Answer:
Chromatography
Explanation:
"involves solvent separation on a solid medium"
Answer:
Handpicking, winnowing, sieving, sedimentation, decantation and filtration are some of the methods of separating substances from their mixtures. Husk and stones could be separated from grains by handpicking. Husk is separated from heavier seeds of grain by winnowing.
Which molecule carries the protein code from the nucleus so translation can occur?
Answer:
messenger RNA
Explanation:
The type of RNA that contains the information for making a protein is called messenger RNA (mRNA) because it carries the information, or message, from the DNA out of the nucleus into the cytoplasm. Translation, the second step in getting from a gene to a protein, takes place in the cytoplasm
What are the Necessary conditions to form a natural lake
Answer:
What conditions are necessary for a natural lake? Lakes form in a variety of ways when a natural depresion fills with water. The lake must have a source of water that is greater than the outflow and evaporation. It must be on earth that does not allow too much water to infiltrate.
Explanation:
Answer:
Lakes form in a variety of ways when a natural depression fills with water. The lake must have a source of water that is greater than the outflow and evaporation. It must be on earth that does not allow too much water to infiltrate.
Arrange the terms in the correct order:
tissue, organism, organ, cell, system
Answer:
cell, tissue, organ, system, organism
Explanation:
Which of these events occurs first during the process of transcription?
A. RNA polymerase joins nucleotides into the RNA molecule.
B. RNA polymerase binds to the promoter.
C. Introns are removed from the RNA molecule.
D. Exons are removed from the RNA molecule.
Answer:
B. RNA polymerase binds to the promoter.
How many amino acids are there in A peptide, B peptide and C peptide in human insulin???
Answer:
Insulin is composed of an A chain of 21 amino acids and a B chain of 30 amino acids. C-peptide is a peptide composed of 31 amino acids
Explanation:
Insulin is composed of an A chain of 21 amino acids and a B chain of 30 amino acids, the chains being held together by two disulfide bonds. A third disulfide bond is present within the A chain. Human insulin differs from porcine insulin by a single amino acid and from beef insulin by three amino acids.
Explanation:
Dashed circles around either an R or K indicate sites of peptidase cleavage that result in generation of the mature insulin that is comprised by two separate peptides: the A chain with 21 and the B chain with 30 amino acids. A third C peptide with 21 amino acids served as a linker between the A and B chains.
which of the following is only a product of the electron transport chain
carbon dioxide
ATP
water
NADH
Answer:
water................
Consider a plant with the following characteristics. Round leaves (R) are dominant to pointed leaves (r). White flowers (W) are dominant to pink flowers (w). Plants heterozygous for both traits are crossed. What is the probability of obtaining a plant with pointed leaves and pink flowers
Answer:
.0625 or 6.25%
Explanation:
Find the probability for the plant to have pointed leaves. If the two parent plants are heterzygous, then the likelihood the plant has a recessive characteristic is 25%, 1/4, or .25 for our calculations.Find the probability for the plant to be pink. If the two parent plants are heterzygous, the likelihood the plant has another recessive characterisitc is again 25%, 1/4, or .25 for our calculations.Multiply them together. (1/4)*(1/4)=(1/16) or .0625, or 6.25%helppppppppppp meeeeeeee
Ask a question about your assignment Explain what are shared characteristics of transcription to translation and what are their differences. Explain what their function is in each cell and their importance to the body.
Explanation:
perform the following the rhythm patterns using the given legend use any kind of membranophones pearl shoes us
help l m a o ........
Answer:
D
Explanation:
LKM iF i AM CORRECT
What can you tell about bacteria that have been Gram stained?
A) Microscopic morphology
B) Macroscopic morphology
C) Gram reaction
D) A and C
Answer:
D) A and C
Explanation:
Gram staining is a laboratory technique used for bacterial species. It is used to differentiate between two groups of bacteria based on the components of their cell wall. Gram staining was developed by a scientist called Christian Gram in the year 1884. In the gram stain procedure, the following occurs:
- Due to the thick peptidoglycan component of their cell wall, GRAM POSITIVE bacteria retains the crystal violet due and stain VIOLET.
