Mr. Lopez was taking a drive to the mountains with his family they arrived at the mountains at 3:09 PM if the drive was two hours and 36 minutes long what time do Mr. Lopez family leave 

Answers

Answer 1

Answer:

they left at 12:34

Step-by-step explanation:

I did the math

Answer 2

9514 1404 393

Answer:

  12:33 pm

Step-by-step explanation:

Often, problems involving addition and subtraction of time values are best worked in 24-hour "military" time.

Here, we want to know the time that is 2:36 before 3:09 pm. We can write 3:09 pm as 15:09. Then the difference is ...

  starting time + travel time = ending time

  starting time = ending time - travel time

  starting time = 15:09 -2:36 = (15-2):(09-36) = 13:(-27) = 12:33

Mr Lopez's family left at 12:33 PM.

__

There are 60 minutes in an hour. 60-27=33.


Related Questions

The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and the Reputation of the Company for over 250 world-wide corporations. Both the Quality of Management and the Reputation of the Company were rated on an Excellent, Good, and Fair categorical scale. Assume the sample data for 200 respondents below applies to this study.

Reputation of Company

Quality of management Excellent Good Fair
Excellent 40 25 5
Good 35 35 10
Fair 25 10 15

Required:
a. Use α = 0.05 level of significance and test for independence of the quality of management and the reputation of the company. What is the p-value and what is your conculsion??
b. If there is a dependence or association between the two ratings, discuss and use the probabilities to justify your answer.

Answers

Answer:

The calculated χ² =  17.0281    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

15                       7.50                                 7.50  

∑                                                               17.0281

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  17.0281    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

3.Construct a line perpendicular to the line given through the point P at the right​

Answers

Answer:

Step-by-step explanation:

The relationship below is proportional true or false

Answers

Answer:

false.........

Step-by-step explanation:

......

Solve the system of equations by graphing

Answers

Answer:

Here's a graph to help you solve this answer:

Which expression is equivalent to this: "3 multiplied by z"?

Answers

Answer:

3z

Step-by-step explanation:

When you write a number followed by a variable with no operation in between them, it means multiplication.

3 multiplied by z is 3 * z, but you can write it without the multiplication sign simply as 3z.

HELP MEEEE !!!
Plsssss

Answers

Answer: option B

This is because you have to work out the range of both periods

The range is the highest number - the lowest number

Range for period 1: 92-81=11
Range for period 3:92-74=18

As you can see the range for period 3 is 7 points greater than period 1 therefore the answer is the second option ( option B)

Hope this helped

Can someone help me? I am stuck on this question! and tysm for the people who helped me!! <3 have a nice day!

Answers

Answer and working out attached below. Hope this helps

Can someone please help me?

Answers

Answer:

D

Step-by-step explanation:

This is a pythagoream thereom question, the area of a square can be found by multiplying the sides. All the sides of a sqaure are the same so we are basically sqauring the side lengths. That is where the [tex]BE^{2}[/tex] and [tex]BH^{2}[/tex] come from. The problem tells us that the area of the two small squares are equal to the one bigger square. And the area of the bigger sqaure can be found by squaring that side EH. So [tex]BE^{2}[/tex]+[tex]BH^{2} =EH^{2}[/tex].

Which line has a slope of 0?

Answers

y= -10
there is no x value so there is no slope, -10 is the y-intercept

Answer:

y =-10

Step-by-step explanation:

because there is no value of x so the slope of y is-10

find the length of the missing side.

Answers

Answer:

I believe it is 12

Step-by-step explanation:

but I am not 100 percent sure

Tell whether the angles are complementary or supplementary. Then find the value of X​

Answers

the answer is x = 5!!!!

PLEASE HELP!!!!!!!!!!!!

Answers

Answer:

I didnt get what the photo shows....

Step-by-step explanation:

I need the answer please don’t scam with a link

Answers

a.) False
b.) True
c.) True
d.) True


Find the sum of the following arithmetic series:
(a) 6-5-16 - .... -115 (b) 21
(c) 13 + 6 -1 - .... -106
Find the sum of the first 500 odd numbers.

Answers

Answer:

12345678910

Step-by-step explanation:

CHARRRRRRRRR joke lang bestie

Consider harmonic oscillators with mass m, spring constant k, and damping coefficient b. For the values specified,

a. write the second-order differential equation and the corresponding first-order system.
b. find the eigenvalues and eigenvectors of the linear system.
c. classify the oscillator (as underdamped, overdamped, critically damped, or undamped) and, when appropriate, give the natural period.
d. sketch the phase portrait of the associated linear system and include the solution curve for the given initial condition.

