NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! PLEASE answer thoroughly. Chapter 9 part 2

4. How can you determine the maximum number of solutions for a polynomial? How are these counted on the graph?

The construction illustrated in the figure is that of a line parallel to [tex]\overrightarrow{HJ}[/tex] through point N.

Given: Figure containing illustration of the construction

To find: The construction illustrated in the figure

It can be seen that the figure contains a straight line passing through H and J, a straight line passing through H and N, and a straight line passing through N which seems to be parallel to [tex]\overrightarrow{HJ}[/tex].

The figure also contains arcs made by a compass that measures the angle between [tex]\overrightarrow{HJ}[/tex] and [tex]\overrightarrow{HN}[/tex]. These arcs have been replicated at the point N on the straight line [tex]\overrightarrow{HN}[/tex].

This implies that the straight line through N has been constructed in such a way, so that the angle between that straight line and [tex]\overrightarrow{HN}[/tex] is equal to the angle between [tex]\overrightarrow{HJ}[/tex] and [tex]\overrightarrow{HN}[/tex]. This makes these angles, corresponding angles and [tex]\overrightarrow{HN}[/tex] as the transversal. Thus, the new straight line is constructed parallel to [tex]\overrightarrow{HJ}[/tex].

A strong counterargument that this illustration is not that of a line perpendicular to [tex]\overrightarrow{HJ}[/tex] through point N is that the figure does not contain any straight line perpendicular to [tex]\overrightarrow{HJ}[/tex].

Thus, the construction illustrated in the figure is that of a line parallel to [tex]\overrightarrow{HJ}[/tex] through the point N.

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Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

Step-by-step explanation:

To find the approximate value of y when

x = 13 and z = 195 we must first find the relationship between them

The statement

y varies jointly with x and z is written as

where k is the constant of proportionality

From the question

y = 2

x = 11

z = 110

We have

2 = 11(110)k

2 = 1210k

Divide both sides by 1210

[tex]k = \frac{1}{605} [/tex]

So the formula for the variation is

[tex]y = \frac{1}{605} xz[/tex]

When

x = 13

z = 195

y is

[tex]y = \frac{1}{605} (13)(195)[/tex]

[tex]y = \frac{507}{121} [/tex]

y = 4.1900

We have the final answer as

Hope this helps you

Answer:

Answer is number 2 as twice of 2 is 4 and double of 4 is 8 and 8+2=10

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

Step-by-step explanation:

The comparison will be the same if you subtract the right side and compare to zero:

  a/b ?? c/d . . . . . . . using ?? for the unknown comparison symbol

  a/b - c/d ?? 0 . . . . subtract the fraction on the right

  (ad -bc)/bd ?? 0 . . . combine the two fractions

  ad - bc ?? 0 . . . . . . multiply by bd to make the job easier

__

5/6 and 2/5

  5(5) -6(2) = 25 -12 > 0   ⇒   5/6 > 2/5

4/10 and 7/8

  4(8) -10(7) = 48 - 70 < 0   ⇒   4/10 < 7/8

3/12 and 1/4

  3(4) -12(1) = 0   ⇒   3/12 = 1/4

_____

Of course, you can use your calculator (or your memory) to change each of these to a decimal equivalent. The comparison should be easy at that point.

  0.833 > 0.400

  0.400 < 0.875

  0.250 = 0.250

Answer:

  3.48%

Step-by-step explanation:

Interest rate is the one variable in the amortization formula that cannot be solved for directly. An iterative or graphical approach is needed. There is no formula. Financial calculators, financial apps, and spreadsheets are all able to do this calculation.

__

In the attached, we have used a graphing calculator to find the value of interest rate (in %) that makes the loan payment be $200 for a loan of $11,000. It shows us the rate is 3.48%. (A financial calculator confirms this value.) The x-intercept in the graph is the interest rate that makes the difference between the payment and $200 be zero. In our formula for the payment, we have used t for years. 60 monthly payments is 5 years.

