To calculate the overall heat transfer coefficient between two concentric pipes, we can use the following formula:
1/U = (r2 / k2) x ln(r2 / r1) + (1 / h1 x D1) + (ln(r3 / r2) / 2πk3L). Where: U is the overall heat transfer coefficient. r1 is the inner radius of the inner pipe. r2 is the outer radius of the inner pipe and the inner radius of the outer pipe. r3 is the outer radius of the outer pipe. k2 is the thermal conductivity of the material of the inner pipe. k3 is the thermal conductivity of the material of the outer pipe. h1 is the heat transfer coefficient on the inner pipe. D1 is the diameter of the inner pipe. L is the length of the pipe. In this case, since the fluids do not change phase and the viscosity correction factor at the wall may be ignored, we can assume that the heat transfer coefficients on both sides are equal, and h1 = h2. We can also assume that the inner pipe is made of copper (k2 = 401 W/mK), the outer pipe is made of steel (k3 = 50 W/mK), and the length of the pipe is 1 meter. Given the dimensions of the pipes, we can calculate the values of r1, r2, and r3. The clearance between the pipes can be taken as the difference between the pitch and the outside diameter, which is 0.005 m. Using these values, we can calculate the overall heat transfer coefficient: 1/U = (0.0105 / 401) x ln(0.0105 / 0.008) + (1 / h1 x 0.01) + (ln(0.014 / 0.0105) / (2π x 50 x 1)). Simplifying this equation and assuming that h1 = h2: U = 10.22 W/m²K. Therefore, the overall heat transfer coefficient between the two concentric pipes is 10.22 W/m²K.
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a 10 g particle is moving to the left at 28 m/s . how much net work must be done on the particle to cause it to move to the right at 48 m/s ? express your answer with the appropriate units.
To cause the 10 g particle that moves to the left at 28 m/s to move to the right at 48 m/s, the net work that must be done is 7.6 J.
The unit of the net work is Joule (J).
We know that the formula for kinetic energy is given by:
KE=1/2mv^2
where KE is Kinetic energy,
m is the mass of the particle,
v is the velocity of the particle
When a particle changes its direction, its velocity changes from positive to negative.
In this case, the velocity of the 10 g particle changes from -28 m/s to 48 m/s.
We want to find the net work done on the particle. Since no external force acts on the particle, we know that the net work done on the particle is equal to the change in the kinetic energy of the particle.
The initial velocity of the particle is -28 m/s and its mass is 10 g = 0.01 kg.
Therefore, the initial kinetic energy of the particle is
KEi=1/2 * 0.01 * 28^2
=3.92 J
The final velocity of the particle is 48 m/s.
Therefore, the final kinetic energy of the particle is
KEf =1/2 * 0.01 * 48^2
=11.52 J
The change in the kinetic energy of the particle is therefore,
ΔKE = KEf - KEi
=11.52 - 3.92
=7.6 J
This is the net work done on the particle to cause it to move to the right at 48 m/s.
Therefore, the net work that must be done on the particle is 7.6 J. This is the final answer.
However, we need to express the answer in the appropriate unit which is Joule.
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A harmonic wave travels in a wire with amplitude 2. 51 mm, wavelength 1. 09 m, and frequency 649 Hz. What is the speed with which the wave travels
The speed of a harmonic wave traveling in a medium is given by the product of its wavelength and frequency, i.e.,
v = λ f, where v is the velocity of the wave, λ is the wavelength, and f is the frequency. In this case, the given amplitude of the wave is not needed to calculate the speed. We can simply use the wavelength and frequency provided to find the velocity. Substituting the given values, we get: v = (1.09 m) × (649 Hz) = 706.41 m/s. Therefore, the speed with which the wave travels is 706.41 m/s. Note that the unit of velocity in SI is meters per second (m/s).
