Name one common base that is NOT harmful to the body when ingested AND a product, or way, in which it is used.

Answer:

2.24 g

Explanation:

First we use the PV=nRT formula to calculate the number of moles of the gas:

Then we can use the given molar mass to calculate the mass:

Answer:

The moon

Explanation:

The answer is A; Sorry i put the wrong answer by accident. I was trying to get to another question.

Give the answer below brainliest!!!

A. The moon influences the air movement

Answer: The pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092

Explanation:

According to the ideal gas equation:'

[tex]PV=nRT[/tex]

P = Pressure of the gas = ?

V= Volume of the gas  

T= Temperature of the gas = [tex]22.165^0C=(273+22.165)K=295.165K[/tex]  (0°C = 273 K)

n= moles of gas =  [tex]\frac{\text {given mass}}{\text {Molar mass}}[/tex]

R= Value of gas constant = 0.0821 Latm/K mol

[tex]P=\frac{mRT}{MV}[/tex]       as [tex]Density=\frac{mass}{Volume}[/tex]

[tex]P=\frac{dRT}{M}[/tex]    where d is density

[tex]P=\frac{1.983g/L\times 0.0821Latm/Kmol\times 295.165K}{44g/mol}=1.092atm[/tex]

Thus  pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = [tex]Mass \ of \ (NaCl+H_2O)[/tex]

                                 = [tex]51.56+164.2[/tex]

                                 = [tex]215.76 \ g[/tex]

hence,

⇒ [tex]Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100[/tex]

                           [tex]=\frac{51.56}{215.76}\times 100[/tex]

                           [tex]=23.896 \ percent[/tex]

Answer:

moles= w/mm

moles=150/30

moles=5

Answer:

D) 373 mm Hg.

Explanation:

We can solve this problem by keeping in mind Dalton's law of partial pressures, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:

The answer is option D) 373 mm Hg.

Answer:

79.1g of weak base must be combined with 56.0g of conjugate acid

Explanation:

that is 1.00 M in the weak base?

The weak base is C5H5N with a pKa of 5.17 (Ka=6.7×10-6)and a desire pH of 5.63

The equilibrium of the weak base is with the bromide salt of the conjugate acid is:

C5H5N(aq) + H2O(l) + Br- ⇄ C5H5NHBr(aq) + OH-(aq)

Where Kb = Kw / Ka = 1x10⁻¹⁴ / 6.7x10⁻⁶

Kb = 1.49x10⁻⁹ is defined as:

Kb = 1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]

Where [OH-] = 10^-(14- pH) = 10^-(14- 5.63) = 4.255x10⁻⁹M

[C5H5N] = 1.00M

Replacing:

1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]

1.49x10⁻⁹ = [C5H5NHBr] [4.255x10⁻⁹M] / [1.00M]

[C5H5NHBr] = 0.35M

In 1L the moles of C5H5NHBr are 0.35 moles

Mass C5H5NHBr: 160.0118g/mol

0.35 moles * (160.0118g / mol) =

56.0g of C5H5NHBr are necessaries

The mass of C5H5N is -79.1g/mol-:

1.00moles * (79.1g/mol) =

Answer:

decreases by 10 gram

Explanation:

Answer:

[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to  write the chemical equation for this reaction as shown below:

[tex]CoS(s)\rightleftharpoons Co^{2+}(aq)+S^{2-}(aq)[/tex]

Thus, since solids are not included in equilibrium expressions, we can set this one up as follows:

[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]

Regards!

Answer:

false

Explanation:

this is because , high temperature speeds up the the random motion of particles which leads to high dissolution

Answer:

4NH3+6NO+5N2+6H20

Explanation:

Answer:

HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER

Which best compares kinetic energy and temperature?

[tex]{\boxed{\mathcal{\red{Answer:}}}}[/tex]

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances. ✅

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.

Explanation:

got it right on edge 2021

Answer:

Saturated organic compound has only single bonds between carbon atoms. An important class of saturated compounds are the alkanes. Many saturated compounds have functional groups, e.g., alcohols.

Unsaturated organic compound have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may be added to the hydrocarbon to make it saturated (i.e. consisting all single bonds).

Answer:

33.30 grams of CaCl2 will be required

Explanation:

Given,

Volume of solution, V= 250 ml

Molarity of solution, M= 1.20 mol/L

Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111

We know,

Required mass, W= SVM/1000

Now,

W = (111 X 250 X 1.20)/1000

    = 33300/1000

    = 33.30

Therefore, 33.30 grams of Calcium Chloride will be required.

