We must change the coefficients in front of the chemical formulae in order to balance equation. The balanced equation is as follows: 4O2 + 6H2O + 6NaCl + Al2O3 + 2NH3 = 6Na + 2AlN2 + 15CI.
How may a chemical equation with a coefficient be balanced?When a chemical equation is balanced, coefficients change. Never alter the subscript. A coefficient is a multiplier for whole numbers. to correct an equation in chemistry.
What has to change for a chemical equation to be balanced?You can only alter the coefficients in an equation when you balance it. The coefficients are shown by the numerals in front of the molecule. The lower numbers found following atoms are called subscripts. When balancing chemical equations, these cannot be altered!.
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How the abiotic factors impacted the biotic factors in Chernobyl??
URGENT!!
Answer:
The Chernobyl disaster of 1986 was a nuclear accident that had a significant impact on the environment and the living organisms in the surrounding area. The abiotic factors, including radiation and temperature changes, had a profound impact on the biotic factors, including plants and animals.
Radiation: One of the primary abiotic factors that impacted the biotic factors in Chernobyl was radiation. The explosion at the nuclear reactor released large amounts of radioactive material into the environment, which had a devastating impact on the plants and animals in the area. Many of the trees and plants in the surrounding forests died, and the animals that ate these plants were also affected. The radiation also caused genetic mutations in many of the organisms in the area.
Soil: The soil in the area was also impacted by the radiation, which caused changes in the nutrient levels and pH levels. This made it more difficult for plants to grow and survive in the area, and it also impacted the animals that depended on these plants for food.
Temperature: The temperature in the area was also impacted by the radiation, which caused changes in the weather patterns. The increased levels of radiation also caused higher temperatures in the area, which made it more difficult for plants and animals to survive.
Overall, the abiotic factors, including radiation, soil, and temperature changes, had a significant impact on the biotic factors in Chernobyl. Many of the plants and animals in the area were negatively impacted, and the ecosystem in the surrounding area was altered in ways that are still being studied today.
Fog is an example of colloid that has the phase of..........
-liquid dispersed in gas
-liquid dispersed in liquid
-liquid dispersed in solid
-solid dispersed in solid
Answer:
solid dispersed in gas
Fog is a type of colloid in which tiny droplets of liquid, such as water, are suspended in a gas, such as air. Fog can be considered a liquid-in-gas colloid since the dispersed-phase droplets are composed of liquid, and the continuous-phase is composed of gas.
Other examples of colloids include smoke (solid particles dispersed within a gas), whipped cream (gas in a liquid), mayonnaise (liquid in a liquid), gelatin (solid in a liquid), and clouds (liquid in a gas).
Fog can be categorized according to the type of gas which is the continuous phase. For instance, water-in-air fog is the most common type, while smoke of air constitutes a solid-in-air colloid. Other types of fog include oil-in-air (liquid-in-gas colloid) and dust-in-air (solid-in-gas colloid).
Colloids form when particles of the dispersed phase are typically larger than 1 nanometer, yet small enough to remain suspended in the continuous phase due to Brownian motion or other forces. The particles remain suspended due to the attraction of the particles for each other (Induced Charge Electrophoresis) and for the carrier phase molecules.
Understanding colloids is important for a variety of applications, such as drug delivery, material engineering, food science, and wastewater treatment
Fog is an example of a colloid that has the phase of "liquid dispersed in gas."
When air becomes saturated with water vapour and condenses into minute water droplets close to the Earth's surface, fog is a natural meteorological occurrence.
Fog is a foggy mist formed when little liquid water droplets are scattered across the atmosphere.
A colloidal system is produced when liquid water droplets are suspended in the gas phase (air).
Thus, because these droplets are so tiny, they can hang suspended in the air for a long time, giving fog its distinctive appearance.
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Can someone please help with this chemistry question
1 mole of sodium (Na) atoms has a mass of 22.99 g. Therefore, 15 g of sodium contains 6.67e23 atoms of sodium.
What is atom?Atom is the smallest and most basic unit of matter. It consists of a nucleus, made of protons and neutrons, surrounded by electrons in a cloud-like structure. Atoms are the building blocks of all matter and are the basis for the development of chemistry and other sciences. Atoms can form chemical bonds with other atoms, resulting in molecules and compounds. Atoms are extremely small, and it takes an electron microscope to observe them. They are also incredibly light, with an average atom weighing only one-trillionth of a gram.
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write the detailed stepwise mechanism for the reaction of pinacolone with piperonaldehyde in the presence of potassium hydroxide.
The mechanism of the reaction have been described in detail in the answer that is below.
What is the step wise mechanism?The reaction of pinacolone with piperonaldehyde in the presence of potassium hydroxide is a type of crossed aldol condensation reaction. Here is the stepwise mechanism:
Step 1: Deprotonation of piperonaldehyde
In the presence of potassium hydroxide, piperonaldehyde undergoes deprotonation to form the enolate ion of piperonaldehyde.
Step 2: Nucleophilic addition of piperonaldehyde enolate to pinacolone
The piperonaldehyde enolate acts as a nucleophile and attacks the carbonyl carbon of pinacolone, resulting in the formation of an intermediate compound.
Step 3: Proton transfer
In this step, a proton is transferred from the hydroxyl group of the intermediate compound to the adjacent carbon atom, leading to the formation of an enol intermediate.
Step 4: Tautomerization of the enol intermediate
The enol intermediate undergoes tautomerization to form a more stable keto form.
Step 5: Rearrangement and elimination
The keto form undergoes a rearrangement in which a hydrogen atom is transferred from the adjacent carbon to the carbonyl carbon, forming a β-hydroxyketone intermediate. This intermediate then undergoes elimination of a water molecule, forming a double bond and resulting in the formation of the final product.
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molten iron and carbon monoxide are produced in a blast furnace by the reaction of iron(iii) oxide and coke (pure carbon). if 25.0 grams of pure fe2o3 are used, how many atoms of iron can be produced?
Molten iron and carbon monoxide are produced in a blast furnace by the reaction of iron(III) oxide (Fe2O3) and coke (pure carbon).
If 25.0 g of Fe2O3 are used, the number of atoms of iron that can be produced is determined using the balanced equation:
Fe2O3 + 3C → 2Fe + 3CO
Using the mole ratio from the equation, we know that for every 1 mole of Fe2O3 that is used, 2 moles of iron are produced.
We can then convert the 25.0 g of Fe2O3 to moles by using the molar mass of Fe2O3 (159.69 g/mol):
25.0 g Fe2O3 × (1 mol Fe2O3/ 159.69 g Fe2O3) = 0.1566 mol Fe2O3
And using the mole ratio, we can calculate the moles of iron produced:
0.1566 mol Fe2O3 × (2 mol Fe/ 1 mol Fe2O3) = 0.3132 mol Fe
Finally, we can convert the moles of iron produced to atoms of iron by using Avogadro's number (6.022 x 1023 atoms/mol):
0.3132 mol Fe × (6.022 x 1023 atoms Fe/ 1 mol Fe) = 1.878 x 1023 atoms Fe
Therefore, if 25.0 g of pure Fe2O3 are used, 1.878 x 1023 atoms of iron can be produced.
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How many moles are in 8. 11 X 10 20 molecules of CH4?
Answer: 0.00135
Explanation:
The Avogadro's number is the number of particles (atoms, molecules, or ions) in one mole of a substance and is equal to 6.02 x 10^23. We can use this value to convert the number of molecules of CH4 into moles.
Number of molecules of CH4 = 8.11 x 10^20
Number of moles of CH4 = (8.11 x 10^20) / (6.02 x 10^23)
Number of moles of CH4 = 0.00135 moles of CH4 (rounded to five significant figures)
Therefore, there are approximately 0.00135 moles of CH4 in 8.11 x 10^20 molecules of CH4.
What is the ground-state electron configuration of O^-2 ?
The ground-state electron configuration of [tex]O^{2-}[/tex] is [He]2s²[tex]2p^{6}[/tex].[tex]2p^{6}[/tex]
What is the ground-state electron configuration?The ground state is the state in which an atom is in its lowest energy state. The ground-state electron configuration of [tex]O^{2-}[/tex] is [He]2s²[tex]2p^{6}[/tex].
Oxygen anion, also known as oxide anion, is formed when oxygen gains two electrons to attain a negative charge. The electronic configuration of oxygen before gaining the two electrons is 1s²2s²[tex]2p^{4}[/tex].
When two electrons are added to oxygen, the resulting configuration becomes 1s²2s²[tex]2p^{6}[/tex]. However, to achieve a filled valence shell, the oxide ion has two additional electrons, resulting in a configuration of [He]2s²[tex]2p^{6}[/tex].
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How many moles of oxygen will be produced if 7.48 moles of KCl are also produced?
2 KClO3 --> 2 KCl + 3 O2
Answer:If 7.48 moles of KClO3 are consumed, 11.22 moles of O2 will be produced.
Explanation:
The balanced chemical equation for the reaction is:
2 KClO3 → 2 KCl + 3 O2
According to the stoichiometry of the balanced equation, for every 2 moles of KClO3 that react, 3 moles of O2 are produced. Therefore, the mole ratio of KClO3 to O2 is 2:3.
If 2 moles of KClO3 produce 3 moles of O2, then 1 mole of KClO3 will produce 3/2 = 1.5 moles of O2.
So, to find out how many moles of O2 will be produced when 7.48 moles of KClO3 are consumed, we can set up a proportion:
2 mol KClO3 / 3 mol O2 = 7.48 mol KClO3 / x mol O2
Solving for x, we get:
x = (3 mol O2 × 7.48 mol KClO3) / 2 mol KClO3
x = 11.22 mol O2
Therefore, if 7.48 moles of KClO3 are consumed, 11.22 moles of O2 will be produced.
What happens to copper during this redox reaction? Select all that apply.
Cu2+(aq) + Fe(s) → Cu(s) + Fe2+(aq)
Copper has gained 2 electrons.
Copper experienced an increase in oxidation state.
Copper has been oxidized.
Copper has been reduced.
Answer:
Copper has gained 2 electrons
Copper has been reduced
Explanation:
The oxidation state of Cu goes from 2+ to 0, meaning it gains 2 electrons (they each have -1 charge);
This is known as reduction
Pneumonic OILRIG:
Oxidation is Loss, Reduction is Gain
Oxidation is the loss of electrons
Reduction is the gain of electrons
Cu2+ gains 2 electrons, thus it is reduced
A 100.0 g Chunk of Aluminum with an Initial Temperature of 450.0 C° is added to 100.0
mL of Ethyl Alcohol with an Initial Temperature of 80.0 C° (A) Calculate Equilibrium
Temperature of the Mixture (B) Calculate the Heat Exchange of the System
A) 150 C° B) 30000 J All answers Approx B
A) 300 C° B) 15000 J All answers Approx
D
A) 198 C° B) 22770 J All answers Approx
all silbeg
A) 110C° B) 10000 J All answers Approx
The correct answer is (D) A) 198°C B) 22770 J. Equilibrium can be achieved in reversible reactions, where the reactants can form products and vice versa.
What is Equilibrium?
Equilibrium is a state of balance or stability in a system. In thermodynamics, it refers to a state in which the temperature, pressure, and concentration of the components of a system do not change with time. At equilibrium, the forward and reverse reactions occur at equal rates, and the system does not undergo any net change.
To solve this problem, we can use the principle of conservation of energy, which states that the total energy of a closed system is conserved, meaning that energy cannot be created or destroyed, only transferred from one form to another.
