Answer:
3 kg
Step-by-step explanation:
Inverse relation:
y = k/x
In this case, the acceleration is inversely proportional to the mass, so using a for acceleration and m for mass, we have:
a = k/m
We need to find the value of k.
We use the given information to find k.
a = 9 m/s^2 when m = 5 kg
a = k/m
9 = k/5
k = 9 * 5 = 45
Now we can complete our equation:
a = 45/m
For a = 15 m/s^2, m = ?
15 = 45/m
15m = 45
m = 45/15
m = 3
Answer: 3 kg
Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
Answer:
The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is [tex]z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)[/tex].
The domain of the function is all real numbers and its range is between -4 and 5.
The graph is enclosed below as attachment.
Step-by-step explanation:
Let be [tex]z (x) = \cos x[/tex] the base formula, where [tex]x[/tex] is measured in sexagesimal degrees. This expression must be transformed by using the following data:
[tex]T = 180^{\circ}[/tex] (Period)
[tex]z_{min} = -4[/tex] (Minimum)
[tex]z_{max} = 5[/tex] (Maximum)
The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of [tex]2\pi[/tex] radians. In addition, the following considerations must be taken into account for transformations:
1) [tex]x[/tex] must be replaced by [tex]\frac{2\pi\cdot x}{180^{\circ}}[/tex]. (Horizontal scaling)
2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:
[tex]\Delta z = \frac{z_{max}-z_{min}}{2}[/tex]
[tex]\Delta z = \frac{5+4}{2}[/tex]
[tex]\Delta z = \frac{9}{2}[/tex]
3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)
[tex]z_{m} = \frac{z_{min}+z_{max}}{2}[/tex]
[tex]z_{m} = \frac{1}{2}[/tex]
The new function is:
[tex]z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)[/tex]
Given that [tex]z_{m} = \frac{1}{2}[/tex], [tex]\Delta z = \frac{9}{2}[/tex] and [tex]T = 180^{\circ}[/tex], the outcome is:
[tex]z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)[/tex]
The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.
if the focus of an ellipse are (-4,4) and (6,4), then the coordinates of the enter of the ellipsis are
Answer:
The center is (1,4)
Step-by-step explanation:
The coordinates of the center of an ellipse are the coordinates that are in the middle of the two focus.
Then if we have a focus on [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], we can say that the coordinates for x and y can be calculated as:
[tex]x=\frac{x_1+x_2}{2}\\ y=\frac{y_1+y_2}{2}[/tex]
So, replacing [tex](x_1,y_1)[/tex] by (-4,4) and [tex](x_2,y_2)[/tex] by (6,4), we get that the center is:
[tex]x=\frac{-4+6}{2}=1\\ y=\frac{4+4}{2}=4[/tex]
tje mean of 12 scores is 8.8 what is the sum of tue 12 scores
Answer:
105.6
Step-by-step explanation:
If the mean is 8.8, than that means that in total the sum must be (8.8 * 12) which equals 105.6.
This is because the sum of all the numbers in a list divided by the amount of numbers in a list equals the mean.
A sample of 150 CBC students was taken, and each student filled out a
survey. The survey asked students about different aspects of their college
and personal lives. The experimenter taking the survey defined the
following events:
A=The student has children
B = The student is enrolled in at least 12 credits
C = The student works at least 10 hours per week
The student found that 44 students in the sample had children, 73 were
enrolled in at least 12 credits, and 105 were working at least 10 hours per
week. The student also noted that 35 students had children and were
working at least 10 hours per week.
Calculate the probability of the event BC for students in this sample. Round
your answer to four decimal places as necessary.
Answer:
The probability of the event BC
= the probability of B * C = 48.6667% * 70%
= 34.0667%
Step-by-step explanation:
Probability of A, students with children = 44/150 = 29.3333%
Probability of B, students enrolled in at least 12 credits = 73/150 = 48.6667%
Probability of C, students working at least 10 hours per week = 105/150 = 70%
Therefore, the Probability of BC, students enrolled in 12 credits and working 10 hours per week
= 48.6667% * 70%
= 34.0667%
Find the slope of the line that passes through (1, 14) and (4,9)
Which two numbers in the points represent x values? Select both in the
list.
In any coordinate pair, the first number is the x-value and the second number is the y-value.
To find the slope, simply take the difference of the y values and divide by the difference in the x values: (14-9)/(1-4) is equal to -5/3.
The slope of the line that passes through (1, 14) and (4,9) is -5/3.
