(-2.27<Z<2.27)\\\\=P(Z<2.27)-P(Z<-2.27)\\\\=0.98840-0.01160\\\\=0.9768\\\\\approx0.9780[/tex]

*Use a z-table.

Thus, the probability that the sample proportion of students living in the dormitories falls in between 0.60 and 0.80 is approximately equal to 0.9780.

The correct option is (a).

If Rob had average monthly expenses of $940.21 and his expenses in April were $945.50 and his expenses in May were $875.13, what were his expenses in June?

Answers

Answer:

  $1000

Step-by-step explanation:

If we assume that the given average applies to April, May, and June expenses, then we can use the formula for average to find June's expenses.

  average expenses = (April +May +June)/3

  940.21 = (945.50 +875.13 +June)/3

  (3)(940.21) = 1820.63 +June

  2820.63 -1820.63 = June = 1000.00

Rob's expenses in June were $1000.00.

Levi would like to use a credit card to make a $3000 purchase. He is considering two credit options. The first requires
a down payment of $1000 followed by monthly payments of $125. The second requires a down payment of $1300
followed by monthly payments of $110. The two options accumulate the same amount of interest and require the
same number of monthly payments.
What is the amount of interest for this loan?

Answers

Answer:

The amount of interest for this loan is 16.6%.

Step-by-step explanation:

Since Levi will make a purchase for $ 3000 with your credit card, you should explore the two options you have:

-On the one hand, a down payment of $ 1000, with fees of $ 125.

-on the other, a down payment of $ 1,300, with fees of $ 110.

In both cases, the fees are the same, and the interest too. Therefore, to determine the amount of installments and interest, the difference between the down payment of one option and the other must be taken and divided by the difference between the value of the installments of either option.

Thus, the difference of the down payment of 300 (1300 - 1000) must be divided by 15 (125 - 110). This yields a result of 20 (300/15), with which that will be the total of quotas until both have paid the same amount of money.

Thus, given that 1300 + 110 x 20 = 3,500, and that 1000 + 125 x 20 = 3,500, in both cases the total value to be paid is $ 3,500. Since 500 is 16.6% of 3000, the total purchase interest will be 16.6%.

2 = x-3, then x equals

Answers

Answer:

x = 5

Step-by-step explanation:

2 = x-3

Adding 3 to both sides

2+3 = x

5 = x

OR

x = 5

Answer:

[tex] \times = 2 + 3 \\ \\ x = 5[/tex]

The phone company Blurizon has a monthly cellular plan where a customer pays a flat
fee for unlimited voice calls and then a certain amount per GB of data used. If a
customer uses 12 GB, the monthly cost will be $105. If the customer uses 34 GB, the
monthly cost will be $237.

A) Find an equation in the form y = mx + b, where is the number of GB of data
used in a month and y is the total monthly cost of the Blurizon plan.
Answer: y =

B) Use your equation to find the total monthly cost if 14 GB are used.
Answer: If 14 GB are used, the total cost will be____
dollars.​

Answers

Answer:

(a)y=6x+33

(b)$117

Step-by-step explanation:

If a  customer uses 12 GB, the monthly cost will be $105.

If the customer uses 34 GB, the  monthly cost will be $237.

given that

x is the number of GB of data  used in a month; and y is the total monthly cost of the Blurizon plan.

We have the pairs: (12, 105) and (34, 237)

(A)To determine the straight-line equation, we first determine the slope, m.

[tex]m=\dfrac{237-105}{34-12}\\\\=\dfrac{132}{22}\\\\m=6[/tex]

Substitution into y = mx + b, we have: y=6x+b

Next, we determine the value of b

When y=105, x=12

105=6(12)+b

b=105-6(12)=33

Therefore, an equation in the form y = mx + b is:

y=6x+33

(B)

Total Cost, y=6x+33

When 14 GB are used, i.e. x=14

y=6(14)+33

y=$117

If 14 GB are used, the total cost will be 117 dollars.

26
Ping lives at the corner of 3rd Street and 6th Avenue. Ari
lives at the corner of 21st Street and 18th Avenue. There is
a gym į the distance from Ping's home to Ari's home.
24
22
20
n
Ari (21.18)
7
x =
18
(x2 – x) + x3
mi+n
16
Avenue
14
-- ( , Jive - y) +
12
10
Where is the gym?
00
6
Ping (36)
4
2
9th Street and 10th Avenue
12th Street and 12th Avenue
0 14th Street and 12th Avenue
15th Street and 14th Avenue
2
x
4 6 8 10 12 14 16 18 20 22 24 26
Street

Answers

Corrected Question

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym 2/3 the distance from Ping's home to Ari's home.  Where is the gym?

9th Street and 10th Avenue 12th Street and 12th Avenue 14th Street and 12th Avenue 15th Street and 14th Avenue

Answer:

(D)15th Street and 14th Avenue

Step-by-step explanation:

Ping's Location: (3rd Street, 6th Avenue)

Ari's Location: (21st Street, 18th Avenue)

The gym is at point P which is [tex]\dfrac{2}{3}[/tex] the distance from Ping's home to Ari's home.

That is, Point P divides the line segment in the ratio 2:1.

We use the section formula:

[tex](x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)[/tex]

m:n=2:1, [tex](x_1,y_1)=(3,6), (x_2,y_2)=(21,18)[/tex]

[tex]=\left(\dfrac{2*21+1*2}{2+1}, \dfrac{2*18+1*6}{2+1}\right)\\=\left(\dfrac{45}{3}, \dfrac{42}{3}\right)\\=(15,14)[/tex]

The gym is located at 15th Street and 14th Avenue.

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Answers

please see the attached picture...

Hope it helps...

Good luck on your assignment.....

Answer:

The answers are

Step-by-step explanation:

7 X -3 = -21

24/ -12= -2

(a) A company that makes crayons is trying to decide which colors to include in a promotional mini-box of crayons. The company can choose the mini-box colors from its collection of colors. How many mini-boxes are possible?

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The number of color are possible  [tex]\left n} \atop }} \right. C _r = 1215450[/tex]

Step-by-step explanation:

From the question we are told that  

   The number of  colors is  r = 4

    The sample size n =  75

The number of color that are possible can be mathematically evaluated as

       [tex]\left n} \atop }} \right. C _r = \frac{n !}{ (n-r)! r!}[/tex]

substituting values

         [tex]\left n} \atop }} \right. C _r = \frac{75 !}{ (75-4)! 4!}[/tex]

       [tex]\left n} \atop }} \right. C _r = \frac{75 !}{ (71)! 4 !}[/tex]

       [tex]\left n} \atop }} \right. C _r = \frac{75 *74 * 73* 72 * 71!}{ (71)! (4*3*2 *1)}[/tex]

        [tex]\left n} \atop }} \right. C _r = 1215450[/tex]

   

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