Answer:
400 44 CX including 4 " +the rotter
What is the value of log↓3 81? 2, 3, 4 or 5?
Answer:The value of log base 3 log base 2 log base √3 81 is -a)1 b) 2 c)3 d) 0
Answer:
4
Step-by-step explanation:
Define [tex]\log_a b=c\implies a^c=b[/tex].
Let
[tex]\log_3 81=x[/tex].
Using our definition [tex]\log_a b=c\implies a^c=b[/tex], we have:
[tex]3^x=81[/tex]
Solving for [tex]x[/tex]:
[tex]x=\boxed{4}\text{ from simply knowing that }3^4=81[/tex]
Or
Algebraically solve step-by-step by taking the log of both sides:
[tex]\log 3^x=\log 81[/tex]
Using log property [tex]\log a^b=b\log a[/tex], rewrite:
[tex]x\log 3=\log81[/tex]
Divide both sides by log(3):
[tex]x=\frac{\log 81}{\log 3}=\boxed{4}[/tex]
If the price of 12 shirts is rupees 3600 3/5 and of 6 pants is rupees 3000 1/5 . Find the price of 4 shirts and 4 pants
Given:
Price of 12 shirts = Rs. [tex]3600\dfrac{3}{5}[/tex]
Price of 6 pants = Rs. [tex]3000\dfrac{1}{5}[/tex]
To find:
The price of 4 shirts and 4 pants.
Solution:
It is given that,
Price of 12 shirts = Rs. [tex]3600\dfrac{3}{5}[/tex]
Price of 1 shirt = Rs. [tex]\dfrac{1}{12}\times 3600\dfrac{3}{5}[/tex]
Price of 4 shirts = Rs. [tex]\dfrac{4}{12}\times 3600\dfrac{3}{5}[/tex]
= Rs. [tex]\dfrac{1}{3}\times \dfrac{18003}{5}[/tex]
= Rs. [tex]\dfrac{18003}{15}[/tex]
Price of 6 pants = Rs. [tex]3000\dfrac{1}{5}[/tex]
Price of 1 pant = Rs. [tex]\dfrac{1}{6}\times 3000\dfrac{1}{5}[/tex]
Price of 4 pants = Rs. [tex]\dfrac{4}{6}\times 3000\dfrac{1}{5}[/tex]
= Rs. [tex]\dfrac{2}{3}\times \dfrac{15001}{5}[/tex]
= Rs. [tex]\dfrac{30002}{15}[/tex]
Now, the price of 4 shirts and 4 pants is:
[tex]\text{Required price}=\dfrac{18003}{15}+\dfrac{30002}{15}[/tex]
[tex]\text{Required price}=\dfrac{48005}{15}[/tex]
[tex]\text{Required price}=\dfrac{9601}{3}[/tex]
[tex]\text{Required price}=3200\dfrac{1}{3}[/tex]
Therefore, the price of 4 shirts and 4 pants is Rs. [tex]3200\dfrac{1}{3}[/tex].
what is the slope of the line shown (-4,3) (3,1)
Answer:
-2/7
Step-by-step explanation:
-Martin bought two bags of jelly beans. The first bag contains 9 red jelly
beans, 5 yellow jelly
beans, 8 green jelly beans, and 2 orange jelly beans. The second bag contains
7 green jelly
beans, 6 red jelly beans, and 8 yellow jelly beans. Martin will randomly select
lol 1 jelly bean from
each bag.
What is the probability that Martin will select a green jelly bean from each
bag?
help quick pls!
Answer:
Step-by-step explanation:
A taxicab moves five blocks due north, five blocks due east, and another three blocks due north. Assume all blocks are of equal size. How far is the taxi from its starting point
Answer:
9.43
Step-by-step explanation:
Given
See attachment for illustration
Required
Distance AE
The actual path taken by the taxicab are in bold lines.
