The light bulb must burn for approximately 46.2 minutes to use the same amount of energy as the car lost during its deceleration.
Consider a 5,000-pound vehicle at 35 mph to illustrate energy loss in an automobile. When the automobile stops, its kinetic energy is transformed into heat and sound, resulting in a large energy loss. We use a 100-Watt light bulb to understand this loss.
The car's initial kinetic energy is [tex]KE = 0.5 * mass * velocity^2[/tex]. Next, we calculate 100-Watt light bulb energy usage per second. Finally, we divide the automobile's kinetic energy by the light bulb's energy consumption per second to determine the time needed for the light bulb to use the same amount of energy as the car.
The light bulb must burn for 46.2 minutes to utilise as much energy as the automobile lost during deceleration. This striking depiction illustrates the significant energy waste required in halting a moving automobile and emphasises energy conservation and efficient transportation systems.
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Faults, folding ridges, mountains, valleys and volcanic arc are formed when the plates move because ????
Plate tectonics can result in the formation of faults, folding ridges, mountains, valleys, and volcanic arcs, among other geological features.
Plate tectonics is the scientific theory that explains how the Earth's lithosphere (its solid outermost layer) is broken up into several large plates that move relative to each other over the underlying asthenosphere (its partially molten layer). When plates move, they can interact with one another in a variety of ways, including colliding, spreading apart, and sliding past one another. Depending on the type of interaction and the characteristics of the plates involved, these interactions can produce a wide range of geological features.When plates move apart, magma from the earth's mantle can arise to fill the gap, forming new crust and forming mid-ocean ridges like the Mid-Atlantic Ridge. This is referred to as seafloor spreading.
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Auto companies frequently test the safety of automobiles by putting them through crash tests to
observe the integrity of the passenger compartment. If a 2000. -kg car is sent toward a cement wall
with a speed of 14 m/s and the impact brings it to a stop in 4. 00 X 10^-2 s, with what average
force is it brought to rest?
The average force acting on the car as it comes to a stop is [tex]7.00 \times 10^5 N.[/tex]
We can use the equation for average force, which is:
average force = change in momentum / time
To use this equation, we first need to find the change in momentum of the car. We can use the equation:
change in momentum = final momentum - initial momentum
The initial momentum of the car is:
p1 = m1 × v1
where m1 is the mass of the car (2000 kg) and v1 is the initial velocity (14 m/s).
p1 = (2000 kg)(14 m/s) = 28,000 kg × m/s
The final momentum of the car is zero, since it comes to a stop.
p2 = 0
So the change in momentum is:
Δp = p2 - p1 = -28,000 kg × m/s
Now we can substitute these values into the equation for average force:
average force = Δp / t
where t is the time it takes for the car to come to a stop[tex](4.00 \times 10^{-2} s).[/tex]
average force =[tex](-28,000 kg\times m/s) / (4.00 \times 10^{-2} s)[/tex]
average force =[tex]- 7.00 \times 10^5 N[/tex]
The negative sign indicates that the force is acting in the opposite direction to the motion of the car. We could also take the magnitude of the force, which would be:
|average force| = [tex]7.00 \times 10^5 N[/tex]
Therefore, the average force acting on the car as it comes to a stop is [tex]7.00 \times 10^5 N.[/tex]
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A uniform bar, of mass M, with seven evenly spaced holes is held by sliding the bar over a horizontal peg through one of the seven holes. The peg passes through hole C, and a cylinder hangs from a hook placed through hole B as shown above. The mass of the bar is equal to the mass of the cylinder, and the location of the center of mass of the bar is at the center of hole D. In this configuration, the bar-cylinder system remains motionless but is free to rotate around the peg in hole C. Frictional forces acting on the bar are negligible. In a clear, coherent paragraph-length response that may also contain equations, explain why the bar does not rotate in this configuration.
Please help!
The torques due to the weights of the bar and the cylinder are balanced, and the bar-cylinder system remains motionless and does not rotate around the peg in hole C.
