**Answer:**

geothermal energy

**Explanation:**

the energy is obtained from the heat within the surface of earth

**Answer:**

heat energy

**Explanation:**

12) A horizontal force of 200 N is applied to move a 55-kg cart (initially at rest) across a 10 m level surface. What is the final speed of the cart? [hint: use work – energy principle] [3 marks]

Hi there!

We can use the following:

W = ΔKE = F · d

Find the work done on the cart:

W = 200 · 10 = 2000 J

Now, this is equal to the change in kinetic energy of the object. Its initial kinetic energy is 0 J since it starts from rest, so:

2000J = KEf - KEi

KE is given as:

[tex]KE = \frac{1}{2}mv^2[/tex]

2000J = 1/2(55)v²

4000 = 55v²

√(4000/55) = **8.53 m/s**

A 300 cm rope under a tension of 120 N is set into oscillation. The mass density of the rope is 120 g/cm. What is the frequency of the first harmonic mode (m

**Answer:**

**Explanation:**

f = [tex]\sqrt{T/(m/L)} / 2L[/tex]

T = 120 N

L = 3.00 m

(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m

(wow that's massive for a "rope")

f = [tex]\sqrt{120/12} /(2(3))[/tex])

**f = **[tex]\sqrt{10\\}[/tex]/6 = **0.527 Hz**

This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.

A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N

8 N to the left , and 4 N to the right. Find the net force. Is this balanced?

**Explanation:**

12N by first law of newton is net force after colloision

yayy here you are f, r, e, e, p, o, i, n, t, s

**Answer:**

**Explanation:**

I need help. please look at the image below and let me know I need this by 7:20 am pst.

**Answer:**

3(1.5) =** 4.5 V**

**Explanation:**

What are sound detectors?

**Answer:**

A sound detector comes in the shape of a rectangular board which comprises a microphone as well as a processing circuitry.

**Answer:**

Sound detection sensor works similarly to our Ears, having diaphragm which converts vibration into signals.

2 examples of non fossil fuels ?

**Answer:**

-> Hydropower

-> Solar power

**Explanation:**

-> Hydropower

[] The power of water! It is the use of falling or fast-running water to produce electricity for power. Impoundments or da*ms are mainly used in this type of power source.

-> Solar power

[] The power of the sun! It is the use of sunlight, or solar energy, to produce electricity for power. You have probably heard of solar panels, and this is the main way to collect it.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

**Answer:**

Wind energy and solar power

**Explanation:**

they do not use fossil fuels

An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?

**Answer:**

**Explanation:**

acceleration= change in velocity/time taken

acceleration= 93/49

=2.02

A 200-kg, 2.0-m-radius, merry-go-round in the shape of a flat, uniform, circular disk parallel to level ground is rotating at 1.2 cycles/second about an axis through its center of mass and perpendicular to the ground. A 50-kg boy jumps onto the edge of the merry-go round and lands at a fixed point. What is the angular velocity of the merry-go-round after the boy lands on it

**Answer:**

**Explanation:**

Conservation of angular momentum.

Disk I = ½MR²

Point mass I = mR² (boy)

Initial angular momentum

L₀ = Iω = ½MR²ω₀

Final angular momentum

L₁ = Iω = (½MR² + mR²)ω₁

as momentum is conserved, these are equal

(½MR² + mR²)ω₁ = ½MR²ω₀

ω₁ = ω₀(½MR²/ (½MR² + mR²))

ω₁ = ω₀(½M/ (½M + m))

ω₁ = 1.2(½(200)/ (½(200) + 50))

ω₁ = 1.2(⅔)

** ω₁ = 0.8 cycles/second or 0.8(2π) = 1.6π rad/s**

Cody hits up food king and uses a scale to weigh the mass of an apple. if the spring potential energy in the scale is .09 j and is spring is stretched 0.6 meters, calculate the spring constant

**Answer:**

**oK so here's** **what you should do is add .09 and 0.6**

**Explanation:**

HELPPP!! Thanks!

