Answer:
a change of position in relation to another object.
Explanation:
Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.
This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.
A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.
Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, displacement, position, etc.
Hence, motion is a change of position in relation to another object.
True or false question scientists can predict when an earthquake will occur
Answer:
False
Explanation:
Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.
14. Which of the following ideas is NOT a part of cell theory?
A. There are only plant and animal cells
B. All living things contain at least one cell
C. Cells come from other cells of the same kind
D. Cells are the basic unit of structure and function of living things
Cell theory states that all living things contain at least one cell, and there are certainly more types of living things than simply plants and animals. For example bacteria and fungi.
So your answer would be A.
Answer: C
Explanation:
all the other ones are part of the cell theory
Hi people; there's a question that has been so confusing for me and a friend of mine.
0°C + 0°C = 64°F
Is this correct or wrong?
Answer:
The correct answer is: 0°C + 0°C = 32°F
Explanation:
We need to remember the conversion equation from Celsius to Fahrenheit:
[tex]y^{\circ}F=(x^{\circ}C * \frac{9}{5})+32[/tex]
In our case x = 0, then y will be:
[tex](0^{\circ}C * \frac{9}{5})+32=32[/tex]
[tex]y=32^{\circ}F[/tex]
Now 0°C + 0°C is just 0°C because if we add a body at a certain temperature to another body with the same temperature the total temperature will the same.
Then, knowing that 0°C = 32°F we can conclude that:
[tex]0^{\circ}C+0^{\circ}C=32^{\circ}F[/tex]
I hope it helps you!
Simplify the expression in part H. Following the five payments, what is the net change in the loan amount from Qulana's viewpoint?
Answer:
I'm not sure but, this video's pretty cool: gestyy.com/eyRkH2
Explanation:
pretty scary gameplay
Answer:
After five monthly payments, Quiana’s loan amount changes by $1,237.15.
Explanation:
how does displacement, acceleration, time, and velocity affect motion?
Answer:
The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.
~Hoped this helped~
~Brainiliest?~
Answer:
We describe motion in terms of velocity and acceleration. Velocity: The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction. ... Acceleration: The rate of change of velocity is acceleration.
Explanation:
Displacement is a vector which points from the initial position of an object to its final position. ... Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity.
Displacement is the vector difference between the ending and starting positions of an object. Velocity is the rate at which displacement changes with time. ... The average velocity over some interval is the total displacement during that interval, divided by the time.
Hope this helps :)
The Law of Conservation of Mass states that mass can be destroyed during a chemical change.
True
False
A car travels 52 mph for 6 minutes, 46 mph for 3 minutes, 40 mph for the remaining time during a 30 minute journey. find the total distance travelled
Answer:
21.5 miles
Explanation:
Distance = Speed * time
Distance traveled in first 6 minutes = 52 * [tex]\frac{6}{60}[/tex] = 5.2 miles
Distance traveled in next 3 minutes = 46 *[tex]\frac{3}{60}[/tex] = 2.3 miles
Remaining minutes = 30 - 6 -3 = 21 minutes
Distance traveled in 21 minutes = 40 * [tex]\frac{21}{60}[/tex] = 14 miles
Total distance traveled = 5.2 + 2.3 + 14 = 21.5 miles
What is the mass of an apple with a potential energy of 8 Joules that is on a shelf that is 4 meters high?
A; 32kg
B; 15Kg
C;4kg
D:2kg
Question 5
Joan wants to decrease her BMI number. How can she achieve her goal?
A. Joan can lose some weight
B. Joan can stretch and get taller
C. Joan can have her blood pressure checked.
D. Joan can take medication
Answer the question?
all of the following describe the motion of an object except
mass
speed
velocity
acceleration
He likes to eat (into passive voice)
Answer:
yes he does
Explanation:
Which of the following is an example of an electromagnetic wave ?
Answer:
Its a wave
Explanation:
THis is one
Answer: a light wave
Explanation: a pex
Solar energy heats the surface of the Earth, including the ground, rocks, and even roadways. As the temperature of these surfaces increases, heat energy is released back into the atmosphere, forming a pocket of warm air. As the warm air pocket rises, it is replaced by cooler air. This process is responsible for many of the weather patterns in our atmosphere and is known as
Answer:
convection
Explanation:
I hope this helps
Explain how a current is induced in the wire?