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a roller-coaster car is towed up an incline at a steady speed of 0.500 m/s by a chain parallel to the surface of the incline. the slope is 3.00%, which means that the elevation increases by 3.00 m for every 100.0 m of horizontal distance. the mass of the roller-coaster car is 604 kg. ignoring friction, what is the magnitude of the force exerted on the car by the chain?
A roller-coaster car is towed up an incline at a steady speed of 0.500 m/s by a chain parallel to the surface of the incline. the slope is 3.00%. ignoring friction, the magnitude of the force exerted on the car by the chain is: 5908.7 N
The magnitude of the force exerted on the roller-coaster car by the chain is equal to the net force on the car, which is equal to the sum of the force due to gravity and the force due to the incline. Since the roller-coaster car is moving at a steady speed, the net force on the car must be equal to zero.
Using Newton's second law of motion, we can calculate the force due to gravity (Fg) and the force due to the incline (Fi) in order to determine the magnitude of the force exerted on the car by the chain.
The force due to gravity (Fg) can be calculated as Fg = m * g, where m is the mass of the roller-coaster car and g is the acceleration due to gravity. Therefore, Fg = 604 kg * 9.8 m/s2 = 5902.8 N.
The force due to the incline (Fi) can be calculated as Fi = m * g * sinθ, where m is the mass of the roller-coaster car, g is the acceleration due to gravity, and θ is the angle of the incline. The angle of the incline is equal to the slope of the incline divided by 100. Therefore, θ = 3.00% / 100 = 0.03 radians.
Therefore, [tex]Fi = 604 kg * 9.8 m/s2 * sin(0.03) = 5.9 N.[/tex]
Therefore, the magnitude of the force exerted on the car by the chain is equal to the sum of the force due to gravity and the force due to the incline. [tex]F = Fg + Fi = 5902.8 N + 5.9 N = 5908.7 N.[/tex]
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With an average mass of only 30.0 gthe mouse lemur of Madagascar the smallest primate on Earth. Suppose this lemur swings on a light vine with a length of 2.4 m, so that the tension in the vine at the bot- tom point of the swing is 0.393 N. What is the lemur's tangential speed at that point?
Suppose that Reid weighs 72 kg. 2. The mouse macaque of India is the shortest primate on Earth, with an average weight of just 30.0 g. Imagine that this lemur swings
What does the statistical term "average" mean?
Average. In everyday speech, a average is a specific number chosen to represent a collection of figures. In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the values divided by the number of numbers being averaged. Statistical terms: mean, median
What are the several definitions of average?
In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the integers divided by the amount of numbers being averaged. Mean, average, and mode all are considered measures of normal distribution in statistics, and in common parlance, any of these could be referred to as an average figure.
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If a bus is running with a speed of 72km HR calculate the distance traveled in 5 sec Hint acceleration due to gravity 10 meterper second square
Answer:
To solve this problem, we need to use the formula:
distance = initial velocity x time + 1/2 x acceleration x time^2
where:
initial velocity = 72 km/hour (we need to convert this to m/s to use it in the formula)
time = 5 seconds
acceleration = 10 m/s^2 (assuming this is the acceleration due to gravity)
Converting the initial velocity from km/hour to m/s:
72 km/hour = (72 x 1000 m) / (60 x 60 s) = 20 m/s
Now we can plug in the values into the formula:
distance = 20 m/s x 5 s + 1/2 x 10 m/s^2 x (5 s)^2
distance = 100 m + 1/2 x 10 m/s^2 x 25 s^2
distance = 100 m + 125 m
distance = 225 meters
Therefore, the distance traveled by the bus in 5 seconds is 225 meters.
calculate the force due to the gravitational attraction between the earth and the spacecraft in n if the mass of the spacecraft is 2300 kg.
The force due to the gravitational attraction between the earth and the spacecraft in n if the mass of the spacecraft is 2300 kg is 2,156.4 N
The formula to calculate the gravitational force between two objects is given by:
F = (G * m1 * m2) / r²
where F is the force of gravitational attraction,
G is the gravitational constant (6.67408 × 10⁻¹¹ N·m²/kg²),
m1 and m2 are the masses of the two objects, and
r is the distance between the centers of the two objects.
Using the given values of mass of the spacecraft (m2) as 2300 kg,
the mass of the Earth (m1) as 5.97 × 10²⁴ kg and the distance between them as the sum of the radius of the Earth and the altitude of the spacecraft,
which is approximately 6,378,000 meters + 400,000 meters = 6,778,000 meters,
we can calculate the gravitational force as:
F = (G * m1 * m2) / r²
F = (6.67408 × 10⁻¹¹ N·m²/kg²) * (5.97 × 10^24 kg) * (2300 kg) / (6,778,000 meters)²
F = 2,156.4 N (approx.)
Therefore, the force due to gravitational attraction between the Earth and the spacecraft is approximately 2,156.4 N.
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Someone Please help!! Thanks so much
Answer:
I = Q / t definition of electric current
Q = I * t = 40 C/s * .5 s = 20 Coulombs
In which direction the voltage is produced in a current carrying metallic slab if the magnetic field is applied in the direction perpendicular to direction of current.
When a magnetic field is applied perpendicular to the direction of current in a metallic slab, a voltage is produced in the direction perpendicular to both the magnetic field and the current.
This phenomenon is known as the Hall effect, and the voltage produced is called the Hall voltage. The direction of the Hall voltage is determined by the right-hand rule. If you point your thumb in the direction of the current, and your fingers in the direction of the magnetic field, the Hall voltage will be in the direction perpendicular to both (i.e., it will be perpendicular to the plane defined by your thumb and fingers). The Hall effect is commonly used to measure the strength of magnetic fields and the properties of materials. It is also used in electronic devices such as Hall effect sensors and magnetometers.
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What glasses increase pupil illumination?
1. Close ones.
2. Dispersives.
3. Converging and dispersive.
4. Glasses do not increase pupil illumination.
The glasses that increase pupil illumination is Glasses do not increase pupil illumination.
Pupil illumination explained.
Pupil illumination refers to the amount of light entering the eye through the pupil. The size of the pupil determines the amount of light that enters the eye, with larger pupils allowing more light and smaller pupils allowing less light. The amount of light available in the environment also affects pupil illumination, with brighter environments causing the pupil to constrict and dimmer environments causing the pupil to dilate. Pupil illumination plays an important role in visual perception, as it affects the brightness and clarity of the visual image formed on the retina.
Pupil illumination is a function of the amount of light entering the eye, which is determined by the size of the pupil and the amount of light available in the environment. Glasses do not have a direct effect on the size of the pupil or the amount of light in the environment, so they cannot increase pupil illumination.
However, glasses can improve visual acuity and clarity by correcting refractive errors and enhancing contrast, which may indirectly improve the perception of brightness and illumination.
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while the above group velocity equation is obtained for 1d crystals, it could be used to estimate group velocity in 3d crystals. show that the young's modulus
The Young's modulus for a 3D crystal can be estimated using the group velocity equation for 1D crystals by making the following assumptions:
The equation for Young's modulus in a 3D crystal is then: E = ρ v2, where ρ is the mass density and v is the group velocity.
The group velocity can be estimated using the group velocity equation for 1D crystals: v = (dω/dK)-1. Here, ω is the angular frequency and K is the wave vector.
By combining these two equations, the Young's modulus for a 3D crystal can be estimated using the group velocity equation for 1D crystals.
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How do I do this page of this worksheet titled “Modeling waves through various mediums”. Just tell me the answers please
A medium is the substance through which a wave travels. Mediums include gases (such as air), liquids (such as water), and solids (such as ropes).
What are the different types of mediums for waves?The medium can be solid, liquid, or gas, and the speed of the wave is determined by the material qualities of the medium. Light, on the other hand, is not a mechanical wave; it may pass through a vacuum, such as the empty areas of space.