We can start by using the formula for heat exchange:
Q = mcΔT
where Q is the heat exchange, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
For the aluminum chunk, we have:
Q_aluminum = (100.0 g) x (0.903 J/g°C) x (450.0°C - T_eq)
For the ethyl alcohol, we have:
Q_ethanol = (100.0 g) x (2.44 J/g°C) x (T_eq - 80.0°C)
At equilibrium, the heat exchange of the system is zero, so we can set Q_aluminum = -Q_ethanol and solve for T_eq:
(100.0 g) x (0.903 J/g°C) x (450.0°C - T_eq) = -(100.0 g) x (2.44 J/g°C) x (T_eq - 80.0°C)
Solving for T_eq, we get:
T_eq = 198.4°C (rounded to one decimal place)
This is the equilibrium temperature of the mixture.
Q_aluminum = (100.0 g) x (0.903 J/g°C) x (450.0°C - 198.4°C) = 22770 J (rounded to the nearest 10 J)
Q_ethanol = (100.0 g) x (2.44 J/g°C) x (198.4°C - 80.0°C) = 22770 J (rounded to the nearest 10 J)
So the total heat exchange of the system is:
Q_total = Q_aluminum + Q_ethanol = 2 x 22770 J = 45540 J (rounded to the nearest 10 J)
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Based on the clues in the messages between Mateo in Quito and Fernanda in Philadelphia, what type of event do you think will occur in Quito, Ecuador? Use evidence from the conversation to explain your answer.
While the circular portion of this solar eclipse is not visible in Quito, a partial solar eclipse can be seen there.
What happens after a partial solar eclipse?A partial eclipse happens when the Sun and Moon are only partly blocked from Earth's view by the Moon. Typically, a sizable portion of the planet's surface outside of an annular or complete eclipse can observe this occurrence.
However, because the umbra travels above the polar areas of the Earth and never touches the Earth's surface, some eclipses can only be seen as partial eclipses. Since it requires well over 90% coverage to observe any dimming of the Sun's brightness, partial eclipses are essentially undetectable. It wouldn't be any dimmer than civil dusk even at 99%.
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What two properties are used to identify clouds?
The two properties are used to identify clouds are atmospheric height and how they look like.
Explain about the clouds and its formations?Often, factors like a cloud's height in the skies, texture, and the kind of "weather" it produces or doesn't generate are used to classify and identify it.
Cirrus clouds have a delicate, wispy appearance that frequently resembles "hair." They are usually white in hue and contain ice crystals which occasionally give the sky unusual colors.The others are more thicker and appear more gray, altocumulus clouds typically have a more white and patchy appearance. With Nimbostratus as an exception, which is generally seen as being more "low-level" due to its falling base.The lowest, most diversely characterized clouds in the sky. These clouds can extend quite far into the troposphere vertically and are likewise made of water droplets.Thus, the two properties are used to identify clouds are atmospheric height and how they look like.
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Consider the reaction 2NH3 (g) #!!!"! N2 (g) + 3H2 (g)
at a temperature where K = 3. 0 x 10-8. In an experiment, 1. 0 x 10-3 mol NH3, 1. 0 x 10-1
mol H2, and 1. 0 mol N2 are mixed in a 5. 0 L vessel
NH₃, N₂, and H₂ are present in concentrations of 0.00144 mol/L, 6.75 x [tex]10^{-13}[/tex] mol/L, and 5.08 x [tex]10^{-2}[/tex] mol/L, correspondingly.
To determine whether the reaction will proceed in the forward or reverse direction, we can calculate the reaction quotient, Q, which is defined as the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.
Q = [N₂] [H₂]³ / [NH₂]²
Plugging in the given concentrations, we get:
Q = (1.0 mol/L)² (1.0 x [tex]10^{-1}[/tex] mol/L)³ / (1.0 x [tex]10^{-3}[/tex] mol/L)²
= 1.0 x [tex]10^{13}[/tex]
Comparing Q to the equilibrium constant K, we see that Q is much larger than K, which means that the reaction will proceed in the reverse direction to reach equilibrium. In other words, some of the N₂ and H₂ will react to form more NH₂ until Q equals K.
