Answer:
False
Explanation:
Freshwater habitats include ponds, lakes, rivers, and streams, while marine habitats include the ocean and salty seas.
What is The charge of PbI2
Answer:
Lead iodide (II) is an inorganic compound, lead salt and hydrogen acid, with the PbI2 formula.
Rank the following compounds in order of increasing stability, putting the least stable first. Group of answer choices II < I < III I < II < III III < II < I III < I < II
Hello. You forgot and show the compounds. The compounds are in the attached image.
Answer:
I < II < III
Explanation:
The stability of the presented compounds must be analyzed, taking into account the free electrons to form arrangements between the atoms. In this case, the molecules of greater stability follow the concept of valence and are characterized as those that manage to reach a large number of elements that manage to obey the octet rule.
What is the molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution?
Answer:
0.389 M
Explanation:
From the question given above, the following data were obtained:
Mass of CuCl₂ = 78.5 g
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Next, we shall determine number of mole in 78.5 g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5 g
Number of mole of CuCl₂ =?
Mole = mass / Molar mass
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 mole
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Number of mole of CuCl₂ = 0.584 mole
Volume of solution = 1.50 L
Molarity of CuCl₂ =?
Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389 M
The molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
HOW TO CALCULATE MOLARITY?The molarity of a solution can be calculated
From the question given above, the following data were obtained:
Mass of CuCl₂ = 78.5 gVolume of solution = 1.50 LMolarity of CuCl₂ =?Next, we shall determine number of moles in 78.5g of CuCl₂. This can be obtained as follow:
Molar mass of CuCl₂ = 63.5 + (35.5×2)
= 63.5 + 71
= 134.5 g/mol
Mass of CuCl₂ = 78.5g
Number of mole of CuCl₂ = 78.5 / 134.5
Number of mole of CuCl₂ = 0.584 moles
The determine the molarity of the solution. This can be obtained as follow:
Number of moles of CuCl₂ = 0.584 molesVolume of solution = 1.50LMolarity of CuCl₂ =?Molarity = mole / Volume
Molarity of CuCl₂ = 0.584 / 1.50
Molarity of CuCl₂ = 0.389M
Therefore, molarity of a solution that contains 78.5 g of copper(II) chloride in 1.50 L of solution is 0.389M.
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59. Which one has 0 dipole moment?
a. H2O2 b. Co2 c. HF
d. HBr
Answer:
the answer to this question is A H202
Please balance the equation, putting the correct coefficient in each box.
Do not leave any boxes blank! Enter "1" for formulas having a presumed
coefficient of 1.
Bi(OH)3 +
HNO3 →
H2O +
Bi(NO3)3
Answer: [tex]Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The balanced equation will be:
[tex]Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3[/tex]
Question 8 of 25
What is alchemy?
O A. A scientific approach to research that uses observations and
measurements to test ideas
O B. An early form of chemistry that people used to try to turn metal
into gold
O c. A belief that chemistry forms the basis of all areas of science
O D. An ancient philosophy that taught that all matter was composed
of earth, fire, water, and air
SUBMIT
Alchemy is "an early form of chemistry that people used to try to turn metal into gold".
The development of a universal cure for illness, as well as the discovery of a way to indefinitely extend life, were the goals of mediaeval chemical research and speculative philosophy.
Boyle contributed to the evolution of chemistry from alchemy. He used the experimental approach from physics and applied it to chemistry. Boyle contributed to the comparison of these two fields of knowledge by demonstrating that chemistry is just as important to study as physics.
Therefore, the correct statement will be "An early form of chemistry that people used to try to turn metal into gold".
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Consider the reaction 2H2(g)+O2(g)→2H2O(l) 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) What is the mass of water, H2O(l) H 2 O ( l ) , produced when 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?hen 5.70 g g of O2(g) O 2 ( g ) reacts with excess H2(g) H 2 ( g ) ?
Answer:
mH₂O = 6.4116 g
Explanation:
Let's write the given reaction:
2H₂ + O₂ -------> 2H₂O
The problem states that 5.7 g of oxygen reacts with excess hydrogen, hence, the limiting reagent is the oxygen. With this mass of oxygen, we can determine the moles, and then, the moles of water with the mole ratio:
moles = mass / atomic weight AW of O₂ = 16 g/mol
Replacing we have:
moles O₂ = 5.70 / (16 * 2)
moles O₂ = 0.1781 moles
According to the balanced reaction, 1 mole of Oxygen produces 2 moles of water, so we have a mole ratio 1:2, therefore the moles of water would be twice the moles of oxygen:
moles H₂O = 0.1781 * 2 = 0.3562 moles
Finally the mass of water can be calculated solving for the mass from the expression of moles, and using molecular mass of water:
m = moles * MM MM H₂O = 18 g/mol
m = 0.3562 * 18
mH₂O = 6.4116 gHope this helps
Using the van der Waals equation, determine the pressure exerted by 4.30 mol Ar in 3.6 L at 325K.