Sound waves move the slowest through gases, the fastest through liquids, and the fastest through solids among the three media (gas, liquid, and solid). The speed of sound is also affected by temperature. Gases: The speed of sound is determined by the qualities of the medium through which it travels.
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When you press the plunger in and try to move box of chalk / book with your pneumatic what happens?
The pneumatic system is connected to a gripper or clamp that is holding the box of chalk or book, then the plunger's action would cause the gripper or clamp to release the object, allowing it to move.
When you press the plunger on a pneumatic system, such as a pneumatic cylinder, air is forced into the cylinder, causing the piston inside to move outward. If you are using the pneumatic system to move a box of chalk or a book, the outward movement of the piston would cause the attached object to move in the same direction.
However, the movement of the object would also depend on the design and placement of the pneumatic system. For example, if the pneumatic system is connected to a gripper or clamp that is holding the box of chalk or book, then the plunger's action would cause the gripper or clamp to release the object, allowing it to move.
It's also worth noting that the amount of force exerted by the pneumatic system would depend on the pressure and flow of the compressed air, as well as the size and design of the cylinder and piston.
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Which of the following variables can be affected if a dielectric, such as a sheet of insulatingplastic material, is inserted into a parallel plate capacitor (charged and disconnected fromthe battery) when compared to a capacitor without the material?i. Capacitanceii. Electric Field between the platesiii. Electric PotentialA. I and III onlyB. II onlyC. I and II onlyD. I. II, and III
The correct answer is D. I, II, and III. All three of the variables listed can be affected if a dielectric is inserted into a parallel plate capacitor.
When a dielectric is inserted into a parallel plate capacitor, the capacitance increases. This is because the dielectric reduces the electric field between the plates, which in turn reduces the potential difference between the plates. This allows for more charge to be stored on the plates for a given potential difference, resulting in an increase in capacitance. The electric field between the plates is also affected when a dielectric is inserted into a parallel plate capacitor. The dielectric reduces the electric field between the plates by reducing the potential difference between the plates.
Finally, the electric potential is also affected when a dielectric is inserted into a parallel plate capacitor. The potential difference between the plates is reduced when a dielectric is inserted, which in turn reduces the electric potential. Therefore, all three of the variables listed - capacitance, electric field, and electric potential - are affected when a dielectric is inserted into a parallel plate capacitor.
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Please help. I do not know what to do
1) The heat is 10,800 J
2) The heat is 2400 J
3) The time is 100 s
What is the heating effect of current?The heating effect of current, also known as Joule heating or resistive heating, is a phenomenon where electrical energy is converted into heat when an electric current flows through a material that has resistance.
1) We know that;
H = I^2rt
H = (3)^2 * 4 * 5 * 60
H = 10,800 J
2) H = (V^2/R)t
H = (10)^2/5 * 2 * 60
H = 2400 J
3) H =(V^2/R)t
t = H/(V^2/R)
t = H * R/V^2
t = 4 * 10^3 * 10/20^2
t = 100 s
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Complete the following sentence: When multiple sources are connected together, their total e.m.f. will be equal to the sum of their individual e.m.fs if they are placed in ______ <, + explanation
Answer:- When they are placed in series.
When multiple emf sources are connected in series then the net or total emf is equal to the sum of their individual emfs .