- On the contrary, due to the thin peptidoglycan component of their cell wall, GRAM NEGATIVE bacteria do not retain the crystal violet dye and hence stain, RED.
Based on this, a bacteria that has been gram stained has been tested for its GRAM REACTION and microscopic morphological characteristics, since it is a microbe.
Consider a cross between a plant with two flower colors, yellow and red. Yellow (Y) exhibits complete dominance over red (y). It also has either single blossoms or double blossoms, single blossoms (S) exhibit complete dominance over double blossoms (s). A dihybrid yellow, single blossomed flower is crossed with a red flowered and double blossomed plant. You observe the following phenotype frequencies among the 1545 offspring plants:
500 yellow flowers and single blossom plants
515 red flowers and double blossom plants
260 yellow flowers and double blossom plants 270 red flower and single blossom plants.
What is the recombination frequency between these two genes?
a. (260+270) 1545
b. 270/1545
c. 1545/ (260+270)
d. 260/1545
e. (500+515)/1545
f. 1545/260
g. 1545/270
From these results one can conclude that:_______.
a. the two genes are linked
b. the two genes are not linked
c. if the genes are linked, they are separated far enough apart to appear to assort independently
Answer:
1) option a is correct. (260+270)/1545
(Note about this option: In the statement, it is written as (260+270) 1545. Lacks the division symbol, / )
2) From these results one can conclude that the two genes are linked (option a)
Explanation:
To know if two genes are linked, we must observe the progeny distribution. If heterozygous individuals, whose genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, phenotypes appearing in different proportions, we can assume linked genes in the double heterozygote parent.
We might verify which are the recombinant gametes produced by the di-hybrid, and we will be able to recognize them by looking at the phenotypes with lower frequencies in the progeny. Phenotypes with the highest frequencies represent the parental gametes.
To calculate the recombination frequency, we will use the following formula: P = Recombinant number / Total of individuals.
In the present example:
Parental) YySs x yyss
Gametes) YS parental type ys, ys, ys, ys
ys parental type
Ys recombinant type
yS recombinante type
The total number of individuals in the offspring: 1545
Phenotypic class Number of offspring
500 Y-S- (parental)515 yyss (parental)260 Y-ss (recombinant)270 yyS- (recombinant)According to this information, the phenotypic frequencies of the progeny differ from the phenotypic ratio 1:1:1:1. We can assume then, that these genes are linked.
The recombination frequency is:
P = Recombinant number / Total of individuals
P = 260 + 270 / 1545
P = 530/1545
P = 0.343
The genetic distance between genes is 0.343 x 100= 34.4 MU.
Please answer the three questions. ☺️
d) Out of the 16 possible outcomes, how many have to yellow leaves?
e) Out of the 16 possible outcomes, how many have green leaves?
f)Out of the 16 possible outcomes, how many have green leaves and rough
seeds?
Answer:
12 out of 16 have yellow leaves
4 out of 16 have green leaves
1 out of 16 has green leaves and rough seeds
Explanation:
<3
The answer to the three questions is as follows:
Out of the 16 possible outcomes, 12 of them have to possess yellow leaves. Out of the 16 possible outcomes, 4 of them have to possess green leaves. Out of the 16 possible outcomes, only one has green leaves and rough seeds. What is a Dihybrid cross?A dihybrid cross may be characterized as a type of cross that significantly takes place between two individuals with two observed traits that are controlled by two distinct genes. It is a breeding experiment between two organisms that are identical hybrids for two traits.
According to the context of this question, the allele Y encodes for yellow color leaves, and y codes for green color leave. Yellow is dominant over the green. Similarly, S encodes for smooth leaves while s codes for rough seeds. Smooth is dominant over rough.
yyss is the only genotype that has a green and rough phenotype. While the possibilities that have yy in their genotypes must possess a green phenotype.
To learn more about Dihybrid cross, refer to the link:
https://brainly.com/question/12540319
#SPJ2
what comes first mieosis or mitosis
Answer:
I'm not sure there's a first exactly, but if I had to guess I'd say mitosis.