Answer:

And 500 mL of 2M NaOH solution contains 80.02g NaOH=40.0 g of NaOH .

Explanation:

So, If we mix 40.0 g of NaOH with enough distilled water to make 500 mL, we will get a 2.00 M NaOH solution.

Answer:

A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.

Answer: 0.637M

10.2M

1.36M

0.0982M

Explanation: the answer is 1.36M

The molarity of the CsOH solution is 0.636 M.

Molarity is the concentration of any substance in a place.

The reaction is

HBr + CsOH —> CsBr + H₂O

The formula of molarity

[tex]M = \dfrac{n}{V}[/tex]

[tex]\dfrac{0.25 \times 38.2 }{15} = 0.6366[/tex]

Thus, the molarity of the CsOH solution is 0.636 M.

Learn more about molarity

https://brainly.com/question/2817451

#SPJ2

Answer:

a. participate in proton transfer - His

b. acts as a nucleophile - Ser

Explanation:

Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.

Answer:

Explanation:

The Chemical Equation for each one of these compounds would be the following

Sodium Chloride: NaCl  

This compound contains 1 Sodium atom and 1 Chlorine atom

Sodium Oxide: Na₂O

This compound contains 2 Sodium atoms and 1 Oxygen atom.

Answer:

87.0%

Explanation:

Step 1: Write the balanced reaction

H₂O₂ ⇒ H₂O + 0.5 O₂

Step 2: Calculate the real yield of oxygen, in grams

We have 375 mL (0.375 L) of O₂ at 42 °C (315 K) and 1.52 atm. First, we will calculate the number of moles using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.52 atm × 0.375 L / (0.0821 atm.L/mol.K) × 315 K = 0.0220 mol

The molar mass of oxygen is 32.00 g/mol.

0.0220 mol × 32.00 g/mol = 0.704 g

Step 3: Calculate the theoretical yield of oxygen, in grams

According to the balanced equation, the mass ratio of H₂O₂ to O₂ is 34.01:16.00.

1.72 g H₂O₂ × 16.00 g O₂/34.01 g H₂O₂ = 0.809 g O₂

Step 4: Calculate the percent yield of oxygen

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 0.704 g / 0.809 g × 100% = 87.0%

Considering the reaction stoichiometry and the ideal gas law, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

The balanced reaction is:

2 H₂O₂ → 2 H₂O +  O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass, this is the amount of mass a substance contains in one mole, of H₂O₂ is 34 [tex]\frac{g}{mole}[/tex]. Then, the amount of moles of H₂O₂ that decomposes when 1.72 grams of H₂O₂ reacts is calculated as:

[tex]1.72 gramsx\frac{1 mole}{34 grams}= 0.0506 moles[/tex]

Then you can apply the following rule of three: if by stoichiometry 2 moles of H₂O₂ produce 1 moles of O₂, 0.0506 moles of H₂O₂ will produce how many moles of O₂?

[tex]amount of moles of O_{2} =\frac{0.0506 moles of H_{2} O_{2} x1 mole of O_{2} }{2 moles of H_{2} O_{2}}[/tex]

amount of moles of O₂= 0.0253 moles

On the other side, an ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, for O₂ gas you know:

Replacing:

1.52 atm× 0.375 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 315 K

Solving:

[tex]n=\frac{1.52 atmx 0.375 L}{0.082\frac{atmL}{molK}x 315 K }[/tex]

n= 0.022 moles

The percent yield is calculated as

[tex]Percent yield= \frac{real yield}{theoretical yield} x100[/tex]

In this case, for oxygen the percent yield is calculated as

[tex]Percent yield of oxygen= \frac{0.022 moles}{0.0253 moles} x100[/tex]

Percent yield of oxygen= 86.96 %

Finally, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

Learn more about:

The gravitational pull of the Sun keeps them in their orbits. The gravitational pull of the Sun and surrounding stars combined is most likely what gives the Oort cloud its spherical shape.

The Oort Cloud is a spherical layer of ice objects that is thought to be located between 2,000 and 100,000 astronomical units (AU) from our Sun, a star.

The Oort cloud, so named after the Dutch astronomer Jan Oort who first confirmed its existence, is a collection of objects with a combined mass estimated to be 10-100 times that of Earth that are less than 100 km (60 miles) across and maybe trillions in number.

To know more about Oort cloud visit:-

https://brainly.com/question/23368033

#SPJ1

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ([tex]s_{2} - s_{1}[/tex]), in joules per gram-Kelvin, by the following model:

[tex]s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-Kelvin.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures of water, in Kelvin.

If we know that [tex]m = 1\,kg[/tex], [tex]c_{w} = 4190\,\frac{J}{kg\cdot K}[/tex], [tex]T_{1} = 373.15\,K[/tex] and [tex]T_{2} = 288.15\,K[/tex], then the change in entropy for the entire process is:

[tex]s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}[/tex]

[tex]s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}[/tex]

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Answer:

Explanation:

Change in entropy,

[tex]\delta S = mCp * In[\frac{T2}{T1}][/tex]

The initial temperature,

[tex]T1 = 100^oC\\\\T1 = 100+273\\\\T1 = 373k[/tex]

Final value of temperature,

[tex]T2 = 15^oC\\\\T2 = 15+273\\\\T2 = 288k[/tex]

where,

[tex]m = 1kg\\\\Cp = 4190 J/kg.k[/tex]

Substitute into [tex]\delta S[/tex]

[tex]\delta S = mCp * In[\frac{T2}{T1}]\\\\\delta S = 1 * 4190 * In[\frac{288}{373}]\\\\\delta S = 4190 * In[0.7721]\\\\\delta S = 4190 * [-0.2586]\\\\\delta S = -1083.534 J/k[/tex]

The negative sign exists because the change in entropy will be decreasing due to cooling.

For more information on this visit

https://brainly.com/question/17756498

Answer:

Acids taste sour while bases taste bitter. An acid reacts with metals to produce bubbles of hydrogen gas while a base feels slimy to the touch. Acids turn blue litmus paper red while bases turn red litmus paper blue.

Answer:

Molarity: 0.522M

Percentage by mass: 2.36 (w/w) %

Explanation:

Formic acid, HCOOH reacts with NaOH as follows:

HCOOH + NaOH → NaCOOH + H₂O

To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:

Moles NaOH = Moles HCOOH:

0.01580L * (0.1322mol / L) =0.002089 moles HCOOH

Moles in the original solution:

0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH

Molarity of the solution:

0.005222 moles HCOOH / 0.01000L =

Mass HCOOH in 1L -Molar mass: 46.03g/mol-

0.522moles * (46.03g / mol) = 24.04g HCOOH

Mass solution:

1L = 1000mL * (1.02g / mL) = 1020g solution

Mass percent:

24.04g HCOOH / 1020g solution * 100

2.36 (w/w) %

Answer:

0.25 M

Explanation:

First we convert 85.5 grams of sucrose into moles, using its molar mass:

Then we divide the number of moles by the number of liters to calculate the molarity:

Answer:

3s and 3p

Explanation:

From the question given above, the following data were obtained:

Electronic configuration =>

1s² 2s²2p⁶ 3s²3p⁴

Location of valence electron =?

From the electronic configuration given above, we can see clearly that the atom has three (3) shells.

Valence electron(s) are located at the outer most shell of an atom.

The outer most shell of the atom above is 3s and 3p.

Therefore, 3s and 3p will contain the valence electron(s)

The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?

Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Explanation:

Given: [tex]Mass_1[/tex] = 1.04 g,      [tex]V_{1}[/tex] = 872 mL

[tex]Mass_2[/tex] = 2.08 g,                [tex]V_{2}[/tex] = ?

As molar mass of chlorine is 35.5 g/mol.

Number of moles is the mass of a substance divided by its molar mass.

Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.04 g}{35.5 g/mol}\\= 0.029 mol[/tex]

Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.

[tex]Moles = \frac{2.08 g}{35.5 g/mol}\\= 0.058 mol[/tex]

Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{872 L}{0.029 mol} = \frac{V_{2}}{0.058 mol}\\V_{2} = 1744 L[/tex]

Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Answer:

349.503 g

https://www.convertunits.com/from/moles+Copper/to/grams

here is a link, you can convert moles of copper to grams here

The answer is 5.50 moles of Cu (Copper) has 349.503 grams mass .

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10 23 atoms, molecules, or formula units of that substance.

1 mole of Cu has 63.546 grams of Cu

So 5.50 moles will have 5.50 * 63.546 grams

=349.503 grams

Therefore 5.50 moles of Cu (Copper) has 349.503 grams mass .

To know more about moles

https://brainly.in/question/148570

#SPJ2