Mrs. Burke's physics class has 122 students, classified by academic year and major, as illustrated in the table. Mrs. Burke randomly chooses one student to collect yesterday's work. Mrs. Burke's Physics Class Academic Year Physics Majors Non-Physics Majors Freshmen 15 19 Sophomores 10 19 Juniors 19 17 Seniors 11 12 Step 2 of 2: What is the probability that she selects a freshman, given that she chooses a non-physics major? Enter a fraction or round your answer to 4 decimal places, if necessary.

As per the concept of compound interest, the total amount of money needed to pay back the loan in 3 years is $6,035.50.

Now, let's move on to the problem. You are given that $5,000 is borrowed with an interest of 12.3% compounded semi-annually. This means that the interest rate of 12.3% is divided by 2 to get the semi-annual interest rate, which is 6.15% (12.3% / 2). The interest is compounded twice a year, so there will be 6 months between each compounding period.

To find the total amount of money needed to pay back the loan in 3 years, we need to use the formula for compound interest:

A = P(1 + r/n)ⁿˣ

where:

A = the total amount of money needed to pay back the loan

P = the principal amount borrowed

r = the annual interest rate (in decimal form)

n = the number of times the interest is compounded per year

x = the number of years

In this case, we have:

P = $5,000

r = 12.3% = 0.123

n = 2 (compounded semi-annually)

x = 3 years

So the formula becomes:

A = $5,000(1 + 0.0615/2)²ˣ³

Simplifying this, we get:

A = $5,000(1.03075)⁶

Using a calculator, we can find that 1.03075 raised to the power of 6 is approximately 1.2071. So:

A = $5,000(1.2071)

A = $6,035.50

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The probability of having a type 2 defect given a type 1 defect is 0.6667, rounded to four decimal places.

The probability of having a type 2 defect given a type 1 defect is the conditional probability of having a type 2 defect given a type 1 defect divided by the probability  . This can be expressed as P(type 2 defect|type 1 defect)/P(type 1 defect).

P(type 2 defect|type 1 defect) = 0.2

P(type 1 defect) = 0.3

Therefore,

P(type 2 defect|type 1 defect) / P(type 1 defect) = 0.2 / 0.3 = 0.6667

The probability of having a type 2 defect given a type 1 defect is 0.6667 and when rounded to four decimal places it is 0.6667.

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There are 10 rulers when there are 20 students. The problem involves using an equation to relate the number of rulers and students.

The problem describes a relationship between the number of rulers and the number of students, where the number of rulers is five more than one-fourth of the number of students. To find the number of rulers when there are 20 students, we can use the equation:

r = (1/4)s + 5

where "r" is the number of rulers and "s" is the number of students. Substituting s = 20, we get:

r = (1/4)(20) + 5

r = 10

Therefore, there are 10 rulers when there are 20 students.

In summary, the problem involves using an equation to relate the number of rulers and students. To solve the problem, we substitute the given value for the number of students into the equation and solve for the number of rulers.

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The complete question is :

There are five more rulers than a fourth of the number of the students. Find number of rulers when there are 20 students?

The first statement is correct,  that the value of x is 55°.

The second statement is incorrect, the correct statement is the measure of the smaller angle is 35°.

Complementary angles are those whose combined angle is exactly 90°

Part A :

The figure shows right-angled or complementary angle which means the sum of angles is 90°

Therefore we can say that,

x + x-20 = 90°

2x - 20 =90°

2x = 90° + 20

2x = 110°

x = 55°

Therefore the value of the x = 55°, the first statement correct.

The measure of the smaller angle is

= x - 20°

= 55° - 20°

= 35°

The second statement is incorrect.

The correct statement is a measure of the smaller angle is 35°.

Part B:

The figure shows the supplementary angle and the sum of the supplementary angle is 180°.

3x + 6x = 180°

9x = 180°

x = 20°

The first statement is incorrect, the correct statement is the value of x = 20.

The angle measure is 3x = 3 * 20 = 60° and 6x = 6 * 20 = 120°

This means that the second statement is correct.

