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thanks + BRAINLIST only for correct answer

Answer:

The AMOUNT of oxygen and carbon atoms released by photosynthesis are EXACTLY EQUAL to the atoms of these material contained in carbon-dioxide converted. In this way photosynthesis has conserved the mass or material, and in this way followed the law of conservation of mass.

Answer:

p₀ = 1.53 10⁴ kgm / s,    p_f = 4.74 10⁴ kg m / s

Explanation:

The moment is defined by

         p = mv

the initial moment is

         p₀ = m v₀

indicate the mass of the car m = 1.58 10³ kg and its initial velocity v₀ = 10 m/s

         p₀ = 1.58 10³   10

         p₀ = 1.53 10⁴ kgm / s

the final moment is

indicate that it increases its speed at v = 30 m/s, in a time of t = 15 s

we look for the moment

         p_f = m v

         p_f = 1.58 10³   30

         p_f = 4.74 10⁴ kg m / s

Answer:

Explanation:

If unit vector towards east is represented by i in the present case ,

initial horizontal velocity of aircraft towards east is 70 m /s . The package dropped by the aircraft will also have same velocity while getting separated from the aircraft . Hence its velocity is represented by the vector ,

v = 70 i .

Its vertical velocity of package at that time will be zero so

v = 70 i + 0 j

= 70 i

Initial Velocity can be defined as the velocity at which the motion starts.

Initial Velocity for the package is [tex]70i[/tex].

Given that an aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m.

Here we express the steady velocity as [tex]u\;\rm m/s[/tex]. Distance is expressed by [tex]d\;\rm meter[/tex]. Initial Velocity can be expressed as [tex]v\;\rm m/s[/tex].

Initial velocity can be calculated by the formula given below.

[tex]v\;=\;u\;+\;at[/tex]

In the above formula, [tex]a[/tex] is expressed the acceleration and [tex]t[/tex] is expressed the time of the motion.

For the initial velocity, time [tex]t\;=\;0[/tex] because motion starts in the vertical direction. Let us assume that unit vector can be expressed by [tex]i[/tex] and [tex]j[/tex].

Initial velocity formula in vector form is given below.

[tex]v\;=\;ui\;+\;atj[/tex]

By substituting all the values in the above formula, initial velocity is

[tex]v\;=\;ui\;+\;a\times0j\\v\;=\;ui\\v\;=\;70i[/tex]

So the initial velocity of the package is 70[tex]i[/tex].

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Answer:

 R_eq = 6 Ω

Explanation:

In a series circuit the current is constant throughout the circuit and the resistance is the sum of all the resistances in it.

         R_eq = ∑

in this case we have

         R_eq = R₁1 + 3 R₂

where R₁ is the resistance of the fan and R₂ the resistance of each light, we must clarify that we will assume that the resistance of the lights does not change with temperature

let's calculate

          R_eq = 3 + 3 1

           R_eq = 6 Ω

Answer:

6 ohms

Explanation:

Answer:

acceleration is the rate of change of velocity

therefore in the above statement, the velocity increases twice per second.

when acceleration is negative, then it is accelerated motion.

ie. the car accelerates twice per second

Answer:

x = 7226.94 m

y = 1677.4 m

Explanation:

This is a classic problem of a parabolic move. Let's analyze the given data.

The speed is 300 m/s but it's fired at 55°, so the x and y component of the speed would be:

Vx = 300 cos55 = 172.07 m/s

Vy = 300 sin55 = 245.75 m/s

Now, to get the x and y components of the shell, we need to apply the following expressions:

X = Xo + Vx*t    (1)

Y = Yo + Vy*t - 1/2 gt²   (2)

Xo and Yo is 0, and we already have the speed in x and y, so the components are:

X = 0 + (172.07)(42)

For the y component:

Y = 0 + (245.75)(42) - 1/2 (9.8)(42)²

Y = 10321.5 - 8643.6

Hope this helps

The average force on our body when  jump off a step, having a stiff-legged landing is 10 time smaller. Thus, the correct answer is option D, reduced by 10.