To calculate the distance AE, we simply consider the triangle AOE where
[tex]AE^2 = OE^2 + AO^2[/tex]
[tex]AE^2 = 5^2 + (5+3)^2[/tex]
[tex]AE^2 = 5^2 + 8^2[/tex]
[tex]AE^2 = 25 + 64[/tex]
[tex]AE^2 = 89[/tex]
Take square roots
[tex]AE = \sqrt{89[/tex]
[tex]AE = 9.43[/tex]
The radius of a sphere is increasing at a rate of 5 mm/s. How fast is the volume increasing when the diameter is 40mm? Note: The volume of a sphere of radius, r, is given by V = (4/3)pi r^3
Answer:
The volume is increasing at a rate of 25,133 mm/s.
Step-by-step explanation:
Diameter is 40mm
Radius is half the diameter, so [tex]r = \frac{40}{2} = 20[/tex]
How fast is the volume increasing when the diameter is 40mm?
We have to apply implicit differentiation, of V and r in function of t. So
[tex]V = \frac{4}{3} \pi r^3[/tex]
[tex]\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}[/tex]
The radius of a sphere is increasing at a rate of 5 mm/s.
This means that [tex]\frac{dr}{dt} = 5[/tex]
Then
[tex]\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}[/tex]
[tex]\frac{dV}{dt} = 4\pi (20)^2(5)[/tex]
[tex]\frac{dV}{dt} = 25133[/tex]
The volume is increasing at a rate of 25,133 mm/s.
Quinton brought 40 cupcakesfo school onhis birthday. He gave a cupcake to eachof the 18 students in Ms. Delmont's class. He also gave a cupcake to eachof the 16 students in Mrs. Donnelly's class. He also gave a cupcake to Ms. Delmont, Mrs. Donnelly, the school nurse, and the schoolprincipal. How many cupcakes did he haveleft over?
Answer:
2
Step-by-step explanation:
18+16+4=36
40-38=2
Answer:
2 cupcakes left
Step-by-step explanation:
40 - (18 + 16 + 1 + 1 + 1 + 1) = 2
The girls in Lana’s troop set a goal to sell 1,000 boxes of cookies this year. There are 13 girls in the troop. At least how many boxes of cookies should each girl sell to reach their goal?
Answer:
This question would be answered by doing devision because you are splitting the amount of cookies that should be delivered amongst 13 girls.
1,000/13
76.92307692
That is what came out in my calculator. I don't know if you need it in decimal or in a solid integer but if you were to round 76.9 you would get 77, it is always good to check your work so,
77 times 13
1001
That equals 1001 so that would help at least reach their goal of 1,000 boxes of cookies.
Step-by-step explanation:
I really hope this helps!
If you place a 24-foot ladder against the top of a 20-foot building, how many feet will the bottom of the ladder be from the bottom of the building? Round to the nearest tenth of a foot.
help please
Pythagoras theorem states that for a right angle triangle the measure of the square of the hypotenuse side is equal to the sum of the square of the other two sides.The ladder has to be kept at 13.3( round to the nearest tenth) feet away from the bottom of the wall.
Given information-
The length of the ladder is 24 foot.
The height of the wall is 20 foot.
Suppose the ladder has to kept at x feet away from the bottom of the wall
Here a right angle is formed in which the ladder is hypotenuse side shown in the diagram attached below.
Pythagoras theoremPythagoras theorem states that for a right angle triangle the measure of the square of the hypotenuse side is equal to the sum of the square of the other two sides.
As the ladder has to be kept at x feet away from the bottom of the wall. Thus,
[tex]24^2=20^2+x^2\\ 576=400+x^2[/tex]
Solve for the x,
[tex]x=\sqrt{576-400}\\ x=\sqrt{176}\\ x=13.266[/tex]
hence the ladder ladder has to be kept at 13.3( round to the nearest tenth) feet away from the bottom of the wall.
