Answers
Answer:
you need to multiply the momentum and the mass
Related Questions
Select all that apply. The spectrum of Star Y is compared to a reference hydrogen spectrum. What can be concluded about Star Y? Reference (normal) Hydrogen Spectrum Star Y I 500 550 600 650 700 750 400 450 9200 OdyssepWare, Ing. Star Y is showing radial motion Star Y is moving away from the Earth Star Y is moving toward the Earth Star Y is showing transverse motion
Answers
Answer:
Star Y is showing radial motion
Star Y is moving toward the Earth
Explanation:
Just answered this question on a quiz and got it right.
Star Y is showing radial motion
Star Y is moving towards earth.
What is a spectrum ?Spectrum is defined as the arrangement of radiations emitted by atoms or molecules based on their characteristic wavelength and frequency.
Here,
The spectrum of the star Y is given and is compared to a reference hydrogen spectrum. The range of wavelengths of the star is given. The spectrum of the star shows that the wavelengths are shifted such that from longer wavelengths to shorter wavelength. This phenomenon of shift in wavelengths from higher to lower is known as blue shift. The star shows blue shift that means shifted to shorter wavelength or it can be said as shifted from lower frequency to higher frequency. As a result, it can be concluded that the star Y is moving towards the earth which implies Star Y is showing radial motion.
Hence,
The star Y is showing radial motion.
Star Y is moving towards the earth.
To learn more about spectrum, click:
https://brainly.com/question/6562844
#SPJ7
which one is correct:
Average acceleration of an object is the:
Change in its position divided by the change in time
Change in time divided by the change in its position
Change in its velocity divided by the change in time
Change in time divided by the change in its velocity
Answers
Answer:
Option (c) is correct.
Explanation:
Acceleration of an object is given by the formula as follows :
[tex]a=\dfrac{v-u}{t}[/tex]
Where
u and v are initial and final velocity
t is time
(v-u) is also called the change in velocity
So, the acceleration of an object is equal to the rate of change of velocity. Hence, the correct option is (c) " Change in its velocity divided by the change in time".
What unit is used to measure energy when calculating specific heat capacity? Give the abbreviation, not the full name.
Answers
The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).
What unit is used to measure energy?The specific heat capacity should be determined in joules per kilogram degree-celsius ( J k g − 1 ∘ C − 1 ).
It is to be supplied for the substance with respect to mass and it increased the temperature.
Hence, The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).
Learn more about unit here: https://brainly.com/question/16660726
The unit used to measure energy when calculating specific heat capacity is the joule (J).
The joule (J), a unit used to quantify energy, is used to calculate specific heat capacity. In the International System of Units (SI), the joule serves as the default unit of energy.
It is described as the quantity of energy that is delivered when one newton of force is exerted across a one-meter distance.
Thus, the quantity of heat energy needed to increase the temperature of a particular substance by a specific amount is measured as specific heat capacity. J/kg°C, or joules per kilogramme per degree Celsius, is the unit of measurement.
For more details regarding specific heat, visit:
https://brainly.com/question/31608647
#SPJ6
A freight train has a mass of 3.8 x 10^7 kg. The locomotive can exert a force of 6.5 x 10^5 N to pull the train.
Required:
a. How long does it take the train to go from rest to 50 km/hr?
b. If there is air resistance of 2.0 x 10^5 N, what is the acceleration of the train, and how long does it take the train to go from rest to 50 km/hr?
Answers
Answer:
(a) The time taken for the plane to reach 50 km/hr is 811.97 s
(b) (i) the acceleration of the plane is 0.012 m/s²
(ii) The time taken for the plane to reach 50 km/hr is 1172.85 s
Explanation:
Given;
mass of the freight train, m = 3.8 x 10⁷ kg
force applied to pull the train, F = 6.5 x 10⁵ N
a. How long does it take the train to go from rest to 50 km/hr?