Answer:
37.7 atm
Explanation:
Using the relation;
(P + an^2/V^2) (V - nb) = nRT
(P + an^2/V^2) = nRT/(V - nb)
a = 0.0341 atm dm^2 Mol^2
b = 0.0237 dm/mol
P = nRT/(V - nb) - an^2/V^2
P = [4.3 * 0.082 * 325 / (3.6 - (4.3 * 0.0237))] - (0.0341 * (4.3^2))/(3.6^2)
P = 114.595/(3.498) - 0.0487
P = 37.7 atm
What a main difference between Earth and Jupiter?
A. Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.
B. Earth is an inner planet with a relatively long distance from the sun, while Jupiter is an outer planet with a relatively short distance from the sun.
C. Earth is an outer planet with a gas surface composition, while Jupiter is an inner planet with a solid rock surface composition.
D. Earth is an outer planet with a relatively short distance from the sun, while Jupiter is an inner planet with a long distance from the sun.
Answer: A. Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.
Answer: What a main difference between Earth and Jupiter?
Earth is an inner planet with a solid rock surface composition, while Jupiter is an outer planet with a gas surface composition.
Earth is an inner planet with a relatively long distance from the sun, while Jupiter is an outer planet with a relatively short distance from the sun.
Earth is an outer planet with a gas surface composition, while Jupiter is an inner planet with a solid rock surface composition.
Earth is an outer planet with a relatively short distance from the sun, while Jupiter is an inner planet with a long distance from the sun.
Explanation:
forms of energy reflection
Answer:
any of these
Explanation:
kinetic energy: kinetic is motion, or released energy
Potential energy: porential energy is the energy of position or stored energy.
Thermal energy: is heat energy, it is stored energy that creats heat.
The following table lists molecular weight data for a polypropylene material. Molecular Weight Range (g/mol) xi wi
8,000 - 16,000 0.07 0.03 16,000 - 24,000 0.15 0.09 24,000 - 32,000 0.26 0.21 32,000 - 40,000 0.27 0.27 40,000 - 48,000 0.18 0.28 48,000 - 56,000 0.07 0.12
Click here to access Table 14.3. Atomic weights for several elements are included in the following table: Carbon 12.01 g/mol Chlorine 35.45 g/mol Fluorine 19.00 g/mol Hydrogen 1.008 g/mol Oxygen 16.00 g/mol Nitrogen 14.01 g/mol Compute the following:
(a) the number-average molecular weight, Enter your answer for part (a) in accordance to the question statement g/mol
(b) the weight-average molecular weight, Enter your answer for part (b) in accordance to the question statement g/mol
(c) the degree of polymerization.
Answer:
a) the number-average molecular weight is 32,400 g/mol
b) the weight-average molecular weight is 36,320 g/mol
c) the degree of polymerization is 770
Explanation:
Given the data in the question;
Molecular Mean Number Weight Number Weight
weight average average
(g/mol) Mi(g/mol) xi wi xiMi wiMi
8,000-16,000 12,000 0.07 0.03 840 360
16,000-24,000 20,000 0.15 0.09 3000 1800
24,000-32,000 28,000 0.26 0.21 7280 5880
32,000-40,000 36,000 0.27 0.27 9720 9720
40,000-48,000 44,000 0.18 0.28 7920 12320
48,000-56,000 52,000 0.07 0.12 3640 6240
∑ Mn=32,400 Mw=36,320
so;
a) the number-average molecular weight
Mn = ∑Mixi
so from the table above; summation of Row Mixi
Mn = ∑Mixi = 32,400
Therefore, the number-average molecular weight is 32,400 g/mol
b) the weight-average molecular weight
Mw = ∑Miwi
so from the table above; summation of Row Miwi
Mw = ∑Miwi = 36,320
Therefore, the weight-average molecular weight is 36,320 g/mol
c) the degree of polymerization
the degree of polymerization of polypropylene can be determined using number-average molecular and repeat unit molecular weight.
now, for polypropylene { CH₂ = CH - CH₃ }
the repeat unit consist of 3 carbon atoms and 6 hydrogen atoms
given that;
Atomic weight of Carbon mC = 12.01 g/mol and
Atomic weight of Hydrogen mH = 1.008 g/mol
now we find the repeat unit molecular weight of polypropylene
m = nCmC + nHmH
where n is the number of repeat of atoms
so we substitute
m = ( 3 × 12.01) + ( 6 × 1.008)
m = 36.03 + 6.048
m = 42.078 g/mol
now we calculate the degree of polymerization;
DP = Mn / m
so we substitute
DP = 32,400 / 42.078
DP = 769.9985 ≈ 770
Therefore, the degree of polymerization is 770
Why do you think the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene?