Explanation:
Meiosis produces genetically identical cells, results in diploid cells and takes place throughout an organism's lifetime; involved in asexual reproduction. Meiosis produces genetically unique cells, results in haploid cells, only happens at curtain times in an organism's life cycle; involved in sexual reproduction.
In cats, some are black, some are orange, and some are calico (fur that is both black and orange) All calico cats are always females. This trait represents two inheritance patterns. This two and explain how you know.
please help.
Calico cats are predominantly female because they’re colouring is related to the X chromosome.
Two X chromosomes are needed for a cat to have that distinctive tri-colour coat.If a cat has an XX pair, she will be female.Male cats have an XY chromosome pair, so they can’t be Calicos.Have a great day <3 (I love cats)
Answer: In cats, one of several genes controlling fur color is located on the X chromosome. The gene has two versions, or alleles. One form of the gene codes for orange fur (XB), and the other form codes for black fur (Xb). While it's difficult to say which allele is dominant and which is recessive, since only one is ever expressed (see below), let's say, for the sake of argument, that orange is dominant to black. Ordinarily, this would mean that an animal inheriting one copy of each gene (genotype XBXb) should have orange fur. Surprisingly, a female cat heterozygous at that locus (XBXb) will not be orange. Instead, her coat will be a patchwork of orange and black, a condition known as tortoiseshell. Male color expression is straightforward. Because only one allele exists for the gene in each cell, it will be expressed. And all males have only B or only b. There are no heterozygotes, because the Y does not carry the allele.
Explanation:
I got this from an article! I hope this helps.
0.3 kilogram golf ball moving at 45 meters/second equals
Answer:
F = 13.5 N
Explanation:
Structure is critically linked to function in most cell organelles.
What is the function of the organelle shown?
Answer:
all eukaryotic organelles, the nucleus is perhaps the most critical. In fact, the mere presence of a nucleus is considered one of the defining features of a eukaryotic cell. This structure is so important because it is the site at which the cell's DNA is housed and the process of interpreting it begins.
Core organelles are found in virtually all eukaryotic cells. They carry out essential functions that are necessary for the survival of cells – harvesting energy, making new proteins, getting rid of waste and so on. Core organelles include the nucleus, mitochondria, endoplasmic reticulum and several others.
hope it will help u in understanding....if u r able to understand thn only mrk it as brainliest.
ESP: actuan las hormonas solo sobre celulas o pueden actuar sobre otras estructuras?
ENG: do hormones act only on cells or can they act on other structures?
Answer:
Hormones act only on cells not structures.
Explanation:
Hormones act only on cells and they do not act on other structures because there are specific cells have receptors for that particular hormone. Some hormones bind itself to the receptors on the surface of target cells whereas other hormones enter the cells and bind itself to the receptors present in the cytoplasm or nucleus of the cell.
Side-chain hydrogen bonding :__________
a) Side chains that can form hydrogen bonds are located on the outside of a protein, where they can stabilize tertiary structure by forming hydrogen bonds with water.
b) Two cysteine residues can form hydrogen bonds.
c) Side chains connect distant parts of a polypeptide chain and introduce loops into the chain.
d) Threonine and glutamine can form hydrogen bonds.
e) Hydrogen bonds stabilize quaternary protein structure by holding together several protein strands.
Answer:
a) Side chains that can form hydrogen bonds are located on the outside of a protein, where they can stabilize tertiary structure by forming hydrogen bonds with water.
Explanation:
A hydrogen bond occurs between a hydrogen atom and four other elements. The side chain hydrogen bonds are resulted from the tertiary arrangement of structural components of the proteins.
The side chain hydrogen bond are present at the outside of the protein at places where the water forming the hydrogen bond can stabilize the tertiary structure.
Select ALL the correct answers.
A pitcher for a professional baseball team allows runs in the first nine games he starts this season. Let A be the set of the number of
runs allowed by the pitcher in his first nine starts.
