NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS ONLY PLZ WILL REPORT FAKE ANSWERS

NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS ONLY PLZ WILL REPORT FAKE ANSWERS

Answers

Answer 1

Answer:

A.   Midline is -1

Step-by-step explanation:


Related Questions

please help I'll give brilliantist:)​

Answers

Answer:

-7

Step-by-step explanation:

The full coordinate is (-7,3) the dot is on the line between -6 and -8

Answer:

-7

Step-by-step explanation:

x = 3

y = -7

the answer is just -7

Find the measure of the missing angles. Help please

Answers

Answer:

< 1 = 92º

< 2 = 24º

< 3 = 35º

< 4 = 35º

< 5 = 81º

Step-by-step explanation:

< 1 = 180 - 88 = 92

< 3 = 64 corresponding angle due to parallel lines

< 2 = 180 - (92 + 64) = 24

< 4 = 180 - (64 - 81) = 35

< 5 = 180 - (64 + 35) = 81

I NEEED SOMEBODY TO HELP ME OUT WITH THIS QUESTION THXS

Answers

Answer:

The answer is less than that is the answer

Consider the initial value problem my''+cy'+ky=F(t), y(0)=0, y'(0)=0, modeling the motion of a spring mass dashpot system initially at rest and subjected to an applied force F(t), where the unit of force is the Newton (N). Assume that m=2 kilograms, c=8 kilograms per second, k=80 Newtons per meter, and F(t)=20 sin(6t) Newtons.
1. Solve the initial value problem. y(t)=?
2. Determine the long term behavior of the system. Is lim as t goes to infinity of y(t)=0? If it is, enter zero. If not, enter a function that approximates y(t) for very large positive values of t. For very large positive values of t, y(t) is approximately.. ?

Answers

Answer:

Hence, the [tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex] and approximately value of [tex]y(t)[/tex] is [tex]-0.844[/tex].

Given :

 [tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]

Where  [tex]m=2[/tex] kilograms

           [tex]c=8[/tex] kilograms per second

           [tex]k=80[/tex] Newtons per meter

          [tex]F(t)=20\sin (6t)[/tex] Newtons

Explanation :

(1)

Solve the initial value problem. [tex]y(t)[/tex]

   [tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]

[tex]\Rightarrow 2y''+8y'+80y=20\sin (6t)[/tex]

[tex]\Rightarrow y''+4y'+40y=10\sin (6t)[/tex]

Auxilary equations :[tex]F(t)=0[/tex]

[tex]\Rightarrow r^2+4r+40=0[/tex]

[tex]\Rightarrow r=\frac{-4\pm\sqrt{4^2-4\times 1\times 40}}{2\times 1}[/tex]

[tex]\Rightarrow r=\frac{-4\pm\sqrt{16-160}}{2}[/tex]

[tex]\Rightarrow r=\frac{-4\pm\sqrt{-144}}{2}[/tex]

[tex]\Rightarrow r=\frac{-4\pm12i}{2}[/tex]

[tex]\Rightarrow r=-2\pm6i[/tex]

The complementary solution is [tex]y_c=e^{-2t}\left(c_1\cos 6t+c_2\sin 6t\right)[/tex]

The particular Integral, [tex]y_p=\frac{1}{f(D)}F(t)[/tex]

[tex]y_{y} &=\frac{1}{D^{2}+4 D+40} 25 \sin (6 t) \\\\ y_{y} &=\frac{25}{-6^{2}+4 D+40} \sin (6 t) \quad\left(D^{2} \text { is replaced with }-6^{2}=-36\right) \\\\y_{y} &=\frac{25}{4 D+4} \sin (6 t) \\\\y_{y} &=\frac{25}{4(D+1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(D+1)(D-1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4\left(D^{2}-1\right)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(-36-1)} \sin (6 t) \\\\y_{y} &=-\frac{25}{148}(D-1) \sin (6 t) \\y_{y} &=-\frac{25}{148}\left(\frac{d}{d t} \sin (6 t)-\sin (6[/tex]

Hence the general solution is :[tex]y=y_c+y_p=e^{-2t}(c_1\cos 6t+c_2\sin 6t)-\frac{25}{148}(6\cos 6t-\sin 6t)[/tex]

Now we use given initial condition.