If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most correct situation?

a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas

b. Keep the gas in a fixed container at constant pressure and increase the temperature

c. Keep the gas in a fixed container at constant pressure and decrease the temperature

d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas

**Answer:c i think**

**Explanation: not sure**

A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. The total mechanical energy is 25 J. The maximum speed of the block is:

**Answer:**

**Explanation:**

easy way

when system is all kinetic energy, velocity is at a maximum

E = ½mv²

v = √(2E/m) = √(2(25)/0.5) = √100 = **10 m/s**

harder way

ω = √(k/m) = √(80/0.5) = √160 rad/s

When the system is entirely spring potential, the amplitude A is

E = ½kA²

A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m

maximum velocity is ωΑ = 0.79√160 = **10 m/s**

A wheel in the shape of a flat, heavy, uniform, solid disk is initially at rest at the top of an inclined plane of height 2.00 m when it begins to roll down the incline. If rolling and sliding friction are neglected, what is the linear velocity, in m/s, of the center-of-mass of the wheel when it reached the bottom of the incline?

**Answer:**

**Explanation:**

If friction is neglected, the wheel cannot roll and can only slide frictionlessly and will have the same velocity at the bottom of the ramp as if it had been in free fall as it has converted the same amount of potential energy.

mgh = ½mv²

v = √(2gh) = √(2(9.81)(2.00)) = 6.26418... =** 6.26 m/s**

However if we do not ignore all friction and the wheel rolls without slipping down the slope, the potential energy becomes linear and rotational kinetic energy

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½(½mR²)(v/R)²

2gh = v² + ½v²

2gh = 3v²/2

v = √(4gh/3) =√(4(9.81)(2.00)/3) = 5.11468... = **5.11 m/s**

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!pls

I think this is the solution:

1: U-1, F,-4

2: Na-6, Mo-1, O-4

3: Bi-1, O-1, C-1, I-1

4: In-9, N-1

5: N-2, H-4, S-1, C-1

6: Ge- 15, N-4

7: N-1, H-4, C-1, I-1, O-3

8: H-7, F-1

9: N-1, O-5, H-1, S-1

10: H-8

11: Nb-1, O-1, C-1, I-3

12: C-3, F-3, S-1, O-3, H-1

13: Ag-1, C-1, N-1, O-1

14: Pb-6, H-1, As-1, O-4

1: U-1, F,-4

2: Na-6, Mo-1, O-4

3: Bi-1, O-1, C-1, I-1

4: In-9, N-1

5: N-2, H-4, S-1, C-1

6: Ge- 15, N-4

7: N-1, H-4, C-1, I-1, O-3

8: H-7, F-1

9: N-1, O-5, H-1, S-1

10: H-8

11: Nb-1, O-1, C-1, I-3

12: C-3, F-3, S-1, O-3, H-1

13: Ag-1, C-1, N-1, O-1

14: Pb-6, H-1, As-1, O-4

A wagon of dog treats (combined mass 55 kg) is rolling at 2.1 m/s. A dog with mass 21 kg dives into the wagon, colliding with just enough momentum to make both stop. If the collision between the dog and the wagon lasts 0.1 s, what is the magnitude of the average force that will be exerted on the dog by the collision with the wagon

**Answer:**

**Explanation:**

An impulse results in a change of momentum

If the wagon and dog both stop, they must have had equal and opposite momentums

FΔt = mΔv

F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)

v₁ = t₀ = 0

F = m(v₀)/t₁

**F =** 55(2.1)/0.1 = **1155 N**

We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.

explain the process of convergence and divergence ! HELPPP

**Answer:**

Divergence generally means two things are moving apart while convergence implies that two forces are moving together. ... Divergence indicates that two trends move further away from each other while convergence indicates how they move closer together.

**Explanation:**

why is it so important that you take care of your nervous system?

**Answer:**

The nervous system handles the stress response, which, if overworked, can eventually lead to diseases ranging from high blood pressure to diabetes.

**Explanation:**

hope I helped

i just want an answer please

Answer: An answer on what? I’ll never ignore you!

Explanation:

**Answer:**

an answer on what?

**Explanation: Im here to help!!**

An object, initially traveling at a velocity of 73 m/s, experiences an acceleration of -9.8 m/s^2. How much time will it take it to come to rest?

7.4 s

**Explanation:**

Given:

[tex]v_0 = 73\:\text{m/s}[/tex]

[tex]v = 0[/tex]

[tex]a = -9.8\:\text{m/s}^2[/tex]

[tex]t = ?[/tex]

To solve the time it takes for the object to come to a stop, we are going to use the equation below:

[tex]v = v_0 + at \Rightarrow t = \dfrac{v - v_0}{a}[/tex]

Using the given values above, we get

[tex]t = \dfrac{0 - 73\:\text{m/s}}{-9.8\:\text{m/s}^2}[/tex]

[tex]\;\;\;\;= 7.4\:\text{s}[/tex]

If you apply a net force of 100 N to the hoverboard, and it accelerates

2m/s/s, how much mass does it have?

**Answer:**

**Explanation:**

The mass of an object given only the force acting on it and it's acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force in N

a is the acceleration in m/s²

From the question

f = 100 N

a = 2 m/s²

We have

[tex]m = \frac{100}{2} = 50 \\ [/tex]

We have the final answer as

50 kgHope this helps you

5.000 km =

3.125

mi

8.000 fl oz =

mL

**Answer:**

236.588 mL

**Explanation:**

The formula for an approximate result is to multiply the volume value by 29.574

[tex]8.000 \times 29.574 = 236.588[/tex]

Is that what you were asking for?

Use the sentence to answer the question.

Light is affected by gravity.

Which inference can be made based on this fact?

(1 point)

Light behaves differently in space than on Earth.

Light behaves differently in space than on Earth.

Gravity causes light to refract.

Gravity causes light to refract.

Light moves faster in space than on Earth.

Light moves faster in space than on Earth.

Stronger gravity causes an increase in light.

**Answer:**

Light behaves differently in space than on Earth.

**Explanation:**

Because the gravity field is greater near earth than in most of space. Not the areas near stars, black holes, pulsars, and such but in the vast emptyness between the clumpy spots.

What initial speed v is required if the blocks m1 =2.5 kg and m2=1.5 kg are to travel a distance d =7.0cm before coming to rest? Assume the coefficient of kinetic friction between m1 and the tabletop is ųk=0.21

**Answer:**

*OPTRIMUM** **PRIDE** **URGH** **URGH** **URGH** *

**Explanation:**

**AHHAAHAHAHAHA**

The diagram below shows a 5.00-kilogram block

at rest on a horizontal, frictionless table.

5.00-kg

block

Table

Which of the following is the correct name and strength of the force holding the block up?

The **name **and **strength **of the **force **holding the **block **up is **50 N upward - Normal force.**

The given parameters:

The **weight **of the block acting **downwards **due to gravity is calculated as follows;

W = mg

where;

W = 5 x 10

W = 50 N *(**downwards**)*

Since the **block **is at **rest**, an a force equal to the weight of the block must be acting upwards. This force is known as **normal reaction.**

Fₙ = 50 N *(**upwards**)*

Thus, the **name **and **strength **of the **force **holding the **block **up is **50 N upward - Normal force.**

Learn more about **Normal force** here: https://brainly.com/question/14486416

The block will remain on the table because the **normal force balances with the weight of the block**. The correct answer is **50 N upward normal force**

From the diagram shown a 5.00-kilogram block at rest on a horizontal, frictionless table. The weight of the block will act downward which will be

**Weight W = mg**

let g = 10 m/[tex]s^{2}[/tex]

W = 5 x 10

W = 50 N

The block will also produce an equal but in opposite direction of a normal force which is** equal to the weight of the block**. That is,

Normal force N = 50 N

The block will remain on the table because the normal force balances with the weight of the block.

Therefore, the correct name and strength of the force holding the block up is **50 N upward normal force**.