Answers

Answer:

a) attached below

b) Eigen values : λ1 = -1  and λ2 = - 1/2

  Eigenvector : V1 = - y1  and V2 = ( - 1/2 ) y2

c) since the Oscillator is > 0 hence  it is Overdamped

Step-by-step explanation:

Lets take  : m = 2 , k = 1 and b = 3

a) Second -order differential equation and the first order system

attached below

b) determine the eigenvalues and eigenvectors of the Linear system

Eigen values : λ1 = -1  and λ2 = - 1/2

Eigenvector : V1 = - y1  and V2 = ( - 1/2 ) y2

attached below is the detailed solution

c) The oscillator is classified as OVERDAMPED

To determine if the oscillator is damped, underdamped, or overdamped we will apply the relation below

 b^2 - 4km

 ( 3 )^2 - 4(1)(2)  = 1

since the Oscillator is > 0 hence it is Overdamped

d) Attached below is the phase portrait of the associated linear system

y(0) = 0

v(0) = 0

A bar of soap weighs 175 g. How much do 15 bars of soap weigh in ounces?

Answers

Answer:

92.59 ounces................

Answer:

92.5941501 ounces, 93 ounces if rounded to whole number, and 92.6 if rounded to the nearest tenth.

Step-by-step explanation:

Hope this helps! have a great day

pls help find area and perimeter

Answers

Answer:

A is 14 and P is 17

Step-by-step explanation:

working is above mentioned


PLEASE HELP !! ILL GIVE BRAINLIEST !!

Answers

Answer: #1 is the answer. Alternate exterior angles are the pair of angles that lie on the outer side of the two parallel lines but on either side of the transversal line. Notice how the pairs of alternating exterior angles lie on opposite sides of the transversal but outside the two parallel lines.

Step-by-step explanation: Parallel Lines: Definition: We say that two lines (on the same plane) are parallel to each other if they never intersect each other, ragardless of how far they are extended on either side. Pictorially, parallel lines run along each other like the tracks of a train.

Help me ASAP HELP ME ASAP HELP ME ASAP

Answers

9514 1404 393

Answer:

  9%

Step-by-step explanation:

The interest earned is ...

  I = Prt . . . . . principal P at annual rate r for t years

Solving for r, we find ...

  r = I/(Pt) = $540/($3000×2) = 0.09 = 9%

The interest rate on Beka's loan is 9%.

PLEASE HELP ASAP
Find the greatest common factor of these two expressions:
30x^8 w^4 v^3 and 12w^7 v^5

Answers

Answer:

[tex]Factor = 6w^4 v^3[/tex]

Step-by-step explanation:

Given

[tex]30x^8 w^4 v^3[/tex] and [tex]12w^7 v^5[/tex]

Required

Determine the common factor.

To do this, we simply factorize each. SO, we have:

[tex](1)\ 30x^8 w^4 v^3=: 2 * 3 * 5 * x^8 * w^4 * v^3[/tex]

[tex](2)\ 12w^7 v^5:=\ 2 * 2 * 3 * w^4*w^3 * v^3 * v^2[/tex]

Check for similar factors.

[tex]Factor = 2 *3 * w^4 * v^3[/tex]

[tex]Factor = 6w^4 v^3[/tex]

The above represents the similar factor

what si the answer to this??​

Answers

Answer:

One solution

Step-by-step explanation:

The slopes are different which means, the systems has one solution.

hope this helps and is right p.s. i really need brainliest :)

Please help very urgent

Answers

Answer:

all sides are equal so the x is 50.1 degree and nearest 100 will be 100

please mark me as brainliest

PLEASE HELP !! ILL GIVE BRAINLIEST !!

Answers

Answer:

∠RQO and ∠STV

∠PQO and ∠UTV

Step-by-step explanation:

A field researcher is gathering data on the trunk diameters of mature pine and spruce trees in a certain area. The following are the results of his random sampling: Pine Trees Spruce Trees Sample Size 40 80 Mean trunk diameter (cm) 35 30 Population variance 160 160 Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

Answers

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

[tex]H_a: \mu_1 - \mu_2 > 0[/tex]

In which [tex]\mu_1[/tex] is the mean pine trees height while [tex]\mu_2[/tex] is the mean spruce trees height.