[tex]y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\\y(0) &=e^{-\alpha 0)}\left(c_{1} \cos (0)+c_{2} \sin (0)\right)-\frac{25}{148}(6 \cos (0)-\sin (0)) \\\\0 &=\left(c_{1}\right)-\frac{25}{148}(6) \\\\c_{1} &=\frac{75}{74} \\\\y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\[/tex]

[tex]y^{\prime}(t)=-2 e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)+e^{-2 t}\left(-6 c_{1} \sin 6 t+6 c_{2} \cos 6 t\right)-\frac{25}{148}(-36 \sin (6 t)-6 \cos (6 t)) \\\\y^{\prime}(0)=-2 e^{0}\left(c_{1} \cos 0+c_{2} \sin 0\right)+e^{0}\left(-6 c_{1} \sin 0+6 c_{2} \cos 0\right)-\frac{25}{148}(-36 \sin 0-6 \cos 0) \\\\0=-2\left(c_{1}\right)+\left(6 c_{2}\right)-\frac{25}{148}(-6) \\\\0=-2 c_{1}+6 c_{2}+\frac{75}{74} \\\\0=-2\left(\frac{75}{74}\right)+6 c_{2}+\frac{75}{74} \\\\[/tex][tex]\begin{array}{l}0=-\frac{150}{74}+6 c_{2}+\frac{75}{74} \\\\\frac{150}{74}-\frac{75}{74}=6 c_{2}\end{array}[/tex]

[tex]\begin{array}{l}c_{2}=\frac{25}{148}\\\\\text { Substitute } c_{1} \text { and } c_{2} \text { in } y(t) \text { . Then }\\\\y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex]

(2)

[tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\left(\frac{75}{74} e^{-2 t} \cos 6 t+\frac{75}{148} e^{-2 t} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\frac{75}{74}\left(e^{-2 t}-1\right) \cos 6 t+\frac{25}{148}\left(3 e^{-2 t}+1\right) \sin 6 t \\\\|y(t)| \leq \frac{75}{74} e^{-2 t}-1|\cos 6 t|+\frac{25}{148}\left|3 e^{-2 t}+1\right||\sin 6 t| \\\\[/tex]

[tex]|y(t)| \leq \frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right| \\\\\lim _{t \rightarrow \infty} y(t) \leq \lim _{t \rightarrow \infty}\left\{\frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right|\right\} \\\\\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}\left|\lim _{t \rightarrow \infty}\left(e^{-2 t}-1\right)\right|+\frac{25}{148}\left|\lim _{t \rightarrow \infty}\left(3 e^{-2 t}+1\right)\right|\right\} \\[/tex]

[tex]\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}(-1)+\frac{25}{148}(1)\right\}=-\frac{75}{74}+\frac{25}{148}=-\frac{-150+25}{148}=-\frac{125}{148} \approx-0.844[/tex]

PLEASE HELP FAST WILL MARK BRAINLIEST PLEASEEE

Answers

Answer:

[tex]\frac{8x^{18} }{y^{2} }[/tex]

Step-by-step explanation:

HELP NEEDED ASAP!! Please CAN SOMEONE HELP

Answers

Answer:

Part 1:

y= 23

Part 2:

x=20

Step-by-step explanation:

Part 1:

cos(y) = 48/52

y=cos^-1(48/52)

y=22.619864948~23

Part 2:

48^2+x^2=52^2

x^2=2704-2304

x=sqrt(400)

x=20 or -20.

A negative length makes no sense, so x=20

Answer:

y = 23º

x = 20 cm

Step-by-step explanation:

Cos∅ = adj/hyp

cosy = 48/52

∅ = arccos48/52

use calculator

∅ = 22.619864948040426

Rounded

∅ = 23º

----------------------------------

a² + b² = c²

x² + 48² = 52²

x² = 52² - 48²

x² = 400

x = 20 cm

HELP HELP HELP PLS ✨

Answers

Answer:

C. 18

Step-by-step explanation:

4-6 paris = about 23

10-12 pairs = about 5

28 - 5 = 18

help how to do this due in a few hours​

Answers

Answer:

x=52   y=116

Step-by-step explanation:

because they give you the angle 116.

those two are actually equal.

y=116

since that is true, you can do 180-116=64.

now, you subtract 64-12

which is 52.

In the first 1/6 hour of a rainstorm, 1/10 inch of rain fell. If the rain continued to fall at the same rate, how much rain fell in 2 1/2 hours?

Answers

Answer:

you should multiply or add

Step-by-step explanation:

Joelle bought some fruit at the store. They bought 5 apples and a bunch of bananas. The bananas cost $1.50, and the total cost was $5.24. How much did each apple cost?

Define your variable: a represents…
Write an equation using your variable that matches the situation.
Solve your equation. Show all your steps.
Write your answer in a complete sentence.

Answers

Answer:

$3.74

Step-by-step explanation:

we already know the cost of the banana's and it gives us the total price including apples. So $5.24 - $1.50 = $3.74, and the 3.74 is the cost of apples

Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle
using radians in terms of te over the interval 0

Answers

Answer:

[tex](6\sqrt{3},\,\frac{5\pi}{6})[/tex]

Step-by-step explanation:

The radius  r  can be found from the relationship

 [tex]r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}[/tex]

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

[tex]\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}[/tex]

See the attached image.