It looks like you're asked to compute

[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz[/tex]

where C is parameterized by ⟨t, t, t⟩ with 0 ≤ t ≤ 1.

In other words, x = y = z = t, so dx = dy = dz = dt, and the integral reduces to

[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz = \int_0^1 t\,\mathrm dt + t\,\mathrm dt + t\,\mathrm dt \\\\ = 3 \int_0^1 t\,\mathrm dt \\\\ =\frac32t^2\bigg|_{t=0}^{t=1} \\\\ =\boxed{\frac32}[/tex]

Answer:

[tex]\huge\boxed{4 ( 20 + 21)}[/tex]

Step-by-step explanation:

4(20) + 84

Resolve Parenthesis

80 + 84

Taking 4 common as both are the multiples of 4

4 ( 20 + 21)

Answer:

x=nπ3, n∈I

Step-by-step explanation:

sin x + sin 5x = sin 2x + sin 4x

⇒⇒   2 sin 3x cos 2x = 2 sin 3x cos x

⇒⇒   2 sin 3x(cos 2x - cos x) = 0

⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3⇒    sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3 , n∈I, n∈I

or    cos 2x−cos x=0 ⇒ cos 2x=cos xcos 2x-cos x=0 ⇒ cos 2x=cos x

⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3⇒   2x=2nπ±x  ⇒  x=2nπ, 2nπ3 , n∈I, n∈I

But solutions obtained by x=2nπx=2nπ , n∈I, n∈I or x=2nπ3x=2nπ3 , n∈I, n∈I are all involved in x=nπ3x=nπ3 , n∈I

the answer to your question is $75

Answer:

B =

[tex]4x - 1 - \frac{4}{2x - 3} [/tex]

Step-by-step explanation:

In this type of questions the answers are required in the

[tex]quotient \: + \frac{remainder}{divisor} [/tex]

form.

First of all, the equations in question must be arranged properly

[tex](8 {x}^{2} - 14x - 1) \div 2x - 3[/tex]

Then you divide.

[tex]2x - 3 \sqrt{8 {x}^{2} - 14x - 1 } [/tex]

Answer

[tex]4x - 1 - \frac{4}{2x - 3} [/tex]

The table that represents a function in the options given is: Table A. (see image attached below).

Recall:

In the tables given, only the first table has exactly one y-value assigned or related to every x-value given.

Therefore, the table that represents a function in the options given is: Table A. (see image attached below).

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Answer:

Graph A

Step-by-step explanation:

Answer:

B y = -1/2x + 7/2

Step-by-step explanation:

We know that it has a negative slope since the points go from the top left to the bottom right

We can eliminate A and D

The y intercept is where it crosses the y axis

It should cross somewhere between 2 and 4

C  has a y intercept of 9 which is too big

Lets verify with a point

x = -4

y = -4(-4)+9 = 16+9 = 25  (-4,25)  not even close to being near the points on the graph

checking B

y = -1/2 (-4) +7/2

  = 2 + 7/2 = 11/2 = 5.5  it seems  reasonable

Answer:

[tex]\Large \boxed{y=-\frac{1}{2} x+\frac{7}{2} }[/tex]

Step-by-step explanation:

Using a graph,

we can see that the line y = -1/2x + 7/2 best fits for the data.

Step-by-step explanation:

Start Unlimited: 

$70 for one line

$60 for two lines

$45 for three lines

$35 for four lines

Play More Unlimited: 

$80 for one line

$70 for two lines

$55 for three lines

$45 for four lines

Do More Unlimited: 

$80 for one line

$70 for two lines

$55 for three lines

$45 for four lines

Get More Unlimited: 

$90 for one line

$80 for two lines

$65 for three lines

$55 for four lines

Answer:

4 months

As we show that ;

40 + (60x * 4)  = 280

100 + (45x * 4) = 280

but in simultaneous equations Verizon must be set equal to 240 being 80 x 3

and T mobile must be equal to 45 x 4 = 180

so that 240+ 180 = 420 to find 4

This would be a method on distribution as "60 sign up is 1/3 more than 1st equation.

