Need help with 9.2 Lesson Practice edhesive asap please

Answers

Answer 1

Answer:

Can you add an attachment please

Answer 2

In this exercise we have to use the computer language knowledge in python, so the code is described as:

This code can be found in the attached image.

So the code can be described more simply below, as:

height = []

height.append([16,17,14])

height.append([17,18,17])

height.append([15,17,14])

print(height)

See more about python at brainly.com/question/26104476

Need Help With 9.2 Lesson Practice Edhesive Asap Please
Need Help With 9.2 Lesson Practice Edhesive Asap Please

Related Questions

The variable strFirst's scope is _____.

Answers

pretty sure it’s d, hope this helps

Answer:

- the usernameMaker function

Explanation:

When you look at the code, you can see it's located alongside the usernameMaker. It it only utilized then, therefore being it's scope. For reassurance, it's also correct on Edge.

I hope this helped!

Good luck <3

Write an algorithm (pseudo-code) that takes an unsorted list of n integers and outputs a sorted list of all duplicate integers. There must be no duplicates in the output list, also the output list should be a sorted list. The algorithm must run in O(n) time. Show your analysis of the running time. Note: Assume that inputs are integer values from 0 to 255. (Hint: use the concept that being used in the separate chaining)

Answers

Answer:

brainliest if it did help you

Explanation:

Given array : A[0...n-1]Now, create a count array Cnt[0...n-1]then, initialize Cnt to zero

for(i=0...n-1)

Cnt[i]=0 ---------O(n) time

Linearly traverse the list and increment the count of respected number in count array.

for(i=0...n-1)

Cnt[A[i]]++; ---------O(n) time

Check in the count array if duplicates exist.

for(i=0...n-1){

if(C[i]>1)

output (i); -----------O(n) time

}

analysis of the above algorithm:

Algorithm takes = O(1 + n + n + n)

                           = O(n)          

//java code

public class SortIntegers {

  public static void sort(int[] arr) {

    int min = arr[0];

    int max = arr[0];

    for (int i = 0; i < arr.length; ++i) {

      if (arr[i] > max) {

        max = arr[i];

      }

      if (arr[i] < min) {

        min = arr[i];

      }

    }

    int counts[] = new int[max - min + 1];

    for (int i = 0; i < arr.length; ++i) {

      counts[arr[i] - min]++;

    }

    for (int i = 0; i < counts.length; ++i) {

      if (counts[i] > 1) {

        System.out.print((i + min) + " ");

      }

    }

    

    System.out.println();

  }

  public static void main(String[] args) {

    sort(new int[] { 5, 4, 10, 2, 4, 10, 5, 3, 1 });

  }

}

Taran is concerned with the security of his macros in a database. Which security option could he use to provide protection?

digital signatures
hide database objects
start-up options
secure VBA code

Answers

Answer:security VBA code

Explanation:

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