M(x)=x^2-3x
N(x)=x-5

MN(-1)= ?

A.18
B.-20
C.-22
D. -24

Answer:

7

Step-by-step explanation:

28x7=196

196=14^2 aka a perfect square

Answer:

w²-24w+144

y²+6y+9

x²+20x+100

Step-by-step explanation:

Answer:

x = 17

Explanation:

Notice that all three of the angles combined create a straight angle. This means that the sum of all three angles is equal to 180 degrees.

Create your equation (7x - 2) + (2x + 4) + (25) = 180

Combine like terms 9x + 27 = 180

Subtract the constant from each side 9x = 153

Divide each side by the coefficient x = 17

You can check your work or find each individual angle by substituting 17 in for x.

Answer:

what ever y equals plug it back into the problem and if get 0=0 then u got

Step-by-step explanation:

it

0.13 cents

So basically u need to do 3.25÷25.

Answer:

either a or x, the value is still 30

Step-by-step explanation:

given:

x = a is 30

find:

a = ?

since x = a = 30

a = 30 = x

therefore,

either a or x, the value is still 30

Answer:

1/36

Step-by-step explanation:

To get a sum of 2, both dice must roll a 1.

The probability of a 1 on the first die is 1/6.

The probability of a 1 on the second die is 1/6.

Therefore, the probability of rolling both 1s is:

P = 1/6 × 1/6 = 1/36

24 = 2x + 4

2x = 20

x = 10

.......................

Answer: perpendicular

Step-by-step explanation:

Hope this helps! If I’m right please give me Brainly-eat!! :)

Answer:

60 is correct answer by method of hcf

Answer:

The greatest common factor of 45 and 60 is 15

Step-by-step explanation:

If a set contains ‘n’ elements, then the number of proper subsets of the set is 2^n - 1.

In this problem,

n = 4

2^4 - 1 = 16 - 1 = 15 proper subsets

Answer:

0

Step-by-step explanation:

4x+ 2( 3 – 3x) = 6

4x+6-6x=6

6-2x=6

6-6=2x

0/2=x

x=0

Answer:

[tex]x=0[/tex]

Step-by-step explanation:

[tex]4x+2\left(3-3x\right)=6[/tex]

Expand:

[tex]4x+2\times3-2\times3x=6[/tex]

[tex]4x+6-6x=6[/tex]

[tex]-2x+6=6[/tex]

Subtract 6 from both sides:

[tex]-2x+6-6=6-6[/tex]

[tex]-2x=0[/tex]

Divide both sides by -2:

[tex]\frac{-2x}{-2}=\frac{0}{-2}[/tex]

[tex]x=0[/tex]

Answer: 14

Step-by-step explanation: 14 because QU is 24, RU is 19, so SU has to be 14. 24-5=19 19-5=14

Answer:

14

Step-by-step explanation:

QR = 5   RS = 5   and   ST = 5

If all of these distances are equal to 5 then all you need to do is subtract the distance of RU, which is 19, from ST, which is 5, and that'll be your answer.

Answer:

17x

Step-by-step explanation:

Step-by-step explanation:

I guess I was help full for u

Answer:

150,000

Step-by-step explanation:

15x10000=150,000

Answer:

$150,000 - Make sure to read my explanation

Step-by-step explanation:

You didn't include the question, but I'm just gonna guess that you what to know how much money she will have deposited by the time she retires. This is just a simple multiplication problem if so.

15 * 10,000 = $150,000

In conclusion she will have saved 150,000 by the time she retires. Sorry If I guessed the question wrong.

Answer:

Step-by-step explanation:

From the figure attached,

A helicopter is flying at a height 'h' and angle of elevations from two islands C and B are 35° and 15° respectively.

Let the measure of BD = x miles

From ΔABD,

tan(15) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{h}{x}[/tex]

h = x.tan(15) ---------(1)

From ΔACD,

tan(35) = [tex]\frac{h}{12-x}[/tex]

h = (12 - x).tan(35) ------(2)

By equating the values of h from equations (1) and (2),

x.tan(15) = (12 - x).tan(35)

[tex]\frac{x}{12-x}=\frac{\text{tan}35}{\text{tan}15}[/tex]

[tex]\frac{x}{12-x}=2.613[/tex]

x = 2.613(12 - x)

x + 2.613x = 31.386

3.613x = 31.386

x = 9.914 ≈ 9.9 miles

From equation (1),

h = x.tan(15)

  = 9.9[tan(15)]

  = 2.65 ≈ 2.7 miles

Therefore, helicopter is flying at the vertical height = 2.7 miles and horizontal distance of the helicopter from the island B = 9.9 miles.

Answer:

2.7

Step-by-step explanation:

I took the quiz and got it right :)

Answer:The "+7" indicates that there will be a y-intercept at 7. Therefore, you can plot a point at (0,7).

Answer:

No te puedo ayudar vbbnn

Step-by-step explanation:

[tex]\bf L.H.S = \tt \dfrac{sec\: \theta + tan \: \theta - 1}{tan \: \theta - sec \: \theta + 1} \\ \\ [/tex]

[tex]: \implies \tt \dfrac{\frac{1}{cos \: \theta} + \frac{sin \: \theta}{cos \: \theta} - 1}{ \frac{sin \: \theta}{cos \: \theta} - \frac{1}{cos \: \theta} + 1 } \: = \dfrac{1 + sin \: \theta - cos \: \theta}{sin \: \theta + cos \: \theta} \\ \\ [/tex]

[tex]: \implies \tt\dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta + (cos \: \theta - 1)} \: \times \: \dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta - (cos \: \theta - 1)} \\ \\ [/tex]

[tex]: \implies \tt\dfrac{ sin^{2} \: \theta + cos^{2} \: \theta + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: (cos \: \theta - 1)}{sin^{2} \: \theta - (cos \: \theta - 1)^{2} } \\ \\ [/tex]

[tex]: \implies \tt\dfrac{1 + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - 1 + 2 \: cos \: \theta } \\ \\ [/tex]

[tex]: \implies \tt\dfrac{2 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - sin^{2} \: \theta - cos^{2} \: \theta + 2 \: cos \: \theta } \\ \\ [/tex]

[tex]: \implies \tt\dfrac{2 (1 - \: cos \: \theta )- 2 \: sin \: \theta (1 - \: cos \: \theta)}{ 2 \: cos \: \theta - 2 \: cos^{2} \: \theta} \\ \\[/tex]

[tex]: \implies \tt\dfrac{(2 + 2 \: sin \: \theta) \: \cancel{(1 - cos\: \theta)}}{2 \: cos \: \theta \: \cancel{(1 - cos \: \theta)}} \: = \: \dfrac{1 + sin \: \theta}{cos \: \theta} \\ \\[/tex]

[tex]: \implies\tt\dfrac{1 + sin \: \theta}{cos \: \theta} \: \times \: \dfrac{1 - sin \: \theta}{1 - sin \: \theta} \\ \\ [/tex]

[tex]: \implies\tt\dfrac{1 + sin^{2} \: \theta}{cos \: (1 - sin \: \theta)} \\ \\ [/tex]

[tex]: \implies\tt\dfrac{cos^{2} \: \theta}{cos \: \theta (1 - sin \: \theta)} \\ \\ [/tex]

[tex]: \implies\tt\dfrac{cos \: \theta}{1 - sin \: \theta} \: = \: \bf{ R.H.S}\\ \\ [/tex]

[tex]\huge\bigstar \:\underline{\red{\sf Hence, Proved}} \: \bigstar \\ [/tex]

Answer:

12/312

Step-by-step explanation:

I did this quiz.

Answer:

=18w2+12x2−36

Step-by-step explanation:

I hope this helps you

Answer:

18w^2+12x^2−36

Step-by-step explanation:

Answer:

The statement that describes a situation that can be modeled as a growth or decay over equal interval is;

C. A species of fly doubles its population every month during the summer

Step-by-step explanation:

We have for exponential growth or decay, the following equation;

Exponential growth or decay;

[tex]y = a \cdot b^t[/tex]

Where;

a = The initial amount of the item

1 + r =  The rate of growth in percentage

b = The growth or decay factor

t = The time

For exponential decay, we have;

0 < b < 1

b = 1 - r

[tex]y = a \cdot(1 - r)^t[/tex]

For exponential growth, we have;

b > 1

b = 1 + r

[tex]y = a \cdot(1 + r)^t[/tex]

Therefore, given that the number of the fly population doubles every month, we have the growth rate, r as 100%, which is written as 100/100 = 1, to give;

[tex]y = a \cdot(1 + 1)^t = a \cdot(2)^t[/tex]

Which is expressed as an exponential growth by an equal factor of, r, over equal intervals of, t, time.

Answer:

B. g(x) = -2/5[x]

...............

Answer:

yes

Step-by-step explanation:

you do that when you have a minus sign and a negative an example is like if you have 4-(-10)=? if you look at the part where its -(- it looks like a positive + so you add them so this is equal to 14, and when you are multiplying 2 negatives they both equal a positive an example is like -4 times -5 this equals 20, but if you have -5+-3=? this equals -8 because you are adding the numbers.

Hope this helps =)

Steps to solve:

(4 + 5 + 3) + 8

~Add everything in parenthesis

12 + 8

~Add

20

Best of Luck!

[tex] \huge \purple {\tt {(4 + 5 + 3) + 8 =? }} [/tex]

By using parenthesis, we get

[tex] \huge \purple {\tt {12 + 8 = 20}} [/tex]

[tex] \huge \purple {\tt {20}} [/tex]

Answer:

7.7 x 10 ^-0.1

Step-by-step explanation:

you move the decimal till it is behind the the first number. making it a whole number.

hope this helps

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

[tex]1 \: cow = 4200 \: {m}^{2} [/tex]

Then, for 4500 cows:

[tex]4500 \: cows = 4200 \: {m}^{2} \times 4500[/tex]

[tex]4500 \: cows = 18900000 \: m {}^{2} [/tex]

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

[tex]1 \: hectare = 10000 \: {m}^{2} [/tex]

[tex]x \: hectare = 18900000 \: {m}^{2} [/tex]

Then, putting them in proportion, We will get:

[tex]x = \dfrac{18900000}{10000} hectares[/tex]

[tex]x = \boxed{ 1890 \: hectares}[/tex]

So, the total area in hectares = 1890 hectares.

And we are done !!

#CarryOnLearning

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Answer:

At 15 weeks they will both weigh 180

Step-by-step explanation:

150 + 2w = 195 - w

2w + w = 195 - 150

3w = 45

w = 45/3

w = 15 <=== they will weigh the same at 15 weeks

150 + 2(15) = 150 + 30 = 180...and they will both weigh 180 lbs

I hope this helps you :)