To determine the equilibrium concentrations of NH₃, N₂, and H₂, we can use the equilibrium constant expression:
K = [N2] [H2]³ / [NH3]²
Rearranging and solving for [NH₃], we get:
[NH₃]² = [N₂] [H₂]³ / K
[NH₃] = √([N₂] [H₂]³ / K)
Plugging in the given concentrations and K, we get:
[NH₃] = 0.00144 mol/L
Similarly, we can find the equilibrium concentrations of N₂ and H₂:
[N₂] = K [NH₃]² / [H₂]³
= (3.0 x [tex]10^{-8}[/tex]) (0.00144 mol/L)² / (1.0 x [tex]10^{-1}[/tex]mol/L)³
= 6.75 x [tex]10^{-13}[/tex] mol/L
[H₂] = K [NH₃]² / [N₂]
= (3.0 x [tex]10^{-8}[/tex]) (0.00144 mol/L)² / (6.75 x [tex]10^{-13}[/tex] mol/L)³
= 5.08 x [tex]10^{-2}[/tex] mol/L
Therefore, at equilibrium, the concentrations of NH₃, N₂, and H₂ are 0.00144 mol/L, 6.75 x [tex]10^{-13}[/tex]mol/L, and 5.08 x [tex]10^{-2}[/tex] mol/L, respectively.
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How many grams are present in 1. 75 moles of carbon dioxide, CO2?
Answer:77.00 grams CO2
Explanation:
1.75 oles/1 mole x 44 grams CO2= 77
(44 comes from the mass of 1 carbon and 2 oxygen)
Calculate the number of ml of 2. 00 m hno3 solution required to react with 216 grams of ag according to the equation
how many moles of water vapour are formed when 10 litres of butane gas, C4H10 is burned in oxygen at STP?
Answer and Explanation: 1 mole of a gas, at STP, occupies a volume of 22.4L. Hence, 10L will contain 10L / 22.4mol/L = 0.446mol of gas.
Every fraction from crude oil contains hydrocarbons with a similar number of carbon and _______ atoms. What one word completes the sentence
Every fraction from crude oil contains hydrocarbons with a similar number of carbon and hydrogen atoms.
Hydrocarbons are organic compounds that are composed of hydrogen and carbon atoms. The number of carbon atoms in a hydrocarbon molecule determines its physical and chemical properties, such as its boiling point, density, and viscosity. The hydrocarbons found in crude oil can be separated into different fractions through a process called fractional distillation, which separates them based on their boiling points.
Each fraction typically contains hydrocarbons with similar carbon chain lengths, which can range from a few carbon atoms to over 50 carbon atoms.
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E
C
A
Making Esters
1. Name the following esters and give the name of the alcohol + carboxylic reacted to make each one.
нн
но
||
Hнн
H-C-ë-o-С-С-Н
II
нн
Н
н н
H-c-c-c
11
нн
H-C - c- c-c
| | |
Hнн
=0
нн
I Т
O
Н
O-C-H
Н
B
нннн
|
|
0 — 0 — c - C - C -H
| | |
НННН
D
H-C-C-
| |
нн
F
Н
H-c-
Н
C
<=0
O
Н
H
нн
НН Н
H-c-c
Кт жи
11
H- C-C — с
11
11
- C — C — C —H
нн
H
| | |
HHH
H
H
|
- C-H
нннн
H
C-C C-C-H
=0
нннн
H-C
ннн
0 - ć - c - C-H
ннн
н н
0-c - C -н
HH
Answer:
Here are the names of the esters and the corresponding alcohols and carboxylic acids that were used to make them:
1. Ethyl acetate, made from ethanol and acetic acid
2. Methyl propanoate, made from methanol and propanoic acid
3. Butyl butyrate, made from butanol and butyric acid
4. Octyl formate, made from octanol and formic acid
5. Ethyl benzoate, made from ethanol and benzoic acid
6. Ethyl propionate, made from ethanol and propanoic acid
7. Methyl butyrate, made from methanol and butyric acid
8. Ethyl butyrate, made from ethanol and butyric acid
9. Propyl formate, made from propanol and formic acid
10. Butyl propionate, made from butanol and propanoic acid.
20. Based on the concept of periodic trends, answer the following questions for these atoms: Au, Zn,
S, Si. Be able to defend your answers.
a. Which element has the highest electronegativity?
b. Which element has the most metallic character?