It is find the slope of the line.
what is slope?The slope of any line, ray, or line segment is the ratio of the vertical to the horizontal distance between any two points on it (“slope equals rise over run”).
The slope is always calculated from the rise divided by the run. Typically, the equation is presented as:
m = Rise/Run
If you have two points, the points should be [tex]P_{1} (x_{1} ,y_{1} )[/tex] and [tex]P_{2} (x_{2} ,y_{2} )[/tex] So, the equation would be:
[tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
In any coordinate pair, the first number is the x-value and the second number is the y-value.
The difference of the y values and divide by the difference in the x values:
m=(14-9)/(1-4) is equal to -5/3.
The slope of the line that passes through (1, 14) and (4,9) is -5/3.
Learn more about slope here:
https://brainly.com/question/17114095
#SPJ5
differentiate with respect to X
[tex] \sqrt{ \frac{cos2x}{1 +sin2x } } [/tex]
Power and chain rule (where the power rule kicks in because [tex]\sqrt x=x^{1/2}[/tex]):
[tex]\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'[/tex]
Simplify the leading term as
[tex]\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}[/tex]
Quotient rule:
[tex]\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}[/tex]
Chain rule:
[tex](\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)[/tex]
[tex](1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)[/tex]
Put everything together and simplify:
[tex]\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}[/tex]
[tex]=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}[/tex]
[tex]=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}[/tex]
[tex]=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}[/tex]
[tex]=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}[/tex]
[tex]=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}[/tex]
[tex]=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}[/tex]
Which interval contains a local minimum for the graphed
function?
Answer:
[2.5 ,4]
Step-by-step explanation:
The graph in this interval has a vertex while opening up wich means it's a minimum
plz help.... 2|x-3|-5=7
Answer:
x = -3 and x = 9.
Step-by-step explanation:
2|x - 3| - 5 = 7
2|x - 3| = 12
|x - 3| = 6
x - 3 = 6
x = 9
-(x - 3) = 6
-x + 3 = 6
-x = 3
x = -3
Hope this helps!
Answer:
x=9 x=-3
Step-by-step explanation:
2|x-3|-5=7
Add 5 to each side
2|x-3|-5+5=7+5
2|x-3|=12
Divide by 2
2/2|x-3|=12/2
|x-3|=6
There are two solutions to an absolute value equation, one positive and one negative
x-3 =6 x-3 = -6
Add 3 to each side
x-3+3 = 6+3 x-3+3 = -6+3
x=9 x = -3
Which statement must be true if ?
A.
B.
C.
D.
Answer:
D
Step-by-step explanation:
D because they are congruent try measuring it.
Answer:
[tex]\boxed{\mathrm{D}}[/tex]
Step-by-step explanation:
The triangles are congruent.
The angles that are corresponding on both triangles must be congruent.
Angle Q in triangle PQR must be congruent to angle T in triangle STU.
Noah tried to prove that cos(θ)=sin(θ) using the following diagram. His proof is not correct.
Answer:
The first statement is incorrect. They have to be complementary.
Step-by-step explanation:
You can't say the measure of angle B is congruent to theta because it is possible for angles in a right triangle to be different.
You can only say that what he said is true if the angle was 45 degrees, but based on the information provided it is not possible to figure that out.
The other two angles other than the right angle in a right triangle have to add up to 90 degrees, which is the definition of what it means for two angles to be complementary. A is the correct answer.
Answer:
[tex]\boxed{\sf A}[/tex]
Step-by-step explanation:
The first statement is incorrect. The angle B is not equal to theta θ. The two acute angles in the right triangle can be different, if the triangle was an isosceles right triangle then angle B would be equal to theta θ.
What is the input value other than -7, for which h (x) = 3?
Answer:
x=5
Step-by-step explanation:
h (x) = 3
We want the x values where y =3
The values are x = -7 and x=5
The _________ measures the strength and direction of the linear relationship between the dependent and the independent variable.
Answer:
Correlation Coefficient
Step-by-step explanation:
please help it's Factorisation with Numbers
Answer:
C.
6a + 18x + 18p
Step-by-step explanation:
3(2a + 6 (x + p)) firs multiply (x + p) with 6
3 (2a + 6x + 6z) now multiply inside the parenthesis with 3 and the answer would be 6a + 18x + 18p
Use the Alternating Series Remainder Theorem to determine the smallest number of terms required to approximate the sum of the series with an error of less than 0.0001.
