NEED HELP ASP
WILL GIVE POINTS OR WHATEVER

NEED HELP ASPWILL GIVE POINTS OR WHATEVER

Answers

Answer 1

Answer:

you need to multiply the momentum and the mass


Related Questions

Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
acceleration of Claudia's 1.80kg foot? B) What is the acceleration of the table if it has a mass
of 20.0kg? (ignore any frictional effects) C) Why would Claudia's toe hurt less if the table had
less mass?

Answers

Answer:

A.) acceleration= 55.6m/s^2

B.) acceleration of table= 5.0m/s^2

C.) More acceleration

Explanation:

A.) 100N/1.8kg= -55.6

B.) 100N÷20kg= 5

C.) Because since the table would have less mass, it would have had to accelerate more

Draw a graph of these results​

Answers

Answer:

Actually I know but I can't cause it will take time

An amateur golfer swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for only 0.00360 s. After the collision, the ball leaves the club at a speed of 34.0 m/s. What is the magnitude of the average force (in N) exerted on the ball by the club?

Answers

Answer:

The average force ≅ 519.44 N.

Explanation:

Impulse = change in momentum of a body

i.e Ft = m(v - u)

where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.

m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s

So that,

F x 0.00360 = 0.055(34 - 0)

F x 0.00360 = 0.055 x 34

                    = 1.87

F = [tex]\frac{1.87}{0.0036}[/tex]

 = 519.4444

The average force exerted on the ball by the club is approximately 519.44 N.

The most commonly accepted theory of muscle growth states that ______________ ________ within a muscle activate a(n) ________________ response process that causes dormant cells to build and regenerate muscle tissue.
A. contractions; inhibitory
B. tension; neurological
C. microscopic tears; inflammatory
D. stress; cytokines

Answers

Answer:

C

Explanation:

The most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.

What is the significance of the microscopic tears in muscle?

It has negative consequences on the muscle, and it is also known as "microtrauma," which occurs as a result of muscle contraction and is a normal part of the muscle repair and growth process. Here, the fibers in the muscle are damaged, and in response, the body initiates a repair process. This leads to muscle growth and increased strength and is helpful for muscle repair.

Hence, the most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.

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This is my question ​

Answers

Answer:

N = 470 [N]

Explanation:

The normal force is defined as the reaction exerted by the surface where the body is located in the opposite direction to the weight component.

It can be easily calculated by means of the product of mass by gravitational acceleration.

N = m*g

where:

N = normal force [N] (units of Joules)

m = mass = 47 [kg]

g = gravity acceleration = 10 [N]

N = 47*10

N = 470 [N]

A physicist's left eye is myopic (i.e., nearsighted). This eye can see clearly only out to a distance of 35 cm.Find the focal length and the power of a lens that will correct this myopia when worn 2.0 cm in front of the eye.

Answers

Answer:

Explanation:

To get the focal length, we will use the lens formula;

1/f = 1/u + 1/v

f is the focal length

u is the object distance

v is the image distance

Given

since the physicist's left eye is myopic, it will be corrected using concave lens and the image distance is negative.

u = 35cm

v = -2.0

1/f = 1/35-1/2

1/f = 2-35/70

1/f = -33/70

f = -70/33

f = -2.12 cm

f = -0.0212m

Power of a lend is the reciprocal of its focal length

Power of the lens = 1/f

P = 1/-0.0212

P = -47.17dioptres

The power of the lens is -47.17D

A freight train has a mass of 3.8 x 10^7 kg. The locomotive can exert a force of 6.5 x 10^5 N to pull the train.

Required:
a. How long does it take the train to go from rest to 50 km/hr?
b. If there is air resistance of 2.0 x 10^5 N, what is the acceleration of the train, and how long does it take the train to go from rest to 50 km/hr?

Answers

Answer:

(a) The time taken for the plane to reach 50 km/hr is 811.97 s

(b) (i) the acceleration of the plane is 0.012 m/s²

    (ii) The time taken for the plane to reach 50 km/hr is 1172.85 s

Explanation:

Given;

mass of the freight train, m = 3.8 x 10⁷ kg

force applied to pull the train, F = 6.5 x 10⁵ N

a. How long does it take the train to go from rest to 50 km/hr?