What is COM?The bar-cylinder system does not rotate around the peg in hole C because it is in equilibrium. The torque on the system due to the weight of the cylinder hanging from hole B is balanced by the torque on the system due to the weight of the bar and its distribution around the center of mass at hole D. The center of mass is located such that the torques due to the weights of the bar and the cylinder are equal and opposite, and hence the net torque on the system is zero.
Mathematically, we can express this equilibrium condition as:
T_cylinder = T_bar
The torque due to the weight of the cylinder is given by:
T_cylinder = r_CB * F_cylinder
Similarly, the torque due to the weight of the bar is given by:
T_bar = r_CD * F_bar
where r_CD is the distance between the peg at hole C and the center of mass at hole D, and F_bar is the weight of the bar.
Since the mass of the bar is equal to the mass of the cylinder, we have:
F_cylinder = F_bar = Mg
where M is the mass of the bar and cylinder, and g is the acceleration due to gravity.
Substituting the above equations into the equilibrium condition, we get:
r_CB * Mg = r_CD * Mg
which simplifies to:
r_CB = r_CD
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1. Identify What is gravity? What determines the gravitational force between objects?
Answer:
Gravity:
It is defined as the force that pulls a body towards the centre of the earth, or towards any other body having mass.
Existence:
We cannot see it with the eye, but that doesn't mean it doesn't exist. After all, we see the effects of gravity. It is the reason why things on Earth fall down while objects in space float around because there is no gravity in space
Determining:
When dealing with gravity between two objects, there are only two things that are important
1. Mass
2. Distance
The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.
So we can write
Gravity is directly proportional to sum of masses of the body. More mass of object, more gravitational pull
And inversely proportional to square of distance between there centre. If the body is close to Earth's surface, more gravity and if away from the surface, less gravity
Hope you understand
I would appreciate if you mark my answer brainliest :)
Find the altitude of Earth’s geostationary orbit.
The mass of the Earth is 5.97 x 1024 kg.
The radius of Earth is 6.38 x 106 m.
Altitude of Earth's geostationary orbit is approximately 35,786 km above the surface of the Earth.
What is Geostationary?
Geostationary refers to an object in orbit around the Earth that appears to remain fixed in the same position above the Earth's surface. Specifically, a geostationary orbit is an orbit in which a satellite orbits the Earth at the same rate that the Earth rotates, so that the satellite appears to remain stationary relative to a fixed point on the Earth's surface.
The altitude of Earth's geostationary orbit can be found using the formula:
h = R(3/2) * √(M/m)
where:
h is the altitude of the geostationary orbit
R is the radius of the Earth
M is the mass of the Earth
m is the mass of the satellite
For a geostationary orbit, the satellite has a period of 24 hours, which means it orbits the Earth once every 24 hours. This requires the satellite to be at an altitude where its orbital period matches the Earth's rotational period, and this altitude is known as the geostationary orbit.
For a geostationary satellite, the mass of the satellite is negligible compared to the mass of the Earth, so we can assume that m is much smaller than M.
Plugging in the given values, we get:
h = (6.38 x 10^6 m) * (3/2) * √(5.97 x 10^24 kg / m)
h = 35,786 km
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Calculate the potential energy, kinetic energy, mechanical energy, velocity, and height of the 45 kg object at various locations as shown on the diagram below.
The potential energy at each point:
PE₁ = 1764 J
PE₂ = 1323 J
PE₃ = 0 J
PE₄ = 441 Jh
The kinetic energy at each point:
KE at point 1 = 0KE at point 2 = 1764 - 1323 JKE at point 2 = 441 JKE at point 3 = 1764 JKE₄ = 1219.7 JTo find the mechanical energy at each point:
ME₁ = 1764 JME₂ = 1764 JME₃ = 1764 JME₄ = 1764 JThe height at point 4, h = 1.23 m
What are the potential energy, kinetic energy, and mechanical energy of the object at each point?
