Need help on this…. Question pls help??

Need Help On This. Question Pls Help??

Answers

Answer 1

The segment lengths for this problem are given as follows:

AB = 7.AE = 9.BC = 10.05.

How to calculate the distance between two points?

Suppose that we have two points of the coordinate plane, and the ordered pairs have coordinates given by [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex].

The shortest distance between them is given by the equation presented as follows, derived from the Pythagorean Theorem:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Hence the length of segment AB is given as follows:

[tex]AB = \sqrt{(2 - (-5))^2 + (4 - 4)^2} = 7[/tex]

The length of segment AE is given as follows:

[tex]AE = \sqrt{(-5 - (-5))^2 + (4 - (-5))^2} = 9[/tex]

The length of segment BC is given as follows:

[tex]BC = \sqrt{(5-4)^2 + (5 - (-5))^2} = 10.05[/tex]

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Related Questions

Find the solution of the exponential equation
5^-x/16=5
in terms of logarithms, or correct to four decimal places.

x= ------------


here is the picture if you need it.

Answers

The solution of the exponential equation is x = -16

Finding the solution of the exponential equation

From the question, we have the following parameters that can be used in our computation:

5^-x/16=5

Take the logarithm of both sides of the equation

So, we have the following representation

-x/16 log(5) = log(5)

Divide both sides of the equation by log(5)

-x/16 = 1

So, we have

x = -16 * 1

Evaluate

x = -16

Hence, the solution to the equation is x = -16

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A student is being randomly selected. The school has 1000 students. Thirty-two students ride on bus 7. Forty students ride on bus 10. Three hundred students walk to school.
What is the probability that the student either rides on bus 7 or rides on bus 10?

Answers

Answer:

The answer is 2,000,

Step-by-step explanation:

Probability :- Probability is a way to gauge how likely something is to happen. It is represented by a number between [tex]0[/tex] and [tex]1[/tex], with [tex]0[/tex] denoting an impossibility and [tex]1[/tex] denoting a certainty. By dividing the number of favorable outcomes by the total number of possible outcomes, the probability of an event is determined.

A total of  [tex]32 + 40 + 300 = 372[/tex]  children either take bus number seven, bus number ten, or walk to school.

The proportion of students that ride bus [tex]7[/tex] or bus [tex]10[/tex] to the total number of students determines the likelihood that a student will board either bus [tex]7[/tex]or bus [tex]10[/tex].

[tex]P(taking bus number seven or ten) = (32 + 40) / 1000[/tex]

[tex]P(taking bus number seven or ten) = 72/1000[/tex]

[tex]P(using bus number 7 or ten) = 0.072[/tex]

Therefore, the probability that the student either rides on bus 7 or rides on bus 10 is 0.072 or 7.2%.

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Find the solutions of the equation in the interval [-2,2] cot(x)= square root 3


X=?

Answers

The solution of the function on the interval is x = 0.524 radians.

What is the solutions of the equation in the interval [-2,2]?

The solution of the function on the interval is calculated as follows;

cot(x)= √3

1/tan(x) = √3

Simplify the expression as follows;

1 = √3tan(x)

tan(x) = 1/√3

The solutions of this equation in the interval [-2,2], is calculated as;

x = tan⁻¹(1/√3)

x = 0.524 radians

Another solution of x;

x = tan⁻¹(1/√3) + π = 3.67 radians

This value is not in the given interval, so there is only one solution to the equation cot(x) = √3 in the interval [-2,2], which is approximately x = 0.524 radians.

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Find the determinant of a 10 x 10 matrix which had a 2 in each main diagonal entry and zeros everywhere else.

Answers

The determinant of the given 10 x 10 matrix is 1024.

What is a matrix?

A matrix is described as  a rectangular array or table with rows and columns and numbers, symbols, or expressions that is used to represent a mathematical object or a property of such an object.

We apply the knowledge that the determinant of a diagonal matrix is the product of its diagonal entries in order to find the determinant of a 10 x 10 matrix with 2s on the main diagonal and zeros elsewhere,

Determinant = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2

We then calculate for the product and have:

Determinant = [tex]2 ^ 1^0[/tex] = 1024

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What is the equation of the line shown in the coordinate plane below?
a=y=6x
b=y=-6x
c=y=1/6x
d=y=-1/6 x
Please show your work.

