mr.twain asked the students in his class to sea the figure below using a scaled factor of 3. then, he asked students to tell him one of the new side lengths of the figure. Some students responses are below
select all that answers mr.twain’s question correctly.

Answer:

128

Step-by-step explanation:

16 x 8 = 128

Answer:

128

Step-by-step explanation:

you multiply 16 and 8 because each team has 16 and there are 8 teams so, 16×8=128

Answer:

3

Step-by-step explanation:

24 + 12 = ___(8+4)

36 = ___(12)

36/12 = 3

Answer:

c

Step-by-step explanation:

c)11 miles

the day and the miles on that day add together to make the miles for the next day so 4+7=11

Answer:

Sample B: A random sample of 5 gallons of water from five different locations in the river

Step-by-step explanation:

Answer:

Question 13 is 27/2 (decimal form, 13.5, Mixed fraction 13 1/2)

Question 14 = 4

Step-by-step explanation:

hope this helped you:)

Answer:

about 28

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

Answer:

20/45

6/45

Step-by-step explanation:

A bag contains 1 green, 4 red, and 5 yellow balls. Two balls are selected at random. Find P( 1 red and 1 yellow) and P(2 red).

--------------------

# of red/yellow pairs: 4*5 = 20

# of random pairs: 10C2 = 45

P(1red & 1yellow) = 20/45

# of red pairs: 4C2 = 6

# of random pairs = 45

P(2 red) = 6/45

Answer:

A. Y= 40w+100

B.  $500

C. That would make her $400 per week plus the 100 dollars from her grandparents

Step-by-step explanation:

Answer:

so least to greatest? 1/4 1/3 1/2

Answer:

1/4, 1/3, 1/2

Step-by-step explanation:

Answer:

168.75

Step-by-step explanation:

......

Answer:

168.75

Step-by-step explanation:

Answer:

170t+D=8500

D=170t−6460

Step-by-step explanation:

Mathematical models are used to explain real life situations.

We can see from the question that the total debt is $8500  while there is  interest rate of 0% for 24 months. We are also told that after 12 months, the remaining debt was $6460.

Now, the equations that correctly model the situation are;

Learn more about mathematical models:https://brainly.com/question/731147

Answer:

(-6, -3) (-3,-3) (-3,-6)

Step-by-step explanation:

Multiple all of the vertices by 1.5.

(-6, -3) (-3,-3) (-3,-6)

Hope I helped!

[enlargment will still be a triangle]

Answer: 53.0

Step-by-step explanation:

Then the diameter equals 53.0122774

The diameter of the sphere is 53.01 inch

What is a Sphere?

A sphere is symmetrical, round in shape. It is a three dimensional solid, that has all its surface points at equal distances from the center. It has surface area and volume based on its radius. It does not have any faces, corners or edges.

The Surface Area of a Sphere = 4πr²

The Volume of a Sphere = ( 4/3 ) πr³

where r is the radius of the sphere

Given data ,

Let the diameter of the sphere be = d

The radius of the sphere be = r

The volume of the sphere is V = 78006 inch³

The Volume of a Sphere = ( 4/3 ) πr³

Substituting the values in the equation ,we get

( 4/3 ) πr³ = 78006 inch³

Now , Multiply by ( 3 / 4 ) on both sides , we get

πr³ = ( 78006 x 3 ) / 4

     = 58504.5 inch³

Divide by π on both sides , we get

r³ = 58504.5 / π

   = 18622.56 inch³

Taking cube roots on both sides , we get

r = 26.506 inch

So , the radius of the sphere is r = 26.506 inch

Now , the diameter of the sphere is d = 2 x r

                                                               = 2 x 26.506

                                                               = 53.01 inch

Hence , The diameter of the sphere is 53.01 inch

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Answer:

B

Step-by-step explanation:

We know that when x=0 y=5

B and D are the only ones that meet this criteria

we know that when x=2 y= 13 or so

D no longer works

it has to be B

Answer:

109.3

Step-by-step explanation:

The area of the figure in square centimeters is 89.6 cm².