Answer:
yeyyyaya
Step-by-step explanation:
In the figure below, which term best describes point L?
Explanation:
The tickmarks show which pieces are congruent to one another, which in turn show the segments have been bisected (cut in half). The square angle markers show we have perpendicular segments. So we have three perpendicular bisectors. The perpendicular bisectors intersect at the circumcenter. The circumcenter is the center of the circumcircle. This circle goes through all three vertex points of the triangle.
A useful application is let's say you had 2 friends and you three wanted to pick a location to meet for lunch. Each person traveling from their house to the circumcenter's location will have each person travel the same distance. We say the circumcenter is equidistant from each vertex point of the triangle. In terms of the diagram, LH = LJ = LK.
Answer: B.) Circumcenter
Step-by-step explanation:
Graph image of figure using transformation given. Reflection across x-axis.
Answer:
Q(1,1), N(3,2) A(2,5)
Step-by-step explanation:
Suppose that you expect SugarCane stock price to decline. So you decide to ask your broker to short sell 2000 shares. The current market price is $40. The proceeds from the short sale $80,000 is credited into your account. However, a few days later the market price of the stock jumps to $80 per share and your broker asks you close out your position immediately. What is your profit or loss from this transaction?
Answer:
Loss = $80000
Step-by-step explanation:
To determine if it's a profit or loss is simple.
He predicted the sugar cane stock to fall so he sold , but few days later the stock grew and went bullish.
He sold at$ 40 for 2000 shares
=$ 80000
But the stock went up to $80 per share that is gaining extra $40
So it was actually a loss.
The loss is =$40 * 2000
The loss = $80000
Please help!!
Find the value of x.
X=
Answer:
Step-by-step explanation:
Hello,
We can write three equations thanks to Pythagoras
[tex]AB^2+AC^2=(7+3)^2\\x^2+7^2=AB^2\\x^2+3^2=BC^2\\[/tex]
So it comes
[tex]x^2+7^2+x^2+3^2=(7+3)^2\\\\2x^2=100-49-9=42\\\\x^2 = 42/2=21\\\\x = \sqrt{\boxed{21}}\\[/tex]
Hope this helps
Answer:
x = [tex]\sqrt{21}[/tex]
Step-by-step explanation:
Δ BCD and Δ ABD are similar thus the ratios of corresponding sides are equal, that is
[tex]\frac{BD}{AD}[/tex] = [tex]\frac{CD}{BD}[/tex] , substitute values
[tex]\frac{x}{7}[/tex] = [tex]\frac{3}{x}[/tex] ( cross- multiply )
x² = 21 ( take the square root of both sides )
x = [tex]\sqrt{21}[/tex]
The altitude of an airplane is decreasing at a rate of 41 feet per second. What is the change in altitude of the airplane over a period of 32 seconds?
Answer:
1312 feet
Step-by-step explanation:
41 ft=1 sec
how about 32 sec
41 x 32=1312/1=1312
a person can do a job in 6 day days . another can do the same job in 4days . if they work together, how long do they need to finish the job?
Answer:
It will take them 2 2/5 days working together
Step-by-step explanation:
To find the time worked
1/a + 1/b = 1/t
Where a and b are the times worked individually and t is the time worked together
1/4 + 1/6 = 1/t
Multiply each side by 12t to clear the fractions
12t( 1/4 + 1/6 = 1/t)
3t + 2t =12
Combine like terms
5t = 12
Divide by 5
t = 12/5
t = 2 2/5
It will take them 2 2/5 days working together
6th grade math help me, please :D
Answer:
option: D
51200
Step-by-step explanation:
64000 x 80/100 = 51200
Answer:
Hi there!!!
your required answer is option D.
explanation see in picture.
I hope it will help you...
Given that r = ( 7, 3, 9) and v = ( 3, 7, -9), evaluate r + v
a. (-21,-21,81)
b. (10,10,0)
c. (21,21,-81)
d. (-10,-10,0)
Answer:
b. (10,10,0)
Step-by-step explanation:
r+v can be evaluated if the vectors/matrices have the same dimensions.
These do. They are both 1 by 3 vectors.
Just add first to first in each.
Just add second to second in each.
Just add third to third in each.
Example:
(5,-5,6)+(1,2,3)
=(5+1,-5+2,6+3)
=(6,-3,9)
Done!
In general, (a,b,c)+(r,s,t)=(a+r,b+s,c+t).
r+v
=(7,3,9)+(3,7,-9)
=(7+3,3+7,9+-9)
=(10,10,0)
Done!