Given;
initial velocity, u = 0
final velocity, v = 50 km/hr = 13.889 m/s
Apply Newton's second law of motion to determine the time traveled by the train at the given speed;
[tex]F = ma = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{6.5*10^5}\\\\t = 811.97 \ s[/tex]
(b)
(i) the acceleration of the plane
Given;
air resistance, = 2.0 x 10⁵ N
Apply Newton's second law of motion;
∑F = ma
6.5 x 10⁵ N - 2.0 x 10⁵ N = ma
4.5 x 10⁵ N = ma
[tex]a = \frac{4.5 * 10^5 }{m}\\\\a = \frac{4.5 * 10^5 }{3.8*10^7}\\\\a = 0.012 \ m/s^2[/tex]
(ii) time taken for the plane to reach 50 km/hr is given by;
[tex]F = \frac{m(v-u)}{t}\\\\t = \frac{m(v-u)}{F}\\\\t = \frac{3.8*10^7(13.889-0)}{4.5*10^5}\\\\t = 1172.85 \ s[/tex]
Find the magnitude of the gravitational force (in N) between a planet with mass 6.00 X 10^24 kg and its moon, with mass 2.50 X 10^22 kg, if the average distance between their centers is 2.70 X 10^8 m. What is the moon's acceleration (in m/s2) toward the planet? (Enter the magnitude.) What is the planet's acceleration (in m/s2) toward the moon? (Enter the magnitude.)
Answers
Answer:
Magnitude of gravitational force between this planet and its moon: approximately [tex]1.37 \times 10^{20}\; \rm N[/tex].
Acceleration of this moon towards the planet: approximately [tex]5.49 \times 10^{-3}\; \rm m \cdot s^{-2}[/tex].
Acceleration of this planet towards its moon: approximately [tex]2.29 \times 10^{-5}\; \rm m \cdot s^{-2}[/tex].
Explanation:
Look up the gravitational constant, [tex]G[/tex]:
[tex]G \approx 6.67 \times 10^{-11}\; \rm m^3\cdot kg^{-1} \cdot s^{-2}[/tex].
Assume that both this planet and its moon are spheres of uniform density. When studying the gravitational interaction between this planet and its moon, this assumption allows them to be considered as two point masses.
The formula for the size of gravitational force between two point masses [tex]m_1[/tex] and [tex]m_2[/tex] with a distance of [tex]r[/tex] in between is:
[tex]\displaystyle F = \frac{G \cdot m_1 \cdot m_2}{r^2}[/tex],
where [tex]G[/tex] is the gravitational constant.
Let [tex]m_1[/tex] and [tex]m_2[/tex] denote the mass of this planet and its moon, respectively.
Calculate the size of gravitational force between this planet and its moon:
[tex]\begin{aligned} F &= \frac{G \cdot m_1 \cdot m_2}{r^2} \\ &\approx \frac{6.67 \times 10^{-11}\; \rm m^3 \cdot kg^{-1} \cdot s^{-2} \times 6.00 \times 10^{24}\; \rm kg \times 2.50 \times 10^{22}\; \rm kg}{{\left(2.70 \times 10^{8}\; \rm m\right)}^2} \\ &\approx 1.37 \times 10^{20}\; \rm N\end{aligned}[/tex].
Assume that other than the gravitational force between this planet and its moon, all other forces (e.g., gravitational force between this planet and the star) are negligible. The magnitude of the net force on the planet and on the moon should both be approximately [tex]1.37 \times 10^{20}\; \rm N[/tex].
Apply Newton's Second Law of motion to find the acceleration of this planet and its moon:
[tex]\displaystyle \text{acceleration} = \frac{\text{net force}}{\text{mass}}[/tex].
For this moon:
[tex]\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{2.50 \times 10^{22}\; \rm kg} \approx 5.49\times 10^{-3}\; \rm m \cdot s^{-2}[/tex].