Learn more about the Pythagoras theorem here;
https://brainly.com/question/343682
How much interest would Mia pay if the simple interest rate were 5%
Answer:
Mia would have a 55$ interest :)
Step-by-step explanation:
In order to evaluate 7 sec(θ) dθ, multiply the integrand by sec(θ) + tan(θ) sec(θ) + tan(θ) . 7 sec(θ) dθ = 7 sec(θ) sec(θ) + tan(θ) sec(θ
Answer:
[tex]\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c[/tex]
Step-by-step explanation:
The question is not properly formatted. However, the integral of [tex]\int {7 \sec(\theta) } \, d\theta[/tex] is as follows:
[tex]\int {7 \sec(\theta) } \, d\theta[/tex]
Remove constant 7 out of the integrand
[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) } \, d\theta[/tex]
Multiply by 1
[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * 1} \, d\theta[/tex]
Express 1 as: [tex]\frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}[/tex]
[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * \frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta[/tex]
Expand
[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta[/tex]
Let
[tex]u = \sec(\theta) + \tan(\theta)[/tex]
Differentiate
[tex]\frac{du}{d\theta} = \sec(\theta)\tan(\theta) + sec^2(\theta)[/tex]
Make [tex]d\theta[/tex] the subject
[tex]d\theta = \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}[/tex]
So, we have:
[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{u}} \,* \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}[/tex]
Cancel out [tex]\sec(\theta)\tan(\theta) + sec^2(\theta)[/tex]
[tex]\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{1}{u}} \,du}}[/tex]
Integrate
[tex]\int {7 \sec(\theta) } \, d\theta = 7\ln(u) + c[/tex]
Recall that: [tex]u = \sec(\theta) + \tan(\theta)[/tex]
[tex]\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c[/tex]
please help. is due tonight. Thank you
Answer:
I am class 6 sorry can'tAnswer:
Step-by-step explanation:
take 60 degree as reference angle
using tan rule
tan 60=opposite/adjacent
[tex]\sqrt{3[/tex]=x/5
5*[tex]\sqrt{3[/tex] =x
5[tex]\sqrt{3[/tex]=x
Hi, I got stucked while solving a differentiation question. Please consider helping me out.
Find the derivative of sin^-1 (yx^2)
The function h (x) = four-thirds x minus 1 represents the composite h(x) = f(g(x)). If f(x) = 2x – 1, what is g(x)?
g (x) = two-thirds x
g (x) = two-thirds x minus 1
g (x) = 2 and one-third x
g (x) = 2 and one-third x minus 1
The g(x) is equal to (2/3)x.To find g(x) in the composite function h(x) = f(g(x)), we need to substitute f(x) = 2x - 1 into the equation and solve for g(x
Given that h(x) = (4/3)x - 1 and f(x) = 2x - 1, we can set up the composite unction:
h(x) = f(g(x))
Substituting f(x) into the equation:
(4/3)x - 1 = 2(g(x)) - 1
Simplifying the equation:
(4/3)x - 1 = 2g(x) - 1
We can now solve for g(x):
2g(x) = (4/3)x
Dividing both sides by 2:
g(x) = (2/3)x
For more such questions on function
https://brainly.com/question/11624077
#SPJ8
A market research analyst claims that 32% of the people who visit the mall actually make a purchase. You think that less than 32% buy something and decide to test this claim of the analyst. You stand buy the exit door of the mall starting at noon and ask 82 people as they are leaving whether they bought anything. You find that actually 20 people made a purchase. 19. State the null and alternative hypotheses to test that less than 32% of mall visitors make a purchase
Answer:
The null hypothesis is [tex]H_0: p \geq 0.32[/tex]
The alternative hypothesis is [tex]H_1: p < 0.32[/tex]
Step-by-step explanation:
State the null and alternative hypotheses to test that less than 32% of mall visitors make a purchase
At the null hypothesis, we test if the proportion is of at least 32%, that is:
[tex]H_0: p \geq 0.32[/tex]
We are testing if less than 32% of visitors make a purchase, so, at the alternative hypothesis, we test if the proportion is less than 32%, that is:
[tex]H_1: p < 0.32[/tex]
12 + 2 × 8 ÷ 2 - 3 × 4 = ?