C. Which element has the largest atom?
The element with lowest electronegativity, based on periodic trends, is Li. An atom's electronegativity is measured.
How would you describe recurring patterns?Atomic radius, ionisation energy, electron attraction, electronegativity, valency, and metallic nature are important periodic trends. Due to the periodic nature of the elements and their similar electrical configurations within their various groups or periods, these tendencies are present.
What contributes to recurring trends?The number of protons on the nucleus, the number of energetic levels, & the shielding effect are three variables that aid in the prediction of trends in the periodic table. In any group, the atomic radii get larger from top to bottom.
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Can someone please help with this chemistry question
The molar mass of barium phosphate to calculate the mass of barium phosphate produced is 48.26 g of Ba₃(PO₄)₂.
What is molar mass?Molar mass is a term used in chemistry to refer to the mass of a single molecule of a substance. It is calculated by multiplying the atomic mass of each element in the molecule by the number of atoms in the molecule and then adding up the results.
Balancing the equation:
Ba + 3Cu + 4PO₄ -> Ba₃(PO₄)₂ + 3Cu
Since 5.84 g of barium is given, we can use the mole ratio between barium and barium phosphate to calculate the number of moles of barium phosphate produced.
Molar mass of barium = 137.33 g/mol
Molar mass of barium phosphate = 377.3 g/mol
5.84 g of barium = 5.84 g / 137.33 g/mol = 0.0427 mol of barium
Using the mole ratio of 1 mol Ba : 3 mol Ba₃(PO₄)₂, we can calculate the amount of barium phosphate produced:
0.0427 mol of Ba * (3 mol Ba₃(PO₄)₂ / 1 mol Ba) = 0.1281 mol of Ba₃(PO₄)₂
Finally, we can use the molar mass of barium phosphate to calculate the mass of barium phosphate produced:
0.1281 mol of Ba₃(PO₄)₂ * 377.3 g/mol = 48.26 g of Ba₃(PO₄)₂.
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What type of proteins are formed by amino acids?
Polymeric proteins
Small proteins
Large proteins
Regular proteins
amino acids form polymeric proteins, which are made up of many amino acid monomers linked together by peptide bonds.
Proteins are made up of amino acids, which are linked together by peptide bonds to form long chains known as polypeptides. Polypeptide chains can fold and interact with one another to form complex three-dimensional structures known as proteins.
Proteins range in size from small proteins made up of only a few amino acids to large proteins made up of thousands of amino acids. Protein regularity varies as well, with some proteins having highly repetitive sequences and others having more irregular structures.
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BRO LITERALLY PLEASE HELP!!!!
A solution consists of 40. 00 g of CuSO4 dissolved in 200. 0 mL of water. The molar mass of Cu is 63. 55 g/mol, the molar mass of S is 32. 07 g/ml, and the molar mass of S is 16. 00 g/mol. What is the molarity of the solution?Show your work
The molarity of the solution is 1.253 M. To find the molarity of the solution, we first need to calculate the number of moles of CuSO4 in the solution.
The molar mass of CuSO4 is
63.55 + 32.07 + (4 x 16.00 ) g/mol = 159.62 g/mol.
Next, we can use the equation moles = mass / molar mass to find the number of moles of CuSO4 in the solution.
Moles of CuSO4 = 40.00 g / 159.62 g/mol = 0.2506 mol
Finally, we can use the equation molarity = moles / volume to find the molarity of the solution.
The volume of the solution is 200.0 mL, or 0.2000 L.
Molarity = 0.2506 mol / 0.2000 L = 1.253 M
Therefore, the molarity of the solution is 1.253 M.