For this planet:
[tex]\displaystyle \frac{1.37 \times 10^{20}\; \rm N}{6.00 \times 10^{24}\; \rm kg} \approx 2.29 \times 10^{-5}\; \rm m \cdot s^{-2}[/tex].
"She finished the sprint with the speed of a cheetah." This statement represents which of the
following functions of language? (2 points)
correct answer is poetic.
Answers
Answer:
Poetic
Explanation:
I took the test
Answer:
Poetic
Explanation:
I got it right on the test
Once a player catches the Frisbee they are only allowed to pivot like in
basketball.
True
False
Answers
Can someone help plzzzzzzz I need it ASAP thank you
Answers
Answer:
Explanation:
Frequency is oscillations per second.
So we have to find the Number of seconds she paced.
2 minutes = 2 X 60
= 120 seconds
Therefore,
Her frequency = 10 / 120
= 1/12 Hertz
Review Question 1
A group of students collected the data shown below while attempting to
measure the coefficient of static friction (of course, it looks like this group
varied the amount of mass sitting on the block with each trial - this is not
recommended). Nonetheless, what is their average coefficient of static friction?
Mass of block (g)
Hanging mass (kg)
Trial
1
105
0.053
2
165
0.081
3
220
0.118
4
280
149
5
315
0.180
6
385
0.198
Answers
Answer:
The average coefficient of static friction = 0.130
Explanation:
The average coefficient of static friction = [tex]\frac{sum of coefficient of static friction}{number of trials}[/tex]
From the given question, the coefficient of static friction given are:
0.053, 0.081, 0.118, 0.149, 0.180, 0.198
Thus,
the sum of the given coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198
= 0.779
The average coefficient of static friction = [tex]\frac{0.779}{6}[/tex]
= 0.129833
= 0.130
Therefore, the average coefficient of static friction is 0.130.
The most commonly accepted theory of muscle growth states that ______________ ________ within a muscle activate a(n) ________________ response process that causes dormant cells to build and regenerate muscle tissue.
A. contractions; inhibitory
B. tension; neurological
C. microscopic tears; inflammatory
D. stress; cytokines
Answers
Answer:
C
Explanation:
The most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.
What is the significance of the microscopic tears in muscle?It has negative consequences on the muscle, and it is also known as "microtrauma," which occurs as a result of muscle contraction and is a normal part of the muscle repair and growth process. Here, the fibers in the muscle are damaged, and in response, the body initiates a repair process. This leads to muscle growth and increased strength and is helpful for muscle repair.
Hence, the most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.
Learn more about the microscopic tears in muscle here.
https://brainly.com/question/29457664
#SPJ2
This is my question
Answers
Answer:
N = 470 [N]
Explanation:
The normal force is defined as the reaction exerted by the surface where the body is located in the opposite direction to the weight component.
It can be easily calculated by means of the product of mass by gravitational acceleration.
N = m*g
where:
N = normal force [N] (units of Joules)
m = mass = 47 [kg]
g = gravity acceleration = 10 [N]
N = 47*10
N = 470 [N]
Doing specific exercises to improve a particular area of fitness is called flexibility? True or false
Answers
Answer:
True.
Explanation:
Exercises and yoga are important for the individual's health. The exercise makes the individual, fit, healthy and also reduces the chances of the deadly disease in human beings.
Different types of exercise can be performed by the individual. The aerobic exercises increase the amount of oxygen in the body. With the aerobic exercise, the exercise that can increase the strength, flexibility and total fitness must also be included.
A force F = (2xî + 4yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-direction from the origin to x = 4.99 m. Find the work W = ∫ F · dr done by the force on the object (in J).
Answers
Answer:
Work done, W = 24.9001 J
Explanation:
Given that,
Force, F = (2xî + 4yĵ) Where x and y are in meters
This force acts on an object as the object moves in the x-direction from the origin to x = 4.99 m.
We need to find the work done by the force on the object. It is given by :
[tex]W=\int\limits^a_b {F dr} \\\\W=\int\limits^{4.99}_0 {(2xi+4yj)dx} \\\\W=\int\limits^{4.99}_0 {2xi\ dx} \\\\W=x^2|_0^{4.99}\\\\\text{Applying limits}\\\\W=(4.99)^2-0^2\\\\W=24.9001\ J[/tex]
So, the work done is 24.9001 J.
A large bottle contains number medical tablets each having a mass of 250
mg.The mass of all tablets is 1kg.Calculate the number of tablets in the
bottle.
Answers
First of all, this isn't physics. But, here's the answer:
1 gram is a 1000 milligram and 250 milligram is 250 * 0.001 g which is 0.25 gram.
Since 1 kg is 1000 g, we divide 1000 by 0.25 and we get 1000 * 4 which is 4000.
There are [tex]4000[/tex] tablets inside the bottle.
What does a switch in an electrical circuit do?
O A. It concentrates negative charges on one side of the circuit when it
is open.
B. It concentrates negative charges on one side of the circuit when it
is closed.
C. It allows electrons to flow from one part of the circuit to another
when it is open.
D. It allows electrons to flow from one part of the circuit to another
when it is closed.
Answers
Answer:
It allows electrons to flow from one part of the circuit to another
when it is closed.
Explanation:
hope this helps <3 !!
Answer: D
Explanation:
A change of temperature of 20 C is equivalent to a change in thermodynamic temperature of
Answers
Answer:
20 K
Explanation:
It is given that,
The change in temperature is 20 C.
We need to find the change in thermodynamic temperature.
If teperauture T₁ = 0° C = 0+273 = 273 K
T₂ = 20° C = 20 + 273 = 293 K
The change in temperature,
[tex]\Delta T=T_2-T_1\\\\=293-273\\\\=20\ K[/tex]
So, the change in temperature of 20°C is equivalent to 20 K.
The change in thermodynamic temperature is equal to 20 Kelvin.
Given the following data:
Change in temperature = 20°CTo determine the change in thermodynamic temperature:
A thermodynamic temperature can be defined as an absolute measure of the average total internal energy possessed by a body or an object. Thus, thermodynamic temperature is typically measured in Kelvin (K).
Mathematically, the change in temperature of an object is given by the formula:
[tex]\theta = T_f - T_i[/tex]
Where:
[tex]T_i[/tex] is the initial temperature (0°C)[tex]T_f[/tex] is the final temperature (20°C).Next, we would convert the values in degree Celsius to Kelvin:
Conversion:
0°C = 273 K
20°C = 273 + 20 = 293 K
For the change in thermodynamic temperature:
[tex]\theta = 293 - 273\\\\\theta =20\;K[/tex]
Read more: https://brainly.com/question/22069910
4.
Vectors P and Q are drawn to scale.
P
Which diagram represents the vector (P +Q)?
A
B
с
D
plz help I will fail.
can anyone plz help me.
plz
Answers
Answer:
hindi ko gets
Explanation:
ang gulo naman nyan
An amateur golfer swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for only 0.00360 s. After the collision, the ball leaves the club at a speed of 34.0 m/s. What is the magnitude of the average force (in N) exerted on the ball by the club?
Answers
Answer:
The average force ≅ 519.44 N.
Explanation:
Impulse = change in momentum of a body
i.e Ft = m(v - u)
where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.
m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s
So that,
F x 0.00360 = 0.055(34 - 0)
F x 0.00360 = 0.055 x 34
= 1.87
F = [tex]\frac{1.87}{0.0036}[/tex]
= 519.4444
The average force exerted on the ball by the club is approximately 519.44 N.
Help me with this please !!
Pt 1_It would be harder to do experiments on or near jupiter for many reasons ! One being that jupiters top layers are known to be gas. However if we could hover over Jupiter and test its gravity, describe or sketch the shape of the position vs time graph for a dropped object.