Answers

Answer:

your answer is c=y=1/6x

Simplify:
-$4500 + $3000 + (-$800)

Answers

-$2300 because - -$4500+$3000+(-$800)=2300

Please help me it’s due today!!!

Answers

Diagonals that bisect each other: Rhombus, Rectangle, Square.

Diagonals that bisect each other and are congruent: Rectangle, Square.

Diagonals that bisect each other and are perpendicular to each other: Square.

A parallelogram does not necessarily have diagonals that bisect each other.

A rhombus has diagonals that bisect each other.

This means that the diagonals intersect at their midpoints.

A rectangle has diagonals that bisect each other.

Additionally, the diagonals of a rectangle are congruent, meaning they have the same length.

A square has diagonals that bisect each other.

The diagonals of a square are congruent and perpendicular to each other.

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what value of x is in the solution set of the inequality 2(3x-1)>4x-6

Answers

Answer:  the solution set of the inequality 2(3x-1)>4x-6 is all values of x greater than -2.

Step-by-step explanation:  To solve the inequality 2(3x-1)>4x-6, we first simplify the left side by distributing the 2, which gives us 6x-2. Substituting this back into the original inequality, we get:

6x-2 > 4x-6

Next, we isolate the variable term (6x) by subtracting 4x from both sides:

2x-2 > -6

Then, we add 2 to both sides to isolate the variable term completely:

2x > -4

Finally, we divide both sides by 2 to solve for x:

x > -2

Therefore, the solution set of the inequality 2(3x-1)>4x-6 is all values of x greater than -2.

approximate the area under the curve y=x^3 from x=3 to x=6

Answers

To approximate the area under the curve y=x^3 from x=3 to x=6, we can use the midpoint rule with four subintervals.First, we need to find the width of each subinterval:delta x = (6 - 3) / 4 = 0.75Next, we can find the midpoint of each subinterval:x1 = 3 + 0.5 * delta x = 3.375

x2 = x1 + delta x = 4.125

x3 = x2 + delta x = 4.875

x4 = x3 + delta x = 5.625Now, we can evaluate the function at each midpoint:y1 = x1^3 = 40.39

y2 = x2^3 = 71.25

y3 = x3^3 = 106.29

y4 = x4^3 = 146.48Finally, we can use the midpoint rule formula to approximate the area:A ≈ delta x * (y1 + y2 + y3 + y4)

= 0.75 * (40.39 + 71.25 + 106.29 + 146.48)

= 267.98Therefore, the approximate area under the curve y=x^3 from x=3 to x=6 is 267.98 square units.

Please help!!! I will give points I need help asap!!!!

Answers

Answer:

[tex]x=(x-3)^{\frac{9}{5}}[/tex]

Step-by-step explanation:

The first thing we are going to do is change both sides of the equation to be base (x-3):

[tex](x-3)^{log_{(x-3)}(x)}=(x-3)^{\frac{9}{5}}[/tex].

Now, since the log is in base (x-3), the base (x-3) and the log cancel out:

[tex]x = (x-3)^\frac{9}{5}[/tex]

This is the final answer.

Mrs lucas classroom is a rectangle that measures by 9 feet by 12 feet what is the diagonal distance across the floor

Answers

Answer:

15 feet

Step-by-step explanation:

a^2+b^2=c^2

9^2+12^2=c^2

81+144=c^2

225=c^2

15=c

distance across floor =15 feet

The circle has center O. Its radius is 2 m, and the central angle a measures 160°. What is the area of the shaded region?
Give the exact answer in terms of
, and be sure to include the correct unit in your answer.

Answers

Answer:

Area_shaded_region = 2 * (√(1 - cos^2(4π/9))) - (16/9)π m^2

Step-by-step explanation:

To find the area of the shaded region, we need to subtract the area of the sector from the area of the triangle formed by the radius and the two radii connecting to the endpoints of the central angle.

First, let's find the area of the sector:

The formula for the area of a sector is (θ/360) * π * r^2, where θ is the central angle and r is the radius.

Given that the radius is 2 m and the central angle is 160°, we have:

θ = 160°

r = 2 m

Converting the angle to radians:

θ_radians = (160° * π) / 180° = (8π/9) radians

Now, we can calculate the area of the sector:

Area_sector = (θ_radians / (2π)) * π * r^2

= (8π/9) / (2π) * π * 2^2

= (4/9) * π * 4

= (16/9)π m^2

Next, let's find the area of the triangle:

The formula for the area of a triangle is (1/2) * base * height.