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Even though cities may be located at approfimately the same latitude, why might the
climate in each city be different? Mark all the answers that apply
A. Some cities may be located at different altitude
B. The type of people who live there
C. Warm ocean currents bring warmer temperatures to coastal cities
D. Mountain ranges create the rain shadow effect
Answer:
A. Some cities may be located at different altitude
C. Warm ocean currents bring warmer temperatures to coastal cities
D. Mountain ranges create the rain shadow effect
Explanation:
The climate in cities can differ due to several factors, including altitude, proximity to oceans or mountains, prevailing winds, and other geographical features. Thus, options A, C, and D are all correct. The type of people who live in a city, as stated in option B, is not a significant factor in determining climate.
504 grams C6H12= ____ moles C6H12
The formula for 504 grammes of C6H12 is 5.988630157885872 moles of C6H12, and the given molecule is C6H12 C 6 H 12. Twelve hydrogen atoms and six carbon atoms this molecule. The solution is therefore 84g/mol.
How does g become mol?To precisely determine its molarity, n, of a material with such a mass m, m (in grammes), use the grammes into moles formula. M represents the substance's molar mass, and n = m / M.
What is 1 metre in moles?The amount of moles per litre, denoted by the unit sign mol/L and mol/dm3 in SI units, is the most often used unit denoting molarity in chemistry. One mol/L of a solution's concentration is referred to as one molar, or 1 M.
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g if 39.99g naoh in 1 l of water is a 1 m solution what would the molarity be if 39.99g naoh was dissolved in 0.2 l water
The molarity of NaOH when 39.99 g NaOH was dissolved in 0.2 L of water is 5 M.
Molarity is a measure of the concentration of a solute in a solution, defined as the number of moles of the solute per liter of the solution. A mole is the amount of a substance that contains the same number of entities as there are atoms in 12 grams of carbon-12.
For example, if you dissolve one mole of a solute in one liter of a solution, you have a one-molar solution (1 M).
The formula for molarity is, Molarity (M) = Moles of solute / Volume of solution (in liters)
The number of moles of NaOH in 1 L of water is calculated as follows:
Weight of NaOH = 39.99 g
The molar mass of NaOH = 39.99 g/mol (As said that 39.99 g of NaOH makes 1 molar solution)
The number of moles of NaOH = weight / molar mass = 39.99/39.99 = 1 mol
Molarity = the number of moles/volume of solution in liters
Molarity = 1mol / 1 L = 1 M
If 39.99 g of NaOH is dissolved in 0.2 L of water, we can calculate the molarity as follows:
Weight of NaOH = 39.99 g
The molar mass of NaOH = 39.99 g/mol
The number of moles of NaOH = weight / molar mass = 39.99/39.99 = 1.0 mol
Molarity = the number of moles/volume of solution in liters
Molarity = 1 mol / 0.2 L = 5 M
Therefore, the molarity of NaOH is 5 M.
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o earn full credit for your answers, you must show the appropriate formula, the correct substitutions , and your answer including the correct units.
This year Bikini Bottom has a starfish population of 1012. There are 182 starfish born and 166 starfish deaths this year. Then 141 starfish leave and move from Bikini Bottom to Jellyfish Fields. There was also a natural disaster in Lava Flow Bend and caused 203 starfish to relocate to Bikini Bottom. Calculate the percent population growth rate for the starfish in Bikini Bottom.
Answer:
clarify
Explanation:
A beam of light distinguishes a colloid from a solution. The particles in a colloid will scatter light, making the beam..........
-visible
-invisible
-no change
-unseeable
[tex] \mathbb{ANSWER:}[/tex]
A beam of light distinguishes a colloid from a solution. The particles in a colloid will scatter light, making the beam visible.
Also, the scattering of light in a colloid is called a Tyndall Effect.This is one way to identify if a mixture is a colloid or not.Calculate the oxidation number of the elements
LiAlH4
K2CO3
KMnO4
K2SO4
LiAlH₄ contains H with an oxidation number of -1, K₂CO₃ and KMnO₄ contain O with oxidation numbers of -2 and -2, respectively, while Li contains +1, Al contains +3, K contains +1, C contains +4, S contains +6, and Mn contains +7 and K₂SO₄ also has O with oxidation number of -2
The oxidation number of an element is a measure of the number of electrons that an atom has gained or lost when it forms a chemical bond. To calculate the oxidation number of the elements in the following compounds, we follow the following rules:
The oxidation number of an element in its elemental state is always zero.