Answer:
See explanation
Explanation:
The reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate as well as the reaction of tetraphenylcyclopentadienone and diphenylacetylene are Diels Alder reactions. The former is performed in presence of a solvent while the former is performed neat.
The reaction of tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate leads to the formation of a more resonance-stabilized aromatic ring(lower energy product) compared to the reaction of tetraphenylcyclopentadienone and diphenylacetylene.
Hence, the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene.
Ethane is a hydrocarbon with a formula of C2H6 . How many Carbon and Hydrogen atoms are contained within 3 molecules of ethane ?
Answer:
Within three molecules of Ethane, it would have 6 carbon, and 18 hydrogen atoms in it.
Explanation:
How many moles of MgCl2 can be made from 10 moles of Cl2?
_Mg + _Cl2 -->_MgCl2
(A) 10 moles MgCl2
(B) 11 moles MgCl2
(C) 8 moles MgCl
(D) 15moles MgCl
8. Label the type and parts of the waves shown here.
longitudinal wave
WORD BANK
engitudinal wave
• transverse wave
compression
• rarefaction
crest
trough
Houghton Mifflin Harcourt
Skin color variations were caused by:
a). The change in melanin, the skin's brown pigment
b). The climate of where people migrated to
c)Diets that are rich in Vitamin D
d) All of the above
I'm certain the answer is D: All of the above, but please correct me if I'm wrong ^^
How much heat (J) is required to heat a 75.00 g copper block from 35.0°F to 59.0°F?
Answer:
[tex] \sqrt[.132 = ]{32 = ? = 1} = .82[/tex]
Answer:
693 j
Explanation:
weight =75 g * specific heat of copper = .385j/g * change in temp = 24
= 693
Hydroxylamine hydrochloride is a powerful reducing agent which is used as a polymerization catalyst. It contains 5.80 mass % H, 20.16 mass % N, 23.02 mass % O, and 51.02 mass % Cl. What is its empirical formula? Determine the molecular formula of the compound with molar mass of 278 g.
Answer: The molecular formula will be [tex]H_{16}NOCl[/tex]
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of H = 5.80 g
Mass of N = 20.16 g
Mass of O = 23.02 g
Mass of Cl = 51.02 g
Step 1 : convert given masses into moles.
Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.80g}{1g/mole}=5.80moles[/tex]
Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{20.16g}{14g/mole}=1.44moles[/tex]
Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.02g}{16g/mole}=1.44moles[/tex]
Moles of Cl =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{51.02g}{35.5g/mole}=1.44moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For H = [tex]\frac{5.80}{1.44}=4[/tex]
For N = [tex]\frac{1.44}{1.44}=1[/tex]
For O = [tex]\frac{1.44}{1.44}=1[/tex]
For Cl = [tex]\frac{1.44}{1.44}=1[/tex]
The ratio of H: N: O: Cl= 4: 1: 1: 1
Hence the empirical formula is [tex]H_4NOCl[/tex]
The empirical weight of [tex]H_4NOCl[/tex] = 4(1)+1(14)+ 1(16) + 1(35.5)= 69.5 g.
The molecular weight = 278 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{278}{69.5}=4[/tex]
The molecular formula will be=[tex]4\times H_4NOCl=H_{16}NOCl[/tex]
How to set up the rate expressions for the following mechanism?
A → B k1
B → A k2
B+C → D k3
If the concentration of B is small compared with the concentrations of A, C, and D, the steady-state approximation may be used to derive the rate law. Derive the rate law, and show that this reaction may follow the first-order equation at high pressures and the second-order equation at low pressures.