Step-by-step explanation:

This is a simultaneous equation but trial and error is below to prove all is true.

step 1 make all equations same

40s + (60x)      * 3 = 180x  LCM   = 80 x 3   =  1   1/3 of 60

100s + (45x)     * 4 = 180x LCM   = 45  x 4   =  1 of 45 as verizon charges 1/3 more sign up.

100s- 40s + 180x = (180x) =  240 + 180

60s + 180x = 420

s = 60

so our equations must each end with 420

when we get 60s + 180x = 420  then

420 - 180 = 240

240/60 =  4

x = 4 months

Verizon = 1st and T mobile = 2nd

40 + (60x * 5)  = 340

100 + 45x * 5 = 325

with $15 out after 5 months so we try 6 months

40 + (60x * 6)  = 400

100 + 45x * 6 = 370

and see this is increasing in difference, so try a smaller value of months..

We try 4 months;

40 + (60x * 4)  = 280

100 + (45x * 4) = 280

Answer:

its multiple choice

A. 26inches (1inch/25.4mm)

B. 26inches (25.4mm/1inch)

C. 25.4inches (1mm/26inch)

D. 26inches (1mm/25.4inch)

and its b

Answer:

20 cm

Step-by-step explanation:

20 cm

8/2 = 4

6/2 = 3

3 and 4 are the sides of the triangle (four triangles in rhombus)

a²+b²=c²

4³+3²=c²

c = 5

5 x 4 = 20

Hope this helped

Answer:

perimeter = 20 cm

Step-by-step explanation:

consider breaking the rhombus into four equal parts.

and that gives you a triangle.

(refer to image attached for more clarification)

let a = 3, b = 4

to get the side c, use Pythagorean theorem = c² = a² + b²

c = sqrt (3² + 4²)

side c = 5

therefore,

perimeter = 4 x sides (c)

perimeter = 4 x 5

perimeter = 20 cm

Answer:

2y= 6-3x when x=0

2y= 6-3(0)

2y= 6-0

2y= 6

y= 6/2

y= 3

#i'm indonesian

#hope it helps.

Answer:

[tex] \boxed{y = 3}[/tex]

Step-by-step explanation:

Given, x = 0

[tex] \mathsf{2y = 6 - 3x}[/tex]

plug the value of x

⇒[tex] \mathsf{2y = 6 - 3 \times 0}[/tex]

Multiply the numbers

⇒[tex] \mathsf{2y = 6 - 0}[/tex]

Calculate the difference

⇒[tex] \mathsf{2y = 6}[/tex]

Divide both sides of the equation by 2

⇒[tex] \mathsf{ \frac{2y}{2} = \frac{6}{2} }[/tex]

Calculate

⇒[tex] \mathsf{y = 3}[/tex]

Hope I helped!

Best regards!

Answer:

70%

Step-by-step explanation:

Given

Number of Siblings:   ||    0  ||    1    ||      2     ||       3

Number of Students: ||    4  ||    18    ||    10     ||       8

Required

Determine the probability of a student having at least one but not more than 2 siblings

First, we have to determine the total number of 10th grade students

[tex]Total = 4 + 18 + 10 + 8[/tex]

[tex]Total = 40[/tex]

The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)

Solving for P(1)

P(1) = number of students with 1 sibling / total number of students

From the given parameters, we have that:

Number of students with 1 sibling = 18

So:

[tex]P(1) = \frac{18}{40}[/tex]

Solving for P(2)

P(2) = number of students with 2 siblings / total number of students

From the given parameters, we have that:

Number of students with 2 siblings = 10

So:

[tex]P(2) = \frac{10}{40}[/tex]