Square root of 5 + square root of 3 the whole divided by sqaure root of 5 - square root of 3
Answer:
The answer is 4 + √15 .
Step-by-step explanation:
You have to get rid of surds in the denorminator by multiplying it with the opposite sign :
[tex] \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } [/tex]
[tex] = \frac{ {( \sqrt{5} + \sqrt{3} ) }^{2} }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) } [/tex]
[tex] = \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} )( \sqrt{3}) + {( \sqrt{3}) }^{2} }{ {( \sqrt{5}) }^{2} - { (\sqrt{3} )}^{2} } [/tex]
[tex] = \frac{5 + 2 \sqrt{15} + 3 }{5 - 3} [/tex]
[tex] = \frac{8 + 2 \sqrt{15} }{2} [/tex]
[tex] = 4 + \sqrt{15} [/tex]
Connor has a collection of dimes and quarters with a total value of $6.30. The number of dimes is 14 more than the number of quarters. How many of each coin does he have?
Answer:
14 Quarters and 28 dimes
Step-by-step explanation: 14 quarters $3.50
28 dimes is $2.80 total is $6.30
Help please someone I have solved this multiple times factoring out the quadratic equations and I keep getting m as -1. But the correct answer says m is -5.
Answer: m = -5
Step-by-step explanation:
[tex]\dfrac{m+3}{m^2+4m+3}-\dfrac{3}{m^2+6m+9}=\dfrac{m-3}{m^2+4m+3}\\\\\\\dfrac{m+3}{(m+3)(m+1)}-\dfrac{3}{(m+3)(m+3)}=\dfrac{m-3}{(m+3)(m+1)}\quad \rightarrow m\neq-3, m\neq-1[/tex]
Multiply by the LCD (m+3)(m+3)(m+1) to eliminate the denominator. The result is:
(m + 3)(m + 3) - 3(m + 1) = (m - 3)(m - 3)
Multiply binomials, add like terms, and solve for m:
(m² + 6m + 9) - (3m + 3) = m² - 9
m² + 6m + 9 - 3m - 3 = m² - 9
m² + 3m + 6 = m² - 9
3m + 6 = -9
3m = -15
m = -5
Find the axis of symmetry and vertex for the parabola y=−5x2+30x+7.
Answer:
axis of symmetry x=3
vertex (3, 52)
Step-by-step explanation:
y = -5x² + 30x + 7
x = -b/2a = -30/2(-5) = -30/-10 = 3
y = -5(3)² + 30(3) + 7
y = -45 + 90 + 7
y = 52
Please Help!!! Find X for the triangle shown.
Answer:
[tex] x = 2 [/tex]
Step-by-step explanation:
Given a right-angled triangle as shown above,
Included angle = 60°
Opposite side length = 3
Adjacent side length = x
To find x, we would use the following trigonometric ratio as shown below:
[tex] tan(60) = \frac{3}{x} [/tex]
multiply both sides by x
[tex] x*tan(60) = \frac{3}{x}*x [/tex]
[tex] x*tan(60) = 3 [/tex]
Divide both sides by tan(60)
[tex] \frac{x*tan(60)}{tan(60} = \frac{3}{tan(60} [/tex]
[tex] x = \frac{3}{tan(60} [/tex]
[tex] x = 1.73 [/tex]
[tex] x = 2 [/tex] (approximated to whole number)
1. Which of the following ordered pairs are solutions to the system of equations below?
4x + 4y = -9
Y = 2x - 13
A : (-3, -7)
B : (3-7)
C : (3,7)
D : (-3,7)
Answer:
43\ 12 , 35/ 6
Step-by-step explanation:
43\ 12 , 35/ 6
Answer: B: (3, -7)
Step-by-step explanation:
4x + 4y = -9
y = 2x - 13
Use Substitution:
4x + 4(2x - 13) = -9
4x + 8x - 52 = -9
12x - 52 = -9
12x = 43
[tex]x=\dfrac{43}{12}[/tex]
None of the options provided are valid so either there is a typo on your worksheet or you typed in one of the equations wrong.
Plan B: Input the choices into the equation to see which one makes a true statement.