The average force is the force exerted by an object moving at a given rate of speed, i.e. velocity, over a given time period. The term "average" is used here to indicate that the velocity is not instantaneous or precisely measured.

When we jump from a certain height and bend our knees upon reaching the ground, the time it takes to come to complete rest is increased by ten times , and the impact force is reduced to one-tenth of its initial value. This is consistent with Newton's second law of motion, which states that the rate of change in velocity is proportional to the force applied to the body.

Therefore, if you make the time of the impact about 10 times as great as for a stiff-legged landing, the average force that you experience would be 10 times smaller.

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Answer:

The standard deviation is a measure of the dispersion of a series of data

Result = x_{average} ± σ

Explanation:

The standard deviation is a measure of the dispersion of a series of data, it is generally used when a series of measurements of some parameters are made and it is desired to take into account the statistical fluctuations of these measurements, its formula is

           [tex]\sigma = \sqrt { \frac{\sum (x_i -x_{average} )^2}{ N} }[/tex]  

where N is the number of measurements

This is a measure equivalent to the absolute error in a single measurement.

Therefore, the number of decimal places in a result must not be greater than the standard deviation.

         Result = x_{average} ± σ

Answer:

The answer should be the one on the top in the picture.

Explanation:

Friction is opposing the downward movement of the crate therefore the friction force is pointing upwards. that is why the answer should be the one on the top of the picture.

Answer:

latitude implies the geographic coordinates that determine the distance of a point, north- South of the equator. longitude alludes to the geographic coordinates, which indentifies the distance of a point, east-west of the prime meridian.

Answer:

[tex] \boxed{q = 1.2 \times {10}^{ - 6} C}[/tex]

Explanation:

[tex]f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6} [/tex]

Answer:

a) The bullet will penetrate 0.375 meters into the bag of sand.

b) The average force exerted by the sand is 15 newtons.

Explanation:

The statement is incorrectly written. The correct form is presented below:

A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.

a) How far the bullet will penetrate into the bag of sand?

b) The average force exerted by the sand?

b) The average force exerted by the sand on the bullet ([tex]F[/tex]), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:

[tex]F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the bullet, measured in kilograms.

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the bullet, measured in meter per second.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]\Delta t = 0.05\,s[/tex], then the average force exerted by the sand is:

[tex]F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}[/tex]

[tex]F = -15\,N[/tex]

The average force exerted by the sand is 15 newtons.

a) The distance travelled by the bullet ([tex]\Delta s[/tex]), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:

[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }[/tex] (2)

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]F = -15\,N[/tex], then the distance travelled by the bullet is:

[tex]\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}[/tex]

[tex]\Delta s = 0.375\,m[/tex]

The bullet will penetrate 0.375 meters into the bag of sand.

Answer:

C.) To indicate different versions of the same variable.

Explanation:

Variables in physics often include a subscript. These subscripts are used for indicating different versions of the same variable in physics.

Basically, subscripts are used to represent the beginning (initial) and ending (final) position or point of a variable in physics.

For example, we would look at Gay Lussac' Law of gases.

Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

[tex] PT = K[/tex]

[tex] \frac{P1}{T1} = \frac{P_{2}}{T_{2}}[/tex]

Where;

[tex] T_{1} [/tex] represents the initial temperature.

[tex] T_{2} [/tex] represents the initial temperature.

[tex] P_{1} [/tex] represents the initial pressure.

[tex] P_{2} [/tex] represents the initial pressure.

Note: 1 and 2 are the subscript while T and P are the variables.

Answer:true

Explanation:

Answer:

Asexual reproduction produces offspring that are genetically identical to the parent because the offspring are all clones of the original parent. During sexual reproduction the genetic material of two individuals is combined to produce genetically diverse offspring that differ from their parents.