PT2_ The acceleration due to gravity near Jupiter is 25.95m/s. If a hammer were dropped, how fast wouldit be going after falling 20.0 meters. Show your work !
Answers
Answer:
he is right he Is
Explanation:
step by step explanation
which statement is true of the particles that make up a substance? a. particles in a liquid have more energy than particles in a gas. b. particles in a liquid and particles in a solid have the same amount of energy. c. particles in a gas have more energy than particles in liquid. d. particles in a solid have moe energy than particles in a gas.
Answers
Explanation:
so sorry
don't know but please mark me as brainliest please
A 2.0 cm thick brass plate (k_r = 105 W/K-m) is sealed to a glass sheet (kg = 0.80 W/K m), and both have the same area. The exposed face of the brass plate is at 80°C, while the exposed face of the glass is at 20 °C. How thick is the glass if the glass brass interface is at 65 C? Ans. 0.46 mm
Answers
The CERN particle accelerator is circular with a circumference of 7.0 km.
Required:
a. What is the acceleration of the protons (m=1.67×10^−27kg) that move around the accelerator at of the speed of light? (The speed of light is v=3.00×10^8m/s.)
b. What is the force on the protons?
Answers
Answer:
Explanation:
a) centripetal acceleration is the acceleration of a body in a circular path. It is expressed as;
a = mv²/r
m is the mass of proton = 1.67×10^−27kg
v is the velocity = 3.00×10^8m/s
r is the radius
Since C = 2πr
7000m = 2πr
r = 7000/2π
r = 1114.08m
Substitute
a = 1.67×10^−27 (3.00×10^8)²/1114.08
a = 1.67×10^−27 * 9×10^16/1114.08
a = 15.03*10^-11/1114.08
a = 0.001346*10^-11
a = 1.346*10^-14m/s²
b) Force on the proton = mass * acceleration
Force = 1.67×10^−27kg * 1.346*10^-14
Force = 2.246*10^-41N
hence the force on the proton is 2.246*10^-41N
free brainlyest. if get thes quston right Devlin recorded the number of days of rain for his town over three months. The bar graph below shows his data.
Bar Graph 1
Explain why his data is more about climate than weather.
Question 12 options:
Answers
Answer:
Weather is the conditions (temperature, wind etc.) at a given time, like on that day. Climate, which is what his data would show, is the conditions over an extended period of time like the 3 months he collected data
A group of students collected the data shown below while attempting to measure the coefficient of static friction (of course, it looks like this group varied the amount of mass sitting on the block with each trial - this is not recommended). Nonetheless, what is their average coefficient of static friction?
Trial Mass of block (g) Hanging mass (kg)
1 105 0.053
2 165 0.081
3 220 0.118
4 280 0.149
5 315 0.180
6 385 0.198
Answers
Answer:
0.130
Explanation:
From the given data, the coefficient of static friction for each trial are:
1. 0.053
2. 0.081
3. 0.118
4. 0.149
5. 0.180
6. 0.198
The sum of the coefficient of static friction = 0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198
= 0.779
So that;
the average coefficient of static friction = [tex]\frac{sum of coefficient of static friction}{number of trials}[/tex]
= [tex]\frac{0.779}{6}[/tex]
= 0.12983
The average coefficient of static friction is 0.130
The average coefficient of static friction is 0.13.
The coefficient of static friction is obtained using the formula; μ = F/R
Where;
F = force acting on the body
R = reaction
μ = coefficient of static friction
The average of measurements is given as; ∑summation of measurements/number of measurements
We can see from the question that there were 6 measurements of the coefficient of static friction. Hence, the average coefficient of static friction is obtained from;
0.053 + 0.081 + 0.118 + 0.149 + 0.180 + 0.198/6
= 0.13
The average coefficient of static friction is 0.13
Learn more: https://brainly.com/question/8155254
Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
acceleration of Claudia's 1.80kg foot? B) What is the acceleration of the table if it has a mass
of 20.0kg? (ignore any frictional effects) C) Why would Claudia's toe hurt less if the table had
less mass?
Answers
Answer:
A.) acceleration= 55.6m/s^2
B.) acceleration of table= 5.0m/s^2
C.) More acceleration
Explanation:
A.) 100N/1.8kg= -55.6
B.) 100N÷20kg= 5
C.) Because since the table would have less mass, it would have had to accelerate more
Draw a graph of these results
Answers
Answer:
Actually I know but I can't cause it will take time
A physicist's left eye is myopic (i.e., nearsighted). This eye can see clearly only out to a distance of 35 cm.Find the focal length and the power of a lens that will correct this myopia when worn 2.0 cm in front of the eye.
Answers
Answer:
Explanation:
To get the focal length, we will use the lens formula;
1/f = 1/u + 1/v
f is the focal length
u is the object distance
v is the image distance
Given
since the physicist's left eye is myopic, it will be corrected using concave lens and the image distance is negative.
u = 35cm
v = -2.0
1/f = 1/35-1/2
1/f = 2-35/70
1/f = -33/70
f = -70/33
f = -2.12 cm
f = -0.0212m
Power of a lend is the reciprocal of its focal length
Power of the lens = 1/f
P = 1/-0.0212
P = -47.17dioptres
The power of the lens is -47.17D
what is the state of y when y = k/x, x is halved.
Answers
Answer:
y becomes doubled.
Explanation:
If;
y = [tex]\frac{k}{x}[/tex]
what is the state of y when x is halved;
the given expression is an inverse relationship. When y increases, x is supposed to decrease and vice versa.
if x is halved; x = [tex]\frac{x}{2}[/tex]
[tex]\frac{k}{\frac{x}{2} }[/tex] = [tex]\frac{2k}{x}[/tex]
Now compare :
[tex]\frac{k}{x}[/tex] : [tex]\frac{2k}{x}[/tex]
we see that y becomes doubled
I'll give brainliest if you give me a good awnser. :)
A football player kicks a ball with a force of 50 N. Find the impulse on the ball if his foot stays in contact with the football for 0.01 second.
Answers
Answer:
0.5
Explanation:
The answer is 0.5! I hope this helps you out!!
If you measured the final velocity of the car to be 1 m/s and the initial mass of the car remains the same, how much coal was added to the car in kg
Answers
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
[tex]p = 14033.7 \ kg\cdot m/s[/tex]
b
[tex]v = 1.22 \ m/s[/tex]
c
[tex]m_2 = 9506.7 \ kg[/tex]
Explanation:
From the question we are told that
The mass of the coal car is [tex]m_1 = 4527 \ kg[/tex]
The velocity is [tex]v_i = 3.1 \ m/s[/tex]
The load of coal dropped is [tex]m_2 = 6952 \ kg[/tex]
Generally the momentum of the system before the coal is added is mathematically represented as
[tex]p = m_j * v_i[/tex]
=> [tex]p = 4527 * 3.1[/tex]
=> [tex]p = 14033.7 \ kg\cdot m/s[/tex]
Generally from the law of momentum conservation is mathematically represented as
[tex]m_1 * v_i + m_2 * v_2 = (m_1 + m_2 )v[/tex]
Here [tex]v_2[/tex] is the velocity of the load before it is dropped and the value is 0 m/s
So
=> [tex]v =\frac{m_1 * v_i }{m_1 + m_2}[/tex]
[tex]v = \frac{4527 * 3.1 }{( 4527 + 6952 )}[/tex]
=> [tex]v = 1.22 \ m/s[/tex]
When v = 1m/s and [tex]m_1[/tex] remain the same
Then
=> [tex]1 =\frac{4527 * 3.1 }{4527 + m_2}[/tex]
=> [tex]4527 + m_2 = 14033.7[/tex]
=> [tex]m_2 = 9506.7 \ kg[/tex]