To calculate the potential energy, kinetic energy, and mechanical energy of the object at each point, we will need to use the following formulas:
Potential energy (PE) = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height above a reference point.
Kinetic energy (KE) = 0.5mv^2, where m is the mass of the object and v is its velocity.
Mechanical energy (ME) = PE + KE
Given:
Mass of the object (m) = 45 kg
Point 1: h = 4 m
Point 2: h = 3 m
Point 3: h = 0 m
Point 4: v = 5.2 m/s
To find the potential energy at each point:
PE₁ = mgh1 = 45 kg x 9.8 m/s^2 x 4 m
PE₁ = 1764 J
PE₂ = mgh2 = 45 kg x 9.8 m/s^2 x 3 m
PE₂ = 1323 J
PE₃ = mgh3 = 45 kg x 9.8 m/s^2 x 0 m
PE₃ = 0 J
PE₄ = mgh4 = 45 kg x 9.8 m/s^2 x h
PE₄ = 441 Jh
KE at point 1 = 0
KE at point 2 = 1764 - 1323 J
KE at point 2 = 441 J
KE at point 3 = 1764 J
To find the kinetic energy at point 4:
KE₄ = 0.5mv^2 = 0.5 x 45 kg x (5.2 m/s)^2
KE₄ = 1219.7 J
To find the mechanical energy at each point:
ME₁ = PE₁ + KE
ME₁ = 1764 J + 0 J = 1764 J
Since the mechanical energy is conserved (ignoring friction and air resistance), we can set ME₁ = ME₂ = ME₃ = ME₄
Solving for h:
ME₁ = ME₄
1764 J = 441 Jh + 1219.7 J
h = (1764 J - 1219.7 J) / (441 J)
h = 1.23 m
Therefore, at point 4, the object has a velocity of 5.2 m/s and a height of 1.23 m.
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Find the work done by a force F = 4i − 3j + 2k that moves an object from the point (3, 2, -1) to the point (2, -1, 4) along a straight line. The distance is measured in meters and the force in newtons.
Answer:
15 N
Explanation:
work done by the force in vector form is given by the equation,
[tex]W = \vec{F}.\delta \vec{r}[/tex]
where . represents the dot product.
in the given question,
[tex]F = 4i - 3j + 2k[/tex]
and
[tex]\delta \vec{r} = (2 - 3)i + (-1 - 2)j + (4 - (-1))k[/tex]
[tex]\delta \vec{r} = -i - 3j + 5k[/tex]
on doing the dot product we get
[tex]W = -4 + 9 + 10\\W = 15[/tex]
Hopefully this answer helped you.
What is the term used to describe the maximum distance that a sound wave displaces air molecules from their original undisturbed position?
The term used to describe the maximum distance that a sound wave displaces air molecules from their original undisturbed position is called the amplitude
The term used to describe the maximum distance that a sound wave displaces air molecules from their original undisturbed position is called the amplitude of the sound wave. Amplitude refers to the magnitude of the wave's displacement and is typically measured in decibels (dB).
The higher the amplitude of a sound wave, the louder the sound will be perceived by our ears. The amplitude of a sound wave is determined by the amount of energy that the sound wave carries. A sound wave with a higher amplitude will have more energy and thus will displace air molecules more strongly than a sound wave with a lower amplitude.
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Hhhhhhhhhhhhhhhhhhhhjj
Answer:
grrr I don't know either grrr
Calculate the wavelength for a sound wave with a frequency of 485 Hz. That has a sound wave in air has a frequency of 420 Hz
The wavelength for a sound wave with a frequency of 485 Hz. That has a sound wave in the air has a frequency of 420 Hz is 70.7cm and 81.7cm.
Wavelength = speed of sound/frequency
The speed of sound is approximately 343 meters per second.
For a sound wave with a frequency of 485 Hz, the wavelength would be:
wavelength = 343 m/s / 485 Hz = 0.707 m or 70.7 cm
For a sound wave in air with a frequency of 420 Hz, the wavelength would be:
wavelength = 343 m/s / 420 Hz = 0.817 m or 81.7 cm.