A = {1, 4, 2, 2, 3, 1, 1, 2, 1}
In the tenth game he starts, he allows 9 runs. Let B represent the set of the number of runs allowed in all ten games he has started.
Select the true statements.
The median of B is 1 run more than the median of A.
The interquartile range of B is greater than the interquartile range of A.
The interquartile range of A is 1 less than the interquartile range of B.
The median of A is the same as the median of B.
Including the runs allowed in the tenth game does not cause the spread of the data to
change.
Answer:
(b) The interquartile range of B is greater than the interquartile range of A.
(d) The median of A is the same as the median of B.
Explanation:
Given
[tex]A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}[/tex]
[tex]10th\ run = 9[/tex]
So:
[tex]B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}[/tex]
Required
Select all true statements
(a) & (d) Median Comparisons
[tex]A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}[/tex] [tex]B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}[/tex]
[tex]n = 9[/tex] [tex]n = 10[/tex]
Arrange the data:
[tex]A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}[/tex] [tex]B = \{1,1,1,1,2,2,2,3,4,9\}[/tex]
[tex]Median = \frac{n + 1}{2}th[/tex]
[tex]Median = \frac{9 + 1}{2}th[/tex] [tex]Median = \frac{10 + 1}{2}th[/tex]
[tex]Median = \frac{10}{2}th[/tex] [tex]Median = \frac{11}{2}th[/tex]
[tex]Median = 5th[/tex] [tex]Median = 5.5}th[/tex] --- average of 5th and 6th
[tex]Median = 2[/tex] [tex]Median = \frac{2+2}{2} = 2[/tex]
Option (d) is correct because both have a median of: 2
(b) & (c) Interquartile Range Comparisons
[tex]A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}[/tex] [tex]B = \{1,1,1,1,2,2,2,3,4,9\}[/tex]
[tex]n = 9[/tex] [tex]n = 10[/tex]
First, calculate the lower quartile (Q1)
[tex]Q_1 = \frac{n + 1}{4}th[/tex][Odd n] [tex]Q_1 = \frac{n}{4}th[/tex] [Even n]
[tex]Q_1 = \frac{9 + 1}{4}th[/tex] [tex]Q_1 = \frac{10}{4}th[/tex]
[tex]Q_1 = \frac{10}{4}th[/tex] [tex]Q_1 = 2.5[/tex]
[tex]Q_1 = 2.5th[/tex]
This means that:
[tex]Q_1 = 2nd + 0.5(3rd - 2nd)[/tex] [tex]Q_1 = 2nd + 0.5(3rd - 2nd)[/tex]
[tex]Q_1 = 1 + 0.5(1- 1)[/tex] [tex]Q_1 = 1+ 0.5(1 - 1)[/tex]
[tex]Q_1 = 1[/tex] [tex]Q_1 = 1[/tex]
Next, calculate the upper quartile (Q3)
[tex]Q_3 = \frac{3}{4}(n + 1)th[/tex] [Odd n] [tex]Q_3 = \frac{3}{4}(n)th[/tex] [Even n]
[tex]Q_3 = \frac{3}{4}(9 + 1)th[/tex] [tex]Q_3 = \frac{30}{4}th[/tex]
[tex]Q_3 = \frac{30}{4}th[/tex] [tex]Q_3 = 7.5th[/tex]
[tex]Q_3 = 7.5th[/tex]
This means that:
[tex]Q_3 = 7th + 0.5(8th- 7th)[/tex] [tex]Q_3 = 7th + 0.5(8th- 7th)[/tex]
[tex]Q_3 = 2 + 0.5(3- 2)[/tex] [tex]Q_3 = 2+ 0.5(4 - 2)[/tex]
[tex]Q_3 = 2.5[/tex] [tex]Q_3 = 3[/tex]
The interquartile range is [tex]IQR = Q_3 - Q_1[/tex]
So, we have:
[tex]IQR = 2.5 - 1[/tex] [tex]IQR = 3 - 1[/tex]
[tex]IQR = 1.5[/tex] [tex]IQR =2[/tex]
(b) is true because B has a greater IQR than A
(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.