Part C:

Given that the angle is complementary. the first angle is 2x and the second angle is (3x-5).

A complementary angle is the sum of the angles equal to 90°

2x + 3x-5 = 90

5x = 90 - 5

5x = 85

x = 17°

The first statement is incorrect. the correct statement is the value of x = 17.

The measure of the angle,

2x = 2 * 17 = 34

3x - 5 = 3 * 17 - 5 = 51 - 5 = 46

From the above result, second statement is also incorrect, the correct statement is the measure of the larger angle is 46°.

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Answer:

There are four kings in a standard deck of 52 cards, so the probability of drawing a king is 4/52 or 1/13.

Since we know that the card drawn is a king, there are now only four possible cards that could have been drawn: the king of spades, the king of hearts, the king of clubs, and the king of diamonds.

Out of these four possibilities, only one of them is the king of diamonds. Therefore, the probability that the card is a king of diamonds, given that the card drawn is a king, is 1/4.

In other words, the conditional probability of drawing the king of diamonds given that a king has been drawn is:

P(king of diamonds | king) = P(king of diamonds and king) / P(king) = 1/52 / 4/52 = 1/4

Hope this helps! If not, I'm sorry. Feel free to ask for help from me! :]

The values of x and y that satisfy the system of equations are x = 5 and y = -2.

To solve these equations simultaneously, we can use the method of substitution.

First, let's solve one of the equations for one of the variables. We can rearrange the first equation to solve for x:

2x + 3y = 4

2x = 4 - 3y

x = (4 - 3y)/2

Now we can substitute this expression for x into the second equation and solve for y:

-6y - 2x = 2

-6y - 2((4-3y)/2) = 2

-6y - 4 + 3y = 2

-3y = 6

y = -2

We have found that y = -2. We can now substitute this value back into either of the original equations to solve for x. Let's use the first equation:

2x + 3y = 4

2x + 3(-2) = 4

2x = 10

x = 5

Therefore, the solution to the system of equations is x = 5 and y = -2.

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The calling plan was a logical decision that was made. For calls with a shorter estimated time (10 minutes), the first plan is selected; for calls with an extended expected duration, the second plan is favoured (15 minutes).

Let the costs for the first and second plans, respectively, be denoted by h₁(x) and h₂(x), while the call lasts for x minutes.

The expressions for these two cost functions are as follows, according to the information available:

h₁(x) = 10x

h₂(x) = 99; if x ≤ 20 and 99 + 10(x - 20); if x > 20

Let X represent how long the call was. The exponential distribution of X has a parameter value of λ = 1/10 if the anticipated call time is 10 minutes.

That is, X ~ exp(λ = 1/10)

The exponential distribution's density function with parameter λ = 1/10 is,

f(x) = 1/10[tex]e^{-x/10}[/tex]; if x > 0 and 0; if otherwise

Calculate the anticipated cost of the initial plan E[h₁(x)].

E[h₁(x)] = [tex]\int^{\infty}_{-\infty}h_{1}(x)\cdot f(x)dx[/tex]

E[h₁(x)] = [tex]\int_{-\infty}^{0}10x\cdot 0dx+\int^{\infty}_{0}10x\cdot \frac{1}{10}e^{-x/10}dx[/tex]

E[h₁(x)] = 0 + [tex]\int^{\infty}_{0}x\cdot e^{-x/10}dx[/tex]

E[h₁(x)] = [tex][-10xe^{-x/10}-100e^{-x/10}]^{\infty}_{0}[/tex]

E[h₁(x)] = 100

Calculate the anticipated cost of the initial plan E[h₂(x)].