Answer:
el resultado es 8 ese es el resultado
Answer:
8
I used a calculator and got this answer so it should be right.
please please please help me find the answerrrrr
Answer:
320.28?
Step-by-step explanation:
Level 1
A B C D
1
3
2
4
Enter the correct 4 digit code (no spaces) *
A car travels at a constant speed of 120km per hour. how many kilometers will the car travel in 6 hours
Answer:
720 km.
Step-by-step explanation:
120 * 6 = 720 km
Answer:
720
Step-by-step explanation:
120km every hour times by 6
Find the volume of the prism.
5 cm
14 cm
9 cm
3 cm
3
Answer:
34
Step-by-step explanation:
Question 12 (2 points)
(08.04 MC)
Mia creates a box plot using 28, 34, 40, 24, 44, 49, and 32 as the data. Which of the following box plots shows the data accurately? (2 points)
a
A box plot is drawn with end points at 24 and 49.The box extends from 32 to 48 and a vertical line is drawn inside the box at 38.
b
A box plot is drawn with end points at 24 and 49.The box extends from 26 to 42 and a vertical line is drawn inside the box at 32.
c
A box plot is drawn with end points at 24 and 49.The box extends from 30 to 46 and a vertical line is drawn inside the box at 36.
d
A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.
Answer:
A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.
Step-by-step explanation:
Ordering the data given :
24,28,32,34,40,44,49
We can calculate the 5 number summary required to give the appropriate boxplot that can be produced :
Minimum = 24
Maximum = 49
Median = 1/2(n+1)th term
n = 7
Median = 1/2(8) = 4th term
Median = 34
Lower quartile, Q1 = 1/4(n+1)th term
n = 7
1/4(8) = 2nd term
Q1 = 28
Upper quartile : 3/4(n+1)th term
n = 7
Q3 = 3/4(8) = 6th term
Q3= 44
Some values of a linear function are shown in this table:
What is the rate of change of this function?
X y
2 11
3 16.5
4 22
5 27.5
9514 1404 393
Answer:
5.5
Step-by-step explanation:
The rate of change is given by the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (16.5 -11)/(3 -2) = 5.5/1
m = 5.5
The rate of change of this function is 5.5.
Melissa got 18 out of 20 on a math quiz. Tom got 85% on the quiz. Whose mark was greater?
Answer:
[tex]tom = \frac{85}{100} \times 20 \\ = 17 \: questions[/tex]
Melissa had a greater mark.
Answer:
Melissa
Step-by-step explanation:
Melissa: 18/20
Tom: 85/100
You need a common denomenater so multiply 18 and 20 by 5:
90/100>85/100
Melissa has the greater mark by 5%
Get brainiest if right?
The sum of four consecutive numbers is two more than three
times the greatest of these numbers. Find the numbers.
Answer:
1, 2, 3, 4
Step-by-step explanation:
x+(x+1)+(X+2)+(X+3)+2 = 3(X+3)
4X+8=3x+9
x=1
Answer:
5,6,7,8
Step-by-step explanation:
5+6+7+8=26
8*3=24
26-24=2
1million got how many zeros?
Answer:
it would get 6 zeros
Step-by-step explanation:
hope it helps :)
What is the difference in unit price between a 5 gallon bucket of paint for $97.45 and a 1 gallon bucket of paint for $21.95?
Answer: $2.46
Step-by-step explanation:
First, let's find the unit price for both buckets!
A 1 gallon bucket of paint is $21.95. But how much will a 1 gallon bucket of paint cost if it had origianlly been 97.45 for 5 gallons of paint?
We need to divide 97.45 by 5, and the answer will be the unit price.
97.45 ÷ 5 = 19.49.