Learn more about stability here: https://brainly.com/question/517289

I need a short answer ?

**Answer:**

**Explanation:**

7a) t = d/v = 100/45cos14.5 = 2.29533...= **2.30 s**

7b) h = ½(9.81)(2.29533/2)² = 6.46056... = **6.45 m**

** **or

h = (45sin14.5)² / (2(9.81)) = **6.47 m**

which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.

A car travels a certain distance from A to B with a speed of 60km/hr and then returns along the same path to the starting point with a speed of 40km/hr. Find the average speed and average velocity.

a) Km/hr

b) m/s

wrong answers will be reported!

**Answer:**

**Explanation:**

Speed is total distance traveled over time taken to do so.

If AB is measured in kilometers, time (t) for the whole trip is

t = AB/60 + AB/40

t = 2AB/120 + 3AB/120

t = 5AB/120 hrs

Average speed is distance over time

s = 2AB / (5AB/120)

s = 2(120)/5

**s =** **48 km/hr**

**s = **48(1000 m/km / 3600 s/hr) = 13.333333.... **13 m/s**

Velocity is displacement over time.

As displacement is zero, velocity is zero

**v = 0 km/hr = 0 m/s**

Pretty harsh reporting answers just because they are wrong.

A mars surface exploration vehicle drops a rock off a 1.00 I'm high vertical Cliff. The sound of the rock landing at the base of the cliff is recorded by instruments on the vehicle 27.1 seconds later. Calculate the acceleration due to gravity on Mars given that the speed of sound on Mars is 320 m/s

The **acceleration **due to **gravity **on **Mars **is** 11.81 m/s²**.

The given parameters:

The **equation **of motion to determine the **acceleration **due to **gravity **on the moon is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2[/tex]

where;

Since the **time **measured is **two way time**, the new equation for the **total distance** traveled is calculated as;

[tex]v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{320 \times 27.1}{2} \\\\d = 4,336 \ m[/tex]

The **acceleration **due to **gravity **is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2\\\\4,336 = 0 \ + \ \frac{1}{2} \times g \times (27.1)^2\\\\4,336 = 367.21g\\\\g = \frac{4,336}{367.21} \\\\g = 11.8 1 \ m/s^2[/tex]

Thus, the **acceleration **due to **gravity **on **Mars **is** 11.81 m/s²**.

Learn more about **acceleration **due to **gravity **here: https://brainly.com/question/88039

During take-off a 8kg model rocket is burning fuel causing its speed to increase

at a rate of 4m/s2 despite experiencing a 90N drag.

What’s is the strength of the thrust?

(Answer unit is in N)( and the answer isn’t 212)

The **strength** of the thrust is 122 newtons.

The **motion** of the **rocket** is described by the **second Newton's law**, whose model is shown below:

[tex]\Sigma F = F - D = m\cdot a[/tex] **(1)**

Where:

[tex]F[/tex] - Thrust, in newtons[tex]D[/tex] - Drag, in newtons[tex]m[/tex] - Mass of the rocket, in kilograms[tex]a[/tex] - Net acceleration of the rocket, in meters per square secondIf we know that [tex]D = 90\,N[/tex], [tex]m = 8\,kg[/tex] and [tex]a = 4\,\frac{m}{s^{2}}[/tex], then the strength of the thrust is:

[tex]F = D + m\cdot a[/tex]

[tex]F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 122\,N[/tex]

The **strength** of the thrust is 122 newtons.

To learn more on **Newton's laws**, we kindly invite to check this verified question: https://brainly.com/question/13678295

Explain how the linear rate spring operates?

A linear spring has the same diameter along its entire length, and this uniform diameter gives it a constant spring rate.

What causes the difference in the angle of the sun on the Earth's surface throughout the year?

**Answer:**

The axis is tilted and points to the North Star no matter where Earth is in its orbit. Because of this, the distribution of the Sun's rays changes. ... It also means that the angle at which sunlight strikes different parts of Earth's surface changes through the year.

**Explanation:**

Pls sub to bdoggaming if this helped

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