Given;

initial velocity, u = 0

final velocity, v = 50 km/hr = 13.889 m/s

Apply Newton's second law of motion to determine the time traveled by the train at the given speed;

[tex]F = ma = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{6.5*10^5}\\\\t = 811.97 \ s[/tex]

(b)

(i) the acceleration of the plane

Given;

air resistance, = 2.0 x 10⁵ N

Apply Newton's second law of motion;

∑F = ma

6.5 x 10⁵ N - 2.0 x 10⁵ N = ma

4.5 x 10⁵ N = ma

[tex]a = \frac{4.5 * 10^5 }{m}\\\\a = \frac{4.5 * 10^5 }{3.8*10^7}\\\\a = 0.012 \ m/s^2[/tex]

(ii) time taken for the plane to reach 50 km/hr is given by;

[tex]F = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{4.5*10^5}\\\\t = 1172.85 \ s[/tex]

Doing specific exercises to improve a particular area of fitness is called flexibility? True or false

Answers

Answer:

True.

Explanation:

Exercises and yoga are important for the individual's health. The exercise makes the individual, fit, healthy and also reduces the chances of the deadly disease in human beings.

Different types of exercise can be performed by the individual. The aerobic exercises increase the amount of oxygen in the body. With the aerobic exercise, the exercise that can increase the strength, flexibility and total fitness must also be included.

What unit is used to measure energy when calculating specific heat capacity? Give the abbreviation, not the full name.

Answers

The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).

What unit is used to measure energy?

The specific heat capacity should be determined in joules per kilogram degree-celsius ( J k g − 1 ∘ C − 1 ).

It is to be supplied for the substance with respect to mass and it increased the temperature.

Hence, The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).

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The unit used to measure energy when calculating specific heat capacity is the joule (J).

The joule (J), a unit used to quantify energy, is used to calculate specific heat capacity. In the International System of Units (SI), the joule serves as the default unit of energy.

It is described as the quantity of energy that is delivered when one newton of force is exerted across a one-meter distance.

Thus, the quantity of heat energy needed to increase the temperature of a particular substance by a specific amount is measured as specific heat capacity. J/kg°C, or joules per kilogramme per degree Celsius, is the unit of measurement.

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4.
Vectors P and Q are drawn to scale.
P
Which diagram represents the vector (P +Q)?
A
B
с
D

plz help I will fail.
can anyone plz help me.
plz

Answers

Answer:

hindi ko gets

Explanation:

ang gulo naman nyan

what is the state of y when y = k/x, x is halved.

Answers

Answer:

y becomes doubled.

Explanation:

If;

       y  = [tex]\frac{k}{x}[/tex]  

what is the state of y when x is halved;

  the given expression is an inverse relationship. When y increases, x is supposed to decrease and vice versa.

 

 if x is halved; x  = [tex]\frac{x}{2}[/tex]

           [tex]\frac{k}{\frac{x}{2} }[/tex]   = [tex]\frac{2k}{x}[/tex]  

Now compare :

      [tex]\frac{k}{x}[/tex]  :  [tex]\frac{2k}{x}[/tex]

we see that y becomes doubled

The CERN particle accelerator is circular with a circumference of 7.0 km.

Required:
a. What is the acceleration of the protons (m=1.67×10^−27kg) that move around the accelerator at of the speed of light? (The speed of light is v=3.00×10^8m/s.)
b. What is the force on the protons?

Answers

Answer:

Explanation:

a) centripetal acceleration is the acceleration of a body in a circular path. It is expressed as;

a = mv²/r

m is the mass of proton = 1.67×10^−27kg

v is the velocity = 3.00×10^8m/s

r is the radius

Since C = 2πr

7000m = 2πr

r = 7000/2π

r = 1114.08m

Substitute

a = 1.67×10^−27 (3.00×10^8)²/1114.08

a =  1.67×10^−27 * 9×10^16/1114.08

a = 15.03*10^-11/1114.08

a = 0.001346*10^-11

a = 1.346*10^-14m/s²

b) Force on the proton = mass * acceleration

Force = 1.67×10^−27kg * 1.346*10^-14

Force = 2.246*10^-41N

hence the force on the proton is 2.246*10^-41N

A 2.0 cm thick brass plate (k_r = 105 W/K-m) is sealed to a glass sheet (kg = 0.80 W/K m), and both have the same area. The exposed face of the brass plate is at 80°C, while the exposed face of the glass is at 20 °C. How thick is the glass if the glass brass interface is at 65 C? Ans. 0.46 mm​

Answers

I need a good phisics teacher for one day online please123

A group of students collected the data shown below while attempting to measure the coefficient of static friction (of course, it looks like this group varied the amount of mass sitting on the block with each trial - this is not recommended). Nonetheless, what is their average coefficient of static friction?

Trial Mass of block (g) Hanging mass (kg)
1 105 0.053
2 165 0.081
3 220 0.118
4 280 0.149
5 315 0.180
6 385 0.198

Answers

Answer:

0.130

Explanation:

From the given data, the coefficient of static friction for each trial are:

1. 0.053

2. 0.081

3. 0.118

4. 0.149

5. 0.180

6. 0.198

The sum of the coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198

                                              = 0.779

So that;

the average coefficient of static friction = [tex]\frac{sum of coefficient of static friction}{number of trials}[/tex]

                                              = [tex]\frac{0.779}{6}[/tex]

                                              = 0.12983

The average coefficient of static friction is 0.130

The average coefficient of static friction is 0.13.

The coefficient of static friction is obtained using the formula; μ = F/R

Where;

F = force acting on the body

R = reaction

μ = coefficient of static friction

The average of measurements is given as; ∑summation of measurements/number of measurements

We can see from the question that there were 6 measurements of the coefficient of static friction. Hence, the average coefficient of static friction is obtained from;

0.053 + 0.081 + 0.118 + 0.149 + 0.180 +  0.198/6

= 0.13

The average  coefficient of static friction is 0.13

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Once a player catches the Frisbee they are only allowed to pivot like in
basketball.
True
False

Answers

True I know from pe hahahahha
True you would know

Select all that apply. The spectrum of Star Y is compared to a reference hydrogen spectrum. What can be concluded about Star Y? Reference (normal) Hydrogen Spectrum Star Y I 500 550 600 650 700 750 400 450 9200 OdyssepWare, Ing. Star Y is showing radial motion Star Y is moving away from the Earth Star Y is moving toward the Earth Star Y is showing transverse motion​

Answers

Answer:

Star Y is showing radial motion

Star Y is moving toward the Earth

Explanation:

Just answered this question on a quiz and got it right.

Star Y is showing radial motion

Star Y is moving towards earth.

What is a spectrum ?

Spectrum is defined as the arrangement of radiations emitted by atoms or molecules based on their characteristic wavelength and frequency.

Here,

The spectrum of the star Y is given and is compared to a reference hydrogen spectrum. The range of wavelengths of the star is given. The spectrum of the star shows that the wavelengths are shifted such that from longer wavelengths to shorter wavelength. This phenomenon of shift in wavelengths from higher to lower is known as blue shift. The star shows blue shift that means shifted to shorter wavelength or it can be said as shifted from lower frequency to higher frequency. As a result, it can be concluded that the star Y is moving towards the earth which implies Star Y is showing radial motion.

Hence,

The star Y is showing radial motion.

Star Y is moving towards the earth.

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What does a switch in an electrical circuit do?
O A. It concentrates negative charges on one side of the circuit when it
is open.
B. It concentrates negative charges on one side of the circuit when it
is closed.
C. It allows electrons to flow from one part of the circuit to another
when it is open.
D. It allows electrons to flow from one part of the circuit to another
when it is closed.

Answers

Answer:

It allows electrons to flow from one part of the circuit to another

when it is closed.

Explanation:

hope this helps <3 !!

Answer: D

Explanation:

Help me with this please !!
Pt 1_It would be harder to do experiments on or near jupiter for many reasons ! One being that jupiters top layers are known to be gas. However if we could hover over Jupiter and test its gravity, describe or sketch the shape of the position vs time graph for a dropped object.
PT2_ The acceleration due to gravity near Jupiter is 25.95m/s. If a hammer were dropped, how fast wouldit be going after falling 20.0 meters. Show your work !

Answers

25.4is the right answer

Answer:

he is right he Is

Explanation:

step by step explanation

A force F = (2xî + 4yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-direction from the origin to x = 4.99 m. Find the work W = ∫ F · dr done by the force on the object (in J).

Answers

Answer:

Work done, W = 24.9001 J

Explanation:

Given that,

Force, F = (2xî + 4yĵ) Where x and y are in meters

This force acts on an object as the object moves in the x-direction from the origin to x = 4.99 m.

We need to find the work done by the force on the object. It is given by :

[tex]W=\int\limits^a_b {F dr} \\\\W=\int\limits^{4.99}_0 {(2xi+4yj)dx} \\\\W=\int\limits^{4.99}_0 {2xi\ dx} \\\\W=x^2|_0^{4.99}\\\\\text{Applying limits}\\\\W=(4.99)^2-0^2\\\\W=24.9001\ J[/tex]

So, the work done is 24.9001 J.

Can someone help plzzzzzzz I need it ASAP thank you

Answers

Answer:

Explanation:

Frequency is oscillations per second.

So we have to find the Number of seconds she paced.

2 minutes = 2 X 60

               = 120 seconds

Therefore,

Her frequency = 10 / 120

                       = 1/12 Hertz

If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the car in kg

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

  [tex]p = 14033.7 \ kg\cdot m/s[/tex]

b

  [tex]v = 1.22 \ m/s[/tex]

c

 [tex]m_2 = 9506.7 \ kg[/tex]  

Explanation:

From the question we are told that

     The mass of the coal car is  [tex]m_1 = 4527 \ kg[/tex]

     The velocity is  [tex]v_i = 3.1 \ m/s[/tex]

     The load of coal dropped is [tex]m_2 = 6952 \ kg[/tex]

Generally the momentum of the system before the coal is added is mathematically represented as

            [tex]p = m_j * v_i[/tex]

=>         [tex]p = 4527 * 3.1[/tex]

=>         [tex]p = 14033.7 \ kg\cdot m/s[/tex]

Generally from the law of momentum conservation is mathematically represented as

          [tex]m_1 * v_i + m_2 * v_2 = (m_1 + m_2 )v[/tex]

Here [tex]v_2[/tex] is the velocity of the load before it is dropped and the value is 0 m/s

So

 =>    [tex]v =\frac{m_1 * v_i }{m_1 + m_2}[/tex]

      [tex]v = \frac{4527 * 3.1 }{( 4527 + 6952 )}[/tex]

=>    [tex]v = 1.22 \ m/s[/tex]

When v =  1m/s  and  [tex]m_1[/tex] remain the same

Then

=>    [tex]1 =\frac{4527 * 3.1 }{4527 + m_2}[/tex]

=>    [tex]4527 + m_2 = 14033.7[/tex]

=>    [tex]m_2 = 9506.7 \ kg[/tex]  

free brainlyest. if get thes quston right Devlin recorded the number of days of rain for his town over three months. The bar graph below shows his data.
Bar Graph 1

Explain why his data is more about climate than weather.

Question 12 options:

Answers

Answer:

Weather is the conditions (temperature, wind etc.) at a given time, like on that day. Climate, which is what his data would show, is the conditions over an extended period of time like the 3 months he collected data

A change of temperature of 20 C is equivalent to a change in thermodynamic temperature of

Answers

Answer:

20 K

Explanation:

It is given that,

The change in temperature is 20 C.

We need to find the change in thermodynamic temperature.

If teperauture T₁ = 0° C = 0+273 = 273 K

T₂ = 20° C = 20 + 273 = 293 K

The change in temperature,

[tex]\Delta T=T_2-T_1\\\\=293-273\\\\=20\ K[/tex]

So, the change in temperature of 20°C is equivalent to 20 K.

The change in thermodynamic temperature is equal to 20 Kelvin.

Given the following data:

Change in temperature = 20°C

To determine the change in thermodynamic temperature:

A thermodynamic temperature can be defined as an absolute measure of the average total internal energy possessed by a body or an object. Thus, thermodynamic temperature is typically measured in Kelvin (K).

Mathematically, the change in temperature of an object is given by the formula:

[tex]\theta = T_f - T_i[/tex]

Where:

[tex]T_i[/tex] is the initial temperature (0°C)[tex]T_f[/tex] is the final temperature (20°C).

Next, we would convert the values in degree Celsius to Kelvin:

Conversion:

0°C = 273 K

20°C = 273 + 20 = 293 K

For the change in thermodynamic temperature:

[tex]\theta = 293 - 273\\\\\theta =20\;K[/tex]

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A large bottle contains number medical tablets each having a mass of 250
mg.The mass of all tablets is 1kg.Calculate the number of tablets in the
bottle.​

Answers

First of all, this isn't physics. But, here's the answer:

1 gram is a 1000 milligram and 250 milligram is 250 * 0.001 g which is 0.25 gram.

Since 1 kg is 1000 g, we divide 1000 by 0.25 and we get 1000 * 4 which is 4000.

There are [tex]4000[/tex] tablets inside the bottle.

I'll give brainliest if you give me a good awnser. :)

A football player kicks a ball with a force of 50 N. Find the impulse on the ball if his foot stays in contact with the football for 0.01 second.

Answers

Answer:

0.5

Explanation:

50x0.01=0.5
The answer is 0.5! I hope this helps you out!!

Find the magnitude of the gravitational force (in N) between a planet with mass 6.00 X 10^24 kg and its moon, with mass 2.50 X 10^22 kg, if the average distance between their centers is 2.70 X 10^8 m. What is the moon's acceleration (in m/s2) toward the planet? (Enter the magnitude.) What is the planet's acceleration (in m/s2) toward the moon? (Enter the magnitude.)

Answers

Answer:

Magnitude of gravitational force between this planet and its moon: approximately [tex]1.37 \times 10^{20}\; \rm N[/tex].

Acceleration of this moon towards the planet: approximately [tex]5.49 \times 10^{-3}\; \rm m \cdot s^{-2}[/tex].

Acceleration of this planet towards its moon: approximately [tex]2.29 \times 10^{-5}\; \rm m \cdot s^{-2}[/tex].

Explanation:

Look up the gravitational constant, [tex]G[/tex]:

[tex]G \approx 6.67 \times 10^{-11}\; \rm m^3\cdot kg^{-1} \cdot s^{-2}[/tex].

Assume that both this planet and its moon are spheres of uniform density. When studying the gravitational interaction between this planet and its moon, this assumption allows them to be considered as two point masses.

The formula for the size of gravitational force between two point masses [tex]m_1[/tex] and [tex]m_2[/tex] with a distance of [tex]r[/tex] in between is:

[tex]\displaystyle F = \frac{G \cdot m_1 \cdot m_2}{r^2}[/tex],

where [tex]G[/tex] is the gravitational constant.

Let [tex]m_1[/tex] and [tex]m_2[/tex] denote the mass of this planet and its moon, respectively.

Calculate the size of gravitational force between this planet and its moon:

[tex]\begin{aligned} F &= \frac{G \cdot m_1 \cdot m_2}{r^2} \\ &\approx \frac{6.67 \times 10^{-11}\; \rm m^3 \cdot kg^{-1} \cdot s^{-2} \times 6.00 \times 10^{24}\; \rm kg \times 2.50 \times 10^{22}\; \rm kg}{{\left(2.70 \times 10^{8}\; \rm m\right)}^2} \\ &\approx 1.37 \times 10^{20}\; \rm N\end{aligned}[/tex].

Assume that other than the gravitational force between this planet and its moon, all other forces (e.g., gravitational force between this planet and the star) are negligible. The magnitude of the net force on the planet and on the moon should both be approximately [tex]1.37 \times 10^{20}\; \rm N[/tex].

Apply Newton's Second Law of motion to find the acceleration of this planet and its moon:

[tex]\displaystyle \text{acceleration} = \frac{\text{net force}}{\text{mass}}[/tex].

For this moon:

[tex]\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{2.50 \times 10^{22}\; \rm kg} \approx 5.49\times 10^{-3}\; \rm m \cdot s^{-2}[/tex].

For this planet:

[tex]\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{6.00 \times 10^{24}\; \rm kg} \approx 2.29 \times 10^{-5}\; \rm m \cdot s^{-2}[/tex].

"She finished the sprint with the speed of a cheetah." This statement represents which of the
following functions of language? (2 points)



correct answer is poetic.

Answers

Answer:

Poetic

Explanation:

I took the test

Answer:

Poetic

Explanation:

I got it right on the test

Review Question 1
A group of students collected the data shown below while attempting to
measure the coefficient of static friction (of course, it looks like this group
varied the amount of mass sitting on the block with each trial - this is not
recommended). Nonetheless, what is their average coefficient of static friction?
Mass of block (g)
Hanging mass (kg)
Trial
1
105
0.053
2
165
0.081
3
220
0.118
4
280
149
5
315
0.180
6
385
0.198

Answers

Answer:

The average coefficient of static friction = 0.130

Explanation:

The average coefficient of static friction = [tex]\frac{sum of coefficient of static friction}{number of trials}[/tex]

From the given question, the coefficient of static friction given are:

0.053, 0.081, 0.118, 0.149, 0.180, 0.198

Thus,

the sum of the given coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198

                                             = 0.779

The average coefficient of static friction = [tex]\frac{0.779}{6}[/tex]

                                             = 0.129833

                                             = 0.130

Therefore, the average coefficient of static friction is 0.130.

which one is correct:
Average acceleration of an object is the:

Change in its position divided by the change in time
Change in time divided by the change in its position
Change in its velocity divided by the change in time
Change in time divided by the change in its velocity

Answers

Answer:

Option (c) is correct.

Explanation:

Acceleration of an object is given by the formula as follows :

[tex]a=\dfrac{v-u}{t}[/tex]

Where

u and v are initial and final velocity

t is time

(v-u) is also called the change in velocity

So, the acceleration of an object is equal to the rate of change of velocity. Hence, the correct option is (c) " Change in its velocity divided by the change in time".

which statement is true of the particles that make up a substance? a. particles in a liquid have more energy than particles in a gas. b. particles in a liquid and particles in a solid have the same amount of energy. c. particles in a gas have more energy than particles in liquid. d. particles in a solid have moe energy than particles in a gas.

Answers

Explanation:

so sorry

don't know but please mark me as brainliest please

Other Questions
The table below lists the scores for a game of cards in which the highest score wins. Players A, B, C, and D recorded their scores for each round, but they did not total the scores until the end of the game.Rounds: 1 2 3 4 5 6 7 8A 130 64 0 -14 -78 158 -68 50B 72 97 13 -7 120 57 80 -37C -26 45 109 -9 67 -56 105 0D -47 54 126 0 -65 95 144 -6If the game ends after 5 rounds, which answer choice correctly lists the order of the players from lowest score to highest score?F. A, B, C, DG. D, A, C, BH. D, C, B, AJ. D, B, A, C Choose the correct sentence that would replace the indirect object with a pronoun: Je donne un cadeau mes parents. (1 point) Group of answer choices Je lui donne un cadeau. Je la donne un cadeau. Je les donne un cadeau. Je leur donne un cadeau. What did you LEARN about causes of family conflict? worth brainliest!!!The _____ are considered to be Mexico's "founding culture" Why would the law of cosines be used to solve for b in the triangle below? SAS is given, and the unknown measure, b, is a side length. SSA is given, and the unknown measure, b, is a side length O 36 O 3.5 7 SSS is given, and the unknown measure, b, is an angle measure. ASA is given, and the unknown measure, b, is an angle measure. DONE b Five years ago, Johns age was half of the age he will be in 8 years. How old is he now? Show your steps. Function and Linear question look at the imageI will give brainliest if correct Please help 100 points!!! :)Who ever answers right first get's brainliest!!! :) Mr. Gomez needs to rent a moving truck. Company "A" charges $75 plus a $50 a day and Company "B" charges $105 plus $35 a day. Write an equation that can tell after how many days would the price be the same. The function of root cap is.....A. Absorb waterB. Enlarge the absorption of waterC. Growth of rootD. Protects apical meristem Identify a pair of Alternate Exterior Angles Find the area of the circle. What are the angle names given in the picture? Plzzzz anyone answer I post question but no one answers them but plz anyone answer this time its a project and its due date is today plz helppp 20 points math test How did Samudra Guptas conquests differ from those of other rulers?A.His conquests were to the north.B. His conquests regained lost territory.C.His conquests covered more territory.D.His conquests were along bodies of water. Explain how roots hair cells use osmosis to take up water. choose the adjectival clause Sorry but I need help once again.. -w- Which inequality does this graph represent?O-10-1 < xOx=-1Oxs-1 answer correctly for a brainleist! :)