Wavelength is a fundamental concept in physics that refers to the distance between two consecutive points on a wave that is in phase, meaning that they are at the same point in their respective cycles. It is usually denoted by the Greek letter lambda (λ).
Wavelength is an important property of all types of waves, including electromagnetic waves (such as light), sound waves, and even waves in water. In general, the wavelength of a wave is inversely proportional to its frequency, which is the number of cycles that occur per unit of time. This means that waves with a higher frequency have a shorter wavelength, while waves with a lower frequency have a longer wavelength.
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1. Rohan always prefer to go by bicycle instead of using his car to go nearby places .
(a) why do you think he prefers to go by a cycle ?
(b) is Rohan act environment friendly ? What can you learn from him ?
Answer:
(b) Yes, Rohan's act of using a bicycle instead of a car is environmentally friendly, as it reduces carbon emissions and promotes sustainable transportation. From him, we can learn the importance of making conscious choices that have a positive impact on the environment and our health. We can also learn that small actions, such as choosing to cycle instead of drive, can make a significant difference in reducing our carbon footprint and promoting a more sustainable future.
Ronaldo or Messi? Who is better?
Answer:
In my opinion, Ronaldo
Explanation:
Ronaldo, who holds the record for most Champions League goals of all time, leads Messi by one on that trophy count. Messi, meanwhile, has a greater number of domestic cups and league titles.
What do you think?
Answer:
In my opinion, it's Christiano Ronaldo. But why is Ronaldo better than Messi?
Explanation:
Ronaldo is a more complete player.
His ability to jump and head balls was flawless. Ronaldo is such a complete player, emphasising his complete nature, that he is dangerous in every minute of the game. This is demonstrated by him being the first player in football history to score in every minute of a 90-minute game.
A man has a mass of 60. 1 kilograms. He jumps from the ground onto a 177 meter building and then dives off of it and comes to a rest at the bottom of a 18. 5 meter excavation. By how much will gravitational energy change in joules?
The change in gravitational potential energy is approximately 93,640 joules.
The change in gravitational potential energy can be calculated using the formula, ΔPE = mgΔh, where ΔPE is the change in gravitational potential energy, m is the mass of the man, g is the acceleration due to gravity, and Δh is the change in height.
The change in height, Δh = 177 m + (-18.5 m) = 158.5 m.
The mass of the man is given as 60.1 kilograms, and the acceleration due to gravity is approximately 9.81 meters per second squared. The change in gravitational potential energy.
ΔPE = (60.1 kg)(9.81 m/s^2)(158.5 m) ≈ 93,640 J
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Very far from earth (at R=infinity), a spacecraft has run out of fuel and its kinetic energy is zero. If only the gravitational force of the earth were to act on it (i. E. , neglect the forces from the sun and other solar system objects), the spacecraft would eventually crash into the earth. The mass of the earth is Me and its radius is Re. Neglect air resistance throughout this problem, since the spacecraft is primarily moving through the near vacuum of space.
a. Find the speed Se of the spacecraft when it crashes into the earth.
Express the speed in terms of Me, Re, and the universal gravitational constant G.
b. Now find the spacecraft’s speed when its distance from the center of the earth is R=αRe, where α >=1. Express the speed in terms of Se and α.
a. The speed Se of the spacecraft when it crashes into the earth is approximately 11.2 km/s.
b. The spacecraft's speed when its distance from the center of the earth is R = αRe is Se / √(α).
a. To find the speed Se of the spacecraft when it crashes into the earth, we can use the law of conservation of energy. At R = infinity, the spacecraft has zero kinetic energy and potential energy, so its total mechanical energy is zero. As it falls towards the earth, the potential energy decreases while the kinetic energy increases. At the moment of impact, all of the potential energy has been converted to kinetic energy.
Using the law of conservation of energy, we have:
[tex]0 = 1/2 mv^2 - GM_em/r[/tex]
where m is the mass of the spacecraft, v is its speed at impact, G is the universal gravitational constant, and r is the distance from the center of the earth to the spacecraft at impact.
We can rearrange this equation to solve for v:
[tex]v = \sqrt{(2GM_e/r)}[/tex]
Substituting the values for G, M_e, and r, we get:
[tex]v = \sqrt{(2 \times 6.6743 \times 10^{-11} m^3/kg s^2 \times 5.97 \times 10^{24} kg / 6.38 \times 10^6 m)}[/tex]
[tex]v = 11.2 km/s[/tex]
Therefore, the speed Se of the spacecraft when it crashes into the earth is approximately 11.2 km/s.
b. To find the spacecraft's speed when its distance from the center of the earth is R = αRe, we can use conservation of energy again. The spacecraft still has zero kinetic energy and potential energy at R = infinity, so we can use the same equation as before:
[tex]0 = 1/2 mv^2 - GM_em/r[/tex]
But now r = αRe, so we can solve for v in terms of Se and α:
v = √(2GM_e/αRe)
Substituting the value of [tex]GM_e[/tex] from before and simplifying, we get:
v = Se / √(α)
Therefore, the spacecraft's speed when its distance from the center of the earth is R = αRe is Se / √(α).
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A charge of 6.5 x 10-5 C is attracted by another charge with a force of 250 N when
they are separated by 0.15 m. Find the magnitude of the other charge.
8.65 X 105 C
9.62 × 10-2 C
6.15 x 10-6 C
O 9.62 x 10 c
Answer:
We can use Coulomb's law to solve this problem:
F = k * q1 * q2 / r^2
where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.
We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:
q2 = F * r^2 / (k * q1)
Substituting the values we have:
q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)
Simplifying:
q2 = 8.65 x 10^5 C
Therefore, the magnitude of the other charge is 8.65 x 10^5 C.
which of the following energy sources is not derived directly or indirectly from solar energy? responses biomass biomass geothermal geothermal hydroelectric hydroelectric wind
The energy source that is not derived directly or indirectly from solar energy is geothermal energy.
Geothermal energy is a type of energy that is generated from heat in the Earth's crust. This heat comes from the Earth's molten core, which is heated by nuclear reactions. Geothermal energy is generated in hot springs, geysers, and volcanoes, and is used to produce electricity by harnessing the energy of hot water and steam.Biomass energy is a renewable energy source that is derived from organic matter, such as wood, crops, and waste materials. Biomass is burned to produce energy, and is often used to power homes and businesses. Hydroelectric energy is generated by harnessing the power of water, which is usually done by building dams and using the energy of falling water to turn turbines. Wind energy is generated by harnessing the power of the wind, which is done by using wind turbines to capture the energy of the wind and turn it into electricity. All of these energy sources are derived directly or indirectly from solar energy, since the sun is responsible for heating the Earth's atmosphere and creating weather patterns that generate wind and precipitation.
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an investigator is measuring the current in a photoelectric effect experiment. the cathode is illuminated by light of a single wavelength. what happens to the current if the wavelength of the light is reduced by a factor of two while keeping the intensity constant?
When the wavelength of light is reduced by a factor of two while keeping the intensity constant, the current in a photoelectric effect experiment decreases by a factor of two. In this case, the kinetic energy of photoelectrons ejected from the cathode would also decrease by a factor of two.
What is the photoelectric effect? The photoelectric effect is the phenomenon of the emission of electrons from a metal surface upon the absorption of light. The photoelectric effect is important in the field of physics as it provides evidence that light behaves as both a wave and a particle.
The energy of the ejected electrons depends on the frequency of the incident light and the work function of the metal, which is a measure of how tightly the electrons are held by the metal. If the frequency of the light is above the threshold frequency of the metal, photoelectrons will be emitted.
What happens when the wavelength of light is reduced by a factor of two? We know that the kinetic energy of the photoelectrons is given by K = hf - φ, where
h is Planck's constant,
f is the frequency of the light,
and φ is the work function of the metal.
In this formula, we can see that the kinetic energy of the photoelectrons is directly proportional to the frequency of the light. When the frequency of the light is reduced by a factor of two, the kinetic energy of the photoelectrons is also reduced by a factor of two.
Since the current is directly proportional to the number of photoelectrons emitted per second, which is proportional to the kinetic energy of the photoelectrons, the current will also decrease by a factor of two.
Therefore, when the wavelength of the light is reduced by a factor of two while keeping the intensity constant, the current in a photoelectric effect experiment decreases by a factor of two.
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A kickball is struck with a 15.2 m/s velocity at a 63 degree angle. It lands on a rooftop 2.4 s later. How high is the roof?
Answer:
the height of the rooftop is approximately 16.4 meters or about 54 feet high.
Explanation:
To solve this problem, we need to use the kinematic equations of motion. We will assume that air resistance is negligible and that the acceleration due to gravity is -9.8 m/s^2.
First, we will use the initial velocity and angle of the kickball to find its horizontal and vertical components of velocity.
The horizontal component of velocity (Vx) can be found using the equation:
Vx = V * cos(theta)
where V is the initial velocity and theta is the angle of the kickball.
Vx = 15.2 m/s * cos(63 degrees)
Vx = 6.62 m/s
The vertical component of velocity (Vy) can be found using the equation:
Vy = V * sin(theta)
Vy = 15.2 m/s * sin(63 degrees)
Vy = 13.7 m/s
Next, we can use the vertical component of velocity to find the maximum height (h) reached by the kickball. We can use the following kinematic equation:
h = Vy^2 / (2 * g)
where g is the acceleration due to gravity.
h = (13.7 m/s)^2 / (2 * 9.8 m/s^2)
h = 9.47 meters
So, the maximum height reached by the kickball is 9.47 meters.
Finally, we can use the time it takes for the kickball to land on the rooftop to find the height (d) of the rooftop. We can use another kinematic equation:
d = Vy * t + 0.5 * g * t^2
where t is the time it takes for the kickball to land on the rooftop.
d = 13.7 m/s * 2.4 s + 0.5 * (-9.8 m/s^2) * (2.4 s)^2
d = 16.4 meters
Therefore, the height of the rooftop is approximately 16.4 meters or about 54 feet high.
Determining the distance to stars can be challenging. The parallax method is one way of finding the distance to many stars around us. Your research team measures the parallax of two stars that have a distance of 5 degrees from each other in the night sky: The first star has a parallax of 0.11 arcsec, and the second has a parallax of 0.13 arcsec. How far apart are the two stars from each other? Express your answer in light-years
A boat accelerates from 8.5 m/s west to 1.8 m/s west at a rate of 2.9 m/s^2 east. How far does it travel
The distance traveled while accelerating can be found by multiplying the average velocity by the time taken to accelerate
Complete question:
A boat accelerates from 8.5 m/s west to 1.8 m/s west at a rate of 2.9 m/s^2 east. How far does it travel while accelerating?
Computation of DistanceThe average velocity is the difference between the initial and final velocities, divided by two. The time taken to accelerate is the difference between the initial and final velocities, divided by the rate of acceleration.
Given Data
Average velocity = (8.5 m/s - 1.8 m/s) / 2 = 3.35 m/sTime taken to accelerate = (8.5 m/s - 1.8 m/s) / 2.9 m/s^2 = 2.03 swe know that the expression for computing distance is given as
Distance traveled while accelerating = Average velocity * Time taken to accelerate
Substituting our data in the expression we have
Distance traveled while accelerating = 3.35 m/s * 2.03 s = 6.80 m
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How do you find the spring constant with this data?
The spring constant with the given data on the period v. mass can be found to be 1. 86.
What is the spring constant ?The spring constant, also known as the force constant or spring stiffness, is a measure of the stiffness of a spring. It is denoted by the letter k and is defined as the amount of force required to stretch or compress a spring by a certain distance (usually measured in meters or centimeters).
When given on a graph, the spring constant is the slope of the line in the graph. The slope of the given line would be the constant that multiplies the independent variable ( x ) which in this case is 1. 86 from the formula :
Period ( s ²) = 1. 86x + 0.0545
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Which uses direct current?
A) A toaster oven thingy (look at pic)
B) A flashlight (look at pic)
C) A microwave (look at pic)
D) A vacuum (look at pic)
The correct answer is Option- B: A flashlight uses direct current (DC).
Direct current (DC) is one-directional flow of electric charge. An electrochemical cell is a prime example of DC power. Direct current may flow through a conductor such as a wire, but can also flow through semiconductors, insulators, or even through a vacuum as in electron or ion beams.
Electric current flows in two ways as an alternating current (AC) or direct current (DC). The main difference between AC and DC lies in the direction in which the electrons flow. In DC, the electrons flow steadily in a single direction, while electrons keep switching directions, going forward and then backwards in AC.Thus,The correct answer is Option- B: flashlight.
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A charge of 6. 00mc is placed at each corner of a square 0. 100m on a side. Determine the magnitude and direction of the force on each charge. (hint: only solve for one charge, you should notice that the magnitude is the same for all charges. )
3.24 x [tex]10^{-2}[/tex] N is the force acting on each charge.
We can use Coulomb's law to determine the magnitude and direction of the force on each charge. Coulomb's law states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Let's assume that we are calculating the force on one of the charges located at a corner of the square. The distance between two adjacent charges is 0.1m, and the charge on each corner is 6.00mc, which is 6.00 x [tex]10^{-6}[/tex] C.
Using Coulomb's law, we can calculate the magnitude of the force on one charge as:
F = kq₁q₂/r²
where k is the Coulomb constant (9 x [tex]10^{9}[/tex] N m²/C²), q₁and q₂ are the charges, and r is the distance between the charges.
If we plug in the values, we get:
F = (9 x [tex]10^{9}[/tex] N m²/C²) * (6.00 x[tex]10^{-6}[/tex] C)² / (0.1m)²
F = 3.24 x [tex]10^{-2}[/tex] N
So the magnitude of the force on each charge is 3.24 x [tex]10^{-2}[/tex] N, and the direction of the force is towards the other charges located at the corners of the square. Since the charges are all the same, the direction of the force will be towards the center of the square.
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Hypothesis of experiment of a focal length of a concave lens?
Variables?
The right choice is C) [tex]\frac{1}{v} +\frac{1}{u} =\frac{1}{f}[/tex] which is the equation that relates u and v
[tex]\frac{1}{u} = \frac{1}{f} - \frac{1}{v}[/tex]
The slant of this curve can be found by differentiation [tex]-\frac{1}{u^2} du = 0 + \frac{dv}{v^2} \\[/tex]
⇒ [tex]\frac{dv}{du} = - \frac{v^2}{u^2}[/tex]
[tex]\frac{dv}{du}[/tex] is the slant which is negative so either curve (c) or curve (a) is correct. Presently the incline relies on the worth of u and v for example it continues to change at each point according to the equation above. So figure (c) is the response.
A convex spherical mirror likewise has a focal point. Occurrence beams lined up with the optical pivot are reflected from the mirror and appear to begin from point F at focal length f behind the mirror. Subsequently, the focal point is virtual in light of the fact that no genuine beams really go through it; they just seem to start from it.
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the complete question is:
In an experiment to find the focal length of a concave mirror, a graph is drawn between the magnitudes of u and v. The graph looks like this:
refer to the attachment for the graph
A car traveling with an initial speed of 25 m/s decelerates at −5 m/s2 to a complete stop. What best approximates the distance the car travels during its deceleration?
What term best describes the regular path of a spacecraft or other object around a planetary body?
a. Cycle
b. Orbit
c. Rotation
d. Spin
Answer:
Explanation:
b. orbit
Describe three ways you can lower the intensity of sound from a speaker, at a rock concert. Refer to the equations learnt in lesson for two of them.