E[h₂(x)] = [tex]\int^{\infty}_{-\infty}h_{2}(x)\cdot f(x)dx[/tex]

E[h₂(x)] = [tex]\int_{-\infty}^{0}99dx+\int^{20}_{0}99\cdot \frac{1}{10}e^{-x/10}dx + \int^{\infty}_{20}(99+10(x-20))\cdot \frac{1}{10}e^{-x/10}dx[/tex]

E[h₂(x)] = 0 + [tex]\frac{99}{10}\int^{20}_{0}e^{-x/10}dx - \frac{101}{10}\int^{\infty}_{20}e^{-x/10}dx+\int^{\infty}_{20}xe^{-x/10}dx[/tex]

E[h₂(x)] = [tex]\frac{99}{10}[-10e^{-x/10}]^{20}_{0} - \frac{101}{10}[-10e^{-x/10}]^{\infty}_{20} + [-10xe^{-x/10}-100e^{-x/10}]^{\infty}_{20}[/tex]

E[h₂(x)] = -99e⁻² + 99 - 101e⁻² + 200e⁻² + 100e⁻²

E[h₂(x)] = 99 + 100e⁻²

E[h₂(x)] = 112.5335

E[h₂(x)] > E[h₁(x)]  (112.53 > 100) is what has been seen. Hence, the first strategy is chosen when a 10-minute call is anticipated.

The exponential distribution's density function with parameter λ = 1/15 is,

f(x) = 1/15[tex]e^{-x/15}[/tex]; if x > 0 and 0; if otherwise

Calculate the anticipated cost of the initial plan E[h₁(x)].

E[h₁(x)] = [tex]\int^{\infty}_{-\infty}h_{1}(x)\cdot f(x)dx[/tex]

E[h₁(x)] = [tex]\int_{-\infty}^{0}10x\cdot 0dx+\int^{\infty}_{0}10x\cdot \frac{1}{15}e^{-x/15}dx[/tex]

E[h₁(x)] = 0 + [tex]\frac{2}{3}\int^{\infty}_{0}x\cdot e^{-x/15}dx[/tex]

E[h₁(x)] = [tex]\frac{2}{3}[-15xe^{-x/15}-225e^{-x/15}]^{\infty}_{0}[/tex]

E[h₁(x)] = 150

Calculate the anticipated cost of the initial plan E[h₂(x)].

E[h₂(x)] = [tex]\int^{\infty}_{-\infty}h_{2}(x)\cdot f(x)dx[/tex]

E[h₂(x)] = [tex]\int^{20}_{0}99\cdot \frac{1}{15}e^{-x/15}dx + \int^{\infty}_{20}(99+10(x-20))\cdot \frac{1}{15}e^{-x/15}dx[/tex]

E[h₂(x)] =  [tex]\frac{99}{15}\int^{20}_{0}e^{-x/15}dx - \frac{101}{15}\int^{\infty}_{20}e^{-x/15}dx+\frac{2}{3}\int^{\infty}_{20}xe^{-x/15}dx[/tex]

E[h₂(x)] = [tex]\frac{99}{15}[-15e^{-x/15}]^{20}_{0} - \frac{101}{15}[-15e^{-x/15}]^{\infty}_{20} + [-15xe^{-x/15}-225e^{-x/15}]^{\infty}_{20}[/tex]

E[h₂(x)] = -99[tex]e^{-4/3}[/tex] + 99 - 101[tex]e^{-4/3}[/tex] + 200[tex]e^{-4/3}[/tex] + 150[tex]e^{-4/3}[/tex]

E[h₂(x)] = 99 + 150[tex]e^{-4/3}[/tex]

E[h₂(x)] = 138.54

E[h₂(x)] < E[h₁(x)]  (138.54 < 150) is what has been seen. Hence, the first strategy is chosen when a 15-minute call is anticipated.

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1 to power 8 multiplied by 3 to power 0 multiplied 5 to the power of 3 multiplied 2 to the power of 2 is written as 1⁸ × 3⁰ × 5³ × 2² = 500

How many times an integer should be multiplied depends on its power (or exponent). It appears as a tiny number above and to the right of the main number.

How many times you should multiply an integer depends on its magnitude. Other terms for powers include exponents and indices.

Given,

1 to power 8 multiplied by 3 to power 0 multiplied 5 to the power of 3 multiplied 2 to the power of 2

That is written as 1⁸ × 3⁰ × 5³ × 2²

1⁸ × 3⁰ × 5³ × 2²

= 1 × 1 × 125 × 4

= 500

Hence the value of the equation is 500.