[tex]P(1) + P(2) = \frac{18}{40} + \frac{10}{40}[/tex]

Take LCM

[tex]P(1) + P(2) = \frac{18 + 10}{40}[/tex]

[tex]P(1) + P(2) = \frac{28}{40}[/tex]

Divide numerator and denominator by 4

[tex]P(1) + P(2) = \frac{7}{10}[/tex]

[tex]P(1) + P(2) = 0.7[/tex]

Convert to percentage

[tex]P(1) + P(2) = 70\%[/tex]

Hence, the required probability is 70%

Answer:

Step-by-step explanation:

bB

Answer: You are correct. The answer is choice C.

The sum of the vectors is the resultant vector, which is where the net force is directed.

An example would be if you had a ball rolling on a table and you bumped the ball perpendicular to its initial velocity, then the ball would move at a diagonal angle rather than move straight in the direction where you bumped it.

Acceleration is the change in velocity over time, so the acceleration vector tells us how the velocity's direction is changing.

The direction of the acceleration on a body upon which multiple forces are applied depends on the direction of the netforce acting on the body.

Therefore, acceleration will be due in the direction of the netforce.

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Answer:

x = sqrt(50) = 5sqrt(2) = 7.071 ft (to 3 decimals)

Step-by-step explanation:

referring to the diagram

theta (x) = atan(10/x) - atan(5/x)

differentiate with respect to x

theta'(x) = 5/(x^2+25) - 10/(x^2+100)

For x to have an extremum (max. or min)

theta'(x) = 0  ="

5/(x^2+25) - 10/(x^2+100) = 0

transpose and cross multiply

10(x^2+25) -5(x^2+100) = 0

expand and simplify

10x^2+250 - 5x^2-500 = 0

5x^2 = 250

x^2=50

x = sqrt(50) = 5sqrt(2) = 7.071 ft (to 3 decimals)

Since we know that if x becomes large, theta will decrease, so

x = 5sqrt(2) is a maximum.

Answer:

V = 904.32 ft^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The radius is 6 and pi = 3.14

V = 4/3 ( 3.14) (6)^3

V = 904.31999 ft^3

Rounding to the hundredths place

V = 904.32 ft^3

[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\red{Volume \: of \: sphere \: = \: \frac{4}{3} \: \pi \: {r}^{3} }}}}}\end{gathered}[/tex]

[tex] \bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: \frac{4}{3} \: \times \: 3.14 \: \times \: {6}^{3} \\ [/tex]

[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: \frac{4}{3} \: \times \: 3.14 \: \times \:216[/tex]

[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: \frac{4}{ \cancel3} \: \times \: 3.14 \: \times \: \cancel{216 \: {ft}^{3} } \: \: \: ^{72 \: {ft}^{3} } [/tex]

[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: 4 \: \times \: 3.14 \: \times \: 72 \: {ft}^{3} [/tex]

[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: 12.56 \: \times \: 72 \: {ft}^{3} [/tex]

[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: 904.32 \: {ft}^{3} [/tex]

Answer:

This number line show the inequality x > 2

Answer:

I am going to show you the first steps to complete squares for the given equation: 1) Starting equation: 3x^2 + 9x -4 = 0 2) Add 4 to both sides => 3x^2 + 9x - 4 + 4 = 4 => 3x^2 + 9x = 4 3) Extract common factor 3 in the left side => 3 (x^2 + 3x). Now, compare with a(x^2 + 3x) and you get a = 3. Answer: a = 3.

Answer:

its c

Step-by-step explanation:

Answer:

1. 24

2. 4.444... (or 4 rounded to the nearest whole number)

Step-by-step explanation:

1. 80/100 = x/30

cross-multiply

100 × x = 100x

80 × 30 = 2400

divide

100x/100 = x

2400/100 = 24

answer

x = 24

2. 90/100 = 4/x

cross-multiply

90 × x = 90x

100 × 4 = 400

divide

90x/90 = x

400/90 = 4.444...

answer

x = 4.444...

Answer:

The  upper limit is    

                   [tex]k = 52.94[/tex]

Step-by-step explanation:

From the question we  told that

     The  sample size is [tex]n = 16[/tex]

      The sample mean is  [tex]\= x = 50[/tex]

      The sample variance is  [tex]\sigma ^2 = 36[/tex]

For  a  95% confidence interval the confidence level is  95%

Given that the confidence level is 95% then the level of significance is  mathematically evaluated  as  

             [tex]\alpha = 100 - 95[/tex]

              [tex]\alpha = 5 \%[/tex]

              [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table(reference- math dot armstrong dot edu), the value is  

              [tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]

Generally the margin of error is mathematically represented as

             [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }[/tex]

 Here  [tex]\sigma[/tex] is the standard deviation which is mathematically evaluated as

                  [tex]\sigma = \sqrt{\sigma^2}[/tex]

substituting values

                  [tex]\sigma = \sqrt{36}[/tex]

=>                [tex]\sigma = 6[/tex]

So

                    [tex]E = 1.96 * \frac{6}{\sqrt{16} }[/tex]

                     [tex]E = 2.94[/tex]

The 95% confidence interval is mathematically represented as

                 [tex]\= x - E < \mu < \= x + E[/tex]

substituting values

                [tex]50 -2.94 < \mu <50 +2.94[/tex]

                [tex]47.06 < \mu <52.94[/tex]

The  upper limit is    

                   [tex]k = 52.94[/tex]

Answer:

Hey there!

A function only has one y value for every x value, so this is a function. Additionally, all linear equations (that are in the y=mx+b form) are functions.

Hope this helps :)

Answer:

Beginning (t=0) population with flu is 23.

After 4 weeks, population with flu is 1250.

After an infinite amount of weeks, the population witf flu is 102000

Step-by-step explanation:

First question asks you to replace t with 0 because it says beginning.

102000/(1+4400e^-0)=102000/(1+4400)=102000/4401=23.17655 approximately. To nearest whole number this is 23.

After 4 weeks means we replace t with 4:

102000/(1+4400e^-4)

Calculator time:

1250.17142 which to nearest whole number is 1250

If t is super large, then e^-t is super close to 0.

So the limiting number is

102000/(1+4400×0)=102000/1=102000

Answer:

The probability that at least, one of the four children the couple has is a boy is 0.8.

Step-by-step explanation:

Given that boys and girls are equally likely, we want to find the probability of having at least, one boy, from four children..

Note that it is possible to have the following for 4 children:

1. 4 boys, 0 girls

2. 3 boys, 1 girl

3. 2 boys, 2 girls

4. 1 boy, 3 girls

5. 0 boys, 4 girls.

To have at least, one boy, out of the 5 options, only 4 is possible.

1. 4 boys, 0 girls.........YES

2. 3 boys, 1 girl ...........YES

3. 2 boys, 2 girls.........YES

4. 1 boy, 3 girls.............YES

5. 0 boys, 4 girls..........NO

The probability is therefore,

(Probability of event = 4) ÷ (Total possible outcome = 5)

P = 4/5 = 0.8

Answer:

Ha : Pilots average gain score not due to alcohol.

Step-by-step explanation:

Null hypothesis is a statement that is to be tested against the alternative hypothesis and then decision is taken whether to accept or reject the null hypothesis. Here the null hypothesis is that pilots average gain due to alcohol. Then if there is no alcohol what is pilots average gain. This thing will be tested as alternative hypothesis.

Answer:

n = 8

Step-by-step explanation:

Follow the question when turning the word equation into an equation

Because we know this is a quadratic equation, the product is a result of n multiplied by itself

[tex]n^{2} -4=60[/tex]

Solve for n

[tex]n^{2} =64[/tex]

[tex]\sqrt{n^{2} } =\sqrt{64}[/tex]

n = 8