Find the exact value of sin A in simplest radical form.

Answers

Using the sine rule,

[tex] \frac{a}{sin(a)} = \frac{b}{sin(b)} = \frac{c}{sin(c)} [/tex]

Here we are going to use the values of A and C,

[tex] \frac{12}{sin(a)} = \frac{14}{sin(90)} \\ \frac{12}{sin(a)} = \frac{14}{1} \\ sin(a) = 12 \div 14 \\ sin(a) = 0.8571[/tex]

So sin(A) = 12/14 = 6/7 = 0.8571, but since the question says in its simplest radical form, I think the closest answer to it should be

[tex] \frac{ \sqrt{3} }{2} [/tex]

Find the component form of the resultant vector.
u=-12i + 35j
Find: -8u
A) 10V 47 - 1 + 10j
B) -40i + 35j
C) 961 – 280j
D) 151 – 5V3.j

Answers

Answer:

C) 96i – 280j

Step-by-step explanation:

Multiplying vector by constant:

When a vector is multiplied by a constant, each component of the vector is multiplied by this constant.

In this question:

u = -12i + 35j

-8u = -8(-12i + 35j) = (8*12i - 8*35j) = 96i - 280j.

The answer is C) 96i – 280j

In a regression analysis, the actual values of Y may be found above or below the regression line. These deviations are called the _____. slope error term variance standard error of the mean standard deviation

Answers

Answer:

Error term

Step-by-step explanation:

Given :

In a regression analysis, the actual values of Y may be found above or below the regression line. These deviations are called the _____. slope error term variance standard error of the mean standard deviation

To find :

Fill in the blanks.

Now, In a regression analysis, the actual values of Y may be found above or below the regression line. These deviations are called the Error term.

Because we use the error term in the regression analysis difference between the actual value of [tex]Y[/tex] and the approximate value of [tex]Y[/tex] which is above of actual value or below of actual value.

 As [tex]Y[/tex]is an actual value and [tex]Y_0[/tex] is an approximate value then,

[tex]|Y-Y_0|[/tex] is an error.

It is a vertical distance between the actual value and the approximate value  of [tex]Y[/tex].

So, the error term is always positive.

What is the value of x?

Answers

Last one 12
I got you:)

I need help please. ​

Answers

the answer it c........

Simran has a bag containing white and yellow marbles. Simran randomly selects one marble from the bag,

records the result, and returns the marble to the bag. The results of the first 65 selections are shown below.

A white marble was selected 41 times.

A yellow marble was selected 24 times.

Based on these results, what is the probability that the next marble Simran selects, rounded to the nearest

Answers

Answer:

d. 63%

Step-by-step explanation:

percent, will be white?

A41% b50% c59% d63%

The probability of white = P (w) = 41/65= 0.63

The  probability of yellow = P (y)= 24/65= 0.369=0.37

The probability of choosing white is 0.63 . When rounded to  nearest percent gives

0.63*100/100

=0.63*100 percent

= 63 percent

= 63%

the probability of getting   the next marble white is the same as the probability of getting a white.

Can someone help me really please

Answers

Answer:

b

Step-by-step explanation:

3/3 = 1

Answer:

C

Step-by-step explanation:

The scale on a map is 55 cm : 88 km.

If the distance between two cities is 5656 km, how far apart in cm are the two cities on the map?

Answers

Answer:

look at the picture i have sent

Answer:

The cities are 35 cm apart in map.

The scale on a map is 5 cm : 8 km.

Step-by-step explanation:

mrk me brainliest please

Voce 2x-u - 1x2-3x+3 = 2​

Answers

Answer:

u=−x2−x+1

Step-by-step explanation:

Let's solve for u.

2x−u−1x^2−3x+3=2

Step 1: Add x^2 to both sides.

−x2−u−x+3+x2=2+x2

−u−x+3=x2+2

Step 2: Add x to both sides.

−u−x+3+x=x2+2+x

−u+3=x2+x+2

Step 3: Add -3 to both sides.

−u+3+−3=x2+x+2+−3

−u=x2+x−1

Step 4: Divide both sides by -1.

−u/−1=x2+x−1

−1/u=−x2−x+1

Answer:

u=−x2−x+1

Hi, i need to calculate roots x1 and x2 using the vieta theorem, can anyone help me? I have found the answer for x1 and x2, its 1,5 and 2, all i need is a solution on how to get this answer, the equation is in the picture, will give you brainliest if you type down the correct solution for me, thanks.
I have left a similar equation that i did. The only thing why i cant do the equation, because in front of x2 there’s an number, so i don’t understand.