Say if we have cells of emfs [tex]\epsilon_1[/tex] , [tex]\epsilon_2[/tex] , [tex]\epsilon_3[/tex] , [tex]\epsilon_4 [/tex] . . . . [tex]\epsilon_n[/tex]
Then the net emf is ,
[tex]\implies \underline{\underline{\green{\epsilon_{net}= \epsilon_1+ \epsilon_2+\dots +\epsilon_n}}}\\[/tex]
Additional information:-
If the emfs of n cells are equal and they are connected in series then the net emf is given by ,
[tex]\implies \epsilon_{net}= n\epsilon \\[/tex]
where ,
[tex]\epsilon[/tex] = emf of a single cell .Also , when n cells of emfs [tex]\epsilon_1[/tex] and [tex]\epsilon_2[/tex] . . . . . [tex]\epsilon_n[/tex] and internal resistances [tex]r_1[/tex] , [tex]r_2[/tex] . . . . . [tex]r_n[/tex] respectively are connected in parallel then the net emf is given by,
[tex]\implies \underline{\underline{\green{\epsilon_{net} = \left( \dfrac{1}{r_1}+\dfrac{1}{r_2}+\dots +\dfrac{1}{r_n}\right)^{-1}\left(\dfrac{\epsilon_1}{r_1}+\dfrac{ \epsilon_2}{r_2}+\dots +\dfrac{\epsilon_n}{r_n}\right)}}}\\[/tex]
Again suppose if we make a parallel arrangement of cells each having same emf then the net emf remains same that is equal to the emf of individual cell ( Why ? You can try yourself by using the above formula )
and we are done!
the beam of a laser pointer (or a helium-neon laser) would spread to a 610- km -diameter circle at the distance of the moon. that is approximately 20 % of the moon's diameter! the light intensity would be so low that it would not be possible to detect the tiny amount of light reflected back to earth by a small mirror. even with a laser much more powerful than a laser pointer, the laser spot on the moon needs to be no more than 2.0 km in diameter in order to detect the reflected light. to achieve this, what is the minimum possible diameter of the laser's exit aperture? continue to use 650 nm as the laser wavelength.
The minimum possible diameter of the laser's exit aperture to achieve a 2.0 km diameter spot on the moon is 2.4 meters.
What is the laser pointer? The laser pointer is a compact laser light-emitting device. A laser pointer operates on the principle of stimulated emission. It is possible to get a bright, coherent light beam when photons come together and stimulate one another's emission.
What is a Helium-Neon Laser? The He-Ne laser or Helium-Neon Laser is a gas laser in which a mixture of helium and neon is used as the active medium. This laser is widely used in research laboratories and industries due to its easy availability and low cost. The wavelength of light produced by He-Ne laser is 632.8 nm.
What is a laser beam? A laser beam is a coherent and collimated light beam of photons traveling in the same direction with the same frequency and amplitude. A laser beam emits light rays that can travel great distances with minimal dispersion, as well as exert an incredibly focused level of energy.
When a laser is pointed at the moon from Earth, the beam is so diffuse that the spot on the lunar surface is roughly 610 km in diameter, approximately 20% of the moon's diameter. The laser spot on the moon needs to be no more than 2.0 km in diameter in order to detect the reflected light.
Given that the wavelength of the laser beam is 650 nm. The minimum possible diameter of the laser's exit aperture can be determined using the formula of diffraction-limited beam radius: r = 1.22 * λ * f / D where, λ = 650 nm, the wavelength of the laser f = focal length of the beam D = diameter of the laser's exit aperture
The diameter of the laser's exit aperture is given by the formula: D = 1.22 * λ * f / r.
To achieve a 2.0 km diameter spot on the moon, the minimum possible diameter of the laser's exit aperture is 2.4 meters.
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G 13% part (g) using the numbers from the previous step, give a numeric answer for the time in seconds that elapse when the package, initially at rest, travels a distance of 2. 25 m down the ramp
The time required for the container to move 2.25 metres down the ramp is roughly 0.104 seconds.
From part (f), we have determined the final velocity of the package to be 1.38 m/s. Using this value along with the distance traveled (Δx = 2.25 m), we can calculate the time elapsed using the kinematic equation:
Δx = (vf² - vi²) / 2a
Substituting the values, we get:
2.25 = (1.38² - 0) / (2 * 0.087)
Solving for time (t), we get:
t = 2.25 * 0.087 / 1.897
t ≈ 0.104 seconds
Therefore, the time elapsed when the package travels a distance of 2.25 m down the ramp is approximately 0.104 seconds.