Answer:
Explanation:
From the given information:
A → B k₁
B → A k₂
B + C → D k₃
The rate law = [tex]\dfrac{d[D]}{dt}=k_3[B][C] --- (1)[/tex]
[tex]\dfrac{d[B]}{dt}=k[A] -k_2[B] -k_3[B][C][/tex]
Using steady-state approximation;
[tex]\dfrac{d[B]}{dt}=0[/tex]
[tex]k_1[A]-k_2[B]-k_3[B][C] = 0[/tex]
[tex][B] = \dfrac{k_1[A]}{k_2+k_3[C]}[/tex]
From equation (1), we have:
[tex]\mathbf{\dfrac{d[D]}{dt}= \dfrac{k_3k_1[A][C]}{k_2+k_3[C]}}[/tex]
when the pressure is high;
k₂ << k₃[C]
[tex]\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_3[C]}= k_1A \ \ \text{first order}[/tex]
k₂ >> k₃[C]
[tex]\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_2}= \dfrac{k_1k_3}{k_2}[A][C] \ \ \text{second order}[/tex]
When salt water is heated leaving behind solid salt, this is separating a mixture by what method?
A)
chromatography
B)
evaporation
Eliminate
filtration
D)
sifting
Answer:
option B is correct answer of this question
it is. Evaporation
Answer:
It's filtration!
Explanation:
Filtration is a physical chemical operation that separates solid matter and fluid from a mixture!
A) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
B) Suppose you separate a 3.02 g mixture of sand and salt. You recover 1.43 g of salt and 1.41 g of sand. What is the percent recovery of the mixture?
C) Calculate the percent by mass of a solution made from 15 g NaCl (the solute) and 69 g water.
D) What percent of 73.0 g is 26.1 g?
Answer:
A-B) 94 %.
C) 17.9 %.
D) 35.8 %.
Explanation:
Hello!
A-B) In this case, since the total mass of the mixture is 3.02 g and 1.43g+1.41g=2.84 g are recovered in total, we can compute the percent recovery as shown below:
[tex]\%rec=\frac{2.84g}{3.02g}*100\%\\\\\%rec=94\%[/tex]
C) Here, since the solution is made up of NaCl and water, we can say that the mass of the solution is 15g+69g=84g; thus, the percent by mass would be:
[tex]\%=\frac{15g}{84g}*100\%\\\\\%=17.9\%[/tex]
D) In this case, we simply divide 26.1 g by 73.0 g in order to obtain the percent:
[tex]\%=\frac{26.1g}{73.0g}*100\%\\\\\%=35.8\%[/tex]
Best regards!
The percentage in the cases are as follows;
A and B is; 94%C is; 17.9%D is; 35.8%Questions A and B are similar and can be solved as follows;
The total mass of the mixture is 3.02g.The recovered mass = 1.43g + 1.41g = 2.84g% recovery = (2.84/3.02) × 100%% recovery = 94%Question C can be solved as follows;
Total mass of solution = 15 + 69 = 84gMass of solute = 15g% by mass = (15/84) × 100%% by mass = 17.9%Question D can be solved as follows;
% = (26.1/73) × 100%% = 35.8%Read more:
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Calculate the number of moles of H2SO4 required to react with 0.93 moles of Al. Do not include units in your answer. Round to the tenths place or further.
Answer:
1.40 moles of H₂SO₄.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below below:
2Al + 3H₂SO₄ —> Al₂(SO₄)₃ + 3H₂
From the balanced equation above,
2 moles of Al reacted with 3 moles of H₂SO₄.
Finally, we shall determine the number of mole of H₂SO₄ required to react with
0.93 moles of Al. This can be obtained as follow:
From the balanced equation above,
2 moles of Al reacted with 3 moles of H₂SO₄.
Therefore, 0.93 moles of Al will react with = (0.93 × 3)/2 = 1.40 moles of H₂SO₄.
Thus, 1.40 moles of H₂SO₄ is needed for the reaction.
What is the concentration of a Kl solution of 20.68 g of solute was dissolved in enough water to form 100. ml of solution?
Answer:
1.25M
Explanation:
The following conditions must be met before a standard calibration curve equation can be used to solve for the concentration of an unknown solution:
a. The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
b. The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
c. The equation from the calibration curve can only be linear.
d. Domain and range restrictions must be observed.
Answer:
The same instrument must be used to measure the unknown solution as was used to measure the known (standard) solutions that were used to create the calibration curve.
The analyte in the unknown solution must be the same analyte (or type of analyte) that is present in the known (standard) solutions that were used to create the calibration curve.
Domain and range restrictions must be observed.
Explanation:
Calibration curves are tools necessary in understanding the instrumental response for any analyte.
A calibration curve is obtained by preparing a set of standard solutions with known concentrations of the analyte. The instrument response for each concentration is measured and plotted against the concentration of the standard solution. The linear portion of this plot may be used to determine the unknown concentration of a sample of the analyte.
The equation of the best-fit line is used to determine the concentration of the unknown sample.