Answer:
If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. This current flows because something is producing an electric field that forces the charges around the wire. (It cannot be the magnetic force since the charges are not initially moving). ... that determines the induced current.
Give examples to show that friction is both friend and foe ?
Answer:
friction as friend
It helps us to hold or catch any objectit alos helps us to walk easilyfriction as foe
It causes wear and tear of tyresit also cause great damages to parts of machinehope it helps
Answer:
Wear and tear of soles of our shoes is due to friction.
When a tyre deflates, it is difficult to move the vehicle because of increased friction between the tyre and the road surface.
Machines get heated up and produce noise because of friction.
I need help asap
What is a homopolar motor?
a. The first electric motor ever made.
b. A motor made by in the North Pole.
c. A motor used in homes in the winter.
Answer: The answer is A
Explanation:
Three charges lie along the x-axis. One positive charge, q1 = 4.80*10^-18 C, is at x = 3.72 m, and another positive charge, q2 = 1.60*10^-19 C, is at the origin.
At what point on the x-axis must a negative charge, q3, be placed so that the resultant force on it is zero?
Answer:
The third charge needs to be placed at [tex]x \approx 0.57\; \rm m[/tex].
Explanation:
Both [tex]q_1[/tex] and [tex]q_2[/tex] would attract [tex]q_3[/tex].
These two electrostatic attractions need to balance one another. Hence, they need to be opposite to one another. Therefore, [tex]q_1[/tex] and [tex]q_2[/tex] need to be on opposite sides of [tex]q_3[/tex]. That is possible only if [tex]q_3 \![/tex] is on the line segment between [tex]q_1 \![/tex] and [tex]q_2 \![/tex].
Assume that [tex]q_3[/tex] is at [tex]x\; \rm m[/tex], where [tex]0 < x < 3.72[/tex] (in other words, [tex]q_3 \![/tex] is on the line segment between [tex]q_1[/tex] and [tex]q_2[/tex], and is [tex]x\; \rm m \![/tex] away from [tex]q_2 \![/tex].)
Let [tex]k[/tex] denote Coulomb's constant.
The magnitude of the electrostatic attraction between [tex]q_1[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}}[/tex].
Similarly, the magnitude of the electrostatic attraction between [tex]q_2[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
The magnitudes of these two electrostatic attractions need to be equal to one another for the resultant electrostatic force on [tex]q_3[/tex] to be [tex]0[/tex]. Equate these two expressions and solve for [tex]x[/tex]:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}} = \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
[tex]\displaystyle \frac{q_1}{(3.72 - x)^{2}} = \frac{q_2}{x^{2}}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1} = \frac{1}{30}[/tex].
By the assumption that [tex](0 < x < 3.72)[/tex], it should be true that [tex](x > 0)[/tex] and [tex](3.72 - x > 0)[/tex]. Therefore, [tex]\displaystyle \frac{x}{(3.72 - x)} > 0[/tex].
Take the square root of both sides of the equation [tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{1}{30}[/tex].
[tex]\displaystyle \sqrt{\frac{x^2}{(3.72 - x)^{2}}} = \sqrt{\frac{1}{30}}[/tex].
[tex]\displaystyle \frac{x}{3.72 - x} = \frac{1}{\sqrt{30}}[/tex].
[tex]\sqrt{30}\, x = 3.72 - x[/tex].
Therefore:
[tex]\left(1 + \sqrt{30}\right)\, x = 3.72[/tex].
[tex]\displaystyle x = \frac{3.72}{1 + \sqrt{30}} \approx 0.57[/tex].
Hence, [tex]q_3[/tex] should be placed at [tex]x \approx 0.57\; \rm m[/tex].
Compare the inner planets with the outer planets.
Inner Planets:
- Rocky
- Small
- Only 3 moons total
- Very close to each other (for space)
- Underweight
Outer Planets:
- Gassy oop-
- GIANT
- Over 200 moons total
- VERY far from each other
- Obese
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Good luck foe.
Lb.