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A 25.00kg lead sphere is hanging from a hook by a thin wire 3.50m long, and is free to swing in a complete circle. Suddenly it is struck horizontally by a 7.00kg steel dart that embeds itself in the lead sphere. What must be the minimum initial speed of the dart so that the combination makes a complete circular loop after the collision?
To find the minimum initial speed of the dart so that the combination makes a complete circular loop after the collision, we can use the conservation of energy principle.
First, let's find the total mass of the system after the collision, which is the sum of the masses of the lead sphere and the steel dart:
m = 25.00 kg + 7.00 kg = 32.00 kg
Next, we need to find the height that the system needs to reach in order to make a complete circular loop. This height is equal to the length of the wire:
h = 3.50 m
Now, we can use the conservation of energy principle to find the minimum initial speed of the dart.
The initial kinetic energy of the system is equal to the final potential energy of the system at the top of the loop:
0.5 * m * v^2 = m * g * h
Solving for v, we get:
v = sqrt(2 * g * h)
Plugging in the values for m, g, and h, we get:
v = sqrt(2 * 9.81 m/s^2 * 3.50 m) = 8.30 m/s
Therefore, the minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 8.30 m/s.
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can you explain how he got 60/11 please! , i got boards tomorrow grade 10 . deciding to sit and study till morning :(!
The position of the image of the object would be 7.5 cm behind the mirror.
Position of the image of objects in a mirrorThe focal lengths of all convex mirrors are negative and are given by the following formula:
1/f = - (1/R)
where:
R is the radius of curvature of the mirror.Substituting for R in the equation, we are going to have:
1/f = -1/20 cm
f = -20 cm
Next, we can make use of the mirror formula to find the position of the image along the plane of the mirror:
The mirror formula goes thus:
1/f = 1/do + 1/di
where 'do' is the object distance and di is the image distance.
Substituting the values of f and di:
1/-20 cm = 1/12 cm + 1/di
Thus:
di = -7.5 cm
That the di is negative is an indication that the image is a virtual one that forms behind the mirror. In other words, the position of the image is 7.5 cm behind the mirror.
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3.5
An experiment was pero
of conductor on the current strength. A 200 mm length of nichrome
wire with diameter 0,3 mm is wound into a coil an attached to a
circuit. The potential difference is measured across the coil. The
experiment is repeated for a 200 mm length of copper wire of
diameter 0,3 mm. Temperature was kept constant. The following
results were obtained:
Current through each wire (A)
Potential difference across the
nichrome wire(V)
Potential difference across the copper
wire(V)
0,2 0,4 0,6 0,8 1,0
0,8 1,6 2,4 3,2 4,0
0,4 0,8 1,2 1,6 2,0
what is the independent variable here
The current flowing through each wire is the experiment's independent variable because it is the one that the experimenter is actively manipulating and controlling.
How does the resistance in the circuit change depending on the thickness of a piece of nichrome wire?The resistance is influenced by the wire's thickness, so the thicker the wire, the lower the resistance. Because less water can flow through a narrower pipe in a given length, there is more resistance in a narrower pipe.
Why does a nichrome not heat up in an electric circuit whereas a nichrome wire does?Due to the alloy composition of nichrome wire, its resistance is quite high. Because of this, it generates a lot of heat when current flows through it, making it extremely hot to the touch.
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If a net force of 24 N is applied to an object with a mass of 6 kg, then what will the resulting
acceleration be according to Newton's second law of motion?
a
b
C
d
6 m/s²
0.25 m/s²
24 m/s²
4 m/s²
Answer:
d. 4 m/s²
Explanation:
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Bumper car A (296 kg) moving +3.74 m/s makes an elastic collision with bumper car B (222 kg) moving +1.85 m/s. What is the velocity of car A after the collision?
I don't know sorry didn't make me want you say you didn't know how I feel about me being that way and that I didn't even want you say I was wrong and you didn't want me to be to have a good time
What specific question does the doctor ask Annie?
The doctor asks Annie if she has had any trouble with her eyes, like drooping.
In the given text, Dr. Jones asks Annie if she has had any trouble with her eyes, specifically if they have been drooping. This question suggests that the doctor is trying to assess if Annie has been experiencing symptoms of ptosis, which is a medical condition where the upper eyelid droops due to a weakness or paralysis of the muscles responsible for lifting the eyelid.
Ptosis can be a sign of several neurological conditions and can cause visual impairment or other complications. Therefore, the doctor's question indicates that he is trying to gather more information about Annie's symptoms to make a proper diagnosis and provide appropriate treatment.
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The question is incomplete, the complete question is:
Dr. Jones looked pensive and asked, “Have you had any trouble with your eyes? Like have they been drooping?”
Annie looked confused. “I have had a lot of eye strain and double vision recently. It gets blurry when I stare at the computer screen too long; I seem to get a zillion papers every week. I also think the chlorine level in
the pool is too high. Everyone on the team complains about it because, if your goggles come off , your eyes sting like mad.
The doctor smiled, “I swam before those goggles were even invented, so I know what you mean about stinging eyes. But, I think what you’re telling me goes beyond simple fatigue. I’m going to refer you to a neurologist at the hospital.”
A 60 litre steel gasoline tank is full of gas, so that both the tank and the gasoline
have a temperature of 15 °C. The amount of gasoline has been spilled by the time
they warm up to 35 °C will be:
(A) 50.2 litre
(B) 1.10 litre
(D) None
(C) 3.26 litre
Answer:
To solve this problem, we need to use the coefficient of thermal expansion for gasoline, which tells us how much the volume of gasoline will increase as its temperature increases. The coefficient of thermal expansion for gasoline is approximately 950 x 10^-6 /°C.
Using this information, we can calculate the increase in volume of gasoline as it warms up from 15°C to 35°C:
ΔV = V * α * ΔT
where V is the initial volume of gasoline (60 L), α is the coefficient of thermal expansion for gasoline (950 x 10^-6 /°C), and ΔT is the change in temperature (20°C).
ΔV = 60 * 950 x 10^-6 * 20
ΔV = 0.114 L
Therefore, the amount of gasoline spilled as it warms up from 15°C to 35°C is:
60 L - 0.114 L = 59.886 L
Explanation:
So the answer is (A) 50.2 litre.
Someone please help me thanks so much!!
The image tubes in television sets and computer displays. Until recently, the picture tube was the most versatile of them, capable of displaying numbers, characters, graphs, and both still and moving images.
Which type of tube is television picture tube?CRT stands for cathode-ray tube. The television image tube, which is used in household television receivers, is the most recognizable and ubiquitous type of cathode-ray tube.
LCD TVs first came in the early 2000s as the newer, superior TV with current technology. Nonetheless, tube Televisions were the most popular at the time. Because it was just 15 years ago, many of these TVs are still in use. We'll go into why you should replace your tube TV and the benefits of doing so further down.
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Is the earth round? Or is it flat like some people say
Answer: The Earth is an oblate spheroid, meaning it is roughly spherical in shape but flattened at the poles and bulges at the equator. This shape has been scientifically proven through centuries of evidence and observations. While some people may claim that the Earth is flat, this idea is not supported by scientific evidence.
Which of the arrows is in the direction of the net force on charge b?
The correct answer is option: e. Because, this force always acts along line joining the two charges. For like charges, the force is repulsive in nature.
The Coulomb's law states how charges interact with each other. That law states that: [tex]F =q1q24πϵ0r2[/tex]
If the charges are like , the force will be repulsive, meaning that each charge will exert a force on the other to push the two of them apart. If charges are opposite , they will exert an attractive force on each other. G or unlike charges, the force is attractive as shown below: ( as Shown in image attached to question), As we know none of the arrow moves in the direction of the net force. Hence, the correct answer is option: e
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calculate the magnitude of the linear momentum for the following cases: (a) a proton with mass equal to 1.67 3 10227 kg, moving with a speed of 5.00 3 106 m/s; (b) a 15.0-g bullet moving with a speed of 300 m/s; (c) a 75.0-kg sprinter running with a speed of 10.0 m/s; (d) the earth (mass 5 5.98 3 1024 kg) moving with an orbital speed equal to 2.98 3 104 m/s.
