Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

The diagram below shows the contents of a jar from which you select marbles at random.

An illustration of a jar of marbles is shown. Four of the marbles are labeled with an upper R, seven of the marbles are labeled with an upper B, and five of the marbles are labeled with an upper G. The key identifies upper R to represent red marbles, upper B to represent blue marbles, and upper G to represent green marbles.

What is the probability of selecting a red marble, replacing it, and then selecting a blue marble? Show your work.
What is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? Show your work.
Are the answers to parts (a) and (b) the same? Why or why not?

Answer:

A:

probability of red = 4/16 = 1/4

prob(blue) = 7/16

probability of red, then blue is (1/4)(7/16) = 7/64

B:

probability red = 1/4

probability blue = 7/15

probability of red, then blue = (1/4)(7/15) = 7/60

c) your decision

Step-by-step explanation:

i took the test

The solution is,

A. 7/64 is the probability of selecting a red marble, replacing it, and then selecting a blue marble.

B. 7/60 is the probability of selecting a red marble, setting it aside, and then selecting a blue marble.

C. the answer is no.

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

here, we have,

given,

There are 4 red marbles.

There are 7 blue marbles.

There are 5 green marbles.

There are 16 marbles in total.

A:

Answer = (probability of selecting a red marble)(probability of selecting a blue marble)

First, the probability of selecting a red marble.

probability of red = 4/16 = 1/4

probability(blue) = 7/16

probability of red, then blue is (1/4)(7/16) = 7/64

B:

Answer = (probability of selecting a red marble)(probability of selecting a blue marble)

First, the probability of selecting a red marble.

probability red = 1/4

probability blue = 7/15

probability of red, then blue = (1/4)(7/15) = 7/60

c) obviously,

7/64 ≠ 7/60

So the answer is no.

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