4x + 4y = -9
A) (x, y) = (-3, -7)
4(-3) + 4(-7) = -9
-12 + -28 = -9
-40 ≠ -9
B) (x, y) = (3, -7)
4(3) + 4(-7) = -9
12 + -28 = -9
-16 ≠ -9
C) (x, y) = (3, 7)
4(3) + 4(7) = -9
12 + 28 = -9
40 ≠ -9
D) (x, y) = (-3, 7)
4(-3) + 4(7) = -9
-12 + 28 = -9
16 ≠ -9
Obviously there is something wrong with the first equation because none of the options provide a true statement.
y = 2x - 13
A) (x, y) = (-3, -7)
-7 = 2(-3) - 13
-7 = -6 -13
-7 ≠ -19
B) (x, y) = (3, -7)
-7 = 2(3) - 13
-7 = 6 -13
-7 = -7 this works!!!
C) (x, y) = (3, 7)
7 = 2(3) - 13
7 = 6 -13
7 ≠ -7
D) (x, y) = (-3, 7)
7 = 2(-3) - 13
7 = -6 -13
7 ≠ -19
Option B is the only one that provides a true statement so this must be the answer.
Solve the equation and give the solution 6x – 3y = 3 –2x + 6y = 14
Answer:
x=3.9 or 39/10 and y=3.13333 or 47/15
Step-by-step explanation:
Since both expressions (6x-3y) and (3-2x+6y) are equal to 14, separate the equations:
6x-3y=14 and 3-2x+6y=14
Simplify the equations
6x-3y=14 and -2x+6y=11
Now, line the equations up and pick a variable (either x or y) to eliminate
6x-3y=14
-2x+6y=11
In this case, let's eliminate y first. To do so make the y values in both equations the same but with opposite signs. Make both be 6y but one is +6y and the other -6y
Multiply (6x-3y=14) by 2 to get:
12x-6y=28
Line the equations up and add or subtract the terms accordingly
12x-6y=28
-2x+6y=11
This becomes:
10x+0y=39
Isolate for x
x= 39/10 or x= 3.9
Now substitute the x value into either of the original equations
6x-3y=14
6(3.9)- 3y=14
Isolate for y
23.4-14=3y
3y= 9.4
y= 3.1333 (repeating) or y= 47/15
Answer: x = 39/10, y = 94/30
Step-by-step explanation:
6x - 3y = 3 - 2x + 6y,
Now solving this becomes
6x + 2x -3y - 6y = 3
8x - 9y = 3 ------------------- 1
3 - 2x + 6y. = 14
-2x + 6y = 14 - 3
-2x. + 6y = 11
Now multiply both side by -1
2x. - 6y = -11 ----------------- 2
Solve equations 1 & 2 together
8x - 9y. = 3
2x - 6y = -11
Using elimination method
Multiply equation 1 through by 2 ,and equation 2 be multiplied by 8
16x - 18y = 6
-16x - 48y = -88 ------------------------- n, now subtract
30y = 94
Therefore. y = 94/30.
Now substitute for y in equation 2
2x - 6y = -11
2x - 6(94/30) = -11
2x - 94/5 = -11
Now multiply through by 5
10x - 94 = -55
10x = -55 + 94
10x = 39
x = 39/10
Determine which expression could represent a polynomial with a factor of (x - √3i)
Answer:
Option (3)
Step-by-step explanation:
[tex](x-i\sqrt{3})[/tex] is a factor of a polynomial given in the options, that means a polynomial having factor as [tex](x-i\sqrt{3})[/tex] will be 0 for the value of x = [tex]i\sqrt{3}[/tex].
Option (1),
3x⁴ + 26x² - 9
= [tex]3(i\sqrt{3})^{4}+26(i\sqrt{3})^2-9[/tex] [For x = [tex]i\sqrt{3}[/tex]]
= 3(9i⁴) + 26(3i²) - 9
= 27 - 78 - 9 [Since i² = -1]
= -60
Option (2),
4x⁴- 11x² + 3
= [tex]4(i\sqrt{3})^4-11(i\sqrt{3})^2+3[/tex]
= 4(9i⁴) - 33i² + 3
= 36 + 33 + 3
= 72
Option (3),
4x⁴ + 11x² - 3
= [tex]4(i\sqrt{3})^4+11(i\sqrt{3})^2-3[/tex]
= 4(9i⁴) + 33i² - 3
= 36 - 33 - 3
= 0
Option (4),
[tex]3x^{4}-26x^{2}-9[/tex]
= [tex]3(i\sqrt{3})^4-26(i\sqrt{3})^{2}-9[/tex]
= 3(9i⁴) - 26(3i²) - 9
= 27 + 78 - 9
= 96
Therefore, [tex](x-i\sqrt{3})[/tex] is a factor of option (3).