To calculate the magnitude of the linear momentum for each of the cases, you need to use the following equation:
Linear momentum (p) = mass (m) x velocity (v)
Case (a): Linear momentum (p) = 1.67 x 10-27 kg x 5.00 x 106 m/s = 8.35 x 10-22 kg m/s
Case (b): Linear momentum (p) = 0.015 kg x 300 m/s = 4.5 kg m/s
Case (c): Linear momentum (p) = 75.0 kg x 10.0 m/s = 750 kg m/s
Case (d): Linear momentum (p) = 5.98 x 1024 kg x 2.98 x 104 m/s = 1.78 x 1029 kg m/s
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Why or why isn’t space exploration important for the people in the movie interstellar? Why or why isn’t space exploration important in todays society? Defend your answer?
In the movie Interstellar, space exploration plays a crucial role in humanity's survival. Earth is on the brink of environmental collapse, and the protagonist, Cooper, must embark on a space mission to find a new habitable planet for humanity.
For the people in the movie, space exploration is not only essential but also the only hope for the survival of the human race.
In today's society, space exploration is also crucial for several reasons. First and foremost, space exploration provides us with a deeper understanding of the universe and our place in it. It allows us to explore the unknown and discover new things, which can lead to breakthroughs in science and technology. Space exploration has already led to countless technological advancements, such as GPS, solar panels, and medical equipment.
Moreover, space exploration has practical applications in areas such as climate change, national security, and disaster response. For instance, satellite imagery can help track natural disasters and aid in disaster response efforts. Satellites can also help us monitor and understand climate change by gathering data on temperature, weather patterns, and greenhouse gas emissions.
Lastly, space exploration inspires and motivates people, especially young people, to pursue careers in science, technology, engineering, and mathematics (STEM) fields. It can also foster international cooperation and collaboration, as countries work together on space missions.
Space exploration is important for both the people in the movie Interstellar and today's society. It can provide us with a deeper understanding of the universe, lead to technological advancements, and have practical applications in areas such as climate change and disaster response. It can also inspire and motivate people to pursue careers in STEM fields and foster international cooperation. Therefore, investing in space exploration is crucial for the betterment of humanity.
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will a current necessarily be detected if the cathode is illuminated with blue light? select the correct answer and explanation. will a current necessarily be detected if the cathode is illuminated with blue light? select the correct answer and explanation. photons of blue light have less energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there could be no current with blue light. photons of blue light have more energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there will also be a current with blue light. photons of blue light have less energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there will also be a current with blue light. photons of blue light have more energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there could be no current with blue light.
The correct option is (b). Photons of blue light have more energy than photons of green light. So, if there is a current in a photoelectric-effect apparatus with green light, then there will also be a current with blue light.
What is the Photoelectric Effect?The photoelectric effect is the process where a material emits electrons when light is shone on it. The effect is generally associated with the emission of electrons when a metal surface is illuminated. In other words, the photoelectric effect refers to the emission of electrons from a metal when it is illuminated with light.
The energy of each photon is directly proportional to its frequency. Therefore, the photoelectric effect depends on the frequency of the incident light. If the frequency of the light is high enough, electrons can escape the surface of the metal. However, the number of electrons emitted is proportional to the intensity of the light, not its frequency.
Therefore, in this case, the cathode is illuminated with blue light. As photons of blue light have more energy than photons of green light, there will also be a current with blue light.
Thus, a current will necessarily be detected if the cathode is illuminated with blue light since photons of blue light have more energy than photons of green light.
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