Area is the entire amount of space occupied by a flat (2-D) surface or an object's shape. The area of a plane figure is the area that its perimeter encloses. The quantity of unit squares that cover a closed figure's surface is its area.

Given:

We have the figure consist of rectangle and 2 quadrants.

Then to calculate area of figure

= Area of 2 quadrant  +  area of rectangle

So,  Area of 2 quadrant = 2 x πr²/4 = πr²/2

                                        = 3.14 x 5² /2

                                        = 19.625 cm²

and, area of rectangle= l x w= 7 x 10 = 70 cm²

Thus, area of figure

= Area of 2 quadrant  +  area of rectangle

= 19.625 + 70

= 89.625 cm²

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Answer:

x=13 y=25

Step-by-step explanation:

Answer:

Step-by-step explanation:

ΔABC has AB = 2BC, hypotenuse is twice the leg

ΔBCD is isosceles right triangle

ΔMPN is isosceles right triangle (∠M = 45°)

ΔMKP is isosceles right triangle (∠M = 45°)

its c because i already did that and got it right

Answers:

Here you go, hope this helps

Step-by-step explanation:

6+2x

Answer: electricity can be used to create magnetism

Step-by-step explanation:

Answer: 8(2x+5y)

Step-by-step explanation:

16x+40y

=8(2x+5y)

Answer:

hut the F اا u ااck up (shut up)

shut the F اا u ااck up (shut up, yeah)

shut the F اا u ااck up (go)

shut the F اا u ااck up (go)

shut the F اا u ااck up (go)

shut the F اا u ااck up (shut up)

shut the F اا u ااck up (shut up)

shut the F اا u ااck up (shut up)

shut the F اا u ااck up (shut up)

shut the F اا u ااck up (hu, huh, yeah)

shut the F اا u ااck up (go)

shut the F اا u ااck up (go)

shut the F اا u ااck up (go)

shut the F اا u ااck up (shut up)

shut the F اا u ااck up (shut up)

shut the F اا u ااck up (shut up)

huh (daytrip took it to 10, hey)

Step-by-step explanation:

Answer:

[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (1,-2)[/tex] --- Point

[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]

The arc length of a function on interval [a,b]:  [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]

By comparison:

[tex]f'(x)^2 = 144x^{-6}[/tex]

[tex]f'(x)^2 = \frac{144}{x^6}[/tex]

Take square root of both sides

[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]

[tex]f'(x) = \±\frac{12}{x^3}[/tex]

Split:

[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]

To solve fo f(x), we make use of:

[tex]f(x) = \int {f'(x) } \, dx[/tex]

For: [tex]f'(x) = \frac{12}{x^3}[/tex]

[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = \frac{12}{2x^2} + c[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = \frac{6}{1^2} + c[/tex]

[tex]-2 = \frac{6}{1} + c[/tex]

[tex]-2 = 6 + c[/tex]

Make c the subject

[tex]c = -2-6[/tex]

[tex]c = -8[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = \frac{6}{x^2} -8[/tex]

For: [tex]f'(x) = -\frac{12}{x^3}[/tex]

[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = -\frac{12}{2x^2} + c[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = -\frac{6}{1^2} + c[/tex]

[tex]-2 = -\frac{6}{1} + c[/tex]

[tex]-2 = -6 + c[/tex]

Make c the subject

[tex]c = -2+6[/tex]

[tex]c = 4[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = -\frac{6}{x^2} + 4[/tex]

You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

If the function is differentiable in the given interval, then we have:

[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]

where s denotes the length of the arc of the given function from x = a to x = b

Using the above formula, as we're already given the arc length, thus,

[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]

This gives us

[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]

Integrating both sides with respect to x, we get:

[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]

where c is constant of integration.

Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:

[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]

c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]

c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]

The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

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Answer:

Step-by-step explanation:

It is J I’m pretty sure

Answer:

128°

Step-by-step explanation:

180-52=128