The base of the triangle is equal to the length of the radius, which is 2 m.

The height of the triangle can be found using the formula h = r * sin(θ/2).

θ = 160°

r = 2 m

Converting the angle to radians:

θ_radians = (160° * π) / 180° = (8π/9) radians

Calculating the height:

h = 2 * sin(θ_radians/2)

= 2 * sin((8π/9)/2)

= 2 * sin(4π/9)

= 2 * (√(1 - cos(4π/9)^2))

= 2 * (√(1 - cos^2(4π/9)))

Now, we can calculate the area of the triangle:

Area_triangle = (1/2) * base * height

= (1/2) * 2 * 2 * (√(1 - cos^2(4π/9)))

= 2 * (√(1 - cos^2(4π/9)))

Finally, we can find the area of the shaded region by subtracting the area of the sector from the area of the triangle:

Area_shaded_region = Area_triangle - Area_sector

= 2 * (√(1 - cos^2(4π/9))) - (16/9)π m^2

This is the exact answer in terms of π, with the correct unit of measurement (m^2).

Suppose we want to choose 2 letter without replacement from the 3 letters a,b and c how many ways can this be done if the order of choice is taken into consideration and how many ways can this be done if the order of choices is not taken into consideration?

Answers

When not considering the order of choice, there are also 3 ways to choose 2 letters from a, b, and c.

How to determine in how many ways can this be done if the order of choices is not taken into consideration

When choosing 2 letters without replacement from the 3 letters a, b, and c, the number of ways can be calculated considering the order of choice and without considering the order of choice.

1. Considering the order of choice:

In this case, the order in which the letters are chosen matters. We can think of this as a permutation problem.

To calculate the number of ways when order matters, we use the formula for permutations:

[tex]nPr = n! / (n - r)![/tex]

where n is the total number of items and r is the number of items chosen.

In this case, we have 3 letters and we want to choose 2, so n = 3 and r = 2.

Using the formula, we get:

[tex]3P2 = 3! / (3 - 2)![/tex]

 [tex]= 3! / 1![/tex]

    = 3

Therefore, when considering the order of choice, there are 3 ways to choose 2 letters from a, b, and c.

2. Without considering the order of choice:

In this case, the order in which the letters are chosen does not matter. We can think of this as a combination problem.

To calculate the number of ways when order does not matter, we use the formula for combinations:

[tex]nCr = n! / (r!(n - r)!)[/tex]

Using the same values of n = 3 and r = 2, we get:

[tex]3C2 = 3! / (2!(3 - 2)!)[/tex]

    = [tex]3! / (2! * 1!)[/tex]

    = 3

Therefore, when not considering the order of choice, there are also 3 ways to choose 2 letters from a, b, and c.

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Jackson invested $680.00 in an account that earns 1.5% simple interest annually. He made no additional deposits or withdrawals for 2 years. What was Jackson's account balance at the end of 2 years?

Answers

At the end of 2 years, Jackson's account balance is $700.40.

We have,

The formula for calculating simple interest is:

I = Prt

Where:

I is the interest earned

P is the principal amount

r is the interest rate

t is the time period

In this case,

Jackson invested $680.00 at an annual interest rate of 1.5% for 2 years. Therefore:

P = $680.00

r = 1.5% = 0.015

t = 2 years

Plugging these values.

I = Prt = $680.00 x 0.015 x 2 = $20.40

So,

Jackson earned $20.40 in interest over 2 years.

To find his total account balance at the end of 2 years, we need to add the interest earned to the initial principal:

Total balance

= $680.00 + $20.40

= $700.40

Therefore,

At the end of 2 years, Jackson's account balance is $700.40.

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Which statement describes the relationship between the x- and y-values shown in the graph?

A coordinate plane has x-axis and y-axis with values ranging from negative 6 to 10. A positive slope passes through the points (negative 4, negative 6), (negative 2, negative 4), (2, 0), (4, 2), and (6, 4).

Answers

In this example, a positive relationship between the x- and y-values is demonstrated. This basically demonstrates that when one value increases, the other typically does too, and vice versa when one value decreases in the graph.

An x and y coordinate plane with values between -6 and +10 is displayed on the graph.

The points (2, 0), (4, 2), (6, 4), (negative 2, negative 4), and (negative 4, negative 6) are all connected by a line. The y values rise in proportion to the x values because the line has a positive slope.

In this example, a positive relationship between the x- and y-values is demonstrated. This basically demonstrates that when one value increases, the other typically does too, and vice versa when one value decreases.

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The complete question is-

Which statement describes the relationship between the x- and y-values shown in the graph?

A coordinate plane has x-axis and y-axis with values ranging from negative 6 to 10. A positive slope passes through the points (negative 4, negative 6), (negative 2, negative 4), (2, 0), (4, 2), and (6, 4).

What is the measure of GEF?
OA. 50°
OB. 60°
OC. 160°
OD. 110°
110°
G

Answers

The measure of angle CDE is 70°.

Option C) 70° is correct.

Angle BAC measures 80°.

Point D is located on side BC such that BD = CD.

Angle ADE measures 30°.

To find: Measure of angle CDE.

Since angle BAC measures 80° and angle ADE measures 30°, we can determine the measure of angle CDE by subtracting the sum of these two angles from 180° (the total measure of angles in a triangle).

Measure of angle CDE = 180° - (80° + 30°)

= 180° - 110°

= 70°

Therefore, the measure of angle CDE is 70°.

The correct answer is:

C) 70°

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The  complete question may be like;

In the diagram below, triangle ABC is shown. Angle BAC measures 80°. Point D is located on side BC such that BD = CD. Angle ADE measures 30°. What is the measure of angle CDE?

A) 50°

B) 60°

C) 70°

D) 80°

Please let me know if you have any specific requirements or if there's anything else I can assist you with.

Prove that sin³A + sin³(60° + A) + sinº(240° + A) = -3/4sin3A ​

Answers

Answer:

See below for proof.

Step-by-step explanation:

[tex]\boxed{\textsf{Prove that}\;\;\sin^3A + \sin^3(60^{\circ} + A) + \sin^3(240^{\circ}+ A) = \sin^3A}[/tex]

Step 1

Rewrite 240° as (180° + 60°):

[tex]\sin^3A + \sin^3(60^{\circ} + A) + \sin^3(180^{\circ}+60^{\circ}+ A)[/tex]

Step 2

As sin(180° + x) = -sin(x), we can rewrite sin³(180° + 60° + A) as:

[tex]\sin^3(180^{\circ}+60^{\circ}+ A)=-\sin^3(60^{\circ}+ A)[/tex]

Step 3

Substitute this into the expression:

[tex]\sin^3A + \sin^3(60^{\circ} + A) -\sin^3(60^{\circ}+ A)[/tex]

Step 4

As the last two terms cancel each other, we have:

[tex]\sin^3A[/tex]

Hence proving that:

[tex]\sin^3A + \sin^3(60^{\circ} + A) + \sin^3(240^{\circ}+ A) = \sin^3A[/tex]

As one calculation:

    [tex]\sin^3A + \sin^3(60^{\circ} + A) + \sin^3(240^{\circ}+ A)[/tex]

[tex]=\sin^3A + \sin^3(60^{\circ} + A) + \sin^3(180^{\circ}+60^{\circ}+ A)[/tex]

[tex]=\sin^3A + \sin^3(60^{\circ} + A) -\sin^3(60^{\circ}+ A)[/tex]

[tex]=\sin^3A[/tex]

[tex]\hrulefill[/tex]

[tex]\boxed{\textsf{Prove that}\;\;\sin^3A + \sin^3(120^{\circ} + A) + \sin^3(240^{\circ}+ A) = -\dfrac{3}{4}\sin 3A}[/tex]

Step 1

Use the sine and cos double angle identities to rewrite sin(3x) in terms of sin(x):

[tex]\begin{aligned}\sin(3x)&=\sin(2x+x)\\&=\sin2 (x)\cos (x)+\sin (x)\cos2 (x)\\&=(2\sin (x)\cos (x))\cos (x)+\sin (x)(1-2\sin^2 (x))\\&=2\sin (x)\cos^2 (x)+\sin (x)-2\sin^3 (x)\\&=2\sin (x)(1-\sin^2 (x))+\sin (x)-2\sin^3 (x)\\&=2\sin (x)-2\sin^3 (x)+\sin (x)-2\sin^3 (x)\\&=3\sin (x)-4\sin^3 (x)\end{aligned}[/tex]

Rearrange to isolate sin³x:

[tex]\begin{aligned}\sin(3x)&=3\sin (x)-4\sin^3 (x)\\\\4\sin^3 (x)&=3\sin (x)-\sin (3x)\\\\\sin^3 (x)&=\dfrac{3\sin (x)-\sin (3x)}{4}\end{aligned}[/tex]

Step 2

Use this expression to rewrite the terms in sin³A on the left side of the equation:

   [tex]\sin^3A + \sin^3(120^{\circ} + A) + \sin^3(240^{\circ}+ A)[/tex]

[tex]=\dfrac{3\sin A-\sin3A}{4}+ \dfrac{3\sin (120^{\circ} + A)-\sin (3(120^{\circ} + A))}{4}+\dfrac{3\sin (240^{\circ}+ A)-\sin (3(240^{\circ}+ A))}{4}[/tex]

[tex]=\dfrac{3\sin A-\sin3A+3\sin (120^{\circ} + A)-\sin (360^{\circ} + 3A)+3\sin (240^{\circ}+ A)-\sin (720^{\circ}+ 3A)}{4}[/tex]

Step 3

As sin(x ± 360°n) = sin(x), we can simplify:

[tex]\sin(360^{\circ}+3A) = \sin (3A)[/tex]

[tex]\sin(720^{\circ}+3A) = \sin (3A)[/tex]

Therefore:

[tex]=\dfrac{3\sin A-\sin3A+3\sin (120^{\circ} + A)-\sin (3A)+3\sin (240^{\circ}+ A)-\sin (3A)}{4}[/tex]

[tex]=\dfrac{3\sin A-3\sin3A+3\sin (120^{\circ} + A)+3\sin (240^{\circ}+ A)}{4}[/tex]

Factor out the 3 in the numerator:

[tex]=\dfrac{3\left(\sin A-\sin3A+\sin (120^{\circ} + A)+\sin (240^{\circ}+ A)\right)}{4}[/tex]

Step 4

Rewrite 240° = 180° + 60°:

[tex]\sin(240^{\circ} + A) = \sin(180^{\circ} + 60^{\circ} + A)[/tex]

As sin(180° + x) = -sin(x), we can rewrite sin(180° + 60° + A) as:

[tex]- \sin(60^{\circ} + A)[/tex]

Therefore:

[tex]=\dfrac{3\left(\sin A-\sin3A+\sin (120^{\circ} + A)-\sin (60^{\circ}+ A)\right)}{4}[/tex]

Step 5

As sin(120° + x) = sin(60° - x) then:

[tex]=\dfrac{3\left(\sin A-\sin3A+\sin (60^{\circ} -A)-\sin (60^{\circ}+ A)\right)}{4}[/tex]

Step 6

As sin(60° - x) - sin(60° + x) = -sin(x), then:

[tex]=\dfrac{3\left(\sin A-\sin3A-\sin A\right)}{4}[/tex]

Step 7

Simplify:

[tex]=\dfrac{-3\sin3A}{4}[/tex]

[tex]=-\dfrac{3}{4}\sin3A[/tex]

Hence proving that:

[tex]\sin^3A + \sin^3(120^{\circ} + A) + \sin^3(240^{\circ}+ A) = -\dfrac{3}{4}\sin 3A[/tex]

Suppose the density field of a one-dimensional continuum is
ρ = exp[cos(t − x)]
and the velocity field is
v = sin(t − x).
1. What is the flux of material past x = 0 as a function of time?

Answers

The flux of material past x = 0 is zero for all times.

What is the flux of material?

The flux of material past x = 0 can be calculated by integrating the product of density and velocity over the spatial domain.

This is calculated as;

Φ = ∫ ρv dx

ρ = exp[cos(t − x)]

v = sin(t − x)

where;

ρ is densityv is the velocity

The flux of material past x = 0 is calculated as;

Φ = ∫ exp[cos(t − x)] sin(t − x) dx

sin(t − x) = an odd functionexp[cos(t − x)] = even function

∫ exp[cos(t − x)] sin(t − x) dx, is the integration of an odd function over a symmetric interval [-π, π] which is zero.

Φ = ∫ exp[cos(t − x)] sin(t − x) dx = 0

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Find the measure of the arc or angle indicated. Assume that lines which appear tangent are tangent.

Answers

Applying the angle of intersecting secant-tangent theorem, the measure of arc VT is calculated as: m(VT) = 116°.

How to Find the Measure of Arc Using the Angle of Intersecting Secant-Tangent Theorem?