1. What is the frequency of the following:
a. radio waves with wavelength 50 m?
b. gamma-ray with a wavelength of 45 m?
2.What is the wavelength of the following?
a. infrared light with frequency of 3 .5x 10° Hz?
b. ultraviolet light with frequency of 4.0x 10 * Hz
Answer:
its soooooo ezy
Explanation:
82828I 87is 818373773622771829383746171948468328933737373737378364737272828374736367181i3i46738100104848070792761527484930201834728the 8585949476425675666
Ammonia reacts with oxygen to form nitrogen dioxide and water according to the
following equation:
4NH71875) + 70212) ---> 4NO2/2) + 6H2013)
You react ammonia and oxygen, and at the end of the experiment you find that you
produced 23 g of water and have 8.52 g of ammonia left over. Determine the mass of
oxygen reacted.
17.66 g 02
40.85 g 02
O 47.66 g 02
71.49 g 02
35.02 g 02
B
What is the difference between an introduced species and an invasive species?
Answer and Explanation:
The introduced species is, literally, a species that was introduced into an environment by human action. In other words, an introduced species is one that is not native to a region, does not occur naturally, but has been taken by humans to that region.
An invasive species, on the other hand, is one that was introduced naturally in an environment, but multiplied in a harmful way, causing a strong imbalance in the region.
3. Noble gases are sometimes called "inert gases." What can you infer about the meaning of the word "inert" in chemistry?
Answer:
Noble gases are sometimes called "inert gases." What can you infer about the meaning of the word "inert" in chemistry? It refers to substances that easily lose electrons. It refers to substances that do not react with other substances. It refers to substances that have strong electrochemical charges.
Explanation:
What is the electrostatic potential energy (Eel) of the ionic bond between a Ca2+ ion and a S2– ion in joules? Before you do the calculation, predict whether the result you get will be less than (more negative) or greater than (less negative) than the Eel value for KCl. The ionic radii of Ca2+ and of S2– are 100 pm and 184 pm, respectively.
Answer: the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
Explanation:
Given the data in the question;
I think the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has more charge that is +2 and -2 respectively when compared to Kcl which has +1 and -1 charge.so it will be more negative.
radius = r[tex]_{ca+2}[/tex] + r[tex]_{s-2}[/tex] = 100 + 184 = 284 pm = 2.84 × 10⁻¹⁰ m
we know that; k = 2.31 × 10⁻²⁸ J
q1 = 2 ( charge on Ca⁺² )
q2 = -2( charge on S⁻²)
so
Ep = k × q1q2/r
so we substitute
Ep = 2.31 × 10⁻²⁸ × (+2×-2) / 2.84 × 10⁻¹⁰
Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰
Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰
Ep = -3.26 × 10⁻¹⁸ J
Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
Based on the data provided, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J
What is electrostatic potential energy?The electrostatic potential energy is the work done in moving the charge from infinity to that point against the electric field.
The electrostatic potential energy between any two charges q1, q2 separated by distance r is derived from Coulomb’s law and mathematically given as:
E = k × [q1q2/r2]where
k is a constant = 2.31 × 10⁻²⁸ Jq1 and q2 are the chargesr is the distance of separationFrom the data provided:
ionic radii of Ca2+ r1 = 100 pm
ionic radii of S2– = 184 pm.
Chargeon Ca2+ = +2
Charge on S2_ = -2
From the data above, it most likely that the value of electrostatic potential energy of calcium sulfide CaS formed will be less(more negative) than KCl because the Ca2+ and S2- ions has a greater charge of +2 and -2 respectively compared to Kcl which has +1 and -1 charge.
Calculating the electrostatic potential energy, Ep:
radius = r1 + r2 = 100 + 184 = 284 pm
r = 2.84 × 10⁻¹⁰ m
k = 2.31 × 10⁻²⁸ J
q1 = 2 ( charge on Ca⁺² )
q2 = -2( charge on S⁻²)
Then:
Ep = k × q1q2/r
Substituting the values above in the equation:
Ep = 2.31 × 10⁻²⁸ × (+2 ×-2) / 2.84 × 10⁻¹⁰
Ep = (2.31 × 10⁻²⁸ × -4) / 2.84 × 10⁻¹⁰
Ep = -9.24 × 10⁻²⁸ / 2.84 × 10⁻¹⁰
Ep = -3.26 × 10⁻¹⁸ J
Therefore, the electrostatic potential energy is -3.26 × 10⁻¹⁸ J.
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Calculate how many grams of BeCl2 are required to produce 0.52 grams of MnCl2
Answer:
65.0cp
Explanation: