Notice that the electromagnet in the virtual simulation is made up of a battery and a wire. What item could you add to the electromagnet to make it even stronger?

Answers

Answer 1

Answer:

Explanation:

Have y’all seen steeleflag19 at all on here?


Related Questions

Which exerts more force, the Earth pulling on the moon or the moon pulling on the Earth? Explain.​

Answers

Answer: the earth

Explanation: Earth exerts a gravitational pull on the moon 80 times stronger than the moon's pull on the Earth. Over a very long time, the moon's rotations created fiction with the Earth's tugging back, until the moon's orbit and rotational locked with Earth.

and that's why the earth pulls the moon

Find the angle between the two unitless vectors: F1 = 8.92 i + 17.37 j F2 = 12.44 i + 7.11 j Answer in degrees, and to the fourth decimal place.

Answers

Answer:

θ = 33.0705°

Explanation:

The angle between the two vectors is given by the formula;

Cos θ = (F1 • F2)/(|F1| × |F2|)

We are given;

F1 = 8.92i + 17.37j

F2 = 12.44i + 7.11j

Thus;

Cos θ = [(8.92i + 17.37j) • (12.44i + 7.11j)]/[√(8.92² + 17.37²) × √(12.44² + 7.11²)]

Cos θ = (110.9648 + 123.5007)/(19.5265 × 14.3285)

Cos θ = 0.8380

θ = cos^(-1) 0.8380

θ = 33.0705°

What is the key for a successful relationship? and Why?

Answers

Answer:

communication, if you don't talk you'll never know what's going on.

Explanation:

Why do you feel that you are being thrown upward out of your seat when going over an arced hump on a roller coaster

Answers

Answer: The options are not given.

Here are the options.

a) There is an additional force lifting up on you.

(b) At the top you continue going straight and the seat moves out from under you.

(c) You press on the seat less than when the coaster is at rest.Thus the seat presses less on you. (

d) Both b and c are correct.

(e) a, b, and c are correct.

The correct option Is D.

B.At the top you continue going straight and the seat moves out from under you. C.At the same time, you press on the seat less than when the coaster is at rest because the normal force expirienced will be less.

Explanation:

At the top you continue going straight and the seat moves out from under you.At the same time, you press on the seat less than when the coaster is at rest because the normal force expirienced will be less because it is as a result of a phenomenon called Weightlessness. This occur when there is no force or little force is acting on your body. At the top you continue going straight and the seat moves out from under you because there is no force acting on your body and when the body is in free fall i.e acceleration due to gravity , the person is not supported by any thing at.

That is the scenarion that occur...

What is the change in internal energy (in J) of a system that absorbs 0.523 kJ of heat from its surroundings and has 0.366 kcal of work done on it

Answers

Answer:

The change in internal energy of the system is 2,054 J

Explanation:

The first law of thermodynamics relates the work and the transferred heat exchanged in a system through internal energy. This energy is neither created nor destroyed, it is only transformed.

Taking into account that the internal energy is the sum of all the energies of the particles that the system has, you have:

ΔU= Q + W

where U is the internal energy of the system (isolated), Q is the amount of heat contributed to the system and W is the work done by the system.

By convention, Q is positive if it goes from the environment to the system, or negative otherwise, and W is positive if it is carried out on the system and negative if it is carried out by the system.

In this case:

Q= 0.523 kJ (because the energy is absorbed, this is,it goes from the environment to the system)W= 0.366 kcal= 1.531 kJ  (because the work is done on the system, and being 1 kcal= 4.184 kJ)

Replacing:

ΔU= 0.523 kJ + 1.531 kJ

Solving:

ΔU= 2.054 kJ = 2,054 J (being 1 kJ=1,000 J)

The change in internal energy of the system is 2,054 J

In a lightning bolt, a large amount of charge flows during a time of 1.2 x 10-3 s. Assume that the bolt can be represented as a long, straight line of current. At a perpendicular distance of 21 m from the bolt, a magnetic field of 8.4 x 10-5 T is measured. How much charged has flowed during the lightning bolt?

Answers

Answer: 10.58 C has flowed during the lightning bolt

Explanation:

Given that;

Time of flow t = 1.2 × 10⁻³

perpendicular distance r = 21 m

Magnetic field B = 8.4 x 10⁻⁵ T

Now lets consider the expression for magnetic field;

B = u₀I / 2πr

the current flow is;

I = ( B × 2πr ) / u₀

so we substitute

I = ( (8.4 x 10⁻⁵) × 2 × 3.14 × 21 ) / 4π ×10⁻⁷

=  0.01107792 / 0.000001256

= 8820 A

Hence the charge flows during lightning bolt  will be;

q = It

so we substitute

q = 8820 × 1.2 × 10⁻³

q = 10.58 C

therefore 10.58 C has flowed during the lightning bolt

Define reflection of sound?​

Answers

The reflection of sound is the movement of sound waves bouncing off of a surface and back into another direction, hope this helped :)

Describe four ways in which improving your muscular fitness would have a positive affect in your life

Answers

Body image, strength, looks, and healthy lifestyle

Four ways in which improving our muscular fitness would have a positive affect on our lives are given below:

Injury preventionBody compositionChronic disease prevention.Lifetime muscle and bone health

Muscular fitness

Muscle fitness simply means having muscles that can lift heavier objects or muscles that will work longer before becoming exhausted.

It helps us improves when a person does activities that build or maintain muscles or that increase how long a person can use his or her muscles.

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Can someone please help me with this following question, If you could visit Pangaea what animals would you find
A). Penguins
B). Mammals
C). Dinosaurs
D). Eagles

Answers

Answer:

C). Dinosaurs

Explanation:

Marisa’s car accelerates at an average rate of 2.6m/s^2. Calculate how long it takes her car to accelerate from 24.6m/s to 26.8m/s? Show your work.

Answers

given info is... Acceleration(a)=2.6m/s^2

                       final velocity(v)=26.8m/s

                       initial velocity(u)=24.6m/s

need to find.... time(t)=?

[tex]a=\frac{v-u}{t} \\2.6=\frac{26.8-24.6}{t} \\\\[/tex]

[tex]t=\frac{v-u}{a}[/tex]

[tex]t=\frac{26.8-24.6}{2.6}[/tex]

[tex]t=0.846s[/tex]

Explanation:

It takes 0.84 second her car to accelerate from 24.6m/s to 26.8m/s.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

Given parameters:

Initial speed of the car: u = 24.6 m/s

Final speed of the car: v = 26.8 m/s.

Acceleration of the car: a = 2.6 m/s²

Time interval: t = ?

change is speed = final speed - initial speed

= 26.8 m/s - 24.6 m/s

= 2.2 m/s

From the definition of acceleration,

acceleration = change is speed / time interval

So, time interval  =  change is speed / acceleration

= 2.2 m/s/2.6 m/s²

= 0.84 second.

Hence, it takes 0.84 second her car to accelerate from 24.6m/s to 26.8m/s.

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QUESTION 2

At the end of an investigation, what should be done if the results do NOT support the hypothesis?

O A Repeat your investigation to ensure your results are accurate and then modify your hypothesis if necessary.

OB. Repeat your investigation over and over again until you get the results that will support your original hypothes

O C. Check your measurement tools to ensure they are working.

OD. Change the topic of your investigation to one that will yield results that support a hypothesis.

Answers

Answer:

A. Repeat your investigation to ensure your results are accurate and then modify your hypothesis if necessary.

Explanation:

Having results that do not support the hypothesis is a common occurrence.

Hypotheses always depend on the data and experiment. If at the end of an investigation the results do not support the hypothesis, the investigation should be be repeated to further confirm this discovery.

And if there is still no correlation, then the hypothesis is not a reasonable explanation for the investigation and should be modified or rejected if necessary.

A diffusion couple, made by welding a thin onecentimeter square slab of pure metal A to a similar slab of pure metal B, was given a diffusion anneal at an elevated temperature and then cooled to room temperature. On chemically analyzing successive layers of the specimen, cut parallel to the weld interface, it was observed that, at one position, over a distance of 5000 nm, the atom fraction of metal A, NA, changed from 0.30 to 0.35. Assume that the number of atoms per m3 of both pure metals is 9 x 10^28. First determine the concentration gradient dnA/dx. Then if the diffusion coefficient, at the point in question and annealing temperature, was 2 10^-14 m^2/s.

Required:
Determine the number of A atoms per second that would pass through this cross-section at the annealing temperature.

Answers

Answer:

The value  is    [tex]H  =  18*10^{2} \  Atom / sec  [/tex]

Explanation:

From the question we are told that

  The atom fraction of metal A at point G is [tex] A  =  0.30 \ m[/tex]

   The atom fraction of metal  A at a distance 5000nm from G is  [tex]A_2 = 0.35[/tex]

   The number of atoms per [tex]m^3[/tex] is    [tex]N_h =  9 * 10^{28}[/tex]

    The diffusion coefficient is  [tex]D =   2* 10^{-14 } m^2/s[/tex]

Generally of the concentration of atoms of metal A at G is  

       [tex] N_A = A * N_h [/tex]

=>    [tex] N_A =  0.3  * 9 * 10^{28}[/tex]

=>     [tex] N_A =   2.7 * 10^{28} 2.7 atoms/m^3[/tex]

Generally of the concentration of atoms of metal A at a distance 5000nm from G is  

       [tex]D =  0.35 *9 * 10^{28}[/tex]

=>     [tex]D =  3.15 * 10^{28} \  atoms / m^3[/tex]

The concentration gradient is mathematically represented as

   [tex]\frac{dN_A}{dx}  =  \frac{(3.15 - 2.7) * 10^{28} }{5000nm - 0 }[/tex]

=> [tex]\frac{dN_A}{dx}  =  \frac{(3.15 - 2.7) * 10^{28} }{[5000 *10^{-9}] - 0 }[/tex]  

=>   [tex]\frac{dN_A}{dx}  = 9 * 10^{20} / m^4[/tex]  

Generally the flux of the atoms per unit  area according to Fick's Law  is mathematically represented as

       [tex]J =  -D* \frac{d N_A}{dx}[/tex]

=>    [tex]J =  -2* 10^{-14 * 9 * 10^{20} [/tex]

=>    [tex] J =  18*10^{6}\   atoms\ crossing\ /m^2 s  [/tex]

Generally if the cross-section area is [tex] a  =  1 cm^2 =  10^{-4} \  m^2[/tex]

Generally the number of atom crossing the above area  per second is mathematically is  

      [tex]H  =  18*10^{6}    *  10^{-4} [/tex]

=>    [tex]H  =  18*10^{2} \  Atom / sec  [/tex]

A block of mass m begins at rest at the top of a ramp at elevation h with whatever PE is associated with that height. The block slides down the ramp over a distance d until it reaches the bottom of the ramp. How much of its original total energy (in J) survives as KE when it reaches the ground

Answers

This question is incomplete, the complete question is;

A block of mass m begins at rest at the top of a ramp at elevation h with whatever PE is associated with that height. The block slides down the ramp over a distance d until it reaches the bottom of the ramp.

How much of its original total energy (in J) survives as KE when it reaches the ground? m = 9.9 kg h = 4.9 m d = 5 m μ = 0.3 θ = 36.87°

Answer:

the amount of its original total energy (in J) that survives as KE when it reaches the ground will is 358.975 J

Explanation:

Given that;

m = 9.9 kg

h = 4.9 m

d = 5 m

μ = 0.3

θ = 36.87°

Now from conservation of energy, the energy is;

Et = mgh

we substitute

Et = 9.9 × 9.8 × 4.9

= 475.398 J

Also the loss of energy i

E_loss = (umg cosθ) d

we substitute

E_loss  = 0.3 × 9.9 × 9.8 × cos36.87°  × 5

= 116.423 J

so the amount of its original total energy (in J) that survives as KE when it reaches the ground will be

E = Et - E_loss

E = 475.398 J - 116.423 J

E = 358.975 J

-. What is the acceleration of 4 kg trolling bag pulled by a girl with a
force of 3 N?

Answers

Answer:

Acceleration(a) = 0.75 m/s²

Explanation:

Given:

Force(F) = 3 N

Mass of thing(m) = 4 kg

Find:

Acceleration(a)

Computation:

Force(F) = ma

3 = (4)(a)

Acceleration(a) = 3/4

Acceleration(a) = 0.75 m/s²

g An angry rhino with a mass of 2700 kg charges directly toward you with a speed of 3.70 m/s. Before you start running, as a distraction, you throw a 0.180 kg rubber ball directly at the rhino with a speed of 9.05 m/s. Determine the speed of the ball (in m/s) after it bounces back elastically toward you.

Answers

Answer:

9.05m/s

Explanation:

given data

m1= 2700kg

v1=3.7m/s

m2=0.18kg

v2=9.05m/s

v3=?

We know that the velocity of the rhino will remains unchanged after impact as the mass of the rubber ball is negligible

m1v1+m2v2=m1v1+m2v3

2700*3.7+0.18*9.05=2700*3.7+0.18*v3

9990+1.629=9990+0.18v3

9991.629-9990=0.18v3

1.629=0.18v3

v3=1.629/0.18

v3=9.05m/s

A .05 kg rubber ball is dropped and hits the floor with an initial velocity of 10 m/s. It rebounds away from the floor with a final speed of 7 m/s after being in contact with the floor for .01 seconds. Find the magnitude of the force exerted by the floor on the rubber ball.

Answers

Answer:the answer is 3

Explanation:

distance is constant and time increseas

Will Speed increase or decrease?

Answers

Answer:

The speed will be decrease

The speed will decrease

Examine the diagram below.
Which of the above objects is moving the fastest?
A.
All 3 objects are moving at the same speed.
B. B
C. C
D. A

Answers

Answer:

Correct choice: D. Object A is the fastest

Explanation:

In a distance vs time graph, the distance is plotted vertically, and the time is plotted horizontally.

The diagram shows three graphs of objects A, B, and C.

The graph of A shows the object traveled 12 meters in 3 seconds, for a speed of 12/3= 4 m/s.

The graph of B shows the object traveled 8 meters in 4 seconds for a speed of 8/4=2 m/s.

Finally, the object C travels 4 meters in 4 seconds, for a speed of 4/4= 1 m/s

Thus, the fastest object is A.

A car stops in 130 m. If it has an acceleration of -5 m/s2 what was the cars starting velocity?
after
Variables:
Equation and Solve:

Answers

Answer:

We are given:

displacement (s) = 130 m

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s      [the cars 'stops' in 130 m]

initial velocity (u) = u m/s

Solving for initial velocity:

From the third equation of motion:

v² - u² = 2as

replacing the variables

(0)² - (u)² = 2(-5)(130)

-u² = -1300

u² = 1300

u = √1300

u = 36 m/s

Plates slide past one another at____.
A. Subduction zones
B. Transform boundaries
C. Convection currents
D. Divergent boundaries

Answers

Answer:

Transform Boundary

Explanation:

The just slide past each other

Answer:

Transform Boundaries

Explanation:

Name the part of the human eye which acts as a protective layer for the eye​

Answers

Answer:

Cornea

Explanation:

Cornea protects outer layer of the eye.

A
6. All other changeable factors that must
be kept the same to ensure a fair test
(what you keep the same).​

Answers

Answer:

a constant variable?

Explanation:

A constant variable is any aspect of an experiment that a researcher intentionally keeps unchanged throughout an experiment.

Experiments are always testing for measurable change, which is the dependent variable. You can also think of a dependent variable as the result obtained from an experiment. It is dependent on the change that occurs

An airplane, starting at rest, takes off on a 600. m long runway accelerating at a rate of 12 m/s/s. How many seconds does it take to reach the end of the runway?

Answers

x = 1/2 at²

where x = length of runway, a = acceleration, and t = time.

600 m = 1/2 (12 m/s²) t²

t² = (1200 m) / (12 m/s²)

t² = 100 s²

t = 10 s

A 20m length wire 1.5mm in diameter has a resistance of 2.5 ohm what is the resistance of a 35m length of wire 3mm in diameter made of the same material?​

Answers

From the calculations, the resistance of the material is 1.1 ohm.

What is the resistance of the wire?

Given that;

R α l/A

R = ρl/A

R = resistance

l = length

A = Area

ρ = resistivity

Now;

A = πr^2

A = 3.142 * (1.5 * 10^-3/2)^2

A = 1.77 * 10^-6 m^2

ρ = RA/l

ρ =  2.5 *  1.77 * 10^-6 /20

ρ = 2.2 * 10^-7 ohm/m

Now;

R =ρl/A

A =  3.142 * (3  * 10^-3/2)^2

A = 7.1 * 10^-6 m^2

Thus

R = 2.2 * 10^-7 * 35/ 7.1 * 10^-6

R = 1.1 ohm

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An object is rolled at 12 m/s down a table. It stops
after 15s. What was its acceleration?
Variables:
Equation and Solve:

Answers

Answer:

We are given:

initial velocity (u) = 12 m/s

final velocity (v) = 0 m/s

time taken (t) = 15 seconds

acceleration (a) = a m/s²

Solving for acceleration:

from the first equation of motion

v = u + at

replacing the variables

0 = 12 + (a)(15)

0 = 15a + 12

a = -12 / 15

a = -4 / 5 m/s²

Grass and plants get energy from
А
the sun.
B
eating food.
с
windmills.
D
electrons.

Answers

A is the answer for that question

Answer:

From the Sun

Explanation:

Plants can't eat any food. They don't ue or need windmills to get energy. They are plants so they don't have any electrons. The only way that they can recive energy from is the sun. Sometimes plants die when they don't get enough sun because they don't have any energy to live.

It took 50 joules to push a chair 5 meters across the floor. With what force was the chair pushed?

Answers

Answer:

The chair was pushed with 10 N.

Explanation:

The chair was pushed with 50 Joules.  

Work = Force * Distance

50 J = F * 5m  

F = 50 / 5 = 10N  

The chair was pushed with 10 N.

The chair was pushed with 10 N force.

What is Work done?

Work is defined as the measure of energy transfer that occurs when an object is moved over a distance by an external force, at least part of which is applied in the direction of displacement.

If the force is constant then work can be calculated by multiplying the length of the path by the component of the force acting along the path, which is expressed mathematically as work W equal to the force f over a distance d, or W = fd.

So, for above given information,

Work done= 50 joules

Distance covered by the chair = 5m

Then, Force= W/d

=50/5= 10N

Thus, the chair was pushed with 10 N force.

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Help me Please!!!!!!!

Answers

The speed is equal to the area under the line up to the point where t .=15 s.
Do find the area of the triangle and that if the rectangle and add them together.
The area of the triangle is 25 and the rectangle is also 25 so the speed is 50 m/s

I need to write 200 words about: boys are most influenced by their fathers and girls are most influenced by their mothers. Do you agree or disagree?

Answers

Answer:

I agree

Explanation:

I agree because most of the times girls pass more time with their mom since they hace more things in common, it’s the same with the boys.

At a certain instant, a proton is moving in the positive x direction through a magnetic field in the negative z direction. What is the direction of the magnetic force exerted on the proton

Answers

Answer: positive y direction

Explanation:

we know that direction of velocity is in +x direction

now the magnetic force is in negative z direction

therefore the magnetic force , F = q × ( v × B)

F = ( i × [ - k ] ) direction

F = j direction

so the direction of the magnetic force on the proton is positive y direction.

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