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

[tex]X = 35 - 30 = 5[/tex]

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2[/tex]

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}[/tex]

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

[tex]s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495[/tex]

Test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{5 - 0}{2.4495}[/tex]

[tex]z = 2.04[/tex]

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

The formula A = 23.1 e 0.01521 models the population of a US state, A, in millions, t years after 2000.
a. What was the population of the state in 2000?
b. When will the population of the state reach 28.3 million?

a. In 2000, the population of the state was__million.
b. The population of the state will reach 28.3 million in ___.

Answers

Answer:

- The population in 2001 is 23.1 million

- It will reach 28.3 million in 2013

Step-by-step explanation:

Given

[tex]A =23.1e^{0.0152t}[/tex]

Solving (a): Population in 2000.

This implies that

[tex]t = 2000 - 2000[/tex]

[tex]t = 0[/tex]

So, we have:

[tex]A =23.1e^{0.0152t}[/tex]

[tex]A =23.1e^{0.0152*0}[/tex]

[tex]A =23.1e^{0}[/tex]

Solve the exponent

[tex]A =23.1*1[/tex]

[tex]A =23.1[/tex]

The population in 2001 is 23.1 million

Solving (b): When will it reach 28.3 million

This implies that:

[tex]A =28.3[/tex]

So, we have:

[tex]A =23.1e^{0.0152t}[/tex]

[tex]28.3 = 23.1e^{0.0152t}[/tex]

Divide both sides by 23.1

[tex]1.225 = e^{0.0152t}[/tex]

Take natural logarithm of both sides

[tex]ln\ 1.225 = ln(e^{0.0152t})[/tex]

Rewrite as:

[tex]ln\ 1.225 = 0.0152t\ ln(e)[/tex]

[tex]ln(e) = 1[/tex]

So:

[tex]ln\ 1.225 = 0.0152t*1[/tex]

[tex]ln\ 1.225 = 0.0152t[/tex]

Make t the subject

[tex]t = \frac{ln\ 1.225}{0.0152}[/tex]

[tex]t = \frac{0.2029}{0.0152}[/tex]

[tex]t \approx 13[/tex]

Add the value of t to 2013 to get the actual year

[tex]Year = 2000 +13[/tex]

[tex]Year = 2013[/tex]

It will reach 28.3 million in 2013

Last year Jacob’s total

Answers

Answer:

the answer is $ 83,634

your welcome

please help! Your swag ! :)

Answers

this my answer not sure you like it or not

Answer:

8: 0,-2  9: 7,-3  10: 7,1/2

Step-by-step explanation:

Hello, for question 8 (the top equation), you trying to find y and x so lets find y first. You need y to be by itself so you divide all the numbers by -3 like this:

6x/-3-3y/-3=6/-3

The equation simplifies to -2x+y=-2. You need y to be by itself so you move it to the other side and you get -2 for y. Now you need x. Go to the second equation and take the number that is y and plug it into the equation like this:

6x+8(-2)=-16

Multiply 8 with -2 which is -16. Then, you add -16 with -16 which makes 0.

6x=0

You then divide 6 on both sides and x is 0. You basically do the same process for questions 9 and 10 which are 7,-3 and 7,1/2. And your done!

A study on the latest fad diet claimed that the amounts of weight lost by all people on this diet had a mean of 22.4 pounds and a standard deviation of 5.8 pounds. Step 1 of 2 : If a sampling distribution is created using samples of the amounts of weight lost by 73 people on this diet, what would be the mean of the sampling distribution of sample means? Round to two decimal places, if necessary.

Answers

Answer:

sampling distribution = 22.4

sampling deviation = 0.68

Step-by-step explanation:

Given that :

Mean , μ = 22.4

Standard deviation, σ = 5.8

n = 73

Therefore, the sampling distribution of the mean and the standard deviation is

[tex]$\mu_{\overline x} = 22.4$[/tex]

So, [tex]$\sigma_{\overline x}=\frac{\sigma}{\sqrt n}$[/tex]

            [tex]$=\frac{5.8}{\sqrt {73}}$[/tex]

          = 0.68

So the sampling distribution of the mean is 22.4

The standard deviation is 0.68

sphere has a diameter of 14 ft. What is its surface​ area?

Answers

good morning

A≈615.75ft²

have a great day

A coin is flipped 50 times and lands on heads 28 times. What is the theoretical probability that the coin will land on heads on the next flip?
A) 32%
B) 50%
C) 56%
D) 64%

Answers

C, because half of 50 is 25 therefore since it has landed on the head 28 which is a little bit more means the answer is gonna be a little more than 50%
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