A 1 gallon bucket of paint that was originally priced as $97.45 for 5 gallons of paint si now $19.49 per bucket.
But we're not done! We still need to find the difference in unit prince between a 5 gallon bucket of paint for $97.45 and a 1 gallon bucket of paint for $21.95.
21.95 - 19.49 = 2.46.
Therefore, the difference in unit price between a 5 gallon bucket of paint for $97.45 and a 1 gallon bucket of paint for $21.95 is $2.46.
Find x. Round your answer to the nearest integer.
25
х
37°
Answer:
A. 15
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityTrigonometry
[Right Triangles Only] SOHCAHTOA [Right Triangles Only] sinθ = opposite over hypotenuseStep-by-step explanation:
Step 1: Define
Identify variables
Angle θ = 37°
Opposite Leg = x
Hypotenuse = 25
Step 2: Solve for x
Substitute in variables [sine]: sin37° = x/25[Multiplication Property of Equality] Multiply 25 on both sides: 25sin37° = xEvaluate: 15.0454 = xRewrite: x = 15.0454Round: x ≈ 15I'LL GIVE BRAINLIST!!! 1. Find the missing parts of the triangle. Round to the nearest tenth when necessary or to the nearest minute as appropriate.
C = 109.3°
a = 5.6 km
b = 10.7 km
Answer:
c=13.6km, B=47.9⁰, A=22.8⁰,
Using the cosine rule, the missing parts of the triangle are:
c = 13.6 km; B = 47.9°; C = 22.8°
What is the Cosine Rule?Cosine rule is given as, c² = a² + b² ﹣ 2ab(cosC)
Given the following:
C = 109.3°a = 5.6 kmb = 10.7 kmFind c using the cosine rule:
c² = 5.6² + 10.7² ﹣ 2(5.6)(10.7)(cos 109.3)
c² = 185.5
c = √185.5
c = 13.6 km.
Use the cosine rule to find A:
5.6² = 10.7² + 13.6² ﹣ 2(10.7)(13.6)(cosA)
31.36 = 299.45 ﹣ 291.04(cosA)
31.36 - 299.45 = ﹣ 291.04(cosA)
-268.09 = ﹣ 291.04(cosA)
0.9211 = (cosA)
C = cos^(-1)(0.9211)
C = 22.8°
Find B:
B = 180 - 22.8 - 109.3
B = 47.9°
Therefore, using the cosine rule, the missing parts of the triangle are:
c = 13.6 km; B = 47.9°; C = 22.8°
Learn more about the cosine rule on:
https://brainly.com/question/23720007
In a valid probability distribution, each probability must be between 0 and 1, inclusive, and the probabilities must add up to 1. If a probability distribution 5 1 has probabilities and x, what is the value of X? 12' 6' 4 ОА. 1 O B. 1 / 2 C. 1 O O D. حاليا SUBMIT
Answer:
1 / 6
Step-by-step explanation:
If the probability distribution has the probabilities :
5/12, 1/6, 1/4 and x
Then ;
The total sum of all the probabilities should be equal to 1 ;
That is ;
5/12 + 1/6 + 1/4 + x = 1
Lcm of 4, 6, 12 = 12
(5 + 2 + 3)/12 + x = 1
10/12 + x = 1
x = 1 - 10/12
x = 2 / 12
x = 1/6
Given that r= 2p2/q-3 ; rearrange the formula to make q the subject of the formula.
Step-by-step explanation:
The given expression is:
[tex]r=\dfrac{2p^2}{q-3}[/tex]
We need to solve it to make q the subject of the formula.
Cross multiplying both sides,
[tex]rq-3r=2p^2[/tex]
Adding 3r to both sides,
[tex]rq-3r+3r=2p^2+3r\\\\rq=2p^2+3r[/tex]
Now, dividing both sides by r,
[tex]q=\dfrac{2p^2+3r}{r}[/tex]
Hence, this is the required solution.