Ms. Parker determined that the mean test score in her first-period class
was 81 with a standard deviation of 7.06. The mean test score in her
second-period class was 88 with a standard deviation of 8.24. Which
conclusion can be made about her students' test scores?
A Period 2 had scores that were less spread out around the mean than
Period 1.
B. Period 1 had scores that were less spread out around the mean than
Period 2.
C. Period 2 had scores that were less spread out around the median than
Period 1.
D
Period 1 had scores that were less spread out around the median than
Period 2.

Answers

Answer 1

Answer:

B. Period 1 had scores that were less spread out around the mean than

Period 2

Step-by-step explanation:

Because the standard deviation of Period 2's scores is greater than that of Period 1's, the test scores for Period 2 are going to be more spread out than Period 1's test scores. B is the most logical choice in this case.


Related Questions

I need some help!! I will try to give brainliest!!!

Answers

Answer:

x = 35

y = 95

Step-by-step explanation:

(For y) The measure of a line is 180 degress. 180 - 95 - 50 = 35.

(For x) The measure of a triangle is 180 degress. 180 - 50 - 35 = 95.

Answer:

x = 85, y = 45

Step-by-step explanation:

solving for x:

180 - 95 = 85

solving for y:

85 + 50 = 135

180 - 135 = 45

Good luck on your schoolwork

Which expression has a value greater than 43 ?

PLEASEEE HELP!

Answers

Answer:

7^2

Step-by-step explanation:

7*7=49

4^3=43

49>43

9 mi
12 mi
What is the length of the hypotenuse?
miles

Answers

15..........................
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