Answers

Answer:

Solution given:

x²-12x+11=0

Comparing above equation with ax²+bx+c

we get

a=1

b=-12

c=11

By using Vieta's theorem

X1+X2=[tex] \frac{-b}{a} [/tex]=[tex] \frac{- -12}{1} [/tex]=12

again

X1X2=[tex] \frac{c}{a} [/tex]=[tex] \frac{11}{1} [/tex]=11

x²-12x+11=0x=-b±√b²-4ac/2ax=12±√144-44/2x=12±10/2x=6±5x=11 or 1

x1.x2=11

x1+x2=12

Which phrase describes the expression 505n ?

Answers

Answer:

I believe it would be "505 times n"

Step-by-step explanation:

If tis is not what you are looking for I am sorry, but the question was vague.

How much is three times two

Answers

Answer:

the answer is 6.

Step-by-step explanation:

Answer:

6.

Step-by-step explanation:

3+3=6 = 2×3=6

you can do draw 3 circles 2 times and add it all together.

The diagram shows two right angled triangles, joined together along a common side.
Calculate the area of the triangle ACD.
you must show all your working.
(Pleaseee it’s really urgent!)

Answers

Answer:

AC² = 10.8²+14.4² = 324

AC = √324= 18

area = AC.DC÷2

area=18×24÷2

area=216

Answer:

216 centimeters squared

Step-by-step explanation:

working is above

Find the volume of the prism. round to the nearest tenth

Answers

Answer:

V = 310.5 cm³

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Geometry

Volume of a Prism Formula: V = lwh

l is lengthw is widthh is height

Step-by-step explanation:

Step 1: Define

Identify variables

l = 13.8 cm

w = 4.5 cm

h = 5 cm

Step 2: Solve for V

Substitute in variables [Volume of a Prism Formula]:                                    V = (13.8 cm)(4.5 cm)(5 cm)Multiply:                                                                                                             V = (62.1 cm²)(5 cm)Multiply:                                                                                                             V = 310.5 cm³


There are 50 pennies in a roll. If you have 150 rolls of pennies, how many pennies do you have?

Answers

Answer: 7500

Step-by-step explanation:

multiply 150 by 50

5% equals what fraction, in lowest terms?

Answers

Answer:

1/20

Step-by-step explanation:

According to G0ogle 5 percent equals 1/20 in lowest terms.

Answer:

5% equals 5/100 which is 1/20 in lowest terms.

Step-by-step explanation:

5% is basically equivalent to 5/100. 5/100 in lowest terms is 1/20 since you divide the numerator and denominator by 5.

I hope this helps, have a nice day.

plzzzzzzzz help for a brainly

Answers

Answer:

The first one is supplementary

The second one is complementary

The third one is vertical

Step-by-step explanation:

Answer:

First answer is supplementary.

second answer is complementary.

Third answer is Vertical.

Which statement describes whether the function is continuous at x = 2?
O The function is continuous at x = 2 because f(2) exists.
O The function is continuous at x = 2 because lim f(x) exists.
X-2
The function is not continuous at x = 2 because f(2) does not exist.
The function is not continuous at x = 2 because lim f(x) does not equal f(2).
X-2

Answers

Answer: (b)

Step-by-step explanation:

Given

The function is given as

[tex]f(x)=\dfrac{x^2-12x+20}{x-2}[/tex]

Solving the function

[tex]f(x)=\dfrac{x^2-2x-10x+20}{x-2}\\\\f(x)=\dfrac{(x-2)(x-10)}{(x-2)}\\\\f(x)=x-10[/tex]

for [tex]x=2[/tex]

[tex]f(2)=2-10\\f(2)=-8[/tex]

The function is continuous at [tex]x=2[/tex] because [tex]\lim_{x \to 2} f(x)[/tex] exists.

If the limit exists at a point, then the function is continuous.  

Answer:

on edge its fs not b or c

Step-by-step explanation:

An isosceles right triangle has legs of equal length. If the
hypotenuse is 10 centimeters long, find the length of each leg.

Answers

Answer:

[tex] \displaystyle 5\sqrt{2}[/tex]

Step-by-step explanation:

we have a right angle isosceles triangle

in order to figure out the length of each leg we can consider Pythagoras theorem given by

[tex] \displaystyle {a}^{2} + {b}^{2} = {c}^{2} [/tex]

remember that,

isosceles triangle has two equal legs so a=b and given that the the hypotenuse is 10

substitute:

[tex] \displaystyle {a}^{2} + {a}^{2} = {10}^{2} [/tex]

simplify addition:

[tex] \displaystyle {2a}^{2}= 100[/tex]

simplify square:

divide both sides by 2:

[tex] \displaystyle {a}^{2}= 50[/tex]

square root both sides:

[tex] \displaystyle {a}^{}= \sqrt{50}[/tex]

[tex] \displaystyle {a}^{}= 5\sqrt{2}[/tex]

hence,

the length of each leg is 52

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