Explanation:

Answer:

v = 12.12 m/s      

Explanation:

It is given that,

Radius of circle, r = 30 m

The coefficient friction between tires and road is 0.5,

The centripetal force is balanced by the force of friction such that,

v = 12.12 m/s

So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.

Answer:

Force is equal to Mass Multiplied by Acceleration

F = M x A

Answer:

Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

Answer:

-10.8m/s^2

Explanation:

a=change in velocity/change in time

-27 m/s/2.5=10.8m/s^2

or if its not negative

27m/s/2.5=10.8m/s^2

Answer:

the bonds that are formed

Explanation:

Energy is absorbed in order to break bonds.  Energy is released when new bonds are formed. Bond-making is a process of exothermic. Whether the reaction is endothermic or exothermic refers to the difference between the energy needed to break bonds and the energy released when new bonds are formed.

Answer: c

Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.

If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.

If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.

The not consistent with a car that is accelerating is a car is moving at a high speed.

A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).

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Answer:

The force felt is the same

Explanation:

Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body. In the attachment we can see a free body diagram which is a schematic of the forces without the details of the bodies.

               N-W = 0

               fr = ma

where N is the normal, W the weight of the body, fr the friction force, m the mass and a the acceleration

The friction force is a macroscopic representation of the interactions between the two surfaces, it is given by the expression

             fr = μ N

where μ is the coefficient of friction between the two surfaces.

We substitute

             μ mg = m a

             a = μ g

Kinematics study the movement of bodies, looking for relationships between position, speed and acceleration.

             v= v₀ – at t

In this case they give tables and graphs with the values ​​of time and speed, where we can see that the relationship is a straight line that has as equation

            y = ax +b

Where y is the dependent variable, x is the independent variable, a is the slope, and b is the cutoff point.

If we relate the two equations:

          a = mug

          μ = [tex]\frac{a}{g}[/tex]

Using linear regression the slope and cutoff point is:

The man.

The slope is a = -0.8 m/s² and the cut-off point b= 4.86 m/s.

Let's calculate the coefficient of friction.

          μ =  [tex]\frac{0.8}{9.8}[/tex]  

          μ  = 0.082

The child.

The slope is a = -0.98 m/s² and the cut-off point b= 4.72 m/s.

We calculate the coefficient of friction.

          μ  = [tex]\frac{0.98}{9.8}[/tex]  

          μ  = 0.1

The relationship between the two coefficients of friction is

        [tex]\frac{\mu_{man} }{\mu_{boy}} = \frac{0.082}{0.1}[/tex]  

         [tex]\frac{\mu_{man}}{\mu_{boy}} = 0.82[/tex]

The results are very exact since there are values ​​of several points in the route and the graphical analysis gives the best possible value for all the points.

There are some variables not taken into account, one of the most important is friction with the wind and wind speed.

In conclusion using Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:

Learn more about kinematics and graphical analysis here: brainly.com/question/11579754

Answer:

15 m/s towards the North

Explanation:

we need to add both velocities to find the effective velocity from the point of view of an observer at rest on the shore:

2.5 m/s + 12.5 m/s = 15 m/s pointing North

Answer:

I. They come from sources across space

II. They travel in a straight line from their source.

III. They can be reflected by some types of material.

Explanation:

Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

The following statements about light waves are true;

I. They come from sources across space.

II. They travel in a straight line from their source.

III. They can be reflected by some types of material. reflection occurs when a ray of light or wavefronts bounces off a smooth surface. Thus, when light hit a surface, it bounces back to the medium from which it was originally propagated with.

However, light waves cannot travel through all type of material except materials that are transparent or translucent but not opaque.

Answer:

i belive it should be C

Explanation:

Answer:

Wave height is the vertical distance between the crest (peak) and the trough of a wave. Some other definitions: Still-Water Line is the level of the lake surface if it were perfectly calm and flat. Crest is the highest point on the wave above the still-water line.

Explanation: