name of scientist that divided elements into 4 catagories

Answers

Answer 1

Answer:

I believe the answer is Mendeleev


Related Questions

The diagram shows a man using a lever to move a rock.
Which change can he make to the fulcrum to decrease the force he has to apply?
A- Remove the fulcrum
B- Put the fulcrum on top of the lever.
C- move the fulcrum closer to himself
D-
move the fulcrum closer to the rock

Answers

D - Move the Fulcrum closer to the rock

What shape can be drawn though a solenoid to determine the magnitude of its magnetic field? A. triangle B. rectangle C. circle D. trapezoid​

Answers

Answer:

Rectangle

Explanation:

because when we find the magnitude of the magnetic field, we apply Ampere's circuital law to a rectangular loop

En una carga de prueba de 2 microcoulomb se sitúa en un punto en el que la intensidad del campo eléctrico es de 5 * 10 / 2 N/C cuál es la fuerza de la magnitud que actúa sobre ella?

Answers

Answer:

Fuerza, F = 0.001 Newton

Explanation:

Dados los siguientes datos;

Intensidad del campo eléctrico = 5 * 10² N/C

Carga = 2 microculombios = 2 * 10^{-6} culombios

Para encontrar la fuerza que actúa sobre la carga;

Matemáticamente, la intensidad del campo eléctrico viene dada por la fórmula;

Intensidad del campo eléctrico = fuerza/carga

F = E * Q

F = 5 * 10² * 2 * 10^{-6}

Fuerza, F = 0.001 Newton

Which of the following phase changes occurs at point B on the phase diagram shown below? (choose all that apply)
solid
liquid

gas
T
melting
sublimating
boiling
condensing

Answers

Answer:

Condensation and Melting

Explanation:

Gas to liquid = Condensation

Solid to liquid = Melting

to increase the frequency by 2 octave (s), to 4 f , by what factor would you have to increase the tension

Answers

Answer:

16

Explanation:

Since frequency in a stretched string f = (n/2L)√T/μ and n, L and μ are constant, f ∝ √T  where T = tension in string

Now f₂/f₁ = √T₂/√T₁

Since f₁ = f (frequency at tension T₁) and f₂ = 4f (since its frequency increases by 2 octaves to 4f at tension T₂).

So,

f₂/f₁ = √T₂/√T₁

4f/f = √T₂/√T₁

√T₂/√T₁ = 4

squaring both sides, we have

(√T₂/√T₁)² = 4²

T₂/T₁ = 16

T₂ = 16T₁

So, the tension would have to increase by a factor of 16

Two resistors A and B are arranged in series in one branch of a parallel arrangement. The other branch contains a single resistor, C. This parallel arrangement is in series with a single resistor D. Describe how you would find the equivalent resistance of the group.

Answers

Answer:

Explanation:

A and B are in series , Total resistance = Ra + Rb

This resistance is in parallel with single resistor C

Equivalent resistance Re = Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )]

Now this combination is in series in single resistance D .

Total resistance = Rd + Re

= Rd + { Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )] }

paano mag drawing ng bilog

Answers

Answer: how to draw a circle

Explanation:

In a series RLC ac circuit, a second resistor is connected in series with the resistor previously in the circuit. As a result of this change, what happens to the impedance of the circuit

Answers

Answer:

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

          Z = R + R₂

Explanation:

The impedance of a series circuit is

          Z₀² = R² + (X_L-X_C) ²

when we place another resistor in series the initial resistance impedance changes to

          Z² = (R + R₂) ² + (X_L - X_C) ²

           

let's analyze this expression

* The first thing we observe is that the frequency response does not change

* The current that circulates in the circuit decreases due to the new resistance at the resonance point,

          Z = R + R₂

If the earth rock takes 2.00 s to reach its highest point, how long will it take the moon rock to do so

Answers

12.0 s

Explanation:

First, let's find the initial vertical velocity of the rock on earth. We know that

vy = v0y - gt

where g = 9.8 m/s^2. When the rock reaches its highest point, vy = 0. So if it takes 2.00 s to reach the maximum height, the initial velocity of the rock is

v0y = (9.8 m/s^2)(2.00 s) = 19.6 m/s.

We know that the moon only has 1/6 of earth's gravity. Therefore, if the same rock is given the same vertical velocity as on earth, then the time it takes to reach its maximum height is

voy = gt ---> t = voy/g

t = (19.6 m/s)/(9.8/6 m/s^2)

= 12.0 s

During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshield or steering wheel. According to safety standards, the bags produce a maximum acceleration of 60g, but lasting for only 32 ms (or less). How far does a person travel in coming to a complete stop in 32 ms at a constant acceleration of 60g

Answers

Answer:

s = 0.3 m

Explanation:

In order to calculate the distance traveled by the person, we will use the second equation of motion:

[tex]s = v_it + \frac{1}{2}at^2[/tex]

where,

s = distance traveled = ?

vi = initial speed = 0 m/s

t = time = 32 ms = 0.032 s

a = acceleration = 60g = (60)(9.81 m/s²) = 588.6 m/s²

Therefore,

[tex]s = (0\ m/s)(0.032\ s)+\frac{1}{2}(588.6\ m/s^2)(0.032\ s)^2[/tex]

s = 0.3 m

A child with a mass of 20 kg slides down a slide at an angle of 40º from the horizontal. She accelerates at 1.3 m/s2. Calculate the magnitude of the frictional force on the child

Answers

Answer:

OK

The component of gravity that aids his sliding down.. is

Mgsin∆

Friction will oppose the motion

Therefore... The net force acting will be

MgSin∆ - Fr=Ma

Where Fr= Frictional Force

Fr = MgSin∆ - Ma

= 20x9.8Sin40 - 20x1.3

=125.99 - 26

=99.99N ~ 100N.

A 3.0 kg puck moving at 2.0 m/s strikes a stationary 2.0 kg puck. After the collision, the 3.0 kg puck has a velocity of 0.40 m/s. Use conservation of momentum to find the velocity of the 2.0 kg puck after the collision.

Answers

Answer:

2.4 m/s

Explanation:

Applying,

The law of conservation of momentum

Total momentum before collision = Total momentum after collision

mu+m'u' = mv+m'v'.................... Equation 1

Where m = mass of the moving puck, m' = mass of the stationary puck, u = initial velocity of the moving puck, u' = initial velocity of the stationary puck, v = final velocity of the moving puck, v' = final velocity of the stationary puck.

make v' the subject of the equation

v' = (mu+m'u'-mv)/m'................ Equation 2

From the question,

Given; m = 3 kg, m' = 2 kg, u = 2 m/s, u' = 0 m/s (stationary), v = 0.4 m/s

Substitute these values into equation 2

v' = [(3×2)+(2×0)-(3×0.4)]/2

v' = (6-1.2)/2

v' = 4.8/2

v' = 2.4 m/s

An electrical appliance draws 9.0 amperes of current when connected to a 120-volt
source of potential difference. What is the total amount of power dissipated by this
appliance?
1100 W
110 W
13 W
130 W

Answers

Answer:

The correct answer is "1080 W".

Explanation:

Given:

Current,

I = 9.0 A

Potential difference,

V = 120 volt

As we know,

⇒ [tex]Power=IV[/tex]

On substituting the values, we get

⇒             [tex]=120\times 9.0[/tex]

⇒             [tex]=1080 \ W[/tex]

In the gure below, two isotropic point sources of light (S1 and S2) are separated by distance 2.70 mm along a y-axis and emit in phase at wavelength 900 nm and at the same amplitude. A light detector is located at point P at coordinate xP on the x-axis. What is the greatest value of xP at which the detected light is minimum due to destructive interference

Answers

The figure is missing, so i have attached it.

The distance between S1 and S2 is 2.70μm

Answer:

7.88 μm

Explanation:

Let the distance in question be x.

The path difference between rays starting from S1 and S2 up to points on the x axis when x is greater than zero is given as;

(√(d² + x²)) - x = (m + ½)λ

Making x the subject of the formula, we have;

x = (d²/(2m + 1)λ) - (2m + 1)λ/4

m is an integer e.g, 0,1,2..

The greatest value of xP will be at m = 0

Thus, putting m = 0,we have;

x = (d²/λ) - (λ/4)

We are given;

d = 2.70 μm = 2700 nm

λ = 900 nm

Thus;

x = (2700²/900) - (900/4)

x = 7875 nm = 7.875 μm ≈ 7.88 μm

A current of 5 a flows in a copper wire for 20 s. how many coulombs of charge passed through the wire in this time?

Answers

Answer:

I think so too

Explanation:

:*

ANSWER PLEASE ASAP science​

Answers

1) cuscuta - parasitic

2) pitcher plant - insectivorous

3) Green plants -Autotrophs

4) Food store in - starch

plants

5) Rhizobium -Bacteria

Mass is measured using a

Answers

Answer:

Balance or Triple-Beam balance

2. A force of magnitude 44 N compresses a spring 0.69 m from equilibrium. What is the value of the spring constant?
60 N/m
64 N/m
32 N/m
49 N/m

Answers

Answer:

Spring constant = 63.77 N/m

Explanation:

Given the following data;

Force = 44 N

Extension = 0.69 m

To find the spring constant;

Force = spring constant * extension

Substituting into the formula, we have;

44 = spring constant * 0.69

Spring constant = 44/0.69

Spring constant = 63.77 N/m

PLEASE HELP I WILL MARK BRAINLYIST!!!!!!!!!
All of the matter in the universe formed after the big bang. Scientists
predicted that hydrogen and helium would be the most abundant elements.
What did scientists discover?
A. The universe has 73% hydrogen and 25% helium, which does not
support the big bang theory
B. Planets are made mostly of other elements, which does not
support the big bang theory
C. Stars are made mostly of other elements, which supports the big
bang theory
D. The universe has 74% hydrogen and 24% helium, which supports
the big bang theory.

Answers

Answer:

The answer is D. Here is proof . Plz mark brainliest

Explanation:

what are 5 examples of energy transformations?

Answers

Answer:

Fuel cells (Chemical energy → Electrical energy) Battery (electricity) (Chemical energy → Electrical energy) Fire (Chemical energy → Heat and Light)

Explanation:

g hoop rolls without slipping on a horizontal surface. The hoop has a mass m and radius r. What is the ratio of the hoop's translational kinetic energy to the hoop's rotational kinetic energy, KT /KR

Answers

Answer:

[tex]\frac{K.E_t}{K.E_r} = 1[/tex]

Explanation:

The translational kinetic energy of the hoop is given as:

[tex]K.E_t = \frac{1}{2} mv^2[/tex]      ---------------------- equation (1)

where,

[tex]K.E_t[/tex] = translational kinetic energy

m = mass of hoop

v = linear speed of hoop

The rotational kinetic energy of the hoop is given as:

[tex]K.E_r = \frac{1}{2} I\omega^2[/tex]

where,

[tex]K.E_r[/tex] = rotational kinetic energy of the hoop

I = Moment of Inertia of the hoop = mr²

r = radius of the hoop

ω = angular speed of hoop = [tex]\frac{v}{r}[/tex]

Therefore,

[tex]K.E_r = \frac{1}{2} (mr^2)(\frac{v}{r} )^2\\\\K.E_r = \frac{1}{2} mv^2[/tex]------------------- equation (2)

dividing equation (1) and equation (2), we get:

[tex]\frac{K.E_t}{K.E_r} = \frac{\frac{1}{2}mv^2 }{\frac{1}{2}mv^2 }\\\\\frac{K.E_t}{K.E_r} = 1[/tex]

A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the lens strength (a.k.a, lens power) of her eyes. What is the closest object she can see clearly

Answers

Answer:

20.0 cm

Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

1/u = P'- 1/v

1/u = 55.0 D - 1/0.02 m

1/u = 55.0 m⁻¹ - 1/0.02 m

1/u = 55.0 m⁻¹ - 50.0 m⁻¹

1/u = 5.0 m⁻¹

u = 1/5.0 m⁻¹

u = 0.2 m

u = 20 cm

So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.

A parallel beam of light of wavelength 4.5 x 10^-7 m is incident on a pair of slits that are 5.0 x 10^-4 m apart. The interference pattern is focused on a screen 2.0 m from the slits. The separation between two adjacent bright fringes is most nearly:_________

Answers

Answer:

1.8x10⁻³m

Explanation:

From the question above, the following information was used to solve the problem.

wavelength λ = 4.5x10⁻⁷m

Length L = 2.0 meters

distance d = 5 x 10₋⁴m

ΔY = λL/d

= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m

= 0.00000045 / 0.0005

= 0.0000009/0.0005

= 0.0018

= 1.8x10⁻³m

from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m

thank you!

Find the magnitude and direction of the resultant force produced by a vertically upward force of 42 N and a left horizontal force of 35N.

Answers

Answer:

Resultant = 54.67 N

Direction: 50.2° to the horizontal

Explanation:

Note: Since both forces form a right angle triangle, As shown in the diagram below,

Applying

Pythagoras theorem,

a² = b²+c²..................... Equation 1

From the question,

a = R, b = 42 N, c = 35 N

Substitute these values into equation 1

R² = 42²+35²

R² = 1764+1225

R² = 2989

R = √2989

R = 54.67 N

Direction

tanФ = a/b

Where Ф = direction of the resultant

tanФ = 42/35

tanФ = 1.2

Ф = tan⁻¹(1.2)

Ф = 50.2° to the horizontal

A 1 kg flashlight is dropped from rest and falls to the floor without air resistance . At the point during its fall, when it is 0.7 meters above the floor, its potential energy exactly equals its kinetic energy. How fast is the flashlight moving at this point, in m/s 3.7

Answers

Answer:

The speed of the flashlight at that point is 3.7 m/s

Explanation:

When an object of mass M is at a height H above the ground, the potential energy of the object is:

U = M*H*g

Where g is the gravitational acceleration, g = 9.8 m/s^2

And for an object with velocity v, the kinetic energy is:

K = (M/2)*v^2

We know that when the flashlight of mass  1kg is 0.7 meters above the ground, the potential energy is equal to the kinetic energy, then:

M = 1kg

H = 0.7m

g = 9.8 m/s^2

Replacing these in the equations, we get:

U = K

(1kg)*(0.7m)*(9.8 m/s^2) = ((1kg)/2)*v^2

As the mass factor appears in both sides, we can remove it:

(0.7 m)*(9.8 m/s^2) = (v^2)/2

Now we can multiply both sides by 2:

2*(0.7 m)*(9.8 m/s^2) = v^2

Now let's apply the square root to both sides:

√(2*(0.7 m)*(9.8 m/s^2)) = v = 3.7 m/s

Which of the following statements about asexual reproduction is NOT true? A Only one parent sex cell is needed. B The offspring are copies of the parent. C Most single-celled organisms reproduce this way. Dit results in more variation in species than does sexual reproduction

Answers

Answer:

D

Explanation:

D is false because asexual reproduction produces offspring much more similar to the parent than that produced in sexual reproduction.

Will give brainliest

Answers

Answer:

D

Explanation:

Think about like charges meaning the charge is the same.

Which only D has two charges and are the same, positive will repel against positive charge so select D.

A graduated cylinder with which of the following gradations would lead to the most precise measurements of volume?
O marked every 10 ml
O marked every mL
O marked every 5 ml

Answers

Probably a marked every 10 ml

If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen distance to be 4030 nm away what is the distance from the zero order fringe to the first order fringe

Answers

Answer:

Y = 3.39 x 10⁶ m

Explanation:

We will use Young's Double Slit formula here:

[tex]Y = \frac{\lambda L}{d}[/tex]

where,

Y = Fringe spacing = ?

λ = wavelength = [tex]\frac{speed\ of\ light}{frequency} = \frac{3\ x\ 10^8\ m/s}{375\ Hz}[/tex] = 8 x 10⁵ m

L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m

d = slit separation = 950 nm = 9.5 x 10⁻⁷ m

Therefore,

[tex]Y = \frac{(8\ x\ 10^5\ m)(4.03\ x\ 10^{-6}\ m)}{9.5\ x\ 10^{-7}\ m}[/tex]

Y = 3.39 x 10⁶ m

state Newton's first law of motion in words

Answers

Answer:

An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.

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