Given that the lines appear tangent, the measure of the arc VT indicated above can be calculated using the angle of intersecting secant-tangent theorem which states that:

m<U = 1/2(m(WT) - m(VT))

Given the following:

measure of angle U = 37 degrees.

measure of arc WT = 190 degrees.

Plug in the values:

37 = 1/2(190 - m(VT))

74 = 190 - m(VT)

m(VT) = 190 - 74

m(VT) = 116°

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Help needed! 20 points pls

The number of peanuts in a 16-ounce can of Nut Munchies is normally distributed with a mean of 94 and a standard deviation of 3 peanuts.

(a) Use the mean and standard deviation to label the intervals below the normal distribution below. (Fill in all 7 of the boxes.)

(b) What is the probability that a 16-ounce can of Nut Munchies will contain between 88 and 97 nuts?

(c) What is more likely to happen, for a 16-ounce can of Nut Munchies to have between 88 and 94 nuts, or for the can to have over 97 nuts? How do you know?

Answers

The mean and standard deviation are less than 88 peanuts: z = (88 - 94) / 3 = -2

between 88 and 91 peanuts: z = (91 - 94) / 3 = -1

between 91 and 94 peanuts: z = (94 - 94) / 3 = 0

between 94 and 97 peanuts: z = (97 - 94) / 3 = 1

greater than 97 peanuts: z = (97 - 94) / 3 = 1

The probability that a 16-ounce can of Nut Munchies will contain between 88 and 97 nuts is 0.8186, or approximately 82%.

The probability of the former event is 0.4772, which is greater than the probability of the latter event, which is 0.1587.

(a) The intervals below the normal distribution can be labeled using z-scores, which are calculated using the formula:

z = (x - μ) / σ

where x is the value of interest, μ is the mean, and σ is the standard deviation.

The intervals and their corresponding z-scores are:

less than 88 peanuts: z = (88 - 94) / 3 = -2

between 88 and 91 peanuts: z = (91 - 94) / 3 = -1

between 91 and 94 peanuts: z = (94 - 94) / 3 = 0

between 94 and 97 peanuts: z = (97 - 94) / 3 = 1

greater than 97 peanuts: z = (97 - 94) / 3 = 1

(b) To find the probability that a 16-ounce can of Nut Munchies will contain between 88 and 97 nuts, we need to find the area under the normal distribution curve between the corresponding z-scores. Using a standard normal distribution table or a calculator, we can find that:

P(88 ≤ X ≤ 97) = P(-2 ≤ Z ≤ 1) = 0.8186

Therefore, the probability that a 16-ounce can of Nut Munchies will contain between 88 and 97 nuts is 0.8186, or approximately 82%.

(c) To determine which event is more likely, we can compare the probabilities of each event. Using the same method as in part (b), we can find that:

P(88 ≤ X ≤ 94) = P(-2 ≤ Z ≤ 0) = 0.4772

P(X > 97) = P(Z > 1) = 0.1587

Therefore, it is more likely for a 16-ounce can of Nut Munchies to have between 88 and 94 nuts than to have over 97 nuts, since the probability of the former event is 0.4772, which is greater than the probability of the latter event, which is 0.1587.

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PLEASE HELP
The box plot represents the number of tickets sold for a school dance.

A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the number line. A line in the box is at 19. The lines outside the box end at 10 and 27.

Which of the following is the appropriate measure of center for the data, and what is its value?

The mean is the best measure of center, and it equals 19.
The median is the best measure of center, and it equals 4.
The median is the best measure of center, and it equals 19.
The mean is the best measure of center, and it equals 4.

Answers

Answer:

The median is the best measure of center, and it equals 19.

Step-by-step explanation:

The line for the median is exactly on 19

Final answer:

The line in the box of a box plot represents the median of the data. For this particular data set shown in the box plot, the median is 19.

Explanation:

In the described box plot, the line in the box that is at the number 19 represents the median of the data. This is because a box plot illustrates the five number summary of a data set: the minimum, the first quartile, the median (second quartile), the third quartile, and the maximum. The line inside the box always represents the median. Therefore, the correct choice is: The median is the best measure of center, and it equals 19.

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Mark brought $43.00 to the state fair. He bought a burger, a souvenir, and a pass. The burger was
1
4
as much as the souvenir, and the souvenir cost
2
3
the cost of the pass. Mark had $4.50 left over after buying these items.
What was the cost of each item?

Answers

The cost of the burger is $10.50, the cost of the souvenir is $28.00, and the cost of the pass is $42.00.

Let's assume the cost of the pass is x dollars.

According to the given information:

The burger costs 1/4 of the souvenir, so the burger's cost is[tex](1/4) \times x[/tex]dollars.

The souvenir costs 2/3 of the pass, so the souvenir's cost is [tex](2/3) \times x[/tex]dollars.

Mark had $4.50 left over after buying these items, so we can set up the following equation:

[tex]43.00 - [(1/4) \times x + (2/3) \times x] = $4.50[/tex]

Simplifying the equation, we have:

[tex]43.00 - [(1/4) \times x + (2/3) \times x] = $4.50[/tex]

[tex]43.00 - (1/4 + 2/3) \times x = $4.50[/tex]

[tex]43.00 - (3/12 + 8/12) \times x = $4.50[/tex]

[tex]43.00 - (11/12) \times x = $4.50[/tex]

To solve for x, we'll isolate the variable on one side of the equation:

$43.00 - $4.50 = (11/12) * x

$38.50 = (11/12) * x

Now, we can solve for x by multiplying both sides of the equation by (12/11):

[tex](12/11) \times $38.50 = x[/tex]

$42.00 = x

Therefore, the cost of the pass is $42.00.

Now we can find the costs of the burger and the souvenir:

The burger costs 1/4 of the souvenir, so its cost is (1/4) * $42.00 = $10.50.

The souvenir costs 2/3 of the pass, so its cost is (2/3) * $42.00 = $28.00.

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A group of 6 students was asked, "How many hours did you watch television last week?" Here are their responses.
20,4,7,7, 10, 10
Find the median and mean number of hours for these students.
If necessary, round your answers to the nearest tenth.
(a) Median:
(b) Mean:
hours
hours

Answers

Answer: median = 8.5

mean=

9.7

total = 58

Answer:

median=8.5 hours Mean=9.7 hours

Step-by-step explanation:

First you take the values and add them together, find the sum.
20+4+7+7+10+10=x
x=58
now take 58 and divide it by the number of students
58/6=9.66666
the mean would be 9.7 hours since it asks to round to the nearest 10th
and for the median sort it from lowest to highest
4,7,7,10,10,20
now since in the middle are 7 and 10, add those together and divide by 2
10+7=17
17/2=8.5
the median is 8.5

AI can buy a box of 30 used CD's for 150.how much would he pay for 80 CD´s at the same unit price

Answers

AI would pay 400 for 80 CDs at the same unit price.

In a Leichtman Research Group survey of 1000 TV​ households, ​74.8% of them had at least one​ Internet-connected TV device​ (for example, Smart​ TV, standalone streaming​ device, connected video game​ console). A marketing executive wants to convey high penetration of​ Internet-connected TV​ devices, so he makes the claim that the percentage of all homes with at least one​ Internet-connected TV device is equal to 78​%. Test that claim using a 0.01 significance level. Use the​ P-value method. Use the normal distribution as an approximation to the binomial distribution.

Answers

W do not have sufficient evidence at the 0.01 level of significance to reject the claim made by the marketing executive

How to explain the normal distribution

We'll perform a one-sample z-test for proportions.

From the survey, we know:

Sample size (n) = 1000

Sample proportion) = 0.748

Under the null hypothesis:

Proportion (p0) = 0.78

Now we can calculate the z-score:

z = (0.748 - 0.78) / ✓(0.78 * (1 - 0.78)) / 1000]

= -0.032 / ✓(0.1716 / 1000]

= -0.032 / 0.0131

≈ -2.44

From the z-table, the P-value for -2.44 is approximately 0.015.

However, we need to double this value to get the two-tailed P-value: 2 * 0.015 = 0.03.

If the P-value is less than the significance level (α = 0.01), we reject the null hypothesis. In this case, the P-value (0.03) is greater than α, so we do not reject the null hypothesis.

Based on the data from the Leichtman Research Group survey, we do not have sufficient evidence at the 0.01 level of significance to reject the claim made by the marketing executive.

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2. Which of the following is an opinion?
A Nicky was one of many other paragliders in competition.
B. Paragliders are scared of the height involved when paragliding.
C. Eagles attacked Nicky's glider in this story.
D. Eagles have a wingspan up to 6 feet.

Answers

Answer:

B. Paragliders are scared of the height involved when paragliding.

Find the surface area

Answers

Answer:

40 is the surface area.

Explanation on hiw to get the answer:

PLEASE HELP ME I HAVE TO ANSWER THIS AND THERES A TIME LIMIT

Answers

The value of m∠ECD is 50°

What is an equation?

An equation is an expression that is used to show how numbers and variables are related using mathematical operators

In the right triangle, m∠B = 90°, hence:

m∠A + m∠B + m∠C = 180° (sum of angles in a triangle)

40 + 90 + m∠C = 180

m∠C = 50°

Also:

m∠C = m∠ECD (opposite angles are equal)

m∠C = m∠ECD = 50°

m∠ECD is 50°

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A small business owner is applying for a small business loan and has been approved for a $50,000 loan with 5.25% annual interest. The first loan is a simple interest rate, the second loan compounds interest quarterly, and the third loan compounds interest continuously. The small business owner plans to pay off the loan in 3 years and 8 months.

Part A: Determine the total value of the loan with the simple interest. Show all work and round your answer to the nearest hundredth.

Part B: Determine the total value of the loan with the quarterly compounded interest. Show all work and round your answer to the nearest hundredth.

Part C: Determine the total value of the loan with the continuously compounded interest. Show all work and round your answer to the nearest hundredth.

Part D: Using the values from Parts A, B, and C, explain which loan option is the best choice for the small business owner.

Answers

Part A: The total value of the loan with simple interest is $59,660.50.

Part B: The total value of the loan with quarterly compounded interest is $60,357.91.

Part C: The total value of the loan with continuously compounded interest is $60,441.82.

Part D: The best choice for the small business owner is the loan with simple interest, as it has the lowest total value and thus the lowest cost to repay.

Part A:

To calculate the total value of the loan with simple interest, we can use the formula:

[tex]Total value = Principal \times (1 + interest rate \times time)[/tex]

Where,

Principal = $50,000

Interest rate = 5.25% = 0.0525

Time = 3 years and 8 months = 3.67 years.

[tex]Total $ value = $50,000 \times (1 + 0.0525 \times 3.67) = $59,660.50[/tex]

Therefore, the total value of the loan with simple interest is $59,660.50.

Part B:

To calculate the total value of the loan with quarterly compounded interest, we can use the formula:

[tex]Total value = Principal \times (1 + (interest rate / n))^{(n \times time) }[/tex]

Where,

Principal = $50,000

Interest rate = 5.25% = 0.0525

Time = 3 years and 8 months = 3.67 years

n = 4 (since interest compounds quarterly)

[tex]Total value = $50,000 \times (1 + (0.0525 / 4))^{(4 \times3.67) } = $60,357.91[/tex]

Therefore, the total value of the loan with quarterly compounded interest is $60,357.91.

Part C:

To calculate the total value of the loan with continuously compounded interest, we can use the formula:

[tex]Total value = Principal \times e^{(interest rate \times time)}[/tex]

Where,

Principal = $50,000

Interest rate = 5.25% = 0.0525

Time = 3 years and 8 months = 3.67 years

[tex]Total value = $50,000 \times e^{(0.0525 \times 3.67) } = $60,441.82[/tex]

Therefore, the total value of the loan with continuously compounded interest is $60,441.82.

Part D:

From the calculations in Parts A, B, and C, we can see that the loan with continuously compounded interest has the highest total value of $60,441.82.

This is followed by the loan with quarterly compounded interest with a total value of $60,357.91, and finally the loan with simple interest with a total value of $59,660.50.

Therefore, the best choice for the small business owner would be to take the loan with simple interest, as it has the lowest total value and thus the lowest cost to repay.

However, if the small business owner is willing to pay a higher cost for the loan, they could consider the loan with quarterly or continuously compounded interest, which have higher total values.

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Graph the function f(x) = -(1/5)^x+5 +7 on the axes below. You must Plot the asymptote and any two points with the integer coordinates

Answers

The graph of the function is added as an attachment

The asymptote: y = 7 and the points are (-5, 6) and (-7, -18)

Sketching the graph of the function

From the question, we have the following parameters that can be used in our computation:

f(x) = -(1/5)ˣ ⁺ ⁵+ 7

The above function is an exponential function that has been transformed as follows

Reflected over the x-axisDecay factor of 1/5Shifted left by 5 unitsShifted up by 5 units

Next, we plot the graph using a graphing tool by taking not of the above transformations rules

The graph of the function is added as an attachment, where we have the following points

Asymptote: y = 7

(-5, 6) and (-7, -18)

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