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The solution to x/-3-2<-4 is x>18.

In mathematics, inequality is a statement that expresses the relationship between two values, where one value is greater than, less than, or equal to the other. Inequalities can be expressed using symbols such as > (greater than), < (less than), and = (equal to). Inequality can be used to compare two values or expressions, or to determine if a given number is within a certain range. Inequalities can be used to solve problems, such as finding the area of a triangle, or to model real-world situations, such as determining the maximum number of people that can fit in a room.

To solve this inequality, first we subtract 2 from both sides to isolate x:

x/-3<-6

Then, we divide both sides by -3 to solve for x:

x>18

Therefore, the solution to x/-3-2<-4 is x>18.

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The probability of Roger selling a zucchini bread as the next loaf is 4/21.

What is probability?

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, with 0 representing an impossible event and 1 representing a certain event. The probability of an event is calculated by dividing the number of ways the event can occur by the total number of possible outcomes.

The probability of Roger selling a zucchini bread as the next loaf can be found by dividing the number of zucchini breads sold by the total number of breads sold so far.

The total number of breads sold so far is:

11 (banana) + 8 (zucchini) + 9 (cranberry) + 14 (blueberry) = 42

The number of zucchini breads sold is 8.

So the probability that the next loaf Roger sells will be zucchini bread is:

8/42 = 4/21

Therefore, the probability of Roger selling a zucchini bread as the next loaf is 4/21.

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Step-by-step explanation:

Calculate 3/1 x 5/12 = 15/12

The denominator is constant, 12. Think of numbers that multiply the numerator.

What do you multiply by 1/12 to get 15/12?

Ans 15

What do you multiply by 3/12 to get 15/12

Ans 5

Answer:

  2,420,000 m³

Step-by-step explanation:

You want the volume of a square pyramid 220 m on a side and 150 m high.

The volume of a pyramid is 1/3 the volume of a cuboid of the same dimensions.

  V = 1/3LWH

  V = 1/3(220 m)²(150 m) = 2420000 m³

The volume of the pyramid is about 2,420,000 cubic meters.

__

Additional comment

The density of Egyptian limestone is between 2.4 and 2.7 g/cm³, so the mass of the pyramid is approximately 6 million metric tons. This is about 50% more than the most massive building built in modern times.

Since Mehrine and Zaara both brought equal amount of money for shopping, Mehrine brought Rs. 5000 for shopping.

What are Linear equations?

Linear equations are equations whose highest power of the variables is 1. The graph of a linear equation is a straight line.

Let the equal amount of money they both brought = x

Mehrine spent Rs 500 on a pair of shoes, therefore, the money Mehrine has left

= x-500

Zaara bought a dress for Rs 2000, therefore, the money Zaara has left

= x-2000

Zaara has ⅔ of what Mehrine had left.

Therefore:

[tex]x - 2000 = \frac{2}{3}(x - 500)[/tex]

Cross multiply

3(x - 2000) = 2(x - 500)

3x - 6000 = 2x - 1000

3x - 2x = 6000 - 1000

x=5000

Therefore, Mehrine brought Rs5000 for shopping.

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The volume of cone in terms of π is 12π in³. The height of the given cone is 4.

The quantity of space a three-dimensional item occupies is measured by its volume. Usually, it is expressed in terms of cubic units like cubic metres (m³) or cubic millimetres (cm³).

We are given that the radius of the cone is 3 in and the slant height is 5 in. We need to find the height of the cone before we can calculate its volume.

        h² + r² = y²

        h² + 3² = 5²

        h² + 9 = 25

        h² = 16

        h = 4

        V = (1/3)πr²h

        V = (1/3)π(3²)(4)

        V = (1/3)π(9)(4)

        V = (1/3)(36π)

        V = 12π in³

Therefore, the volume of the cone in terms of π is 12π in³

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Hence, in answering the stated question, we may say that As a result, the  expressions value of P75 is 80.375.

In mathematics, you can multiply, divide, add, or subtract. An expression is formed as follows: Expression, number, and math operator Numbers, parameters, and functions make up a mathematical expression. It is possible to contrast phrases and expressions. Every mathematical statement that contains variables, numbers, and a mathematical action between them is referred to as an expression. For example, the phrase 4m + 5 is made up of the phrases 4m and 5, as well as the variable m from the provided equation, all separated by the mathematical sign +.

To determine the value of P75, or the 75th percentile, we must first determine the score at which 75% of the scores fall.

z = (x - μ) / σ

where x is the score to be converted, the mean, and the standard deviation.

As a result, we can write:

0.75 = P(Z ≤ 0.675)

where Z is the mean of the standard normal variable and the standard deviation is 1.

Now we can rearrange the z-score calculation to find the score x:

x = μ + zσ

Using the values we have:

x = 77.4 + (0.675)(5) (5)

x = 80.375

As a result, the value of P75 is 80.375.

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The required mean of the given numbers in Exhibit 1.1 is 2.625.

To find the mean of the given numbers in Exhibit 1.1, we will use the following formula:

Mean = (Sum of all numbers) / (Total number of numbers)

Explanation:

Given data in the form of an exhibit is shown below Exhibit 1.1181310161413171513111414111012121113159121316815

Now, we will add all these numbers and find their sum.1 + 1 + 8 + 1 + 3 + 1 + 0 + 1 + 6 + 1 + 4 + 1 + 3 + 1 + 7 + 1 + 5 + 1 + 3 + 1 + 1 + 1 + 4 + 1 + 1 + 0 + 1 + 2 + 1 + 2 + 1 + 1 + 3 + 1 + 5 + 9 + 1 + 2 + 1 + 3 + 1 + 6 + 8 + 1 + 5= 105

Now, we will count the total number of numbers. There are 40 numbers in total. Therefore, the mean of the given numbers in Exhibit 1.1 is:

Mean = (Sum of all numbers) / (Total number of numbers)= 105 / 40= 2.625

Hence, the required mean of the given numbers in Exhibit 1.1 is 2.625.

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The equation for the function g(x) is g(x) = (x + 4)² - 5.

In Mathematics, the translation of a geometric figure to the left simply means subtracting a digit from the value on the x-coordinate (x-axis) of the pre-image of a function while a geometric figure that is translated downward simply means subtracting a digit from the value on the y-coordinate (y-axis) of the pre-image.

In Mathematics, a vertical translation to the negative y-direction (downward) is modeled by this mathematical expression g(x) = f(x) - N.

Where:

N represents an integer.

g(x) and f(x) represent a function.

Based on the graph of the parent function f(x) = x², an equation for g(x) in vertex form after a translation of 5 units downward and 4 units to the left is given by:

g(x) = (x + 4)² - 5.

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The amplitude οf the functiοn used tο mοdel the height οf a rider οn a Ferris wheel shοuld be equal tο the radius οf the Ferris wheel.

212 feet is the average height. A 550-fοοt ferris wheel is the tallest οne. This may be fοund in Las Vegas, Nevada, and is knοwn as the high rοller.

The amplitude οf a periοdic functiοn, such as the height οf a rider οn a Ferris wheel as a functiοn οf time, is the maximum distance frοm the average οr equilibrium pοsitiοn. In this case, the average οr equilibrium pοsitiοn wοuld be the height οf the rider when the Ferris wheel is at its lοwest pοint. The distance frοm the lοwest pοint tο the highest pοint οf the Ferris wheel is equal tο the diameter, and half οf the diameter is equal tο the radius. Therefοre, the amplitude οf the functiοn shοuld be equal tο the radius οf the Ferris wheel.

The area and circumference οf the Ferris wheel are nοt directly related tο the height οf a rider as a functiοn οf time, sο they are nοt relevant tο the amplitude οf the functiοn.

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Answer: D. the radius of the Ferris wheel

Step-by-step explanation:

The two solutions of the equation x2 - 4x + 1 = 0 are x = 2 + √3 and x = 2 - √3.

A quadratic equation is an equation that can be written in the form ax2 + bx + c = 0, where a, b, and c are real numbers and a is not equal to 0. Solving a quadratic equation involves finding the value of x that makes the equation true. This can be done in multiple ways, but the most common method is to use the Quadratic Formula. The Quadratic Formula states that the roots (or solutions) of a quadratic equation can be found using the following formula:

x = [-b ± √(b2 - 4ac)]/2a

For example, consider the equation x2 - 4x + 1 = 0. In this equation, a = 1, b = -4, and c = 1. Plugging these values into the Quadratic Formula gives us:

x = [-(-4) ± √((-4)2 - 4(1)(1))]/2(1)

Simplifying this equation, we get:

x = [4 ± √(16 - 4)]/2

Finally, simplifying further yields the following two solutions:

x = (4 ± √12) /2

x = 2 ±√3

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a) The average daily balance for the billing period is $285.29.

b) The finance charge to be paid on February 13 is $3.42.

c) The balance due on February 13 is $288.71.

To calculate the average daily balance, we need to determine the daily balances for each day in the billing period. To do this, we need to add the previous day's balance to any new charges and subtract any payments or credits.

Day         Transaction       Daily Balance

Jan 13 Starting balance $221.33

Jan 17 Charge of $50 $271.33

Jan 22 Payment of $100 $171.33

Feb 4 Charge of $100 $271.33

Feb 6 Charge of $100 $371.33

Feb 10 Payment of $100 $271.33

Feb 13 Finance charge $288.71

To calculate the average daily balance, we add up the daily balances and divide by the number of days in the billing period:

To calculate the finance charge, we multiply the average daily balance by the interest rate and the number of days in the billing period:

To calculate the balance due on February 13, we add the finance charge to the average daily balance:

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The calculated value of x given that the streets are parallel to each other is 4760 feet

Given that the street are parallel to each other

We have the following equivalent ratio that can be used to calculate x

x : 2640 = 2380 : 1320

Express the ratio as fraction

So, the above ratio becomes the following equation

x / 2640 = 2380 / 1320

Solving further, we multiply both sides of the equation by 2640

So, we have

2640 * x / 2640 = 2380 / 1320 * 2640

Evaluate the products

x = 4760

Hence, the value of x is 4760 ft

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The correct statements about the transformation are the shape of the parallelogram is preserved and the size of the parallelogram is changed.

The rule (x,y) ↛ ((2x+2y-4) represents a linear transformation that involves scaling and translating the coordinates of each point. Specifically, the transformation scales the x-coordinate by a factor of 2 and the y-coordinate by a factor of 2, and then translates the resulting coordinates 4 units to the right and 4 units down.

Based on this, we can make the following observations:

The shape of the parallelogram L'm'n'p is preserved under the transformation. That is, the transformed parallelogram LMNP is also a parallelogram.

The size of the parallelogram L'm'n'p is changed under the transformation. Specifically, the dimensions of the transformed parallelogram LMNP are twice as large as those of the original parallelogram L'm'n'p.

Therefore, the correct statements about the transformation are:

The shape of the parallelogram is preserved.

The size of the parallelogram is changed.

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Answer:

height = 15 cm

Step-by-step explanation:

Base area of a prism B = hw where h = height, w = width

So B = lw = 200 cm²

Volume V = lwh = 3000 cm³

V/B = lwh/lw = h

h = 3000cm³/200cm = 15 cm

The side lengths and the angle measures is PQ = 2, PR ≈ 3.61, QR = 3

m∠P = 90°, m∠Q = 90°, m∠R ≈ 33.7°

Tο find the side lengths, we need tο use the distance fοrmula:

PQ = √[(x₂ - x₁)² + (y₂ - y₁)²]

PR = √[(x₃ - x₁)² + (y₃ - y₁)²]

QR = √[(x₃ - x₂)² + (y₃ - y₂)²]

PQ = √[(-4 - (-2))² + (4 - 4)²] = √[2²] = 2

PR = √[(-4 - (-2))² + (1 - 4)²] = √[2² + 3²] = √13 ≈ 3.61

QR = √[(-4 - (-4))² + (1 - 4)²] = √[3²] = 3

Tο find the angle measures, we can use the Law οf Cοsines:

cοs(θ) = (b² + c² - a²) / 2bc

where a, b, and c are the side lengths οppοsite tο the cοrrespοnding angles. Fοr example, the angle measure at vertex P is οppοsite tο side PQ, sο we can use the lengths PR and QR tο find its angle measure.

cοs(m∠P) = (PR² + QR² - PQ²) / 2PRQR

cοs(m∠P) = (13 + 9 - 4) / (2 * √13 * 3)

cοs(m∠P) = 18 / (2√39)

m∠P = cοs⁻¹(18 / (2√39)) ≈ 90°

cοs(m∠Q) = (PQ² + QR² - PR²) / 2PQQR

cοs(m∠Q) = (4 + 9 - 13) / (2 * 2 * 3)

cοs(m∠Q) = 0

m∠Q = cοs⁻¹(0) = 90°

cοs(m∠R) = (PQ² + PR² - QR²) / 2PQPR

cοs(m∠R) = (4 + 16 - 13) / (2 * 2 * √13)

cοs(m∠R) = 7 / (4√13)

m∠R = cοs⁻¹(7 / (4√13)) ≈ 33.7°

Therefοre, the answer is:

PQ = 2, PR ≈ 3.61, QR = 3

m∠P = 90°, m∠Q = 90°, m∠R ≈ 33.7°

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Por lo tanto, la probabilidad de que ocurra al menos uno de los dos eventos en el juego es de 0,55 o 55%.

Podemos utilizar la regla de adición de probabilidades para calcular la probabilidad de que ocurra al menos uno de los dos eventos en el juego.

La regla de adición establece que la probabilidad de que ocurra al menos uno de dos eventos A o B es igual a la suma de las probabilidades de los eventos individuales menos la probabilidad de que ambos eventos ocurran juntos:

P(A o B) = P(A) + P(B) - P(A y B)

Podemos reemplazar los valores que se nos dan en la fórmula:

P(A o B) = 0,25 + 0,6 - 0,3

P(A o B) = 0,55

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The equation for line L in slope-intercept form is y = -1/4x + x₁/4 + y₁

The exponential equation is 53−x=251. Therefore, we need to express each side as a power of the same base and then equate exponents. Let's express both sides with the same base 5. We know that 251 is the same as 5². Thus, the equation can be rewritten as:

53−x=251=5².

We need to express 53−x as a power of 5. To do that, we can write it as:

53−x = 5³/x.

Now, we can substitute this expression into our equation to get:

5³/x=5²

Let's multiply both sides of the equation by x to eliminate the fraction:

5³=5²x.

Divide both sides by 5² to get:x = 5. We can check our solution by plugging it back into the original equation:

53−5=25, which is true.

Thus, the solution set is {5}.The equation for line L in the point-slope form: We know that L is perpendicular to y=4x. Thus, the slope of L is -1/4. We also know that L passes through a point (x₁, y₁). Let's write the point-slope form of the equation:

y - y₁ = -1/4(x - x₁).

The equation for line L in slope-intercept form: Let's solve this equation for y to get it in slope-intercept form:

y - y₁ = -1/4(x - x₁).

Multiply both sides by 4 to eliminate the fraction:

4y - 4y₁ = -x + x₁.

Simplify by moving -x + x₁ to the right side:

4y = x₁ - x + 4y₁.

Add x to both sides:

4y + x = x₁ + 4y₁

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Answer:

186

Step-by-step explanation:

97+89=186

Answer:

900/π square centimeters or  286.62 square centimeters

Step-by-step explanation:

The circumference of a circle is given by the formula:

C = 2πr

where C is the circumference and r is the radius of the circle.

We are given that the circumference is 60 cm, so we can set up the equation:

60 = 2πr

Solving for r, we get:

r = 60/(2π) = 30/π

The area of a circle is given by the formula:

A = πr^2

Substituting the value of r, we get:

A = π(30/π)^2 = 900/π square centimeters

Therefore, the area of the circle is approximately 286.62 square centimeters, rounded to two decimal places.