Reduce the volume: Reducing the volume is one of the simplest ways to lessen the sound intensity coming a speaker. As you move farther away from the source of the sound, the intensity of the sound also diminishes.
What level of volume is there at a rock concert?Nonetheless, regardless of the location, a rock concert can be quite loud. Decibel levels during rock concerts often range from 90 to 120 dB. This decibel level is alarming since it could endanger your ability to hear.
What causes a sound's strength to lessen?The intensity of the sound is proportional to the square of the distance from the source of the sound wave. The strength of a sound wave depends on whether it travels through a two-dimensional or three-dimensional medium to carry its energy.
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 Two trumpet players are riding in separate convertibles which are moving in opposite directions at a speed of 30 m/s. They both strike a note with a frequency of 1024 Hz Calculate:
(A). The pitch heard coming from one vehicle by a listener of the other vehicle.
(B). The pitch heard coming from either vehicle by an observer stationed directly between both vehicles.
(C). The pitch heard by a listener in either vehicle if both vehicles turn around and move toward each other at the same speeds.
How long will it take a runner to complete a marathon race of 42. 2 km if that runner can maintain an average speed of 4. 1 m/s?
It would take the runner approximately 10,268.29 seconds (or about 2 hours, 51 minutes, and 8 seconds) to complete a marathon race of 42.2 km, maintaining an average speed of 4.1 m/s.
We can use the formula:
time = distance ÷ speed
to calculate the time it would take the runner to complete a marathon race of 42.2 km, given an average speed of 4.1 m/s.
First, we need to convert the distance to meters, as the speed is given in meters per second:
42.2 km = 42,200 m
Now, we can substitute the values into the formula:
time = distance ÷ speed
time = 42,200 m ÷ 4.1 m/s
time ≈ 10,268.29 s
Thus the time that the runner would take is 10,268.29 seconds to complete a marathon race.
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To test the performance of its tires, a car travels along a perfectly flat (no banking) circular track of radius 179 m. The car increases its speed at uniform rate of
until the tires start to skid.
If the tires start to skid when the car reaches a speed of 29. 7 m/s, what is the coefficient of static friction between the tires and the road?
The acceleration of gravity is 9. 8 m/s^2
The coefficient of static friction between the tires and the road is approximately 0.252
The maximum speed that a car can travel without skidding is determined by the maximum force of static friction that the tires can exert on the road. The formula for this maximum force of static friction is:
f_s = m × g × μ_s
where f_s is the force of static friction, m is the mass of the car, g is the acceleration due to gravity (9.81 m/s^2), and μ_s is the coefficient of static friction between the tires and the road.
When the car reaches a speed of 20 m/s, it is moving in a circular path of radius 139 m. The centripetal force required to keep the car moving in this circular path is given by:
f_c = m × v^2 / r
where f_c is the centripetal force, m is the mass of the car, v is the speed of the car, and r is the radius of the circular path.
At the point where the tires start to skid, the maximum force of static friction is equal to the centripetal force required to keep the car moving in the circular path:
f_s = f_c
Substituting the formulas for f_s and f_c and solving for μ_s, we get:
m × g × μ_s = m × v^2 / r
μ_s = v^2 / (g × r)
We are given that the car increases its speed at a uniform rate of 5.26 m/s^2. We can use the formula for uniform acceleration to find the time it takes for the car to reach a speed of 20 m/s:
v = u + a × t
20 = 0 + 5.26 × t
t = 20 / 5.26 = 3.8 s
Using this time, we can find the distance traveled by the car before the tires start to skid:
s = u × t + 1/2 × a × t^2
s = 0 + 1/2 × 5.26 × (3.8)^2
s = 36.6 m
Now we can substitute the given values into the formula for μ_s:
μ_s = v^2 / (g × r)
μ_s = (20)^2 / (9.81 × 139)
μ_s = 0.252
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