The sum of oxidation numbers of all atoms in a compound is equal to the charge on the compound.
The oxidation number of hydrogen is usually +1, except when it is combined with a metal, in which case it is -1.
The oxidation number of oxygen is usually -2, except when it is combined with a peroxide, in which case it is -1, or with fluorine, in which case it is +2.
Using these rules, we can calculate the oxidation numbers of the elements in the following compounds:
LiAlH₄:
The oxidation number of Li is +1.
The oxidation number of Al is +3.
The oxidation number of H is -1.
Therefore, the oxidation number of H in LiAlH₄ is -1.
K₂CO₃:
The oxidation number of K is +1.
The oxidation number of C is +4.
The oxidation number of O is -2.
Therefore, the oxidation number of O in K₂CO₃is -2.
KMnO₄ :
The oxidation number of K is +1.
The oxidation number of Mn is +7.
The oxidation number of O is -2.
Therefore, the oxidation number of O in KMnO₄ is -2.
K₂SO₄:
The oxidation number of K is +1.
The oxidation number of S is +6.
The oxidation number of O is -2.
Therefore, the oxidation number of O in K₂SO₄ is -2.
In summary, LiAlH₄ has H with oxidation number of -1, K₂CO₃ and KMnO₄ have O with oxidation number of -2, and K₂SO₄also has O with oxidation number of -2, while Li has +1, Al has +3, K has +1, C has +4, S has +6, and Mn has +7.
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If you had 9. 65 x 1026 atoms of Ag, how many moles would you have?
If you had [tex]9.65 * 10^{26[/tex] atoms of Ag, you would have [tex]1.603 * 10^3[/tex] moles of Ag.
To find the number of moles of Ag atoms you have, you need to use Avogadro's number, which is 6.022 x 10^23. This number represents the number of atoms in one mole of any substance.
To find the number of moles, you need to divide the number of atoms you have by Avogadro's number:
Number of moles = Number of atoms / Avogadro's number
Plug in the given values:
Number of moles = 9.65 x 10^26 atoms / 6.022 x 10^23 atoms/mole
Simplify:
Number of moles = 1.603 x 10^3 moles
So, if you had 9.65 x 10^26 atoms of Ag, you would have 1.603 x 10^3 moles of Ag.
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According to the following equation, calculate the percent yield if 550.0g of toluene is added to an excess of nitric acid and provides 305g of the p-nitrotoluene product in the lad experiment.
C7H8+HNO3-->C7H7NO2+H2O
The percent yield of the reaction is 37.2%. The theoretical yield, or maximum amount of product that can be produced based on the amount of limiting reagent utilized in the reaction, must first be ascertained in order to calculate the percent yield.
What use does the percent yield serve?In chemistry, the percentage yield is used to compare the actual outcome of a reaction to the maximum outcome anticipated.
Why is yield rate crucial?Several institutions place a high value on yield because past yield data enables them to forecast the number of students they will need to accept to order to reach their enrollment goal. Fewer pupils may be admitted if the school's yield rates historically have been high.
We can use stoichiometry to calculate the theoretical yield of p-nitro-toluene:
1 mole of toluene produces 1 mole of p-nitro-toluene
The molar mass of toluene is 92.14 g/mol, and the molar mass of p-nitro-toluene is 137.14 g/mol.
550.0 g of toluene is equivalent to 5.97 moles (550.0 g / 92.14 g/mol).
Therefore, the theoretical yield of p-nitro-toluene is:
5.97 moles of p-nitro-toluene = 5.97 moles of toluene
5.97 moles of p-nitro-toluene x 137.14 g/mol = 819.9 g
we can calculate the percent yield:
Percent yield = (actual yield / theoretical yield) x 100%
In the given experiment, the actual yield of p-nitro-toluene is 305 g.
Percent yield = (305 g / 819.9 g) x 100% = 37.2%
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