The upper quartile and the interquartile range of A and B are not equal
modern scientific explanations of evolution
a. have replaced darwin’s thinking
b. combine the principles of natural selection and genetic inheritance
c. rely on genetics instead of natural selection
d. fail to explain how traits are inherited
Which of the following is an example of a learned response? OA A child figures out how to ride a bicycle. O B. An adult salmon is able to return to the river where it hatched. OC. A plant turns to follow the sun during the day. OD. A man blinks when an object is tossed toward his face.
Answer:
Explanation:
I would say A. Learning to ride a bicycle is a process of getting on and falling off. You have no idea how to do it properly without practice. That's learned.
But look out for D. I'm not sure that that isn't instinctive. Somewhere along the line I think even a baby knows not to let his/her eyes be touched. Is it learned? It's close but A is a much better answer.
The salmon is instinctive. The plant doesn't learn to turn towards the sun. It does so because more food is produced.
Yes, it's A.
A is the only option that is not instinctual. Riding a bicycle is something that has to be taught (and even if you weren't taught to ride a bike, you had to figure it out by trial and error.)
The other options are instinctual and reflexive responses. The salmon returning to the river is a behavior that is pretty much hard-wired into the salmon's brain. The plant turns to follow the sun because it is a source of light and energy.
The other user expressed uncertainty as to option D, but in fact, option D is very much a reflexive, instinctual response as well. To flinch or blink when something abruptly moves towards you is not a choice or something you have to be taught — it's a reflex, something you can't control.
Complete the following statement from what you have learned about the motor unit. In some neurodegenerative diseases the lower motor neuron cell bodies die and the remaining lower motor neurons sprout processes that innervate the neuromuscular synapses vacated by the dead lower motor neurons. In these muscles, the size of the motor unit ____________ and the strength of the muscle contraction generated by individually activating each surviving motor neuron _________.
Answer:
The correct answer is - increase, increase.
Explanation:
In some neurodegenerative diseases, some lower motor neuron cells die and the remaining lower motor neurons continuing the process of the vacated dead motor neuron cells to innervate the neuron and muscle synapses.
The size of the motor unit increases and due to the innervations of the new axon
increases the strength of the muscle contraction occurred by individually activating each surviving motor neuron. Here multiple motor units will be controlled by a single neuron.
Answer for 10 points!
Answer:
I think the answer is D
Explanation:
Hope that helps!
What is cellular respiration
Answer:
cellular respiration is the process by which organisms uses oxygen (O²) and glucose (C⁶H¹²O⁶) to digest food molecules to acquire chemical energy for cells function.
Something you might call someone who is small invertebrates animals
Pretty please help!!!
what would happen if scientific knowledge was not adaptable
there where no more correct solutions, they would be wrong, since the scientific method establishes relationships between facts, where it is a useful application for man.
If you throw a rock into the air, its instantaneous speed is probably highest
A) at the top of its flight
B) halfway to the top of its flight
C) when you throw it and right before it hits the ground
D) when you throw it
E) right before it hits the ground
Answer:
B halfway to the top of it's flight
The earliest hominid fossil, “Lucy," is estimated to be 3.2 million years old. This early
human-like species shares an important characteristic with modern humans: bipedalism.
Which of the following would favor the selection of bipedal posture over walking on all
fours?
Bipedal posture allowed for greater mobility in the tree canopy.
ООО
Bipedal posture allowed arms to be free to develop and use tools.
Bipedal posture allowed for an increase in hominid brain and jaw size.
Bipedal posture allowed a greater number of offspring to be produced in
hominids.
Answer: Bipedal posture allowed arms to be free to develop and use tools.
Explanation:
Answer:
Bipedal posture allowed arms to be free to develop and use tools.
Explanation:
Bipedalism favors in the arms to be free
Hope this helps! :)
Jesse is learning about how Earth's landmasses are shaped by natural forces. Jesse's science teacher says that water is constantly changing Earth's surface. Describe two ways that water makes lasting changes to Earth's surface